15) Mr. and Mrs. Rupe and their 4 sons are taking a 2500 mile camping trip across country. They plan to spend $120 for campsites per
day. The camper rental fee is $65 a day. While pulling the camper their car has a fuel economy of 8 miles per gallon. They estimate $85
per day for food for the 5-day trip. If gasoline is $1.92 per gallon how much will their trip cost?
O a.) $1950
Ob.) $1850
Oc.) $2950
Od.) $1750

Answers

Answer 1

Answer:

A $1950

Step-by-step explanation:

Food, camper rental and camp site will cost 1350

(120 + 65 + 85)5 = 1350

The trip is 2500 and the car gets  8 miles per gallon  2500/8 = 31.5.  The will need to buy 31.5 gallons of gas at 1.92 a gallon or $600 (31.5 x 1.92).

When we add the cost of gas to the other costs, we get a total of 1950 (1350 + 600)


Related Questions

Find the value of x in each case. Show your work with proper statements and notation. P belongs to line MQ

Answers

Answer:

x = 14

Step-by-step explanation:

PMN forms a triangle and the sum of interior angles in a triangle is equal to 180 therefore we can use the following equation to find the value of x

32 + 64 + 6x = 180 add like terms

96 + 6x = 180 subtract 96 from both sides

6x = 84 divide both sides by 6

x = 14

A couple deposits $20,000 into an account earning 5% annual interest for 30 years. Calculate the future value of the investment if the interest is compounded monthly. Round your answer to the nearest cent.

Answers

The future value of the investment if the interest is compounded monthly is $89,354.89.

What is the future value of the investment?

Given that;

Principal P = $20,000Annual interest rate r = 5% = 5/100 = 0.05Time t = 30 yearsCompound monthly = 12Future value = A = ?

Using the compound interest formula;

A = P( 1 + r/n )^(nt)

We plug in our values.

A = 20000( 1 + 0.05/12 )^(12 × 30)

A = 20000( 1 + 0.0041666666666667)^(360)

A = 20000( 1.0041666666666667)^(360)

A = 20000( 4.46774965 )

A = 89354.89

Therefore, the future value of the investment if the interest is compounded monthly is $89,354.89.

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A Ferris wheel with a diameter of 10 m and makes one complete revolution every 80
seconds. Assume that at time t = 0, the Ferris Wheel is at its lowest height above
the ground of 2 m. You will develop the equation of a cosine graph that models your
height, in metres, above the ground as you travel on the Ferris Wheel over time, t in
seconds. To do this, answer the following questions.


1. State the amplitude of the graph.
2. State the value of k in the general form y = a cos [k(x − d)] + c.
-
3. State the value of d.
4. State the value of c.
5. State the cosine equation of the graph.

Answers

A Ferris wheel with a diameter of 10 m and makes one complete revolution every 80 seconds. Assuming that at time t = 0, the Ferris Wheel is at its lowest height above the ground of 2 m, the cosine equation of the graph drawn is, y = 5 cos [( π/40)(x - (π/2))] + 3.  Here, amplitude of the graph is 5, value of k is  π/40, d is π/2 and c is 3.

Developing the Equation of a Cosine Graph

The given information constitutes the following,

Diameter = 10 m

⇒ Radius, r = 5 m

Time, t = 80 s

Height above the ground, h = 2 m

Thus, we can infer that,

Amplitude, A = 5 m

Period, T = 80 s

Minimum height = 2 m

The cosine function is given as,

a cos [k(x − d)] + c

Here, A is amplitude

B is cycles from 0 to 2π and thus period = 2π/k

d is horizontal shift

c is vertical shift (displacement)

Now, 2π/k = 80

⇒ k = 2π/80 = π/40

The value of c is given as,

c = Amplitude - Minimum height

c = 5 - 2

c = 3

For a shift to the left by π/2 gives, we have,

d = π/2

Thus, the desired equation of the drawn cosine graph is,

y = 5 cos [( π/40)(x - (π/2))] + 3

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The sum of two numbers is 43 . The smaller number is 9 less than the larger number. What are the numbers?

Answers

Answer:

17 & 26

Step-by-step explanation:

The equation

[tex]x+(x+9)=43\\2x+9=43[/tex]

[tex]2x=43-9\\2x=34[/tex]

[tex]x=34/2=17[/tex]

One number is 17

The other number is:

[tex]x+9=17+9=26[/tex]

Hope this helps

Si: x;y∈ℜ y f={(2;8),(x;x+1),(2;x2−2x),(−2;9),(3;9),(y;y−1),(3;y+4)} es una función, calcúlese x y y, dando como respuesta la representación de la función.

