A chemist is mixing a 30% salt solution with a 15% salt solution to make 60 L of a new solution that will contain 20% salt. How much of the 30% solution
should the chemist use?

Answers

Answer 1

20 amount of 30% salt solution

How to find the salt solution percentage?

Divide the solute's gram weight by the total weight of the solution, then multiply the result by 100 to get the mass/mass percent of the solution. The amount of solute (measured in grams) per milliliter of solution is known as the mass/volume percent.

Let x be the amount of 30% salt solution

Then, 60-x = amount of 15% salt solution

Salt content of the first solution + salt content of second solution = salt content of the mixture

∴ 0.30x + 0.15(60-x) = 0.20*60

  0.30x + 9 - 0.15x = 12

             0.15x = 3

                   x = 20

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Related Questions

Calculate total of (A) current assets, (B) plant assets, and (C) stockholders' equity from these selected titles: Cash $7,500, Common Stock $30,000, Retained Earnings $51,000, Prepaid Rent $12,000, Accounts Payable $1,900, Accounts Receivable $6,000, Merchandise Inventory $19,000, Land $16,000, Building $11,000. (Enter your answers as a whole dollar amount.)

Answers

The value of the current assets is $44500.

Plants asset = $27000

Equity = $81000

How to calculate the current assets?

The value of the current asset will be:

Cash $7,500

Prepaid Rent $12,000

Accounts Receivable $6,000

Merchandise Inventory $19,000,

Current asset = $44500

Plant assets will be:

Land $16,000

Building $11,000.

Plant asset = $16000 + $11000 = $27000

Stockholders equity will be:

Common stock = $30000

Retained earnings = $51000

Equity = $81000

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1. Given segment AB with A(-3, 2) and B (5, -4). If point P lies on segment AB such that the ratio of
AP to PB is 2:6. Find the coordinates of p

Answers

The coordinates of P is ( -1 , 0.5) .

What is section formula ?

  We can get a point's coordinates using the section formula when it divides a line segment externally or internally in a certain ratio. It is a useful tool for determining the coordinates of the point that divides the line segment in a particular ratio. The midpoint of a line segment can be found using this section formula, and it can also be used to derive the midpoint formula.

Here Using the section formula, if a point P(x,y) divides the line joining the points A[tex](x_1,y_1)[/tex] and B[tex](x_2,y_2)[/tex]  in the ratio of m:n then,

=>  (x,y) = [tex](\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n} )[/tex]

Here A[tex](x_1,y_1)[/tex] =( -3,2) and  B[tex](x_2,y_2)[/tex]  = (5,-4)  and m:n = 2:6

Then,

=> ( x,y ) = [tex](\frac{2(5)+6(-3)}{2+6} ,\frac{2(-4)+6(2)}{2+6})[/tex]

=> (x,y) = [tex](\frac{10-18}{8},\frac{-8+12}{8} )[/tex]

=> (x,y) = [tex](\frac{-8}{8} ,\frac{4}{8})[/tex]

=> (x,y) = (-1,0.5)

Hence the coordinates of P is (-1 , 0.5) .

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Select the correct answer from each drop-down menu. The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is . The center of the circle is at the point , and its radius is units.

Answers

[tex]7x^2+7y^2-28x+42y-35=0 \\ \\ x^2 +y^2-4x+6y-5=0 \\ \\ x^2+y^2-4x+6y=5 \\ \\ x^2-4x+4+y^2+6y+9=18 \\ \\ \boxed{(x-2)^2+(y+3)^2=18}[/tex]

So, the center is [tex](2,-3)[/tex] and the radius is [tex]3\sqrt{2}[/tex].

what is the present value of $2525 per year, at a discount rate of 10 percent, if the first payment is received 9 years from now and the last payment is received 24 years from now?

Answers

The present value of $2525 per year, at a discount rate of 10 percent, if the first payment is received 9 years from now and the last payment is received 24 years from now is; $9215.77

What is the Present Value of Annuity?

An annuity is defined as a fixed amount of cash that is received or paid periodically over a certain period of time. This would mean that the amount in each cash flow of the annuity would be equal and occur for a specific period of time.

