1. What is the definition of work done?
2. What is the unit for energy?
3.
The engine of Tilly's car exerts a force of 750N. How much
energy would be transferred by the engine if the car moved a
distance of 100m?
4.
Rehana is holding an object of weight 50N is raised by a height
of 200cm. What is the work done in raising the object?
5.
700J of energy is used by Ikram to move a distance of 10m.
What is the force exerted by the person as they walk the
distance?
6. Hifza has a weight of 200N. Aymen has a weight of 350N. If
1000) of energy is used to raise each object, which object will
gain the most height?

Answers

Answer 1

The combination of a force's constituent acting inside the displacement's direction as well as its magnitude would be known as the work done mostly via force.

1) Work is done when an applied force produces mobility in a body.

Mathematically , Work = Force x displacement

2) Unit for energy is Joule.

3) Energy can be calculated by such as:

Work = F s

750 x 100 = 75000J would be transferred by engine if car moved a distance of 100m.

4)For the case of Rehana : 200 cm converted to 2m .

again using same concept , W=FS

50 x 2=100J of work done in raising the object.

Energy consumed = 700 J

Distance (Displacement) = 10 m

7) We know work done is also a type of energy which tells the energy consumed by anything in order to move a distance, We know

⇒ Work done = Force × Displacement

⇒ 700 = F × 10

⇒ F = 70 newton

Hence, The force exerted by the person as walked the distance is 70 newton.

6) For the hifza case:- 200N will take more height because it is lighter than 350N so we can do it upward and downward as it is lighter and the energy used is 1000J .

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Related Questions

Two objects have a gravitational force of attraction to each other, equal to 10 Newtons. What is their gravitational force if the distance between them is halved?

I have the answer, however I do not know how to get to it. Please explain.

Answers

The gravitational force when the distance between them is halved is 40 N

How to determine the gravitational force?

Newton's law of universal gravity states as follow:

F = GM₁M₂ / r²

Where

F is the force of attraction K is the electrical constant M₁ and M₂ are the masses of the objects r is the distance apart

Finding a relationship between force and distance, the following were obtained:

F = GM₁M₂ / r²

Cross multiply

Fr² = GM₁M₂

GM₁M₂ = constant

F₁r₁² = F₂r₂²

Now, we can obtain the new gravitational force of as illustrated below:

Initial gravitational force (F₁) = 10Initial distance (r₁) = rNew distance (r₂) = 1/2r = 0.5rNew gravitational force (F₂) =?

F₁r₁² = F₂r₂²

10 × r² = F₂ × (0.5r)²

10r² = F₂ × 0.25r²

Divide both side by 0.25r²

F₂ = 10r² / 0.25r²

F₂ = 10 / 0.25

F₂ = 40 N

Thus, the gravitaional force is 40 N

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If the mass of an object is 2 kg, the gravitational field strength is 4 ms and the
change in height is 2 m, what is the change in gravitational potential energy stored?

Answers

The change in gravitational potential energy stored in 16 Jule.

What is gravitational potential energy?

In classical mechanics, of the  gravtitational potential at in a  location is equal to the work per unit mass that's would be needed to Move an object to that locations from a fixed references  location. It is analogous to the electric potential with the mass playing the role of charge.

Sol-As per the given question ∆PE = mgh

M= skg

g= 4m/s^2

∆h = 2m

∆PE = 2m×4m×2m

= 16 Joules.

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16. [-/1 Points] DETAILS SERCP11 8.6.P.069.
MY NOTES
ASK YOUR TEACHER
A solid, horizontal cylinder of mass 12.2 kg and radius 1.00 m rotates with an angular speed of 5.50 rad/s about a fixed vertical axis through its center. A 0.250-kg piece of putty is
dropped vertically onto the cylinder at a point 0.900 m from the center of rotation and sticks to the cylinder. Determine the final angular speed of the system.
rad/s
PRACTICE ANOTHER

Answers

The final angular speed of the system that contains a solid, horizontal cylinder of mass 12.2 kg and radius 1.00 m rotates with an angular speed of 5.50 rad/s about a fixed vertical axis through its center is 5.33 rad / s

Let M and R be mass and radius of the cylinder. Let m and r be mass and distance of piece of putty.

