Answer:
3
Step-by-step explanation:
6(5)-10(3)+3(1)
6*5=30
10*3=30
3*1=3
30-30+3=3
the perimeter of a rectangle is 12cm. If the length is 2 less than 3 times the width, find the length
Answer:
The length of the rectangle would be 4.
Step-by-step explanation:
We can start by naming the width x.
Therefore, the length would 3x-2.
The perimeter of the rectangle would then be:
2(3x-2+x)
We can set up the given equation
2(3x-2+x)=12
Solve for x.
Divide both sides by 2.
3x-2+x=6
Combine like terms.
4x-2=6
Add 2 to both sides.
4x=8
Divide both sides by 4.
x=2
The width would then be 2.
We can plug that into the expression for length.
3x-2
3(2)-2
6-2
4
The length of the rectangle would be 4.
n ΔABC, AB = 10 and BC = 5. Which expression is always true? A. 5 < AC < 10 B. AC = 5 C. 5 < AC < 15 D. AC = 10
Answer:
A. 5 < AC < 10
Step-by-step explanation:
If ∆ABC is a right angled triangle, we use the Pythagoras formula:
c² = a² + b²
Where c = longest side
When given sides AB, AC and BC, the formula becomes:
AB² = AC² + BC²
Where AB = Longest side
In the question,
AB = 10 and BC = 5.
10² = AC² + 5²
AC² = 10² - 5²
AC² = 100 - 25
AC² = 75
AC = √75
AC = 8.6602540378
Therefore, the expression that is always true = A. 5 < AC < 10
Find the equation of the line using the point-slope formula. Passes through the point (−5, 8) and is parallel to the graph y = 4/5x+1
Answer: y=4/5x+12
Step-by-step explanation:
Slope-intercept form: y=ax+b, where a is the slope and b is the y-intercept
When a line is parallel to another line, they will have the same slope. So the slope of the new line is also 4/5.
y=4/5x+b
To find the y-intercept, we simply plug in the point it passes through.
y=4/5x+b
8=4/5(-5)+b
8=-4+b
b=12
y=4/5x+12
Hope this helps!! :)
Please let me know if you have any question
Find an equation of the line passing through the point (−3,−7) that is perpendicular to the line y= −5x+4
Answer:
y = 1/5x - 6.4
Step-by-step explanation:
Perpendicular lines have opposite reciprocal slopes, so the slope will be 1/5
Then, plug the slope and the point into the equation y = mx + b to find b
y = mx + b
-7 = 1/5(-3) + b
-7 = -0.6 + b
-6.4 = b
Then, plug this and the slope into the equation
y = 1/5x - 6.4 will be the equation
411,500 science notation
Answer:
the answer is 4.115 x 10^5
Step-by-step explanation:
hope that helps
Use the Trapezoidal Rule and Simpson's Rule to approximate the value of the definite integral for the value of n. Round the answers to four decimal places and compare the results with the exact value definite integral.
∫9 4 √xdx,n=8.
Answer and Step-by-step explanation: The Trapezoidal and Simpson's Rules are method to approximate a definite integral.
Trapezoidal Rule evaluates the area under the curve (definition of integral) by dividing the total area into trapezoids.
The formula to calculate is given by:
[tex]\int\limits^a_b {f(x)} \, dx = \frac{b-a}{2n}[f(x_{0})+2f(x_{1})+2f(x_{2})+...+2f(x_{n-1})+f(x_{n})][/tex]
The definite integral will be:
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{9-4}{2.8}[2+2.\sqrt{5} +2.\sqrt{6} +2.\sqrt{7}+2.\sqrt{8}+3][/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{5}{16}[25.3193][/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = 7.9122[/tex]
Simpson's Rule divides the area under the curve into an even interval number of subintervals, each with equal width.
The formula to calculate is:
[tex]\int\limits^a_b {f(x)} \, dx = \frac{b-a}{3n}[f(x_{0})+4f(x_{1})+2f(x_{2})+...+2f(x_{n-2})+4f(x_{n-1})+f(x_{n})][/tex]
The definite integral will be:
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{9-4}{3.8}[2+4.\sqrt{5} +2.\sqrt{6} +4.\sqrt{7} +4\sqrt{8} +3][/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{5}{24}[40.7398][/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = 8.4875[/tex]
Calculating the definite integral by using the Fundamental Theorem of Calculus:
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \int\limits^9_4 {x^{\frac{1}{2} }} \, dx[/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{2.\sqrt[]{x^{3}} }{3}[/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{2.\sqrt[]{9^{3}} }{3}-\frac{2.\sqrt[]{4^{3}} }{3}[/tex]
[tex]\int\limits^9_4 {\sqrt{x} } \, dx = 12.6667[/tex]
Comparing results, note that Simpson's Rule is closer to the exact value, i.e., gives better approximation to the exactly value calculated by the fundamental theorem.
