Answer:
1. 1/6
2. 1/6
Step-by-step explanation:
Let A be the event that the sum of the two die is 6 and B be an event that the green die is either 4 or 1.
The conditional probability will be given by P (A/B) = P (A∩B)/ P (B).
Now the total sample space consists of 36 outcomes .
And to find (A∩B) we need to find the outcomes in which green die is either 4 or 1 and the sum of the two die is 6.
So when green is 1 red must be 5
So when green is 4 red must be 2
So there are two ways in which green die is either 4 or 1 and the sum of the two die is 6.
Therefore the probability of (A∩B)= P (A∩B)= 2/36= 1/18
Now we find the probability of green die having 4 or 1
So when green is 4 red can have all the numbers from 1- 6
And when green is 1 red can have all the numbers from 1- 6
The total number would be 12 .
So probability of green die having 1 or 4 is given by = P (B)= 12/36
Now the conditional probability = P (A/B) = P (A∩B)/ P (B)=1/18/ 1/3
= 3/18= 1/6
2. Similarly we find the conditional probability of the two die when the red one is 6, given that the sum is 11.
When red is 6 the green must be 5 to get 11. So the probability
=P (A∩B)= 1/36
Now we find the probability of red die having 6 =P(B)= 6/36
Now the conditional probability = P (A∩B)/P(B) = 1/36/ 6/36= 1/6
Answer 1:
Let A be the event that the sum of the two die is 6 Let B be an event that the green die is either 4 or 1.
Conditional probability Formula :
P (A/B) = P (A∩B)/ P (B).
Total sample space=36 outcomes
Conditions are :
So when green is 1 red must be 5 So when green is 4 red must be 2 So there are two ways in which green die is either 4 or 1 and the sum of the two die is 6.
The probability of (A∩B)= P (A∩B)= 2/36= 1/18
Now we find the probability of green die having 4 or 1
When green is 4 red can have all the numbers from 1- 6
And when green is 1 red can have all the numbers from 1- 6
Total number = 12
P (B)= 12/36
Therefore, conditional probability = P (A/B)
P (A/B) = P (A∩B)/ P (B) P (A/B)=1/18/ 1/3 P (A/B)= 3/18 P (A/B)= 1/6
The conditional probability of the indicated event when two fair dice are rolled will be 1/6.
Answer 2:
Let A be the event that the sum of the two die is 6 Let B be an event that the green die is either 4 or 1. The sum is 11.
Condition :
When red is 6 the green must be 5 to get 11.
P (A∩B)= 1/36
The probability of red die having 6 =P(B)= 6/36
The conditional probability= P (A∩B)/P(B)
P (A∩B)/P(B) = 1/36/ 6/36P (A∩B)/P(B)= 1/6The conditional probability of the indicated event when two fair dice are 1/6.
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Length of tangent line - geometry please help
Answer:
12
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
PC * PA = PB^2
(PA+AC) * PA = PB^2
(4+32) * 4 = PB^2
36*4 = PB^2
144 = PB^2
Taking the square root of each side
sqrt(144) = sqrt(PB^2)
12= PB
Answer:
a
Step-by-step explanation:
Given a tangent and a secant to a circle from an external point, then
The square of the tangent is equal to the product of the external part and the whole of the secant , that is
PB² = PA × PC = 4(4 + 32) = 4 × 36 = 144 ( take square root of both sides )
PB = [tex]\sqrt{144}[/tex] = 12 → a
The first common multiple of two number is 6. What is their fourth common multiple?
Answer:
4th multiple = 24
Step-by-step explanation:
Given
Let the two numbers be represented by m and n
Required
Find the 4th common multiple of the numbers.
From the question, we understand that the first common multiple of m and n is 6.
This can be represented as:
m * n * 1 = 6
mn = 6
Their fourth common multiple can be represented as: m * n * 4
4th multiple = m * n * 4
4th multiple = 4 * mn
Substitute 6 for mn
4th multiple = 4 * 6
4th multiple = 24
Hence, the 4th multiple of both numbers is 24.
Here is some information about the goals scored in some hockey games. Each game has four quarters. Please give the answer asap with full explanation and working out.
