Answer:
Their common velocity after collision is 3.6 m/s
Explanation:
Given;
mass of the first meatball, m₁ = 3.0 kg
initial velocity of the first meatball, u₁ = 6.0 m/s
mass of the second meatball, m₂ = 2.0 kg
initial velocity of the first meatball, u₂ = 0 m/s
let their common velocity after collision = v
Apply the principle of conservation of linear momentum for inelastic collision ;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(3 x 6) + (2 x 0) = v( 3 + 2)
18 = 5v
v = 18 / 5
v = 3.6 m/s
Therefore, their common velocity after collision is 3.6 m/s
Radio stations broadcast signals on two different frequency bands. These are called
Answer:
AM(amplitude modulation) and FM(frequency modulation)
Explanation:
A radio frequency band is a small adjacent section of the radio spectrum frequencies, whereby channels are usually used or set aside to be used.
They are usually of two different bands called AM which is known as amplitude modulation and FM which is known as frequency modulation
Name all errors and type it again
EZ POINTS CMON
Answer:
you need to capitalize
Explanation:
When Grandpa Joe comes to visit, he tells us stories about when he was in the army with Colonel Jack S. Anderson.
Is it okay to keep an albino gecko
Answer:
Yes
Explanation:
Please help me! Yes, I know the quality SUCKS I have an old Android lol
Answer:
top to 2\
next to top
then to up one
next to up
Explanation:
Which TWO correctly relate the attraction between the particles of a liquid and the temperature at which the liquid changes state?
A. Strong attractions mean the liquid melts at a higher temperature
B. Strong attractions mean the liquid melts at a lower temperature
C. Strong attractions mean the liquid boils at a higher temperature
D. Strong attractions mean the liquid boils at a lower temperature
Answer:
a &c
Explanation:
>3
Attraction between the molecules of a liquid and the temperature at which the liquid changes state is "Strong attractions mean the liquid boils at a higher temperature". The correct option is C
What is Temperature ?Temperature is a physical quantity which measures hotness and coldness of a body. Temperature measures the degree of vibration of molecule in a body. Temperature is measured in centigrade (°C), Fahrenheit (°F) and Kelvin (K) in which Kelvin (K) is a SI unit of temperature. Absolute scale of temperature means Kelvin scale of temperature.
relation between Kelvin(K) and centigrade (°C),
°C= K - 273.15
from equation, 273.15 K means 0 °C, which is freezing point of water (ice).
when we give temperature to the body, its molecule or atom absorbs thermal energy and vibrate about their mean position. Amplitude of vibration get increases as we go on increasing temperature and for higher temperature force of attraction between molecules gets weaker. Hence for higher temperature, due to weaken the force of attraction between molecule, solid goes into liquid state. and further increase in temperature liquid goes into gaseous state.
Liquid has stronger force of attraction than gas and weaker than solid. Strong force of attraction means high temperature should be given to break molecular bonds. Therefore Strong attractions mean the liquid boils at a higher temperature.
Hence option C is correct.
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A baseball player’s bat applies an average force of 220. newtons to a tennis ball for 0.03 second. The average force exerted on the racket by the tennis ball is
Answer:
98
Explanation:
A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?
Answer:
(a) 5.62 m/s²
(b) 5.46 m/s²
Explanation:
The given values are:
mass,
m = 50 kg
angle
= 35°
(a)
If friction neglected,
⇒ [tex]F_x=mgSin \theta=ma[/tex]
⇒ [tex]a_x=gSin \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}[/tex]
[tex]=5.62 \ m/s^2[/tex]
(b)
If friction present,
⇒ [tex]F_x=mgCos \theta[/tex]
⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]
⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]
[tex]=5.46 \ m/s^2[/tex]
Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg
Answer:
(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) Un satélite de 1,200 kg pesará allí 264 N.
Explanation:
(a) Cada punto del espacio tiene un valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:
[tex]g=G*\frac{m}{r^{2} }[/tex]
donde m será masa, r la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]
En este caso:
m= 6*10²⁴ kgr=42,370 km= 42,370,000 mReemplazando:
[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]
Resolviendo, obtenes:
g= 0.22 [tex]\frac{m}{s^{2} }[/tex]
La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria. Esto se expresa matemáticamente como:
F= m*a
en donde F es fuerza neta , m la masa y a la aceleración.
El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:
P=m*g
En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].
