A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?

Answers

Answer 1

The ratio of time of flight for inelastic collision to elastic collision is 1:2

The given parameters;

mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂

Considering inelastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]

The time of motion of the system form top of the table is calculated as;

[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]

Considering elastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]

Apply one-directional velocity

[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]

Substitute the value of [tex]v_1[/tex] into the above equation;

[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]

where;

[tex]v_2[/tex] is the final velocity of the block after collision

Since the bullet bounces off, we assume that only the block fell to the ground from the table.

The time of motion of the block is calculated as follows;

[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]

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Related Questions

I am unique even though there are billions of me no two are the same what am I


AND IT'S NOT A FINGER-PRINT

Answers

I think the answer is Snow flakes

Since every ice crystal takes a different route to the ground. They will float through various clouds with various temperatures and moisture contents, which will cause the ice crystal to develop in a distinctive manner.

What make snowflakes unique?

A snowflake's shape changes as it flies through the atmosphere, thus no two are ever the same. Even two flakes floating side by side will each be blown through various vapour and humidity levels to produce a genuinely unique shape.

One of the most recognizable representations of winter weather are snowflakes. There are an unlimited amount of conceivable shapes for snowflakes, and each one is distinct.

Therefore, snowflakes unique even though there are billions.Even two floating flakes will each be exposed to different vapour and humidity conditions, creating a really distinctive form.

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What did Ernest Rutherford expect to happen when he aimed a beam of particles at a thin gold foil

Answers

Answer:

he expected a fire to happen I think

Answer:

When Ernest Rutherford aimed a beam of particles at a thin gold foil he expected that the particles would be deflected slightly after passing through the foil.

Explanation:

hope it helped

How to do this question plz ​

Answers

Answer:

  C

Explanation:

Most discussions of refraction will have a diagram similar to that of C.

The angle of incidence is measured from the normal to the boundary, as is the angle of refraction. The product of the sine of the angle and the index of refraction is the same for the media on either side of the boundary.

  n₁·sin(θ₁) = n₂·sin(θ₂)

For media, such as optical fiber, that has an index of refraction greater than 1, the angle of refraction will be smaller in that media than the angle of incidence coming from air.

Figure C applies.

Explain how the potential energy is changed to kinetic energy in the Hoover Dam​

Answers

The water behind a hydroelectric dam stores gravitational potential energy since it is at a higher level than the water on the other side of the dam. As the water falls, this potential energy is converted into kinetic energy, which turns turbines to generate electricity. Often, the water comes from behind a dam built across a river valley. The water high up behind the dam contains gravitational potential energy . This is transferred to kinetic energy as the water rushes down through tubes inside the dam. The moving water drives electrical generators , which may be built inside the dam.

How to find final velocity and initial velocity and acceleration ? :(

Answers

Explanation:

Final velocity=Initial velocity+(acceleration×time)

4 ways to find initial velocity:

1) Initial velocity=Final velocity-(acceleration×time)

2) Initial velocity=(Distance/Time)-((acceleration×time)/2)

3) Initial velocity=√Final velocity-(2×(acceleration×distance))

4) Initial velocity=2(distance/time)-Final velocity

Total force = Mass×Acceleration

(F=ma)

A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?​

Answers

The radius of the new moons orbit is R= 7.715 x 10^7 m
The orbital period of the moon is T= 14.48 hr

Convert 8 m/s to miles per hour

Answers

Answer:

17.8954903 or 17.9 mph

Explanation:

m/s is meters per second. 1609.344 meters is one mile. There are 3,600 seconds in an hour.  8 meters *3600 seconds= 28,800.  28,800/1609.344 = 17.8954903. Simplify to 17.9


(a) One medium is air, in which the speed of light is 3.00 x 108 m/s. The other
medium is ice, in which light has a speed of 2.29 x 108 m/s. Use this information to
identify medium A and medium B. Explain

Answers

Answer:

WARNING WRONG SPELLING.that is a ternadow and very dangeruse air .

Give proof that mass is constant and weight keeps changing.​

Answers


The mass of an object stays the same wherever it is, but its weight can change. This happens if the object goes where the gravitational field strength is different from the gravitational field strength on Earth, such as into space or another planet.

I need help asap! Will give brainliest

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[tex]\\ \tt\hookrightarrow \dfrac{(3\times 10^4kg)(4\times 10^4m)}{6\times 10^4s)}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{12\times 10^8kgm}{6\times 10^4s}[/tex]

[tex]\\ \tt\hookrightarrow 2kgm/s[/tex]

We have calculated momentum

will mark brainliest if answer​

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I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.

PLEASE HELP!! 10 points!!!! brainliest!!!
Why is a sound wave considered to be a mechanical wave? What properties of sound
waves are responsible for pitch and volume

Answers

Answer:

Mechanical Sound Waves - A sound wave moves through air by displacing air particles in a chain reaction. ... Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave. For pitch the higher the frequency, the higher the pitch. Frequency is measured in hertz, or cycles per second. Frequency also affects loudness, with higher-pitched sounds being perceived as louder. Amplitude and frequency of sound waves interact to produce the experiences of loudness and pitch.

Mechanical Sound Waves - A sound wave moves through air by displacing air particles in a chain reaction. ... Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave. For pitch the higher the frequency, the higher the pitch. Frequency is measured in hertz, or cycles per second. Frequency also affects loudness, with higher-pitched sounds being perceived as louder. Amplitude and frequency of sound waves interact to produce the experiences of loudness and pitch.

Do two indentical objects become statically charged when you rub them together? Explain why they do or do not.

Answers

Answer:

Yes, they do. When two different materials are rubbed together, there is a transfer of electrons from one material to the other material. This causes one object to become positively charged and the other object to become negatively charged.

Explanation:

hope this helps

who has the best answer for this
what percentage more water is used to provide us with electricity vs for irrigation

Answers

Answer:

electricity because it has more percentage nd energy

Explanation:

mark me brainliest pl

Help me pls both answers i’ll give brainly

Answers

Do u know the formula

Someone answer? Please

Answers

I don’t know ask your parents

9. When a balloon rises into the air, it
A. Expands on cooling
B. Contracts on cooling
C Expands on heating
D. Contracts on heating

Answers

Answer:

Answer 3: When a balloon goes up higher in the air, its size will increase. Since there's less air in the upper atmosphere, there's less stuff pushing back on the balloon, and hence the pressure is lower, which allows the balloon to expand

Answer: C

Explanation:

As the balloon rises, the gas inside the balloon expands because the atmospheric pressure surrounding the balloon drops. The atmosphere is 100 to 200 times less dense at the float altitudes than on the ground. and as the air is heated inside the balloon it causes it to rise upwards (because it is lighter than the cooler air on the outside). When the pilot needs to bring the balloon down again, he simply reduces the temperature of the air inside the balloon causing it to slowly descend.

I need some help with this.

Answers

[tex]I = \frac{V}{R} \\ [/tex]

Thus :

[tex]I = \frac{160}{2} \\ [/tex]

[tex]I = 80 \: \: A[/tex]

So :

[tex]V = 160[/tex]

[tex]I = 80[/tex]

[tex]R = 2[/tex]

As a satellite is accelerated away from the Earth by a rocket, the satellite's mass ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
increases
remains the same
decreases

Answers

The mass of the satellite will remain the same when it is accelerated away from the Earth.

The mass of an object is a scalar quantity. This implies that mass of an object can be completely described with magnitude only.

The mass of every object in the universe is independent of the gravity and will always maintain the same value from place to place.

Thus, we can conclude that, the mass of the satellite will remain the same when it is accelerated away from the Earth.

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What are some of the dangers that volcanoes pose to human populations? a. Destruction of property from lava flow b. Destruction from mud flows c. Lung problems from ash and toxic gases d. All of the above.

Answers

Destruction of property from lava flow, destruction from mud flows and lung problems from ash and toxic gases are all some of the dangers that volcanoes pose to human populations.

Volcanoes refer to an opening that appears on the earth's surface and serves as a vent for lava, volcanic ash, and gases. These could lead to a fire outbreak in mountains sometimes.

The following are dangers posed by volcanoes pose to human populations;

Destruction of property from lava flow Destruction from mud flowsLung problems from ash and toxic gases

Hence, the correct answer to the question is "all of the above".

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Answer:

D

Explanation:

EDGE 2021

free tingsssssssssss

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Explanation:

yayyy thx u soo muchihuhuhu

Answer:

thx

Explanation:

What would be the difference in your welght if you were four times farther from the center of Earth than you are now?

Answers

you would die.

the core of the earth is as hot as the sun surface so you would be dead

You slide towards the window when a car makes a sudden turn

Answers

Answer:

thats ummm

Explanation:

law of inertia

Newton’s 1 law

The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)​

Answers

Answer:

F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2

F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons

F = 3.53E22 N

If an input force of 202N is applied to the handles of the wheelbarrow in the sample problem how large is the output force that just lifts the load?

Answers

For this case, the relationship between the two forces is given by:

F1 = nF2

Where,

F1: output strengthF2: input forcen: mechanical advantage

Then, replacing the values we have:

F1 = (2.2)(202)

Having the calculations we have:

F1 = 444.4N

Answer: The output force that only lifts the load is F1 = 444.4N.

Does the coefficient of kinetic friction depend on the speed?

Answers

Answer:

yes because if the speed/K.E. of body increases the friction will also apply more instantly

A father places his daughter in a swing that is 0.60\,\text{m}0.60m0, point, 60, start text, m, end text above ground. Then he raises the swing to a height of 1.3\,\text{m}1.3m1, point, 3, start text, m, end text and lets go. The girl and the swing have a combined mass of 14\,\text{kg}14kg14, start text, k, g, end text. Assume friction is negligible and use g = 9.8\,\text{m/s}^2g=9.8m/s
2
g, equals, 9, point, 8, start text, m, slash, s, end text, squared.
Calculate the girl’s fastest speed.

Answers

This question involves the concepts of the law of conservation of energy and kinetic energy.

The girl's fastest speed is "3.7 m/s".

According to the law of conservation of energy, the girl will have the fastest speed at mean position, which will be calculated as follows:

Loss in Potential Energy = Gain in Kinetic Energy

[tex]mg\Delta h=\frac{1}{2}mv^2\\\\v=\sqrt{2g\Delta h}[/tex]

where,

v = maximum speed = ?

g = acceleration due to gravity = 9.81 m/s²

Δh = change in height = 1.3 m - 0.6 m = 0.7 m

Therefore,

[tex]v=\sqrt{2(9.81\ m/s^2)(0.7\ m)}[/tex]

v = 3.7 m/s

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Please help if you can

Answers

Answer:

The answer is B

Explanation:

Because when the both sides aren't balanced one side has to cause motion. (fall down)

A 2-kg object is pulled to the left with a force of 30 N and to the right with a force of 9 N. What is the acceleration of the object?

Answers

An object that weighs  75  N is pulled horizontally to the right with a force of  50  N. The force of friction on this object is  30  N to the left. What is the acceleration of the object?

The force on the object is  50  N to the right and  30  N to the left.

⇒  The net force on the object is,  =50−30=20  N to the right.

The weight of the object is,  =75  N.

⇒  The mass of the object is  ==759.8  kg.

⇒  The acceleration of the object is  ==20759.8=2.613  m/s 2.

The acceleration of the object is 10 [tex]m/s^2[/tex].

What is Acceleration?

Acceleration is defined as the rate of change of velocity of an object with respect to time which are vector quantities i.e. both magnitude and direction. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.

It can be expressed as:

a= v/t

where, a is the acceleration

v is the velocity

t is the time taken

It can also be expressed as F=ma

where, F= force applied

m= mass of the object

So, for above given information

The force on the object is 9N to the right and  30N to the left. The net force on the object is 21N to the left

The mass of the object is 2kg

So, a= 21N/ 2 kg = 10.5 [tex]m/s^2[/tex]

Thus, the acceleration of the object is 10 [tex]m/s^2[/tex].

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write of the following does not represent electrical power in a circuit ?

(a) I²R


(b) IR²

(c)VI

(d) V²/R​

Answers

(b) IR^2 does not represent electrical power in a circuit.


The equations for electrical power are as follows:

P=I^2R

P=VI

P=V^2/R
(You can get this equation by rearranging V=IR, making I the subject to get I=V/R and substituting that into P=VI)

P=E/T
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