Answer:
8 home games and 10 away games
Step-by-step explanation:
Total home goals
= 8+5+9+8
= 30
Number of home games
= 30/3.75
= 8
Total away game goals
= 7+8+4+5
= 24
Number of away games
= 24/2.4
= 10
Answer:
i think it is 8 home and 10 away matches
Step-by-step explanation:
Find the perimeter of the rectangle with the following vertices. (−6, −2), (0, −10), (5, 2), (−1, 10) 23 52 46 40
Answer:
46
Step-by-step explanation:
See attached for reference
The points given:
(−6, −2), (0, −10), (5, 2), (−1, 10)They form a rectangle as seen in the picture.
We can notice that this is a parallelogram, as respective lines have same difference of coordinates.
So calculating only the two of the sides will be sufficient to get its perimeter:
a = √(-1+6)² + (10+2)² = √25+144 = √169= 13b = √(0+6)² + (-10+2)² = √36+64 = √100 = 10So, the perimeter:
P = 2(13+10) = 46
Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans. If she gave pounds of jelly beans away to her friends, how many pounds of jelly beans does Allison have left?
Answer: [tex]1\dfrac{11}{12}\text{ pounds}[/tex]
Step-by-step explanation:
The complete question is provided in the attachment.
Given, Amount blueberry jelly beans= [tex]1\dfrac{1}{4}[/tex] pounds
[tex]=\dfrac{5}{4}[/tex] pounds.
Amount lemon jelly beans = [tex]2\dfrac{1}{3}[/tex]pounds
[tex]=\dfrac{7}{2}[/tex] pounds
Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans
[tex]=(\dfrac{5}{4}+\dfrac{7}{3})[/tex] pounds
[tex]=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}[/tex]
Amount of jelly beans she gave away = [tex]1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}[/tex]
Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away
=[tex]\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}[/tex]
She has left [tex]1\dfrac{11}{12}\text{ pounds}[/tex] of jelly beans.
I need help please, m bda =
And m bca =
Step-by-step explanation:
Exterior angle BOA = 250°
Interior angle BOA = 360°- 250° = 110°
Now,
(A) BDA = interior angle BOA / 2 = 55°( Property of circles)
(B) From the figure, we observe that AOBC is a cyclic quadrilateral (i.e. sum of opposite angles is 180°).
Therefore, BCA + BOA = 180°
BCA = 180° - 110° = 70°
A local statistician is interested in the proportion of high school students that drink coffee. Suppose that 20% of all high school students drink coffee.
What is the probability that out of these 75 people, 14 or more drink coffee?
Answer:
the probability that out of these 75 people, 14 or more drink coffee is 0.6133
Step-by-step explanation:
Given that:
sample size n = 75
proportion of high school students that drink coffee p = 20% = 0.20
The proportion of the students that did not drink coffee = 1 - p
Let X be the random variable that follows a normal distribution
X [tex]\sim[/tex] N (n, p)
X [tex]\sim[/tex] N (75, 0.20)
[tex]\mu = np[/tex] = 75 × 0.20
[tex]\mu =[/tex] 15
[tex]\sigma = \sqrt{p (1-p) n}[/tex]
[tex]\sigma = \sqrt{0.20(1-0.20) 75}[/tex]
[tex]\sigma = \sqrt{0.20*0.80* 75}[/tex]
[tex]\sigma = \sqrt{12}[/tex]
[tex]\sigma = 3.464[/tex]
Now ; if 14 or more people drank coffee ; then
[tex]P(X \geq 14) = P(\dfrac{X-\mu }{\sigma} \leq \dfrac{X-\mu}{\sigma})[/tex]
[tex]P(X \geq 14) =P(\dfrac{14-\mu }{\sigma} \leq \dfrac{14-15}{3.464})[/tex]
[tex]P(X \geq 14) = P(Z \leq \dfrac{-1}{3.464})[/tex]
[tex]P(X \geq 14) = P(Z \leq -0.28868)[/tex]
From the standard normal z tables; (-0.288)
[tex]P(X \geq 14) = P(Z \leq 0.38667)[/tex]
[tex]P(X \geq 14) = 1 - 0.38667[/tex]
[tex]P(X \geq 14) = 0.61333[/tex]
the probability that out of these 75 people, 14 or more drink coffee is 0.6133
A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance that all three are selected
Answer:
3/11
Step-by-step explanation:
In the above question, we have the following information
Total number of balls = 12
White balls = 4
Blue balls = 3
Red balls = 5
We are to find the chance of probability that if we select 3 balls, all the three are selected.
Hence,
Probability ( all the three balls are selected) = P(White ball) × P(Blue ball) × P( Red ball)
Probability ( all the three balls are selected) = 4/12 × 3/11 × 5/10
= 60/1320
= 1/22
The number of ways by which we can selected all the three balls is a total of 6 ways:
WBR = White, Blue, Red
WRB = White, Red, Blue
RBW = Red, Blue, White
RWB = Red, White, Blue
BRW = Blue, Red, White
BWR = Blue, White, Red
Therefore, the chance that all three are selected :
1/22 × 6 ways = 6/22 = 3/11
akram is 20 year old and his sister shazia is 15
1-what was the ratio of their ages before 4 years
2-what was the ratio of their ages after 5 years
3-what do the above two points explain about ratios
Answer:
1) akram : shazia
20-4 : 15-4
16 : 11
2) akram : shazia
20 + 5 : 15 + 5
25 : 20
5 : 4
3) ratios are not always constant
Question 2 (1 point)
Saved
A year ago, Rebecca purchased 100 shares of Havad stock for $20 per share.
Yesterday, she placed a limit order to sell her stock at a price of $33 per share before
the market opened. The stock's price opened at $23 and slowly increased to $26 in
the middle of the day, before declining to $22 by the end of the day. The stock did
not pay any dividends over the period in which Rebecca held it. Given Rebecca's
initial investment of $ 20 per share, her return is
Answer:
Rebecca does not have a return yet because the stock was not sold since there was a limit order at $33.
However, the value of her investment can be put around $2,400 (100 x $24 average price).
Step-by-step explanation:
Price of Havad Stock bought a year ago = $20
No. of shares = 100
Limit order selling price = $33
Stock prices during the limit order day = $23, $26, and $22
The stock cannot be sold, since its price did not reach $33.
Rebecca's limit order is an order to buy or sell her stock in Havad at $33 or better. Since her order is a sell limit order, it can only be executed at the limit price of $33 or higher. Unfortunately, the price of the stock did not reach the limit order on that particular day. This implies that her limit order is not guaranteed to execute.
5x^2-4x=6
Solve for X.
Answer:
x= (2+ √ 34) /5 , (2- √ 34) /5
decimal form= 1.566
Step-by-step explanation:
Solve this problem (-25) +(-12)+(-34)=show me the steps
Answer:
(-25)+(-12)+(-34) = -71
so when you add negative numbers you simply add them such as -2+-2 -4
so same conditions
so it will be -25+-12+-34 and it will simply be 25+12+34 so -71
If 2/3 of the girls in class have brown eyes and 1/4 of the girls have blue eyes what fraction of the girls in class have neither blue or brown
A random sample of size 100 is taken from a population described by the proportion p = 0.60. The probability that the sample proportion is less than 0.55 is ________.
Answer:hope it helps
Step-by-step explanation:
Result:
0.6
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Number line:
Number line
Rational form:
3/5
Hello Pls help and thanks
Answer:
c.) in the correct answer
Twice the difference of a number and 9 is 3. Use the variable b for the unknown number.
Answer:
b = 10.5
Step-by-step explanation:
2(b-9) = 3
then:
2*b + 2*-9 = 3
2b - 18 = 3
2b = 3 + 18
2b = 21
b = 21/2
b = 10.5
check:
2(10.5 - 9) = 3
2*1.5 = 3
Please help on my hw
Answer:
b. The solution is a non empty set.
Step-by-step explanation:
There are no common elements.
About 60% of U.S full-time college students drank alcohol within a one-month period. You randomly select six U.S. full-time college students. Find the probability that the number of U.S. full-time college students who drank alcohol within a one-month period is exactly two.
Answer:
13.82%
Step-by-step explanation:
Here we have proportion of U.S. full time college students= p = 0.60, Random sample = n = 6
Here we apply Binomial distribution .
p ( X =x ) = nCx * px * ( 1 -p) n-x
a) Exactly two.
