1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de aplicación es el mismo borde de dicha rueda provocando un impulso en el sentido de las agujas del reloj. Solución:

Answers

Answer 1

Answer:

τ= F r     into the blade

Explanation:

The moment of a force is defined by

         τ = F x r

where the bold indicates vectors

Let us write in the expression in magnitude

         τ = F r sin θ

in our case the force is tangent to the wheel therefore the angle between F and the radius is 90º, and the sin 90 = 1

       τ= F r

The direction of τ can be used by the rule of the right hand, the fingers curve in the direction of the torque when advancing from the force to the radius and the thumb points in the direction of the torque.

In this case, for a clockwise rotation, the fingers are curved in the direction and the thumb points into the blade, this is the direction of the τ.

TRASLATE

El momento de una fura es definido por

         τ = F x r

donde la negrillas indican vectores

Escribamos en ta expresión en magnitud

          τ = F r sin θ

en nuestro caso la fuerza es tangente a la rueda por lo tanto el angulo entre F y el radios es 90º, y el sin 90=1

        τ = F r

la dirección de tau la podemos  usar la regla de la mano derecha, los dedos curva en la dirección del torque al avanzar dese la fuerza al radio y el pulgar apunta en la dirección del torque.

En este caso para un giro en sentido horario los dedos se curvan ente sentido y el pulgar apunta hacia dentro de lla hoja, esta es la dirección del troque


Related Questions

Which is one use for radioactive isotopes? sanitation architecture meteorology archaeology

Answers

Answer:

Archaeology

Explanation:

Radioisotopes are radioactive atoms of an element in which their atoms contain excess energy making them unstable. When broken down they become more stable releasing radiations.

Carbon 14 is a radioactive isotope that is used in archaeology to study and estimate the lifespan and age of organic materials such as wood, leather. Carbon 14 can be used to estimate the ages of materials up to 50000 to 60000 years.

Answer:

archaeology

Explanation:

What is the most accurate and precise method to measure the thickness of a coin? ​

Answers

Answer:

The most accurate and precise method to measure the thickness of a coin would be by a micrometer screw guage.

The most accurate and precise method to measure the thickness of a coin is with the help of a screw gauge.

What is a unit of measurement?

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.

It is determined by convention or regulation.

Any additional quantity of that type can be stated as a multiple of the measurement unit.

The smallest length that a screw gauge can measure is called its least count.

Thus, if we have to measure the thickness of a coin using a screw gauge to measure a coin is the most exact and precise approach available.

Learn more about the unit of measurement here, refer to the link given below;

brainly.com/question/12629581

#SPJ2

An element is highly conductive, highly reactive, soft, and lustrous. The element most likely belongs to which group?(1 point)

transition metals
noble gases
metalloids
alkali metals

Answers

Answer:

Alkali metals

Explanation:

Elements in this group are highly reactive, soft, lustrous and highly conductive.

An element which is highly conductive, highly reactive, soft, and lustrous is most likely an alkali metal.

Alkali metals are in group 1 of the Periodic table which means that they have only a single valence electron.

This causes them to be soft and highly reactive because:

The single valance electron leads to weak bonds amongst the element's atoms which makes them softThe elements want to lose the single valance electron so as to become stable so they will react with other elements to give away the electron.

Examples of alkali electrons include:

Lithium Sodium Potassium etc

In conclusion therefore, alkali metals are highly reactive and soft and so the element described above is most likely an alkali metal.

Find out more at https://brainly.com/question/18722874.

Which value would complete the last cell?

(1 point)

3.0

100.0

25.0

4.0

Answers

Answer:

4.0

Explanation:

The following data were obtained from the question:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as

Force (F) = mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain th acceleration of the body as follow:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

F = ma

20 = 5 x a

Divide both side by 5

a = 20/5

a = 4 m/s²

Therefore, the value that will complete the last cell in the question above is 4.

Air contains 78.08% nitrogen, 20.095% oxygen, and 0.93% argon. a sample of air occupies 8 l at 273 k and applies a pressure of 2.45 atm to its container. the sample of air is heated to 550 k, at which time it takes up 11.8 l. what is the partial pressure of nitrogen after the air has been heated

Answers

Answer:

the partial pressure of nitrogen after the air has been heated is 2.61atm

Explanation:

Using combined gas law which is the combination of Boyle's Law and Charles' Law, and it gives The relationship between pressure, volume, and absolute temperature

PV/T= K

P1₁V₁/T₁=P₂V2₂/T₂

P₂=final pressure= ?

P₁= initial pressure=2.45 atm

.T₁= initial temperature= 273k

T₂= final temperature= 550 K,

We can make P₂ subject of the formula then we have

P₂=P₁V₁T₂/T₁T₂

=( 2.45×8×550)/(273×11.8)

P2=3.35atm

Now we can calculate the partial pressure of N₂

N₂= 3.35×(78.08/10)

=2.61atm

Therefore, the partial pressure of nitrogen after the air has been heated is 2.61atm

1-A boy rolls a toy car across a floor with a velocity of 3.21 m/s. How long does it take the car to travel a distance of 4.50 m?
A-0.71s
B-1.40s
C-2.9s
D-14s
2-A girl heads out for a jog and runs at 2.95 m/s, due North, for 3600 s. How far did she run?
A-0.194 x 10^-4
B-1220m
C-5240
D-10620
3-A car is traveling South on I-85. It travels between two exits that are 5.40 km apart in 4.85 minutes. What is the average velocity of the car in m/s?
A-8.42m/s
B-12.8m/s
C-14.9m/s
D-18.6m/s
4-An airplane takes 1.30 hours to travel to an airport north of Atlanta. If the average speed of the plane is 134 m/s, what is the plane's displacement as measured from Atlanta?
A-129,324m=129,000m rounded
B-356,247m=356,000m rounded
C-498,782m=499,000m rounded
D-627,120m=627,000m rounded
5-How long does it take a sailboat traveling 18.0 m/s to go 15.7 km west?
A-15,000s
B-872s
C-594s
D-326s

Answers

B 4.5/3.21 = 1.4
B 3600/2.95 = 1220
D 5.4*1000=1113.4/60=18.6
D 60*1.3=78*60=4,680*134=627,120
B 15.7*1000=15,700/18=872

Select the correct answer. x y 2.5 6.25 9.4 88.36 15.6 243.63 19.5 380.25 25.8 665.64 The table lists the values for two parameters, x and y, of an experiment. What is the approximate value of y for x = 4? A. 11 B. 16 C. 24 D. 43

Answers

Answer: B. 16

Explanation:

The given table:

x y

2.5 6.25

9.4 88.36

15.6 243.63

19.5 380.25

25.8 665.64

Here, we observed that value of y is the square value of x.

i.e. [tex]y=x^2[/tex]  [For example 2.5²=6.25, 9.4²=88.36, 15.6²=243.63]

Put x=4, we get

[tex]y=4^2=16[/tex]

Hence, the approximate value of y for x = 4 is 16.

So, the correct option is B. 16 .

Answer:

The answer is A.

Explanation:

What is the difference between virtual images produced by concave, plane, and convex mirrors?
What does the negative sign in the value of magnification produced by a mirror indicate about
an image?

Answers

Answer:

Explanation:

A concave mirror is a curved mirror that is coated outwards. The outer part of the mirror is always coated. The nature of image formed by an object placed in front of a concave mirror can be real or virtual depending on the distance of the object on the axis from the mirror. The only time the object produces a virtual image is when it is placed between the focus and the pole of the mirror. The virtual image formed is a "MAGNIFIED and upright image"

For a convex mirror, the inner part is always coated and the nature of the image formed by the object doesn't depend on the distance between the image and the mirror. No matter where the object is placed, the image formed will always be virtual, upright and DIMINISHED. This means that magnification is always less than 1.

For a plane mirror, the nature of the image produced by a plane mirror also virtual because it is always formed behind the mirror. The size of the image formed is always THE SAME as that of the object. This means that the magnification is always equal to 1.

a) In summary, the difference between virtual images produced by concave, plane, and convex mirrors is that virtual images produced by concave mirror are MAGNIFIED, virtual images produced by plane mirror are THE SAME SIZE as that of the object and virtual images produced by convex mirrors are always DIMINISHED.

b) Magnification is defined as the ratio of the image distance to the object distance. Mag = v/u

Note that object distances are always positive, hence it is only the image distance that can either be positive or negative which in turn affects the magnification causing it to be positive or negative.

Negative image distance shows that the image is virtual while positive image distance shows that the image is real.

A negative magnification therefore shows that the nature of the image is a virtual image.

What is the god particle

Answers

Answer:

Explanation:

hThe media calls the Higgs boson the God particle because, according to the theory laid out by Scottish physicist Peter Higgs and others in 1964, it's the physical proof of an invisible, universe-wide field that gave mass to all matter right after the Big Bang, forcing particles to coalesce into stars, planetsig

the mass of an object is 45 kg and it has a density of 5 gram per centimetre cube what is the volume ​

Answers

Density = Mass/Volume

=> 5g/cm³ = 45kg/Volume

=> 0.005kg/cm³ = 45kg/Volume

=> Volume = (cm³×45kg)/0.005kg

=> Volume = 9000kg/cm³

5 grams fits into 45 kg 9,000 times.

Since each 5 grams occupies 1 cm³, 9,000 little packages of 5 grams must occupy 9,000 cm³ .  (That's 9 liters.)

On which factor mechanical advantage of simple machine depend on? Please help me and perfect answer will be brainlest answer. ​

Answers

Answer:

The factor that determines the mechanical advantage (or ideal mechanical advantage (IMA) - in the absence of frictional forces) in a simple machine is the ratio perpendicular distance of the applied force to the fulcrum to the perpendicular distance of the load to the fulcrum

The mechanical advantage can therefore by larger than 1 (requiring less force per load), or equal to 1 (effort equal to load) or less than 1( effort more than load)

Explanation:

Help please with question 2bii

The one that starts with calculate the average ....

Answers

Answer:

add text fully or atleast add book name edition . solution is in picture.  chk pictures ignore b part

Explanation:

difference between effort distance and load distance​

Answers

Answer:

Lever systems are simple machines that change or increase the input force that we apply to the load. The lever provides us with some mechanical...

Answer:

● Effort arm or Effort distance (ED): The perpendicular distance from the fulcrum to the point of effort is called effort arm.

● Load arm or Load distance (LD): The perpendicular distance from the fulcrum to the point of load is called load arm.

On a frictionless air track, a 0.30 kg glider moving at 0.40m/s to the right collides with a stationary 0.80kg glider moving at 0.15 m/s to the left. The collision is cushioned by a bumper made of perfectly elastic spring steel. a. What is the velocity of each glider after the collision? b. What is the minimum amount of total kinetic energy during the collision? c. Where is the missing energy?

Answers

Answer:

Explanation:

It is the case of perfectly elastic collision . So we shall apply formula of velocity after collision as follows .

Let  m₁ and m₂ be the mass colliding with velocity u₁ and u₂ and their velocity become v₁ and v₂ after collision .

[tex]v_1=\frac{(m_1-m_2)u_1 }{m_1+m_2)} +\frac{2 m_2u_2}{(m_1+m_2)}[/tex]

Putting the values

[tex]v_1=\frac{ (.30-.80).40 }{( .30+.80)} +\frac{2\times .80\times(-.15) }{(.30+.80 )}[/tex]

= - 0.4 m /s

So direction of .30 kg mass will be reversed .

[tex]v_2=\frac{ ( m_2-m_1) u_2 }{( m_1+m_2)} +\frac{2 m_1u_1}{(m_1+m_2)}[/tex]

putting the values

[tex]v_2=\frac{ ( .80-.30)(-.15) }{( .30+.80)} +\frac{2 \times.30\times.40}{(.30+.80)}[/tex]

= .15 m /s

The direction of .80 kg will become from left to right ie its direction will be reversed .

b ) Minimum amount of kinetic energy will be at the position when they move with common velocity

common velocity

v = .3 x .4 - .8 x .15 / (.3 + .8)

= 0

c )

Missing energy is stored as elastic potential energy in the spring .

A physical inventory on December 31 shows 3500 units on hand. Bonita sells the units for $15 each. The company has an effective tax rate of 20%. Bonita uses the periodic inventory method. The weighted-average cost per unit is

Answers

The answer would be 10,500 be cause you multiply 3500 times 15 and you get 52500 the you multiply that by .20 and you get 10,500.

Calculate the average kinetic energy of molecules of a gas at a temperature of 18 ° C

Answers

Answer:

6.0×10⁻²¹ J

Explanation:

KE = 3/2 kT,

where KE is average kinetic energy per molecule,

k is the Boltzmann constant,

and T is absolute temperature.

KE = 3/2 (1.38×10⁻²³ J/K) (18 + 273.15) K

KE = 6.0×10⁻²¹ J

Answer:

The answer is 6.0×10⁻²¹ J , because KE = 3/2 kT,  where KE is average kinetic energy per molecule,  k is the Boltzmann constant,  and T is the absolute temperature.

KE = 3/2 (1.38×10⁻²³ J/K) (18 + 273.15) K

KE = 6.0×10⁻²¹ J

Does the surface tension of water affect the rate of evaporation? If so, would adding a surfactant speed up evaporation?

Answers

Answer:

The evaporation time gradually increased with the increase in surfactant concentration, i.e., from water to the concentration level of 0.005%. Furthermore, the evaporation time is significantly reduced, even lower than that of water containing relatively high concentrations from 0.01% to 0.1%.

6. 15. A boy takes 5 seconds to reach each point from ‘A’ to ‘B’, ‘B’ to ‘C’ and ‘C’ to ‘D’ as
shown in the diagram. If AB = BC = CD = 20 m then which of the following information is
correct when the boy reaches point D from point A via BC?

Answers

Explanation:

Could you also show the diagram

What is the electric force acting between two charges of 0.0072 C and -0.0060 C that are 0.0040 m apart?

Answers

Answer:

Fe = 2.4 × 10^10 N

Explanation:

Given the following :

q1 = charge 1 = 0.0072 C = positive direction

q2 = charge 2 = 0.0060 C = - ve direction

r = distance = 0.0040

Using the relation :

Fe = K(q1q2) /r^2

Where K = columb's constant = 9×10^9 Nm^2/C^2

Fe = electric force

Fe = 9×10^9(0.0072 * 0.0060) / 0.0040^2

Fe = [9×10^9 (0.0000432)] / 0.000016

Fe = 388,800 / 0.000016

Fe = 24300000000

Fe = 2.43 × 10^10 N

Earth orbits 1 AU from the Sun, and the Oort cloud extends from about 10,000 to 100,000 AU from the Sun. If you represent Earth’s orbit around the Sun with a paper plate 4 inches in radius, how far away will the inner edge of the Oort Cloud be? The outer edge? Express your answers in miles.

Answers

Explanation:

Earth’s orbit around the Sun represented as :

1 AU = 4 inches

Therefore,

Inner edge of the Oort Cloud represented as :

10,000 AU = 40,000 / 63360 = 0.631 miles

Outer edge of the Oort Cloud represented as:

100,000 AU = 400,000 / 63360 = 6.31 miles

A metal ring 4.30 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpendicular to the magnetic field. These magnets produce an initial uniform field of 1.12 T between them but are gradually pulled apart, causing this field to remain uniform but decrease steadily at 0.230 T/s.(a) What is the magnitude of the electric field induced in the ring? (b) In which direction (clockwise or counterclockwise) does the current flow as viewed by someone on the south pole of the magnet?

Answers

Answer:

A)0.00966 N/C

B) counterclockwise direction

Explanation:

We are given;

Diameter of the metal ring; d = 4.3 cm

Radius;r = 2.15 cm = 0.021- m

Initial magnetic field, B = 1.12 T

Rate of decrease of the magnetic field;dB/dt = 0.23 T/s

Now, as a result of change in magnetic field, an emf will be induced in it. Thus, , electric field is induced and given by the formula :

∫E•dr = d/dt∫B.A •dA

This gives;

E(2πr) = dB/dt(πr²)

Gives;. 2E = dB/dt(r)

E = dB/dt × 2r

We are given;

E = 0.23 × 2(0.021)

E = 0.00966 N/C

The magnitude of the electric field induced in the ring has a magnitude of 0.00966 N/C

B) The direction of electric field will be in a counterclock wise direction when viewed by someone on the south pole of the magnet

Name two safety measures commonly used in electric circuits and
appliances​

Answers

Answer:

Here are two security mechanisms that are widely used in electrical circuits as well as appliances.

