Answer:
The resistance is [tex]R = 2.88 \ \Omega[/tex]
Explanation:
From the question we are told that
The voltage rating of the headlamp is [tex]V_1 = 12 \ V[/tex]
The voltage of the power system is [tex]p = 24 \ V[/tex]
The power rating of the headlamp is [tex]P = 50 W[/tex]
Generally the power which the resistor dissipates is mathematically represented as
[tex]P = V_L * I[/tex]
=> [tex]50 = 12 * I[/tex]
=> [tex]I = 4.1667 \ A[/tex]
Generally the resistance is
[tex]R = \frac{V_1 }{I}[/tex]
[tex]R = \frac{12 }{4.1667}[/tex]
[tex]R = 2.88 \ \Omega[/tex]
A resistance of 4 ohm is offered by a conductor when a potential difference of 6 V l'd applied across it. Calculate the current through it?.
Answer:
1.5 Ampere
Explanation:
The formula is V=IR
so now we can derive out the formula which is
I =V
R
I = 6
4
I = 1.5 Ampere
Joey drives his Skidoo 13 kilometres north. He stops for lunch and then drives 10kilometres south. What distance did he cover? What was his displacement?
Answer:
Total distance covered (scalar quantity) = 23 km
Displacement (vector quantity) = 3 km north from the original starting point
Explanation:
Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km
On the other hand, his displacement was 3 km north from where he started.
A paper pinwheel is spinning in the wind. Which statement is correct about the forces responsible for the rotation?
A. The perpendicular components of gravity and the force of wind are responsible for the rotation.
B. Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
C. The components of gravity and the force of wind that point through the pivot are responsible for the rotation.
D. Only the perpendicular component of gravity is responsible for the rotation, because wind points toward the pivot.
Answer:
Only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.
Explanation:
A person drives a car around a circular cloverleaf with a radius of 77 m at a uniform speed of 10 m/s. What is the acceleration of the car?
Answer:
770m/s
Explanation:
caculation using one of the newton law of motion
if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.
Answer:
4 seconds
Explanation:
Given:
v₀ = 20 m/s
v = 0 m/s
a = -5 m/s²
Find: t
v = at + v₀
0 m/s = (-5 m/s²) t + 20 m/s
t = 4 s
5. What occurs when an enzyme and a substrate interact at an
active site?
a. Activation energy is reduced.
b. The products are bound irreversibly.
c. The enzyme is changed by the reaction.
d. Activation energy is increased.
Answer:
B
Explanation:
The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex
When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.
What are enzymes?Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.
All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.
Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.
Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.
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in a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance they travel by a multiple of
Answer:
The path difference will be zero.
Explanation:
Given that,
In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.
Suppose, we find the multiple of wavelength
In young's double slit experiment,
We need to calculate the multiple of wavelength
Using formula of path difference
[tex]\Delta x=d\sin\theta[/tex]....(I)
[tex]d\sin\theta=m\lambda[/tex]
Where, m = fringe number
[tex]\lambda[/tex] = wavelength
For center of a bright fringe ,
m = 0
Put the value into the formula
[tex]d\sin\theta=0\times\lambda[/tex]
[tex]d\sin\theta=0[/tex]
Put the value in equation (I)
[tex]\Delta x=0[/tex]
Hence, The path difference will be zero.
A Nichrome wire 50 cm long and 0.27 mm in diameter is connected to a 1.5 V flashlight battery. What is the electric field inside the wire
Answer:
E=3V/m
Explanation:
The electric field here is simply the voltage running through the wire divided by its length. (Meaning E is independent of the diameter of the wire.)
Short work is in the attachment.