P ( x = 2 ) = 6C2 * 0.602 * ( 1 -0.60) 6-2
= 0.1382
Actual time in seconds recorded when statistics students participated in an experiment t test their ability to determine when one minute 60 seconds has passed are shown below.Find the mean median mode of the listed numbers. 55 51 70 64 68 60 49?49
Step-by-step explanation:
mean add upp all the numbers and divide by how many they are
Tại Trường Tiểu học ABC, số học sinh của Khối lớp 1, Khối lớp 2, Khối lớp 3, Khối lớp 4 và Khối lớp 5 chiếm tỉ lệ lần lượt là 28%; 22%; 20%; 16% và 14% tổng số học sinh toàn trường. Trong mỗi Khối, tỉ lệ học sinh giỏi năm nay của Khối lớp 1 là 45%, Khối lớp 2 là 50%, Khối lớp 3 là 55%, Khối lớp 4 là 65% và Khối lớp 5 là 75%. Xét trong Khối lớp 1, tỉ lệ học sinh giỏi của Khối lớp 1 là bao nhiêu?
Answer:
hello bro
Step-by-step explanation:
can you translate it on english so i can help you
A thin metal plate, located in the xy-plane, has temperature T(x, y) at the point (x, y). Sketch some level curves (isothermals) if the temperature function is given by
T(x, y)= 100/1+x^2+2y^2
Answer:
Step-by-step explanation:
Given that:
[tex]T(x,y) = \dfrac{100}{1+x^2+y^2}[/tex]
This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c
here c is the constant.
[tex]c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)[/tex]
By cross multiply
[tex]c({1+x^2+2y^2}) = 100[/tex]
[tex]1+x^2+2y^2 = \dfrac{100}{c}[/tex]
[tex]x^2+2y^2 = \dfrac{100}{c} - 1 \ \ -- (2)[/tex]
From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.
Now,
[tex]\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1[/tex]
This is the equation for the family of the eclipses centred at (0,0) is :
[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1[/tex]
[tex]a^2 = \dfrac{100}{c} -1 \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}[/tex]
Therefore; the level of the curves are all the eclipses with the major axis:
[tex]a = \sqrt{\dfrac{100 }{c}-1}[/tex] and a minor axis [tex]b = \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}[/tex] which satisfies the values for which 0< c < 100.
The sketch of the level curves can be see in the attached image below.
Solve 5(2x + 4) = 15. Round to the nearest thousandth.
[tex]5(2x + 4) = 15\\10x+20=15\\10x=-5\\x=-\dfrac{5}{10}=-0,5[/tex]
Answer:
[tex]\huge\boxed{x=-0.5}[/tex]
Step-by-step explanation:
[tex]5(2x+4)=15\qquad\text{divide both sides by 5}\\\\\dfrac{5\!\!\!\!\diagup(2x+4)}{5\!\!\!\!\diagup}=\dfrac{15\!\!\!\!\!\diagup}{5\!\!\!\!\diagup}\\\\2x+4=3\qquad\text{subtract 4 from both sides}\\\\2x+4-4=3-4\\\\2x=-1\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{-1}{2}\\\\\boxed{x=-0.5}[/tex]
Determine whether (a) x = -1 or (b) x = 2 is a solution to this equation
Answer:
2x-1=3
2x=3+1
2x=4
x=2
[tex]\huge\boxed{\underline{\bf \: Answer}}[/tex]
(a) Let's try with x = - 1
[tex] \sf \: 2x - 1 = 3 \\\sf 2( - 1) - 1 = 3 \\ \sf- 2 - 1 = 3 \\ \\ \boxed{\bf- 3 \: \bcancel= \: 3}[/tex]
So, x = - 1 is not the solution to the given equation.
______________
(b) Now, try with x = 2
[tex]\sf2x - 1 = 3 \\ \sf2(2) - 1 = 3 \\ \sf4 - 1 = 3 \\ \\ \boxed{\bf3 = 3}[/tex]
Yes, we can see that x = 2 is the correct solution for the equation.
______________
Hope it helps.
RainbowSalt2222
A potato chip company makes potato chips in two flavors, Regular and Salt & Vinegar. Riley is a production manager for the company who is trying to ensure that each bag contains about the same number of chips, regardless of flavor. He collects two random samples of 10 bags of chips of each flavor and counts the number of chips in each bag. Assume that the population variances of the number of chips per bag for both flavors are equal and that the number of chips per bag for both flavors are normally distributed. Let the Regular chips be the first sample, and let the Salt & Vinegar chips be the second sample. Riley conducts a two-mean hypothesis test at the 0.05 level of significance, to test if there is evidence that both flavors have the same number of chips in each bag. (a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test. (b) t≈1.44 , p-value is approximately 0.167 (c) Which of the following are appropriate conclusions for this hypothesis test?
A. There is insufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag.B. There is sufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag.C. Reject H0.D. Fail to reject H0.
Answer:
A. There is insufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag.
D. Fail to reject H0.
Step-by-step explanation:
From the summary of the given test statistics.
The null and the alternative hypothesis are:
[tex]H_0:\mu_1=\mu_2 \\ \\ Ha:\mu_1 \neq \mu_2[/tex]
This test is also a two tailed test.
Similarly, the t value for the test statistics = 1.44
The p- value - 0.167
The level of significance ∝ = 0.05
The objective we are meant to achieve here is to determine which of the following from the given options are appropriate conclusions for this hypothesis test.
From what we have above:
Decision Rule: We fail to reject the null hypothesis since the p-value is greater than the level of significance at 0.05
CONCLUSION: Therefore, we can conclude that there is insufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag as we fail to reject H0.
Time-series data are often graphically depicted how?
A. Bar chart.
B. Histogram.
C. Line chart.
D. All of these choices are true.
Answer:
C. Line chart
Step-by-step explanation:
Answer:
B. Histogram
Step-by-step explanation:
Histogram uses time.
The width of a rectangle is
3
inches less than the length. The perimeter is
54
inches. Find the length and the width.
please help asap!!!
Answer:
let length be x
b = x - 3
perimeter = 2( l + b)
54 = 2(x+x-3)
27 = 2x - 3
30 = 2x
x = 15
l = 15
b = 15 - 3
b = 12
Write the expression
using only positive exponents.
-3/x-4
HELPPPPPPP PLZZZZ ASPPPPPP
Answer: Choice B
[tex](f * g)(x) = \frac{x^2+6x+8}{x^2+2x-15}, \ \text{ for } x \ne -5 \text{ and } x \ne 3\\\\[/tex]
=================================================
Work Shown:
[tex]h(x) = (f * g)(x)\\\\h(x) = f(x) * g(x)\\\\h(x) = \frac{x^2-16}{x^2+3x-10}*\frac{x^2-4}{x^2-7x+12}\\\\h(x) = \frac{(x-4)(x+4)}{(x+5)(x-2)}*\frac{(x-2)(x+2)}{(x-3)(x-4)}\\\\h(x) = \frac{x+4}{(x+5)(x-2)}*\frac{(x-2)(x+2)}{x-3} \ \ \text{ ... see note 1}\\\\h(x) = \frac{x+4}{x+5}*\frac{x+2}{x-3} \ \ \text{ ... see note 2}\\\\h(x) = \frac{(x+4)(x+2)}{(x+5)(x-3)}\\\\h(x) = \frac{x^2+6x+8}{x^2+2x-15}\\\\[/tex]
note 1: A pair of (x-4) terms canceled
note 2: A pair of (x-2) terms canceled
------------------------------
Extra info (optional section):
The fact that [tex]x \ne -5 \text{ and } x \ne 3[/tex] is to avoid a division by zero error in the simplified version of h(x).
I would argue that [tex]x \ne 2 \text{ and } x \ne 4[/tex] should be thrown in as well simply so that the domains match up perfectly with the original f(x) and g(x) functions.
So I think the full domain should be that x is any real number but
[tex]x \ne -5 \text{ and } x \ne 2\\x \ne 3 \text{ and } x \ne 4[/tex]
Put another way: if x = 2 is allowed in h(x), then that clashes with the fact that it's not allowed in f(x). The same idea happens with x = 4 but with g(x) this time. It's possible your teacher glossed this fact over, or ran out of room.
Given a sphere with radius r, the formula 4 r2 gives
O A. the volume
O B. the surface area
O c. the radius
O D. the cross-sectional area
Answer: surface area
Step-by-step explanation:
I NEED HELP WITH THESE 4 ASAP
Answer:
I'm confused by this. What do they mean by prove?
Step-by-step explanation: