Answer: The cube with side length of 12cm is alone in one plate, the other 3 cubes are in the other plate.
Step-by-step explanation:
We have 4 cubes with side lengths of:
6cm, 8cm, 10cm and 12cm.
Now, some things you need to know:
If we want a scale to be balanced, then the mass in both plates must be the same.
The volume of a cube of side length L is:
V = L^3
And the mass of an object of density D, and volume V is:
M = D*V.
As all the cubes are of the same material, all of them have the same density, so the fact that we do not know the value of D actually does not matter here.
Then we want to forms two groups of cubes in such a way that the total volume in each plate is the same (or about the same), the volumes of the cubes are:
Cube of 6cm:
V = (6cm)^3 = 216cm^3
Cube of 8cm:
V = (8cm)^3 = 512cm^3
Cube of 10cm:
V = (10cm)^3 = 1000cm^3
cube of 12cm
V = (12cm)^3 = 1728cm^3
First, if we add the volumes of the first two cubes, we have:
V1 = 216cm^3 + 512cm^3 = 728cm^3
Now we can see that we add 1000cm^3 the volume will be equal to the volume of the larger cube, so here we can also add the cube with side length of 10cm
Then the volume of the 3 smaller cubes together is:
V1 = 216cm^3 + 512cm^3 + 1000cm^3 = 1728cm^3.
Then, if we want to have the same volume in each plate, then we need to have the 3 smaller cubes in one plate, and the larger cube in the other plate.
Three students were given the expression shown and were asked to take a common factor out of two of the terms. Use the drop-down menus to complete the statements about whether each student's answer is an equivalent expression. Then choose an expression that is equivalent.
Answer:
Step-by-step explanation:
Given: 4 - 9x +21
Factorizing this expression, we have;
4 -3(3x - 7)
i. Chang's expression: 4 - 3(3x + 7)
This is not an equivalent expression, because by expansion of the bracket, the expression gives: 4 -9x -21
ii. Benjamin's expression: 4 + 3(3x + 7)
This is not an equivalent expression, because by expansion of the bracket, the expression gives: 4 +9x +21
iii. Habib's expression: 4 + 12x
This is not an equivalent expression, because the expression is not related to the given question
Comparing the three student's answers with the appropriate expression, none of the student's is an equivalent expression.
This expression that is equivalent to the given question is;
4 -3(3x - 7) = 4 -9x + 21
Answer:
1,2,4
Step-by-step explanation:
what is the decimal equivalent of 7/20
Sum of × +1 and × + 2
Step-by-step explanation:
X +1 + X + 2
X + X + 1 + 2
2x + 3
Therefore it's 2x + 3
What is the volume of a cube with a side length of
of a unit?
formula of a square minus b square
Answer:
(a+b)(a-b)
Step-by-step explanation:
[tex]\\ \sf\longmapsto (a+b)(a-b)[/tex]
[tex]\\ \sf\longmapsto a(a-b)+b(a-b)[/tex]
[tex]\\ \sf\longmapsto a^2-ab+ba-b^2[/tex]
[tex]\\ \sf\longmapsto a^2-ab+ab-b^2[/tex]
[tex]\\ \sf\longmapsto a^2-b^2[/tex]
[tex]\large\bf{\orange{ \implies}} \: \tt \: {a}^{2} \: - \: {b}^{2} [/tex]
[tex]\large\bf{\pink{ \implies}} \: \tt \: (a + b) \quad \: (a - b)[/tex]
[tex]\large\bf{\pink{ \implies}} \: \tt \: a \: (a - b) \quad \: b \: (a - b)[/tex]
[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: ab \: + \: ba \: - \: {b}^{2} [/tex]
[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: ab \: + \: ab \: - \: {b}^{2} [/tex]
[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: \cancel{ab} \: + \: \cancel{ab} \: - \: {b}^{2} [/tex]
[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: {b}^{2} [/tex]
Lillie is saving up for a trip she is taking with friends during her break from school. If Lillie's current monthly net pay is $560.00 and her monthly expenses are $347.49, what percent of her net pay is left for savings? (2 points)
19%
23%
38%
Answer:
38%
Step-by-step explanation:
First determine her savings
560-347.49
212.51
Then divide by the total amount
212.51/560
.379482143
Change to percent form
37.948%
Answer:
38%
Step-by-step explanation:
[tex]560.00-347.49=212.51\\212.51\div560.00==38[/tex]
3,
If an angle measures 29°, find its supplement.
7
4
Kelsey is drawing a triangle with angle measures of 128° and 10°. What is the measure of
the missing angle?
A
1280
10°
В
not to scale
7.6.2 DOK
9514 1404 393
Answer:
3. 151°
4. 42°
Step-by-step explanation:
3. The measure of the supplement is found by subtracting the angle from 180°.
supplement of 29° = 180° -29° = 151°
__
4. The total of angles in a triangle is 180°, so the third one can be found by subtracting the other two from 180°.
third angle = 180° -128° -10° = 42°
Aiko and Kendra arrive at the Texas
State Fair with $60. What is the total
number of rides they can go on if
they each pay the entrance fee of
$17 and rides cost $3 each?
Answer:
They can go on 14 rides the maximum.
Step-by-step explanation:
First, you have to set up the equation. Basically, Aiko and Kendra only carry $60 with them. They cannot go over that limit. Furthermore, the entrance free is $17. Each ride is $3.
(x = the amount of rides)
17 + 3x ≤ 60
17 represents the entrance fee which only has to be paid one time. 3x represents the cost of each ride (x equals to the amount of rides).
Now you solve.
Isolate the variable, which is 3x.
3x ≤ 60 - 17
3x ≤ 43
Now, divide 43 by 3 to find the value of x.
x ≤ 43 ÷ 3
x ≤ 14.3333333333
They can go on a max of 14 rides. Anymore, and they will go over budget. Normally, with problems like this one, if you have a decimal, you should round down unless your instructor says otherwise.
After all, who would you be able to go on a third of a ride? It isn't possible, so generally, they just have you round down.
How much money will there be in an account at the end of 10 years if $4000 is deposited at 6% compounded quarterly
Answer:
$7,256.07
Step-by-step explanation:
A = p(1+r/n)^nt
A = 4000(1+.06/4)^(10*4)
Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped). Consider a random sample of 200 shafts, and let X denote the number among these that are nonconforming and can be reworked.Required:a. What is the (approximate) probability that X is at most 30?b. What is the (approximate) probability that X is less than 30?c. What is the (approximate) probability that X is between 15 and 25 (inclusive)?
Answer:
(a) The probability that X is at most 30 is 0.9726.
(b) The probability that X is less than 30 is 0.9554.
(c) The probability that X is between 15 and 25 (inclusive) is 0.7406.
Step-by-step explanation:
We are given that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked. A random sample of 200 shafts is taken.
Let X = the number among these that are nonconforming and can be reworked
The above situation can be represented through binomial distribution such that X ~ Binom(n = 200, p = 0.11).
Here the probability of success is 11% that this much % of all steel shafts produced by a certain process are nonconforming but can be reworked.
Now, here to calculate the probability we will use normal approximation because the sample size if very large(i.e. greater than 30).
So, the new mean of X, [tex]\mu[/tex] = [tex]n \times p[/tex] = [tex]200 \times 0.11[/tex] = 22
and the new standard deviation of X, [tex]\sigma[/tex] = [tex]\sqrt{n \times p \times (1-p)}[/tex]
= [tex]\sqrt{200 \times 0.11 \times (1-0.11)}[/tex]
= 4.42
So, X ~ Normal([tex]\mu =22, \sigma^{2} = 4.42^{2}[/tex])
(a) The probability that X is at most 30 is given by = P(X < 30.5) {using continuity correction}
P(X < 30.5) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{30.5-22}{4.42}[/tex] ) = P(Z < 1.92) = 0.9726
The above probability is calculated by looking at the value of x = 1.92 in the z table which has an area of 0.9726.
(b) The probability that X is less than 30 is given by = P(X [tex]\leq[/tex] 29.5) {using continuity correction}
P(X [tex]\leq[/tex] 29.5) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{29.5-22}{4.42}[/tex] ) = P(Z [tex]\leq[/tex] 1.70) = 0.9554
The above probability is calculated by looking at the value of x = 1.70 in the z table which has an area of 0.9554.
(c) The probability that X is between 15 and 25 (inclusive) is given by = P(15 [tex]\leq[/tex] X [tex]\leq[/tex] 25) = P(X < 25.5) - P(X [tex]\leq[/tex] 14.5) {using continuity correction}
P(X < 25.5) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{25.5-22}{4.42}[/tex] ) = P(Z < 0.79) = 0.7852
P(X [tex]\leq[/tex] 14.5) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{14.5-22}{4.42}[/tex] ) = P(Z [tex]\leq[/tex] -1.70) = 1 - P(Z < 1.70)
= 1 - 0.9554 = 0.0446
The above probability is calculated by looking at the value of x = 0.79 and x = 1.70 in the z table which has an area of 0.7852 and 0.9554.
Therefore, P(15 [tex]\leq[/tex] X [tex]\leq[/tex] 25) = 0.7852 - 0.0446 = 0.7406.
It can be shown that the line with intercepts (a, 0) and (0, b) has the following equation:
x/a + y/b= 1, a ≠ 0, b ≠ 0.
Use this result to write an equation of the line.
Point on line:
(−2, 4)
x-intercept: (a, 0)
y-intercept: (0, a)
(a ≠ 0)
The equation of the straight line is [tex]x+y=2[/tex].
Given:
The line with intercepts (a,0) and (0,b) has the equation [tex]\frac{x}{a} +\frac{y}{b} =1, a\neq 0, b\neq 0[/tex] Point on the line: (-2, 4)x-intercept: (a, 0)y-intercept: (0, a)[tex]a\neq 0[/tex]To find: The equation of this line
It is given that a line with intercepts (a,0) and (0,b) has the equation [tex]\frac{x}{a} +\frac{y}{b} =1, a\neq 0, b\neq 0[/tex]
Now, it is given that the referred line has intercepts (a, 0) and (0, a). Then, using the above statement, the equation of this line can be written as,
[tex]\frac{x}{a} +\frac{y}{a}=1[/tex]. It is already given that [tex]a\neq 0[/tex]. So, we need not mention it again.
It is also given that the point (-2, 4) lies on this line. Then, the coordinates of this point must satisfy the equation of the line.
This implies that,
[tex]\frac{-2}{a} +\frac{4}{a} =1[/tex]
[tex]\frac{2}{a} =1[/tex]
[tex]a=2[/tex]
Now, put [tex]a=2[/tex] in the equation of the line, [tex]\frac{x}{a} +\frac{y}{a}=1[/tex] to get,
[tex]\frac{x}{2} +\frac{y}{2} =1[/tex]
[tex]x+y=2[/tex]
So, the equation of the line is [tex]x+y=2[/tex].
Learn more about equations of straight lines here:
https://brainly.com/question/18879008
Ethan has collected 417 football cards. He shares them equally between himself and his two friends. How many will each person get
Answer:
139 cards
Step-by-step explanation:
This is basically just a division statement - we have 417 cards and want to split it with 3 people (two friends + himself = 3 people).
We can divide these using a calculator or long division, but either way you will get:
[tex]417\div3=139[/tex]
Hope this helped!
Answer: 139
Step-by-step explanation:
417 divided by 3 gives you 139.
evaluate the expression for -c-12=
Answer:
-10
Step-by-step explanation:
We can substitute c into the equation as -2.
[tex]-(-2) - 12[/tex]
Two negatives make a positive:
[tex]2-12[/tex]
And [tex]2 - 12 = -10[/tex].
Hope this helped!
PLS PLS PLS HELP QUICKKKK
Find the value of x in each case
Answer:
KI and HE are parallel
So we apply the law of exterior angles ;
3X=X + 180– 2X
3X +X = 180
4X= 180
X= 180/4
X= 45
I hope I helped you^_^
Ashley, Milan, and Carlos sent a total of 131 text messages over their cell phones during the weekend. Carlos sent 7 times as many messages as Ashley. Ashley sent 4 more messages than Milan. How many messages did they each send?
Answer:
Ashley= 15
Milan= 11
Carlos= 105
Step-by-step explanation:
Let, A, M and C denotes Ashley, Milan and Carlos respectively.
A+M+C= 131 (according to the question)
Here,
C= 7A
A= M+ 4
So, M= A - 4
Now,
A+M+C = 131
or, A+ A-4+ 7A = 131 (putting the values)
or, 9A - 4 = 131 (adding like terms i.e. A + A + 7A)
or, 9A = 131 + 4
or, 9A = 135
or, A = 135 / 9
So, A = 15
C= 7A = 7×15= 105
M= A-4 = 15 - 4 = 11
The heat evolved in calories per gram of a cement mixture is approximately normally distributed. The mean is thought to be 100, and the standard deviation is 2. You wish to test H0: μ = 100 versus H1: μ ≠ 100 with a sample of n = 9 specimens.
A. If the acceptance region is defined as 98.5 le x- 101.5, find the type I error probability alpha.
B. Find beta for the case where the true mean heat evolved is 103.
C. Find beta for the case where the true mean heat evolved is 105. This value of beta is smaller than the one found in part (b) above. Why?
Answer:
A.the type 1 error probability is [tex]\mathbf{\alpha = 0.0244 }[/tex]
B. β = 0.0122
C. β = 0.0000
Step-by-step explanation:
Given that:
Mean = 100
standard deviation = 2
sample size = 9
The null and the alternative hypothesis can be computed as follows:
[tex]\mathtt{H_o: \mu = 100}[/tex]
[tex]\mathtt{H_1: \mu \neq 100}[/tex]
A. If the acceptance region is defined as [tex]98.5 < \overline x > 101.5[/tex] , find the type I error probability [tex]\alpha[/tex] .
Assuming the critical region lies within [tex]\overline x < 98.5[/tex] or [tex]\overline x > 101.5[/tex], for a type 1 error to take place, then the sample average x will be within the critical region when the true mean heat evolved is [tex]\mu = 100[/tex]
∴
[tex]\mathtt{\alpha = P( type \ 1 \ error ) = P( reject \ H_o)}[/tex]
[tex]\mathtt{\alpha = P( \overline x < 98.5 ) + P( \overline x > 101.5 )}[/tex]
when [tex]\mu = 100[/tex]
[tex]\mathtt{\alpha = P \begin {pmatrix} \dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{\overline 98.5 - 100}{\dfrac{2}{\sqrt{9}}} \end {pmatrix} + \begin {pmatrix}P(\dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}} > \dfrac{101.5 - 100}{\dfrac{2}{\sqrt{9}}} \end {pmatrix} }[/tex]
[tex]\mathtt{\alpha = P ( Z < \dfrac{-1.5}{\dfrac{2}{3}} ) + P(Z > \dfrac{1.5}{\dfrac{2}{3}}) }[/tex]
[tex]\mathtt{\alpha = P ( Z <-2.25 ) + P(Z > 2.25) }[/tex]
[tex]\mathtt{\alpha = P ( Z <-2.25 ) +( 1- P(Z < 2.25) })[/tex]
From the standard normal distribution tables
[tex]\mathtt{\alpha = 0.0122+( 1- 0.9878) })[/tex]
[tex]\mathtt{\alpha = 0.0122+( 0.0122) })[/tex]
[tex]\mathbf{\alpha = 0.0244 }[/tex]
Thus, the type 1 error probability is [tex]\mathbf{\alpha = 0.0244 }[/tex]
B. Find beta for the case where the true mean heat evolved is 103.
The probability of type II error is represented by β. Type II error implies that we fail to reject null hypothesis [tex]\mathtt{H_o}[/tex]
Thus;
β = P( type II error) - P( fail to reject [tex]\mathtt{H_o}[/tex] )
∴
[tex]\mathtt{\beta = P(98.5 \leq \overline x \leq 101.5) }[/tex]
Given that [tex]\mu = 103[/tex]
[tex]\mathtt{\beta = P( \dfrac{98.5 -103}{\dfrac{2}{\sqrt{9}}} \leq \dfrac{\overline X - \mu}{\dfrac{\sigma}{n}} \leq \dfrac{101.5-103}{\dfrac{2}{\sqrt{9}}}) }[/tex]
[tex]\mathtt{\beta = P( \dfrac{-4.5}{\dfrac{2}{3}} \leq Z \leq \dfrac{-1.5}{\dfrac{2}{3}}) }[/tex]
[tex]\mathtt{\beta = P(-6.75 \leq Z \leq -2.25) }[/tex]
[tex]\mathtt{\beta = P(z< -2.25) - P(z < -6.75 )}[/tex]
From standard normal distribution table
β = 0.0122 - 0.0000
β = 0.0122
C. Find beta for the case where the true mean heat evolved is 105. This value of beta is smaller than the one found in part (b) above. Why?
[tex]\mathtt{\beta = P(98.5 \leq \overline x \leq 101.5) }[/tex]
Given that [tex]\mu = 105[/tex]
[tex]\mathtt{\beta = P( \dfrac{98.5 -105}{\dfrac{2}{\sqrt{9}}} \leq \dfrac{\overline X - \mu}{\dfrac{\sigma}{n}} \leq \dfrac{101.5-105}{\dfrac{2}{\sqrt{9}}}) }[/tex]
[tex]\mathtt{\beta = P( \dfrac{-6.5}{\dfrac{2}{3}} \leq Z \leq \dfrac{-3.5}{\dfrac{2}{3}}) }[/tex]
[tex]\mathtt{\beta = P(-9.75 \leq Z \leq -5.25) }[/tex]
[tex]\mathtt{\beta = P(z< -5.25) - P(z < -9.75 )}[/tex]
From standard normal distribution table
β = 0.0000 - 0.0000
β = 0.0000
The reason why the value of beta is smaller here is that since the difference between the value for the true mean and the hypothesized value increases, the probability of type II error decreases.
One number is eight less than a second number. Five times the first is 6 more than 6 times the second. Find the numbers.
The value of the first number is -
Answer:
-42/11
Step-by-step explanation:
x = y - 8
5x = 6 - 6y
So now solve the system of equations, divide everything in the second equation by 5 to get it to x = 6/5 - 6y/5
Now...
x = y - 8
x = 6/5 - 6y/5
Now substitute first equation into the second and x is gonna be -42/11 or the first number
If f(x) = 3x-1 and g(x)= x+2 find (f-g) (x)
Answer:
2x-3
Step-by-step explanation:
f(x) = 3x-1
g(x)= x+2
(f-g) (x) = 3x-1 - (x+2)
Distribute the minus sign
= 3x-1 -x-2
Combine like terms
= 3x-x -1-2
=2x -3
If P is the midpoint of XY, XP = 8x - 2 and PY = 12x - 30, find the
value of x.
Answer:
x=7
Step-by-step explanation:
If P is the midpoint of XY, then XP = PY:
8x - 2 = 12x - 3012x -8x = 30 -24x = 28x= 28/4x= 7a shopping center form 300000 square feet to an excess of 1 million square feer that consists mostly of large national chain stores is called a
Answer: Honeymoon2871
Step-by-step explanation:
here is my question hope this works now
Answer:
[tex]\boxed{x=1}[/tex] and [tex]\boxed{x=7}[/tex]
Step-by-step explanation:
This quadratic is already factored down to its factors (x - 1) and (x - 7).
Set these equal to zero and solve for x by adding 1 or 7 to both sides of the equation.
[tex]x-1=0\\\\\boxed{x=1}[/tex]
[tex]x-7=0\\\\\boxed{x=7}[/tex]
Please answer this correctly without making mistakes
Answer:
1/2 mi
Step-by-step explanation:
Fairfax to Greenwood is equal to one mile
Now think of it as an equation and substitute 1/2 for fairfax and x for greenwood
1/2 + x = 1
This means that x = 1/2
Because of this from Arcadia to Greenwood it is 1/2 mi
7.19 We are given the following probability distribution. x P(x) b. c. d. 0 1 2 3 .1 .4 .3 .2 a. Calculate the mean, variance, and standard deviation.
Answer:
Mean = 1.6
Variance = 0.84
Standard deviation = 0.916
Step-by-step explanation:
We are given the following probability distribution below;
X P(X) [tex]X \times P(X)[/tex] [tex]X^{2} \times P(X)[/tex]
0 0.1 0 0
1 0.4 0.4 0.4
2 0.3 0.6 1.2
3 0.2 0.6 1.8
Total 1.6 3.4
Now, the mean of the probability distribution is given by;
Mean, E(X) = [tex]\sum X \times P(X)[/tex] = 1.6
Also, the variance of the probability distribution is given by;
Variance, V(X) = [tex]\sum X^{2} \times P(X) - (\sum X \times P(X))^{2}[/tex]
= [tex]3.4 - (1.6)^{2}[/tex]
= 3.4 - 2.56 = 0.84
And the standard deviation of the probability distribution is given by;
Standard deviation, S.D. (X) = [tex]\sqrt{Variance}[/tex]
= [tex]\sqrt{0.84}[/tex] = 0.916.
janice is buying paint to paint her new apartment
Answer:
I canot answer this
Step-by-step explanation:
0.18 divided by 0.04
Given the set of data: 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25 Determine the quartiles.
Answer:
Lower quartile= 4.75
Middle quartile= 9.5
Upper quartile= 14.25
Step-by-step explanation:
The given date set is 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25
On counting them we notice that it's number of element is 18
So N = 18
Arranging them in ascending order gives
12,18,18,20,23,24,24,25,25,29,31,43,43,43,53,53,65,78
Lower quartile= (N+1)*1/4
Lower quartile= (18+1)/4
Lower quartile= 19/4
Lower quartile= 4.75
Middle quartile= (N+1)*2/4
Middle quartile= (18+1)*2/4
Middle quartile= (19)*2/4
Middle quartile= 9.5
Upper quartile= (N+1)*3/4
Upper quartile= (18+1)*3/4
Upper quartile= (19)*3/4
Upper quartile= 14.25
Inter quartile range = upper quartile- minutes lower quartile
= 14.25-4.75
= 9.5
Can someone help me ASAP!!!?
Answer:
√x-x-2x³+√x+x
= 2√x-2x³
= -2x³+2√x
which is option A
What is the solution for the quadratic equation?
If x=64 &y=27 Evaluate x½-y⅓÷y-x⅔
━━━━━━━☆☆━━━━━━━
▹ Answer
-191/162
▹ Step-by-Step Explanation
Answer:
-191/162
Step-by-step explanation:
Substitute the numbers for the variables:
64 1/2 - 27 1/3 ÷ 27 - 64 2/3
Convert the mixed numbers to improper fractions:
129/2 - 82/3 * 1/27 - 194/3
Multiply the improper fractions:
129/2 - 82/81 - 194/3
= -191/162
Hope this helps!
CloutAnswers ❁
━━━━━━━☆☆━━━━━━━
. A population is currently 6,000 and has been increasing by 1.2% each day. Write an exponential model for the population.
Answer: [tex]A=6000(1.012)^t[/tex]
Step-by-step explanation:
General exponential function:
[tex]A=P(1+r)^t[/tex]
, where P= current population
r= rate of growth
t= time period
A= population after t years
As per given , we have P=6,000
r= 1.2% = 0.012
Then, the required exponential function: [tex]A=6000(1+0.012)^t[/tex]
or [tex]A=6000(1.012)^t[/tex]