Answer:
always use insulated wire and use all the electrical appliances in proper way
When a rubber ball dropped from rest bounces off the floor, its direction of motion is reversed becaue
(A) energy of the ball is conserved
(B) momentum of the ball
(C) the floor exerts a force on the ball that stops its fall and then drives it upward
(D) the floor is in the way and the ball has to keep moving
(E) none of the above
Answer:In physics, energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object.[note 1] Energy is a conserved quantity; the law of conservation of energy states that energy can be converted in form, but not created or destroyed. The SI unit of energy is the joule, which is the energy transferred to an object by the work of moving it a distance of 1 metre against a force of 1 newton.
Common forms of energy include the kinetic energy of a moving object, the potential energy stored by an object's position in a force field (gravitational, electric or magnetic), the elastic energy stored by stretching solid objects, the chemical energy released when a fuel burns, the radiant energy carried by light, and the thermal energy due to an object's temperature.
Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.
Living organisms require energy to stay alive, such as the energy humans get from food. Human civilization requires energy to function, which it gets from energy resources such as fossil fuels, nuclear fuel, or renewable energy. The processes of Earth's climate and ecosystem are driven by the radiant energy Earth receives from the sun and the geothermal energy contained within the earth.
Explanation:
Some forms of energy (that an object or system can have as a measurable property)
Type of energy Description
Mechanical the sum of macroscopic translational and rotational kinetic and potential energies
Electric potential energy due to or stored in electric fields
Magnetic potential energy due to or stored in magnetic fields
Gravitational potential energy due to or stored in gravitational fields
Chemical potential energy due to chemical bonds
Ionization potential energy that binds an electron to its atom or molecule
Nuclear potential energy that binds nucleons to form the atomic nucleus (and nuclear reactions)
Chromodynamic potential energy that binds quarks to form hadrons
Elastic potential energy due to the deformation of a material (or its container) exhibiting a restorative force
Mechanical wave kinetic and potential energy in an elastic material due to a propagated deformational wave
Sound wave kinetic and potential energy in a fluid due to a sound propagated wave (a particular form of mechanical wave)
Radiant potential energy stored in the fields of propagated by electromagnetic radiation, including light
Rest potential energy due to an object's rest mass
Thermal kinetic energy of the microscopic motion of particles, a form of disordered equivalent of mechanical energy
Main articles: History of energy and timeline of thermodynamics, statistical mechanics, and random processes
The World Snail Racing Championships have been held in the English village of Congham, Norfolk since the 1960s. The contestants are placed at the center of a circular table covered with a damp tablecloth and race outwards 13 inches (33 cm) towards the finish line. A contestant known only as Archie set the current world record of 2 minutes 20 seconds in 1995. Determine Archie's speed in m/s and km/h.
Speed = distance / time
Speed = (33 cm) / (2min 20sec)
Speed = (0.33 m) / (140 sec)
Speed = 0.0024 m/s
Speed = (0.0024 m/s) x (3600 sec / 1 hr) x (1 km / 1000 m)
Speed = (0.0024 x 3600 / 1000) (m-sec-km / sec-hr-m)
Speed = 0.0085 km/hr
For the time of 2 min and 20 seconds, Archie's speed in m/s will be 0.0024 m/s and Archie's speed in km/hr will be 0.0085 km/hr.
What is Speed?The "speed at which an object is traveling," or speed, is a scalar quantity. The speed of an object is the rate at which it moves through space. A fast-moving object covers a considerable distance in a short amount of time while traveling at a high speed. An object moving slowly, on the other hand, moves a comparatively modest distance in the same amount of time. An object with zero speed is one that is not moving at all.
According to the question, the given values are :
Distance, d = 33 inches or,
d = 33 cm
Time, t = 2 minutes 20 seconds, or,
t = 140 seconds.
Speed is the ratio of distance to time.
s = 33/140
s = 0.0024 m/s
Now the distance in km/hr will be :
s = 0.0024 m/s × 3600 sec / 1hr × 1 km/ 1000 m
s= 0.0085 km/hr
Hence, the speed in km/hr is 0.0085 km/hr and in m/s speed is 0.0024 m/s.
To get more information about Speed :
https://brainly.com/question/28224010
#SPJ2
Use the table below to calculate the acceleration of the object. Time (s) 0.0 3.0 6.0 9.0 Velocity (m/s) 0.0 1.2 2.4 3.6
explanation
a=average velocity/average time
average velocity=0.0+1.2+2.4+3.6/4
average velocity=7.2/4
average velocity=1.8 m/s
average time=0.0+3.0+6.0+9.0/4
average time=18/4
average time=4.5 s
a= average velocity/average time
a=1.8/4.5
a=0.4 m/s²
A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.5 m on a frictionless horizontal surface. If the cord will break when the tension in it exceeds 63 N, what is the maximum speed the ball can have?
Answer:
The maximum speed the ball can have is 15.37 m/s
Explanation:
Given;
mass of the ball, m = 0.4 kg
radius of the chord, r = 1.5 m
maximum tension on the chord, T = 63 N
The maximum tension on the chord is given by;
[tex]T_{max} = \frac{mv_{max}^2}{r} \\\\v_{max}^2 = \frac{T_{max} *r}{m}\\\\ v_{max} = \sqrt{\frac{T_{max} *r}{m}} \\\\ v_{max} =\sqrt{\frac{63 *1.5}{0.4}}\\\\v_{max} = 15.37 \ m/s[/tex]
Therefore, the maximum speed the ball can have is 15.37 m/s
A current of 1.70 A flows in a wire. How many electrons are flowing past any point in the wire per second
Answer:
1.0625×10¹⁹ electrons
Explanation:
From the question,
Using,
Q = It........................ Equation 1
Where Q = charge, I = current flowing in the wire, t = time (seconds)
Given: I = 1.70 A, t = 1 Seconds.
Substitute these values into equation 1
Q = 1.7(1)
Q = 1.7 C.
But,
1.6×10⁻¹⁹ C = 1 electron
Therefore,
1.7 C = 1.7/(1.6×10⁻¹⁹) electrons
= 1.0625×10¹⁹ electrons
Hence, 1.0625×10¹⁹ electrons flows through the wire per seconds.
An electron in a region where there is an electric field experiences a force of magnitude 3.1 10-16 N. What is the magnitude of the electric field at the location of the electron?
Answer:
1.938*10^3N/C
Explanation:
Using F= qE
E= F/q
Where q= 1.6x10-19
So 3.1*10^-16/1.6*10^-19
= 1.938*10^3N/C
Explanation:
water is boiling in a pan at 100c if heat is transferred to the pan at a rate of 2 kw how much water in kg will evaporate in 10min
Answer:
The mass of water that will evaporate 2.857 kg.
Explanation:
Given;
temperature of the water, T = 100 c
rate of heat transfer, H = 2 kW = 2000 w
time, t = 10 min = 10 min x 60s = 600s
heat capacity of water is given by;
Q = McΔT
Where;
Q is the quantity of heat transfer to the pan = P x t = 2000 x 600 = 1200000 J.
c is specific heat capacity of water = 4200 J/kg.°C
m = (Q) / (cΔT)
m = (1200000) (4200 x 100)
m = 2.857 kg
Therefore, the mass of water that will evaporate 2.857 kg.
Tell uses of cancave mirror and convex mirror.
Answer:
Uses of concave mirror:
Shaving mirrors.
Head mirrors.
Ophthalmoscope.
Astronomical telescopes.
Headlights.
Solar furnaces.
Uses of convex mirror:
Convex mirrors always form images that are upright, virtual, and smaller than the actual object. They are commonly used as rear and side view mirrors in cars and as security mirrors in public buildings because they allow you to see a wider view than flat or concave mirrors.
please give me full points.
Sapphire has an index of refraction of 1.77. The critical angle for sapphire in air with an index of refraction of 1.0 is _____ degrees.
Answer:
The value is [tex]\theta = 34.40^o[/tex]
Explanation:
From the question we are told that
The index of refraction is [tex]n_s = 1.77[/tex]
The refractive index of air is [tex]n_a = 1.0[/tex]
Generally the critical angle is mathematically represented as
[tex]\theta = sin ^{-1} [\frac{1}{n_s} ][/tex]
=> [tex]\theta = sin ^{-1} [\frac{1}{1.77} ][/tex]
=> [tex]\theta = sin ^{-1} [0.565 ][/tex]
=> [tex]\theta = 34.40^o[/tex]
A three-phase load has a phase voltage of 240 V and a phase current of 18 A. What is the apparent power of this load
Answer:
7482.5VA
Explanation:
We have that,
phase voltage of a three phase load is,240v
The phase current of a three phase load is, 18A
So To find apparent load we use
VA= √3*E*I
=√ 3*240*18
=7482.5VA
If a planet has an angular size of 0.29 degrees, what will be its angular size in arcminutes?