The formula for present value is;

PV = P[1 - (1 + r)⁻ⁿ)/r]

where;

PV is present value

P is periodic cash flow

r is interest rate

n is time

We are given the following;

Periodic cash flow (P) = $2525 /Year

Interest rate (r) = 10% /Year = 0.1

Time (n) = 16 Year (from 9 years to 24 years)

Thus;

PV = 2525[1 - (1 + 0.1)⁻¹⁶)/0.1]

PV = $19754.86

This is the present value in 9 years

Thus, the present value in 24 years which is now will be expressed by the formula;

PV = FV/(1 + i)^(t)

where;

PV is present value

FV is future value

i is interest rate

t is time

Thus;

PV = 19754.86/(1 + 0.1)^(8)

PV = $9215.77

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Which expression is equivalent to 3x – 5?

Answers

Answer:

2x – 4 – 1 + x

Step-by-step explanation:

Answer:

Step-by-step explanation:  -15

Birdseed costs ​$0.67 a pound and sunflower seeds cost ​$0.97 a pound. Angela​ Leinenbachs' pet store wishes to make a 30 pound mixture of birdseed and sunflower seeds that sells for ​$0.79 per pound. How many pounds of each type of seed should she​ use?

Answers

All the coordinates on the line represent the possible quantities in pounds which she can take to prepare the mixture.

What is Equation Modelling?

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

Given is Birdseed that costs ​$0.67 a pound and sunflower seeds that cost ​$0.97 a pound. Angela​ Leinenbachs' pet store wishes to make a 30 pound mixture of birdseed and sunflower seeds that sells for ​$0.79 per pound.

Assume that she used [x] pound and [y] pound of each type. We can write -

0.67x + 0.97y = 0.79 x 30

0.67x + 0.97y = 23.7

Plot the graph of this function. All the coordinates on the line represent the possible quantities in pounds which she can take to prepare the mixture.

Therefore, all the coordinates on the line represent the possible quantities in pounds which she can take to prepare the mixture.

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lamp post tilts
toward the Sun at a 2° angle from
the vertical and casts a 25-foot shadow.
The angle from the tip of the shadow
to the top of the lamp post is 45°.
Find the length of the lamp post.

Answers

Answer:

the lamp of post is 24 of the same

Does anybody know how to help me??

Answers

Answer:

D? I'm not sure tho so don't be mad if it's wrong

A candidate for mayor in a small town has allocated $40,000 for last-minute advertising in the days preceding the election. Two types of ads will be used: radio and television. Each radio ad costs $200 and reaches an estimated 3,000 people. Each television ad costs $500 and reaches an estimated 7,000 people. In planning the advertising campaign, the campaign manager would like to reach as many people as possible, but she has stipulated that at least 10 ads of each type must be used. Also, the number of radio ads must be at least as great as the number of television ads. How many ads of each type should be used? How many people will this reach?

Answers

To maximize the $40,000 allocated to reach the most people, using linear programming, 10 TV ads and 175 radio ads should be used

The number of people reached is 595,000

What is linear programming?

Linear programming is a method of maximizing a straight-line or linear function that consists of two or more variables such as the cost and the number of people reached.

Let R represent the number of radio ads and let T represent the number of television ads.

The constraints are;

200·R + 500·T ≤ 40,000

R ≥ 10

T ≥ 10

The maximum value function is 7,000·T + 3,000·R

R ≥ T

R - T ≥ 0

R ≥ T

The equations are therefore;

200·R ≤ 40,000 - 500·T

R ≤ (40,000 - 500·T)/200 = 200 - 2.5·T

R ≤ 200 - 2.5·T

When R = T, we have;

T = 200 - 2.5·T

3.5·T = 200

T = 200 ÷ 3.5 ≈ 57.14

The value of the maximizing function, 7,000·T + 3,000·R, at the vertices of the feasible region are therefore;

(T, R)

