.....................

Josh's monthly fuel expenses are $1,050.

Given that Josh is looking to get a new car because he decided he was spending too much on gas, and over the past year he found that he drove 7,700 miles, and at current gas prices of $4.5 he was getting about 27 miles per gallon, To determine, if he bought a vehicle that realizes 33 miles per gallon, what might be a reasonable estimate of monthly gas costs, the following calculation must be made:

Therefore, Josh's monthly fuel expenses are $1,050.

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Answer:Josh's monthly fuel expenses are $1,050.

Step-by-step explanation:

Answer:

A. 12

Step-by-step explanation:

If she had 12 quarters, then she would have to have 4 nickels according to the problem.

12 * .25 = $3 (money in quarters)

4 * .05 = $.2 ( money in nickels)

Adding those 2 together, we get $3.2.

She have 12 quarters

It is a method where we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

There are two situation in Unitary method:

There are 5 ice-creams. 5 ice-creams cost $125.

Step 1: Let’s find the cost of 1 ice cream. In order to do that, divide the total cost of ice-creams by the total number of ice-creams. The cost of 1 ice-cream = Total cost of ice-creams/Total number of ice-creams = 125/5 = 25. Therefore, the cost of 1 ice cream is $25.

Step 2: To find the cost of 3 ice-creams, multiply the cost of 1 ice cream by the number of ice-creams. The cost of 3 ice-creams is cost of 1 ice-cream × number of ice-creams = 25 × 3 = $75. Finally, we have the cost of 3 ice-creams i.e. $75.

Given:

If she had 12 quarters, then

12 * .25 = $3 ( quarters)

4 * .05 = $.2 ( in nickels)

Hence, she have 12 quarters.

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Answer:

z=16

Step-by-step explanation:

10=z-6

10+6=z-6+6

16=z

Answer:

10=z-6

or, z= 10+6

or, z = 16

the vale of y is 16

The trigonometric form of the complex number given in the task content is; 18(isin(π/2)).

If follows from the task content that the complex number whose trigonometric representation is to be determined is; 18i.

Hence, It follows that the trigonometric form is;

= 18(cos(π/2) + isin(π/2)). where; cos(π/2) = 0.

Hence, we have;

= 18(isin(π/2)).

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The first function is a type of cubic function and the second function is a type of linear function. The key feature(s) do f(x) and g(x) have in common as they both have value of domain and range as (-∞, ∞).

A function assigns the value of each element of one set to the other specific element of another set.

The function given in the problem is:

f(x) = x³ + x² – 3x + 4

The highest degree (power) of this function is 3. Thus, this function is a type of cubic function.

The second function given in the problem is:

g(x) = 2x – 4

The highest degree (power) of this function is 1. Thus, this function is a type of linear function.

Both the function has the value of domain and range from -∞ to ∞ (-∞,∞).

Thus, the first function is a type of cubic function  and second function is a type of linear function. The key feature(s) do f(x) and g(x) have in common as they both have value of domain and range as (-∞, ∞).

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Answer:

Undefined (DNE)

Step-by-step explanation:

Any vertical line has an undefined slope.

Finding the inverse function of [tex]f(x) = 5\sqrt{x + 3} - 2[/tex], it is best described by graph B.

Supposing we have a function y = f(x), to find the inverse, we exchange x and y, and isolate y.

In this problem, the function is:

[tex]f(x) = 5\sqrt{x + 3} - 2[/tex]

[tex]y = 5\sqrt{x + 3} - 2[/tex]

Exchanging x and y:

[tex]x = 5\sqrt{y + 3} - 2[/tex]

Working through the function to isolate y:

[tex]5\sqrt{y + 3} = x + 2[/tex]

[tex]\sqrt{y + 3} = \frac{x + 2}{5}[/tex]

[tex](\sqrt{y + 3})^2 = \left(\frac{x + 2}{5}\right)^2[/tex]

[tex]y + 3 = \frac{(x + 2)^2}{25}[/tex]

[tex]y = \frac{(x + 2)^2}{25} - 3[/tex]

[tex]f^{-1}(x) = \frac{(x + 2)^2}{25} - 3[/tex]

Which is best represented by graph B.

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The quantity of product that would result in the same profit is 1 thousand. Option A

Given the polynomial function as;

P(t) = –2t³ + 8t² + 2t

Where;

Let's equate the values

–2t³ + 8t² + 2t = 8

–2t³ + 8t² + 2t - 8 = 0

Factorize the expression

(-2t³ + 8t²) + ( 2t -8) = 0

- t² ( 2t - 8) + (2t -8) = 0

We take the similar factor

2t - 8 = 0

2t = 8

t = 8/2

t = 4

But we have that the company produced 4 thousand products for $8 million profit, so we have

= 4/ 4

= 1 thousand

Thus, the quantity of product that would result in the same profit is 1 thousand. Option A

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Using a system of equations, the translated expression is:

P - 32.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variable is the number of dollars Paul owes, which is P. That amount minus 32 is represented by:

P - 32.

