1) Find out the equivalent resistance.
2) find out all the current's in every resistors.
3) find out the voltage in resistor 1 and 4.

1) Find Out The Equivalent Resistance.2) Find Out All The Current's In Every Resistors.3) Find Out The

Answers

Answer 1

Answer:

1) 2.388ohms

2) R1 3.36A

R2 1.682A

R3 2.88A

R4 2.16A The current has 5.048A over all

3) Voltage in R1 is 3.36v

Voltage in R4 is 8.63v

Explanation:

1. Each of the resistance R1 and R2 are in parallel in series combination with R3 and R4 so we calculate

R1 and R2 which is 1×2÷(1+2)= 0.6667ohms

R3 and R4 which is 3×4÷( 3+4)= 1.71ohms

so the equivalent resistance is 0.667+ 1.71= *2.377ohms*

2. The overall current = voltage source ÷ total resistance

= 12÷ 2.377= 5.048Amps

so current in every resistor will be

current in 1ohms will be (2÷3)×5.048= 3.36Amps

current in 2ohms will be (1÷3)×5.048= 1.68Amps

current in 3ohms will be (4÷7)×5.048= 2.88amps

current in 4ohms will be (3÷7)× 5.048= 2.16amps

3. voltage in R1 is 0.667ohms × 5.048amps= 3.36v

voltage in R4 is 1.71ohms × 5.048amps= 8.63v


Related Questions

500 cm³ of water at 100°C is added to another 500 cm³ of water at a temperature of 30°C. Assuming no heat is lost to the surrounding, what is the final temperature of the mixture when thermal equilibrium is achieved?​

Answers

Answer: 35 degree Celsius

Explanation: Subtract both the temperatures And divide by two.

in a hyrdo electic power plant the moving water turns the turbine creating ____________ energy.

Answers

Answer:

....................

Explanation:

................

Answer:

Mechanical Energy

Explanation:

Mechanical energy is energy possessed by motion.  A hydroelectric power plant creates energy by motion.

A toy rocket travels at an initial velocity of 144 feet per second. The height of the rocket can be modeled by the function h(t)-144t-16t^2 where t is the time in seconds. When will the rocket return to the ground?

Answers

Answer:

t = 4.5 second

Explanation:

A toy rocket travels at an initial velocity of 144 feet per second. The height of the rocket can be modeled by the function as follows :

[tex]h(t)=-16t^2+144t[/tex]

t is time in seconds

We need to find the time when the rocket return to the ground.

When it reaches ground, h(t) = 0

So,

[tex]-16t^2+144t=0\\\\t(-32t+144)=0\\\\t=0\ \text{and} -32t+144=0\\\\t=0\ \text{and}\ t=4.5\ s[/tex]

So, at 4.5 second the rocket will return to the ground.

solve this questions please ​

Answers

Answer:

10.37×10³j

Explanation:

hope this helps you !!!

what is the mass of density=2 g/mL volume= 20mL?

Answers

Answer:

m = 40 g

Explanation:

d = m/V => m = d×V

m = 2g/ml×20ml

= 40 g

Which items in this image are electrically conductive? Check all that apply.

Answers

Answer: a and d

Explanation: A.) the power lines themselves

B.) the wooden pole that supports the lines

C.) the rubber soles on the worker’s boots

D.) the metal tools the worker uses

E.) the wooden ladder leaning against the lines

a second class lever needs less effort to lift a heavy load.why give reason​

Answers

Answer:second class lever needs less force to lift a load

Explanation: because the load is between the fulcrum/pivot point and the force. The fulcrum is far away from the force

Super fine 40-gauge copper wire has a diameter of only 0.080mm and weighs only 44.5/gkm. Suppose a spool of 40-gauge wire weighs 570.g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Answers

Answer:

[tex]Amount\ of\ wire\ used=\frac{M}{44.5\ g/km}[/tex]

mount of wire used=12.808989 Km

Amount of wire used=12808.989 m

Explanation:

Given Data:

Diameter of wire=d=0.080 mm=0.00008 m

Weight of wire per unit length=44.5 g/km

Spool weighs=M=570 g

Required:

Amount of wire used=L=?

Solution:

Formula is:

[tex]Amount\ of\ wire\ used=\frac{Spool\ weighs}{Weight\ per\ unit\ length}[/tex]

[tex]Amount\ of\ wire\ used=\frac{M}{44.5\ g/km}[/tex]

The above expression is mathematical model of finding how much wire is used. just put the Value of M we will get the answer.