Answer:
Angular size in arc-minutes = 17.4 arc-minutes
Explanation:
Given:
Angular size = 0.29
Find:
Angular size in arc-minutes
Computation:
1 degree = 60 arc-minutes
So,
0.29 degree = 60 × 0.29 arc-minutes
0.29 degree = 17.4 arc-minutes
Angular size in arc-minutes = 17.4 arc-minutes
(a) Calculate the kinetic energy, in joules of a 1200 -kg automobile moving at 18 m/s .
(b) Convert this energy to calories.
(c) When the automobile brakes to a stop is the "lost" kinetic energy converted mostly to heat or to some form of potential energy?
Answer:
a) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules, b) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories, c) the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat.
Explanation:
a) Let be the automobile considered as particle travelling on horizontal ground, so that motion is entirely translational and whose formula for kinetic energy, measured in joules, is:
[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]
Where:
[tex]m[/tex] - Mass, measured in kilograms.
[tex]v[/tex] - Speed of automobile, measured in meters per second.
If [tex]m = 1200\,kg[/tex] and [tex]v = 18\,\frac{m}{s}[/tex], the kinetic energy of the automobile is:
[tex]K = \frac{1}{2}\cdot (1200\,kg)\cdot \left(18\,\frac{m}{s} \right)^{2}[/tex]
[tex]K = 194400\,J[/tex]
The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules.
b) A calory equals 4.186 joules. The kinetic energy in calories is:
[tex]K = 194400\,J \times \left(\frac{1}{4.186}\,\frac{cal}{J} \right)[/tex]
[tex]K = 46440.516\,cal[/tex]
The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories.
c) When the automobile brakes to a stop, the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat. Hence, such energy cannot be recovered. Potential energies are conservative by nature.
Calculate the radius of each ball to the nearest tenth. Use the formula r = d/2 where r is the radius and d is the diameter. Record the average in Table A of your Student Guide. What is the radius of the table tennis ball? cm What is the radius of the golf ball? cm
Answer:
What is the radius of the table tennis ball?
⇒ 2.1 cm
What is the radius of the golf ball?
2.0 cm
Explanation:
divide the radius and round it to the nearest 10th place..... but hope that help ;)
Answer:
1) What is the radius of the table tennis ball?
2.1 cm
2) What is the radius of the golf ball?
2.0 cm
Explanation:
Did this on Edge 2023 and got it right. Hope this helps :)
PLEASE HELP NEED ANSWERS NOW! Time-Distance Graph
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, some have more details available when you click on them. Drag and drop each label to the corresponding area it identifies in the image.
Answer: I added a picture of the answer
Explanation: its right
The image of answer with labeled Time-Distance Graph is attached.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
What is a Distance-Time Graph?How far an object has moved in a certain amount of time is displayed on a distance-time graph. The graph that shows the results of the distance vs time analysis is a straightforward line graph.
The Y-axis represents the distance.The X-axis is used to plot time.When the object's motion is uniform, and the graph is a straight line. we can determine the object's speed at any given moment of time from the graph. The object was in the following positions when it started and stopped:
Speed = (Final Position-Initial position)/Time
Drawing a rectangle anywhere along the straight line that regulates the object's speed will reveal the slope of the line. A horizontal line on the distance-time graph indicates that an object is at rest if it is not moving.
Learn more about speed here:
https://brainly.com/question/28224010
#SPJ5
You toss a 100-g rock in the air with a kinetic energy of 5.0 J. How much is its speed as it leaves your hand
Answer:
The speed is 10 m/s
Explanation:
Th mass if the rock = 100 g = 0.1 kg
The kinetic energy = 5.0 J
speed of the rock = ?
The kinetic energy of the rock is given by the equation
E = [tex]\frac{1}{2} mv^{2}[/tex]
where
m is the mass of the rock
V is the velocity of the rock
substituting, we have
5 = [tex]\frac{1}{2} *0.1*v^{2}[/tex]
[tex]v^{2}[/tex] = 5/0.05 = 100
v = [tex]\sqrt{100}[/tex] = 10 m/s
URGENT!!!!! I WILL MARK U AS BRAINLIEST!!!!!!! A step-down transformer converts 120 V to 5 V in a phone charger. If the primary coil has 600 turns, how many turns are in the secondary coil? SHOW ALL WORK WITH CORRECT ANSWER WITH CORRECT UNIT AS WELL.
Answer:
25 turns
Explanation:
The voltage ratio is the turns ratio:
secondary turns / primary turns = secondary voltage / primary voltage
secondary turns / 600 = 5/120
secondary turns = 600(5/120) = 25 . . . turns
The secondary coil has 25 turns.
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Complete Question
A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.
Answer:
The value [tex]v_2 = 4 \sqrt{10} \ m/s[/tex]
Explanation:
From the question we are told that
The charge on the first sphere is [tex]q_1 = 2\mu C = 2*10^{-6} \ C[/tex]
The charge on the second sphere is [tex]q_2 = 8 \mu C = 8*10^{-6} \ C[/tex]
The mass of the second charge is [tex]m = 1.50 \ g = 1.50 *10^{-3} \ kg[/tex]
The distance apart is [tex]d = 0.4 \ m[/tex]
The speed of the second sphere is [tex]v_1 = 20 \ ms^{-1}[/tex]
Generally the total energy possessed by when [tex]q_2[/tex] and [tex]q_1[/tex] are separated by [tex]0.8 \ m[/tex] is mathematically represented
[tex]Q = KE + U[/tex]
Here KE is the kinetic energy which is mathematically represented as
[tex]KE = \frac{1 }{2} m (v_1)^2[/tex]
substituting value
[tex]KE = \frac{1 }{2} * ( 1.50 *10^{-3}) (20 )^2[/tex]
[tex]KE = 0.3 \ J[/tex]
And U is the potential energy which is mathematically represented as
[tex]U = \frac{k * q_1 * q_2 }{d }[/tex]
substituting values
[tex]U = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.8 }[/tex]
[tex]U = 0.18 \ J[/tex]
So
[tex]Q = 0.3 + 0.18[/tex]
[tex]Q = 0.48 \ J[/tex]
Generally the total energy possessed by when [tex]q_2[/tex] and [tex]q_1[/tex] are separated by [tex]0.4 \ m[/tex] is mathematically represented
[tex]Q_f = KE_f + U_f[/tex]
Here [tex]KE_f[/tex] is the kinetic energy which is mathematically represented as
[tex]KE_f = \frac{1 }{2} m (v_2^2[/tex]
substituting value
[tex]KE_f = \frac{1 }{2} * ( 1.50 *10^{-3}) (v_2 )^2[/tex]
[tex]KE_f = 7.50 *10^{ -4} (v_2 )^2[/tex]
And [tex]U_f[/tex] is the potential energy which is mathematically represented as
[tex]U_f = \frac{k * q_1 * q_2 }{d }[/tex]
substituting values
[tex]U_f = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.4 }[/tex]
[tex]U_f = 0.36 \ J[/tex]
From the law of energy conservation
[tex]Q = Q_f[/tex]
So
[tex]0.48 = 0.36 +(7.50 *10^{-4} v_2^2)[/tex]
[tex]v_2 = 4 \sqrt{10} \ m/s[/tex]
Which equation describes the cosine function for a right triangle?
A. cos(O)
opposite
adjacent
B. cos(2)
adjacent
hypotenuse
C. cos(0)
opposite
hypotenuse
D. cos(e)
hypotenuse
adjacent
SUENT
Answer:
cosine is adjacent over hypotenuse
Explanation:
How I know? It's just a basic formula for triangles, and my teacher taught me this. Sorry if this didn't help.
Answer:
D.cos(e)
hypotenuse adjacent
SUENT
Explanation:
it is helpful to you
if the DIY parachute is dropped freely from the rooftop of the building of a building and reached the ground 3s later.Upon reaching the ground,What is the (a)final velocity of DYI parachutes ?(b) Height of the rooftop?