M = 12.2 kg

R = 1 m

ω = 5.5 rad / s

m = 0.25 kg

r = 0.9 m

According to law of conservation of angular momentum,

1 / 2 M R² ω = ( 1 / 2 M R² + m r² ) ω'

1 / 2 * 12.2 * 1 * 5.5 = [ ( 1 / 2 * 12.2 * 1 ) + ( 0.25 * 0.9² ) ] ω'

ω' = 33.55 / 6.3

ω' = 5.33 rad / s

Therefore, the final angular speed of the system is 5.33 rad / s

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how does Cavendish's experiment disprove the idea that only planet-sized masses cause gravitational attraction?

Answers

It is evident from Isaac Newton's equation for universal gravitation that ANY TWO masses will act as an easily calculable attractive force on one another. Cavendish proved that this was accurate (for masses that he gathered in his shed).

What is Cavendish's experiment?

The Cavendish experiment was the first to accurately determine the gravitational constant and the force of gravity between masses in a laboratory setting. Cavendish's work does not directly mention the gravitational constant due to the unit norms in use at the time. Instead, the outcome was initially stated as Earth's specific gravity, or alternatively, as Earth's mass. The first precise values for these geophysical constants came from his experiment.

Thus, by measuring the universal  gravitational constant though experiment,  Cavendish's experiment makes easy to calculate gravitational attraction force for minute objects also.

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You are holding a small helium balloon. Your friend says that the buoyant force from the atmosphere is greater on her car than your balloon. Is she correct? Explain your answer.

Answers

Buoyant force from the atmosphere is greater on her car than the balloon is a correct statement  

buoyant force = - rho * g * V

where

rho = fluid density or in our case air density

g = acceleration due to gravity

V = volume of displaced liquid or volume of displaced air

volume of  displaced air is more in the case of car as compared to balloon because car has larger volume then balloon .

and volume displaced is directly proportional to the buoyant force , hence buoyant force from the atmosphere is greater on her car than the balloon is a correct statement .

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calculate the density of 1mole of oxygen ata pressure of 4×10^-4Nm^-2 and a temprature of 273.2°K

Answers

The density of 1 mole of oxygen at a pressure of 4×10⁻⁴ Nm⁻² and a temprature of 273.2 K is 2.82×10⁻⁶ g/m³

How to determine the density of oxygen

We'll begin by obtaining the volume of the oxygen. This can be obtained as follow:

Number of mole (n) = 1 molePressure (P) = 4×10⁻⁴ Nm⁻²Temperature (T) = 273.2 K Gas constant (R) = 8.314 m³Nm⁻²/KmolVolume = ?

PV = nRT

Divide both sides by P

V = nRT / P

V = (1 × 8.314 × 273.2) / 4×10⁻⁴

V = 5678462 m³

Finally, we shall determine the density of the oxygen. This can be obtained as follow:

Mass of 1 mole of oxygen = 16 gVolume of 1 mole of oxygen = 5678462 m³Density of oxygen =?

Density = mass / volume

Density of oxygen = 16 / 5678462

Density of oxygen = 2.82×10⁻⁶ g/m³

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Find the work done in moving a particle from P (0.92, 2.5) to Q(−3.1, 5) if the force is ⃗v = −3.6ˆı + 2.1ˆ.

Answers

The magnitude of the work done on the particle by the applied force is 19.72 J.

What is work done?

The work done in moving a charged particle is determined from the product of force and displacement of the object.