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Answer:

x = 5 ,  x = - 6

Step-by-step explanation:

First we factor using factorisation method :

We need 2 numbers that multiply to give +1 and add to give -30 :

To find these numbers we write out all the factors of 30 :

1, 30

2 , 15

3 , 10

5 , 6    ----> These must be the numbers as -5+6 = 1

Now we split +x into -5x and +6x :

x² -5x + 6x -30 = 0

Factor the first 2 terms together and the last two terms :

x(x-5) + 6(x-5) = 0

Keep 1 bracket and terms outside the brackets collect them into one:

(x-5)(x+6) = 0

We know that 1 of these brackets must be equal to zero as anything multiplied by zero = 0

Either x - 5 =0      OR x + 6 = 0

So x = 5                x = - 6

These are our final answers

Hope this helped and have a good day

Answer:

(x-5) (x+6)

x=5

X=-6

Step-by-step explanation:

x²+x-30=0

factorizing

x²-5x+6x-30=0

x(x-5)+6(x-5) =0

(x-5)(x+6)=0

now solve individually

x-5=0

send 5 to the other side

x=5

x+6=0

send 6 to the other side

x=-6

hope you understand the procedure

Answer:

  h > 5

  h < 0

Step-by-step explanation:

We suppose that a "Special Solution" inequality is one that is technically incorrect, but is written using a compact "shorthand" form.

As written, the inequality claims that 17 < 2, which is false. There can be no value of the variable that will make this true. We presume the intended meaning is ...

  17 < 3h +2   or   3h +2 < 2

Subtracting 2 from the inequality gives ...

  15 < 3h < 0

Dividing by 3 gives ...

  5 < h < 0

There is no value of h that is both greater than 5 and less than 0, so we presume this means the OR (union) of the solution sets ...

  h > 5

  h < 0

Probability someone chosen at random will not have brown hair = 1/6

The number of girls = 15

The number of boys = 15

The total number of children = 15 + 15 = 30

Probability that someone chosen at random will have a brown hair, P(Brown hair) = 5/6

P(Brown hair) + P(Not Brown hair) = 1

5/6  +  P(Not brown hair) = 1

P(not brown hair) = 1 - 5/6

P(not brown hair) = 1/6

Therefore, if someone is chosen at random, probability that they will not have brown hair = 1/6

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After conversion 98.2 °F=119.2°C

96.6 °F=116.3°C

100.1 °F==122.6°C

How can we convert temperature from Fahrenheit to Celsius?

We will convert using this formula

C= (F-32) *5/9

We will convert temperature from Fahrenheit to Celsius as shown below:

C= (F-32) *5/9

For Oral

Temperature=98.2°F

C= (98.2-32) *5/9

=119.16°C

Rounding to nearest tenth

=119.2°C

For Axillary

Temperature=96.6 °F

C= (96.6-32) *5/9

=116.28°C

Rounding to nearest tenth

=116.3°C

For Rectal

Temperature=100.1 °F

C= (100.1-32) *5/9

=122.58

Rounding to nearest tenth

=122.6°C

Hence, after conversion 98.2 °F=119.2°C

96.6 °F=116.3°C

100.1 °F=122.6°C

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Using Green's Theorem to evaluate the given line integral with the given conditions and vertices gives us; -30

The line integral of a vector-valued function along the edges of a rectangle or any other closed curve can be found by converting the line integral into a double integral. We apply Green's theorem to do this. The resulting double integral is integrated over the two-dimensional region bounded by the same closed curve.

Green's Theorem can be applied as follows:

∮_c (P.dx + Q.dy) = ∫∫_R ((dQ/dx) - (dP/dy))dA

The vertices of the rectangle (1,1), (3,1), (1,4), and (3,4).

Applying Green's Theorem to the given function gives;

∮_c (ln x + y) dx - x² dy

= ∫14∫13 Dx(-x2) -Dy(ln(x) +y) dx dy

= ∫₁⁴∫₁³ (-2x - 1) dx dy

= -3·[x² +x]₁³

= -30

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Answer:

no

Step-by-step explanation:

because no

Answer: B. 9 hours

Step-by-step explanation:

Question analysis (Optional if you can understand the question)

Since they are 1170 miles apart, with their speed, the question is asking how long would it take them to travel 1170 miles together.

In other words, the distance that Jo and Jan together add up to 1170 miles.

Given information

Total distance = 1170 miles

Jo's rate = 60 mph

Jan's rate = 70 mph

Set variables

Let x be the time they took to meet each other

Set equation

60x + 70x = 1170

Solve equation

130x = 1170

Divide 130 on both sides

130x / 130 = 1170 / 130

[tex]\boxed{x=9 \: hrs}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer: $350

Step-by-step explanation:

$700 divided by 2 is 350

The description of the corresponding partition is given as follows:
The infinite classes can be defined as:

At equal  distance of x from point [1,2] 

Where x can vary from o to infinity.

The analogous partition, commonly known as "the set of equivalence classes," is the set A/R, the elements of which are the subsets of A satisfying  the following:


For every a∈A there is some B∈A/R such that a∈B.

