A 78 N block is supported by a spring whose constant is 12 N/m. Calculate the elongation of the spring under this load.
Group of answer choices

a. 7.2 m

b. 6.5 m

c. 8.2 m

d 1.5 m

Answer:

F = Q E      force acting on charge Q due to field E

A positive electric field is directed from positive to negative.

An electron will be attracted to the positive terminal.

Thus if the electric force is upwards the direction of the field must be directed downwards, or

if F is positive and Q is negative E must also be negative or downwards.

(taking upwards as positive)

Newton's second law is the hardest to describe as it is about momentum  (F = ma), and a lot of people don't know the concept of momentum.

Newton's first law of motion:- every object moves in a straight line unless acted upon by a force.

Newton's 2nd law of motion:-the acceleration of an object is directly proportional to the net force exerted and inversely proportional to the item's mass. Newton's 2nd law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Newton's 3rd law of motion:- For every action, there's an equal and opposite reaction.

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From position 1 to position 2, the kinetic energy is increasing.

The kinetic energy of a pendulum undergoing simple harmonic motion decreases as the displacement of the pendulum increases and increases as the displacement of the pendulum decreases.

From position 1 to position 2, the kinetic energy is increasing while the potential energy is decreasing.

Thus, from position 1 to position 2, the kinetic energy is increasing.

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Answer:6km/sec

Explanation: Acceleration = Change in velocity / Time

Change in velocity = 60km/h minus 30km/hr

Time = 5seconds

Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

                        [tex]F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2[/tex]

                      [tex]M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m[/tex]

               [tex]F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN[/tex]

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

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Answer:

Approximately [tex]13\; {\rm N \cdot m^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].)

Explanation:

Let [tex]F_{\text{s}}[/tex] denote the force that this spring exerts on the object. Let [tex]x[/tex] denote the displacement of this spring from the equilibrium position.

By Hooke's Law, the spring constant [tex]k[/tex] of this spring would ensure that [tex]F_\text{s} = -k\, x[/tex].

Note that the mass of the object attached to this spring is [tex]m = 540\; {\rm g} = 0.540\; {\rm kg}[/tex]. Thus, the weight of this object would be [tex]m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}[/tex].

Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, [tex]F_{\text{s}} = 5.230\; {\rm N}[/tex].

The spring in this question was stretched downward from its equilibrium by:

[tex]\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}[/tex].

(Note that [tex]x[/tex] is negative since this displacement points downwards.)

Rearrange Hooke's Law to find [tex]k[/tex] in terms of [tex]F_{\text{s}}[/tex] and [tex]x[/tex]:

[tex]\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}[/tex].

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

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Time period is T if increasing the amplitude to 2A

What is Time period?

The length of time during which an activity occurs or a condition remains.

The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.

Formula of Time period, T:

[tex]T = 2\pi \sqrt{\frac{M}{k} }[/tex]

Where,

k is the spring constant

mass of system = M

Amplitude = A

Time period = T  

Here,

The amplitude is doubled = 2A

Since from the formula we can say that, The Time period is not dependent on amplitude.

Increasing the amplitude implies increase in the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period.

So the restoring force cancels the effect of the increase in amplitude.

Hence,

Time period is T if increasing the amplitude to 2A

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The high-frequency radio signal is the answer.

Radiofrequency (RF) radios are in the wavelength band of 100 to 10 meters and extend from 3 MHz to 30 MHz. Much of the HF bandwidth is allocated to mobile and fixed voice communications services that require transmission bandwidth of less than 12 kHz. International (Shortwave) Broadcast

Radio Frequency (HF) is an ITU term for the range of high-frequency electromagnetic waves (radio waves) from 3 to 30 MHz (MHz). It is also known as the decameter band or decameter wave because it has wavelengths in the range of 1 to 10 decameter (tens to hundreds of meters).

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The direction of the force vector and acceleration are identical (downwards) during the motion. The simulation also indicates the same relation.

Newton's 2nd regulation, F = ma is a vector equation. It says that the net force (a vector) acting on a mass m (a range of) causes an acceleration (a vector) of the object within the same path as the net force.

A simple mathematical relationship exists between the mass of an item (m), the net force at the item (f) and its acceleration (a). The acceleration of an object is without delay proportional to the net force and indirectly proportional to the item's mass (a = f/m).

For example, displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.

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Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.

Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.

The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.

The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.

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The highest elevation reached by the ball in its trajectory is 16.4 m.

To find the answer, we need to know about the maximum height reached in a projectile.

What's the mathematical expression of the maximum height reached in a projectile motion?