The equation a = 640 s gives the relationship between s square miles and a acres. Pam owns 4.5 square miles of farmland. How many acres does she own? a. 2,880 acres b. 288 acres c. 0.7 acres d. 7.03 acres
Answer:
A. 2880 acres
Step-by-step explanation:
Formula: a = 640 s
Given information: s = 4.5
--> a = 640 x 4.5 = 2880 (acres)
Solve M= 2HA + 2HT for H.
Answer:
H = M/(2A +2T)
Step-by-step explanation:
Factor out H and divide by its coefficient.
M = 2HA +2HT
M = H(2A +2T)
M/(2A +2T) = H
H = M/(2A +2T)
Answer I need help !!!!!!!!!!!
Answer:
Pay for the day = $ 123.25
Step-by-step explanation:
From the question given:
Monday morning:
Time in: 8:15
Time out: 12:15 pm
Monday afternoon:
Time in: 13:00
Time out: 17:30
Pay = $ 14.5 /hr
Next, we shall determine the number of hours of work in the morning. This is illustrated below:
Time in: 8:15
Time out: 12:15 pm
Difference in time = 12:15 – 8:15 = 4 hrs
Next, we shall determine the pay for the work done in the morning. This can be obtained as follow:
Pay = $ 14.5 /hr
Pay for work done in the morning
= 4 × 14.5 = $ 58
Next, we shall determine the number of hours of work in the afternoon. This is illustrated below:
Time in: 13:00
Time out: 17:30 pm
Difference in time = 17:30 – 13:00 = 4 hrs 30 minutes
Next, we shall convert 4 hrs 30 minutes to hours. This is illustrated below:
60 minutes = 1 hr
30 minutes = 30/60 = 0.5 hrs.
Therefore,
4 hrs 30 minutes = 4 + 0.5 = 4.5 hrs
Next, we shall determine the pay for the work done in the afternoon. This can be obtained as follow:
Pay = $ 14.5 /hr
Pay for work done in the afternoon
= 4.5 × 14.5 = $ 65.25
Finally, we shall determine the pay for the day as follow:
Pay for work done in the morning
= $ 58
Pay for work done in the afternoon
= $ 65.25
Pay for the day = pay for morning + pay for afternoon
Pay for the day = $ 58 + $ 65.25
Pay for the day = $ 123.25
Therefore, the pay for the day is
$ 123.25
What is mAngleRST in degrees?
Answer:
The measure of angle RST = 120°
Step-by-step explanation:
Answer:
The measure of angle RST = 120°
hope this helps
which equation represents a line that is parallel to y= -4x+3 and passes through the point (-3,2)
Answer:
The answer is
[tex]y = - 4x - 14[/tex]Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the parallel line we must first find the slope of the original line
From the question
y = - 4x + 3
Comparing with the general equation above
Slope / m = - 4
Since the lines are parallel their slope are also the same
Slope of parallel line = (-3 , 2) and slope
- 4 is
[tex]y - 2 = - 4(x + 3) \\ y + 2 = - 4x - 12 \\ y = - 4x - 12 - 2[/tex]We have the final answer as
[tex]y = - 4x - 14[/tex]Hope this helps you
Answer:
y=-4x-14
Step-by-step explanation:
Solve for w 98 = 7w Simplify your answer as much as possible.
Answer:
W = 14
Step-by-step explanation:
7w=98
Divide
w=98/7
Done
w=14
Hope this helps! :)
(pls mark brainliest)
Answer:
w = 14
Step-by-step explanation:
98 = 7w
98/7 = 7w/7
14 = w
Hope this helps.
Find the area of the region that lies inside the first curve and outside the second curve.