[tex]Amount\ of\ wire\ used=\frac{570\ g}{44.5\ g/km}[/tex]

Amount of wire used=12.808989 Km

Amount of wire used=12808.989 m

A poster is 0.95m high and 1.0m wide how many digits follow the decimal point when the perimeter of the poster is expressed with the correct number of significant figures
A) zero digits
B) one digit
C)two digits
D)three digits

Answers

Explanation:

It is given that,

Length of the poster, l = 0.95 m

Breadth of the poster, b = 1 m

The poster is in the shape of rectangle. For a rectangular shape, perimeter is equal to :

P = 2(l+b)

P=2(0.95+1)

P=3.9 m

(b) One digits, P = 4 m

(c) Two digits, P = 3.9 m

(d) Three digits, P = 3.90 m

What is the average speed of a car that traveled 300 meters in 5.5 seconds?

Answers

Answer: 54.55 m/s

Explanation:

Distance = 300 m

Time = 5.5 s

Average Speed = Total Distance/Total Time

= 300/5.5

= 54.55 m/s

Hope this helped..

Black object are good at? ​

Answers

Explanation:

Absorbing heat from the sun rather than reflecting.

Select all the correct answers. In most cases, what happens to a liquid when it cools? Its density increases. Its density decreases. Its mass increases. Its mass decreases. Its volume increases. Its volume decreases.

Answers

Answer:

its density decrease

Explanation:

Explanation: As the molecules of a liquid are cooled they slow down. As the molecules slow down they take up less volume. Taking up less room because of the molecules lower energy causes the liquid to contract.

Answer:

A & F

Explanation:

As the liquid cools down, it means the temperature decreases the density of the liquid increases in most o the cases.

Now the volume is inversely proportional to the density of substance so density increases.


Which of the following is a helpful process in evaluating scientific claims? (2 points)

A.quoting statistics

B. Making Lists

C. Biased thinking

D. Critical thinking

Answers

Answer:

I think D. Critical thinking is the answer

D is the right answer

Mr. Ben drove from Town A to Town B. For the first 3 h, he traveled at an average speed of
60 km/h, and after that, he drove at another average speed of 70 km/h. If the distance
between Town A and B is 460 km, what was the total time for the whole journey?

Answers

Answer:

It’s 7 hours

Explanation:

You have to use the formula your teacher has given to you plug in the numbers then solve be sure to use a calculator made for physics it helps a lot :)

Highest molecular motion, highest kinetic energy, no forces of attraction, least dense packaging of molecules."Which state of matter is defined by this description?

Answers

Answer: Plasma

Explanation:

Plasma is a state of matter that consists of hot ionized gas. It should also be noted that plasma contains negatively charged electrons and positive ions.

Therefore, Highest molecular motion, highest kinetic energy, no forces of attraction, least dense packaging of molecules describes plasma.

A ball rolled at a velocity of 12 m/sec. After 36 seconds, it comes to a stop. What is the acceleration of the ball? Round to the nearest tenth.

Answers

Solving the problem mathematically,

Initial velocity of the ball 12m/s

Final velocity 0m/s

Travel time 36s

Assuming the velocity follows a straight line, then the slope of the curve is equal to the rate of change of velocity (acceleration)

ie taninv(dv/dt) since it is linear taninv(12/33)= 0.33 m/s^2 deceleration.

If in case the velocity doesn’t follow the linear path acceleration= d(velocity profile)/dt. ie the first order differentiation of velocity is the acceleration.

Una bala de cañón se dispara horizontalmente con una velocidad inicial de 120m/s y un ángulo de elevación de 35°.Encuentra:a)su alcance maximo,b)si altura máxima,c)si tiempo maximo de vuelo

Answers

Answer:

a) x = 1353,2 m.

b) [tex]y_{max}[/tex] = 236,9 m [/tex]

c) [tex]t_{v} = 13,8 s[/tex]

Explanation:

a) El alcance máximo se puede calcular usando la siguiente ecuación:

[tex] y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}} [/tex]   (1)

En donde:

y: es la altura final = 0

[tex]y_{0}[/tex]: es la altura inicial = 0

x: es el alcance

θ: es el angulo respecto a la horizontal = 35°  

[tex]v_{0}[/tex]: es la velocidad inicial = 120 m/s

g: es la gravedad = 10 m/s²

Resolviendo la ecuación (1) para x, tenemos:

[tex] x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(35)*(120 m/s*cos(35))^{2}}{10 m/s^{2}} = 1353,2 m [/tex]          

El alcance máximo es 1353,2 m.

b) La altura máxima es:

[tex] y_{max} = \frac{v_{0}_{y}^{2}}{2g} = \frac{(v_{0}sen(\theta))^{2}}{2g} = \frac{(120 m/s*sen(35))^{2}}{2*10 m/s^{2}} = 236,9 m [/tex]

Entonces, la altura máxima es 236,9 m.                                       

c) El tiempo de vuelo es el siguiente:

[tex]t_{v} = \frac{x}{v_{0}cos(\theta)} = \frac{1353,2 m}{120 m/s*cos(35)} = 13,8 s[/tex]

Por lo tanto, el tiempo de vuelo es 13,8 s.

