1. A paper pinwheel is spinning in the wind. Which statement is correct about the forces responsible for the rotation?
The components of gravity and the force of wind that point through the pivot are responsible for the rotation.
Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
Only the perpendicular component of gravity is responsible for the rotation, because wind points toward the pivot. <- MY ANSWER
The perpendicular components of gravity and the force of wind are responsible for the rotation.
2. Which statement about kinetic and static friction is accurate?
Static friction is greater than kinetic friction, but they both act opposite the applied force.
Static friction is greater than kinetic friction, and they both act in conjunction with the applied force.
Kinetic friction is greater than static friction, but they both act opposite the applied force.
Kinetic friction is greater than static friction, and they both act in conjunction with the applied force.
3. A group of engineers is preparing a satellite to land by moving it 10% closer to Earth in each rotation. Which statement is correct about the rotational inertia of the satellite?
Rotational inertia decreases proportional to the decrease in the radius of rotation.
Rotational inertia increases proportional to the decrease in the radius of rotation. <- MY ANSWER
Rotational inertia first decreases and then increases as the satellite is ready to land.
Rotational inertia does not change because it is conserved.
4. In the experimental setup shown (see image attached), a car has one end of a string attached to it. The other end of the string has a hanger on which metal discs can be added or removed. The car moves along the table, and two photogate probes sense the motion of the car. The probes send information to a computer that displays the experimental results.
Which quantity is being held constant in this experiment?
mass
force
acceleration
velocity <- MY ANSWER
Answers
Answer:
1) Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
2) static friction is greater than kinetic friction and the applied force acts oppositely
3) Inertia decreases with decreasing radius of the orbit.
4) constant is the mass of the car
Explanation:
1) In order to know which statement is correct, let's analyze the movement of the mill.
The rotation of the blades due to a force perpendicular to each one, which creates a torque that results in its rotation.
The true force does not affect the movement because it is applied at the center of mass of the mill that coincides with its axis of rotation.
Of the statements, the correct one is:
The perpendicular to the wind is responsible for the movement
2) static friction is the result of microscopic bonds between two surfaces when there is no relative motion between them
kinetic friction is the result of the unions between the two surfaces when there is a relative movement between them.
From these statements it follows that friction is contrary to motion, static friction must be greater than kinetic friction.
Of the statements the correct one is:
static friction is greater than kinetic friction and the applied force acts oppositely
3) The inertia of a particle is
I = m R²
where m is the mass of the satellite and R is the distance from the center of the Earth, decreasing with each orbit
The correct answer is:
Inertia decreases with decreasing radius of the orbit.
4) From the figure it can be seen that the motorist subjected to a constant force, for which we can apply Newton's second law
F = m a
The force equals the applied weight.
The quantity that is held constant is the mass of the car
since the applied force and therefore the acceleration can be changed by changing the applied weight.
Answer:
1. The perpendicular components of gravity and the force of wind are responsible for the rotation.
2. Static friction is greater than kinetic friction, but they both act opposite the applied force.
3. Rotational inertia decreases proportional to the decrease in the radius of rotation.
4. mass
Related Questions
A variable is defined as anything that
Answers
Identify two types of motion where an object's speed remains the same while it continues to change direction.
Answers
Answer:
circular motionmotion of light (photons) on a non-linear pathExplanation:
Velocity is a vector with speed and direction components. If the speed does not change, then the direction must. In order to change the direction of a velocity vector, there must be some acceleration, and it must be orthogonal to the direction of motion.
Circular motion is motion that has a constant acceleration perpendicular to the direction of travel.
__
Another kind of motion that meets the requirement is the motion of light. Light travels at a constant speed, regardless. If light changes direction (as in a gravitational field or when reflected), its direction will change, but its speed will not.
To whom does the vha provide care for today ?
Answers
Answer:
The Veterans Health Administration (VHA) is the largest integrated health
care system in the United States, providing care at 1,255 health care
facilities, including 170 VA Medical Centers and 1,074 outpatient sites of care
of varying complexity ( VHA outpatient clinics) to over 9 million Veterans
enrolled in the VA .
A graph of x vs. t2 is linear, and intercepts the vertical axis at 12 m and the horizontal axis at 4 s2. What is the function?