r= 10cos( θ)
r= 5
Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = [tex]\dfrac{1}{2}[/tex]
[tex]\theta = -\dfrac{\pi}{3}, \ \ \dfrac{\pi}{3}[/tex]
Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e
[tex]A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \ \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ 5^2 d \theta[/tex]
[tex]A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \ \theta d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ d \theta[/tex]
[tex]A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} \dfrac{cos \ 2 \theta +1}{2} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}[/tex]
[tex]A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} {cos \ 2 \theta +1} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}[/tex]
[tex]A =25 \begin {bmatrix} \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}} \ \ - \dfrac{25}{2} \begin {bmatrix} \dfrac{2 \pi}{3} \end {bmatrix}[/tex]
[tex]A =25 \begin {bmatrix} \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3}) \end {bmatrix} - \dfrac{25 \pi}{3}[/tex]
[tex]A = 25 \begin{bmatrix} \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} + \dfrac{\pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}[/tex]
[tex]A = 25 \begin{bmatrix} \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}[/tex]
[tex]A = \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}[/tex]
The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
What will be the remainder when 6x ^5+ 4x^4 -27x^
3
- 7x² + 27x + 3/2 is divided by (2x^2 - 3)
^2
Answer:
Remainder = (3145/8)x - 408
Step-by-step explanation:
We want to find the remainder when 6x^(5) + 4x⁴ - 27x³ - 7x² + 27x + 3/2 is divided by (2x² - 3)²
Let's expand (2x² - 3)² to give ;
(2x - 3)(2x - 3) = 4x² - 6x - 6x + 9 = 4x² - 12x + 9
So,we can divide now;
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
First of all, we'll divide the term with the highest power inside the long division symbol by the term with the highest power outside the division symbol. This will give;
3/2x³
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
We now subtract the new multiplied term beneath the original one from the original one to get;
3/2x³
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
22x⁴+(27/2)x³+27x +3/2
We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;
(3/2)x³ + (11/2)x²
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
22x⁴+(27/2)x³+27x +3/2
22x⁴-66x³ + (99/2)x²
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
We now subtract the new multiplied term beneath the immediate one from the immediate one to get;
(3/2)x³ + (11/2)x²
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
22x⁴+(27/2)x³-7x²+27x +3/2
22x⁴-66x³ + (99/2)x²
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
(159/2)x³-(113/2)x²+27x+(3/2)
We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;
(3/2)x³ + (11/2)x² + (159/8)x
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
22x⁴+(27/2)x³-7x²+27x +3/2
22x⁴-66x³ + (99/2)x²
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
(159/2)x³-(113/2)x²+27x+(3/2)
(159/2)x³-(477/2)x²+(1431/8)x
We now subtract the new multiplied term beneath the immediate one from the immediate one to get;
(3/2)x³ + (11/2)x² + (159/8)x
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
22x⁴+(27/2)x³-7x²+27x +3/2
22x⁴-66x³ + (99/2)x²
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
(159/2)x³-(113/2)x²+27x+(3/2)
(159/2)x³-(477/2)x²+(1431/8)x
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
182x²-(1215/8)x + (3/2)
We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;
(3/2)x³+(11/2)x²+(159/8)x+(91/2)
______________________
4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2
6x^(5)-18x⁴-(27/2)x³
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
22x⁴+(27/2)x³-7x²+27x +3/2
22x⁴-66x³ + (99/2)x²
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
(159/2)x³-(113/2)x²+27x+(3/2)
(159/2)x³-(477/2)x²+(1431/8)x
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
182x²-(1215/8)x + (3/2)
182x²-545x + 819/2
We now subtract the new multiplied term beneath the immediate one from the immediate one to get;
182x² - (1215/8)x + (3/2) - 182x² + 545x - 819/2 = (3145/8)x - 408
Remainder = (3145/8)x - 408
Round to the nearest cent.
6. $10.407
Answer:
the answer is 10.41. If you have a number 5 or more you round the nearest number on the left up 1 if it's 4 or less it stays the same it doesn't go up or down.
Tony ran 1/2 of a mile for 1/4 of an hour. How many miles per hour did he run? A)1.0 B)2.0 C)3.0 D)4.0 E)5.0
Answer:
2.0
Step-by-step explanation:
Answer:
B. 2.0 miles
Step-by-step explanation:
Tony ran 1/2 of a mile for 1/4 of an hour.
First, to make it easier, change each fraction into decimals:
1/2 = 0.5
1/4 = 0.25
It takes Tony 0.25 hours to run 0.5 miles.
You are solving for 1 hours worth. Multiply 4 to both terms:
0.25 hr x 4 = 1 hr
0.5 miles x 4 = 2.0 miles
B. 2.0 miles is your answer.
~
I really help worth these question.
Answer:
[tex] \frac{7}{3} [/tex]
Step-by-step explanation:
Given that,
p = -6,
q = 6
r = -19
Plug in the above values to evaluate the expression, [tex] \frac{\frac{q}{2} - \frac{r}{3}}{\frac{3p}{6} + \frac{q}{6}} [/tex]
[tex] \frac{\frac{6}{2} - \frac{(-19)}{3}}{\frac{3(-6)}{6} + \frac{6}{6}} [/tex]
[tex] \frac{\frac{3}{1} - \frac{(-19)}{3}}{\frac{-3}{1} + \frac{1}{1}} [/tex]
[tex] \frac{\frac{9 -(-19)}{3}}{3 + 1} [/tex]
[tex] \frac{\frac{28}{3}}{4} [/tex]
[tex] \frac{28}{3}*\frac{1}{4} [/tex]
[tex] \frac{28*1}{3*4} [/tex]
[tex] \frac{7*1}{3*1} [/tex]
[tex] \frac{7}{3} [/tex]
evaluate the following -3 - (-8)
Answer:
The answer to the problem is 5.