Answers

La relación dada es una función si x = 4 y y = - 1. La representación de la función es f= {(2, 8), (4, 5), (- 2, 9), (3, 9), (5, 4)}.

¿Que valores tienen dos variables reales tal que una relación dada es una función?

Las relaciones están formadas por dos conjuntos relacionados entre sí, un conjunto de entrada denominado dominio y uno de salida denominado rango. Una función es una relación cuyos elementos del dominio solo están asociados a un solo valor del rango.

Bajo estas consideraciones, tenemos que (2, 8) = (2, x² - 2 · x) y (3, 9) = (3, y + 4), cuyas ecuaciones algebraicas se resuelven a continuación:

x² - 2 · x = 8     (1)

y + 4 = 9     (2)

By (1):

x² - 2 · x - 8 = 0

(x - 4) · (x + 2) = 0

x = 4 ∨ x = - 2

By (2):

y = 5

Si sabemos que x = 4 y y = - 1, entonces la representación de la función es:

f= {(2, 8), (4, 5), (- 2, 9), (3, 9), (5, 4)}

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Which of these is smaller? 1/3 or 35%

Answers

♨ANSWER♥

1/3 = 1/3 × 100%

= 33%

☆ 33 % < 35 %

Therefore

* 1/3 is the smaller one.

...hope this helps...

_♡_mashi_♡_

The comparison of  1/3 and 35% in decimals shows that 1/3 is smaller than 35%.  

Given that:

The fraction is  1/3 and the number in percentage is 35%.

The conversion of  a fraction to a percentage can be obtained by  dividing the numerator by the denominator and multiply by 100.

The decimal form of the fraction 1/3 is 33.33...%

1/3 ≈ 0.3333...

0.3333... * 100 ≈ 33.33...%

The value 35% is already in percentage.

Since, both the values are in percentage form, it can be easily compared.

On comparing, the resultant would be

33.33...% < 35%

Since 35% is greater than 33.33...%

It can be concluded  that 35% is larger than 1/3.

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The graph of a function is given. Determine whether the function is increasing, decreasing, or constant on the given interval. (-3, 1)

Answers

The information given illustrates that the graph of the function decreasing.

How to illustrate the information?

We say that a function is increasing on an interval if the function values increase as the input values increase within that interval.

Similarly, a function is decreasing on an interval if the function values decrease as the input values increase over that interval.

So according to the given graph on the interval (-3, 1) the graph is decreasing.

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19
Select the correct answer.
Which exponential function has the greatest average rate of change over the interval [0, 2]?
OA j(x) = 3(1.6)²
OB. An exponential function, f, with a y-intercept of 1.5 and a common ratio of 2.
OC.
OD.
g(x)
k(x)

Answers

The function with the greatest average rate of change is the function k(x)

How to determine the function?

The average rate of change is calculated as

[tex]m = \frac{y_2 - y_1}{x_2 -x_1}[/tex]

The interval is [0,2].

So, we have

[tex]m = \frac{y_2 - y_1}{2 -0}[/tex]

[tex]m = \frac{y_2 - y_1}{2}[/tex]

For function j(x), we have

j(2) = 3 * 1.6^2 = 7.68

j(2) = 3 * 1.6^0 = 3

So, we have

[tex]m_j = \frac{7.68 - 3}{2}[/tex]

[tex]m_j = 2.34[/tex]

For function g(x), we have

g(2) = 25/2

g(0) = 8

So, we have

[tex]m_g = \frac{25/2 - 8}{2}[/tex]

[tex]m_g = 2.25[/tex]

For function k(x), we have

k(2) = 9

k(0) = 4

So, we have

[tex]m_k = \frac{9 - 4}{2}[/tex]

[tex]m_k = 2.5[/tex]

For function f(x), we have

f(2) = 1.5 * 2^2 = 6

f(0) = 1.5

So, we have

[tex]m_f = \frac{6 - 1.5}{2}[/tex]

[tex]m_f = 2.25[/tex]

The function with the greatest average rate of change is the function k(x) with a rate of 2.5

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Which transformations must be applied to object A to place it in the position of object B?

rotation and reflection

rotation and translation

reflection and translation

rotation, reflection, and translation

Answers

In order for object A to be placed in the position of object B, there needs to be a rotation and translation.