W = Fd

where;

F is the applied forced is the displacement of the particle

The magnitude of the particle's displacement is calculated as follows;

|d| = √[(x₂ - x₁)² + (y₂ - y₁)²]

where;

x₁ and x₂ are the initial and final position of the particle in horizontal directiony₁ and y₂ are the initial and final position of the particle in vertical direction

|d| = √[(-3.1 - 0.92)² + (5 - 2.5)²]

|d| = 4.73 m

The magnitude of the force is calculated as follows;

F = √(-3.6² + 2.1²)

F = 4.17 N

The work done = 4.17 N x 4.73 m = 19.72 J

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Consider a wooden cylinder of density 0.75g/cm³ floating in water with its axis perpendicular to the surface and the height is 15cm. How much of the cylinder will be under water?. If the radius were 10cm, how much would be under water? Suppose the cylinder is completely submerged and anchor in the water by a string, for the cylinder nof 10cm radius, what will be the force on the string?. Where g=9.8m/s, density of water=1g/cm³.​

Answers

6923 N is the force on the string, Where g=9.8m/s, density of water=1g/cm³.​

volume=2πrh

volume= 942 cm³

density= mass/volume

mass=density× volume

mass=0.75g/cm³× 942 cm³

mass=706 kg

F= mg

F=706×9.8

F= 6923 N

Every action that attempts to maintain, modify, or change the motion of a body is referred to as a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).

According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight route in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changing velocity) in the direction of the force.

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Carbon -14 forms nitrogen -14 by? A.alpha decay B.gamma decay C.positron decay D.beta decay.

Answers

Nitrogen-14 is created through the beta decay of carbon-14. Beta particle emission occurs along with this kind of disintegration.

How does alpha decay work?

The unstable nucleus emits alpha particles during this disintegration. A helium nucleus with two protons and two neutrons makes up an alpha particle. Additionally, it bears a +2 charge.

Beta decay

This kind of radioactive decay results in the emission of gamma rays. The process produces a lot of energy, yet the number of protons doesn't change.

How can carbon become nitrogen?

Carbon has an atomic number of 6, while nitrogen has a number of 7. Since the only way that carbon-14 and nitrogen-14 differ from one another is in their atomic number. Nitrogen-14 is created through the beta decay of carbon-14. Only beta decay allows for the conversion of carbon-14 into nitrogen-14, and the number of protons remains constant.

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explain the impact covid had had on the rate of cardiovascular disease

Answers

The inner walls of veins and arteries can be affected by coronavirus infection, which can result in blood vessel inflammation, harm to extremely small vessels, and blood clots leading to the risks of cardiovascular diseases.

How covid had an impact on the rate of cardiovascular diseases?

The mechanisms by which the COVID-19 pandemic might change trends in cardiovascular health have been the subject of numerous ideas. People with COVID-19 have a worse prognosis when they have established CVD and atherosclerosis cardiovascular disease risk factors.

Like other viral illnesses, such as some flu strains, the coronavirus may directly infect and harm the heart's muscular tissue. The body's immune system's response could also indirectly harm and inflame the heart.Less oxygen can enter the circulation as the virus induces inflammation plus fluid to clog the air sacs of the lungs. Blood pumping through the body requires more effort from the heart, which can be problematic for those who already have heart disease.

Therefore, covid had a great impact on cardiovascular diseases and increased the overall disease rate.

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Mars has a mass of about 6.79 x 102³ kg, and its
moon Phobos has a mass of about 9.1 × 10¹5 kg. If
the magnitude of the gravitational force between
the two bodies is 4.98 x 10¹5 N, how far apart are
Mars and Phobos? The value of the universal
gravitational constant is
6.673 x 10-¹¹ N. m²/kg².
Answer in units of m.

Answers

When mass of Mars and Phobos are given then we can calculate that Mars and Phobos are 9.098x 10⁶ meters apart.

What is gravitational force?

The gravitational force is that force that pulls objects with mass towards each other.

The formula for the gravitational force between two objects is given as:

Force = G  (M1) (M2) / (distance²)

Given, Force  =  4.98 x 10¹⁵N

G  =  6.673 x 10⁻¹¹  N·m²/kg²

Given One mass =   6.79 x 10²³ kg

and Other mass = 9.1 x 10¹⁵ kg  

Force = (G) · (M1) · (M2) / (distance²)

4.98x10¹⁵N = (6.673x10⁻¹¹N-m²/kg²)·(6.79x10²³kg)·(9.1x10¹⁵kg) / (distance²)

(distance²)·(4.98x10¹⁵N) = (6.673x10⁻¹¹N-m²/kg²)·(6.79x10²³kg)·(9.1x10¹⁵kg)

(distance²)=(6.673x10⁻¹¹N-m²/kg²)·(6.79x10²³kg)·(9.1x10¹⁵kg) / (4.98x10¹⁵N)

 (distance²)  =  8.279 x 10¹³  m²

distance  =  9.098x 10⁶ meters .  