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When [tex]n=0[/tex], we have

[tex]5^{3^0} + 1 = 5^1 + 1 = 6[/tex]

[tex]3^{0 + 1} = 3^1 = 3[/tex]

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for [tex]n=k[/tex], that

[tex]3^{k + 1} \mid 5^{3^k} + 1[/tex]

Now for [tex]n=k+1[/tex], we have

[tex]5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)[/tex]

so we know the left side is at least divisible by [tex]3^{k+1}[/tex] by our assumption.

It remains to show that

[tex]3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1[/tex]

which is easily done with Fermat's little theorem. It says

[tex]a^p \equiv a \pmod p[/tex]

where [tex]p[/tex] is prime and [tex]a[/tex] is any integer. Then for any positive integer [tex]x[/tex],

[tex]5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3[/tex]

Furthermore,

[tex]5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3[/tex]

which goes all the way down to

[tex]5^{3^k} \equiv 5 \pmod 3[/tex]

So, we find that

[tex]\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3[/tex]

QED

The equation of the ellipse is [tex]\frac{x^2}{49} + \frac{y^2}{65} = 1[/tex]

The given parameters are:

The above means that:

c = 4 and

The semi-major axis, a = 7 i.e 14/2

Calculate b using

[tex]b = \sqrt{c^2 + a^2[/tex]

So, we have:

[tex]b = \sqrt{4^2 + 7^2[/tex]

[tex]b = \sqrt{65[/tex]

Square both sides

[tex]b^2 = 65[/tex]

The standard form of the ellipse is represented as:

[tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex]

This gives

[tex]\frac{x^2}{7^2} + \frac{y^2}{65} = 1[/tex]

Evaluate

[tex]\frac{x^2}{49} + \frac{y^2}{65} = 1[/tex]

Hence, the equation of the ellipse is [tex]\frac{x^2}{49} + \frac{y^2}{65} = 1[/tex]

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Answer:

6

Step-by-step explanation:

no calculator at hand ?

really ? you are using us a simple calculator ?

Answer:

6

Step-by-step explanation:

what is the sum of .74+.19+3.09+1.98=​

0.74+

0.19+

3.09+

1.98=

-----------------

6

Answer:

A

Step-by-step explanation:

the sum to n terms of a geometric series is

[tex]S_{n}[/tex] = [tex]\frac{a_{1}(r^{n}-1) }{r-1}[/tex] , then for n = 7

S₇ = [tex]\frac{-1(2^{7}-1) }{2-1}[/tex] = [tex]\frac{-1(128-1)}{1}[/tex] = - 1 (127) = - 127

The value of the angle TSU is.97°. Therefore, none of the given options are correct.

From the information given, the value of UZ will be:

= YZ - YU

= 63 - 26

= 37°

UZ = TZ = 37°

Therefore, the value of TSU will be:

= 23° + (37° × 2)

° 23° + 74°

= 97°

In conclusion, the correct option is E.

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Answer:

Yes because putting value of x and y as 1 and -1 in equation :

y=3x-4

-1 = 3 * 1 - 4

-1 = -1 (True)

Answer:

[tex]x \approx 1.16[/tex]

Step-by-step explanation:

a.

To find the values of m and n, we have to first expand  [tex](x + m)^2 + n[/tex] :

[tex](x + m)^2 + n[/tex]

⇒ [tex]x^2 + 2mx + m^2 + n[/tex]

[tex]f(x) = x^2 + 4x - 6[/tex]

Now  compare the coefficients of the x-terms:

• [tex]2mx = 4x[/tex]

⇒ [tex]\bf m = 2[/tex]

• [tex]m^2 + n = -6[/tex]

⇒  [tex]2^2 + n = -6[/tex]

⇒ [tex]n = -10[/tex]

b.

[tex]x^2 + 4x - 6 = 0[/tex]

∴ [tex](x + 2)^2 - 10 = 0[/tex]

⇒ [tex](x + 2)^2 = 10[/tex]

⇒ [tex]x + 2 = \sqrt{10}[/tex]

⇒ [tex]x = \sqrt{10} -2[/tex]

⇒ [tex]x \approx 1.16[/tex]

We know that,

slope = [tex] \rm{\frac{(y2 - y1)}{(x2 - x1)} }[/tex]

Let (0,1)=(x 1 ,y 1 ) and (1,2)=(x 2,y 2 )

So,

Slope of line = [tex] \frac{(2 - 1)}{(1 - 0)} = 1[/tex]

Now,

The required line equaqtion is given by,

==> y−y 1 = m(x-x1)

==> y−1=1(x−0)

==> y−1=x

==> y=x+1

The measure of angle A and C will be 94.5° and 85.5°.

(5y - 3) + (3y + 27) = 180

Collect like terms

5y + 3y - 3 + 27 = 180

8y = 180 - 27 + 3

8y = 156

y = 156/8 = 19.5

(5y - 3) = (5 × 19.5) - 3 = 94.5

(3y + 27) = (3 × 19.5) + 27 = 85.5

Therefore, the measure of angle A and C will be 94.5° and 85.5°.

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