How would object A get to object B?

The first step would be to rotate object A to the left to give it the same orientation as object B.

Then, translate object A to the coordinates of object B. This would lead to object A fitting into object B.

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The weight of each “Golden Dairy’s Probiotic Yogurt with Fruit” cup is normally distributed with a mean of 170 grams and a standard deviation of 12 grams. One package contains six random cups and any package with an average weight per cup lower than 158 grams will be rejected.
Part A: What fraction of packages will be rejected because the average weight is too low?
Part B: In addition to original rejection criteria, suppose any packages that have an average weight per cup higher than 179 grams must be rejected as well. What is the total fraction of packages that will be accepted?

Answers

Using the normal distribution, it is found that:

A. 0.0071 = 0.71% of packages will be rejected because the average weight is too low.

B. 0.96 = 96% of packages that will be accepted.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For this problem, the parameters are given as follows:

[tex]\mu = 170, \sigma = 12, n = 6, s = \frac{12}{\sqrt{6}} = 4.9[/tex]

Item A:

The proportion is the p-value of Z when X = 158, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{158 - 170}{4.9}[/tex]

Z = -2.45

Z = -2.45 has a p-value of 0.0071.

0.0071 = 0.71% of packages will be rejected because the average weight is too low.

Item B:

The proportion that will be accepted is the p-value of Z when X = 179 subtracted by the p-value of Z when X = 158, hence:

X = 179:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{179 - 170}{4.9}[/tex]

Z = 1.84

Z = 1.84 has a p-value of 0.9671.

X = 158:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{158 - 170}{4.9}[/tex]

Z = -2.45

Z = -2.45 has a p-value of 0.0071.

0.9671 - 0.0071 = 0.96 = 96% of packages that will be accepted.

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match the expressions with their resultant terms in exponential form.
137
1319
131
13-22
13-14
1315
13-7
Resultant Terms in Exponential Form
Expressions
13-11 × 1316 × 13-3 × 134 × 13-5
arrowBoth
13-21 × 13-4 × 13-5 × 1314 × 13-6
arrowBoth
1333 × 13-2 × 135 × 13-13 × 13-8
arrowBoth
130 × 1310 × 13-12 × 135 × 134
arrowBoth

Answers

The correct matching of the exponential form is given.

How to illustrate the information?

1: 13^-11 × 13^16 × 13^-3 × 13^-4 × 13^-5

= 13

2. 13^-21 × 13^-4 × 13^-5 × 13^14 × 13^-6

= 13^-22

3. 13^0 × 13^10 × 13^-12 × 13^5 × 13^4

= 13^7

This illustrates the exponential form.

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What is the probability of flipping a coin once and getting heads if you have gotten 5 tails in a row before that?
a. 1/32
b. 1/5
c. 1/4
d. 1/2​

Answers

Answer:

Answer is..... D

Step-by-step explanation:

every single flipping may two results, head or tail.So last one has equal chance.

What is the following product 3 root 24 • 3 root 45

Answers

Answer:

54sqrt(30)

Step-by-step explanation:

3sqrt(24) can be simplified to 6sqrt(6) as 24 can be written as 4 * 6 and 4 is a perfect square

3sqrt(45) can also be written as 9sqrt(5) as 45 can be written as 5 * 9 and 6 is a perfect square

you can multiply 6sqrt(6) * 9sqrt(5) as though the square roots were variables

so

54sqrt(30)

this is your final answer

the rounded answer is 295.770181


Solve the equation 5 (x + 1) = 5x

Answers

[tex]\textbf{Heya !}[/tex]

✏[tex]\bigstar\textsf{Given:-}[/tex]✏

an equation = [tex]\sf{5(x+1)=5x}[/tex]

✏[tex]\bigstar\textsf{To\quad find:-}[/tex]

x = ?

✏[tex]\bigstar\textsf{Solution \quad steps:-}[/tex] ✏

first use the distributive property

[tex]\sf{\longmapsto{ 5x+5=5x}[/tex]

subtract both sides  by 5x

[tex]\sf{\longmapsto{0x+5=0}[/tex] (strange expression right)

[tex]\sf{\longmapsto 0=-5}[/tex] (whattt ?!)

the above statement's false, so the equation has no solutions

`hope that was helpful to u ~

Write these decimals in order from smallest to largest: 0.507, 0.75, 0.5, 0.078

Answers

0.078, 0.5, 0.507, 0.75.

Hope it helps ; )
0.078, 0.5, 0.507, 0.75

In ΔABC, BC = 13, CA = 20 and AB = 19. Which statement about the angles of ΔABC must be true?
m∠B > m∠A > m∠C
m∠C > m∠B > m∠A
m∠A > m∠B > m∠C
m∠C > m∠A > m∠B
m∠B > m∠C > m∠A
m∠A > m∠C > m∠B​

Answers

Answer:

m∠B > m∠C > m∠A

Step-by-step explanation:

The angle opposite the largest side in a triangle is the largest, and the angle opposite the shortest side is the smallest.

while sshopping ,you see a jacket mark down 20%.if the original price of the jacket $175.what is the sale price of the jacket?

Answers

The sales price of the jacket is $140.

What is a markdown price?

A price markdown is a planned decrease in the retail item's selling price. It is used to accelerate an item's sales rate, usually for clearing at the closing of a season or to get rid of outdated goods when their useful lives have passed.

Markdown prices are reductions in a product's selling price from its initial selling price expressed as a rate called markdown percentage. Markdown prices are more commonly referred to as discounts. 

From the given information:

The markdown price of the jacket  = 20% of the original price.If the original price of the jacket is $175.

Then the sales price of the jacket is:

= $175 - (20% of $175)

=$175 -  $35

= $140

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they’re 25 student’s 14 female and 11 male two students are selected at random to participate in a probability experiment. compute that
b) a male is selected then a female
c) a female selected then a male
d) two females are selected
e) no males are selected

Answers

The probabilities in each of the given categories are; A) 51.33%; B) 51.33% C) 30.33% D) 30.33%

How to find the Probability of Selection?

The number of ways to select 2 out of 25 is; 25C2 = 25! / (23! * 2!)

= 25*24/2

= 300

(A) Probability of selecting 1 male and 1 female:

[(11C1) * (14C1)]/300 = [11!/(10! * 1!)] * [(14!/(12! * 2!))

= 51.33%

(B)  Probability of selecting 1 female and 1 male:

[(14C1) * (11C1)]/300 = 51.33%

                                           

(C)   Probability that 2 females are selected is;

(14C2)/300 = 30.33%

D) Probability that no males are selected is;

P(no males) = (11C0 * 14C2 )/300 = 30.33%

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Theo solved the following problem correctly for homework.

2 x + y = 7. Negative 3 x + y = 2.

What is the y-coordinate of his solution?
y = negative 3
y = negative 1
y = 1
y = 5

Answers

Answer:

y=5

Step-by-step explanation:

OK, let see, 2x+y=7, –3x+y=2:

[tex]2x + y = 7 \\ - 3x + y = 2 \\ we \: need \: to \: solve \: the \: equation \: so \\ - 2x - y = - 7 \\ - 3x + y = 2 \\ - 5x = - 5 = = > x = 1 \\ 2(1) + y = 7 = = = > y = 5[/tex]

in triangle ABC, AC=13, BC=84, and AB=85. find the measure of angle C.

Answers

The sides all satisfy the Pythagorean Theorem so it is a right triangle. I attached an image of how the triangle should look like and as you can see, the angle is 90 degrees or pi/2 radians.

in triangle ABC, AC=13, BC=84, and AB=85.  the measure of angle is C.5.1 degrees,

How can the angle be found?

Using the The Law of Cosines in any triangle which can be expressed as;

[tex]c^2 = a^2 + b^2 - 2ab * cos(C)[/tex]

Then if we expressed the given sides in the cosine formula we have

[tex]13^2 = 85^2 + 84^2 - 2 * 85 * 84 * cos(C)[/tex]

Then we have [tex]169 = 7225 + 7056 - 14280 * cos(C)[/tex]

[tex]14280 * cosC = (7225 + 7056 - 169)[/tex]

[tex]cosC = \frac{14212}{ 14280}[/tex]

cos 0.9947

[tex]C = cos^-1(0.9947)[/tex]

C = 5.1 degrees

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Find the constant of variation when t varies directly as the square of s, and t = 64 when S = 4.