Espero que te sea de utilidad!

(PLEASE HELP!!) Identify two types of motion where an object's speed remains the same while it continues to change direction.

Answers

The 2 types of motions would be linear motion. Linear motion follows a straight linear path. Rotatory motion is also another type of motion. A rotatory motion is a motion along a curved path that may be planar or in 3 directions.

1) An astronaut has a mass of 40Kg. Calculate his weight on earth if Gravity (g) = 10m/s^2.
2) The same astronaut goes to the International Space Station. Here the gravitational pull is equal to .5 m/s^2. Calculate his weight.
3) Our astronaut friend is assigned to study a neutron star. He travels to the surface using a special suit. Here the gravitational force is terrible at 150m/s^2 What is the astronaut’s weight?

Answers

Answer:

The formula is W=mg.

1.) W=40×10=400.

2.)W=40×5=200.

3.)W=40×150=6000.

A ship sets out to sail to a point 154 km due north. An unexpected storm blows the ship to a point 72 km due east of its starting point. How far must it now sail to reach its original destination

Answers

Answer:

170km

Explanation:

If a ship sets out to sail to a point 154 km due north and an unexpected storm blows the ship to a point 72 km due east of its starting point, then the ships distance from the original destination can be gotten by finding the displacement of the ship and this can be gotten by using pythagoras theorem.

Let D be the unknown displacement

According to the theorem;

D² = 154² + 72²

D² = 23716 + 5184

D² = 28900

D = √28900

D = 170km

This means that the ship must now sail a distance of 170km for it to reach its original destination.

A child rides a wagon down a hill. Eventually, the wagon comes to a stop. Which is most responsible for causing the wagon to stop

Answers

Answer:

well, the hill isn't constantly going down hill, there's an ending point or goes back up hill making a v/u shape or there's nothing helping the wagon being pushed or pull currently

Explanation:

A wedge is a double inclined plane. why?​

Answers

Answer:

A wedge is a double inclined plane. ... When a wedge is moved, it applies force on an object. It applies an output force greater than your input force. In the case of an axe, the output force is so great that it causes wood to split.

HELP ME PLEASE !!!!!!!!!!!!!!!!!

Answers

Answer:

Option D. 6.1 m/s²

Explanation:

We'll begin by calculating the acceleration due to gravity in each case. This is illustrated below:

1. For Rock:

Mass (m) = 20 g

Force (F) = 0.1224 N

Acceleration due to gravity (g) =?

Next, we shall convert 20 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

20 g = 20/1000

20 g = 0.02 kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.02 kg

Force (F) = 0.1224 N

Acceleration due to gravity (g) =?

F = mg

0.1224 = 0.02 × g

Divide both side by 0.02

g = 0.1224/0.02

g = 6.12 m/s²

2. For Grain of sand:

Mass (m) = 0.8 g

Force (F) = 0.00501 N

Acceleration due to gravity (g) =?

Next, we shall convert 0.8 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

0.8 g = 0.8/1000

0.8 g = 0.0008 kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.0008 kg

Force (F) = 0.00501 N

Acceleration due to gravity (g) =?

F = mg

0.00501 = 0.0008 × g

Divide both side by 0.0008

g = 0.00501/0.0008

g = 6.26 m/s²

3. For Metal bolt:

Mass (m) = 79 g

Force (F) = 0.4871 N

Acceleration due to gravity (g) =?

Next, we shall convert 79 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

79 g = 79/1000

79 g = 0.079kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.079 kg

Force (F) = 0.4871 N

Acceleration due to gravity (g) =?

F = mg

0.4871 = 0.079 × g

Divide both side by 0.079

g = 0.4871/0.079

g = 6.17 m/s²

From the above calculation we obtained the following values for acceleration due to gravity (g):

Object >>>> Acceleration due to gravity

Rock >>>>> 6.12 m/s²

Sand >>>>> 6.26 m/s²

Metal >>>>> 6.17 m/s²

Thus, closest approximation of the acceleration due to gravity of the planet is 6.1 m/s²

How much time will have passed by the time a sample of an isotope has decayed to 6.25% of its original mass if the half-life is 15 days? 45 days 60 days 75 days 30 days

Answers

Answer:

60 days.