Answer:
5Step-by-step explanation:
[tex]-3-\left(-8\right)\\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\=-3+8\\\\\mathrm{Add/Subtract\:the\:numbers:}\:\\-3+8\\=5[/tex]
Solve the problem. A variable x has the possible observations shown below. Possible observations of x: -3 -1 0 1 1 2 4 4 5 Find the z-score corresponding to an observed value of x of 2.
Answer:
The z-score corresponding to an observed value of x of 2 is 0.215.
Step-by-step explanation:
We are given that a variable x has the possible observations shown below;
Possible observations of X: -3, -1, 0, 1, 1, 2, 4, 4, 5.
Firstly, we will find the mean and the standard deviation of X, i.e;
Mean of X, ([tex]\mu[/tex]) = [tex]\frac{\sum X}{n}[/tex]
= [tex]\frac{(-3)+ (-1)+ 0+ 1+ 1+ 2+ 4+ 4+ 5}{9}[/tex]
= [tex]\frac{13}{9}[/tex] = 1.44
Standard deviation of X, ([tex]\sigma[/tex]) = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex]
= [tex]\sqrt{\frac{(-3-1.44)^{2}+(-1-1.44)^{2}+......+(4-1.44)^{2}+(5-1.44)^{2} }{9-1} }[/tex]
= 2.603
Now, the z-score corresponding to an observed value of x of 2 is given by;
z-score = [tex]\frac{X-\mu}{\sigma}[/tex]
= [tex]\frac{2-1.44}{2.603}[/tex] = 0.215.
Now change matrix B to a 3 x 3 matrix and enter
these values for B:
B=
1.2 1.4 3.1
2.2 1.1 5.6
3.7 4.2 6.7
The 3×3 Matrix is [tex]B=\left[\begin{array}{ccc}1.2&1.4&3.1\\2.2&1.1&5.6\\3.7&4.2&6.7\end{array}\right][/tex]
What is Matrix?
In mathematics, a matrix is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns, which is used to represent a mathematical object or a property of such an object
What is 3×3 Matrix?A 3 x 3 matrix is calculated for a matrix having 3 rows and 3 columns
Given,
B=
1.2 1.4 3.1
2.2 1.1 5.6
3.7 4.2 6.7
Then the 3×3 matrix is
[tex]B=\left[\begin{array}{ccc}1.2&1.4&3.1\\2.2&1.1&5.6\\3.7&4.2&6.7\end{array}\right][/tex]
Hence, The 3×3 Matrix is [tex]B=\left[\begin{array}{ccc}1.2&1.4&3.1\\2.2&1.1&5.6\\3.7&4.2&6.7\end{array}\right][/tex]
Learn more about Matrix and 3×3 Matrix here
https://brainly.com/question/12759849
#SPJ2
Answer:
Step-by-step explanation:
c11 =
⇒ 56.1
c12 =
⇒ 12.1
c13 =
⇒ 236
Find the velocity, acceleration, and speed of a particle with position function r(t)=⟨−8tsint,−8tcost,2t2⟩
Answer:
The answer is below
Step-by-step explanation:
Velocity is the rate of change of displacement. Velocity is the ratio of distance to time.
The velocity v(t) = [tex]\frac{d}{dt}r(t)[/tex]
Where r(t) is the position function
Given that:
r(t)=⟨−8tsint,−8tcost,2t²⟩
[tex]v(t)=\frac{d}{dt}r(t)= <-8tcost-8sint,8tsint-8cost,4t>[/tex]
Acceleration is the rate of change of velocity, it is the ratio of velocity to time. Acceleration a(t) is given as:
[tex]a(t)=\frac{d}{dt}v(t)= \frac{d}{dt} <-8tcost-8sint,8tsint-8cost,4t>\\=<8tsint-16cost,8tcost+16cost,4>\\\\a(t)=<8tsint-16cost,8tcost+16cost,4>[/tex]
Speed = |v(t)| = [tex]\sqrt{(-8tcost-8sint)^2+(8tsint-8cost)^2+(4t)^2}\\\\ =\sqrt{64t^2cos^2t+128tcostsint+64sin^2t+64t^2sin^2t-128tsintcost+64cos^2t+16t^2}\\ \\=\sqrt{64t^2cos^2t+64t^2sin^2t+64sin^2t+64cos^2t+16t^2}\\\\=\sqrt{64t^2(cos^2t+sin^2t)+64(sin^2t+cos^2t)+16t^2}\\\\=\sqrt{64t^2+64+16t^2}=\sqrt{80t^2+64}[/tex]
Which x values is the graph below discontinuous
Answer:
-3,-1,1,3,5
Step-by-step explanation:
algebra 2
50 POINTS
HELP
Answer:
{-3, 2}U{2, 5}
Step-by-step explanation:
For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.
