-3x^5y^7/6xy^8
PLEASE HELP

Answers

Answer 1

9514 1404 393

Answer:

  -x^4/(2y)

Step-by-step explanation:

Perhaps you want to simplify ...

  [tex]-\dfrac{3x^5y^7}{6xy^8}=-\dfrac{3}{6}x^{5-1}y^{7-8}=-\dfrac{x^4y^{-1}}{2}=\boxed{-\dfrac{x^4}{2y}}[/tex]

__

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

_____

Comment on notation

When writing a fraction in plain text, any denominator that includes an arithmetic operation must be enclosed in parentheses. Your given expression is properly written as ...

  -3x^5y/(6xy^8)

Without the parentheses, the product xy^8 is in the numerator. This is demanded by the order of operations, which requires you evaluate your expression as (-3x^5y^7/6)·xy^8


Related Questions

What is the maximum value of the objective function, P, with the given constraints?

P = 25x+45y

(4x+y≤16)
(x+y≤10)
(x≥0)
(y≥0)

Options

A: 100
B: 410
C: 450
D: 720

Answers

Answer:

D

Step-by-step explanation:

|5x|=3 please help me

Answers

Answer: see below

Explanation:

|5x| = 3

5x = 3
x = 3/5

5x = -3
x = -3/5

To the nearest square inch, what is the surface area of the square pyramid shown in the image? A. 175 in.^2 B. 200 in.^2 C. 400 in.^2 D. 700 in.^2 Please show ALL work! :D

Answers

Answer: C. 400  in^2

Step-by-step explanation:

First find the surface area or the area of the base which is in the shape of  a square and has a side length of 10 in. So square 10 to find the area.

Area of base:  10 * 10 = 100

Next find the area of one of the triangles.

As we could see the triangle has a slant height of 15 in and a base of 10. To find the area of a triangle we multiply the base times the height and multiply it by half.

Area of one triangle.  15 * 10 = 150 * 1/2 = 75  

Since one side of the triangle has a surface area of 75 inches we will multiply it by 4 since there are four triangles to find the total surface area of the four faces.

75 * 4 = 300  

We now know that the the 4 triangles surface area dd up to 300 so we will add it to the area of the base which is 100 to find the whole surface area of the figure.

300 + 100 = 400

What is the surface area of a cone with a slant height of 12.5m and a diameter of 9m? Round to the nearest whole number.

Answers

9514 1404 393

Answer:

  240 m²

Step-by-step explanation:

The lateral surface area is given by the formula ...

  LA = πrs . . . . . cone with radius r and slant height s

The base area is given by the formula ...

  BA = πr²

The total surface area is the sum of these:

  SA = BA +LA = πr² +πrs = πr(r+s)

The radius is half the diameter, so is 9m/2 = 4.5 m. Then the surface area is ...

  SA = π(4.5 m)(4.5 m +12.5 m) = 76.5π m² ≈ 240 m²

Answer:

1: A. 448 2: 209 pi cm^2 3: D. 351 m^2 4. B 240 cm^2 5. C. 561.1 cm^2

Step-by-step explanation:

just took the test!!!

If g(x) = x^2 + 8x - 24 find the value of g(6)

Answers

Answer:

hope it helps you..........

Answer:

60

Step-by-step explanation:

g(x)= x^2 +8x - 24

Substitute x for 6 in the equation

g(6)= 6^2 + 8(6) - 24

= 36+48-24

= 60


please help and show work
i need 17 19 and 21

Answers

Answer:

Step-by-step explanation:

(17). g(x) = x³ + 4x

f(x) = 4x + 1

( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = 4 [tex]x^{4}[/tex] + x³ + 16x² + 4x

(19). f(t) = 4t - 4

g(t) = t - 2

( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = 19t - 22

(21). h(t) = t + 3

g(t) = 4t + 1

h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = 5t - 6

Classify the expression: 5x + 3x^2 − 7x^3 + 2
A. Linear Expression
B. Quadratic Expression C. Cubic Expression
D. Quartic Expression

Answers

Answer:

C. Cubic expression.

Step-by-step explanation:

The highest exponent is 3 ( in the term 7x^3) so it is cubic.

Answer:

C. Cubic Expression.

Step-by-step explanation:

5x + 3x^2 - 7x^3 + 2

= 3x^2 - 7x^3 + 5x + 2

= -7x^3 + 3x^2 + 5x + 2

The highest value of exponent in the equation is 3.

For a linear expression, the highest exponent is 1.

For a quadratic expression, the highest exponent is 2.

For a cubic expression, the highest exponent is 3.

For a quartic expression, the highest exponent is 4.

So, this is C. Cubic Expression.

Hope this helps!

A rectangular tank that is 2048 ft cubed with a square base and open top is to be constructed of sheet steel of a given thickness. Find the dimensions of the tank with minimum weight.

Answers

Answer:

16ft by 16ft by 8ft.

Step-by-step explanation:

Let the total surface area of the rectangular tank be S = 2LW+2LH+2WH where;

L is the length of the box

W is the width of the box

H is the height of the box.

Since the box is openend at the top, S = lw + 2lh+ 2wh

If the base is a square base then, l = w

S = l(l) + 2wh+2wh

S = l²+4wh ............... 1

If volume = lwh

lwh = 2028 ft³

wh = 2048/l ................ 2

Substitute equation 2 into 1;

S = l²+4(2048/l)

S = l²+8192/l

dS/dl = 2l - 8192/l²

If dS/dl = 0 (since we are looking for dimensions of the tank with minimum weight.)

2l - 8192/l² = 0

2l = 8192/l²

2l³ = 8192

l³ = 8192/2

l³ = 4096

l =∛4096

l = 16 ft

Since the length is equal to the width, hence the width = 16ft (square based tank)

Given the volume V = lwh = 2048

lwh = 2048

16*16*h = 2048

256h = 2048

divide both sides by 256

256h/256 = 2048/256

h = 8ft

Hence, the dimensions of the tank with minimum weight is 16ft by 16ft by 8ft.

(Algebra)
Plz help me ASAP!! I’ll be so grateful!

Answers

Answer:

y > 1

Step-by-step explanation:

-2(7 + y) > -8(y + 1)

-14 -2y > -8y -8

-2y +8y > -8 +14

6y > 6

6y/6 > 6/6

y > 1

Find the sum. 1. -7+(-5)
O-12
O-2
0 2
0 12​

Answers

Answer:

-12

Step-by-step explanation:

-7+(-5)=

-7-5=

-12

in alska the colderst temprauter ever recorded is -80 that is much colder than in hawil where the coldest temperature is 15

Answers

Answer: What are we supposed to do ???

HELP ASAP PLS :Find all the missing elements:

Answers

Answer:

a ≈ 1.59

b ≈ 6.69

Step-by-step explanation:

Law of Sines: [tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]

Step 1: Find c using Law of Sines

[tex]\frac{6}{sin58} =\frac{c}{sin13}[/tex]

[tex]c = sin13(\frac{6}{sin58})[/tex]

c = 1.59154

Step 2: Find a using Law of Sines

[tex]\frac{6}{sin58} =\frac{a}{sin109}[/tex]

[tex]a = sin109(\frac{6}{sin58} )[/tex]

a = 6.68961

Find a particular solution of the differential equation
-(5/4)y" + 2y' + y = 3x*e^(3x)
using the Method of Undetermined Coefficients (primes indicate derivatives with respect to x).
Find the following particular solution
yp= ?

Answers

Note that the characteristic solutions to this ODE are [tex]e^{-2x/5}[/tex] and [tex]e^{2x}[/tex], so we can safely assume a particular solution of the form

[tex]y_p=(ax+b)e^{3x}[/tex]

with derivatives

[tex]{y_p}'=ae^{3x}+3(ax+b)e^{3x}=(3ax+a+3b)e^{3x}[/tex]

[tex]{y_p}''=3ae^{3x}+3(3ax+a+3b)e^{3x}=(9ax+6a+9b)e^{3x}[/tex]

Substitute these expressions into the ODE and solve for a and b. Notice that each term on either side contains a factor of [tex]e^{3x}[/tex], which we can cancel.

[tex]-\dfrac54(9ax+6a+9b)+2(3ax+a+3b)+(ax+b)=3x[/tex]

[tex]-\dfrac{17a}4x-\left(\dfrac{11a}2+\dfrac{17b}4\right)=3x[/tex]

[tex]\implies\begin{cases}-\frac{17a}4=3\\\frac{11a}2+\frac{17b}4=0\end{cases}[/tex]

[tex]\implies a=-\dfrac{12}{17}\text{ and }b=\dfrac{264}{289}[/tex]

So the particular solution is

[tex]y_p=\left(-\dfrac{12x}{17}+\dfrac{264}{289}\right)e^{3x}=\boxed{\dfrac{12}{289}(22-17x)e^{3x}}[/tex]

what principle will amount to Rs. 4000 in 20 yrs at 2.5%?​

Answers

Answer:

3200

Step-by-step explanation:

Consider principle =Rs.P, Time (T)=4 years

Consider principle =Rs.P, Time (T)=4 yearsRate =6

Consider principle =Rs.P, Time (T)=4 yearsRate =6 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200

in a class of 40 students, 30 students read chemistry, 40 students read physics, if all students read at least one of the subject, find the probability a students is selected at random will read only chemistry ​

Answers

Answer: 0%

Step-by-step explanation:

There's 40 students, and 40 students read physics. That means that every student reads physics. So, no student could read only chemistry.

Consider the following. x = t − 2 sin(t), y = 1 − 2 cos(t), 0 ≤ t ≤ 2π Set up an integral that represents the length of the curve. 2π 0 dt Use your calculator to find the length correct to four decimal places.

Answers

Answer:

L = 13.3649

Step-by-step explanation:

We are given;

x = t − 2 sin(t)

dx/dt = 1 - 2 cos(t)

Also, y = 1 − 2 cos(t)

dy/dt = 2 sin(t)

0 ≤ t ≤ 2π

The arc length formula is;

L = (α,β)∫√[(dx/dt)² + (dy/dt)²]dt

Where α and β are the boundary points. Thus, applying this to our question, we have;

L = (0,2π)∫√((1 - 2 cos(t))² + (2 sin(t))²)dt

L = (0,2π)∫√(1 - 4cos(t) + 4cos²(t) + 4sin²(t))dt

L = (0,2π)∫√(1 - 4cos(t) + 4(cos²(t) + sin²(t)))dt

From trigonometry, we know that;

cos²t + sin²t = 1.

Thus;

L = (0,2π)∫√(1 - 4cos(t) + 4)dt

L = (0,2π)∫√(5 - 4cos(t))dt

Using online integral calculator, we have;

L = 13.3649

Suppose that 1% of the employees of a certain company use illegal drugs. This company performs random drug tests that return positive results 99% of the time if the person is a drug user. However, it also has a 2% false positive rate. The results of the drug test are known to be independent from test to test for a given person.

a) Steve, an employee at the company, has a positive test. What is the probability that he is a drug user?

b) Knowing he failed his first test, what is the probability that Steve will fail his next drug test?

c) Steve just failed his second drug test. Now, what is the probability that he is a drug user?

Answers

Answer:

a) Pr(drug user| positive test) = 0.3333

b) The probability that he will failed his first test = 0.9703

c) the probability that he is a drug user since  failed his second drug test

= 0.961165

Step-by-step explanation:

From the given information:

Suppose that 1% of the employees of a certain company use illegal drugs.

Probability of illegal drug user = 0.01

Probability of user that do not use drug = 1 - 0.01 = 0.99

From the person that is a illegal drug user, the company performs random drug tests that return positive results = 0.99

Therefore, the negative result for illegal drug user = 1 - 0.99 = 0.01

However, it also has a 2% false positive rate.

i.e the probability of the user that do not use drug has a positive result of 2% = 0.02

Thus, the probability of the user that do not use drug has a negative result of = 1 - 0.02

= 0.98

We are tasked to answer the following questions.

a) Steve, an employee at the company, has a positive test. What is the probability that he is a drug user?

i.e This employee we are taking about is a drug user and he has a positive test.

Thus;

Pr(drug user| positive test) = [tex]\dfrac{0.99 \times 0.01}{0.99 \times 0.01+ 0.02 \times 0.99}[/tex]

Pr(drug user| positive test) = [tex]\dfrac{0.0099}{0.0099+0.0198}[/tex]

Pr(drug user| positive test) = [tex]\dfrac{0.0099}{0.0297}[/tex]

Pr(drug user| positive test) = 0.3333

b) Knowing he failed his first test, what is the probability that Steve will fail his next drug test?

The probability that he will failed his first test = ((0.01 × 0.01) + (0.99×0.98))

The probability that he will failed his first test = ( 1 × 10⁻⁴ + 0.9702)

The probability that he will failed his first test = 0.9703

c)  Steve just failed his second drug test. Now, what is the probability that he is a drug user?

the probability that he is a drug user since he  failed his second drug test using Bayes theorem can be expressed as:

= [tex]\dfrac{0.01 \times(0.99\times 0.99)}{0.01 \times (0.99 \times0.99)+ 0.99(0.02 \times0.02)}[/tex]

the probability that he is a drug user since failed his second drug test

= [tex]\dfrac{0.01 \times(0.9801)}{0.01 \times (0.9801)+ 0.99(4 \times 10^{-4})}[/tex]

the probability that he is a drug user since  failed his second drug test

= [tex]\dfrac{0.009801}{0.009801+ 3.96 \times 10^{-4}}[/tex]

the probability that he is a drug user since  failed his second drug test

= 0.961165

a. Which number is greater? 1/4 or 5/4 -3/4 or 5/8

b. Which number is farther from 0? 1/4 or 5/4 -3/4 or 5/8

c. Is the number that is farther from 0 always the greater number?

Answers

Answer:

a. Which number is greater? 1/4 or 5/4 -3/4 or 5/8:

answer: 5/4

b. Which number is farther from 0? 1/4 or 5/4 -3/4 or 5/8:

answer: 5/4

c. Is the number that is farther from 0 always the greater number?:

answer: nah really.

A number can be further from zero but when it's a negative or positive. But negative value is less than zero.

[tex] {}^{ - } \infin \leqslant 0 \leqslant {}^{ + } \infin[/tex]

(a) answer is 5/4

(b) answer is 5/4

(c) No , when dealing with negative numbers , the number closer to zero is the bigger number . zero has the unique distinction of being neither positive nor negative . zero separates the positive number from the negative ones .

hope this will help you

mrk above ans braniliest

Simplify 6.92 to the exponent of 1000

Answers

Answer:

Whatever is raised to the power of 0 is 1

SO the answer is 1

Someone help me!!! Help

Answers

Answer B.ED

Step-by-step explanation:

Simplify (3n - 2m)^2 = Can someone break this down for me? I don't understand why I'm having issues with this.

Answers

Answer:

9n² - 12mn + 4m²

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

(3n - 2m )² = (3n-2m)(3n-2m) = 3n*3n + 3n*-2m -2m*3n - 2m*-2m

= 9n² - 6nm -6mn + 4m²

= 9n² - 12mn + 4n²

Answer:

Once you simplify the given expression, your answer will be 9n² - 12mn + 4m

Step-by-step explanation:

In this problem, we are given an expression.

(3n - 2m)²

when an expression or equation is raised to the power of 2, then you are going to multiply the base term by itself. For example, if you have 2² or 16², then would you do 2 × 2 and 16 × 16 in order to solve the expressions. We will do the same for this expression.

(3n - 2m)² = (3n - 2m) × (3n - 2m)

We will use the foil method to solve this expression

(3n - 2m)(3n - 2m)

9n² - 6mn - 6mn + 4m

Combine like terms together.

9n² - 12mn + 4m

So, the simplified form of the expression is 9n² - 12mn + 4m

In the given figure, if POQ is a straight line then find ∠POT. please help !!!!!!

Answers

Answer:

∠POT = 78°

Step-by-step explanation:

If POQ is straight then

x + 18° + 50° + x + 24° = 180° add like terms

2x + 92° = 180°

2x = 180° - 92°

2x = 88° and x = 44 If we say SOT is a straight line then

∠POT + 50° + x + 18° = 180°

∠POT + 102° = 180°

∠POT = 78°

A line passes through the point (2, 3) and has a slope of -8. Write an equation for this line.

Answers

Answer:

y = -8x+19

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = -8x+b

Substitute the point into the equation

3 = -8(2)+b

3 = -16+b

Add 16 to each side

3+16 = b

19 = b

y = -8x+19

Step-by-step explanation:

to find the equation of this line you use the equation of the slope intercept which is y-y1= m (x-x1)

y-3=-8(x-2)

y-3=-8x+16

y=-8x+16+3

y=-8x+19

I hope this helps

(3+4i)^2

(2+4i)(7-8i)

Answers

Answer:

10 (-61 + 102 i)

(3 + 4 i)^2 (2 + 4 i) (7 - 8 i)  

Step-by-step explanation:

(3 + 4 i)^2 (2 + 4 i) (7 - 8 i)

10 (-61 + 102 i)

r = 50 sqrt(565) (radio), θ = π - tan^(-1)(102/61) (ángulo)

50 sqrt(565) (cos(π - tan^(-1)(102/61))+i sin(π - tan^(-1)(102/61)))

50 sqrt(565) e^(i (π - tan^(-1)(102/61)))

x^2 + 1220 x + 1412500

4) If the perimeter of a square is 48cm",
What is the length of each side?
Simplify your answer.

Answers

Answer:

If the total perimeter of square is 48 cm, then the length of one side is equal to 48 divided by 4, since all sides of a square are the same.

So, the correct answer is 12.

Let me know if this helps!

The length of each side is 12cm.

Explanation:

The perimeter of a square is calculated by the formula:

P = 4a , where  P = perimeter, and a = length of any side, all sides being equal in a square.

From the given data we write:

48 = 4a

Divide both sides by

4.12 = a

The length of each side is 12cm.

The Masmim family’s monthly budget is shown in the circle graph provided in the image. The family has a current monthly income of $5,000. How much money do they spend on food each month? A. $250 B. $500 C. $750 D. $1,100 Please include ALL work! <3

Answers

The correct answer is $750

Explanation:

The total of food the Masmin family spend according to the graph is 15%. Now, to know the amount of money this represents, it is necessary to find the 15% of $5000, which is the total budget. The steps to do this are shown below.

1. To calculate the percentage of a given number, first, write all values

5000 = 100%

 x       =  15%

2. Use cross multiplication, this means you multiply 5000 by 15 and x by 15

x 100 = 75000

3. Solve the equation to find x or the 15% of 5000

x = 75000 ÷ 100

x = 750

BRAINLIST AND A THANK YOU AND 5 stars WILL BE REWARDED PLS ANSER

Answers

Answer:

The first picture's answer would be (6, 21)

Step-by-step explanation:

You have to find the points on the 8th and the 9th day, and then you would add them together, and then divide by two finding the average, which would be 24 and 18, so when added, you get 42, divided by 2 you get 21. You look on the graph for the point with 21, and you find it is on 6.

paul worked 50 hours last week. if he earns $10 per hour plus time-and-a-half for any hours worked beyond 40 in a week, how much did he earn last week?

Answers

Answer: 4150

Step-by-step explanation:

You take the 50, becuse the amount earned increases once you surpass 40 you do 40 x 10 and that = 4000 then you take the remaining 10 and times that by 15 (becuse after 40 it is 1.5 of what you where earning before you hit 40 hours and half of ten is 5 so you do 10 plus 5 and times that by 10) then add both numbers together and you have 4150! Hope that helped!

Help!!! QUICK! What is the pattern of the exponents on the a terms in Pascal's Triangle?


A. The largest exponent value of the a terms is equal to one more than the value of the exponent on the binomial. The exponent values then decrease from left to right.


B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.


C. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values are then equal to 0 throughout the expansion.


D.The largest exponent value of the a terms is equal to one more than the value of the exponent on the binomial. The exponent values are then equal to 1 throughout the expansion.

Answers

Answer:

B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.

Step-by-step explanation:

The exponent values of the a terms increase from one side of the binomial to the other. The value of the largest exponent is equal to part of the binomial expression.

Suppose you have a bag with the following in it: 5 one dollar bills, 4 fives, 3 tens, 5 twenties, and 3 fifties. Assuming the experiment requires drawing one bill from the bag at random, complete the probability distribution for this experiment.

Required:
What is the probability of drawing 9 dollars or less in a single draw?

Answers

Answer:

(a) Probility Distribution

Outcome   probability

$1               5/15 = 1/3

$5              4/15

$10             3/15 = 1/5

$20            5/15 = 1/3

(b) P($9 or less) =  3/5

Step-by-step explanation:

(a) Probility Distribution

Outcome   probability

$1               5/15 = 1/3

$5              4/15

$10             3/15 = 1/5

$20            5/15 = 1/3

Any other denomination

                  0

(b)

ways to draw $9 or less in a single draw

P($1) = 1/3

P($5) = 4/15

P($9 or less) = P($1) + P($5) = 1/3 + 4/15 = 9/15 = 3/5

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