1: A generator produces electricity at about 21,600 V. This voltage needs to be increased to about 345,000 V via a transformer before being transmitted through the power grid. What is the ratio of windings between the secondary coil and the primary coil needed to do this
Answer:
16:1
Explanation:
From the question,
Since the voltage of the transformer is increased, then the winding in the secondary coil is greater than the winding in the primary coil
Applying transformer's equation
Vs/Vp = Ns/Np............. Equation 1
Where Vs = Secondary voltage, Vp = primary Voltage, Ns/Np = Ratio of the winding between the secondary coil to the winding in the primary coil.
Given: Vs = 345000 V, Vp = 21600 V
Substitute these values into equation 1
Ns/Np = 345000/21600
Ns/Np = 16:1
PHYSICS HW HELP PLS!! explain how you got it too thank you! :)
1.) F= Gm1m2/d2 for m2
2.) R= V/I for I
3.) = xd/L for d
4.) ac= v^2/r for v
5.) A= πr^2 for r
6.) vf^2= vi^2+2ax for x
Answer:
Explanation:
Can you please place the square roots in a proper manner so I may assist you?
A trucker drives with an average velocity of 27 m/s toward the east on a perfectly
straight highway.What will the trucker's displacement be after 2.0 h?
Answer:
The displacement of the driver is 194400m in the east direction
Explanation:
In physics, the displacement of a body is the distance the body travels in a specified direction.
We are told that the trucker is driving east on a perfectly straight highway. From this, we know that his direction is East. The thing left will be to find the distance travelled within 2 hours.
We can convert the time (2 hours) to seconds by multiplying it by 3600
2 hours = 7200 seconds
The distance travelled will be obtained by a product of truck's speed and the time travelled.
distance = 27m/s X 7200 s = 194400m
Therefore the displacement of the driver is 194400m in the east direction
. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional analysis, find the dimensionality of B.
Answer:
The dimensionality of B is length per cubic time.
Explanation:
Units for displacement and time are length [tex][L][/tex] and time [tex][T][/tex], respectively. Then, formula can be tested for dimensional analysis as follows:
[tex][L] = B\cdot [T]^{3}[/tex]
Now, let is clear [tex]B[/tex] to determine its units:
[tex]B = \frac{[L]}{[T]^{3}}[/tex]
The dimensionality of B is length per cubic time.
A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency of 2 Hz, what is the speed of the wave that travels through the string to the other end?
Wave speed = (wavelength) x (frequency)
Wave speed = (0.5 m) x (2 /sec)
Wave speed = 1 m/s
A right triangle has a hypotenuse of 37 and a leg of 10. What is the second leg of the triangle?
Answer:
The second leg of the triangle is 35.62
Explanation:
Given that
Hypotenuse = 37
A leg = 10
Based on the above information
The second leg of the triangle is
According to the Pythagorean theorem
a^2 + b^2 = c^2
where,
a and b = legs
And, the c = hypotenuse.
Now put these values to the above formula
So,
10^2 + b^2 = 37^2
b^2 = 37^2 - 10^2
b^2 = 1269
b = sqrt(1269)
b = 35 .62
Hence, the second leg of the triangle is 35.62
The other leg is 35 mm.
a train it speed steading from 10 m/s to 20m/s in 1 minutes average speed during this time in m/s
how far does it travel while increase its speed
Explanation:
Given:
v₀ = 10 m/s
v = 20 m/s
t = 60 s
Find: v_avg and Δx
v_avg = ½ (v + v₀)
v_avg = ½ (20 m/s + 10 m/s)
v_avg = 15 m/s
Δx = v_avg t
Δx = (15 m/s) (60 s)
Δx = 900 m
A 1700 W laser emits light with a wavelength of 700 nm into a 3.0 mm diameter beam. What force does the laser beam exert on a completely absorbing target?
Answer:
F=5.7×10⁻⁶
Explanation:
Not knowing a formula outright, I decided to follow the units of some relationships I did know. Radiation pressure is defined as force per area and also intensity divided by velocity (the speed of light here of course). Breaking intensity down into power per area and isolating force gave me the relationship F=(Power/Velocity),where power is given and the velocity is a constant.
