1.a) express 64 in the form of 2^p

b)hence find the value of p when:
2^p= 1/64​

Answer:

Length of diagonal = 6

Step-by-step explanation:

Given that

Diagonal of a rectangle makes an angle of [tex]30^\circ[/tex] with the longer side.

Kindly refer to the attached diagram of the rectangle ABCD such that diagonal BD makes angles of [tex]30^\circ[/tex] with the longer side CD and BA.

[tex]\angle CDB =\angle DBA =30^\circ[/tex]

Side AD = BC = 3 units

To find:

Length of diagonal BD = ?

Solution:

We can use the trigonometric ratio to find the diagonal in the [tex]\triangle BCD[/tex] because [tex]\angle C =90^\circ[/tex]

Using the sine :

[tex]sin\theta = \dfrac{Perpendicular }{Hypotenuse }[/tex]

[tex]sin\angle CDB = \dfrac{BC}{BD}\\\Rightarrow sin30^\circ = \dfrac{3}{BD}\\\Rightarrow \dfrac{1}2 = \dfrac{3}{BD}\\\Rightarrow BD =2 \times 3 \\\Rightarrow BD = \bold{6 }[/tex]

So, the answer is:

Length of diagonal = 6

Answer:

[tex]\huge\boxed{x = 8}[/tex]

Step-by-step explanation:

[tex]\sf -18 = -3x+6\\Subtracting \ 6 \ to \ both \ sides\\-18-6 = -3x\\-24 = -3x\\Dividing \ both \ sides \ by \ -3\\8 = x\\OR\\x = 8[/tex]

Answer:

x = 8

Step-by-step explanation:

Here, -3x = -24

x = 8

hope that helps you

Answer:

B = (3.3)

Step-by-step explanation:

Answer:

Step-by-step explanation: Given that a civil servant own a car is 1/6.

A) The Pr. that each own a car = Pr of each multiplied by the other.

Pr = 1/6 ×1/6

P = 1/36

B) Pr that only one owns a car

= 1/6 × (1-1/6) + 1/6 × (1-1/6)

= 1/6 × 5/6 + 5/6 × 1/6

= 5/36 + 5/36

= 10/36

= 5/18

Answer:

True.

Step-by-step explanation:

Cheetahs can reach speeds of 109.4–120.7 km/h (68.0–75.0 mph), and some have been recorded at over 80mph. The cheetah can accelerate from 0 to 96.6 km/h (60.0 mph) in under three seconds, though endurance is limited.

The second fastest land animal is the Pronghorn antelope at 98kph (60mph).

Answer:

It is a Fact because it can run 70mph or 112kph

The data from a dot plot can be analyzed to find the five number summary, from which a box plot can be constructed

The correct option for the details of the box plot that represents the dot plot data is;

Box plot titled ACT Score with a minimum of 18, quartile 1 of 21, median of 22, quartile 3 of 23, and maximum of 25

The process of deriving the five number summary of the box plot above is as follows;

Known:

The data from the dot plot can be expressed in increasing order for analysis of a box plot as follows;

18, 19, 19, 19, 21, 21, 21, 21, 22, 22, 22,22, 23, 23, 23, 24, 24, 25

The number of data points in the statistics, n = 18

Unknown:

The five number summary

Method:

Finding the five number summary as follows;

The minimum value = 18

The maximum value = 25

∴ Quartile 1 = Q₁ = 5th term = 21

Quartile 2 = 22

Quartile 3 = 23

Combining the above 5 number summary, the correct option for the box plot representing the dot plot data, is therefore;

Box plot titled ACT Score with a minimum of 18, quartile 1 of 21, median of 22, quartile 3 of 23, and maximum of 25

Learn more about box and whiskers, and dot plots here;

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Answer:

The corresponding point is (-8, -6).

Step-by-step explanation:

Given that

(-6,-6) lies on the graph of [tex]f(x)[/tex]

A function is represented in the form:

[tex]y = f(x)[/tex]

i.e. (-6,-6) means value of x = -6 is put and value y came out as -6.

[tex]f(-6) = -6[/tex]

Now, we have to find the corresponding point on [tex]f(\frac{3}{4}x)[/tex].

We know the value of [tex]f(-6)[/tex]

Let us find the value of x where [tex]\frac{3}{4}x[/tex] becomes equal to -6

[tex]\dfrac{3}{4}x=-6\\\Rightarrow 3x=-24\\ \Rightarrow x =-8[/tex]

So, let us put value of [tex]x = -8[/tex] in [tex]f(\frac{3}{4}x)[/tex]:

[tex]f(\frac{3}{4}\times (-8))\\\Rightarrow f(3\times (-2))\\\Rightarrow f(-6) = -6[/tex](as per given statement)

So, the corresponding point is (-8, -6).

Answer:

8

Step-by-step explanation:

khan

Answer:

8

Step-by-step explanation:

The correct solution graph to the inequalities are

[tex]4(9x-18)>3(8x+12)[/tex]  →  C

[tex]-\frac{1}{3}(12x+6) \geq -2x +14[/tex]  → A

[tex]1.6(x+8)\geq 38.4[/tex]  →  B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

[tex]4(9x-18)>3(8x+12)[/tex]

First, clear the brackets,

[tex]36x-72>24x+36[/tex]

Then, collect like terms

[tex]36x-24x>36+72\\12x >108[/tex]

Now divide both sides by 12

[tex]\frac{12x}{12} > \frac{108}{12}[/tex]

∴ [tex]x > 9[/tex]

For the second inequality

[tex]-\frac{1}{3}(12x+6) \geq -2x +14[/tex]

First, clear the fraction by multiplying both sides by 3

[tex]3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)[/tex]

[tex]-1(12x+6) \geq -6x +42[/tex]

Now, open the bracket

[tex]-12x-6 \geq -6x +42[/tex]

Collect like terms

[tex]-6 -42\geq -6x +12x[/tex]

[tex]-48\geq 6x[/tex]

Divide both sides by 6

[tex]\frac{-48}{6} \geq \frac{6x}{6}[/tex]

[tex]-8\geq x[/tex]

∴ [tex]x\leq -8[/tex]

For the third inequality,

[tex]1.6(x+8)\geq 38.4[/tex]

First, clear the brackets

[tex]1.6x + 12.8\geq 38.4[/tex]

Collect likes terms

[tex]1.6x \geq 38.4-12.8[/tex]

[tex]1.6x \geq 25.6[/tex]

Divide both sides by 1.6

[tex]\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}[/tex]

∴ [tex]x \geq 16[/tex]

Let the graphs be A, B and C from left to right

The first graph (A) shows [tex]x\leq -8[/tex] and this matches the 2nd inequality

The second graph (B) shows [tex]x \geq 16[/tex] and this matches the 3rd inequality

The third graph (C) shows [tex]x > 9[/tex] and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

[tex]4(9x-18)>3(8x+12)[/tex]  →  C

[tex]-\frac{1}{3}(12x+6) \geq -2x +14[/tex]  → A

[tex]1.6(x+8)\geq 38.4[/tex]  →  B

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Answer:

4(9x − 18) > 3(8x + 12) = x > 9

(12x + 6) ≥ -2x + 14 = x ≤ -8

1.6(x + 8) ≥ 38.4 = x ≥ 16

Just follow the numbers with the dotted thing and see the numbers I underlined.

Step-by-step explanation:

Use the properties of inequality and real numbers to solve each inequality.

4(9x − 18) > 3(8x + 12)

36x − 72 > 24x + 36

12x − 72 > 36

12x > 108

x > 9

The graph has an open circle at 9, and moves toward the right on the number line.

(12x + 6) ≥ -2x + 14

12x + 6 ≤ 6x − 42

6x + 6 ≤ -42

6x ≤ -48

x ≤ -8

The graph has a closed circle at -8, and moves toward the left on the number line.

1.6(x + 8) ≥ 38.4

x + 8 ≥ 24

x ≥ 16

The graph has a closed circle at 16, and moves toward the right on the number line.

Answer:

$420

.8 x = 336

x = 336/.8

X=$420

Step-by-step explanation:

Answer:

[tex]x = 2.75[/tex]

Step-by-step explanation:

I'm assuming you have an equation

[tex]12x + 7 = 40\\[/tex]

and you want to solve for x.

This is easy. First, subtract 7 from each side of the equation.

[tex]12x+7-7 = 40-7[/tex]

[tex]12x = 33[/tex]

Then divide both sides by 12, to get x alone on the left side.

[tex]\frac{12x}{12} = \frac{33}{12}[/tex]

[tex]x = \frac{33}{12} = 2.75[/tex]

Answer:

$8

Step-by-step explanation:

Firstly, Let us identify the variables in the functions.

The function states that for every n ball, the price is $0.80. Plus the $5.50.

Now that we know what the function stands for, we can substitute 10 into n, and remove the entrance fee of $5.50.

P=0.80n

This gives us $8, which means the price for 10 balls not including the entrance fee is $8.

Answer:

Step-by-step explanation:

16y = 80

You want to get y by itself so you divide 80 by 16

y = 80/16

y = 5

Hope I helped

The solution to the equation 16y = 80 is y = 5.

To solve the equation 16y = 80 for the variable y, you can follow these steps:

Step 1: Divide both sides of the equation by 16 to isolate the variable y:

(16y)/16 = 80/16

y = 5

Therefore, the solution to the equation is y = 5.

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No they are not the same.

We can plug in x = 0 to get

11-2x = 11-2(0) = 11-0 = 11

2x-11 = 2(0)-11 = 0-11 = -11

We get the results 11 and -11 for the expressions 11-2x and 2x-11 respectively. Since we got different outputs, this is enough to show that the expressions are not the same. They would need to produce the same outputs for any given x value.

On a graph, y = 11-2x and y = 2x-11 are two different lines to show they are not the same expression.

note: if you plug in x = 11/2 = 5.5, then both outputs are the same; otherwise, you'll get different outputs.

Answer:

Amdjss

Step-by-step explanation:

You can do the proportion  

1 inch/ 80 miles =x inch/ 1100 miles

1100=80x

11oo divided by 80 equals 13.75

The trip would be about 13.75 inches on the map

Feel free to brainliest :)

Answer:

13.75 inches

Step-by-step explanation:

To find an estimated distance on the map, we can simply create a proportion.

Let X represent the unknown distance in inches on the map.

1100 miles / 80 miles = X inches / 1 inch

Now let's solve for X.

X inches = (1100 miles / 80 miles) * 1 inch

X inches = 13.75 inches

So the approximate travel distance on the map will be 13.75 inches.

Hey There!!

Your best choice is 76%

Because, 19/25 = x/100

25x = 1900

x = 76

°He got 76% correct!!°

By °Itsbrazts°

Answer:

76%

Step-by-step explanation:

Thomas got 19/25 marks.

** Note: Percents are always out of 100.

We don't know how many marks he got out of 100.

=> 19/25 = x/100

There are two ways to solve it from now.

=> Multiply 19 and 100; 25 and x

=> 25x = 1900

Next, Divide 25 on each side.

=> 25x/25 = 1900/25

=> x = 76

He got 76% on the quiz.

Another way is:

=> 19/25 = x/100

=> We need to divide 25 from 100.

=> We get 4.

So, 25 x 4 = 100

=> 19 x 4 = x

=> x = 76

He got 76% on the quiz.

Both ways are correct.

Step-by-step explanation:

1+6k=25

collect like terms

1-25=6k

-24=6k

divide both sides by 6

-4=k

;- k= -4

The scale factor of the dilation is 0.78

The centre of dilation is located at (0,0)

The scale factor of a dilation is the ratio of the corresponding component of the final image to the original image.

According to the image given, the scale factor will be the ratio of the radius of the final image to the original image as shown below:

[tex]Scale \ factor = \frac{small \ radius}{large \ radius} \\Scale \ factor = \frac{7}{9}\\ Scale \ factor=0.78[/tex]

Hence the scale factor of the dilation is 0.78

The centre of dilation is located at the origin because the radius is the distance between the centre of the circle and its circumference. We can therefore conclude that the centre of dilation is located at (0,0)

The scale factor of the dilation is [tex]\frac{7}{9}[/tex].

The center of dilation is a point to the right of both circles.

From Analytical Geometry we know that every Circle is defined by its Radius, its form is directly proportional to its radius. Hence, the Scale Factor of the Dilation ([tex]f[/tex]) is the following ratio:

[tex]f = \frac{r_{2}}{r_{1}}[/tex] (1)

Where:

[tex]r_{1}[/tex] - Radius of the original circle.

[tex]r_{2}[/tex] - Radius of the dilated circle.

If we know that [tex]r_{1} = 9[/tex] and [tex]r_{2} = 7[/tex], then the scale factor of the dilation is:

[tex]f = \frac{7}{9}[/tex].

The scale factor of the dilation is [tex]\frac{7}{9}[/tex].

There is a geometrical approach to determine the location of the Center of Dilation. We draw two lines tangent (blue lines) to both circles and we extend to the right of the scene, the point in which both intersects each other is the location of the center of dilation. (representation is included in the image attached below)

In a nutshell, the center of dilation is a point to the right of both circles.

Answer:

[tex]5(4)^x=320\\\frac{5(4)^x}{5}=\frac{320}{5}\\ 4^x=64\\x*(log(4) )=log(64)\\x=\frac{log(64)}{log(4)}\\ x=3[/tex]

Step-by-step explanation:

Answer:

A. 48

Step-by-step explanation:

There is a diameter of the circle through point O. The bottom right angle is an inscribed and that intersects a diameter, so its measure is 90 deg.

a + 90 + 42 = 180

a + 132 = 180

a = 48

The measure of angle 'a' is 48°.

We need to find the measure of 'a'.

Angles are formed by drawing lines from the ends of the diameter of a circle to its circumference from a right angle.

There is a diameter of the circle through point O. The bottom right angle is inscribed and that intersects a diameter, so its measure is 90°.

Now, a + 90°+ 42° = 180°

⇒a + 132°= 180°

⇒a = 48°

Therefore, the measure of angle 'a' is 48°.

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-5,3,-2,1 on a number line

<-|----|----|----|----|----|----|----|----|->

-5 -2 0 1 3

The statements that can be used to describe the reasoning used to determine if Kelsey’s inequality is correct include:

It should be noted that the inequality symbol is incorrect because she can spend up to and including $65.

Based on the information given, the correct expression that can be used to solve the question should be:

65 - (5.50b + 7.5)

In conclusion, the correct options are B and C.

Read related link on:

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Answer:

B and C

Step-by-step explanation:

Answer:

4 pieces

Step-by-step explanation:

Total length of lumber = 9 feet

How many 2 1/4 foot pieces can you cut from this piece of lumber

To find the number of 2 1/4 foot pieces of lumber in a 9 feet of lumber, we will divide the total length of lumber by the length of each piece of lumber

9 ÷ 2 1/4

= 9 ÷ 9/4

= 9 × 4/9

= 36/9

= 4 pieces of lumber

Therefore, 4 pieces of 2 1/4 foot of lumber can be gotten from 9 feet of lumber

Answer:

XY = 17

Step-by-step explanation:

Intersect secant theorem, EX * EY = EZ*EW

34 * EY = 25.5 * 68

      [tex]EY = \frac{25.5*68}{34}\\\\ = 25.5* 2\\\\ = 51.0 = 51[/tex]

EY  = 51

EX + XY = 51

 34 + XY = 51

        XY = 51 - 34 = 17

Answer:

Hello,

Answer B

Step-by-step explanation:

[tex]C(x)=300*x^2+200*x\\\\R(x)=-0.5*x^3+900*x^2-500*x+400\\\\\\P(x)=R(x)-C(x)\\\\=-0.5*x^3+900*x^2-500*x+400-(300*x^2+200*x)\\\\=-0.5x^3+900x^2-300x^2-500x-200x+400\\\\=-0.5x^3+600x^2-700x+400\\[/tex]

Answer:

1. One Solution

Step-by-step explanation:

y=2x+1

−3y=6x+6

Divide the second equation by -3

−3y/-3=6x/-3+6/-3

y = -2x-2

The slopes are different so we know that the lines are not parallel

The will intersect at a point

There will be one solution

We know

[tex]\boxed{\sf Area=Length\times Width}[/tex]

[tex]\\ \sf\longmapsto 336=x(x+5)[/tex]

[tex]\\ \sf\longmapsto x^2+5x=336[/tex]

[tex]\\ \sf\longmapsto x^2+5x-336=0[/tex]

[tex]\\ \sf\longmapsto x^2-16x+21x-336=0[/tex]

[tex]\\ \sf\longmapsto x(x-16)+21(x-16)=0[/tex]

[tex]\\ \sf\longmapsto (x-16)(x+21)=0[/tex]

[tex]\\ \sf\longmapsto (x-16)=0\:or\:(x+21)=0[/tex]

[tex]\\ \sf\longmapsto x=16\:or\:x=-21[/tex]

[tex]\\ \sf\longmapsto Length=x=16yd[/tex]

[tex]\\ \sf\longmapsto Width=x+5=16+5=21yd[/tex]

Answer:

Option B, random sample

That should be the answer