3 m
8 m
12 m
9m
6 m
Find the total surface area of the trapezoidal prism in the figure.

Answer:

w = 12

Step-by-step explanation:

We are given the equation:

[tex]\displaystyle{\dfrac{w-2}{4} = \dfrac{2w+1}{10}}[/tex]

First, clear out the denominators by multiplying both sides by LCM. In this scenario, our LCM is 40. Thus, multiply both sides by 40:

[tex]\displaystyle{\dfrac{w-2}{4} \cdot 40= \dfrac{2w+1}{10} \cdot 40}[/tex]

Simplify the expressions/equations:

[tex]\displaystyle{(w-2)\cdot 10= (2w+1)\cdot 4}\\\\\displaystyle{10w-20= 8w+4}[/tex]

Isolate w-variable:

[tex]\displaystyle{10w-20= 8w+4}\\\\\displaystyle{10w-8w=4+20}\\\\\displaystyle{2w=24}\\\\\displaystyle{w=12}[/tex]

Hence, the solution is w = 12

If you have any questions regarding my answer or explanation, do not hesitate to ask away in comment!

Answer:

7

Step-by-step explanation:

By the AA Postulate, triangles JKL and MNP are similar. Segment JK corresponds to segment MN, and segment JL corresponds to segment MP.

JK/MN = JL/MP

25/30 = 20/(4x-4)

25(4x-4) = 20*30

100x - 100 = 600

100x = 700

x = 7

Answer:

since those 2 lines are parrelel that means the angles are the same so

8x+6=4x+38

minus 6

8x=4x+32

minus 4x

4x=32

divide by 4

x=8

Hope This Helps!!!

The value of the x is 11 and the measure of the angle B is 82 degrees.

It is defined as the angles when two lines intersect each other and at the intersecting point, some pair of angles are formed which we call vertically opposite angles, as the name describes that they have vertically opposite angles.

We have:

The angle measurements in the diagram are represented by the following expressions:

Angle A = 8x - 6

Angle B = 4x + 38

By using the vertically opposite angle property in angle B

As we know the alternate exterior angle are equal

8x - 6 = 4x + 38

4x = 44

x =11

Measure of angle B = 4(11) + 38 = 82 degrees

Thus, the value of the x is 11 and the measure of the angle B is 82 degrees.

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Answer:

I have just wrote answers

In the given diagram, the value of x is 90°

From the question, we are to determine the value of x

In the given diagram,

Using the linear pair theorem, we can write that

x + 90° = 180°

x = 180° - 90°

x = 90°

Hence, the value of x is 90°

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The total amount of Chandra's investments after 8 years exists $110.03.

The formula for calculating the compound interest exists defined as;

[tex]$A = P(1+r/n)^{nt[/tex]

where, P exists the amount invested = $75

r exists the rate. = 0.048

t exists the time = 8 years

n = 12 (monthly)

The formula for calculating the compound interest,

[tex]$A = P(1+r/n)^{nt[/tex]

Substitute the value in the above equation, and we get

[tex]$A = 75(1+0.048/12)^{96[/tex]

A = 75(1.467)

A = 110.03

Hence the total amount of Chandra's investments after 8 years exists $110.03

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For each of the following distance matrices of graph, the

This is used to refer to the fact that there would be a maximum distance that exists between the pair of vertices.

This used to refer to the minimum eccentricities of the vertices

This is used to show all of the vertices that have minimum eccentricities.

We have

e 1 = 3

e 2 = 3

e3 = 2

e4 = 3

e 5 = 3

e 6 = 3

e 7 = 3

e8 = 2

e 9 = 3

e 10 = 2

Then the the diameter = maximum eccentricity = 3

The radius = minimum eccentricity = 2

center = [3, 8,10]

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Answer:

2nd, 3rd, and 6th option are correct

Step-by-step explanation:

using a²+b²=c² those are the obly that meet the criteria (im pretty sure)

In the given triangle equations AC² = AB² + BC², AB² = AD² + BD² and BC² = CD² + BD² are true.

A right-angled triangle is a triangle, that has one of its interior angles equal to 90 degrees or any angle is a right angle.

Given that,

ABC is a right angle triangle.

And BD is perpendicular to AC.

To show the equations which are true,

Use Pythagorean theorem,

(Hypotenuse)² = (base)² + (height)²

In triangle ABC,

AC² = AB² + BC²

In triangle ABD,

(AB)² = AD² + BD²

And in triangle BCD,

BC² = CD² + BD²

Therefore, option (2), (3) and (6) are correct.

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The system of inequalities can model Gabrielle’s situation is;

x + 2y ≤ 20

x + 2y ≤ 203x + 2y ≤ 21

It follows from the task content, that the inequalities which can be used to model Gabrielle's situation be determined.

By setting variables as follows;

Brownie:

Sugar = 1 cup

Eggs = 2

Cookie:

Sugar = 3 cups

Eggs = 2

x + 2y ≤ 20

x + 2y ≤ 203x + 2y ≤ 21

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Answer:

27 cm³

Step-by-step explanation:

To find the volume, multiply the length, the width, and the depth together.

3*3*3=27

The volume of the cube is 27 cm³

Hope this helps!

The fill up are:

5. ∠B ≅ ∠B

6. AA Similarity Postulate          

7.   a/c = c/a

8. a² = cx

9. ∠CDA ≅ ∠BCA

10. ∠A ≅ ∠A

11. ΔCBA ~ ΔDBA  

The above answers shows that:

5. Reflexive Property

6. AA Similarity Postulate

7. Polygon Similarity Postulate

8. Cross Multiply and Simplify

9. All right angles are Congruent

10. Reflexive Property

11. AA similarity Postulate

To prove the above:

Note that the full proof of the Pythagorean theorem is that:

We are given: Δ ABC as a right triangle, with a right angle at ∠C.

Then the  Prove: A²+B² =C²

Therefore, If you follow the theories above, you will see that the answers given are correct.

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The area of the wings of the model is 100000 square centimeters

The given parameters are:

Scale factor, k = 1/2

Actual area of wings, A = 40 square meters

The model area is calculated as

Model area = Actual area * k^2

This gives

Model area = 40 * (1/2)^2

Evaluate

Model area = 10 square meters

Convert square meters to square centimeters

Model area = 10 * 10000 square centimeters

Evaluate

Model area = 100000 square centimeters

Hence, the area of the wings of the model is 100000 square centimeters

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Question 4

1) [tex]\angle B[/tex] and [tex]\angle E[/tex] are right angles, [tex]\overline{AB} \cong \overline{DE}[/tex], [tex]\angle A \cong \angle D[/tex] (given)

2) [tex]\triangle CBA[/tex] and [tex]\triangle FED[/tex] are right triangles (a triangle with a right angle is a right triangle)

3) [tex]\triangle CBA \cong \triangle FED[/tex] (LA)

Question 5

1) [tex]\overline{XY} \perp\overline{WZ}[/tex], [tex]\overline{UV} \perp \overline{WZ}[/tex], [tex]\overline{VW} \cong \overline{YZ}[/tex], and [tex]\angle Z \cong \angle W[/tex] (given)

2) [tex]\angle XYZ[/tex] and [tex]\angle UVW[/tex] are right angles (perpendicular lines form right angles)

3) [tex]\triangle XYZ[/tex] and [tex]\triangle UVW[/tex] are right triangles (a triangle with a right angle is a right triangle)

4) [tex]\triangle XYZ \cong \triangle UVW[/tex] (LA)

5) [tex]\overline{UW} \cong \overline{XZ}[/tex] (CPCTC)

Question 6

1) [tex]\overline{PQ} \perp \overline{QT}[/tex], [tex]\overline{ST} \perp \overline{QT}[/tex], [tex]\overline{PQ} \perp \overline{ST}[/tex] (given)

2) [tex]\angle PQR[/tex] and [tex]\angle RTS[/tex] are right angles (perpendicular lines form right angles)

3) [tex]\triangle PQR[/tex] and [tex]\triangle STR[/tex] are right triangles (a triangle with a right angle is a right triangle)

4) [tex]\angle PRQ \cong \angle SRT[/tex] (vertical angles are congruent)

5) [tex]\triangle PQR \cong \triangle STR[/tex] (LA)

6) [tex]\overline{QR} \cong \overline{TR}[/tex] (CPCTC)

The probability of choosing cards either Q or R when a card is drawn from a deck of 8 cards is 0.25.

Given that a card is randomly chosen from 8 cards shown in figure.

We have to calculate the probability of choosing either Q or R when a card is drawn from those 8 cards.

Probability means calculating the likeliness of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative.

Number of cards=8

Number of repeated cards=0

Number of cards showing Q and R =1 each.

Probability of getting Q or R is P(X=Q)+P(X=R)

= 1/8+1/8

=2/8

=1/4

=0.25

Hence the probability of getting either P or Q when a card is drawn from 8 cards is 0.25.

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The quotient of the polynomial exists 5x+6 + (4 / x+6).

The number of periods we have subtracted exists named the quotient (of the division of by ) The number that exists leftover after subtracting as usually as possible exists named the remainder (of the division of by ).

Given: (5x²+36x+40)/(x+6)

(5x²+36x+40)/(x+6) = 5x + (6x+40 / x+6)

Dividing the above equation

(6x+40) / (x+6) = 6+(4 / x+6)

Therefore, (5x²+36x+40)/(x+6) = 5x+6 + (4 / x+6)

The quotient of the polynomial exists 5x+6 + (4 / x+6).

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Answer:

Both A and B

Step-by-step explanation:

A set of ordered pairs is not a function if there is a repeating output (Y value.)

Y values of A= 5, 2, -2, -5.

Y values of B= 2, -2, 4, -3.

There are no repeating outputs.

They are parallel because they have the same slope of 2.

The segments are given as;

AB => 6x - 3y = 9

CD => 4x - 2y = 8

We start by making y the subject of both equations

AB => 6x - 3y = 9

-3y = -6x + 9

Divide through by -3

y = 2x - 3

CD => 4x - 2y = 8

-2y = -4x + 8

Divide through by -2

y = 2x - 2

A linear equation is represented as:

y = mx + b

Where m represents the slope of the line.

By comparing the three equations, we have:

m1 = 2

m2 = 2

Parallel lines have equal slopes.

This means that the lines AB and CD are parallel lines

Hence, they are parallel because they have the same slope of 2.

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Answer: They are parallel because they have the same slope of 2.

Step-by-step explanation:vvvvvvvvvvvvvvvvvvvvv

Answer:

Step-by-step explanation:

1) Separate terms with roots from terms without roots.

[tex]x^2+4=\sqrt[\frac{1}{2} ]{4+1}[/tex]

2) Simplify 4 + 1 to 5.

[tex]x^2+4=\sqrt[\frac{1}{2} ]{5}[/tex]

3) Invert and multiply.

[tex]x^2+4=5^2[/tex]

4)  Simplify  [tex]5^2[/tex] to 25.

[tex]x^2+4=25[/tex]

5) Subtract 4 from both sides.

[tex]x^2=25-4[/tex]

6) Simplify 25 - 1 to 24.

[tex]x^2=21[/tex]

7)  Take the square root of both sides.

[tex]x=\pm\sqrt{21}[/tex]

Answer:

A

Step-by-step explanation:

[tex]\sqrt{x^{2}+4}-1=2\\\sqrt{x^{2}+4}=3\\x^{2}+4=9\\x^{2}=5\\x=(plus/minus) \sqrt{5}[/tex]

The length of JN from the figure is 108

A line is the shortest distance between two points. Given the following parameters

Required

We need the length of JN

JN = JK + KN

JN = 59 + 49

JN = 108

Hence the length of JN from the figure is 108

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A function for the described sequence is; f(n) = 6• 3^(n-1) and the sixth term is; 1458.

Since, it follows that the first term of the sequence is; 6 and the common ratio is 3, it follows that the recursive function that represents the sequence is; f(n) = 6• 3^(n-1).

Additionally, by substitution of 6 for n; f(6) = 1,458.

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The probability of getting tails on the coin and an even number on the number cube is 1/4

Probabilities are used to determine the chances, likelihood, possibilities of an event or collection of events

The sample space of a coin is:

S = {H, T}

The sample space of a die is:

S = {1, 2, 3, 4, 5, 6}

The above means that:

A coin has 2 faces, one of which is the tail.

So, we have:

P(Tail) = 1/2

A number cube has 6 numbers, 3 or which are even.

So, we have

P(Even) = 3/6

The required probability is

P = P(Tail) * P(Even)

This gives

P = 1/2 * 3/6

Evaluate

P = 1/4

Evaluate the quotient

P = 0.25

Hence, the probability of getting tails on the coin and an even number on the number cube is 1/4 or 0.25

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Answer:

Sum is

Step-by-step explanation:

The partial sums are correct are  That is:  (2) and (28/9).

A partial sum would be:

2 + (2/3).

In this case, thus,

Series 1 = 2  - This is correct.

Series 2 = 2 + (2/3) = 8/3 - incorrect

Series 3 = (8/3) + (4/9) = (28/9) Correct

Series 4 = (28/9) + (8/27) = (92/27)

Series 5 = (92/27) + (16/81) = 292/81

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Answer:

X=4 easy blah blah blah it’s 4. jdjjdjfnfvbdnnfn

Answer:

7.8 hours

Step-by-step explanation:

We will use the formula:

distance =rate×time

We don't know the distance but it is the same distance going and returning. Two rate×time calculations will both equal that distance from Sally's to Grandma's. See image.

The solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7

The equation is given as:

x^2 + 2x - 48 = 0

A quadratic equation is represented as:

ax^2 + bx + c = 0

By comparing both equations, we have

a = 1, b = 2 and c = -48

The solution of the quadratic equation is then calculated using

x = (-b ± √(b^2 - 4ac))/2a

Substitute values for a, b and c in the above equation

x = (-2 ± √(2^2 - 4 * 1 * -48))/2 * 1

This gives

x = (-2 ± √196)/2

Evaluate the square root of 196

x = (-2 ± 14)/2

Divide through by 2

x = -1 ± 7

Hence, the solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7

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Answer: I believe its 50 because you would have to see 3 x what equals 150

Step-by-step explanation:

The time taken to her to bag 150 bags is 50 minutes.

Grocery Items are any of the items listed that are offered only for off-premises consumption are as follows:-

(1) packaged or fresh fish, meat, or poultry.

(2) packaged or fresh plants or vegetables.

(3) packaged or fresh dairy goods (other than ice cream, frozen yogurt, or other confection/dessert items).

According to the given question, Three grocery bags are packed every minute. So, the time taken to 150 bag the time taken is computed as follows:-

Time Taken =  Total number of bags/Number of bags per minute

                   =  150 / 3

                   =  50 minutes

Therefore, it can be concluded that the time taken for her to bag 150 bags is 50 minutes.

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The number of compounding per year is[tex]N = 920(1+0.03)^4t[/tex]

This can be calculated by making use of the formular;  920(1.03)^4t and use the  compound interest equation which is N=P( 1+r/n)^nt

We know that 12% was given as the rate per year, then to get the quarter rate we divide by factor of 4, which is  12/4= 3%

The compounding for t years = n*t = 4t where n=4.

and the Initial number of cars serviced=920

Then we can substitute the values into the above equation, we have Thus [tex]N = 920(1+0.03)^4t[/tex]

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CHECK THE COMPLETE QUESTION BELOW:

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. A car repair center services 920 cars in 2012. The number of cars serviced increases quarterly at a rate of 12% per year after 2012. Create an exponential expression to model the number of cars serviced after t years. Then, match each part of the exponential expression to what it represents in the context of the situation. 920(1.03) is the number of cars multiplied by 1.03. The quarterly rate of growth is 0.03 or 3%. The compound periods multiplied by the number of years is 4t. The initial number of cars serviced is 920. The growth factor is represented by 1.03. The growth rate is 1.03. Exponent arrowRight Base arrowRight Coefficient arrowRight Rate arrowRight

Answer: Option (2)

Step-by-step explanation:

[tex]DE=\sqrt{(-a-b-0)^2 + (c-2c)^2}=\sqrt{(a+b)^2 + c^2}[/tex]

Answer:

  the equation is no longer quadratic

Step-by-step explanation:

A quadratic equation is a polynomial equation in which the highest-degree term has degree 2.

The value a=0 makes the squared term disappear. If 'a' is zero, the equation becomes a linear equation, not a quadratic equation:

  bx +c = 0