A 300 g object attached to a horizontal spring moves in simple harmonic motion with a period of 0.340 s. The total mechanical energy of the spring–object system is 3.00 J.
(a) What is the spring constant (in N/m)?
(b) What is the amplitude (in m) of the motion?
(c) What is the percentage change in amplitude of motion if the total energy of the system is increased to 5.00 J?

Answers

Answer 1

Answer:

Explanation:

angular velocity ω = 2π / T where T is time period of rotation .

= 2 x 3.14 / .34 = 18.47 rad /s

Total mechanical energy = 1/2 m ω²Α² where A is amplitude .

spring constant = k

[tex]\omega=\sqrt{\frac{k}{m} }[/tex]  

m is mass

[tex]\omega^2=\frac{k}{m} }[/tex]

18.47² = k / .3

k = 102.34 N /m

b )

energy = 1/2 m ω²Α²

3 = .5 x 18.47² x A²

A² = .01759

A = .1326

13.26 cm .

c )

If energy becomes 5 J

5 = .5 x 18.47² x A²

A² = .0293

A = .1711

= 17.11 cm

percent increase

= (17.11 - 13.26 )x100 / 13.26

= 29%


Related Questions

asheed and Sofia are riding a merry-go-round that is spinning steadily (uniform circular motion). Sofia is twice as far from the axis as is Rasheed. Sophia's acceleration is _________ that of Rasheed. *

Answers

Answer:

The same as

Explanation:

First of all, they are in a merry go round, which is a circular one. And thus, we would be dealing with circular motions.

The angular velocity of a merry go round, in this instance, is given by

w = Δ/Δt

The formula has nothing whatsoever to do with distance, and as such, both Rasheed and Sofia would have the same angular velocity.

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Remember I said the velocity has nothing to do with distance, well, so does the acceleration as we can see from the formula stated. And therefore, both Rasheed and Sofia would have the same angular acceleration

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Answers

Voltage = (current) x (resistance) (Ohm's law)

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carter found the rock shown in the picture below near a river ​

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Explanation:

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Answers

Answer:

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Explanation:

Given that,

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So, the required speed is 2.51 m/s.

QUESTION 13
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Answer:

A mixture is when two or more substances combine physically together.

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Explanation:

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Explanation:

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Answer:

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Explanation:

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Answer:

There's three rules on determining how many important quantities are in a number: Non-zero digits are always predominant. Any zeros between two significant digits are always major. The final zero or dangling zeros in the decimal segment are really only important.

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Answers

V = at + V0

where v0 is the initial speed, a is the acceleration and t is the time.

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v = 5m/s^2*5s + 25m/s = 50 m/s

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Answer:

Students need a safe environment to take risks and struggle. It’s uncomfortable to struggle, but struggling—falling down and getting back up—is an important facet to learning. Productive struggle is not about being in pain or becoming frustrated.

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1500 POINTS TO WHOEVER ANSWERS THIS FIRST!!!!!!!!!!

1. You drop a bowling ball 15m from the top of the science building. What is its
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2. A cheetah accelerates from 0 to 13m/s in 3 seconds. How far does it travel
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3. Your foolish friend shoots a bullet straight in the air at a muzzle velocity of
380 m/s. How high does the bullet go (neglecting air resistance)?

4. Your foolish friend shoots a bullet straight in the air at a muzzle velocity of
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Answers

Answer: Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

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Answers

Answer:

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Answers

Answer:

4.2s

Explanation:

Given parameters:

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distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

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        Power  = [tex]\frac{work done}{time}[/tex]  

   Time  = [tex]\frac{work done}{power}[/tex]  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

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If a car traveled 50 meters in 2 seconds, what will the velocity be? (Write the answer with a number, on decimal if needed, then a space and the units, for example 5.7 m/s)

Answers

Answer:

The answer is 25 m/s

Explanation:

The velocity of the car can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{50}{2} \\ [/tex]

We have the final answer as

25 m/s

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