If a Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute then the acceleration of a passenger at his lowest point during the ride is 4.11 [tex]\text{m/s}^{2}[/tex].
Calculation:
Step-1:
It is given that the radius of the Ferris wheel is r=15 m, and the angular speed of the wheel is [tex]\omega[/tex]=5rev/min.
It is required to find the angular acceleration of a passenger at his lowest point during the ride.
The formula required to calculate the angular acceleration is, [tex]a=\omega ^2 r[/tex].
Step-2:
Now substituting the given values into the equation to get the value of the angular acceleration.
[tex]\begin{aligned}a &=\omega^{2} r \\&=(5 \mathrm{rev} / \mathrm{min})^{2}(15 \mathrm{~m}) \\&=\left(5 \mathrm{rev} / \mathrm{min} \times \frac{\left(\frac{2 \pi}{60}\right) \mathrm{rad} / \mathrm{sec}}{1 \mathrm{rev} / \mathrm{min}}\right)^{2}(15 \mathrm{~m}) \\&=(0.2741 \times 15) \mathrm{m} / \mathrm{s}^{2} \\&=4.11 \mathrm{~m} / \mathrm{s}^{2}\end{aligned}[/tex]
The acceleration is towards upwards that means towards the center of the wheel.
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Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of:
Answer: Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through angle [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of n .
Explanation: To find the correct answer, we need more clarifications about the Malu's law.
What is Malu's law?When a beam of plane polarized light is passed through an analyzer, the intensity I of the transmitted light varies directly as the square of the angle between the direction of polarizer and the analyzer.[tex]I=I_0cos^2\alpha[/tex]
where, [tex]I_0[/tex] is the maximum intensity of transmitted light.
Intensity of the light transmitted through the polarizer is half of the incident intensity.How to solve the problem?Here in the question ,let's take the factor at which the intensity of transmitted light is reduced by as n.we have the expression[tex]I=I_0cos^2\alpha[/tex]
we have to find the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n.[tex]\alpha =cos^-1\sqrt{(\frac{I}{I_0}} )=cos^-1\sqrt{\frac{I}{nI} } \\\alpha =cos^-1\sqrt{\frac{1}{n} }[/tex]
If we know the value of n, then we can easily find the angle.Thus, we can conclude that, the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n will be,
[tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] .
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In a series lrc circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance, the capacitance, and the voltage amplitude of the ac source, what is the new resonance frequency?.
When you double capacitance and inductance, the new resonance frequency becomes f/2.
Resonance frequency:The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.
It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.
Xc = Xl
which gives the value for resonance frequency:
[tex]f = \frac{1}{2\pi \sqrt{LC} }[/tex]
where;
f is the resonance frequency
L is the inductance
C is the capacitance
When you double capacitance and inductance, the new resonance frequency becomes;
[tex]f' = \frac{1}{2\pi \sqrt{2L2C} }[/tex]
[tex]f' = \frac{1}{2\pi \sqrt{4LC} }[/tex]
[tex]f' = \frac{1}{\pi \sqrt{LC} }\frac{1}{2}[/tex]
[tex]f' = \frac{1}{2} f[/tex]
Thus from above,
When you double capacitance and inductance, the new resonance frequency becomes f/2.
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What happens within a protostar to create a star?
Clouds of gas in space
A protostar resembles a star, but its core is still too cool for fusion to occur. The protostar's heating as it contracts is the only source of brightness. The light that protostars release is typically blocked by dust, making them challenging to study in the visible spectrum.
By the time a protostar is produced, the cloud has flattened and a protostellar disk is spinning around it. The cloud starts spinning as it collapses. These disks occasionally form planetary systems and are thought to slow the protostar's rotation. The protostar produces a powerful magnetic field as it revolves.
Additionally, a strong protostellar wind—a movement of particles into space—is produced by the magnetic field. A lot of protostars also release gas into space in the form of fast-moving streams or jets.
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True or false: power output can be increased by increasing the rate at which work is done.