My work is in the attachment, where I double checked the units too, comment with any questions.
The force exerted by the beam on a completely absorbing target is of 0.0120 N.
Given data:
The power of laser beam is, P = 1700 W.
The wavelength of light emitted from the laser is, [tex]\lambda = 700 \;\rm nm[/tex].
The diameter of the beam is, [tex]d =3.00 \;\rm mm =3.00 \times 10^{-3} \;\rm m[/tex].
When the laser beam strikes the target, then the force exerted by the laser beam on the target is equal to the product of the laser power and the area of projection of beam.
Then the expression is,
[tex]P = \dfrac{F}{A}\\\\F = P \times \dfrac{\pi}{4} d^{2}[/tex]
Solving as,
[tex]F = 1700 \times \dfrac{\pi}{4} \times (3.00 \times 10^{-3})^{2}[/tex]
F = 0.0120 N
Thus, we can conclude that the force exerted by the beam on a completely absorbing target is of 0.0120 N.
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The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm3. (Assume atmospheric pressure.)(a) What is the number of molecules of air inhaled with each human breath when the air temperature is 18.0°C?________molecules(b) If the molar mass of air is 28.96 g/mol, what is the mass of air molecules inhaled with each breath? (Assume the air temperature is 18.0°C.)(c) It has been calculated that all of the air in Earth's atmosphere could be collected into a sphere of diameter 1,999 km at a pressure of 1.00 atm. What is the mass of the air in Earth's atmosphere? (Assume the density of air used in this calculation was 1.225 kg/m3.)(d) If all 7 billion humans on Earth inhaled simultaneously, what percentage of the atmosphere would be inhaled during this process? (Assume the air temperature is 18.0°C everywhere on Earth.)
Answer:
Explanation:
Temperature of air = 18°C = 273 + 18 = 291 K .
volume = 500 cc = 0 .5 litre .
pressure = one atmosphere ( atm) .
From gas equation , we can calculate this volume at NTP as follows.
volume = .5 x ( 273 / 291 ) litre
= 0.469 litre .
In any gas at NTP , 22.4 litre contains 6.02 x 10²³ molecules
.469 litre will contain 6.02 x 10²³ x .469 / 22.4 molecules
= 126 x 10²⁰ molecules .
b )
one mole = 6.02 x 10²³ molecules
6.02 x 10²³ molecules has weight of 28.96 grams
126 x 10²⁰ molecules has weight of 28.96 x 126 x 10²⁰ / 6.02 x 10²³ grams
= .606 gram .
c )
volume of all the air in the atmosphere = volume of sphere
= 4 / 3 x π x R³
= ( 4 / 3) x 3.14 x (999.5 x 10³ )³ m³
= 4.18 x 10¹⁸ m³
density of air = 1.225 kg / m³
mass of air = 1.225 x 4.18 x 10¹⁸ kg
= 5.12 x 10¹⁸ kg
d )
volume of air inhaled by 7 billion people
= . 5 x 7 x 10⁹ litre
= 3.5 x 10⁶ m³ .
Total volume of air in atmosphere = 4.18 x 10¹⁸ m³
required percentage
= 3.5 x 10⁶ x 100 / 4.18 x 10¹⁸
= .8373 x 10⁻¹⁰ % .
2.
Which of the following is NOT a symptom of strong emotions?
A. Impulsiveness
B. Hostility
C. Blindness
D. Distraction
Answer:
blindness
Explanation:
got it right
Blindness is not a symptom of strong emotions in this scenario and is denoted as option C.
What is Emotion?These are mental states brought on by neurophysiological changes and examples include sad, happy etc.
Blindness is a physical condition which involves impairment of the eyes which is why it was chosen.
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whos on the 1 dollar bills
Answer:
George Washington
Explanation:
The image of the famous first President of the United States-George Washington (from 1789 to 1797) is found on every $1 bill. George Washington's image began to be found on the $1 bill in 1869.