Explanation:

Electric Fuse: A sequence, an electrical fuse remains attached which preserves the connection from overburdening as well as avoids short-circuiting. Proper apparatus throughout all electrical circuits whereby any existing leakage in such an electrical system is passed to the surface while individuals who use the equipment are not getting the shock.

difference Between Newton's first law and third law of motion​

Answers

Newton first law state that anything in motion or rest will remain in motion or in rest until an external force is applied

Newton third law of motion state that every action have equal and opposite reaction

Answer:

Newton's laws of motion relate an object's motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. ... In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

mark me brain list please

Helpppp!!!ASAP!! THANK YOUUUU!

Answers

Answer:

F = 9.675Hz

Explanation:

pls for certain reasons let us make

wavelength = $frequency = FV = velocity

3 loops : 6$/4 = L

6$/4 = 2

$ = 4/3 = 1.333

V = F x $

F = V/$

F = 12.9/1.333 = 9.675Hz

F = 9.675Hz

Determine the magnitude of the force that must be applied to a wooden block whose weight has a magnitude of 8N, so that it acquires an acceleration of 0.5 m / s²

Answers

Answer:

0.4 N

Explanation:

The weight mg is 8 N, so the mass is:

mg = 8 N

m = 8 N / g

m = 8 N / (10 m/s²)

m = 0.8 kg

The force needed to accelerate it to 0.5 m/s².

F = ma

F = (0.8 kg) (0.5 m/s²)

F = 0.4 N

What is common between the quantities of area, density and speed?​

Answers

Answer:

They are all s

calar quantities

they are all s, calar quantities

Which class of lever has all advantages of lever

Answers

Answer:

Helo ....

so this answer would be First class levers

becoz...

First-class levers have a considerable practical advantage over the other types of levers. They convert a downward moving force into a lifting force

is it possible to mark it brainliest <3

Look at the diagram below. The value of equivalent resistor is: A. 4 Ω B. 6 Ω C. 8 Ω D. 10 Ω

Answers

Answer:

R=4Ω

Explanation:

R1 and R3 are parrallel

so we have : R=R1*R2/R1+R2

R=6*3/6+3

R=18/9

R=2Ω

R2 and 2Ω are in series,so we have

R=R2+2

R=2+2

R=4Ω

Will mark as BRAINLIEST.......

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation 4x³+3x²-5x+2 , where x is in meters and t is in sec.
a)Find velocity of particle at i) t=2 sec ii) t=4 sec.
b) Find the acceleration of the particle at t=3 sec.

Answers

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

[tex]x=4t^3+3t^2-5t+2[/tex]

Where,

x is in meters and t is in sec

We know that,

Velocity,

[tex]v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5[/tex]

(a) i. t = 2 s

[tex]v=12(2)^2+6(2)-5=55\ m/s[/tex]

At t = 4 s

[tex]v=12(4)^2+6(4)-5=211\ m/s[/tex]

(b) Acceleration,

[tex]a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6[/tex]

Pu t = 3 s in above equation

So,

[tex]a=24(3)+6\\\\a=78\ m/s^2[/tex]

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²

someone can help me?
FORMACION DE IMÁGENES EN UN ESPEJO
1. Un objeto es situado frente a un espejo cóncavo, como se muestra en la figura
Con ayuda de los rayos notables, dibuja en donde se forma la imagen y responde
a) ¿Qué tipo de imagen es?:
b) ¿Qué dirección tiene?:
c) ¿Cuál es su tamaño?:
TRANSLATION:
FORMATION OF IMAGES IN A MIRROR
1. An object is placed in front of a concave mirror, as shown in the figure
With the help of the noticeable rays, draw where the image is formed and respond
a) What kind of image is it?:
b) What is your address?:
c) What is its size?:

Answers

When the object is placed at a further distance from the center of the mirror's curvature (twice the focal length), we will get a thumbnailposition of the image from the mirror; Between focus and center of curvature of the mirror (double focal length) picture description; real, inverted, mini

* This picture is to draw the rays, just replace the candle with an apple .

Do you want me to write it in Spanish to help you?? ^_^

I hope I helped you^_^

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