Therefore, the first set of negative values is (-3, 2).
Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).
The negative values are {-3, 2}U{2, 5}.
Answer:
{-3, 2}U{2, 5}
Step-by-step explanation:
Robert has available 400 yards of fencing and wishes to enclose a rectangular area. Express the areaAof the rectangle as a function of the widthwof the rectangle. For what value ofwis the arealargest? What is the maximum area?
Answer:
A) A = 200w - w²
B) w = 100 yards
C) Max Area = 10000 sq.yards
Step-by-step explanation:
We are told that Robert has available 400 yards of fencing.
A) we want to find the expression of the area in terms of the width "w".
Since width is "w", and perimeter is 400,if we assume that length is l, then we have;
2(l + w) = 400
Divide both sides by 2 gives;
l + w = 200
l = 200 - w
Thus, Area of rectangle can be written as;
A = w(200 - w)
A = 200w - w²
B) To find the value of w for which the area is largest, we will differentiate the expression for the area and equate to zero.
Thus;
dA/dw = 200 - 2w
Equating to zero;
200 - 2w = 0
2w = 200
w = 200/2
w = 100 yards
C) Maximum area will occur at w = 100.
Thus;
A_max = 200(100) - 100(100)
A_max = 10000 sq.yards
Simplify and Show all of your work please!
Answer:
[tex]\Huge \boxed{\mathrm{9}}[/tex]
Step-by-step explanation:
[tex]\Rightarrow \displaystyle \frac{18 \div 2 * 3}{5-2}[/tex]
Dividing first.
[tex]\Rightarrow \displaystyle \frac{9 * 3}{5-2}[/tex]
Multiplying and subtracting.
[tex]\Rightarrow \displaystyle \frac{27}{3}[/tex]
Division.
[tex]\Rightarrow 9[/tex]
Number of times the individual changed jobs in the last 5 years is what kind of variable? A. This variable is a continuous numerical variable that is interval-scaled. B. This variable is a discrete numerical variable that is interval-scaled. C. This variable is a categorical variable that is ordinal-scaled. D. This variable is a discrete numerical variable that is ratio-scaled. E. This variable is a continuous numerical variable that is ratio-scaled. F. This variable is a categorical variable that is nominal-scaled.
Answer: D. This variable is a discrete numerical variable that is ratio-scaled.
Step-by-step explanation:
A Discrete variables are variables which are countable in a finite amount of time. For example, you can count the amount of money in your bank wallet, but same can’t be said for the money you have deposited in eveyones bank account as this is infinite.
So the number of times an individual changes job in a five years period is a perfect example of a discrete numerical variable that is ratio scaled because it can be counted.
3 πd=12 π
what does d equal?
__________
D = 4
__________
i blelieve this is it.
Answer:
d =4Step-by-step explanation:
[tex]3\pi d = 12 \pi\\\\divide\:both\:sides\:of\:the\:equation\:by\: 3\:\pi\\\frac{3 \pi d}{3\pi} = \frac{12 \pi}{3\pi} \\\\d=4[/tex]
which fraction is less then 7/10
Answer:
Well, there is a lot of answers to that. Check explanation, please!
Step-by-step explanation:
For example, some basic fractions that are less than 1/7 are:
1/8 (Compare their size!)2/18Or 1/154You can also set up a number line, and compare the fractions.
Hopefully, this answer helps! :D
If a wind turbine makes 64 full revolutions every 1 minute, what is its angular speed?
Answer:
this is wind turbine angular speed
Step-by-step explanation:
given data
angular speed ω = 64 rpm
time = 1 min = 60 seconds
solution
we know that angular speed ω is expess as
ω = [tex]\frac{2\pi }{T}[/tex] .........................1
ω = 64 × [tex]\frac{2\pi }{T}[/tex]
ω = 6.70 rad/s
so this is wind turbine angular speed
is 27.14159 rational or irrational
Answer:
It´s rational
Step-by-step explanation:
27,14159 = 2714159/100000
Rational