What's the maximum height reached by a block that is thrown with an initial velocity of 30.0 m/s at an angle of 25° above the horizontal?

= 16.4m

Thus, we can conclude that the highest elevation reached by the ball in its trajectory is 16.4 m.

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For the different wires the values given are

For Wire A,  Area=[tex]A_{A}[/tex], Resistivity=[tex]ρ_{A}[/tex], Length= [tex]L_{A}[/tex], Heat=[tex]H_{A}[/tex], Voltage= V, Time= t, Wire B,  Area=[tex]A_{B}[/tex], Resistivity=[tex]ρ_{B}[/tex], Length= [tex]L_{B}[/tex], Heat=[tex]H_{B}[/tex]

So, [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]=[tex]\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }[/tex]/[tex]\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }[/tex]

Therefore [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]= [tex]\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }[/tex]

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

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B. The heat loss by the heat engine is 8,330 J.

The heat loss by the heat engine is calculated as follows;

H = E - W

where;

H = 10,750 J - 2,420 J

H = 8,330 J

Thus, the heat loss by the heat engine is 8,330 J.

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The threshold frequency for sodium metal is

5.49 x 10^14 s-1

Given:

photon with frequency = 6.66 × 10^14 s−1

kinetic energy = 7.74 × 10−20 j

To Find:

threshold frequency

Solution: The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely. irrespective of the intensity of incident radiation

We know, relation between threshold frequency, kinetic energy and frequency s given by :

K.E = hv - hvo

Here h is plank's constant and vo, is threshold frequency.

Putting all these value in above equation we get:

7.74 x 10^-20 = (6.66 × 10^14-vo) x 6.626 x 10^-34

vo = 5.49 x 10^14 s^-1

Hence, the threshold frequency for sodium metal is 5.49 x 10^14 s-1

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D. The maximum electromotive force induced in the coil is determined as 3,200 V.

emf(max) = NAB/t

where;

Substitute the given parameters and solve for emf

emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)

emf(max) = 3,187.1 V

emf(max) ≈ 3,200 V

Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.

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The lion has a kinetic energy of 5000 j, the speed of the lion is  v = 100 / [tex]\sqrt{M1}[/tex]  m/s

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy or Kinetic energy is the energy that an object possesses due to its motion. It is basically the energy of mass in motion. Kinetic energy can never be negative and it is a scalar quantity i.e. it provides only the magnitude and not the direction.

given

kinetic energy = 5000 J

speed = ?

since , mass is not given in the question

Let mass of lion will be = M1

kinetic energy = 1/2 * M1 * [tex]v^{2}[/tex]

             5000 J = 1/2 * M1 *  [tex]v^{2}[/tex]

             [tex]v^{2}[/tex] = [tex]\sqrt{10,000 / M1}[/tex]  m/s

              v = 100 / [tex]\sqrt{M1}[/tex]  m/s

The speed of the lion =  v = 100 / [tex]\sqrt{M1}[/tex]  m/s

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If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.

We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.

So we can conclude that point B has three times more turns as compared to point A.

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Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.

The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

q = m x C x AT

As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.

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frequency fapproach is heard by a passenger = 302.05 Hz

frequency frecede is heard by a passenger = 228.37433 Hz

Given :

speed of train to the ground = 30.0 m/s

frequency emitted by the train whistle = 262 Hz

speed of sound in air = 344 m/s

To Find :

(A) frequency fapproach (B) frequency frecede

Solution :

The frequency of approach is given by

f' = f v + v(relative)

v - v(air)

= 262x 344 + 18

344 - 30

f' = 302.05 Hz

The frequency of approach is 302.05 Hz

The frequency of recede is given by

f' = f v - v(relative)

v + v(air)

= 262 x 344 - 18

344 + 30

The frequency of recede is 228.37433 Hz

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The force of friction acting on him is 122 N. The correct answer is option C

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is  [tex]F_{r}[/tex] = μN

[tex]F_{r}[/tex] = 0.15 x 813.4

[tex]F_{r}[/tex] = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

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The potential energy of the monkey at the given position is 600.9 J.

Potential energy is the energy stored in a body that depends upon the relative position of various parts of the body.

It increases with increase in the height of the object above the ground level.

The potential energy of the monkey is calculated as follows;

P.E = mgh

P.E = mg (L sin43)

where;

Substitute the given parameters and solve potential energy of the monkey

P.E = (16.9)(9.8)( 5.32 x sin 43)

P.E = 600.9 J

Thus, the potential energy of the monkey at the given position is 600.9 J.

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The center of gravity is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.

what do you mean by center of balance and center of gravity ?

A location where an object is balanced in relation to applied forces is known as the center of balance (COB).

The average location of an object's weight is known as its center of gravity. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.

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Answer:

a = v^2 / R        where a is the centripetal acceleration and R the radius

v = 2 π R N / t        where (N / t) is the revolutions / sec giving distance / time

a = 4 g         horizontal acceleration

4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2

(N / t)^2 = g / (π^2 * R)

N / t = 1 /  π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2  = .352 / sec

Answer:

R = ρ L / A       resistance of wire

ρC / ρA = [RC AC/ LC] / [RA AA/ LA} = AC / AA

Since resistance and length are the same for both wires where A is the area of the wire

ρC / ρA = rC^2 / rA^2        where r is the radius of the wire

(ρC / ρA)^1/2 = rC / rA

rC / rA = (1.72 / 2.83)^1/2

rC / rA = .780        radius of copper wire is .780 of aluminum wire

Answer: 1280 J

[tex]KE=\frac{1}{2}mv^{2} \\\\KE= \frac{1}{2} (10 kg)(16 m/s)^2\\=1280 J[/tex]

I have to be honest with you . . . It's not possible to determine the answer with only the information given in the question.

Kinetic energy = (1/2) (mass) (speed squared).

Josie's Kinetic energy as she crosses the finish line is

(1/2) (her mass) (her speed as she crosses the finish line)².

That's (5 kg) x (her speed as she crosses the finish line)² .

But read the question again.

WE DON'T know her speed as she crosses the finish line.

The question only tells us her average speed for the whole race.

We can be confident that her Average Kinetic Energy was

(5 kg) (16 m/s)²  =  1,280 Joules.

But we can't tell what her kinetic energy was as she crossed the finish line, beause we don't know what her speed was at that instant.

yes, it causes an energy crisis. Burning Fossil Fuels

When we burn oil, coal, and gas, we don't just meet our energy needs, we move the current global warming crisis as well.

Fossil fuels produce large amounts of carbon dioxide when burned. Carbon emissions trap heat in the air and lead to climate change.

Most energy crises have been caused by localized shortages, wars and market manipulation. Some have argued that government efforts like tax hikes, nationalization of energy companies, and rule of the energy sector, shift supply and demand of energy away from its economic stability.

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The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

What is a drag force?

Drag force is a force acting opposite to the relative motion of any object moving concerning a surrounding fluid. This exists between two fluid layers or between a fluid and a solid surface.

Here,

mass of the water, m1 = 3.0 kg

mass of the squid, m2 = 36 kg

initial speed, v2 = 3.5 m/s

(a)

According to the conservation of momentum:

m1*v1 = m2*v2

3 * v1 = 36 * 3.5

v1 = 42 m/s

It is the speed at which the squid rejects the water.

(b)

The maximum range:

R(max) = (v2) ^2 / g

where,

g=9.8 m/s^2 and launch angle is 45°

R(max) = 3.5^2 / 9.8

R(max) =  1.25 m

Hence,

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

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Your question is incomplete, but most probably the full question was:

We’ve seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air—a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.

a. At what speed does the squid eject the water?

b. If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

The tension in the string is 36 N.

To find the answer, we need to know about pseudo acceleration.

Tension of the string= mass × effective acceleration

= 5 × 7.2 = 36 N

Thus, we can conclude that the tension in the string is 36 N.

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If a Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute then the acceleration of a passenger at his lowest point during the ride is 4.11 [tex]\text{m/s}^{2}[/tex].

Calculation:

Step-1:

It is given that the radius of the Ferris wheel is r=15 m, and the angular speed of the wheel is [tex]\omega[/tex]=5rev/min.

It is required to find the angular acceleration of a passenger at his lowest point during the ride.

The formula required to calculate the angular acceleration is, [tex]a=\omega ^2 r[/tex].

Step-2:

Now substituting the given values into the equation to get the value of the angular acceleration.

[tex]\begin{aligned}a &=\omega^{2} r \\&=(5 \mathrm{rev} / \mathrm{min})^{2}(15 \mathrm{~m}) \\&=\left(5 \mathrm{rev} / \mathrm{min} \times \frac{\left(\frac{2 \pi}{60}\right) \mathrm{rad} / \mathrm{sec}}{1 \mathrm{rev} / \mathrm{min}}\right)^{2}(15 \mathrm{~m}) \\&=(0.2741 \times 15) \mathrm{m} / \mathrm{s}^{2} \\&=4.11 \mathrm{~m} / \mathrm{s}^{2}\end{aligned}[/tex]

The acceleration is towards upwards that means towards the center of the wheel.

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