We use sponge when we have fever.Which phenomenon best describe the above statement in physics?
Answer: heat loss by conduction
Explanation:
As the thermal energy from our body is flowing to the sponge, our body is losing heat.
an rlc series circuit has a 40.0 resistor,a 3.00 mH inductor, and a 5.00 capacitor, (a find the circuits impendance at 60.0 Hz
Answer:
Z = 530.89 ohms
Explanation:
Given that,
Resistor, R = 40 ohms
Inductor, L = 3 mH
Capacitor, C = 5 μF
We need to find the impedance of the circuit at frequency of 60 Hz. For a series LCR circuit, its impedance is given by the formula as follows :
[tex]Z=\sqrt{R^2+(X_L-X_c)^2} \\\\Z=\sqrt{R^2+(2\pi fL-\dfrac{1}{2\pi fC})^2} \\\\Z=\sqrt{(40)^2+(2\pi \times 60\times 3\times 10^{-3}-\dfrac{1}{2\pi \times 60\times 5\times 10^{-6}})^2} \\Z=530.89\ \Omega[/tex]
So, the impedance of the circuit is 530.89 ohms.
Given that average speed is distance traveled divided by time, determine the values of mm and nn when the time it takes a beam of light to get from the Sun to the Earth (in ss) is written in scientific notation. Note: the speed of light is approximately 3.0××108 m/sm/s.
Complete Question
Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of light to get from the Sun to the Earth (in s) is written in scientific notation. Note: the speed of light is approximately 3.0×108 m/s.
Answer:
The values of m and n is 5 and 2
Explanation:
From the question we are told that
The speed of light is [tex]v = 3.0 *10^{8} \ m/s[/tex]
Generally the distance between the sun and the earth has a constant value
[tex]d = 1.5*10^{11} \ m[/tex]
So the time taken is mathematically evaluated as
[tex]t = \frac{1.5*10^{11}}{3.0*10^{8}}[/tex]
[tex]t = 5.0 *10^{2}[/tex]
Generally scientific notation is represented as
[tex]m* 10^n[/tex]
So comparing the standard representation of scientific notation and the value obtained we see that
m = 5 and n= 2
A small metal ball is given a negative charge, then brought near to end A of an insulating rod. What happens to end A of the rod when the ball approaches it closely this first time
Answer:
Weak attraction will be observed
Explanation:
This is because the charge induction is less than the insulating rod, and a postive charge is induced when a a negative sphere is placed closed to the end of the rod
Acceleration: A water rocket can reach a speed of 75 m/s in 0.050 seconds from launch. What is its average acceleration
Answer:
1500 m/s squared
Hope this helps :)
Explanation:
A poundal is the force required to accelerate a mass of 1 lbm at a rate of 1 ft/s2 , and a slug is the mass of an object that will accelerate at a rate of 1 ft/s2 when subjected to a force of 1 lbf. (a) Calculate the mass in slugs and the weight in poundals of a 135 lbm woman (i) on earth and (ii) on the moon, where the acceleration of gravity is one-sixth of its value on earth. (b) A force of 405 poundals is exerted on a 35.0-slug object. At what rate (m/s2 ) does the object accelerate?