Explanation:

Let the original mass (N₀) = 1 g

Amount remaining (N) = 6.25% of its original mass

= 6.25% × 1

= 6.25/100 × 1

= 0.0625 g

Half life (t½) = 15 days

Time (t) =?

Next, we shall determine the rate of decay. This can be obtained as follow:

Decay constant (K) = 0.693/ half life

K = 0.693 / t½

Half life (t½) = 15 days

Decay constant (K) =?

K = 0.693 / t½

K = 0.693 / 15

K = 0.0462 / day

Finally, we shall determine the time taken for the sample of the isotope to decay to 6.25% of its original mass.

This can be obtained as follow:

Original amount (N₀) = 1 g

Amount remaining (N) = 0.0625 g

Decay constant (K) = 0.0462 / day

Time (t) =?

Log (N₀/N) = Kt/2.3

Log (1/0.0625) = 0.0462 × t / 2.3

Log 16 = 0.0462 × t / 2.3

1.2041 = 0.0462 × t /2.3

Cross multiply

0.0462 × t = 1.2041 × 2.3

Divide both side by 0.0462

t = (1.2041 × 2.3)/0.0462

t = 59.9 ≈ 60 days

Therefore, the time taken for the sample of the isotope to decay to 6.25% of its original mass is 60 days

354 cm + 64565 mm = ______________m?

Answers

Answer:

68.105m

Explanation:

Convert to meters. So,

3.54 + 64.565 = 68.105

A man dropped a dime in a wishing well , he heard it 5 sec later ..Find distance traveled if moving at 10 m/s 2

Answers

Answer:

The distance traveled is 109.58 m

Explanation:

The Speed of sound in air = 344 m/s

Let the time in which the dime dropped by the man reach an impact in the well = t₁

Let the time in which the sound travel from the well to the man = t₂

Then

1/2× 10 × t₁² = 344 × t₂ which gives;

5 × t₁² = 344 × t₂.........................(1)

Also the total time before the man heard the dime = t₁ + t₂ = 5

Therefore;

 t₂ = 5 - t₁

Substituting the value of t₂ in equation (1), we have;

5 × t₁² = 344 × (5 - t₁)

5·t₁² + 344·t₁ - 1720 = 0

Using the quadratic formula, we have;

[tex]x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex]

Which gives;

[tex]t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 5\times (-1720)}}{2\times 5}[/tex]

t₁ = 4.68 s or -73.48 s

Therefore, with the positive value for t₁ = 4.68 s, we have

The distance = 1/2× 10 × 4.68² = 109.58 m

The distance traveled = 109.58 m.

A sample of 2 moles of an ideal diatomic gas experiences a temperature increase of 60 K at constant volume. (a) Find the increase in internal energy if only translational and rotational motions are possible. 8.73 103 J (b) Find the increase in internal energy if translational, rotational, and vibrational motions are possible. 0.01222 (c) What fraction of the energy calculated in (b) is translational kinetic energy?

Answers

Answer:

A. To find increase in internal energy

We use

CV= f/2* R

=20.77J/molK

So change in internal energy is

nCvdt

So substituting

= 2 x 20.77x 60K

= 2493J

B.

We know that molar specific heat increase by R/2

So CV= (f/2+1)R

Which is 29.1J/milk

So

Increase in internal energy will be

nCvdt

= 2* 29.1*60

= 3490.2J

C. the translational energy is 3/2R

And the total molar specific heat capacity is 7/2R

So the fraction of energy in b due to K.E will be

3/7 * 3490.2

=1495.8J





One of the descriptions below is from the perspective of anatomical study, the rest are from a physiological perspective. Select the description below that comes from
an anatomical perspective

Answers

Answer:

The innermost lining of the lungs is composed primarily of thin tissue cakes simple squamous epithelium.

Explanation:

car travels 80 meters due north in 12 seconds then the car turns around and travels 30 Mi do South in 4 seconds calculate the average speed and average velocity of the car during this 60-second interval use guess method​

Answers

Answer:

1) 3.1 m/s

2) 7 m/s

Explanation:

Distance due north = 80 m

Distance due south = 30 m

Distance between north and south = (80 - 30) m = 50 m

Total time = (12 + 4) sec = 16 sec

1) Average speed = 50/16 = 3.1 m/s

2) Average velocity = Total distance/total time = (80 + 30) m/16 s = 110/16 = 7 m/s

Which statements are included in the kinetic theory of matter? Select all that apply.

Answers

Answer:

There is empty space between matter's particles.

Matter's particles are in constant random motion or vibration.

Matter is made of small particles.

Explanation:

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