By speeding up the process of doing work, power production may be enhanced. The following statement is true.
Description:
Work is completed at a rate determined by power. It is the ratio of work to time. It may be calculated mathematically using the next equation.
Power = Work / Time
or, P = W / T
If the amount of effort/work increases and the amount of time decreases, power will grow. To complete a task in a short amount of time, a lot of force is used.
The Watt is the common metric unit of power. A quantity of power is one unit of labor divided by one unit of time, as the expression for power suggests. As a result, one Watt is equal to one Joule/second. The term "horsepower" is sometimes used to describe a machine's output of power for historical reasons. The equivalence of horsepower is around 750 Watts.Therefore it is concluded that the questioned statement is true.
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A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?
The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
To find the answer, we have to know more about the basic forces acting on a body.
How to find the net force on the box?Let us draw the free body diagram of the given box with the data's given in the question.From the diagram, we get,[tex]N=mg\\F_t=ma\\F_t=F-f[/tex]
where, N is the normal reaction, mg is the weight of the box, [tex]F_t[/tex] is the net force, f is the kinetic friction.
We have the expression for kinetic friction as,[tex]f=kN=kmg=0.267*1.75*9.8= 4.58N[/tex]
Thus, the net force will be,[tex]F_t= 8.35-4.58=3.77N[/tex]
Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
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The net force acting on the box is 3.77 N.
We need to learn more about the fundamental forces affecting a body in order to locate the solution.
How can I determine the box's net force?Let's use the information provided in the question to draw the free body diagram of the given box.The diagram gives us,[tex]N=mg\\F_n=F-f[/tex]
where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.
The kinetic friction expression is as follows:[tex]f=kN=kmg=4.58N[/tex]
the net force will be as follows:[tex]F_n=3.77N[/tex]
Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.
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Compared with a car moving at some original speed, how much work must the brakes of a car supply to stop a car that is moving twice as fast? how will the stopping distances compare?.
It takes four times the work and four times the stopping distance.
Given:
original speed of car = x
brakes applied so final speed = 0
moving speed of another car = 2x
To Find:
work done to stop the car
Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
Work done is given by
W = KE(final) - KE(initial)
W = 1/2m(v)^2 - 1/2m(u)^2
W = 1/2m(0 - (x)^2)
W = 1/2m(4x^2)
W = 4(1/2mx^2)
W = 4W
So, work done will be 4 times initial work
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(d) A force of 30 N is required to accelerate a skateboard at 1.5 m/s². How much force
would accelerate the same skateboard at 6.0 m/s²?
Answer:
[tex]\huge\boxed{\sf F = 120\ N}[/tex]
Explanation:
Firstly, we need to find the mass of the skateboard.
Using formula:
F = maWhere,
Force = f = 30 NAcceleration = a = 1.5 m/s²30 = m (1.5)
Divide 1.5 to both sides
30/1.5 kg = m
20 kg = m
m = 20 kgNow, finding the force:Using the same formula.
F = maWhere,
mass = m = 20 kgAcceleration = a = 6 m/s²F = (20)(6)
F = 120 N[tex]\rule[225]{225}{2}[/tex]
help me and I will be your friend forever.
Answer:
1. iodine
2. convection
3. radiation
4. conduction
5. gases
6. expansion
7. freezing point
8. absorber
9. thermos flask
10. mercury
the work done by the brakes during braking is equal to
Answer:
The amount of pressure delivered to them
Explanation:
Normal human body temperature is 98.6°F. What is this temperature expressed in Celsius (°C) and in Kelvin (K)?
Answer: 37 Celsius and 310.15 K
Explanation:
C/5 = (F-32)/9 = (98.6-32)/9 = 66.6/9 = 7.4
C = 7.4 * 5 = 37 so the temperature is 37 Celsius
K = C + 273.15 = 37 + 273.15 = 310.15 K
It is well known that for a hollow, cylindrical shell rolling without slipping on a horizontal surface, half of the total kinetic energy is translational and half is rotational. What fraction of the total kinetic energy is rotational for the following objects rolling brainly
The fraction of the total kinetic energy that is rotational for a uniform sphere is 1/3.