Answers

Answer:

The constant of variation is 4

Step-by-step explanation:

We are looking for the constant of variation when t varies directly as the square of s

t = k s^2  where k is the constant of variation

t = 64 and s = 4

64 = k  4^2

64 = k * 16

Divide each side by 16

64/16 = k * 16/16

4 = k

The constant of variation is 4

Complete the solution of the equation. Find
the value of y when x equals 4.
-3x + 9y = -57

Answers

Answer: -5

Step-by-step explanation:

-3x+9y=-57                x=4

-3(4)+9y=-57

-12+9y=-57

             +12

9y=-45

    9y

y=-5

any answer is better than mine. need help asap

Answers

From the line bisected with the given midpoints, we have been able to prove that; BC = CE by substitution property of Equality

How to prove bisection of a Line?

We are given that;

C is the midpoint of BD

D is the midpoint of CE

1) Thus, BC = CD because of definition of Midpoint.

2) Similarly, by definition of midpoint we know that CD = DE.

3)  We can say that BC = DE because of substitution property of equality.

4) We can say that BC + CD = BD because of segment addition postulate.

5) Similarly, by segment addition postulate, we can say that CD + DE = CE.

6) Finally we can say that BC = CE by substitution property of Equality

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1
Select the correct answer from each drop-down menu.
Ray and Terry work in the same office. They sit across from each other at fixed desks that are separated by a partition, or a short dividing wall,
exactly halfway between them. The distance between the end of each desk and the partition is 35 inches. For both Ray and Terry, the top of the
partition is at an angle of elevation of 30° with respect to the end of the desk. This scenario can be modeled by the given diagram.

Answers

Ray has the incorrect reasoning because he incorrectly select the sine  function when he should have utilized the tangent.

How to find the height of a right triangle?

A right angle triangle is a triangle that has one of its angles as 90 degrees.

The height of the ray can be found using trigonometric ratios.

Therefore,

tan 30 = opposite / adjacent

where

opposite side = height

adjacent side = 35 inches

Therefore,

tan 30° =  height / 35

cross multiply

height = 35 tan 30°

height = 20.2072594216

height = 20.21 inches

Therefore, Ray has the incorrect reasoning because he incorrectly select the sine  function when he should have utilized the tangent.

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Answer:

1. Ray

2. Sine

3. Tangent

Step-by-step explanation:

Plato/Edmentum

Which of these is equal to ⅔ × ¾ × ⅗?

Answers

Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers)  and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5  would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor.  I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers.  I will choose 3.  I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathsf{\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{3}{5}}[/tex]

[tex]\huge\textbf{Simplifying:}[/tex]

[tex]\mathsf{\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{3}{5}}[/tex]

[tex]\mathsf{= \dfrac{2\times3\times3}{3\times4\times5}}[/tex]

[tex]\mathsf{= \dfrac{6\times3}{12\times5}}[/tex]

[tex]\mathsf{= \dfrac{18}{60}}[/tex]

[tex]\mathsf{= \dfrac{18\div3}{60\div 3}}[/tex]

[tex]\mathsf{= \dfrac{6}{20}}[/tex]

[tex]\mathsf{= \dfrac{6\div2}{20\div2}}[/tex]

[tex]\mathsf{= \dfrac{3}{10}}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\frak{\dfrac{3}{10}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

PLEASE IF ANYONE CAN HELP I HAVE 35 MINUTES LEFT 1-8 ANSWERS ONLY WILL DO THANK YOU

Answers

Answer:

1. x=2       2.

y=1

Step-by-step explanation:

Im sorry I TRIED :(

Given the similar hexagon-based prisms pictured below, if prism 2 has a surface area of 256 cm, what is the surface area prism 1? Hint : the ratio of surface areas is the scale factor squared.

Answers

Using the hint that the ratio of surface areas is the scale factor squared, the surface area of prism 1 is 36 square cm

How to determine the surface area prism 1 using the hint that the ratio of surface areas is the scale factor squared?

From the figure, we have the following parameters

Prism 1 = 3 cm

Prism 2 = 8 cm

Calculate the scale ratio of dilation from prism 2 to prism 1 using the following equation

Scale ratio = Prism 1/Prism 2

Substitute the known values in the above equation

Scale ratio = 3m/8m

This gives

Scale ratio = 0.375

The surface area of prism 1 is then calculated using the following equation

Area of prism 2 = Scale ratio^2 * Area of prism 1

Substitute the known values in the above equation

Area of prism 2 = 0.375^2 * 256 square cm

Evaluate the product

Area of prism 2 = 36 square cm

Hence, the surface area of prism 1 is 36 square cm

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A company determines that the revenue, in dollars, for selling a particular model of lamp is given by R(x)=x(−20x+1200), where x is the price of each lamp. At which of the following prices will the company’s revenue be $10,000?

Answers

The price that will maximize company’s revenue of $10,000 is $50.

How to calculate the price?

From the information, the company determines 50that the revenue, in dollars, for selling a particular model of lamp is given by R(x)=x(−20x+1200),

Therefore, this will be:

R(x) = -20x² + 1200x

10000 = -20x² + 1200x

-20x² + 1200x - 10000 = 0

x² - 60x + 500

x² - 50x - 10x + 500

x(x - 50) - 10(x - 50)

(x - 50)(x - 10)

Therefore, x - 50 = 0

x = 0 + 50 = 50

The price is 50.

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PLEASE ANSWER PLEASE ANSWER

2. The spread of the Ebola virus in Africa in 2014 could be modeled by where C(1) represents the number of cases, and t represents the number of days since May 1, 2014). (source: http://www.geert.io/exponential-growth-of

ebola.html) a. [3 pts] Approximately how many cases were there on May 1, 2014 (round to two decimal places)?

b. [3 pts] How many cases were projected by November 24, 2014 (round to 2 decimal places)?

c. [4 pts] Find C(92) and explain what it means in the context of the problem.​

Answers

(a) The number of cases on May 1, 2014, was approximately 188.59.

(b) The number of cases on November 24, 2014, was approximately 27107.76.

(c) C(92) = 1715.70.

This means that on the 92nd day from May 1, 2014, the number of Ebola cases in Africa was approximately 1715.70.

Computed using the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].

We are given that the spread of the Ebola virus in Africa in 2014 could be modeled by the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex], where C represents the number of cases and t represents the number of days since May 1, 2014.

(a) In the question, we are asked for the approximate number of cases on May 1, 2014.

Since, the date is May 1, 2014, t = 0.

Thus, the number of cases, C, can be calculated by putting t = 0, in the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].

[tex]C(0) = 188.59e^{0.024*0}\\\Rightarrow C(0) = 188.59e^0\\\Rightarrow C(0) = 188.59[/tex]

Thus, the number of cases on May 1, 2014, was approximately 188.59.

(b) In the question, we are asked for the approximate number of cases on November 24, 2014.

Since, the date is November 24, 2014, t = 207.

Thus, the number of cases, C, can be calculated by putting t = 207, in the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].

[tex]C(207) = 188.59e^{0.024*207}\\\Rightarrow C(207) = 188.59e^{4.968}\\\Rightarrow C(207) = 188.59*143.739121458\\\Rightarrow C(207) = 27107.76[/tex]

Thus, the number of cases on November 24, 2014, was approximately 27107.76.

(c) We are asked to find C(92).

This can be found by putting t = 92, in the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].

[tex]C(92) = 188.59e^{0.024*92}\\\Rightarrow C(92) = 188.59e^{2.208}\\\Rightarrow C(92) = 188.59*9.09750317953\\\Rightarrow C(92) = 1715.70[/tex]

Thus, C(92) = 1715.70.

This means that on the 92nd day from May 1, 2014, the number of Ebola cases in Africa was approximately 1715.70.

The complete question is:

"The spread of the Ebola virus in Africa in 2014 could be modeled by [tex]C(t) = 188.59e^{0.024t}[/tex] where C represents the number of cases and t represents the number of days since May 1, 2014. (source: http://www.geert.io/exponential-growth-of-ebola.html)

a. [3 pts] Approximately how many cases were there on May 1, 2014?

b. [3 pts] How many cases were projected by November 24, 2014?

c. [4 pts] Find C(92) and explain what it means in the context of the problem.

Learn more about exponential equations at

https://brainly.com/question/27161222

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lim f(x) 2^x-1/x. Find the limit of x as x approaches 0

Answers

The limit happens to be the derivative of [tex]2^x[/tex] at [tex]x=0[/tex]:

[tex]\displaystyle f'(c) = \lim_{x\to c}\frac{f(x)-f(c)}{x-c} \implies \lim_{x\to0} \frac{2^x - 1}x = (2^x)'\bigg|_{x=0} = \ln(2)\,2^x \bigg|_{x=0} = \boxed{\ln(2)}[/tex]

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