a 300-acre farm produced 20,000 bushels of corn last year. what is the minimum rate of production, in bushels per acre, that is needed this year, so the farm's two-year production total will be at least 49,100 bushels of corn?

Answers

Answer 1

The minimum production rate of bushels per acre of corn needed this year is 97 for two year's production to reach the goal of 49,100.

How to calculate the minimum production rate?

To calculate the minimum production rate for this year, we must subtract the production rate of the previous year, with what is expected to be obtained this year.

49,100 - 20,000 = 29,100

Then we must divide the minimum that must be obtained by the total area, by the 300 acres that we have, to know how much corresponds to each acre.

29,100 ÷ 300 = 97

According to the above, each acre must produce 97 bushels of corn to reach the goal of 49,100 for both years.

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Related Questions

Express v=
(2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0)

Answers

The expression of v = (2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0) is [tex](2,1,5)=1(1,2,1)+2(1,0,2)+-1(1,1,0)[/tex]

Linear Combinations

To express v= (2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0), it will be written as:

[tex](2,1,5)=x(1,2,1)+y(1,0,2)+z(1,1,0)[/tex]

This will yield the following equations:

x + y + z = 2........(1)

2x + z = 1..........(2)

x + 2y = 5........(3)

The solution to the system of equations above is:

x = 1, y = 2, z = -1

Therefore, the linear combination is:

[tex](2,1,5)=1(1,2,1)+2(1,0,2)+-1(1,1,0)[/tex]

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Polygon ABCD is rotated 90º counterclockwise about the origin to create polygon A′B′C′D′. Match each set of coordinates to the vertices of polygon A′B′C′D′. (-1, 3)
B′
(-2, 2)
C′
(-2, 1)
D′
(-1, 1)

Answers

Answer:Rules for rotating points about the origin

1. The point (a,b) rotated 90° counterclockwise about the origin

becomes (-b,a).

A′ (-1, 3) B′ (-2, 2) C′ (-2, 1) D′ (-1, 1)

A (a,b)-----------------A′ (-b,a)=(-1, 3)----------->A( 3,1)

B (a,b)-----------------B′ (-b,a)=(-2, 2)----------->B( 2,2)

C (a,b)-----------------C′ (-b,a)=(-2, 1)----------->C( 1,2)

D (a,b)-----------------D′ (-b,a)=(-1, 1)----------->D( 1,1)

Step-by-step explanation:

first prime factor....​

Answers

Answer:

The first 10 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29.

3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared the insect endangered and transplanted the insect to protected area. The population P(t) (in thousands) of insects in t months after being transplanted is

a. [3 pts] Determine the number of months until the insect population reaches 40 thousand (round to 2 decimal places).

b. [3 pts] What is the limiting factor on the insect population as time progresses? Explain your answer.

c. [3 pts] Sketch a graph of the function using the window and. Be sure to indicated the scale on the graph, label the axes, at least 2 points on the graph, and any asymptotes.​

Answers

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

[tex]\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end[/tex]

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

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Which expression is equivalent to
xay
8
700
8√√√x
y
8√√y
Mark this and return
128x56
√ 2x75
? Assume x > 0 and y> 0.
Save and Exit

Answers

The equivalent expression of [tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex] is [tex]\frac{8\sqrt y}{x}[/tex]

How to determine the equivalent expression?

The expression is given as:

[tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex]

Divide 128 by 2

[tex]\sqrt{\frac{64x^5y^6}{x^7y^5}}[/tex]

Apply the law of indices to the variables

[tex]\sqrt{\frac{64y^{6-5}}{x^{7-5}}}[/tex]

Evaluate the differences

[tex]\sqrt{\frac{64y}{x^2}}[/tex]

Take the square root of 64

[tex]8\sqrt{\frac{y}{x^2}}[/tex]

Take the square root of x^2

[tex]\frac{8\sqrt y}{x}[/tex]

Hence, the equivalent expression of [tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex] is [tex]\frac{8\sqrt y}{x}[/tex]

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The transformation from parallelogram LMNO to parallelogram L'M'N'O' was carried out as shown in the coordinate plane below.

Answers

The transformation from parallelogram LMNO to parallelogram L'M'N'O' is a reflection across the x-axis

How to determine the transformation?