Answer:
It depends on what the parachute is made out of.
Explanation:
A hole is drilled in a metal plate. When the metal is raised to a higher temperature, what happens to the diameter of the hole?
Answer:
The diameter of the hole increases
Explanation:
Metals expand and contract with temperature. Whenever metal is heated, it usually expands in relation to its thermal expansivity. This expansion leads to a slight increase in surface area.
Once the surface area of the metal changes, this means that the dimensions of the whole metal surface changed. As a result, the diameter of the hole drilled in the metal plate will change also. In our case, the diameter of the hole will increase.
E
Which is the downward pull on an object due to gravity?
volume
mass
weight
matter
Answer:
Weight
Explanation:
Weight is the downward pull on an object due to gravity.
For example, the moon has less gravity than Earth so we would weigh less on the moon. Our Mass and volume always stay the same but our weight could change.
Answer:
weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight
Explanation:
What is the direction of the magnetic field at the location of the charge due to the current-carrying wire
Answer: please find the answer in the explanation.
Explanation:
The direction of the magnetic field at the location of the charge due to the current-carrying wire can be determined by using right hand rule.
The thumb points in the direction of current while the fingers curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight wire. The thumb is pointed in the direction of the current and the fingers then give the direction of the magnetic field lines.
Two campers in a national park hike from their cabin to the same spot on a lake, each taking a different path, as illustrated below. The total distance traveled along Path 1 is 7.5 km, and that along Path 2 is 8.2 km. What is the final displacement of each camper?
Answer:
Their displacement is 5 Km from the cabin.
Explanation:
The displacement is define is the shortest distance between two points. It is the shortest distance of a line that joins two points together. It quantifies both the distance and direction of the net or total motion along a straight line from the initial position to the final position of the point trajectory. In this case, the straight line joining the cabin to the stream is line S which is equal to 5 Km
A football is kicked from ground level with an initial velocity of 23.8 m/s at angle of 42.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.
Answer:
The value is [tex]t = 3.28 \ s[/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]u = 23.8 \ m/s[/tex]
The angle is [tex]\theta= 42.5^o[/tex]
Generally from the projectile motion equation we know that the time of flight is mathematically represented as
[tex]t = \frac{2 * u *sin (\theta )}{ g }[/tex]
=> [tex]t = \frac{ 2 * 23.8 * sin (42.5)}{9.8 }[/tex]
=> [tex]t = 3.28 \ s[/tex]
A 5 kg object is launched from a 35 m high cliff at an angle of 30 degrees with a speed of 100 m/s. How far from the cliff does it hit the ground
Answer:
The object will hit the ground at 882.77 m from the lunch
Explanation:
we are to find the range of the motion
What is range?
It is the distance from the point of projection to the point where the object hits the ground
R=(v^2sin2θ)/g
Given data
v= 100 m/s
θ= 30 degree
g= 9.81 m/s^2
Substituting to find the R we have
R= 100^2 *sin(2*30)/9.81
R= (10000*0.866)9.81
R= 8660/9.81
R= 882.77 m
You are trying to overhear a juicy conversation, but from your distance of 24.0m , it sounds like only an average whisper of 40.0dB . So you decide to move closer to give the conversation a sound level of 80.0dB instead. How close should you come?
Answer:
The distance is [tex]r_2 = 0.24 \ m[/tex]
Explanation:
From the question we are told that
The distance from the conversation is [tex] r_1 = 24.0 \ m[/tex]
The intensity of the sound at your position is [tex]\beta _1 = 40 dB[/tex]
The intensity at the sound at the new position is [tex]\beta_2 = 80.0dB[/tex]
Generally the intensity in decibel is is mathematically represented as
[tex]\beta = 10dB log_{10}[\frac{d}{d_o} ][/tex]
The intensity is also mathematically represented as
[tex]d = \frac{P}{A}[/tex]
So
[tex]\beta = 10dB * log_{10}[\frac{P}{A* d_o} ][/tex]
=> [tex]\frac{\beta}{10} = log_{10} [\frac{P}{A (l_o)} ][/tex]
From the logarithm definition
=> [tex]\frac{P}{A * d_o} = 10^{\frac{\beta}{10} }[/tex]
=> [tex]P = A (d_o ) [10^{\frac{\beta }{ 10} } ][/tex]
Here P is the power of the sound wave
and A is the cross-sectional area of the sound wave which is generally in spherical form
Now the power of the sound wave at the first position is mathematically represented as
[tex]P_1 = A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ][/tex]
Now the power of the sound wave at the second position is mathematically represented as
[tex]P_2 = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ][/tex]
Generally power of the wave is constant at both positions so
[tex]A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ] = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ][/tex]
[tex]4 \pi r_1 ^2 [10^{\frac{\beta_1 }{ 10} } ] = 4 \pi r_2 ^2 [10^{\frac{\beta_2 }{ 10} } ][/tex]
[tex]r_2 = \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}[/tex]
substituting value
[tex]r_2 = \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}[/tex]
[tex]r_2 = 0.24 \ m[/tex]
A dolphin swims due east for 1.90 km, then swims 7.20 km in the direction south of west. What are the magnitude and direction of the vector that will take the dolphin back to its starting point? (Enter the magnitude in km and the direction in degrees north of east.)
Answer:
magnitude = 7.446 km, direction = 75.22° north of east
Explanation:
From the questions,
To get the the magnitude of the resultant vector we use Pythagoras theorem
a² = b²+c²
From the diagram,
y² = 1.9²+7.2²
y² = 55.45
y = √(55.45)
y = 7.446 km.
The direction of the dolphin is given as,
θ = tan⁻¹(7.2/1.9)
θ = tan⁻¹(3.7895)
θ = 75.22° north of east
Hence the magnitude of the resultant vector = 7.446 km, and it direction is 75.22° north of east
Andy took a bus and then walked from his home to downtown.
For the first 16 hour, the bus drove at an average speed of 15
km/h. For the next 0.4 hours, he walked at an average speed
of 4.5 km/h. What was the average speed for the whole
journey?
Given :
Speed of bus for first 16 hours is , u = 15 km/h .
Distance he walked for next 0.4 hour is , v = 4.5 km/h .
To Find :
The average speed for the whole journey.
Solution :
Average speed is given by :
[tex]v_{avg}=\dfrac{u_1t_1+u_2t_2}{t_1+t_2}\\\\v_{avg}=\dfrac{15\times 16 + 4.5\times 0.4}{16+0.4}\\\\v_{avg}=14.74\ km/h[/tex]
Therefore , the average speed of the journey is 14.74 km/h .
Hence , this is the required solution .
Which of the following describe a condition or location for the right environment for tropical cyclone formation over the north eastern tropical Pacific Ocean?
A. light surface winds
B. a La Nina event
C. stable air
D. a deep layer of humid air
E. converging surface winds
F. ocean surface temperature greater than 80 °F
Answer:
E. converging surface winds
Explanation:
For the formation of tropical cyclones to occur in the northeast of the tropical Pacific Ocean, it is necessary to have converging surface winds that present a strong convection. This allows for the formation of vertical movements of an ascending nature that have great strength and are intense and violent. This also allows closed cyclonic circulation to occur at the lower levels which together with a low frontal pressure system over the waters of the Pacific Ocean can form the tropical cyclone.
What speed would such a block have if pushed horizontally 108 m along a frictionless track by such a laser
Hello. This question is incomplete. The full question is:
You've recently read about a chemical laser that generates a 20-cm-diameter, 25.0 MW laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a 20-cm-diameter, 100 kg,perfectly absorbing block. What speed would such a block have if pushed horizontally 108 m along a frictionless track by such a laser?
Answer:
V = 0.408 m / s
Explanation:
First, it is necessary to find the radiation pressure on the surface. You will find it using the following formula:
P = P / (πr ^ 2) c
where P is the pressure and c is the speed of light in vacuum
P = 25 * 10 ^ 6 / π (0.2 / 2) ^ 2 * (3 * 10 ^ 8) = 2,652 N / m ^ 2.
Then you must calculate the force (F) and the acceleration (a). This is done through the formulas:
F = P * (πr ^ 2)
F = 2,652 * π * (0.2 / 2) ^ 2 = 0.083N
a = F / m
a = 0.083 / 100 = 0.0002129 m / s ^ 2
You can now calculate the speed.
V = √2ad
V = √2 *0.0002129 * 108
V = 0.2144 m / s