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Aside from density, what other information from the table of planetary data can help someone decide if a planet is terrestrial, jovian, or dwarf?

Answers

Jovian planets are less dense than terrestrial planets.

The ratio of these two characteristics—an object's mass divided by its volume is that determines its density.

The Jovian planets lack solid surfaces, in contrast to the terrestrial planets that make up our inner solar system—Mercury, Venus, Earth, and Mars. They are made mostly of hydrogen and helium instead, with minute amounts of other gases like methane, ammonia, water, and others in their atmospheres.

Terrestrial planets formed from metal and rock-based planetesimals, but they were ultimately too small to hold much of the solar nebula's rich hydrogen and helium gas. The Jovian planets, on the other hand, originated distant from the Sun where there were abundant ices and rocks.

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If 600 J of energy of chemical energy is contained inside the gasoline in a gas tank, how much work can the engine perform on the car? What kinetic energy can be achieved?

Answers

Kinetic energy will be 600J. According to law of conservation energy: All the energy in a system will simply change the state, and no more nor less energy will be created or lost during the operation of the system. In this case, then all 600J of energy will be transformed during the operation of car.

This chemical energy, what is it?

kinetic energy, Chemical compounds' bonds contain energy. Chemical reactions have the potential to release chemical energy, frequently in the form of heat; these kinds of reactions are referred to as exothermic. Some of the energy from reactions that need heat input to continue may be stored as chemical energy in newly formed bonds.

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Q10. In an ideal situation without any air resistance, any free-falling body will fall at the same rate of acceleration, regardless of its mass, and thus would simultaneously hit the
ground if released from the same height. However, in real-life scenarios, air resistance plays a vital role in determining the fall rate of any object. Which parameters would affect
the fall if air drag is also considered? Choose all possible answers.
Weight of the object.
>>
Shape of the object.
Density of the air.
Velocity of the object.
Submit

Answers

Velocity of the object parameters would affect the fall if air drag is also considered.

What is velocity in physics with example?

Velocity can be defined as the rate at which that moves in a specific direction. as the velocity of a car driving north on a road or the pace at which a rocket takes off. Because the velocity vector is scalar, its integrand magnitude will always equal the motion's speed.

Can velocity be negative?

A moving object has a negative velocity when it is moving in the wrong direction. If an object is slowing down, its generate and evaluate is pointing away from the direction in which it is moving (in this case, a positive acceleration).

What is the principle of velocity?

An object must move at a constant speed and direction in order to have a constant velocity. The object can only travel in a straight line if the direction is constant. So, motion in a single direction at a constant speed is defined as having a constant velocity.

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What does an old sandwich rotting in a trashcan and building a tower out of magnetic blocks have in common

Answers

An old sandwich rotting in a trashcan and building a tower out of magnetic blocks both are undergoing chemical changes.

What are chemical changes?

Chemical changes are said to occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.

Examples of chemical changes include burning of wood, cooking of pasta, rusting of metal , and rotting of sandwiches.

In conclusion, chemical changes involve the formation of new substances while Physical change is a temporary change.

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A body of mass 2kg falls freely from rest through a height 8m onto a hard floor bounces back to a height of 2m. calculate the change of momentum, if the bady is in contact with the floor for 0.1s, what is the force exerted on the body? (g=10ms^2)​

Answers

The force exerted on the body is 12.66 N.

Linear momentum, translational momentum, or clearly momentum is the made of the mass and velocity of an item. it's miles a vector amount, possessing significance and a path. If m is an object's mass and v is its speed.