The complete question is added as an attachment

From the graph, we have the following highlights:

Parallelogram LMNO and parallelogram L'M'N'O' are on either sides of the x-axisThey are equidistant from the x and y axesThey have equal dimensions

This means that parallelogram LMNO is reflected across the x-axis to get parallelogram L'M'N'O'

Hence, the transformation from parallelogram LMNO to parallelogram L'M'N'O' is a reflection across the x-axis

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If the function is:

What is f(-4)?

Answers

Answer:

D.  -11

Step-by-step explanation:

Piecewise functions have multiple pieces of curves/lines where each piece corresponds to its definition over an interval.

Given piecewise function:

[tex]f(x)=\begin{cases}2x-3 & \textsf{if }x \leq -4\\x^2 & \textsf{if }-4 < x < 0\\x+5 & \textsf{if }x \geq 0\end{cases}[/tex]

Therefore, the function has three definitions:

[tex]f(x)=2x-3 \quad \textsf{ when x is equal to or less than -4}[/tex]

[tex]f(x)=x^2 \quad \textsf{ when x is greater than -4 or less than zero}[/tex]

[tex]f(x)=x+5 \quad \textsf{ when x is greater than zero}[/tex]

f(-4) means to substitute x = -4 into the function.

As x = -4 satisfies the interval of the first piece of the function, substitute x = -4 into f(x) = 2x - 3:

[tex]\begin{aligned}\implies f(-4) & =2(-4)-3\\& = -8 -3\\& = -11\end{aligned}[/tex]

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Answer is D. -11

Answer:

Solution Given:

f(-4) depends on the condition x≤-4,

so

f(-4)=2*-4-3=-8-3=-11

do you have a picture of what the graph would look like?

Answers

The attached graph represents the piecewise function.

How to determine the graph of the equation?

The piecewise function is given as:

f(x) = 3x - 5, x ≤ -1

      = -2x + 3, -1 < x < 4

      = 2, x ≥ 4

To plot the graph, we simply plot the equations together with their domains

i.e.

3x - 5 with the domain of x ≤ -1,  -2x + 3 with the domain of -1 < x < 4 and 2 with the domain of x ≥ 4

See attachment for the graph of the function

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Please help ASAP
What of the secants below is a secant?

Answers

The secant in the diagram is [tex]\overline{AD}[/tex]

Segment AD intersect the circle at two points. So it can be a secant.

We have been given that a circle of center O. We have to find the segment that is secant.

What is Secant?

Secant : If a line which intersect the circle at two points.Then the line segment  is called  secant.

If the ray lies onto the considered line segment(overlapping), then it can be said belonging to the considered line segment.

(line segment has 2 fixed ends, whereas a ray has one end only, other end is not fixed)

Segment OB intersect the circle at one point B only. so OB cannot be a Secant.

Segment AD intersect the circle at two points. So it can be a secant.

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A. Reflection around the x-axis:
1. A (5, 1)→ A'
2. B (1, 3) B¹.
3. C (-2, 2)→ C'.
4. D (-5, 4) D'
B. Reflection around the y-axis:
1. A (5, 1)→ A'
2. B (1, 3) B¹.
3. C (-2, 2)→ C'_
4. D (-5, 4) D'

Answers

Part A

1) (5, -1)

2) (1, -3)

3) (-2, -2)

4) (-5, -4)

Part B

1) (-5, 1)

2) (-1, 3)

3) (2, 2)

4) (5, 4)

I can't find the answer for 46.3 divided by 1.5 Help!

Answers

46.3/1.5 = 30.87 or 1.5/46.3 = 0.034
Is that what your looking for??

The solution to the problem when [tex]46.3[/tex] divided by [tex]1.5[/tex]  the result of the division is [tex]30.8666667[/tex] in decimal form.

When a large number is distributed into small numbers of equal parts is called division.

The number [tex]1.5[/tex] is not a factor of [tex]46.3[/tex] ,  on dividing them the remainder is not zero.

Therefore,  first convert [tex]1.5[/tex] it into a whole number by multiplying it  [tex]10[/tex] so it becomes [tex]15[/tex] .

Then convert [tex]46.3[/tex]  it into a whole number by multiplying it by [tex]10[/tex] so it becomes [tex]463[/tex]

Here,  [tex]\dfrac{463 \times 10}{15 \times 10}[/tex] which results in [tex]\dfrac{463}{15}[/tex].

Now, divide [tex]\dfrac{463}{15}[/tex] ,  the result will be [tex]30.8666667[/tex].

The solution to the problem when [tex]46.3[/tex] divided by  [tex]1.5[/tex] the result is [tex]30.8666667[/tex].

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If (x, 68, 85) form a Pythagorean Triple, what is the value of x?

Answers

Answer:

x = 51

Step-by-step explanation:

If (x, 68, 85) form a Pythagorean Triple, what is the value of x?

to solve we again use Pythagoras, x is the smallest number, so 68 is a cathetus and 85 the hypotenuse

x = √(85²- 68²)

x = (7225 - 4624)

x = √2601

x = 51

Answer:

  x = 51

Step-by-step explanation:

The missing value of the Pythagorean triple can be found using the Pythagorean theorem, or it can be found by comparing the values in the triple to known triples.

What are Pythagorean triples?

A Pythagorean triple is a set of integers {a, b, c} that satisfy the equation of the Pythagorean theorem:

  a² +b² = c²

The smallest such triple is {3, 4, 5}. It is also the only triple that is an arithmetic sequence. Other triples of small integers are ...

  {5, 12, 13}, {7, 24, 25}, {8, 15, 17}

There are an infinite number of "primitive" Pythagorean triples, ones that are not multiples of another triple.

What is this triple?

The given values of the triple have the ratio ...

  68/85 = (4·17)/(5·17) = 4/5

Only the values in the {3, 4, 5} triple and its multiples will have this ratio.

The value of x is 3·17 = 51, so the triple is {51, 68, 85}.

  x = 51

__

Additional comments

Any primitive triple will have two odd numbers.

The ratios of numbers in a primitive triple are unique to that triple. That is, the numbers are mutually prime.

For any pair of positive integers m > n, there is a Pythagorean triple {2mn, m²-n², m²+n²}. Such triples will not be primitive if m and n have the same parity.

__

The above triple can be verified using the Pythagorean theorem:

  51² +68² = 2601 +4624 = 7225 = 85²

The graph of f(x) = x3 + x2 – 9x – 9 is shown.


Based on the graph, what are the solutions of x3 + x2 – 9x – 9 = 0?

x = –1, 3
x = –3, –1
x = –3, –1, 3
x = –9, –3, –1, 3

Answers

Answer:

the third option, x = –3, –1, 3

Step-by-step explanation:

a In a concert band, the probability that a member is in the brass section is
0.50. The probability that a member plays trombone, given that he or she is in
the brass section, is 0.24.
What is the probability that a randomly selected band member is in the brass
section and plays trombone?
A. 0.26
B. 0.74
C. 0.12
D. 0.48

Answers

Answer:

C. 0.12

Step-by-step explanation:

Let's use a sample number of 100

Out of 100 members, 50 are in the brass section

Out of those 50, 24% play the trombone. This means that 12 people total play the trombone.

12/100 is .12.. That is the final answer

Let a and b be real numbers where a b 0. Which of the following functions could represent the graph below?

Answers

A function which could represent the graph is: C. f(x) = x⁴(x - a)(x - b)².

How to interpret the graph?

The nature of the intercept on a polynomial graph highlights the nature of its multiplicity. Also, the polynomial graph has no single zero (factor) but bounced off the x-axis at three (3) different locations.

This ultimately implies that the polynomial graph has an even multiplicity at these three (3) points:

x⁴

x - a

(x - b)²

In conclusion, a function which could represent the graph is f(x) = x⁴(x - a)(x - b)².

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A recent tax bill proposed raising the income-tax rate on families earning at least $200,000 a year by 25%, to 25%. What was the previous tax rate ?

Answers

The previous tax rate was 20%

What is tax rate?

Tax rate is the percentage of the earnings tax payers would pay to the government from their earnings as taxes.

It should be borne in mind that the new tax rate is 25% which has increased by 25% compared to the previous tax rate, which is the unknown.

The mathematical relationship between the current and prior tax rates is as shown below:

Current tax rate=previous tax rate*(1+% increase in tax rate)

Current tax rate=25%

previous tax rate=X

% increase in tax rate=25%

25%=X*(1+25%)

25%=X*1.25

X=25%/1.25

X=previous tax rate=20%

Technically speaking, an increase of 25% in 20% is 5%(i.e. 20%*25%=5%), which when added to the original 20% would give a tax rate of 25%.That the shortcut to affirming that the new tax rate of 25% is correct

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"The Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures the motivation, attitude toward school, and study habits of students. Scores range from 0 to 200, with 200 being the highest level of motivation. The mean score for U.S. college students is about 115, and the standard deviation is about 30. A teacher who suspects that older students have better attitudes toward school gives the SSHA to 30 students who are at least 29 years of age, and their mean was 135.2"

Calculate the observed test statistic (Zobt or Tobt) for hypothesis test. Round up to the second decimal place.

Answers

Using the z-distribution, the observed test statistic is given as follows:

z = 3.69.

What are the hypothesis tested?

At the null hypothesis, it is tested if older students have the same mean as the general population, that is:

[tex]H_0: \mu = 115[/tex]

At the alternative hypothesis, it is tested if they have a greater mean, that is:

[tex]H_0: \mu > 115[/tex]

What is the test statistic?

The test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which:

[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested at the null hypothesis.[tex]\sigma[/tex] is the standard deviation of the population.n is the sample size.

For this problem, the parameters are:

[tex]\overline{x} = 135.2, \mu = 115, \sigma = 30, n = 30[/tex]

Hence the test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{135.2 - 115}{\frac{30}{\sqrt{30}}}[/tex]

z = 3.69.

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Which is true regarding the system of equations?

6 x + 2 y = 46. 3 x + y = 23.
The system results in a false statement.
The system results in an intersection at one point.
The system results in parallel lines.
The system results in a true statement because they are the same line.

Answers

Answer:

they are the same line

Step-by-step explanation:

if you divide the first line by 2 you'll get:

2(3x)+2y=2(23)===> 3x+y=23

please help I've been trying to figure it out but I can't​

Answers

answer : 2 1/2

divide y by x

divide  2 1/2 by 1

its 2 1/2

10 divided by 4 is also

2 1/2

17 1/2 divided by 7 is also

2 1/2

Which logarithmic equation is equivalent to 82 = 64?
2 = log Subscript 6 Baseline 64
2 = log Subscript 64 Baseline 8
8 = log Subscript 2 Baseline 64
64 = log Subscript 2 Baseline 8

Answers

Answer: Choice B

[tex]2 = \log_{8}(64)[/tex]

======================================================

Explanation:

The original equation is [tex]8^2 = 64[/tex] with 8 as the base. That is also the base of the log when we get the final answer shown above. Logs are useful to isolate the exponent.

The general rule is that [tex]\text{y} = b^{\text{x}}[/tex] is equivalent to the log form of [tex]\text{x} = \log_{b}(\text{y})[/tex] where b is the base of each.

2 = log Subscript 64 Baseline 8 is the  logarithmic equation which is equivalent to 82 = 64.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

A logarithmic equation is an equation that involves the logarithm of an expression containing a variable.

The logarithmic equation equivalent to 82 = 64 is:

2 = log Subscript 64 Baseline 8

This is because the logarithmic equation relates the base (64) to the result of the exponentiation (8), which in this case is 2.

Hence, 2 = log Subscript 64 Baseline 8 is the  logarithmic equation which is equivalent to 82 = 64.

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just need b1 and b2
brainliest to whoever answers
50 points

Answers

Step-by-step explanation:

b1) Any line parallel to the x-axis is horizontal. If we look at the graph of a horizontal line, we see that for any x-value you give, the y-value will be the same. In this case, the y-value is -1. Hence, the equation for the line is [tex]y=-1[/tex], as y will be -1 no matter the x.

The gradient for a horizontal line is 0, as the "rise" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would have 0 on the top, which makes the whole fraction 0.

b2) Any line parallel to the y-axis is vertical. If we look at the graph of a vertical line, we see that for any y-value, the x-value will be the same. In this case, the x-value is -1. Hence, the equation for the line is [tex]x=-1[/tex], as x will be -1 no matter the y.

The gradient for a vertical line is undefined, as the "run" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would be dividing by 0, which is undefined.

A tape manufacturer reduces the price of its Heavy Duty tape from $40 to $38 a reel and the price of Regular tape from $32 to $31 a reel. A computing center normally spends $1600 a month for tapes and 3/5 of this is for Heavy Duty tapes. How much will they save a month under the new prices?

Answers

Answer:

68

Step-by-step explanation:

Lets first find the quantity of tape the computing center is purchasing/month.

3/5 Of their 1600 dollar spending is on the heavy duty tapes, meaning they are spending 960 dollars/month on heavy duty tape, if we divide that by the original price, 40, it will give us the original quantity of heavy tape they are purchasing, 24/month.

The other 2/5 of their money, 640 dollars, are spent on regular tape, meaning they purchase 20 rolls of regular tape/month.

Given they are purchasing 24 rolls of heavy tape and 20 rolls of regular tape every month, we can simply multiple those by the new prices and sum the results.

24*38=912

20*31=620

912+620=1532

Then to find the money they are saving we subtract the new price from the original price.

1600-1532=68

The final result after substituting a value into an equation is the output.
A. true
B. false

Answers

The question is true
the answer is true also letter “a”

Primer numbers list maths

Answers

Answer:

1 - 100 primes numbers

Step-by-step explanation:

2,3,5,7,11,13,17,19,23,29,31,37,41,47,57,59,61,67,71,79,83,8797

Please answer the questions below.

Answers

The volumes of the right prisms are listed below:

1 / 9 ft³39 / 512 in³7 / 384 cm³1 / 12 cm³3 / 25 m³3 / 8 yd³What is the volume of the prisms?

In this problem we have six cases of right prisms with rectangular bases, the volume of right prisms (V), in cubic length units, is equal to the product of the area of the base (A), in square length units, and the height (h), in length units. The equation of the volume of the right prism is shown below:

V = w · l · h     (1)

Where:

w - Width of the base, in length units.l - Length of the base, in length units.h - Height of the prism, in length units.

Now we proceed to calculate each volume:

Prism 1 (w = 2 / 3 ft, l = 1 / 3 ft, h = 1 / 2 ft)

V = (2 / 3 ft) · (1 / 3 ft) · (1 / 2 ft)

V = 1 / 9 ft³

Prism 2 (w = 1 / 8 in, l = 3 / 4 in, h = 13 / 16 in)

V = (1 / 8 in) · (3 / 4 in) · (13 / 16 in)

V = 39 / 512 in ³

Prism 3 (w = 7 / 8 cm, l = 1 / 4 cm, h = 1 / 12 cm)

V = (7 / 8 cm) · (1 / 4 cm) · (1 / 12 cm)

V = 7 / 384 cm³

Prism 4 (w = 1 / 7 cm, l = 7 / 8 cm, h = 2 / 3 cm)

V = (1 / 7 cm) · (7 / 8 cm) · (2 / 3 cm)

V = 1 / 12 cm³

Prism 5 (w = 9 / 10 m, l = 2 / 3 m, h = 1 / 5 m)

V = (9 / 10 m) · (2 / 3 m) · (1 / 5 m)

V = 3 / 25 m³

Prism 6 (w = 7 / 8 yd, l = 6 / 7 yd, h = 1 / 2 yd)

V = (7 / 8 yd) · (6 / 7 yd) · (1 / 2 yd)

V = 3 / 8 yd³

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Which is the statement is true about f(x)=-2/3|x+4|-6

Answers

Answer: The graph of f(x) is horizontally stretched

find p + q

someone pls help

Answers

Answer:

70

Step-by-step explanation:

45+90=135

180-45=45

q=45

45+65=110

180-110=70

70-45=25

p=25

45+25=70

Answer: 70°

Step-by-step explanation:

We know that the sum of all 3 angles in a triangle is 180°. Hence, we can just set all measures to be equal to 180° and solve for the variables.

Left Triangle

[tex]p+65+90=180\\p+155=180\\p=25[/tex]

Right Triangle

[tex]45+90+q=180\\135+q=180\\q=45[/tex]

Sum

[tex]p+q=25+45=70[/tex]

The sum of p and q is 70°.

Identify the vertices of the feasible region and use them to find the maximum and/or minimum value for the given linear programming constraints.

System of Linear Programming:

z=−3x+5y

x+y≥−2

3x−y≤2

x−y≥−4

Maximum value of z:

Minimum value of z

Answers

The maximum value of the objective function is 26 and the minimum is -10

How to determine the maximum and the minimum values?

The objective function is given as:

z=−3x+5y

The constraints are

x+y≥−2

3x−y≤2

x−y≥−4

Start by plotting the constraints on a graph (see attachment)

From the attached graph, the vertices of the feasible region are

(3, 7), (0, -2), (-3, 1)

Substitute these values in the objective function

So, we have

z= −3 * 3 + 5 * 7 = 26

z= −3 * 0 + 5 * -2 = -10

z= −3 * -3 + 5 * 1 =14

Using the above values, we have:

The maximum value of the objective function is 26 and the minimum is -10

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Graph the following inequality. y ≤ 3x +5 Use the graphing tool to graph the inequality Click to enlarge graph​

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Please see the graph below

WHAT TWO EQAUL NUMBERS ADD TO THE EVEN NUMER 40

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Answer:

20

Step-by-step explanation:

20+20=40

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