1. If A = {1, 2, 3,4}, B = {3,4,5,6}, C = {1, 2, 4, 6, 7}, then find i) AUB ii) BUC iii) (AUB)UC v) An(BNC) vi) AU(BUC) iv) AN(BUC)​

Answer:

600

Step-by-step explanation:

[tex]p(x) = 1 + 6x - 5x^2[/tex]

x max = [tex]-b/2a[/tex]

a = -5

b = 6

-6/2(-5) = 6/10 = 3/5 = .6

.6 thousand = 600

600 speakers should be sold.

Alternatively, you can check the vertex of the parabola formed.

Answer:

−8x3−1

Step-by-step explanation:

let's simplify step-by-step.

3−8x3−4

=3+−8x3+−4

Combine Like Terms:

=3+−8x3+−4

=(−8x3)+(3+−4)

=−8x3+−1

Answer:

-1 - (2x^3)^3

Step-by-step explanation:

The equation is:

=> 3 - 8x^3 - 4

=> -1 - 8x^3

=> -1 - (2x^3)^3

Answer:

2,200

Step-by-step explanation:

6.6 x 10^10

= 66,000,000,000

3 x 10^7

= 30,000,000

66,000,000,000 ÷ 30,000,000

2,200

Answer:

2200.

Step-by-step explanation:

6.6 / 3  *  10^10/10^7

= 2.2 * 10^3

= 2200

Answer:

there is a 20% chance of getting a red marble

Step-by-step explanation:

Answer:

there is a 1/5 percent chance or 20%

Step-by-step explanation:

Hope this helps!

Answer:

[tex]y = 7 - 7x \\ y + 7x = 7 \\ 7x + y = 7[/tex]

Answer:

7x + y = 7

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = 7 - 7x ( add 7x to both sides )

7x + y = 7 ← in standard form

Answer:

well all of these look like a way so we have to use elimination method

A : random number tables : well it has random numbers so X out

B: PHONE NUMBERS: well phone numbers are random so X out

C: USing the internet : totally X out

D: books of random numbers: X out

so none of the above i guess

The only way that might not be used in generating random numbers is : (B). using phone numbers selected at random in a local phone book

Random numbers are numbers that occurs randomly without prediction. these numbers are impossible to predict using past values.

Random numbers are important for computer encryption and lotteries.

In conclusion, The only way that might not be used in generating random numbers is using phone numbers selected at random in a local phone book

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Answer:

16. f(y-2) = 2(y-2)²-5

= 2(y²-4y+4)-5

= 2y²-8y+8-5

= 2y²-8y+3

17. f(a+h)-f(a) = 2(a+h)²-5-(2a²-5)

= 2(a²+2ah+h²)-5-2a²+5

= 2a²+4ah+h²-2a²

= h²+4ah

Equation:- 2y-x=10

For L to intersects Y axis then X cordinate must be zero

so put value of X as zero (0)

2y=10

So Y cordinate is equal to 5

Cordinate:- (0,5)

answer:

2 on the picture is the amplitude

Answer:

The hypotenuse is the longest side in a triangle.

a^2=b^2+c^2.

14^2=9^2+c^2.

c^2=196-81.

c^2=115.

c=√115.

c=10.72~11cm

Answer:

8

Step-by-step explanation:

Hello,

[tex]x=3y^2<=>y=\sqrt{\dfrac{x}{3}} \ \ for \ x\geq 0[/tex]

And for y = 2, x = 3 * 2 * 2 = 12 so first, let's compute

[tex]\displaystyle \int\limits^{12}_0 {\sqrt{\dfrac{x}{3}}} \, dx =\dfrac{1}{\sqrt{3}} \int\limits^{12}_0 {\sqrt{x}} \, dx\\\\=\dfrac{1}{\sqrt{3}} \left[ \dfrac{2}{3}x^{3/2}\right]_0^{12}\\\\=\dfrac{1}{\sqrt{3}} *\dfrac{2}{3}*12*\sqrt{12}\\\\=\dfrac{2*12*2*\sqrt{3}}{3*\sqrt{3}}\\\\=2*4*2=16[/tex]

The area which is asked is 12*2 - 16 = 24 - 16 = 8

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Using integrals, it is found that the area of the region enclosed by the curves in the interval is of 27 units squared.

In this problem:

Then, the integral for the area is:

[tex]A = \int_{0}^{2} 3y^2 dy[/tex]

[tex]A = y^3|_{y = 0}^{y = 3}[/tex]

[tex]A = 3^3 - 0^3[/tex]

[tex]A = 27[/tex]

The area of the region enclosed by the curves in the interval is of 27 units squared.

You can learn more about the use of integrals to calculate an area at https://brainly.com/question/15127807

Answer:

65 ft

Step-by-step explanation:

The area of a rectangle is

A = lw

6045 = 93*w

Divide each side by 93

6045/93 = 93w/93

65 =w

Answer:

[tex]\huge \boxed{\mathrm{65 \ feet}}[/tex]

Step-by-step explanation:

The area of a rectangle formula is given as,

[tex]\mathrm{area = length \times width}[/tex]

The area and length are given.

[tex]6045=93 \times w[/tex]

Solve for w.

Divide both sides by 93.

[tex]65=w[/tex]

The width of the rectangular garden is 65 feet.

Answer:

The  p-value is  [tex]p-value = 0.62578[/tex]

Step-by-step explanation:

From the question we are told that    

    The  sample size of male infant is  [tex]n_1 = 12[/tex]

     The  sample size of female infant is [tex]n_2= 9[/tex]

     The sample mean of male infant is  [tex]\= x_1 = 7.70 \ lb[/tex]

      The sample mean of female infant is  [tex]\= x_2 = 7.80 \ lb[/tex]

     The population standard deviation is  [tex]\sigma = 0.5[/tex]

       The significance level is  [tex]\alpha = 0.05[/tex]

The null hypothesis is  [tex]H_o : \mu_ 1 = \mu_2[/tex]

The  alternative hypothesis is  [tex]H_1 : \mu_1 > \mu_2[/tex]

The  test statistics is mathematically represented as

            [tex]t =\frac{\= x_1 - \= x_2 }{\sqrt{\frac{\sigma }{n_1} } + \frac{\sigma }{n_2} } }[/tex]

=>          [tex]t = \frac{7.70 -7.80}{\sqrt{\frac{0.5 }{12} } + \frac{0.5 }{9} } }[/tex]

=>        [tex]t = -0.3207[/tex]

From the z-table  the p-value is  obtained, the value is  

     [tex]p-value = P(Z > -0.3207) = 0.62578[/tex]

     [tex]p-value = 0.62578[/tex]

[tex]\boxed{\sf a_n=\dfrac{(-1)^n}{5n}}[/tex]

a:-

[tex]\\ \sf\longmapsto a_1=\dfrac{(-1)^1}{5(1)}[/tex]

[tex]\\ \sf\longmapsto a_1=\dfrac{-1}{5}[/tex]

[tex]\\ \sf\longmapsto a_1=-5[/tex]

b:-

[tex]\\ \sf\longmapsto a_4=\dfrac{(-1)^4}{5(4)}[/tex]

[tex]\\ \sf\longmapsto a_4=\dfrac{1}{20}[/tex]

c:-

[tex]\\ \sf\longmapsto a_{30}=\dfrac{(-1)^{30}}{5(30)}[/tex]

[tex]\\ \sf\longmapsto a_{30}=\dfrac{1}{150}[/tex]

d:-

[tex]\\ \sf\longmapsto a_{19}=\dfrac{(-1)^{19}}{5(19)}[/tex]

[tex]\\ \sf\longmapsto a_{19}=\dfrac{-1}{95}[/tex]

Answer:

(x - 2)/3

(x - 4)/-5 or (-x + 4)/5

Step-by-step explanation:

this is an inverse function, and to solve an inverse function you would :

swap x and g(x) without bringing the x coefficient with it, just simply swap the variables. Then, solve for g(x), and that's it

the first question's answer is :

g(x) = 3x + 2

x = 3(g(x)) + 2

x - 2 = 3(g(x))

(x - 2)/3 = g(x)

the second one is:

g(x) = 4 - 5x

x = 4 - 5(g(x))

x - 4 = -5(g(x))

(x-4)/-5 = g(x)

g(x) = 3x + 2

y = 3x + 2

x = 3y + 2

3y = x - 2

y = x/3 - 2/3

inverse g(x) = (x - 2) / 3

g(x) = 4 - 5x

y = 4 - 5x

x = 4 - 5y

5y = 4 - x

y = 4/5 - x/5

inverse g(x) = (4 - x) / 5

Answer:

60 pounds

Step-by-step explanation:

Let x = number of pounds of grass seeds A

The number of pounds of grass seed B = 140 pounds

Total pounds of the resulting mixture = (140 + x) pounds

Rye grass A = 60% = 0.6

Rye grass B = 80% = 0.8

Total percent of mixture formed = 74% = 0.74

Hence, we have the equation:

0.6x + 0.8 × 140 = 0.74 ( 140 + x)

0.6x + 112 = 103.6 + 0.74x

Collect like terms

112 - 103.6 = 0.74x - 0.6x

8.4 = 0.14x

x = 60 pounds

Therefore, the quantity of the 60% mixture used is 60 pounds.

The manager of a garden shop mixes grass seed that is 60% rye grass with 140 pound of grass seed that is 80% rye grass to make a mixture that is 74% rye grass. How much of the 60% mixture is used?

Answer:

a.

[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]

[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]

[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]

b.

[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]

Step-by-step explanation:

Given that:

C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)

a. Find a piecewise smooth parametrization of the path C.

r(t) = { 0

If C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1),

Then:

[tex]C_1 = (0,0) \\ \\ C_2 = (1,0) \\ \\ C_3 = (0,1)[/tex]

Also:

[tex]\mathtt{r_1 = (0,0) + t(1,0) = (t,0) }[/tex]

[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]

[tex]\mathtt{r_2 = (1,0) + t(-1,1) = (1- t,t) }[/tex]

[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]

[tex]\mathtt{r_3 = (0,1) + t(0,-1) = (0,1-t) }[/tex]

[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]

b Evaluate :

Integral of (x+2y^1/2)ds

[tex]\mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \int \limits ^1_{0} \ (t + 0) \sqrt{1} } \\ \\ \mathtt{ \int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \begin {pmatrix} \dfrac{t^2}{2} \end {pmatrix} }^1_0 \\ \\ \mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \dfrac{1}{2}}[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits (x+2 \sqrt{y} \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2 \ dt } }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits 2- t + 2\sqrt{t-1} \ \sqrt{1+1} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} \int \limits^2_1 2- t + 2\sqrt{t-1} \ dt }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2t - \dfrac{t^2}{2}+ \dfrac{2(t-1)^{3/2}}{3} (2) \end {pmatrix} ^2_1}[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{1}{2} (4-1)+\dfrac{4}{3} (1)^{3/2} -0 \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{3}{2} + \dfrac{4}{3} \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{12-9+8}{6} \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{11}{6} \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ \sqrt{2} }{6} \ (11 )}[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ 11 \sqrt{2} }{6}}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 0+2 \sqrt{3-t} \ \sqrt{0+1} }[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 2 \sqrt{3-t} \ dt}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits^3_2 \begin {pmatrix} \dfrac{-2(3-t)^{3/2}}{3} (2) \end {pmatrix}^3_2 }[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [(0)-(1)]}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [-(1)]}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \dfrac{4}{3}}[/tex]

[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}}{6}+\dfrac{1}{2}+ \dfrac{4}{3}}[/tex]

[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+3+8}{6}}[/tex]

[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]

Answer:

B, C, and D........................

He must do a 8,00,000 sales to make total of 75000 for the year.

For salesman base salary = 35000, Salary to be atained is 75000. Having commission of 5% on every sales. Sales to be determine so the salesman attained 75000 for year.

In mathematics it deals with numbers of operations according to the statements.

Here, according to the statement.
Let x be sales,
35,000 + 5%x = 75,000
0.05x = 75000-35000
x = 40000/0.05
x = 8,00,000

Thus, he must do a 8,00,000 sales to make total of 75000 for the year

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Answer:

y=-2/3x+3

Step-by-step explanation:

the equation of line J is y=3/2x-5

perpendicular slope would be -2/3

you want it at point (6, -1) so sub the points into y=-2/3x+b

-1=-2/3(6)+b

-1=-4+b

3=b

y=-2/3x+3

Answer:

below

Step-by-step explanation:

that is the solution above

Answer:

The previous palindrome date in all formats came 909 years ago on 11/11/1111. The next will come in 101 years on 12/12/2121 and after that there will not be another until 03/03/3030.

It depends how you format the date. If you do mm/dd/yyyy format

mm = month

dd = day

yyyy = year

then the last palindromic date was September 10th, 2019 since this would be written as 9/10/2019 in the mm/dd/yyyy format

Taking out the slash symbols, we have the number 9102019 which is the same when we reverse the digits.

The answer will be different if you have the date format as dd/mm/yyyy

Answer:

H0: μd=0 Ha: μd≠0

t= 0.07607

On the basis of this we conclude that the mean weight differs between the two balances.

Step-by-step explanation:

The null and alternative hypotheses as

H0: μd=0 Ha: μd≠0

Significance level is set at ∝= 0.05

The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571

The test statistic under H0 is

t = d/ sd/ √n

Which has t distribution with n-1 degrees of freedom

Specimen        A               B           d = a - b         d²

1                     13.76        13.74         0.02           0.004

2                    12.47        12.45          0.02         0.004

3                    10.09        10.08           0.01        0.001

4                       8.91       8.92          -0.01          0.001

5                     13.57      13.54           0.03        0.009

6                     12.74      12.75          -0.01        0.001

∑                                                      0.06         0.0173

d`= ∑d/n= 0.006/6= 0.001

sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882

sd= 0.05368

t= 0.001/ 0.05368/ √6

t= 0.18629/2.449

t= 0.07607

Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.

Answer:

$0.75

Step-by-step explanation:

Given that

Number of bags of popcorn bought = 4

Total money spent = $3.00

To find:

Unit rate per bag of popcorn = ?

i.e. price of one bag of popcorn is to be find out.

Solution:

We can use ratio here to find the rate of one bag of popcorn.

4 bags bought at $3

4 bags : $3

Let us divide both the sides with 4.

[tex]\frac{4}4[/tex] bags : $ [tex]\frac{3}4[/tex]

OR

1 bag bought at $ 0.75

We can alternatively use unitary method.

4 bags are bought at $ 3

1 bag is bought at $ [tex]\frac{3}{4}[/tex]

1 bag is bought at $0.75.

So, unit rate per bag of popcorn is $0.75.

Answer: a. [tex]2.02\times10^6\ m[/tex]

b. [tex]9.901\times10^6\ m/s[/tex]

c. [tex]3.02\times10 ^{-3}\ km[/tex]

d. [tex]1.1\times10^{-3}\ mm[/tex]

Step-by-step explanation:

Scientific notation is a technique to express a very big or a very small number in the product of a decimal form of number ( between 1 and 10) and powers of 10.

a.  [tex]2,020,000 m\ = 2.02\times1,000,000=2.02\times10^6\ m[/tex]

b. [tex]9,901,000\ m/s =9.901\times1000000=9.901\times10^6\ m/s[/tex]

c. [tex]0.003020\ km=\dfrac{3020}{1000000}[/tex]

[tex]=3.02\times10 ^{-3}\ km[/tex]

d. [tex]0.001100\ mm=\dfrac{1100}{1000000}=\dfrac{11}{10000}[/tex]

[tex]1.1\times10^{-3}\ mm[/tex]

Answer:

Some texts are missing from the question, I found a possible match, and here it is:

A particular country has total of 45 states. If the areas of 35 states are added and the sum is divided by 35​, the result is 135,600 square kilometres. Determine whether this result is a statistic or a parameter.

Answer:

The result is a statistic because the data involved are samples.

Step-by-step explanation:

A Parameter is a numerical representation of an entire population. That is they are numbers summarizing data for an entire population. In this case, if all the 45 states were measured, the result would have been a parameter.

On the other hand, statistics are numbers that are subsets (representative portions) of an entire population. Since 35 states were chosen out of 45 states, the average area of the 35 states is a statistic and not a parameter.

Answer:

135.7 yd²

Step-by-step explanation:

Surface area of the cone,

πr²+πrl

= π×3²+π×11.4×3

= 43.2π

= 135.7 yd² (rounded to the nearest tenth)

Answer:

Solution : y = 4x - 8

Step-by-step explanation:

The first thing we want to do is isolate t², rather than t. Why? As you can see when we substitute t² into the second equation, it will be easier than substituting t, as t is present in the form t². So, let's isolate t² in the first equation --- ( 1 )

x = t² + 2,

t² = x - 2

Now let's substitute this value of t² in the second equation --- ( 2 )

y = 4t²,

y = 4(x - 2),

y = 4x - 8 ~ And hence our solution is option c.

9514 1404 393

Answer:

  (x/y)^(m+n)

Step-by-step explanation:

  [tex]\displaystyle\frac{\left(x+\frac{1}{y}\right)^m\left(x-\frac{1}{y}\right)^n}{\left(y+\frac{1}{x}\right)^m\left(y-\frac{1}{x}\right)^n}=\left(\frac{x}{y}\right)^m\left(\frac{x}{y}\right)^n\\\\=\boxed{\left(\frac{x}{y}\right)^{m+n}}[/tex]