Given;

mass = 2 kg

height = 8m

bounce height = 2 m

let velocity just before striking the floor is initial velocity 12.65 m/s

the potential energy at 8 m = mgh

                                        = 2 ×10× 8

                                        = 160 J

same converted into kinetic energy 160 J = 1/2 mv²

                                                               V² = 320/2

                                                                v = 12.65 m/s

Final velocity

mgh = 1/2 mv²

2×10×2 = 1/2×2 × v²

v² = 6.32 m/s

Acceleration = change in velocity per unit of time

                      = - 6.32 - (-12.65)  = 6.33 m/s² / 0.1

Force = mass × acceleration

          = 2 ×  6.33 m/s²

           = 12.66 N

Momentum may be described as a mass in motion. All objects have mass; so if an object is transferring, then it has momentum - it has its mass in movement. the quantity of momentum that an item has depends upon variables: how an awful lot of stuff is moving and the way speedy the stuff is moving.

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What should your guide hand (non shooting hand) do when you shoot a ball?

Answers

Help aim with your other hand so that you can make a basket in the net
Here’s a step by step process that will break this bad shooting habit and keep your guide hand quiet...

Week 1

Step 1 – Put on the J-strap as explained in this video:



Step 2 – Shoot 50 shots away from the basket. You can shoot to a spot on the wall or a line on the floor. Focus on perfect technique for every shot. Take your time. Make sure you have good foot positions, correct grip, etc.

Focus on shooting straight and holding your follow through with perfect technique.

Step 3 – Shooting 50 form shots at the basket. Take your time, shooting about 4 feet from the basket.

Step 4 – Shoot 50-100 mid-range shots. Take 50-100 shots slowly moving away from the basket...

Start 8 feet from the basket. Take 10-20 shots. If you make at least 60% you can move back to one foot (so you now are shooting 9 feet from the basket). Repeat the process and continue moving back one foot at a time until you complete 50-100 shots.

Step 5 – Go home and rest. Return to the gym the following day. Repeat the process (step 1 -4) for one week.

After one week you should have taken over 1000 shots with correct technique… keeping your guide hand still.

Week 2

Repeat the process above WITHOUT the J-strap.


After each shot, check to make sure your guide hand does not move. Make sure the thumb on your guide hand is pointing back towards your head. If it is, that means your guide hand stayed quiet! Good job!

As shown in the picture to the right, your guide hand stays to the side and does not influence the flight of the ball.

Continue shooting. Take your time. Make sure each rep is perfect.

If possible, film yourself shooting to make sure your guide hand is quiet.

CoachesEye has a great app that lets you analyze your shot in slow motion. (Be sure to use 60 FPS so you can see your hand movement clearly.)

If you find your guide hand is still moving, put the J-strap back on and repeat the process from week 1.

Final Thoughts

The solution to breaking a habit is simple. Create a new habit by taking thousands of repetitions the new way.

Unfortunately it is much easier said than done!

We found the process above is a surefire way to get results. Give it a try and let us know what you think.

If it takes more force for an object with more mass to accelerate because it has more inertia and objects with less mass have more acceleration (because a∝1/m in Newton's Second Law F=ma), then why do objects with more mass and objects with less mass accelerate at the same rate towards Earth (about 9.8m/s^2)?

Answers

Explanation:

Gravity is the only force acting on an object in free-fall. According to Newton's second law, the force is equal to mg, so the mass is taken into account there.

In the article the study author recommends going on a photo hunt what was the purpose of this activity with choices becoming less introvered
Becoming less neurotic
Becoming more extroverted
Becoming more assertive

Answers

In the article the study author recommends going on a photo hunt and the purpose of this activity is Becoming more assertive.

What is the reason why the author gave the recommedation about going for the photo hunt ?

The reason why the author gave the recommedation about going for the photo hunt is that the activity can bring about assertiveness which has not been seen in the participants before.

It should be noted that with the assertion, there will be display of  confident as well as  forceful personality as they are taking part in the photo hunt, because it involves the activity whereby the participants will be competing with themselves in the collection of the greatest number of objects which is been goteen from the predetermined list.

In conclsion, the recomedation about going to the photo hunts by te author was made so that they can become more assertive.

Therefore , the last option is correct.

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A rod slides along a metal frame. The earth’s magnetic field is 3.5 × 10−5 T at right angles to the plane of the frame. The rod is of length 0.23 m inside the frame and moves at 0.68 m/s. What is the motional EMF produced by the rod? Answer in units of V.

Answers

The motional EMF produced by the rod is 5.474 × 10⁻⁶ V.

What is electromotive force?

When no current is flowing, electromotive force (EMF) equals the terminal potential difference.

Despite the fact that both EMF and terminal potential difference (V) are expressed in volts, they are not the same thing. EMF is the quantity of energy (E) that the battery supplies to each coulomb of charge (Q) that passes through.

Given parameters:

The earth’s magnetic field; B= 3.5 × 10⁻⁵ T

The length of the rod; l = 0.23 m.

Speed of the rod; v = 0.68 m/s.

So, the motional EMF produced by the rod = Blv

= 3.5 × 10⁻⁵ × 0.23 × 0.68

= 5.474 × 10⁻⁶ V.

Hence, motional EMF produced by the rod is 5.474 × 10⁻⁶ V.

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If I wanted to increase the current, but maintain the voltage in a USB 3.1 port that provides a current of 0.9 A and a voltage of 5 V, to which I have connected a device with 4 ohms of resistance, how would I have to associate several USB ports to achieve this?

Answers

To achieve an increase in the current delivered in the USB 3.1 port, at a constant voltage, the several USB ports must be connect in parallel to each other. This will ensure an increase in current and constant voltage.

What is the relationship between current and resistance?

According to ohms Law the current flowing through an ohmic conductor is directly proportional to the voltage across the conductor.

V = IR

where;

I is the current in the circuitR is the resistance across the circuitV is the voltage across the circuit

I = V/R

To increase the current at a constant voltage, the resistance must decrease.

In a parallel circuit, the current flowing in each circuit component is different while the voltage drop in each circuit component is the same.

Thus, to increase the current delivered in the USB port, and maintain the initial voltage, the several USB ports must be connect in parallel to each other.

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An SUV crashes into a wall. The mass of the vehicle is 2,150 kg and the crumple zone rigidity is 342 kN. Assuming the safety cell is perfectly rigid, what will be the acceleration of the SUV during a crash as the crumple zone is collapsing?

Answers

The acceleration of the SUV during crash as the crumple zone is collapsing is 0.0063 m/s².

What is acceleration?

Acceleration is the ratio of the force on a body to the mass of the body.

To calculate the acceleration of the  SUV, we use the formula below.

Formula:

F = ma............ Equation 1

Where:

F = Crumple zone rigiditym = Mass of the vehiclea = Acceleration of the SUV

Make a the susbject of the equation

a = F/m................. Equation 2

From the question,

Given:

m = 2150 kgF = 342 kN = 342000 N

Substitute these values into equation 2

a = 2150/342000a = 0.0063 m/s²

Hence, the acceleration of the SUV is 0.0063 m/s².

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A 5 -kg ball hangs at one end of a string that is attached to a support on a railroad boxcar. When the boxcar
accelerates to the right, the string makes an angle of 30° with the vertical. The acceleration of gravity is 9.8 m/s
and air resistance is negligible. Find the acceleration of the boxcar

Answers

The acceleration of the boxcar is 5.586m/s².

Explain what an acceleration is.

We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both since velocity is a function of both speed and direction.

Positive acceleration is a property of objects that are accelerating and moving in the right direction. In the first illustration, positive acceleration was demonstrated by the moving car. The acceleration is occurring in the same direction that the vehicle is moving forward and accelerating.

θ = ma/mg

tanθ = a/g

a = tanθ g

a = tan 30×9.8

a = 0.57×9.8

a = 5.586m/s².

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In a barfight, one person swings a punch with their bare hand and knocks another person over a table in spectacular fashion. The person who threw the punch remains stationary, their hand undamaged.

Why does this defy physics? Give Equations/Laws to justify your answer

Answers

The person who threw the punch remains stationary, and their hand undamaged because the impulse received by the opponent is greater than the reaction force experienced by the person who threw the punch.

What is Newton's third law of motion?

Newton's third law of motion states that for every action, there is an equal and opposite reaction. That is, action force and reaction force are equal and opposite.

Mathematically, the Newton's third law of motion can be stated as follows;

Fa = Fb

where;

Fa is the action force applied Fb is the reaction force received due to the applied force

In a barfight, when one person swings a punch with their bare hand and knocks another person over a table in spectacular fashion. The person who threw the punch remains stationary, their hand undamaged because the impulse received by the opponent is greater than the reaction force experienced by the person who threw the punch.

The force applied by the person who threw the punch maybe equal and opposite to reaction he received but the impulse experienced by the opponent is greater.

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2) Calculate the Energy of each of the following
a) Radio waves with a wavelength of 3.0 x 10¹¹ nm (6.626 x 10-28 J)
b) Microwaves with a wavelength of 3.0 x 107 nm (6.626 x 10-24 J)
c) X-Ray at 1nm (1.99 x 10-¹6J)
d) Violet at 400nm (4.97 x 10-¹⁹ J)
e) Red at 700nm (2.84 x 10-¹⁹J)
f) Gamma rays at 1nm (1.98 x 10-¹6J)

Answers

The energy, E of the given waves are as follows:

a. Energy, E  = 6.63 * 10⁻²⁸ J

b. Energy, E  = 6.63 * 10⁻²⁴ J

c. Energy, E  = 1.99 * 10⁻¹⁶ J

d. Energy, E  = 4.97 * 10⁻¹⁹ J

e. Energy, E  = 2.84 * 10⁻¹⁹J

f. Energy, E = 1.99 * 10⁻¹⁶ J

What is the formula to calculate the energy of a wave?

The formula to calculate the energy of a wave s given below as follows:

Energy, E = hc / λ

where;

h is Planck's constant = 6.63 * 10⁻³⁴ Js

c is the velocity of light = 3.0 * 10⁸ m/s

λ is the wavelength of the light

The energies of the waves are calculated as follows:

a. λ = 3.0 x 10¹¹ nm or 3.0 * 10² m

E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 3.0 * 10²

E = 6.63 * 10⁻²⁸ J

b. λ = 3.0 x 10⁷ nm or 3.0 x 10⁻² m

E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 3.0 * 10⁻²

E = 6.63 * 10⁻²⁴ J

c. λ = 1 nm or 1.0 x 10⁻⁹ m

E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 1.0 x 10⁻⁹ m

E = 1.99 * 10⁻¹⁶ J

d. λ = 400 nm or 4.0 x 10⁻⁷ m

E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 4.0 x 10⁻⁷ m

E = 4.97 * 10⁻¹⁹ J

e. λ = 700 nm or 7.0 x 10⁻⁷ m

E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 7.0 x 10⁻⁷ m

E = 2.84 * 10⁻¹⁹J

f. λ = 1 nm or 1.0 x 10⁻⁹ m

E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 1.0 x 10⁻⁹ m

E = 1.99 * 10⁻¹⁶ J

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An apple with mass M is hanging at rest from the lower end of a light vertical rope. A dart of mass M/4 is shot vertically upward, strikes the bottom of the apple, and remains embedded in it.

Answers

The apple moves a height of  h = [tex]\frac{v^{2} }{50 g}[/tex] because of its collision with the dart.

How do we calculate height?

we can calculate the height of an object using the distance and angle.

In order to calculate the height of an apple with mass M is hanging at rest from the lower end of a light vertical rope. A dart of mass M/4 is shot vertically upward, strikes the bottom of the apple, and remains embedded in it.

We first calculate the velocity that the final mass gets once the collision takes place, in order to do this, we use momentum conservation.

pi = Pf = (5/4)Mv

We get the value for the velocity of the final mass, v , once the collision has been produced.

Once we have pi, with this final velocity, we can calculate the final height that the mass will get, to do this we use energy conservation.

An instant after the collision, the mass has kinetic energy, and we say that that is our altitude zero, but when the mass gets to its higher altitude, the kinetic energy is zero and the potential energy is different than zero, and we will write as follows:

Ei = Ef =  (1/2) (5/4 M (V/5)²  =(5/4 M)g*h

Equating and solving for height, we will get as the apple moves a height of  h = [tex]\frac{v^{2} }{50 g}[/tex] because of its collision with the dart.

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2. The total mass of a boy and his bike is 45 kg. The boy rides his bike at a velocity of -5.0 m/s. What is
the boy's momentum?

Answers

The correct answer is momentum of boy = 225 Kg. m /s

What is momentum?

Momentum is the product of the units of mass and velocity is the unit of Momentum.

To get the value the momentum,  formula: P=mv, where P is the momentum.

Given, total mass and boy = 45 Kg., Velocity = -5 m/s

Momentum = Mass x Velocity = 45 Kg.  x 5 m/s = 225 Kg. m / s

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Which has the most momentum?
C: 150 g object at 5 m/s
D: 200 kg object at 2 m/s
A: 50 kg object at 5 m/s
B: 100 kg object at 10 m/s

Answers

Option D) 200 kg object at 2 m/s has the highest momentum.

What is momentum?

Momentum is calculated using Newtonian mechanics by multiplying an object's mass by its velocity.As a vector quantity with both a magnitude and a direction, it has both. Considering that an object's mass is m and its speed is v (also a vector quantity),

Momentum formula,                P = mv

p = momentum

m = mass \ velocity

The newton-second is a unit of measurement for momentum in the International System of Units (SI), and the kilogram metre per second (kg m/s) is its SI counterpart.

A) 50 kg object at 5 m/s

m = 50 kg

v = 5 m/s

Momentum, p = m x v

                       = 50 x 5

                       = 250 kg m/s

B) 100 kg object at 10 m/s

m = 100 kg

v = 10 m/s

Momentum, p = m x v

                       = 100 x 10

                       = 1000 kg m/s

C) 150 g object at 5 m/s

m = 150 g

    = 0.15 kg

v = 5 m/s

Momentum, p = m x v

                       = 0.15 x 5

                       = 0.75 kg m/s

D) 200 kg object at 2 m/s

m = 200 kg

v = 2 m/s

Momentum, p = m x v

                       = 200 x 2

                       = 400 kg m/s

Hence, Option B has the highest momentum.

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Part G
List several examples of applied force, normal force, and friction?

Answers

Examples of following forces mentioned -

Normal  Force   :- Book kept on the table , Girl standing on floor, ...infact every object experience a normal force in the universe.Applied Force    :- this term literally means force responsible for the movements in the object or changes in the object , like throwing stones , playing ball , pushing an object , moving a pen from desk to chair..etc...Friction force     :-Force responsible for the resistance in the flow of system's work , For example air resistance a type of obstruction experienced in air when a Paper ball is thrown from terrace of a society , Viscosity of honey is also an example of liquid friction / viscous drag...Sometimes friction is useful for the stability of universe. But some times its necessary. It is due to this force we walk without collapsing into the core of earth as earth is a market of gravitational field. To substantiate the field effect , friction is necessary to necessitate  the life in planet. Rubbing of hands in winter season is also another example.

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34. An object with mass 5.00 kg is being pushed up an inclined plane with a constant force F. The plane makes an angle of 30.0with respect to the horizontal . The object is moving with constant velocity . The coefficient of kinetic friction between the object and the surface is 0.300 . What is the magnitude of this force ?

Answers

The magnitude of the force is 12.73N.

What is force?

this can be defined as a push or pull in a particular direction. It is calculated using the formula:

F=m*a

Where,

m=mass of the object

a=acceleration

What is magnitude of force?

This is the quantity or strength of the force. It is calculated using the formular:

Normal Force, N=m*g*Cos θ

From the question given:

     m   =5.00kg

Cos θ= 30°

        g=9.8m/s²

Coefficient of Friction, μ=Frictional force/Normal force

                                        =F/N

coefficient kinetic friction, μ=0.300

Magnitude of Force F= Coefficient of Friction*Normal Force

                                   =μN

                                   =μmg Cos θ

                                 F= 0.300*5.00*9.8*Cos30°

                                 F=0.300*5.00*9.8*0.8660

The magnitude of Force,F=12.73N

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