What is kinetic energy?Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.Option (a) [tex]f = \frac{0.5}{1.5} = \frac{1}{3}[/tex]
Option (b) uniform sphere
[tex]f = \frac{2}{7}[/tex]
C) uniform hollow sphere
[tex]f = \frac{2}{5}[/tex]
D) uniform hollow cylinder with inner radius R/2 and outer radius R
[tex]f = \frac{5}{13}[/tex]
that fraction of total energy as rotational energy is given as
[tex]f = \frac{\frac{1}{2}Iw^{2} }{\frac{1}{2}mv^{2} + \frac{1}{2} Iw^{2} }[/tex]
[tex]f = \frac{m k^{2}(\frac{v^{2} }{R^{2} }) }{mv^{2} + m k^{2}(\frac{v^{2} }{R^{2} } )}[/tex]
[tex]f = \frac{\frac{k^{2} }{R^{2} } }{1 + \frac{k^{2} }{R^{2} } }[/tex]
A) uniform Solid cylinder for cylinder we know that
[tex]\frac{k\\ ^{2} }{R^{2} }[/tex] = 0.5
[tex]f = \frac{0.5}{1.5} = \frac{1}{3}[/tex]
B) uniform Sphere for sphere we know that
[tex]\frac{k^{2} }{R^{2} } = \frac{2}{5} \\[/tex]
[tex]f = \frac{0.4}{1.4} = \frac{2}{7}[/tex]
C) uniform hollow sphere for hollow sphere we know that
[tex]\frac{k^{2} }{R^{2} } = \frac{2}{3}[/tex]
[tex]f = \frac{\frac{2}{3} }{\frac{5}{3} } = \frac{2}{5}[/tex]
D) uniform hollow cylinder with inner radius R/2 and outer radius R for annular cylinder
[tex]\frac{k^{2} }{R^{2} } = \frac{5}{8}[/tex]
[tex]f = \frac{\frac{5}{18} }{\frac{13}{8} } = \frac{5}{13}[/tex]
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The complete question is -
It is well known that for a hollow, cylindrical shell rolling without slipping on a horizontal surface, half of the total kinetic energy is translational and half is rotational. What fraction of the total kinetic energy is rotational for the following objects rolling without slipping on a horizontal surface?Part AA uniform solid cylinder.Part BA uniform sphere.Part CA thin-walled hollow sphere.Part DA hollow, cylinder with outer radius R and inner radius R/2.
is the Earth bigger than the moon
Answer:
Yes
Explanation:
The Earth is about 4x bigger than the moon. Scientists speculate that the moon was once part of Earth, until something hit the Earth, and broke off a large chunk of it. These pieces were flung off the Earth, and began to orbit it. Slowly, the pieces were mashed together by gravity, and formed the moon.
In the writing of ionic chemical formulas, what factor is "crossed over" in the crossover rule?
In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.
Rules for naming Ionic compounds
Frist RuleThe oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.
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Because white dwarfs are small, as their name implies, they are hard to see. What is a way astronomers have to find white dwarfs that distinguishes them from main sequence stars
Astronomers find white dwarfs that distinguish them from main sequence stars because white dwarfs get really hot, we can search for their ultraviolet radiation.
What is a white dwarf?A white dwarf is a very hot star that radiated much energy in the form of ultraviolet radiation.
This UV radiation is initially very bright and then these stars become red with time.
In conclusion, Astronomers find white dwarfs they can search for their ultraviolet radiation.
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A lot contains 750 square yards and has a length of 150 feet, what does the frontage measure?
The frontage measure is 45 feet.
FeetThe British imperial and American customary systems of measurement both use the feet (standard symbol: ft) as a unit of length. One foot has exactly 0.3048 meters since the International Yard and Pound Agreement of 1959. One yard equals three feet in both customary and imperial measurements. One foot equals 12 inches.
Throughout history, numerous regional systems of units, including the Greek, Roman, Chinese, French, and English systems, included the concept of "feet." Its length varied from one nation to another, from one city to another, and occasionally from one trade to another. Its length was often divided into 12 inches or 16 digits, however this was not always the case. Its typical length was between 250 mm and 335 mm.
A lot contains 750 square yards and has a length of 150 feet, what does the frontage measure?
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deidre walked her dog a distance of 95 meters to the north. the walk took 45 seconds. what was their velocity
Velocity of Deidre and her dog is 2.11m/s.
What is velocity?Velocity is the rate of change of position of an object in a particular frame of reference Mathematically, velocity of an object = Displacement of the object/time taken What is velocity of Deidre and her dog ?The distance covered by Deidre and her dog is 95 meter towards north.The time taken to cover the distance is 45 second.So velocity of Deidre and her dog =95/45=2.11m/s
Thus , we can conclude that the velocity of Deidre and her dog is 2.11 m/s towards north .
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How much the aproximate number of atoms in bacteria.assume that average mass of an atom in bacteria is ten times the mass of hydrogen atom
Select the correct answers. which two pieces of information show that a research source is reliable?\
Answer:
2
Explanation:
just took the assignment
Noah drops a rock with a density of 1.73 g/cm° into a
pond. Will the rock float or sink? Explain your answer.
Answer:
the rock will probably sink in water because density of rock heavier than the density of water.
Density of water=1g/cm
density of rock=1.73g/cm
1g/cm< 1.73g/cm
A brick and a feather fall to the earth at their respective terminal velocities. Which objectexperiences the greater force of air friction?
Answer:
Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.
Explanation:
Objects at terminal velocity, only under the influence of gravity, have maximized their speed and have an acceleration of zero. Thus, neither object is accelerating.
Recall Newton's second law: [tex]\sum {\vec {F}}=m \vec {a}[/tex]
Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.
Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, the force of air friction must be equal in magnitude and opposite in direction to the force of gravity.
Recall that near the surface of the earth, [tex]F_{gravity}=mg[/tex], so the Force of Gravity acting on an object is directly proportional to the object's mass. (A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).
If the masses of the objects are different, the object with the greater mass will experience a larger force of gravity, and hence a larger force of air friction at terminal velocity.
Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.
Arrange these objects according to size, largest to smallest. Group of answer choices traditional dwarf elliptical, ultra-compact dwarfs, globular clusters ultra-compact dwarfs, traditional dwarf galaxies, globular clusters globular clusters, traditional dwarf elliptical, ultra-compact dwarfs globular clusters, ultra-compact dwarfs, traditional dwarf elliptical
Among the given objects, the largest one is dwarf elliptical, then ultra-compact dwarf and then globular clusters. Thus, option a is correct.
To find the correct answer, we need to know about the galaxies.
Are galaxies bigger than globular clusters?Globular clusters are spherical groups of stars that are primarily located in the spiral galaxy' stellar halo. There are 150 or so globular clusters in our Milky Way galaxy, some of which house our galaxy's oldest stars.Globular clusters are much smaller than galaxies.a system of gas and dust, as well as millions or billions of stars, kept together by gravitational attraction is called galaxy.Ultracompact dwarfs are more extended and have higher surface brightness than typical dwarf nuclei.Dwarf elliptical galaxies are elliptical galaxies that are smaller than ordinary elliptical galaxies. They are quite common in galaxy groups and clusters and are usually companions to other galaxies.Thus, we can conclude that, option a is correct.
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The measure of arc ed is 68°. what is the measure of angle efd? 34° 68° 112° 132°
The measure of the angle EFD = 34°. That is option A.
Calculation of an angle of an intercepted arcThe radii of the given circle are CE and CD.
The measure of the given angle of the arc is = 68°
But the central angle of an intercepted arc measure the double of the inscribed angle by the same arc.
Therefore, the measure of angle of an intercepted arc is 68/2 = 34°
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Answer:
34
Explanation:
edge 2023
Which one of the following aqueous solutions would you expect to have the smallest conductance: _______
(a) 0. 060 m nacl,
(b) 0. 030 m nacl, or
(c) 0. 015 m nacl? explain your reasoning
(c) 0. 015 m NaCl of the following aqueous solutions would be expected to have the smallest conductance.
Conductance is the expression of the ease of the passing of the electrons. Conductivity is a numerical expression of the tendency of an aqueous solution to carry an electric current. Electricity is conducted through an electrolytic solution due to the movement of ions. In general, the greater the number of ions in the solution higher is the conductance.
The conductance of a solution depends on 1) the concentration of the ions it contains, 2) on the number of charges carried by each ion, and 3) on the mobilities of these ions.
In an aqueous solution , charged particles that conduct electricity are ions , because of free ions electricity can be conducted in the solution. So , conductance depend upon concentration of the solution , more the concentration of solution more will be the conductance .
out of given solution , options a) 0.060 m solution of NaCl will be the most conducting solution as it is most concentrated option c) 0.015 m solution of NaCl will be the least conducting solution as it is the least concentrated solution .
correct option will be (c) 0. 015 m NaCl of the following aqueous solutions would be expected to have the smallest conductance.
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What does a dielectric do to a capacitor?
A dielectric fabric is used to split the conductive plates of a capacitor. This insulating cloth significantly determines the properties of a component. The dielectric constant of fabric determines the amount of strength that a capacitor can keep while voltage is applied.
A capacitor is an electrical component that attracts energy from a battery and stores the power. Internal, the terminals connect with metal plates separated by way of a non-engaging in substance. While activated, a capacitor quickly releases electricity in a tiny fraction of a 2d.
Capacitor, a tool for storing electric electricity, together with two conductors in near proximity and insulated from each different. A simple example of this sort of garage tool is the parallel-plate capacitor.
A capacitor is a tool that shops electric power in an electric-powered area. it is a passive digital thing with terminals. The effect of a capacitor is called capacitance.
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How many people are allowed daily into the coyote buttes north area, which includes the wave?.
64 people are allowed daily into the coyote buttes north area, which includes the wave.
What can be seen in coyote buttes north?The Wave and other aesthetically stunning natural sandstone formations can be found in Coyote Buttes North.
Where is coyote butte north located?It is a small portion of the 112,500-acre Paria Canyon-Vermilion Cliffs Wilderness of Northern Arizona.
To enter Coyote Buttes North (The Wave) and Coyote Buttes South, you need a permission. There are only daytime permits available. Permits have a daily maximum. Coyote Buttes North (The Wave) permits are distributed via lottery.How was the wave in coyote buttes formed?
The Wave is a Navajo Sandstone formation found in the Paria Canyon-Vermilion Cliffs Wilderness of Northern Arizona. The amazing patterns in the rock here were created by the wind and erosion over millions of years.To learn more about coyote buttes north visit:
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64 people are allowed daily into the coyote buttes north area, which includes the wave.
What can be seen in coyote buttes north?The Wave and other aesthetically stunning natural sandstone formations can be found in Coyote Buttes North.
Where is coyote butte north located?
It is a small portion of the 112,500-acre Paria Canyon-Vermilion Cliffs Wilderness of Northern Arizona.
To enter Coyote Buttes North (The Wave) and Coyote Buttes South, you need a permission.
There are only daytime permits available.
Permits have a daily maximum.
Coyote Buttes North (The Wave) permits are distributed via lottery.
How was the wave in coyote buttes formed?The Wave is a Navajo Sandstone formation found in the Paria Canyon-Vermilion Cliffs Wilderness of Northern Arizona.
The amazing patterns in the rock here were created by the wind and erosion over millions of years.
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When the Sun runs out of hydrogen in its core, it will become larger and more luminous because Choose one: A. energy balance no longer holds, and the star just drifts apart. B. infalling material rebounds off the core and puffs up the star. C. it starts fusing hydrogen in a shell around a helium core. D. it starts fusing helium in a shell and hydrogen in the core.
It starts fusing hydrogen in a shell around a helium core
Eventually, a star will run out of hydrogen fuel in its core, nuclear fusion will stop, and the star will enter a new stage of its lifetime.
What happen to the Sun when it runs out of hydrogen ?Faster hydrogen burning means the star will grow larger and more luminous to allow the extra energy created to escape but since the temperature of the core remains constant the star's surface temperature will drop.
When our Sun runs out of hydrogen fuel in the core, it will contract and heat up to a sufficient degree that helium fusion can beginOnce that mass/temperature threshold is crossed, the star begins fusing hydrogen into helium, and will encounter one of three different fates.Learn more about Sun here:.
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A person riding a Ferris wheel moves through positions at (1) the top, (2) the bottom, and (3) mid-
height. If the wheel rotates at a constant rate, rank these three positions according to
(a)the magnitude of the person’s centripetal acceleration,
(b) the magnitude of the net centripetal force on the person, and
(c) the magnitude of the normal force on the person from the bottom, and
(d) the weight the person feels, greatest first.
A person riding a Ferris wheel moves through positions at
(1) the top,
(2) the bottom, and
(3) mid-height. If the wheel rotates at a constant rate, rank these three positions according to
(a)the magnitude of the person’s centripetal acceleration, is same in all cases.
(b) the magnitude of the net centripetal force on the person, is same in all three cases.
(c) the magnitude of the normal force on the person from the bottom,
2<3<1
(d) the weight the person feels, greatest first is at the bottom.
What is the relation between force and acceleration?The centripetal acceleration [tex]a_{c}[/tex] exists provided by : a= [tex]v^{2} /r[/tex] , therefore the magnitude depends upon the speed and the radius. This represents that in the case of the Ferris wheel the centripetal acceleration includes a constant magnitude so its value exists the same in all cases.From Newton's second law the force is provided by F=ma and since a exists constant in magnitude , F is also constant in magnitude. and its value exists the same in all three cases.At the top [tex]a_{c}[/tex] stands directed downward so the normal force exist given by [tex]F_{N}[/tex]=[tex]mg[/tex]- [tex]ma_{c}[/tex]While at the bottom [tex]a_{c}[/tex] exist directed upward and the normal force is provided by [tex]F_{N}[/tex]=mg +m[tex]a_{c}[/tex]Meanwhile,at mid -height [tex]a_{c}[/tex] stands directed horizontally to the inside so it doesn't have a vertical component so its normal force is provided by [tex]F_{N}[/tex]=mgThe normal force exists greatest at the bottom than at mid-height than at the top.To learn more about centripetal force , refer :
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convert 14 mg to kg ....
14mg = 14 × 10^-3 g
= 14 × 10^-3 / 10^3 kg
= 14 × 10^-6 kg
= 0.014 kg
☆...hope this helps...☆
_♡_mashi_♡_
Answer:
0.000014 kg
Explanation:
A total electric charge of 4.00 nC is distributed uniformly over the surface of a metal sphere with a radius of 26.0 cm. The potential is zero at a point at infinity.
for what we can get from our side then we will see if they are being made in a letter or something which is leading enormous growth in cities with brick and its own way that it will not on the market and its not a good life for us to stay in and
A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod:.
After the rod is charged and then touched on the neutral metallic sphere and then separated from it, the rod is repelled by the sphere. Option A
What is a static charge?There are very ways in which a static charge could be built up in an object. The ways include;
FrictionElectrostatic induction and ContactNow, after the rod is charged and then touched on the neutral metallic sphere and then separated from it, the rod is repelled by the sphere.
Missing parts;
A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from the ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod
A. is attracted by the sphere
B. is repelled by the sphere
C. feels no force due to the sphere
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