Reemplazando:
P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]
Resolviendo:
P= 264 N
Un satélite de 1,200 kg pesará allí 264 N.
NEED HELP IS THERE SOMEONE CAN HELP ME PLS :)
please help!!! give me a summary on why human population is either good or bad!! thank youu
A bullet is fired straight up from ground level for a distance of 1688.3m at a speed of 182 m/s. How long does it take for the bullet to stop?
What is the mass of a man who accelerates 4 m/s2 under the action of a 300 N net force?
Answer:
F = m*a
therefore m = F / a
m = 100 / 5 = 20 kg?
hope this helped you
Explanation:
The required mass of man, undergoing the acceleration is of 75 kg.
Given data:
The magnitude of acceleration of man is, a = 4 m/s².
The magnitude of action force on the man is, F = 300 N.
Here we can apply the Newton's second law of motion, which says that the applied force causes the acceleration of any object. Where the applied force is equal to the mass of object and the magnitude of acceleration of object.
Therefore,
F = ma
Solving as,
300 = m × 4
m = 300/4
m = 75 kg
Thus, we can conclude that the mass of man, undergoing the acceleration is of 75 kg.
Learn more about the Newton's second law here:
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Can you hear sounds from space or not? Why or Why not?
does anyone know how to do this? the scenario is ""dominique reads that race cars have wide tires because the increased area of contact between the tire and the road results in a stronger force of friction. she hypothesizes that the force of kinetic friction on an object is directly proportional to the area of the object in contact with the surface and wants to test this hypothesis. Dominique and Blake take a long wooden plank and cut the plank into pieces that have different lengths but the same width and height. The students also have access to other equipment commonly available in a school physics lab.
Answer:
Stupid
Explanation:
Because there is never a answer when we are trying to find one
What is mean by speed?
Answer:
Speed is acceleration or a high rate of motion
Answer:
the rate at which something or someone moves or operates or is able to move or operate .
What two things must you know to describe the motion of an object? __________________________________________________________________________
Distance is _________________________________________________________________
What is the displacement of a cyclist, who travels 1 mile north, then 1 mile east, and finally 1 mile south? ___________________________
Define speed ________________________________________________________________
How do speed and velocity differ? ______________________________________________
__________________________________________________________________________
How do velocities combine? In opposite directions? ________________________________ In the same direction? ________________________________________________________
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves upstream at a velocity of 15 km/h relative to the river. What is the velocity of the boat relative to the riverbank? ___________________________________
The rate at which velocity changes is called ________________________
True or false? Acceleration is the result of increases or decreases in speed.
A horse on a carousel that is moving at a constant speed is accelerating because _________________________________________________________________________
True or false? When the final velocity is less than the initial velocity of an object, the acceleration is negative.
The total distance traveled divided by the total time is _______________________
What are some common units for speed (give at least two) _____________ ___________
Define velocity ____________________________________________________________
Define acceleration _________________________________________________________
A quantity that has both magnitude and direction is called a _________________.
WILL MARK BRAINLIEST PLEASE HELP DUE IN 2 MINS
On a distance-time graph speed is a ____________ line and thus a ____________ graph.
On a distance-time graph acceleration is a ___________ line and thus a _______________ graph.
Answer:
velocity is vector Quantity
an athlete running 2.6m/ increases his velocity to 3.7m/s in 2.7s. what is the acceleration of the runner
Question 3 of 10
Which sentence best explains the difference between potential energy and
kinetic energy?
A. Potential energy is related to an object's motion, and kinetic
energy is related to its position.
B. Potential energy is related to an object's position, and kinetic
energy is related to the arrangement of its particles.
C. Potential energy is related to an object's shape, and kinetic energy
is related to its position.
D. Potential energy is related to an object's position, and kinetic
energy is related to its motion.
SUBMIT
Answer
D
Explanation:
Potential energy is related to an object's position, and kinetic
energy is related to its motion.
how can you differentiate between fast motion and slow motion
Use the formula, F = ma, which is the basic equation of motion in classical mechanics. A slow motion will tend to have lower acceleration and vice versa
While sitting in class, your body exerts a force of 600 N on your chair. How much work do you do?
Answer:
1000 N
Explanation:
What tool of dream analysis says that feelings and urges are hidden inside an event? condensation symbolism projection displacement
Answer:
Condensation
Explanation:
Answer:
Condensation! Hope this helps!!!
Explanation:
A 5.0kg concrete block accelerates down a 34 degree slope at 4.2 m/s^2. Find the Coefficient of friction between the block and the slope.
Answer:
The coefficient of friction between the block and the slope is 0.16.
Explanation:
We can find the coefficient of friction between the block and the slope by using Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex]P_{x} -\mu N = ma[/tex]
[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex] (1)
Where:
m: is the mass of the block = 5.0 kg
a: is the acceleration = 4.2 m/s²
θ: is the angle = 34°
μ: is the coefficient of friction =?
g: is the gravity = 9.81 m/s²
By entering the above values into equation (1) we have:
[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]
[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]
Therefore, the coefficient of friction between the block and the slope is 0.16.
I hope it helps you!
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
Answer:
The angular velocity of the propeller is 2.22 rad/s.
Explanation:
The angular velocity (ω) of the propeller is:
[tex] \omega = \frac{\Delta \theta}{\Delta t} [/tex]
Where:
θ: is the angular displacement = 10.6 revolutions
t: is the time = 30 s
[tex] \omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s [/tex]
Therefore, the angular velocity of the propeller is 2.22 rad/s.
I hope it helps you!
Given:
Angular displacement,
[tex]\Theta = 10.6[/tex]Diameter,
3 mTime,
[tex]\Delta t = 30 \ s[/tex]Now,
The angular velocity will be:
→ [tex]\omega = \frac{\Delta \Theta}{\Delta t}[/tex]
By putting the values, we get
[tex]= \frac{10.6\times \frac{2 \pi rad}{1 \ rev} }{30 \ s}[/tex]
[tex]= 2.22 \ rad/s[/tex]
Thus the response above is right.
Learn more about velocity here:
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A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg. The robot pushes on the doll with a force of 1 N. The magnitude of the acceleration of the robot is
Answer:
1.43m/s²Explanation:
According to newtons second law.
F = mass * acceleration
If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg
Force applied = 1N
acceleration = Force/mass
Substitute the values and get acceleration
acceleration = 1/0.7
acceleration = 1.43m/s²
Hence the magnitude of the acceleration of the robot is 1.43m/s²
A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?
Answer:
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m
Explanation:
The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water
The net force, F acting on the body falling through the fluid is given as follows;
F = Weight force, W, from gravity - Drag force, D, from the fluid
F = W - D
Given that F = Mass, m × Acceleration, a, we have;
F = m × a
The acceleration, a = F/m = (W - D)/m
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.
What velocity must a 1240 kg car have in order to have the same
momentum as a 3660 kg truck traveling at a velocity of 12 m/s to the
west?
Answer:
90
Explanation:
cause
What is one physical benefit that can be obtained from participating in field events?
A) strengthen balance
B) better sleep pattern
C) increase capacity for learning
D) all of the above
Answer:
D
Explanation:
It does all three
A driver brings a car to a full stop in 2.0 s. If the car was initially
traveling at 22 m/s, what is the acceleration?
a -17 m/s2
b 27 m/s2
c 7 m/s2
d –11 m/s2
Answer:
[tex]\boxed {\boxed {\sf D. \ -11 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
where Vf is the final velocity, Vi is the initial velocity, and t is the time.
Since the car came to a complete stop, it's final velocity was 0 meters per second.
The initial velocity was 22 meters per second.
The time was 2.0 seconds.
[tex]v_f=0 \ m/s\\v_i=22 \ m/s\\t= 2.0 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-22 \ m/s}{ 2.0 \s }[/tex]
Subtract in the numerator first.
0 m/s- 22 m/s = -22 m/s[tex]a=\frac{-22 \ m/s}{2.0 \ s}[/tex]
Divide.
[tex]a= -11 \ m/s^2[/tex]
The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.
All of the following are good conductors of heat exept
a. Wood
b. Aluminum
c. Copper Silver
(Sorry if its the wrong subject, Im not sure which science this is.)
A giant treasure chest is sitting in the sand, when two rival groups of pirates (the sharks and the squids) come upon it at the same time from opposite directions. Both groups run forward and each pirate grabs a side. On the shark’s side, they have one pirate pulling with 20N, one with 30N, one with 50N, and one with 10N. On the squid’s side, they have one pirate pulling with 10N, one with 25N, one with 30N, and one with 40N.
Which team is able to pull harder?
What is the net force experienced by the chest?
If the chest weighs 100 kg, how fast is it accelerating?
Answer: if you search this up there is a video saying the answer
Explanation: