A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequency of its oscillations?

Electric forces can be explained using fields that extend through space. We can think of these fields as surrounding any charged object. The force acting on a charged particle at a spot may be calculated by knowing the electric field there. This is further explained below.

The electric force is the term used to describe the repulsion or attraction between two charged things. Newton's rules of motion define how a force interacts with a particular body.

In conclusion, Space-spanning fields may be used to explain electric forces. These fields may be thought of as enclosing any charged object. Knowing the electric field at a certain location will allow one to compute the force acting on a charged particle there.

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Answer:

(Choice B, Checked, Correct)   A field helps predict how electric forces will affect any charge at any location in the field.

Explanation:

CORRECT (SELECTED)

A field helps predict how electric forces will affect any charge at any location in the field.

Modeling the electric force as a field can help us understand electric forces. For instance, we know that any charge in an electric field will experience an electric force. We don’t need to measure the force on each charge to know its direction.

The x component would be Ex = 412 x cos 49° = 270 N/C

Assume there is a small positive charge located at point P. By definition the magnitude of the electric field at point P due to charge Q1 is

E = kQ1/d2

where k is the coulomb constant and d is the straight line distance from Q1 to P.

The distance is the hypotenuse of the triangle formed by Q1, Q2, and P.

d = √0.065^2 + 0.075^2 = 0.099 m at an angle of θ = arctan 7.5/6.5 = 49°.

|E| = 8.99 x 10^9 Nm^2 C^-2 x 0.45 x 10^-9 C/ 0.099^2 m^2 = 412 n/C

The x component would be Ex = 412 x cos 49° = 270 N/C

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Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

                        [tex]F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2[/tex]

                      [tex]M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m[/tex]

               [tex]F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN[/tex]

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

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The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

What is a drag force?

Drag force is a force acting opposite to the relative motion of any object moving concerning a surrounding fluid. This exists between two fluid layers or between a fluid and a solid surface.

Here,

mass of the water, m1 = 3.0 kg

mass of the squid, m2 = 36 kg

initial speed, v2 = 3.5 m/s

(a)

According to the conservation of momentum:

m1*v1 = m2*v2

3 * v1 = 36 * 3.5

v1 = 42 m/s

It is the speed at which the squid rejects the water.

(b)

The maximum range:

R(max) = (v2) ^2 / g

where,

g=9.8 m/s^2 and launch angle is 45°

R(max) = 3.5^2 / 9.8

R(max) =  1.25 m

Hence,

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

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Your question is incomplete, but most probably the full question was:

We’ve seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air—a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.

a. At what speed does the squid eject the water?

b. If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

For the different wires the values given are

For Wire A,  Area=[tex]A_{A}[/tex], Resistivity=[tex]ρ_{A}[/tex], Length= [tex]L_{A}[/tex], Heat=[tex]H_{A}[/tex], Voltage= V, Time= t, Wire B,  Area=[tex]A_{B}[/tex], Resistivity=[tex]ρ_{B}[/tex], Length= [tex]L_{B}[/tex], Heat=[tex]H_{B}[/tex]

So, [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]=[tex]\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }[/tex]/[tex]\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }[/tex]

Therefore [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]= [tex]\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }[/tex]

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

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Answer:

R = ρ L / A       resistance of wire

ρC / ρA = [RC AC/ LC] / [RA AA/ LA} = AC / AA

Since resistance and length are the same for both wires where A is the area of the wire

ρC / ρA = rC^2 / rA^2        where r is the radius of the wire

(ρC / ρA)^1/2 = rC / rA

rC / rA = (1.72 / 2.83)^1/2

rC / rA = .780        radius of copper wire is .780 of aluminum wire

Latitude of the line will be = 1436.033

Departure of the line will be   = 28.152

Given

let line be = a = 1436. 32

azimuthal be = x = 178° 52' 13''

This line must have two components , one is horizontal component which is its latitude and other will be vertical component which is departure . Resolving both the components we get,

latitude = a*cos(178° 52' 13'')

             = 1436. 32 * cos(178° 52' 13'')

             = 1436. 32 * (- 0.9998)                              

latitude = 1436.033

departure  =  a * sin (178° 52' 13'')

                  = 1436. 32  *  0.0197

  departure  = 28.152

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frequency fapproach is heard by a passenger = 302.05 Hz

frequency frecede is heard by a passenger = 228.37433 Hz

Given :

speed of train to the ground = 30.0 m/s

frequency emitted by the train whistle = 262 Hz

speed of sound in air = 344 m/s

To Find :

(A) frequency fapproach (B) frequency frecede

Solution :

The frequency of approach is given by

f' = f v + v(relative)

v - v(air)

= 262x 344 + 18

344 - 30

f' = 302.05 Hz

The frequency of approach is 302.05 Hz

The frequency of recede is given by

f' = f v - v(relative)

v + v(air)

= 262 x 344 - 18

344 + 30

The frequency of recede is 228.37433 Hz

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Two 1-d waves of amplitude a and period t and constant phase 0 are superposed. If wave 1 travels 13. 5 wavelengths farther than wave 2,  the interference is 3/2π.

Interference of light is the phenomena of multiple light waves interfering with each other under certain circumstances, causing the mixed amplitudes of the waves to both boom or lower.one of the exceptional examples of interference is demonstrated by the light contemplated from a film of oil floating on water.

The phenomenon of addition or superposition of mild waves which produces an increase in intensity at some factors and a decrease in depth at a few other points are known as interference of light.

The intensities of light at exceptional factors of the medium are distinctive. At a few factors of the medium, depth is most and at a few different points intensity is maximum ( about 0) This phenomenon is called the interference of mild waves, the interference is known as negative interference.

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Answer:

false

Explanation:

From position 1 to position 2, the kinetic energy is increasing.

The kinetic energy of a pendulum undergoing simple harmonic motion decreases as the displacement of the pendulum increases and increases as the displacement of the pendulum decreases.

From position 1 to position 2, the kinetic energy is increasing while the potential energy is decreasing.

Thus, from position 1 to position 2, the kinetic energy is increasing.

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The angle that the stuck ball makes with the direction of motion and the velocity of both the billiard balls are 65°, 2.6 m/s and 5.5m/s respectively.

To find the answer, we need to know about the linear momentum and angle made in elastic 2 dimensional collision.

           0= m×v×sin25°-m×u×sin65°

            v×sin25°=u×sin65°

            v= 2.1u

                6= 2.1u× cos25° +u×cos65°

                  = 2.33u

Thus, we can conclude that the angle that the stuck ball makes with the direction of motion and the velocity of both the billiard balls are 65°, 2.6 m/s and 5.5m/s respectively.

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The force of friction acting on him is 122 N. The correct answer is option C

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is  [tex]F_{r}[/tex] = μN

[tex]F_{r}[/tex] = 0.15 x 813.4

[tex]F_{r}[/tex] = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

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The threshold frequency for sodium metal is

5.49 x 10^14 s-1

Given:

photon with frequency = 6.66 × 10^14 s−1

kinetic energy = 7.74 × 10−20 j

To Find:

threshold frequency

Solution: The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely. irrespective of the intensity of incident radiation

We know, relation between threshold frequency, kinetic energy and frequency s given by :

K.E = hv - hvo

Here h is plank's constant and vo, is threshold frequency.

Putting all these value in above equation we get:

7.74 x 10^-20 = (6.66 × 10^14-vo) x 6.626 x 10^-34

vo = 5.49 x 10^14 s^-1

Hence, the threshold frequency for sodium metal is 5.49 x 10^14 s-1

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The direction of the force vector and acceleration are identical (downwards) during the motion. The simulation also indicates the same relation.

Newton's 2nd regulation, F = ma is a vector equation. It says that the net force (a vector) acting on a mass m (a range of) causes an acceleration (a vector) of the object within the same path as the net force.

A simple mathematical relationship exists between the mass of an item (m), the net force at the item (f) and its acceleration (a). The acceleration of an object is without delay proportional to the net force and indirectly proportional to the item's mass (a = f/m).

For example, displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.

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amount of work done is 5880 J

Given:

mass of object = 50kg

Final height = 20m

initial height = 8m

To Find:

amount of work done

Solution:

work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

The work done by gravity is given by the formula,

W = mgh

W = 50 x 9.8 x ( 20-8)

= 5880 J

So the work done is 5880 J

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The maximum deceleration of the car is 10.5 m/[tex]s^{2}[/tex] approximately. While the stopping distance is 9.3 m

Stopping force is the force required to stop the object in motion. Stopping force is tantamount to frictional force.

Given that a brother approaches a stop sign at a velocity of 14 m/s [E] as the light turns amber, He applies the brakes to get the maximum stopping force while avoiding skidding. The car has a mass of 1500 kg, and the coefficient of friction between the tires and the road is 1.07. Ignoring your brother's reaction time.

The given parameters are;

The normal reaction N = mg

N = 1500 x 9.8

N = 14700 N

The stopping force = μN = ma

1.07 x 14700 = 1500a

15729 = 1500a

a = 15729/1500

a = 10.486 m/[tex]s^{2}[/tex]

From 3rd equation of motion

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS

where U = 0

[tex]14^{2}[/tex] = 2 x 10.486 x S

196 = 20.972S

S = 196/20.972

S = 9.3 m

Therefore, the maximum deceleration of the car is 10.5 m/[tex]s^{2}[/tex] approximately. While the stopping distance is 9.3 m

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Wave power can be regarded as a reliable source of energy because the ocean currents are always moving.

Wave power is a device that can be used to convert the mechanical energy of the ocean waves into electrical energy based on the principle of conservation of energy.

The major challenges that face the use of wave power in electricity generation is the unreliability of the waves which leads to uncertainty in the quantity of power generated Also, the wave direction and direction of ocean currents all limit the amount of power generated by this method. However, in spite of challenges, it can be regarded as a reliable source of energy because the ocean currents are always moving.

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Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.

Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.

The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.

The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.

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Newton's second law is the hardest to describe as it is about momentum  (F = ma), and a lot of people don't know the concept of momentum.

Newton's first law of motion:- every object moves in a straight line unless acted upon by a force.

Newton's 2nd law of motion:-the acceleration of an object is directly proportional to the net force exerted and inversely proportional to the item's mass. Newton's 2nd law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Newton's 3rd law of motion:- For every action, there's an equal and opposite reaction.

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Answer:6km/sec

Explanation: Acceleration = Change in velocity / Time

Change in velocity = 60km/h minus 30km/hr

Time = 5seconds

Time period is T if increasing the amplitude to 2A

What is Time period?

The length of time during which an activity occurs or a condition remains.

The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.

Formula of Time period, T:

[tex]T = 2\pi \sqrt{\frac{M}{k} }[/tex]

Where,

k is the spring constant

mass of system = M

Amplitude = A

Time period = T  

Here,

The amplitude is doubled = 2A

Since from the formula we can say that, The Time period is not dependent on amplitude.

Increasing the amplitude implies increase in the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period.

So the restoring force cancels the effect of the increase in amplitude.

Hence,

Time period is T if increasing the amplitude to 2A

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The center of gravity is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.

what do you mean by center of balance and center of gravity ?

A location where an object is balanced in relation to applied forces is known as the center of balance (COB).

The average location of an object's weight is known as its center of gravity. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.

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The lion has a kinetic energy of 5000 j, the speed of the lion is  v = 100 / [tex]\sqrt{M1}[/tex]  m/s

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy or Kinetic energy is the energy that an object possesses due to its motion. It is basically the energy of mass in motion. Kinetic energy can never be negative and it is a scalar quantity i.e. it provides only the magnitude and not the direction.

given

kinetic energy = 5000 J

speed = ?

since , mass is not given in the question

Let mass of lion will be = M1

kinetic energy = 1/2 * M1 * [tex]v^{2}[/tex]

             5000 J = 1/2 * M1 *  [tex]v^{2}[/tex]

             [tex]v^{2}[/tex] = [tex]\sqrt{10,000 / M1}[/tex]  m/s

              v = 100 / [tex]\sqrt{M1}[/tex]  m/s

The speed of the lion =  v = 100 / [tex]\sqrt{M1}[/tex]  m/s

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Answer: 1280 J

[tex]KE=\frac{1}{2}mv^{2} \\\\KE= \frac{1}{2} (10 kg)(16 m/s)^2\\=1280 J[/tex]

I have to be honest with you . . . It's not possible to determine the answer with only the information given in the question.

Kinetic energy = (1/2) (mass) (speed squared).

Josie's Kinetic energy as she crosses the finish line is

(1/2) (her mass) (her speed as she crosses the finish line)².

That's (5 kg) x (her speed as she crosses the finish line)² .

But read the question again.

WE DON'T know her speed as she crosses the finish line.

The question only tells us her average speed for the whole race.

We can be confident that her Average Kinetic Energy was

(5 kg) (16 m/s)²  =  1,280 Joules.

But we can't tell what her kinetic energy was as she crossed the finish line, beause we don't know what her speed was at that instant.

The highest elevation reached by the ball in its trajectory is 16.4 m.

To find the answer, we need to know about the maximum height reached in a projectile.

What's the mathematical expression of the maximum height reached in a projectile motion?

What's the maximum height reached by a block that is thrown with an initial velocity of 30.0 m/s at an angle of 25° above the horizontal?

= 16.4m

Thus, we can conclude that the highest elevation reached by the ball in its trajectory is 16.4 m.

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If a Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute then the acceleration of a passenger at his lowest point during the ride is 4.11 [tex]\text{m/s}^{2}[/tex].

Calculation:

Step-1:

It is given that the radius of the Ferris wheel is r=15 m, and the angular speed of the wheel is [tex]\omega[/tex]=5rev/min.

It is required to find the angular acceleration of a passenger at his lowest point during the ride.

The formula required to calculate the angular acceleration is, [tex]a=\omega ^2 r[/tex].

Step-2:

Now substituting the given values into the equation to get the value of the angular acceleration.

[tex]\begin{aligned}a &=\omega^{2} r \\&=(5 \mathrm{rev} / \mathrm{min})^{2}(15 \mathrm{~m}) \\&=\left(5 \mathrm{rev} / \mathrm{min} \times \frac{\left(\frac{2 \pi}{60}\right) \mathrm{rad} / \mathrm{sec}}{1 \mathrm{rev} / \mathrm{min}}\right)^{2}(15 \mathrm{~m}) \\&=(0.2741 \times 15) \mathrm{m} / \mathrm{s}^{2} \\&=4.11 \mathrm{~m} / \mathrm{s}^{2}\end{aligned}[/tex]

The acceleration is towards upwards that means towards the center of the wheel.

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The tension in the string is 36 N.

To find the answer, we need to know about pseudo acceleration.

Tension of the string= mass × effective acceleration

= 5 × 7.2 = 36 N

Thus, we can conclude that the tension in the string is 36 N.

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Effective polymerization of the composite resin is essential to obtain long term clinical success and has a great importance obtaining improved mechanical properties.

The purpose of this study was to measure the effect of the light intensity of LED and QTH curing devices in relation to the light distances, on the hardness (KHN) of two light cure nano-resin composite.

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If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.

We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.

So we can conclude that point B has three times more turns as compared to point A.

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