Answers
Answer:
x = -3t² + 12
Explanation:
x vs t² is a line.
x = at² + b
The y intercept is 12.
x = at² + 12
At t² = 4s², x = 0.
0 = a(4) + 12
a = -3
Therefore, the function is:
x = -3t² + 12
Robert pushes the box to the left at constant speed. In doing so, Robert does ______ work on the box. A. positive B. negative C. zero
Answers
Answer:
He does postive work
Explanation:
Because W= F xS sinစ
So since work is done such that Force and distance have the Sam direction
Thus စ=0
Then work is positive in value
If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, after 10 s: How fast (speed) would it be traveling (in m/s)
Answers
Answer:
Explanation:
Using the equation of motion v = u + at to get the speed at which the object would be travelling.
v is the final speed (in m/s)
u is the initial velocity (in m/s)
a is the acceleration (in m/s²)
t is the time taken (in secs)
Given parameters
u = 0m/s
t = 10s
a = g = 9.8m/s²
Substituting this values into the formula;
v = 0+9.8(10)
v = 0+ 98
v = 98m/s
Hence the rock will be travelling at a speed of 98m/s.
If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed
Answers
Answer:
speed=d/t.
s=4/5=0.8m/s.
X-rays with wavelength of 2.0 nm scatter from a NaCL crystal with plane spacing of 0.281 nm. Find the scattering angle for the second order maxima.
Answers
Explanation:
Wavelength of x-rays = 2 nm
Plane spacing, d = 0.281 nm
It is assumed to find the scattering angle for second order maxima.
For 2nd order, Bragg's law is given by :
[tex]2dsin\theta =n\lambda[/tex]
For second order, n = 2
[tex]sin\theta =\frac{n\lambda}{2d} \\Sin\theta =\frac{2\times2}{2\times0.281} \\\theta =\arcsin (7.14)[/tex]
Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.
You want to create an electric field vector E = < 0, 5 104, 0> N/C at location < 0, 0, 0>. Where would you place a proton to produce this field at the origin?
Answers
Answer:
1.696 × 10^(-7) m on the y axis.
Explanation:
We are given the electric field as;
E = < 0, 5 × 10⁴, 0> N/C
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
E = 5 × 10⁴ N/C in the y direction.
Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
The proton to produce this field at the origin should be put on [tex]1.696 \times 10^{(-7)} [/tex]m on the y axis.
The calculation is as follows:We are given the electric field as;
[tex]E = < 0, 5 \times 10^{4}, 0> N/C[/tex]
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
[tex]E = 5 \times 10^{4} N/C[/tex] in the y direction.
The Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Now Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
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What is the momentum of a tiger that has a mass of 81 kg and runs with a velocity of 5.4 m/s to the east
Answers
Given :
Mass of tiger , m = 81 kg .
Velocity of tiger , v = 5.4 m/s .
To Find :
The momentum of tiger .
Solution :
We know , momentum of a body is given by the product of its mass and velocity .
[tex]P=m\times v[/tex]
Now , putting value of m and v in above equation , we get :
[tex]P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s[/tex]
Therefore , the momentum of tiger is 437.4 kg m/s .
Hence , this is the required solution .
Answer:
437.4
Explanation: did the math
When a circuit is arranged in parallel
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
B. There is only one path the electrons can take through the circuit, and they must pass through all circuit components
Answers
Answer:
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
Explanation:
Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You blow across the open mouth of an empty test tube and produce the fundamental standing wave of the air column inside the test tube. The speed of sound in air is 344 m/s and the test tube acts as a stopped pipe. Required:a. If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave? b. What is the frequency of the fundamental standing wave in the air column if the test tube is half filled with water?
Answers
Answer:
a
[tex]f = 614.3 \ Hz[/tex]
b
[tex]f_h = 1229 \ Hz[/tex]
Explanation:
From the question we are told that
The speed of sound in the air is [tex]v_s = 344 \ m/s[/tex]
The length of the test tube is [tex]l = 14.0\ cm = 0.14 \ m[/tex]
Since the test tube is closed at on end the frequency is mathematically represented as
[tex]f = \frac{v_s}{ 4 l }[/tex]
=> [tex]f = \frac{344}{ 4 * 0.14 }[/tex]
=> [tex]f = 614.3 \ Hz[/tex]
From the part B the column of the test tube is half filled with water so the frequency becomes
[tex]f_h = \frac{v_s}{ 2 l }[/tex]
[tex]f_h = \frac{344}{ 2 * 0.14}[/tex]
[tex]f_h = 1229 \ Hz[/tex]
What is the toy's total energy at any point of its motion? Express your answer with the appropriate units.]