Answer:
We are given that
The
Mass of person = 135lbm
Weight of person on earth will be
= mass x gravity constant
= 135lbm x 32.174 ft/s2
=4343.49 lbm-ft/s2 x 1 poundal-s2/lbm-ft
= 4343.49 poundal
Again we are given that
Mass of person = 135 lbm
But here remember Mass remains the same
So
Weight of person on moon will be
mass x gravity constant on moon
= 135 lbm x 32.174 ft/s2 x 1/6
= 723.9 lbm-ft/s2 x 1 poundal-s2/lbm-ft
= 723.9poundal
But we know that
1 ft slug / lbf-s2 = 32.174 ft lbm/ lbf-s2
So
1 slug = 32.174 lbm
So then the Mass of person
= 135lbm x 1slug/32.174 lbm
=4.2slugs
So finally
Weight = 405 poundals is same as
405 lbm-ft/s2
So
Mass = 35 slug x 32.174 lbm/slug = 1126.09 lbm
Acceleration rate = weight /mass
= (405 lbm-ft/s2) / (1126.09 lbm)
= 0.3597ft/s2 x 0.305m/ft
= 1.179 m/s²
(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
Complete Question
(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
The tensile strength of the nylon string is [tex]600*10^{6} \ N/m^2[/tex]
Answer:
A
T = 471.3 \ N
B
To prevent breakage the thickness of the string is increased
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
Explanation:
From the question we are told that
The diameter is [tex]d = 1.00 \ mm = 0.001 \ m[/tex]
The tensile strength of the nylon string is [tex]\sigma = 600 *10^{6} \ N/m^2[/tex]
Generally the radius is mathematically evaluated as
[tex]r= \frac{d}{2}[/tex]
=> [tex]r = \frac{0.001}{2}[/tex]
=> [tex]r = 0.0005 \ m[/tex]
The cross sectional area is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * (0.005)^2[/tex]
=> [tex]A = 7.855*10^{-7}\ m^2[/tex]
Generally the tensile strength of nylon is mathematically represented as
[tex]\sigma = \frac{T}{ A }[/tex]
Where T is the tension on the maximum tension on the string
So
[tex]T = \sigma * A[/tex]
=> [tex]T = 600*10^{6} * 7.855*10^{-7}[/tex]
=> [tex]T = 471.3 \ N[/tex]
Form the equation above we see that
[tex]T \ \alpha \ A[/tex]
So if the tension is increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional area )
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns through an angle of 80 radians. Assuming the wheel started from rest, how long had it been in motion at the start of the 4.0-s interval?
a. 3 s.
b. 6 s.
c. 9 s.
d. 12 s.
Answer:
a. 3 s.
Explanation:
Given;
angular acceleration of the wheel, α = 4 rad/s²
time of wheel rotation, t = 4 s
angle of rotation, θ = 80 radians
Apply the kinematic equation below,
[tex]\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s[/tex]
Given initial angular velocity, ω₀ = 0
Apply the kinematic equation below;
[tex]\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s[/tex]
Therefore, the wheel had been in motion for 3 seconds.
a. 3 s.
Draw the velocity vectors starting at the black dots and the acceleration vectors including those equal to zero. The orientation of the vectors will be graded. The location and length of the velocity vectors will be graded. The location and length of the nonzero acceleration vectors will not be graded. To draw a zero vector click at the point of its location.
Answer:
hello your question is incomplete attached below is the remaining part and the solution
Explanation:
The accelerations at points 1,2,3 is zero and this is because the velocities at points 1,2,3 are constants. attached below is the velocity vector diagram and the acceleration vectors
what is the significant contribution of Heraclitus
Explanation:
HERACLITUS ALSO SPELLED HERADEITUS, [ BORN C.540 bce, EPHESUS, ANATOLIA [ NOW SELCUK, TURKEY] - DIED C.486 ] GREEK PHILOSOPHER REMEMBERED FOR HIS COSMOLOGY, IN WHICH FIRE FORMS THE BASIC MATERIAL PRINCIPLE OF AN ORDERLY UNIVERSE . LITTLE IS KNOWN ABOUT HIS LIFE, AND THE ONE BOOK HE APPARENTLY WROTE IS LOST.
HOPE IT HELP.....❤❤Which parenting style is thought to produce children who grow up to be emotionally withdrawn,
distant, and lacking in curiosity?
Answer:
Uninvolved (provide little guidance , nuturing and attention) that causes to grow up to be emotionally withdrawn, distant and lacking in curiosity.
Explanation: