a block of mass m is attached to a spring and placed on an inclined plane. the spring has a spring constant k, and there is negligible friction between the block and inclined plane.the block is released from rest at the position shown in the figure above with the spring initially unstretched. what distance d does the block slide down the plane before coming momentarily to rest?

Answers

Answer 1

The distance travelled by the block of mass m will be l₀ + x or d which can be calculated through implementing the Conservation of energy from Work energy theorem

For  l₀ + x, (from figure)

sinᶿ = h / (l₀+x) ----- equation 1

We know from conservation of energy,

Ka + Ua = Kc + Uc

Here

Ka = kinetic energy at point A

Ua = potential energy at point A

Kc = kinetic energy at point C

Uc = potential energy at point C

Since the block is at rest Ka = 0 & block comes to rest after moving Kc = 0 as well

Therefore Ua = Uc

Ua = m.g.h

Uc = ½ kx²

m.g.h = ½ kx²

h = kx²/2mg ---- equation 2

Substitute the obtained value of h i.e. equation 2 in equation 1 for calculation of distance travelled by the block on an inclined plane.

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A Block Of Mass M Is Attached To A Spring And Placed On An Inclined Plane. The Spring Has A Spring Constant
Answer 2

Answer:

d = (2mg sinθ) / k

Explanation:

We can use the conservation of energy.

At the point when the block comes to rest, all of its initial potential energy mgh is converted into the potential energy stored in the spring (1/2)kx², where x is the amount by which the spring is compressed.

Using trigonometry, we can see that the height h of the incline is equal to

d sinθ

where d is the distance traveled by the block down the incline.

We know this because d represents an incline and to find the y value of an incline we use sinθ

Therefore, we can write:

mgh = (1/2)kx²

Substituting h = d sinθ and solving for d, we get:

mgd sinθ = (1/2)kd²

d = (2mgsinθ)/k

Therefore, the correct answer for the distance that the block slides down the incline before coming momentarily to rest is (2mg sinθ)/k.

I hope this helped! :)


Related Questions

A 30.0 kg object is falling in air and experiences a force due to air resistance of 50.0 N. What is the net force acting on the object?

Answers

Answer:

250N

Explanation:

weight of object - air resistance= net force

weight=mg

=30×10

=300N

air resistance =50

300-50=250

Which of the following describes a way that neighborhoods help children build new relationships?
OA neighborhood holds a winter festival with activities for children and families.
O Families of the neighborhood walk around the block on differing weeknights.
O Lawn crews ensure that the neighborhood is properly maintained each week.
O Members of the community form a Neighborhood Watch team.

Answers

The neighborhood can help children build new relationships by holding a winter festival with activities for children and families.

In today's world, where everyone is quite busy in their own world, children have academic pressure and many more.

They tend to detach themselves from people, and hence many relationships ruin.

Building relationship helps the children grow and makes them more sociable. It boots their intelligence and makes them aware of the importance of having a relationship and building bonds with people.

The neighborhood holds a winter festival with activities for children and families is a great way to build new relationships.

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Which statements explain current theories about dark energy and dark matter? Check all that apply. Space that appears empty actually contains dark energy and dark matter. Dark matter does not emit electromagnetic radiation. Scientists believe dark energy will cause the universe to collapse inward to a single point. Scientists theorize that dark energy is causing the expansion of the universe to accelerate. Dark matter includes all of the dust, ice, and debris that scientists observe in black holes.

Answers

The correct statements which describes current theories about dark energy and dark matter among the choices above are given below:

Space that appears empty actually contains dark energy and dark matter.Dark matter does not emit electromagnetic radiation.Scientists theorize that dark energy is causing the expansion of the universe to accelerate.

The answers are options a, b, and d.

What meant by dark energy ?

Dark energy refers to that energy which acts against gravity, thereby resulting in the expansion of the universe. It's major constituent is current characterized with vacuum fluctuation. It is on this premise that dark energy was theorized to be causing the expansion of the universe to accelerate and itself including dark matter is filled in empty space.

So therefore, from the simple note above, it can be deduced that this type of energy does not produce electromagnetic radiation.

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Answer:

a b d

Explanation:

Which statements explain current theories about dark energy and dark matter? Check all that apply.

Space that appears empty actually contains dark energy and dark matter.

Dark matter does not emit electromagnetic radiation.

Scientists believe dark energy will cause the universe to collapse inward to a single point.

Scientists theorize that dark energy is causing the expansion of the universe to accelerate.

Dark matter includes all of the dust, ice, and debris that scientists observe in black holes.


a. When rock on Earth's surface is broken into
smaller pieces, forming loose material

Answers

When rock on Earth's surface is broken into smaller pieces, forming loose material  is called Weathering.

Physical weathering and chemical weathering are the two basic types of weathering. On this page, we discuss mechanical weathering (and more).

Rocks naturally fracture at a number of different levels. The borders between mineral grains can be a source of weakness in the rock. Sedimentary rocks are frequently stratified, and the layers are occasionally not tightly bonded together. As larger, more massive rocks are exposed by erosion, joints (cracks with no relative motion across them, merely spreading) may form in the rocks. These rock fissures become wider due to physical deterioration. Of course, biological weathering refers to weathering caused by living creatures.

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How can I figure out the area of something in physics?

Answers

Area in physics can be found by division of the area into simple figures such as triangles, rectangles and trapezoids and offsets from a straight line.

How to find area in physics?

Area is a measure of how much space is there inside a shape and calculating the area of a shape or surface can be useful in everyday life.

The amount of surface a two-dimensional shape can cover which is measured in square units is called area and the SI unit of area is the square meter.

Area = length x breadth and  Area = π × radius × radius - formulas can be used for finding area of different quadrilaterals.

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1 5kg cat is lifted 2 m into the air.how much gpe does it gain?

Answers

Answer:

Potential Energy= mgh = (5)(9.8)(2)= 98.

derive from one of the laws of motion the relation between the momentum produced in a body and the force applied on the body​

Answers

Answer:

The fact that change in moment is equal to force times duration can be derived from Newton's Second Law of Motion (assuming that the net force on the object is constant.)

Explanation:

Let [tex]m[/tex] denote the mass of an object. Let [tex]\Delta v[/tex] denote the change in the velocity of this object. The change in momentum of this object will be [tex]\Delta p = m\, \Delta v[/tex].

Let [tex]F_{\text{net}}[/tex] denote the net force (resultant force) on the object. Let [tex]a[/tex] denote the acceleration of this object. By the law of motion, [tex]F_{\text{net}} = m\, a[/tex], or equivalently, [tex]a = (F_{\text{net}} / m)[/tex].

Assume that this net force is constant and is exerted on this object over a period of [tex]\Delta t[/tex]. With an acceleration of [tex]a = (F_{\text{net}} / m)[/tex], the velocity of this object would have changed by:

[tex]\begin{aligned}\Delta v &= a\, \Delta t \\ &= \left(\frac{F_{\text{net}}}{m}\right)\, (\Delta t) \\ &= \frac{F_{\text{net}}\, \Delta t}{m}\end{aligned}[/tex].

Multiply both sides of this equation by the mass [tex]m[/tex] of the object to obtain:

[tex]m\, \Delta v = F_{\text{net}}\, \Delta t[/tex].

Note that [tex]m\, \Delta v[/tex] is equal to the change in momentum ([tex]\Delta p = m\, \Delta v[/tex].) Therefore, if the net force [tex]F_{\text{net}}[/tex] on the object is constant, the change in the momentum [tex]\Delta p[/tex] over time period [tex]\Delta t[/tex] will be equal to [tex]F_{\text{net}}\, \Delta t[/tex] (net impulse on the object.)

A 1.5 kg ball is dropped so that is is traveling at a velocity of -27 m/s when it hits the ground. If the ball rebounds upward with the same speed, what is the change in momentum of the ball?

Answers

Answer:

The change in momentum of the ball = 81 kg·m/s

Explanation:

Given:

m = 1.5 kg

V₁ = - 27 m/s

V₂ = + 27 m/s

____________

Δp - ?

The change in momentum of the ball:

Δp = m·ΔV

Δp = m· (V₂ - V₁) = 1.5·(27 - (-27)) = 1.5·(27 + 27) = 81 kg·m/s

Two students are pushing a broken-down car. One student is pushing with a force of 200 N. If there is 350 N of frictional force acting against them, how hard must the second student push to cause the car to accelerate?

Answers

The second student must push with a force greater than 150 N to cause the car to accelerate.

What is the net force on the car?

The net force on the car is the sum of all the forces acting on the car. The direction of the net force on the car will determine the direction of motion of the car.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on the car is calculated as follows;

F(net) = F - Ff

ma = F - Ff

where;

a is the acceleration of the carm is the mass of the carF is the applied force on the carFf is the force of friction resisting the motion of the car

For the car to move, sum of the applied forces must be greater than the force of friction.

200 + F > 350

F > 350 - 200

F > 150

Thus, the second student must push with a force greater than 150 N before the car can accelerate.

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how much work is done when a 125 g tomato is lifted 13.6 m ? express your answer with the appropriate units.

Answers

Work done when a 125 g tomato is lifted 13.6 m is calculated as 16.66 J .

What do you understand by work done?

The product of the component of force in the direction of the displacement and the magnitude is called work done by force and energy is defined as the ability to do work.

Work can be calculated by multiplying force with distance in the direction of force , and can be written as :

W = F × d

Given m= 125g = 0.125 kg

h= 13.6 m

W= P E

= m *g *h

= 0.125 * 9.8 * 13.6

Work done = 16.66 J

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a boy drops a rock off of a bridge and times its fall into a river. if it takes the rock 10.0 seconds to fall, what is the velocity of the rock when it hits the river?

Answers

The rock's impact velocity with the river is - 98.1 m/s. At the time of impact, the  rock was traveling at a speed of 42.14 m/s.

Find out how fast a rock is moving ?

G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity).

In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.

The rock was traveling at 42.14 m/s when it impacted the ocean.

Then V = -9.81 * 10 = -98.1.

There for,

The rock's impact velocity with the river is -98.1m/s .

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the triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 1495 n with an effective perpendicular lever arm of 2.10 cm , producing an angular acceleration of the forearm of 125.0 rad / s2 . what is the moment of inertia of the boxer's forearm?

Answers

The moment of inertia of the boxer's forearm that has an angular acceleration of 125.0 rad / s² is 0.25 kg m²

τ = F * ⊥d

τ = Torque

F = Force

⊥d = Perpendicular distance

F = 1495 N

⊥d = 2.1 cm = 0.021 m

τ = 1495 * 0.021

τ = 31.395 N m

τ = I α

I = Moment of inertia

α = Angular acceleration

α = 125 rad / s²

I = τ / α

I = 31.395 / 125

I = 0.25 kg m²

Therefore, the moment of inertia of the boxer's forearm is 0.25 kg m²

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xii. a fan rotating with an initial angular velocity of 1200 rev/min is switched off. in 2 seconds, the angular velocity decreases to 300 rev/min. assuming the angular acceleration is constant, how many revolutions does the blade undergo during this time?

Answers

The blade goes through 25 evolutions throughout this period.

What does angular velocity mean?

Angular velocity is the speed at which an object rotates or revolves around an axis or alters the angle between two bodies. The angle between a line on one body and a line on the other in the illustration serves as a representation of this displacement.

Formula using,

Ф = (ω+ω')t/2

Where Ф = amount of revolution the blade undergo,

Given: ω = 1200 rev/min,

ω' = 300 rev/min,

t = 2 seconds = (2/60) min = 1/30 min

Substitute into equation 1

Ф = (1200+300)(1/30)/2

Ф = 1500/(30×2)

Ф = 1500/60

Ф = 25revolutions.

The blade goes through 25 evolutions throughout this period.

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a string is under a tension of 760.0 n. a 1.7 m length of the string has a mass of 4.8 grams. what is the speed of a transverse wave of wavelength 0.50 m in this string? what is the frequency of the wave?

Answers

The number of waves that pass by each second is the frequency of a wave, which is expressed in Hertz (Hz). For instance, a sound wave may have a frequency of 450 Hz.

Explain about the frequency of wave?

The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second. When two waves of equal amplitude and frequency are compared, the higher frequency wave has greater energy.

Divide the wave's velocity by its wavelength to determine its frequency. The unit for frequency is Hertz (Hz), so use that while writing your response. The frequency will be the inverse of the time, or 1 divided by T, if you need to determine it from the amount of time it takes for a wave cycle to complete, or T.

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PLEASE ASAP HELP, ILL GIVE WHATEVER POINTS I CAN BUT PLEASE HELP ASAP ASAP

Paul was kicking around a soccer ball with his friend Leo the Lion. Paul decided to kick the ball off a 9.63 m tall cliff and lands on the ocean, 8.85 m away from the edge of the cliff.

Th ball is in the air for S._______m/s
The horizontal velocity of the ball as it rolls off the table is_________m/s
The vertical velocity of the ball right before it hits the ground is________m/s
The horizontal velocity of the ball right before it hits the ground is___________m/s
The initial vertical velocity as soon as the ball comes of the cliff is________m/s​

Answers

(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s​.

What is the time of motion of the ball?

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

h is the height of the cliffg is acceleration due to gravity

t =  √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

d is the horizontal distance travelled by the ball = 8.85 m

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

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an automobile of mass 1500kg moving at 25.0m/s collides with a truck of mass 4500kg at rest. this time, the car and the truck bounce off each other completely elastically. what is the final velocity of the car (in m/s) after the collision? call the initial direction of the automobile positive.

Answers

the final velocity of the car (in m/s) after the collision is 6.25 m/s

12.5 m/s is moving in the initial direction of the car

1. A car of mass 1500 kg moving at a speed of 25.0 m/s collides with a truck of mass 4500 kg at rest. the bumpers of both vehicles lock on impact.

A. Compare the force exerted by the car on the truck with the force exerted by the truck on the car during the collision. Is one force greater than the other, or are they equal in magnitude?

the force exerted by the car on the truck and the force exerted by the truck in the collision.

creates a pair of actions and reactions

are equal in magnitude and opposite in direction according to Newton's third law

b. What is the final speed of the car and the truck just after the collision? show your calculations.

v=m1u1+m2u2/m1+m2=1500*25+0/1500+4500=6.25 m/s

2. the same collision as in the above question occurs, but this time the car and truck bounce off each other completely elastically.

C. Compare the force exerted by the car on the truck with the force exerted by the truck on the car in the collision. is one force greater than the other or are they equal?

the force exerted by the car on the truck and the force exerted by the truck in the collision.

creates a pair of actions and reactions

are equal in magnitude and opposite in direction according to Newton's third law

d. what is the final speed of the car and truck just after the collision?

view the calculation

v1=[m1-m2/m1+m2]u1+[2m2/m1+m2]u2=[1500-4500/6000]*25+[9000/6000]*0=-12.5 m/s

a negative sign means the car is moving backwards at 12.5 m/s

v2=[m2-m1/m1+m2]u2+[2m1/m1+m2]u1=[4500-1500/6000]*0+[3000/6000]25=12.5 m/s

moves in the original direction of the car

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a(n) 54.8 kg astronaut becomes separated from the shuttle, while on a space walk. she finds herself 45.3 m away from the shuttle and moving with zero speed relative to the shuttle. she has a(n) 0.767 kg camera in her hand and decides to get back to the shuttle by throwing the camera at a speed of 12 m/s in the direction away from the shuttle. how long will it take for her to reach the shuttle? answer in minutes.

Answers

The overall momentum of a system is constant.

Hence, The time taken to get to the shuttle is  4.49  min.

What is the conservation of momentum ?The conservation of linear momentum is a general law of physics which states that the overall momentum of a system is constant and that the quantity called momentum which characterizes motion never changes in an isolated collection of objects.

according to  the linear momentum conservation theorem, we have:

M1 V1 + M2 V2 =M1 V[tex]_0[/tex]1 + M2 V[tex]_0[/tex]2.

the initial velocity is Zero

then,

M1 V1 = - M2 V2

V1 = ( - M2 V2)/ M1

V1 = -  [tex]\frac{0.767 *12}{54.8}[/tex] = - 0.168 m/s

That is 0.168 m/s in the opposite direction of the camera.

the time taken to get to the shuttle is given by:

t = d/v

t = [tex]\frac{45.3}{0.168}[/tex] = 269.64 s

[tex]t_{min} =\frac{269.64}{60}[/tex] = 4.49 min.

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what is the heaviest the book he can hold vertically before it slips out of his fingers? the coefficient of static friction between his fingers and the book cover is 0.88

Answers

Mass of the heaviest book is 0.733 kg.

Heaviest book has weight

= (6 + 6) * 0.6 N

= 7.2 N

If m = mass of the heaviest book in kg

m = 7.2/9.81 kg

   = 0.733 kg.

Children often bring a well-established "life-view" of friction with them because of their experiences with slippery surfaces like frozen ponds (low friction) and "gripping" surfaces like deep pile carpets (high friction) and the effects they have on movement. This way of existence needs to be expanded and understood in the perspective of science.

The force that modifies movement as a result of surface/surface interaction is known scientifically as friction (all changes of movement require the action of a force). When using diagrams to portray forces in action, the direction of the frictional force should be depicted as being opposed to that of the movement.

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What kind of electronic transitions are responsible for colored light being given off?.

Answers

Answer:

The answer is photons.

A weightlifter lifts a 32 kg barbell a distance of 0.1 m in 0.83 s. How much power is demonstrated by the lift?

Answers

To find power, you have to find work first.

Given :
F = 32kg —> 313.6 N
d = 0.1m
Work = Fd
= (313.6)(0.1)
= 31.36

P=W/t
=(31.36)/(0.83)
≈ 38 W

Answer:

Explanation:

Work:

A = m·g·h = 32·9.8·0.1 = 31.36 L

Power:

N = A / t = 31.36 / 0.83 ≈ 38 W

four amperes of current exist in the primary coil of a transformer. the voltage across the primary coil is 120 v. what is the power output of the secondary coil?

Answers

480 W  is the power output of the secondary coil.

primary  coil current = ip = 4A

primary coil  voltage = vp = 120v

power out put of secondary coil

p = vi

   = 120v * 4A = 480W.

What is power?

Power is the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

The rate at which work is performed on an object is referred to as its power. Power is a temporal concept. It has to do with how quickly a task gets completed. The power equation is described below.

Power = Time + Work

P = W / t

The standard metric unit for power is a Joule/second, which is defined as the product of the standard metric units of work (the Joule) and time (the second).

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water flows from the pipe shown in the figure with a speed of 8.0 m/s what is the water pressure as it exits into the air? what is the height h of the standing column of water?

Answers

The atmosphere supports a column of mercury with a height of 760 mm. Supports a 32 m high water column. And, of course, that's why we fill the barometer with mercury instead of water or alcohol.

The vapor pressure of mercury is also minimal. Therefore, the pressure at the exit point is equal to atmospheric pressure. This pressure is therefore equal to 10 to the power of 5 times 1.1. The base area of ​​this water cube is 12" x 12" = 144 square inches. So, the pressure at the bottom of the water cube is 62.4 pounds / 144 square inches = 0.433 pounds per square inch (psi). The RCC column minimum size is 9" x 9" and incorporates four 12mm bars steel stiffeners and cleats of 8mm steel rings spaced 150mm center to center.

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A 0.1 kg ball is kicked from the edge of a cliff so that it attains a launch speed of 20 m/s at an angle of 37 to the horizontal, as shown above. On the axes below, sketch a graph of the vertical component of the ball's velocity as a function of time for the first 3 s of motion.

Answers

The graph of the vertical component of the ball's velocity is in the attachment

What is speed?

Speed is the distance moved per unit time.

What is velocity?

Velocity is the total displacement per unit time of an object.

How to sketch a graph of the vertical component of the ball's velocity as a function of time for the first 3 s of motion?

Since a 0.1 kg ball is kicked from the edge of a cliff so that it attains a launch speed of 20 m/s at an angle of 37 to the horizontal, as shown above. To determine the vertical component of velocity,we use the equation of motion

v = u - gt where

v = final vertical component of velocity, u = initial vertical component of velocity = u'sinФ where u' = initial launch speed = 20m/s and Ф = angle above horizontal = 37°, g = acceleration due to gravity = 9.8 m/s² and t = time

So, substituting the values of the variables into the equation, we have

v = u - gt

v = u'sinФ - gt

v = (20 m/s)sin37° - (9.8 m/s²)t

v = (20 m/s) × 0.6018 - (9.8 m/s²)t

v = 12.04 m/s - (9.8 m/s²)t

So, for the first 3 seconds, we have

for t = 0 s

v = 12.04 m/s - (9.8 m/s²) × 0 s

v = 12.04 m/s - 0 m/s

v = 12.04 m/s

for t = 1 s

v = 12.04 m/s - (9.8 m/s²) × 1 s

v = 12.04 m/s - 9.8 m/s

v = 2.24 m/s

for t = 2 s

v = 12.04 m/s - (9.8 m/s²) × 2 s

v = 12.04 m/s - 19.6 m/s

v = -7.56 m/s

for t = 3 s

v = 12.04 m/s - (9.8 m/s²) × 3 s

v = 12.04 m/s - 29.4 m/s

v = -17.36 m/s

So, we plot the graph of the vertical component of the ball's velocity using the equation v = 12.04 m/s - (9.8 m/s²)t

Find the graph in the attachment

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a rock is dropped from a 100-m-high cliff. how long does it take to fall (a) the first 50 m and (b) the second 50 m?

Answers

(a) For the first 50 m:

h1 = 0.5 x a x t12

50 m = 0.5 x 9.8 m/s2 x t12

t1 = 3.19 s

Time to fall first 50 m = 3.19 s

(b) For the full 100 m:

h2 = 0.5 x a x t22

100 m = 0.5 x 9.8 m/s2 x t22

t2 = 4.52 s

Time to fall second 50 m = t2 - t1 = 1.33 s

Dropped rocks and other objects gain speed rapidly as they fall. Velocity defines the direction in which a body or object is moving. Velocity is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance.

If our planet loses gravity for even 5 seconds it means the end of life on Earth as we know it. Gravity pulls objects together. The greater the mass of an object, the stronger its gravitational pull. Any submarine you choose for skydiving should be designed with movement in mind. If the weather is cool on the day of skydiving, you should choose pants that cover the entire leg. We recommend wearing sweatpants or sweatpants.

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The pressure of the gas is 112 kPa when its temperature is 35 °C.
The gas is heated to 340°C using some different apparatus.
Calculate the pressure of the gas when its temperature is 340 °C.
Assume the gas has a constant volume.
Pressure =
kPa

Answers

Answer:

Pressure = 223 kPa

Explanation:

Given:

p₁ = 112 kPa = 112 000 Pa

t₁ = 35°C;    T₁ = 273 + 35 = 308 Pa

t₂ = 340°C;    T₂ = 273 + 35 = 613 Pa

V - const

___________

p₂ - ?

Charles' law:

p₁ / T₁ = p₂ / T₂

The pressure:

p₂ = p₁·T₂ / T₁

p₂ = 112 000·613 / 308 ≈ 223 000 Pa   or  p₂ = 223 kPa

blood is flowing through an artery of radius 2.0 mm at a rate of 33.0 cm/s. determine the flow rate and the volume that passes through the artery in a period of 20 s.

Answers

The flow rate and the volume that passes through the artery in a period of 20 s is Q= 4.1448cm³/s and V= 82.896cm³.

How is a flow rate calculated?

We must define both the volume V and the instant in time it is flowing past represented by t in order to determine the Flow Rate denoted by Q, which is equal to V/t. In addition, the relationship between flow rate and velocity can be seen in the equation Q = Av, where A is the flow's cross-sectional area and v is its average velocity.

We must utilize the equation Q=V x A, where Q is the flow rate, V is the velocity, and A is the area, to determine the flow rate.

We must apply this formula to determine the volume. V = Q x t, where Q is the flow rate, t is the time, and V is the volume.

Converting 2mm to cm is the first thing we must accomplish.

2mm x 0.1= 0.2 cm

Currently, we utilize the calculation Q=V x A, but we must keep in mind that the area of an artery is circular, therefore we swap out A with the formula π r2.

Q= 33 cm/s x 3,14x (0.2cm)²

Q= 33cm/s x 0.1256cm²/s

Q= 4.1448cm³/s.

There is a flow at 4.1448cm³/s.

Now, using the flow rate (Q), we may

V=  4.1448 cm³/s x 20s

V= 82.896cm³.

82.896cm3 of fluid travels through the artery every 20 seconds.

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using your spectroscope, you observe a light source and see several strong, distinct lines. is this source continuous or discrete? given a line with a wavelength corresponding to 500 nm, calculate the energy of the emitted light.

Answers

With the aid of your spectroscope and E = (h*c)/wavelength, you can determine the energy of the emitted light to be 3.97 x 10-19.

What does a mean in terms of wavelength?

mathematical representation The movement v (in the x direction), frequency f, and wavelength of traveling sinusoidal waves are frequently expressed mathematically as follows: where y is the value of the wave at any place x and time t, and A is the wave's amplitude.

What is the wavelength measurement unit?

The symbol for the wavelength in the SI is typically m, or one metre. The multiples or fractions of something like a meter are also employed for measuring wavelength. Notably, when wavelengths are a significant attribute, exponential powers of 10 are employed. Shorter wavelengths are given as negative exponentials.

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Using what you have learned about series and parallel circuits, explain how some appliances in your kitchen receive power while others do not. (PLEASE HELPP)

Answers

To learn series and parallel circuits, to know the some appliances in your kitchen receive power while others do not.

What is series circuits?

A series circuit is an easy way for electrons to travel to one or more resistors. Anything that depends on a cell for power is a resistor. A bulb frequently serves as the resistor in a series circuit.

What is parallel circuit?

Branching is used in a parallel circuit so that the current is divided and only a portion of it passes through each branch. In a parallel circuit, the voltage, or potential difference, across each branch is the same, but the currents may differ.

While plugged in, a range of various electronic equipment and appliances, such as televisions, toasters, lamps, and more, can use electricity even when they're off.

Therefore, known the series and parallel circuits, the some appliances receive powers.

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monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35 mm. find the wavelength of the light.

Answers

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

How to find Wavelength of the light?

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

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a rocket with a mass of 4kg accelerates up from the ground at a rate of 20ft m/s^2, what is the drag force acting on the rocket if the thrust of the rockets is 150n

Answers

The drag force acting on the rocket is 80N.

Give an explanation of drag force?

The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.

The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.

The drag force acting on the rocket F = ma

Given,

m = 4kg, a = 20ftm/s²

Substituting m and a values in the above formula,

The drag force acting on the rocket F = 4×20

The drag force acting on the rocket F = 80N.

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