A chemical company makes two brands
of antifreeze. The first brand is 30% pure
antifreeze, and the second brand i$ 80% pure
antifreeze. In order to obtain 80 gallons of a
mixture that contains 70o£ pure antifreeze, hov
mabry gallons of each band ot antifneze must
bo used?​

Answers

Answer 1

Answer:

16 bags for the first(30% pure) and 64 bags of the second(80% pure)

Step-by-step explanation:

If they are mixed in a ratio of x bags to y bags

(0.3x+0.8y)/(x+y) = 0.7

0.3x + 0.8y = 0.7(x+y)

Multiply both sides with 10

3x + 8y = 7(x+y)

4x = y ——(1)

x + y = 80 ——(2)

Solve simultaneously

x + 4x = 80

5x = 80

x = 16 bags

y = 4x = 64 bags


Related Questions

x − 6 ≤ 3 solve for x please

Answers

Answer:

x  ≤ 9

Step-by-step explanation:

x − 6 ≤ 3

Add 6 to each side

x − 6+6 ≤ 3+6

x  ≤ 9

Answer:

x ≤ 9

I hope this helps!

what is the answer of
445+584-85

Answers

Answer:

944 is the correct answer

Answer:

the answer it's 944

445+558=1,029

1,029-85=. [944]✓

Which of the following is the correct factorization of 64x³ + 8? (2x + 4)(4x² - 8x + 16) (4x + 2)(16x² - 8x + 4) (4x - 2)(16x² + 8x + 4) (2x - 4)(4x² + 8x + 16)

Answers

Answer:

work is pictured and shown

The volume of a rectangular prism is the products it’s dimensions. If the dimensions of a rectangle prism are approximately 1.08 feet,5.25 feet, and 3.3 feet ,what is the approximate volume of the cube?Express your answer using an approximate level of accuracy.

Answers

Answer:

18.711

Step-by-step explanation:

Volume = L * W * H

V = 1.08 * 5.25 * 3.3

1.08 * 5.25 = 5.67

5.67 * 3.3 =

V = 18.711

Erik drew the diagram below of his irregularly shaped garden.
What is the area of Erik's garden? Show all work.

Answers

answer:

238 ft

explanation:

area of rhombus base×hight (14×12) = 168

find area of triangle 1/2(10)(14)=70

total area 168+70=238 ft.

Which represents a measure of volume?
O 5 cm
O 5 square cm
05 cm
05 cm

Answers

Answer:

5 cm³

Step-by-step explanation:

The correct options to the given question will be:

5 cm³ 5 square cm 5 cm 5 cm²

The volume of a solid is referred to as the space that the figure occupies. The three dimensions are covered and recorded to measure the volume. It is measured by multiplying the length, breadth, and the height of the solid. Since three units are multiplies, therefore the unit of the volume becomes a cubic unit. Usually, the volume is measured in cubic meter or cubic centimetre.

the area of an equilateral triangle of side 8cm is
pls i need answer ASAP
I'll mark brainliest for anyone who can help me​

Answers

Side=a=8cm

[tex]\\ \sf\longmapsto Area=\dfrac{\sqrt{3}}{4}a^2[/tex]

[tex]\\ \sf\longmapsto Area=\dfrac{\sqrt{3}}{4}(8)^2[/tex]

[tex]\\ \sf\longmapsto Area=\dfrac{64\sqrt{3}}{4}[/tex]

[tex]\\ \sf\longmapsto Area=16\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto Area=16\times 1.732[/tex]

[tex]\\ \sf\longmapsto Area=27.7cm^2[/tex]

HaLP a beggar in need

Answers

Answer:

C) 2

Step-by-step explanation:

From the point (2,0), the next point on the graph is up 2, right 1, meaning that the slope is a positive 2.

The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged, the risk of heart problems is increased. A paper described a study in which the left atrial size was measured for a large number of children ages 5 to 15 years. Based on this data, the authors conclude that for healthy children, left atrial diameter was approximately normally distributed with a mean of 26.5 mm and a standard deviation of 4.8 mm.

Required:
a. Approximately what proportion of healthy children has left atrial diameters less than 24 mm?
b. Approximately what proportion of healthy children has left atrial diameters greater than 32 mm?
c. Approximately what proportion of healthy children has left atrial diameters between 25 and 30 mm?
d. For healthy children, what is the value for which only about 20% have a larger left atrial diameter?

Answers

Answer:

a) P [ X < 24 mm ] = 0,3015          or     P [ X < 24 mm ] =  30,15 %

b) P [ X > 32 mm ]  = 0,1251          or        P [ X > 32 mm ]  = 12,51 %

c) P [  25 < X < 30 ] = 0,4964      or     P [  25 < X < 30 ] = 49,64 %

d) z(s) = 0,84

Step-by-step explanation:

Normal Distribution    N (  μ₀  ;   σ )   is  N ( 26,5 ; 4,8 )

a) P [ X < 24 mm ] = ( X - μ₀ ) / σ

P [ X < 24 mm ] = (24 - 26,5)/ 4,8 = - 0,5208 ≈ - 0,52

P [ X < 24 mm ] = - 0,52  

And from z-table we find area for z score

P [ X < 24 mm ] = 0,3015          or     P [ X < 24 mm ] =  30,15 %

b)P [ X > 32 mm ]  =  1  - P [ X < 32 mm ]

P [ X < 32 mm ]  = ( 32 - 26,5 ) / 4,8

P [ X < 32 mm ]  = 5,5/4,8  =  1,1458 ≈ 1,15

P [ X < 32 mm ]  = 1,15

And from z-table  we get

P [ X < 32 mm ]  = 0,8749

Then:

P [ X > 32 mm ]  =  1  -  0,8749

P [ X > 32 mm ]  = 0,1251          or        P [ X > 32 mm ]  = 12,51 %

c) P [  25 < X < 30 ] = P [ X < 30 ] - P [ X < 25 ]

P [ X < 30 ]  = 30 - 26,5 / 4,8   =  0,73

From  z-table    P [ X < 30 ]  =  0,7673

P [ X < 25 ] = 25 - 26,5 / 4,8  = - 0,3125  ≈  - 0,31

From z-table  P [ X < 25 ] =  0,2709

Then

P [  25 < X < 30 ] =  0,7673 -  0,2709

P [  25 < X < 30 ] = 0,4964      or     P [  25 < X < 30 ] = 49,64 %

d) If  20 %

z- score for 20% is from z-table

z(s) = 0,84

How many solutions does the system of equations below have y=3x+2 y-2x=4

Answers

it has one solution
(2,8)
x=2
y=8

Answer:

Only one solution.

Step-by-step explanation:

y = 3x +2

y -2x =4

y - 2x = 4

=> y = 2x +4

y = 3x + 2

y = 2x + 4

Since both equations are not the same, so the answer cannot be "infinitely many solutions".

They both intersect each other 1 point, so it cannot be "no solutions".

So the answer is "Only 1 solution".

A group of pirates captures Kevin, Lisa, Matt and Neal, and forces them to play a game. They each roll a fair 6-sided-die once. If the product of their roll is a multiple of 3, they all have to walk the plank, but otherwise they are safe. What is the probability that they survive? A)2/3 B)16/81 C)145/1296 D)65/81 E)625/1296 PLZ answer been waiting. I'll give 30 points

Answers

Answer: Option B, 16/81

Step-by-step explanation:

So we have 4 prisoners, they will roll a fair six side die and the product of the four rolls must NOT be a multiple of 3.

We know that every integer number can be "decomposed" into a product of prime numbers.

Then a number N,  that is divisible by 3, can be written as:

N = 3*k

Where k is another integer.

Here we will have a product of 4 numbers, each of them are in between 1 and 6.

Now, if only one of the prisoners rolls a 3, then the product of the rolls will always be a multiple of 3. And if one of the rolls is 6 the same will happen, because 6 = 3.2

Then the probability of surviving is when in none of the four rolls we have a 3 or a 6.

Then we must have a 1, 2, 4 or 5.

The probability of 4 outcomes out of 6, is:

P = 4/6.

But we have 4 rolls, so we have that probability four times, and the joint probability will be equal to the product of the probabiliities for each roll, then the probability of surviving is:

P = (4/6)^4 = (2/3)^4 = 16/81

Answer:

16

Step-by-step explanation:

From -13°C to 15°C.
a. -28°C
b. -2°C
C. 28°C
d. 2°C

Answers

ccccccccccccccccccccccc

Answer:

Option B

-13°c-2°c= 15°c

hope it helps

The position of an object at time t is given by s(t) = -9 - 3t. Find the instantaneous velocity at t = 8 by finding the derivative. I think its either -3 or -36

Answers

Answer:

[tex] \boxed{\sf Instantaneous \ velocity \ (v) = -3} [/tex]

Given:

Relation between position of an object at time t is given by:

s(t) = -9 - 3t

To Find:

Instantaneous velocity (v) at t = 8

Step-by-step explanation:

To find instantaneous velocity we will differentiate relation between position of an object at time t by t:

[tex] \sf \implies v = \frac{d}{dt} (s(t))[/tex]

[tex] \sf \implies v = \frac{d}{dt} ( - 9 - 3t)[/tex]

Differentiate the sum term by term and factor out constants:

[tex] \sf \implies v = \frac{d}{dt} ( - 9) - 3 (\frac{d}{dt} (t))[/tex]

The derivative of -9 is zero:

[tex] \sf \implies v = - 3( \frac{d}{dt} (t)) + 0[/tex]

Simplify the expression:

[tex] \sf \implies v = - 3( \frac{d}{dt} (t))[/tex]

The derivative of t is 1:

[tex] \sf \implies v = - 3 \times 1[/tex]

Simplify the expression:

[tex] \sf \implies v = - 3 [/tex]

(As, there is no variable after differentiating the relation between position of an object at time t by t so at time t = 8 is of no use.)

So,

Instantaneous velocity (v) at t = 8 is -3

A population of bacteria P is changing at a rate of dP/dt = 3000/1+0.25t where t is the time in days. The initial population (when t=0) is 1000. Write an equation that gives the population at any time t. Then find the population when t = 3 days.

Answers

Answer:

- At any time t, the population is:

P = 375t² + 3000t + 1000

- At time t = 3 days, the population is:

P = 13,375

Step-by-step explanation:

Given the rate of change of the population of bacteria as:

dP/dt = 3000/(1 + 0.25t)

we need to rewrite the given differential equation, and solve.

Rewriting, we have:

dP/3000 = (1 + 0.25t)dt

Integrating both sides, we have

P/3000 = t + (0.25/2)t² + C

P/3000 = t + 0.125t² + C

When t = 0, P = 1000

So,

1000/3000 = C

C = 1/3

Therefore, at any time t, the population is:

P/3000 = 0.125t² + t + 1/3

P = 375t² + 3000t + 1000

At time t = 3 days, the population is :

P = 375(3²) + 3000(3) + 1000

= 3375 + 9000 + 1000

P = 13,375

Write the degree of the following polynomials.
a⁴+a³b²+a²b²+b⁵​

Answers

Answer:

downloadable content of the year and I have a nice day ahead of

Answer:

5

Step-by-step explanation:

The highest cumulative degree of variables is the degree of the polynomial.

a⁴+a³b²+a²b²+b⁵​4, 5, 4, 5

As we see the highest degree is 5

5 pencils for 15 dollers how much for each pencil

Answers

5 pencils = 15 dollors

1 pencil = 15/5 dollors

therefore 1 pencil = 3 dollors...

Answer:

Each pencil would cost $3.00

Step-by-step explanation:

If 5 costs $15, to find the cost of one you divide 15 by 5

15 ÷ 5 = 3

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! PLEASE explain thoroughly. Chapter 9 part 1

1. How can you determine the end behaviors for a graph from the function? What are the possible behaviors?

2. How is solving a polynomial inequality different from a solving a polynomial equation? How do the solutions differ?

3. What is a composite function? How does order of the composite function play a role in solving the composition?

Answers

9514 1404 393

Explanation:

1. End behavior is the behavior of the function when the value of the independent variable gets large (or otherwise approaches the end of the domain). There are generally four kinds of end behavior:

the function approaches a constant (horizontal asymptote)the function approaches a function (slant asymptote, for example)the function oscillates between two of the above end behaviorsthe function tends toward +∞ or -∞

Of these, behavior 2 will ultimately look like one of the others.

For polynomials, the function will always approach ±∞ as the independent variable approaches ±∞. Whether the signs of the infinities agree or not depends on the even/odd degree of the polynomial, and the sign of its leading coefficient.

For exponential functions, the end behavior is a horizontal asymptote in one direction and a tending toward ±∞ in the other direction.

For trig functions sine and cosine, the end behavior is the same as the "middle" behavior: the function oscillates between two extreme values.

For rational functions (ratios of polynomials), the end behavior will depend on the difference in degree between numerator and denominator. If the degree of the denominator is greater than or equal to that of the numerator, the function will have a horizontal asymptote. If the degree of the numerator is greater, then the end behavior will asymptotically approach the quotient of the two functions—often a "slant asymptote".

__

2. A polynomial inequality written in the form f(x) ≥ 0, or f(x) > 0, will be solved by first identifying the real zeros of the function f(x), including the multiplicity of each. For positive values of x greater than the largest zero, the sign of the function will match the sign of the leading coefficient. The sign will change at each zero that has odd multiplicity, so one can work right to left to identify the sign of the function in each interval between odd-multiplicity zeros.

The value of the function will be zero at each even-multiplicity zero, but will not change sign there. Obviously, the zero at that point will not be included in the solution interval if the inequality is f(x) > 0, but will be if it is f(x) ≥ 0. Once the sign of the function is identified in each interval, the solution to the inequality becomes evident.

As a check on your work, you will notice that the sign of the function for x > max(zeros) will be the same as the sign of the function for x < min(zeros) if the function is of even degree; otherwise, the signs will be different.

The solution to a polynomial inequality is a set of intervals on the real number line. The solution to a polynomial equation is a set of points, which may be in the complex plane.

__

3. A composite function is a function of a function, or a function of a composite function. For example f(g(x)) is a composite function. The composition can be written using either of the equivalent forms ...

  [tex](f\circ g)(x)\ \Leftrightarrow\ f(g(x))[/tex]

It can be easy to confuse an improperly written composition operator with a multiplication symbol, so the form f(g(x)) is preferred when the appropriate typography is not available.

When simplifying the form of a composition, the Order of Operations applies. That is, inner parenthetical expressions are evaluated (or simplified) first. As with any function, the argument of the function is substituted wherever the independent variable appears.

For example, in computing the value f(g(2)), first the value of g(2) is determined, then that value is used as the argument of the function f. The same is true of other arguments, whether a single variable, or some complicated expression, or even another composition.

Note that the expression f(g(x)) is written as the composition shown above. The expression g(f(x)) would be written using the composition operator with g on the left of it, and f on the right of it:

  [tex](g\circ f)(x)\ \Leftrightarrow\ g(f(x))[/tex]

That is, with respect to the argument of the composition, the functions in a composition expression are right-associative. For example, ...

  for h(x)=2x+3, g(x)=x^2, f(x)=x-2 we can evaluate f(g(h(x)) as follows:

  f(g(h(x)) = f(g(2x+3) = f((2x+3)^2) = (2x+3)^2 -2

It should be obvious that g(h(f(x)) will have a different result.

  g(h(f(x)) = g(h(x-2)) = g(2(x-2)+3) = (2(x-2)+3)^2

In the expression 3x2 + y − 5, which of the following choices is the exponent in the term 3x2?

Answers

Answer:

2

Step-by-step explanation:

The term 3x² has 2 as an exponent, the correct option is C.

What are Exponents?

Exponents are the base raised by power, it is written in the superscript of a number.

The expression is  3x² +y-5

The term 3x² has 2 as an exponent.

Therefore, the correct option is C.

The missing options are

A.3x2

B. y

A 2

C. -5

D. None of these choices are correct.

To know more about Exponents

https://brainly.com/question/5497425

#SPJ2

using sets what is the intersection of a=(-2-1,0,1,7) I=(-2,-1,1,2,8)​

Answers

The answer is (-2,-1,1)

3x^2+4x-5 find the coefficient

Answers

The answer is 3 ! I hope that helped

HELLO THERE

3 and 4 is the answer

I hope I helped

solve for y then find the slope and y intercept and graph
y=4x+3

y=
b=
m=

Answers

Answer:

y = 4x+3

m =4

b =3

Step-by-step explanation:

y=4x+3

This is already solved for y

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 4x+3

m =4

b =3

The products of (2,3) and (-2,-3) is

Answers

Answer:

(-4,-9)

Step-by-step explanation:

multiply (a,b)

An opinion poll asked a random sample of adults whether they believe flu shots are ineffective in the United States. A commentator believes less than 35% of all adults believe they are ineffective. Which null and alternative hypotheses should be used to test this claim? H0: p ≠ 0.35, Ha: p 0.35

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The second option is the correct option

Step-by-step explanation:

From  the question we are told that

    The  sample  proportion is  [tex]\r p = 0.35[/tex]

The  Null Hypothesis is  [tex]H_o : \r p = 0.35[/tex]

The reason for this is that the this original claim when represented mathematically does not contain an equality sign ([tex]i.e \ it \ is \ mathematically \ represented \ as \ \r p < 0.35[/tex])  so the null hypothesis is the compliment of it ( i.e  [tex]\r p = 0.35[/tex])

The  Alternative hypothesis is  [tex]H_a : \r p < 0.35[/tex]

What is the equation of the following line? Be sure to scroll down first to see all answer options.



A.
y = - 1/2x

B.
y = 1/2x

C.
y = 2x

D.
y = -6x

E.
y = 6x

F.
y = 3x

Answers

Answer:

y=-6x

Step-by-step explanation:

Please help. I’ll mark you as brainliest if correct

Answers

Answer:

bonds: $65,000

cd's: $30,000

stocks: $20,000

Step-by-step explanation:

b + c + s = 115000

0.045b + 0.0325c + 0.082s = 5540

b = c + 35000

b = 65,000

c = 30,000

s = 20,000

Part III- Percentage Problems

1. You currently have $4,500 saved in your bank account. You have decided to use $2700.

What percentage of your savings did you use? Show all your work to justify your answer.

2. An organization raises money for students who attend Berkeley College every year.

Currently, they have raised $11,250 which represents 45% of the money they raise.

Determine the amount of money the organization will raise in total. Show all your work

to justify your answer.

Answers

The percentage of your savings that I use is 60%

This shows that the amount of money the organization will raise in total is $25,000.

1) Given

Total amount saved = $4500

Amount used = $2,700

Percentage of money used = Amount used/Total amount saved × 100%

[tex]Percentage \ of \ money \ used = \frac{2700}{4500} \times 100\\Percentage \ of \ money = \frac{27}{45} \times 100\\Percentage \ of \ money \ used = \frac{2700}{45} \\Percentage \ of \ money \ used = 60 \%[/tex]

Hence the percentage of your savings that I use is 60%

2) Let the amount of money the organization will raise in total be x

Since the 45% of the money they raise represents $11,250, hence:

[tex]45\% \ of \ x = \$11,250\\0.45x = 11,250\\x = \frac{11250}{0.45}\\ x = 25,000[/tex]

This shows that the amount of money the organization will raise in total is $25,000

Learn more on percentages here: https://brainly.com/question/18811795

giving brainliest! :)

Answers

Answer:

239=5

478=10

956=20

Step-by-step explanation:

Gianna's car can travel 478 mi with 10 gallons of gas

so, 47.8 mi with 1 gallon

by dividing 239 by 47.8 miles/gallon we get the answer 5 miles.

if we multiply 20 gallons by 47.8 mi/gallon #e get the answer 956 miles.

easy weasy

1+9+40-40+40+10x2 equals what?

Answers

Answer:

70

Step-by-step explanation:

1+9+40-40+40+10*2

----------------------- 20

10+40-40+40+20

50 (-40+40 cancels out to 0) +20

50+20= 70

(Following PEMDAS)

Multiply, add, subtract.

if you were to instead go through it left to right, you would get 120, which is incorrect.

Need help with this problem ASAP, don’t need an explanation, just an answer

Answers

Answer:

x^3-10x^2+1/9

Step-by-step explanation:

For standard form you need to put the exponents in order. So x^3 is first, followed by -10x^2, and finally 1/9. Hope this helps!

9.3.2 Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d overbar and s Subscript d. In​ general, what does mu Subscript d ​represent? Temperature (degrees Upper F )at 8 AM 98.1 98.8 97.3 97.5 97.9 Temperature (degrees Upper F )at 12 AM 98.7 99.4 97.7 97.1 98.0 Let the temperature at 8 AM be the first​ sample, and the temperature at 12 AM be the second sample. Find the values of d overbar and s Subscript d.

Answers

Answer:

[tex]\frac{}{d}[/tex] = −0.26

[tex]s_{d}[/tex] = 0.4219

Step-by-step explanation:

Given:

Sample1:  98.1  98.8  97.3  97.5  97.9

Sample2: 98.7  99.4  97.7  97.1  98.0

Sample 1           Sample 2              Difference d

98.1                        98.7                       -0.6  

98.8                       99.4                       -0.6

97.3                        97.7                       -0.4

97.5                        97.1                         0.4

97.9                        98.0                       -0.1

To find:

Find the values of [tex]\frac{}{d}[/tex] and [tex]s_{d}[/tex]

d overbar ( [tex]\frac{}{d}[/tex])  is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5

[tex]\frac{}{d}[/tex] = ∑d/n

 = (−0.6 −0.6 −0.4 +0.4 −0.1) / 5

 = −1.3 / 5

[tex]\frac{}{d}[/tex] = −0.26

s Subscript d is the sample standard deviation of the difference which is calculated as following:

[tex]s_{d}[/tex] = √∑([tex]d_{i}[/tex] - [tex]\frac{}{d}[/tex])²/ n-1

[tex]s_{d}[/tex] =

[tex](-0.6 - (-0.26))^{2} + (-0.6 - (-0.26))^{2} + (-0.4 - (-0.26))^{2} + (0.4-(-0.26))^{2} + (-0.1 - (-0.26))^{2} / 5-1[/tex]

    =  √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −  

                                                                     (−0.26))² + (−0.1 − (−0.26))² / 5−1

=  [tex]\sqrt{\frac{0.1156 + 0.1156 + 0.0196 + 0.4356 + 0.0256}{4} }[/tex]

= [tex]\sqrt{\frac{0.712}{4} }[/tex]

= [tex]\sqrt{0.178}[/tex]

= 0.4219

[tex]s_{d}[/tex] = 0.4219

Subscript d ​represent

μ[tex]_{d}[/tex] represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.

Other Questions
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