Answers
The complete question is as follows:
A 0.150-kg toy is undergoing SHM on the end of a horizontal spring with force constant k = 300 N/m. When the toy is 0.0120 m from its equilibrium position, it is observed to have a speed of 0.400 m/s.
Answer:
The correct answer is 0.034 J.
Explanation:
Given :
mass of the toy is m = 0.15 kg.
The force constant of restoring force k = 300 Nm⁻¹
When the position of the toy from the equilibrium is x = 0.012m, then the
speed of the toy vx = 0.4m s
The total mechanical energy in SHM is given by
E= 1/2 (mv²+ kx²) = 1/2 kA²
(here, m = mass of the object, vx = velocity, k = force constant
of restoring force, and A = amplitude of SHM.)
Hence by substituting the numerical values in equation 1, we get
[tex]E= \frac{1}{2} (0.15* 0.4) + \frac{1}{2} (300* 0.012)[/tex]
= 0.034 J
Thus, the correct answer is 0.034 J.
a net external force of 100.0 N acts on an object of mass 20.0 kg whose initial speed is 10.0 m/s. The force acts in the opposite direction from the objects motion, and it acts for 1.00 s. what is the objects final speed in m/s
Answers
Explanation:
We know that :
[tex]F = m\frac{(v - u)}{t} [/tex]
[tex]100 = 20 \frac{(v - 10)}{1} [/tex]
[tex]v(final \: velocity) = 15 \: m \: sec^{ - 1} [/tex]
Which of these equations is dimensionally correct?
I. mv/ t= F
II. xv^2= Fx^3/ x^2
III. xt= vt^2+at^3
Answers
Answer: first and third.
Explanation:
An equation is dimensionally correct if the units are the same in both sides of the equation.
first, let's define the units used:
{m} = kg
{v} = m/s
{F} = kg*m/s^2
{x} = m
{t} = s
{a} = m/s^2
Now, let's analyze each option:
1) m*v/t = F
in the left side the units are:
{m}*{v}/{t} = kg*(m/s)*(1/s) = kg*m/s^2
And as is written above, these are the units of F, so this is correct.
2) x*v^2 = F*(x^3/x^2)
This is more trivial, in the right side we can see an F, that has mass units (kg) and in the left side we have x and v, and we know that none of these have mass units, so this expression is not correct.
3) xt= vt^2+at^3
the units in the right side are:
{x}*{t] = m*s
in the right side are:
{v}*{t}^2 + {a}*{t}^2 = (m/s)*s^2 + (m/s^2)*s^3 = m*s + m*s
So in both sides of the equation we have the same units, then this equation is dimensionally correct.
which component of health related fitness is developed by performing a wall sit
Answers
Answer:
it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle
As the frequency of the ac voltage across an inductor approaches zero, the inductive reactance of that coil Group of answer choices
Answers
Answer:
The inductive reactance also approaches zero
Explanation:
This is because from the relation
XL = 2πfL
Meaning frequency f and inductive reactance XL are directly proportional so as one approaches zero so does the other
Find the value of x in the triangle shown below.
9
C
3
Answers
A car traveling at 7 m/s accelerates at a rate of -0.8 m/s for an interval of 2 seconds.
Find the final velocity.
The nosition of a ninewood derhucar a ohraniodaturi
Answers
Answer:
6.2m/s
Explanation:
v=u+at
v=7+(-0.8/2)(2)
v=7-0.8
v=6.2m/s
State two precautions each that you will take while performing refractive index of a glass box experiment
Answers
Answer:
light should be direct
glass should not be cracked
pins should be pointed carefully
Explanation:
A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its average velocity.
Answers
Answer:
1.43 × 10^-2 m/s
Explanation:
Given the following :
Distance covered away from it's master = D1 = 24×10^-2 m
Time taken to cover the distance = t1 = 12.6s
Then runs halfway back D2 =
D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m
Time taken =T2 = T1/3 = 12.6/3 = 4.2s
Since the kitten ran in a straight line, the it is linear :
Average speed
Linear Average Velocity:
Change in distance / change in time
(D1 - D2) / (T2 - T1)
(24 - 12)×10^-2 / (12.6 - 4.2)
(12 × 10^-2)m / 8.4s
1.4285 × 10^-2
= 1.43 × 10^-2m/s
Tim can type 2,000 words at a speed of 50 words per min.
Bob's typing speed is 80 words per min. How much less time
did Bob take than Tim to type 2000 words?
min
h
Answers
Answer: the awnser to this question is 15
Explanation:
First you will divide the typing speed and the total number of words by the speed 2000 ÷ 50
Then divide bobs typing speed by 2000 equation 2000÷80 once you get the total both you will subtract the 2 totals together and get 15 as your awnser.
Hoped this helped!
The harder a gas pedal in a car is pressed the faster the car's velocity increases. Which phrase best describes the relationship between how hard the gas pedal is pressed and the acceleration of the car?
A. There is both a negative correlation and causation
B. There is a positive correlation but no causation.
C. There is a negative correlation but no causation.
D. There is both a positive correlation and causation.
Answers
Answer:
D
There is both a positive correlation and causation
The relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
From the given statement the relationship between the cause (pedal) and the effect (velocity) can be described as direct relationship.
In direct proportionality, the outcome of one variable produces similar effect to the other variable.The harder the gas pedal in a car is pressed, the velocity increases. This shows that as the force applied to the gas pedal increases (the cause of the action), the greater the velocity of the car (the effect of the cause).
Thus, we can conclude that the relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
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when would a swimmer have the most potential energy due to her position
Answers
Answer: A
Explanation:
A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
What is potential energy?The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.
The potential energy is found as;
[tex]\rm PE = mgh[/tex]
The potential energy is mainly depending upon the height of the object.
When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
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If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial acceleration of each of them. aelectron = nothing m/s2
Answers
Answer:
The acceleration of the proton is 2.823 x 10¹⁷ m/s²
The acceleration of the electron is 5.175 x 10²⁰ m/s²
Explanation:
Given;
distance between the electron and proton, r = 7 x 10⁻¹⁰ m
mass of proton, [tex]m_p[/tex] = 1.67 x 10⁻²⁷ kg
mass of electron, [tex]m_e[/tex] = 9.11 x 10⁻³¹ kg
The attractive force between the two charges is given by Coulomb's law;
[tex]F = \frac{k(q_p)(q_e)}{r^2}[/tex]
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/c²
[tex]F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N[/tex]
Acceleration of proton is given by;
F = ma
[tex]F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2[/tex]
Acceleration of the electron is given by;
[tex]F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2[/tex]
Given:
Mass of proton, [tex]m_p = 1.67\times 10^{-27} \ kg[/tex]Mass of electron, [tex]m_e = 9.11\times 10^{-31 } \ kg[/tex]Distance between electron & proton, [tex]r = 7\times 10^{-10} \ m[/tex]By using Coulomb's law, the attractive force will be:
→ [tex]F = \frac{k(q_p) (q_e)}{r^2}[/tex]
By substituting the values, we get
[tex]= \frac{(9\times 10^9)(1.602\times 10^{-19}) (1.602\times 10^{-19})}{(7\times 10^{-10})^2}[/tex]
[tex]= 4.714\times 10^{-10} \ N[/tex]
Now,
The acceleration of proton will be:
→ [tex]F = ma[/tex]
[tex]= m_p a_p[/tex]
or,
→ [tex]a_p = \frac{F}{m_p}[/tex]
[tex]= \frac{4.714\times 10^{-10}}{1.67\times 10^{-27}}[/tex]
[tex]= 2.823\times 10^{17} \ m/s^2[/tex]
and,
The acceleration of electron will be:
→ [tex]F = m_c a_c[/tex]
or,
→ [tex]a_e = \frac{F}{m_e}[/tex]
[tex]= \frac{4.714\times 10^{-10}}{9.11\times 10^{-31}}[/tex]
[tex]= 5.175\times 10^{20} \ m/s^2[/tex]
Thus the above answer is correct.
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The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?
Answers
Answer:
The value is [tex]Q_{net} = 1.239 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The electric flux is [tex]\Phi = 1.4*10^{5} \ N\cdot m^2/C[/tex]
Generally the net charge is mathematically represented as
[tex]Q_{net} = \Phi * \epsilon_o[/tex]
Here [tex]\epsilon_o[/tex] is the permetivity of free space with value
[tex]\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2[/tex]
So
[tex]Q_{net} = 1.4*10^5 * 8.85*10^{-12}[/tex]
=> [tex]Q_{net} = 1.239 *10^{-6} \ C[/tex]
In the absence of government, what would determine the way people act towards each other?
Answers
Answer:
In the absence of government, what would determine the way people act towards each other is the need to acquire means of survival such as food or shelter.
Thus, since the government regulates the rights and obligations of citizens to guarantee equal access to essential services and goods for life, in the event of the disappearance of the state as a form of social organization, people would tend to act selfishly. to provide itself with those goods and services.
Society would then return to a state of nature, where man competes with his peers for access to resources. So the need for those resources would ultimately determine the way humans relate to each other.
Throughout the absence of regulation, the necessity to gain means of subsistence, which includes extra help, would decide how individuals interact with one another.
Absence of Government:
As a consequence, while the organization governs individuals' rights and duties purpose of providing equitable access to vital services and products for life, if the community as more than just a form of social organization disappears, individuals might likely behave selfishly to offer such commodities.
The community would therefore revert to its natural condition, with man competing with equal fellows for distribution of wealth. As a result, the necessity for such resources would eventually decide how humans interact with one another.Thus the response above is right.
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A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed
Answers
Answer:
6779.7m/s
Explanation:
Using
GMm/(Re +h)² = mv²/ (Re+h)
So making v subject we have
V= √GM/Re+h
So
V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3
V= 6779.7m/s
Note h = height of satellite
Re= radius of the earth
M = mass of the earth
A toy police car moves across the room in 10 seconds. The distance the car traveled is
450 centimeters. At what speed did the car travel?
Answers
Answer:
45cm/s
Explanation:
If the distance traveled is 450 centimeters we can assume the speed is 45cm/s by taking the distance and dividing by the time, in this case that is 450 and 10
so our answer would be 45cm/s
what magnetic field strength will allow the electron to pass between the plates without being deflected
Answers
Complete Question
An electron travels with speed 2.0 X 10^7 m/s between two parallel charged plates. The plates are separated by 2.0 cm and are charged by a 400V battery. What magnetic field strength and direction will allow the electron to pass between the plates without being deflected.?
Answer:
The value [tex]B = 0.001 \ T[/tex]
Explanation:
From the question we are told that
The speed of the electron is [tex]v = 2.0 *10^{7} \ m/s[/tex]
The voltage is [tex]V = 400 \ V[/tex]
The distance of separation is [tex]d= 2.0 \ cm = 0.02 \ m[/tex]
Generally the electric field is mathematically represented as
[tex]E = \frac{V}{d }[/tex]
=> [tex]E = \frac{400}{0.02 }[/tex]
=> [tex]E = 20000 V/m[/tex]
Generally for the electron to pass without deflection then
[tex]F_B = F_E[/tex]
Where [tex]F_B[/tex] is the maximum magnetic force acting on the electron which is mathematically represented as
[tex]F_B = evBsin (\theta )[/tex]
Since we are considering maximum magnetic field then [tex]\theta = 90^o[/tex]
=> [tex]F_B = evB[/tex]
And
[tex]F_E[/tex] is the electric force on the electron which is mathematically represented as
[tex]F_E = e * E[/tex]
Here e is the charge on the electron with the value [tex]e = 1.60 *10^{-19} \ C[/tex]
=> [tex]F_E = 1.60*10^{-19} * 20000[/tex]
=> [tex]F_E = 3.2*10^{-15} \ N[/tex]
So
[tex]3.2*10^{-15} = q* v B[/tex]
=> [tex]B = \frac{3.2*10^{-15}}{ 2.0*10^7 * 1.6*10^{-19}}[/tex]
=> [tex]B = 0.001 \ T[/tex]