At (10, 10); 7,000 × 10 + 3,000 × 10 = 100,000

At (10, 175); 7,000 × 10 + 3,000 × 175 = 595000

At (57.14, 57.14); 7,000 × 57.14 + 3,000 × 57.14 = 571400

The number of adds of each type that will reach the maximum number of people is 10 television ads and 175 radio ads

The number of persons the ads reaches is 595,000

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Express the number as a ratio of integers.
0.46 = 0.46464646

Answers

Answer:

3.45

Step-by-step explanation:

this is how it is supposed to be

Write the expression ;



The quotient of seven and a number, added to ten.​

Answers

Answer: (7/x) + 10

A quotient is a result you get after dividing two numbers, for example, 10 divided by 2 is 5. 5 is the quotient because it's the result of 10/2. Hence, the quotient of seven and a number is simply (7/x), x being any number. And that value is added to 10, leaving us with the expression (7/x) + 10.


Teddy and Henry both bought a used car on the same day. Teddy's used car has
4,298 miles on it already, and he drives 426 miles per month. Henry's car has 6,129
miles on it already, and he drives 223 miles per month. After how many months will
each car have the same nulaber of miles on it?

Answers

After 9 months each car will have the same number of miles on it.

What is a linear equation?

Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here,

Let miles per month be x.

then, by a linear equation, we get

4298 + x(426) = 6129 + x(223)

203x = 1831

x = 9 months

Hence, after 9 months each car will have the same number of miles on it.

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An airplane travels 3582 kilometers against the wind in 6 hours and 4482 kilometers with the wind in the same amount of time. What is the rate of the plane in still air and what is the rate of the wind?

Answers

Answer: Let us assume speed of jet in still air =x

speed of wind =y

Jet flying against the wind

Relative speed of the jet = speed of jet in still air -speed of the wind=x-y

distance covered =3426

time =6 hours

distance = speed * time

3426=(x-y)*6

x-y =3426/6

x-y=571——(1)

Jet flying with the wind

Relative speed of the jet = speed of jet in still air +speed of the wind=x+y

distance covered =4026

time =6 hours

distance = speed * time

4026=(x+y)*6

x+y =4026/6

x+y=671———-(2)

solving 1 and 2 we get

x+y=671

x-y=571

x=621

y=50

speed of jet in the still air =x= 621 miles per hour

Step-by-step explanation:

a bag with 2/3 pounds of peanuts can make 1/8 pounds of peanut butter how many pounds of peanuts would be needed to make one pound of peanut butter for middle school

Answers

The required pounds of peanut that can make one pound of peanut butter is given as 5 1/3

How to solve for the quantity

If  2/3 pounds of peanut = 1/8 pounds of peanut butter

? quantity of peanut = one pound of peanut butter

This would be better expressed in numbers as

2/3 = 1/8

? = 1

To solve for this , we would have to cross multiply

such that we would have

2/3 = 1/8?

to get the unknown, we have to divide through by 1/8

2/3 ÷ 1/8 = unknown

2/3 x 8/1

= 16/3

= 5 1/3

Hence the required pound that would be needed to make the peanut butter is given as 5 1/3

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Simon uses 121 one-inch tiles to make his square mosaic. What is the length of one side of his mosaic?

Answers

11 inches, you just take the square root of 1213

Juan has a sandbox and wants to double the length, width and height. If the original box holds 1 cubic foot of sand, how many more feet of sand must be added to fill up the new box.

Answers

Juan must add a volume of 7 cubic feet for the enlarged sandbox.

How much sand must we add to an enlarged sandbox?

The volume occupied by the sandbox (V), in cubic feet, is represented by the volume formula for a parallelpiped:

V = w · l · h

Where:

w - Width, in feetl - Length, in feeth - Height, in feet

Juan wants to know the additional amount of sand required for the enlarged sandbox. If we know that the initial volume is equal to a cubic foot and each length is double, then we find that the resulting volume for sandbox is:

V' = (2 · w) · (2 · l) · (2 · h)

V' = 8 · (w · l · h)

V' = 8 · V

V = 8 ft³

The addition of sand is found by the following subtraction:

ΔV = V' - V

ΔV = 8 ft³ - 1 ft³

ΔV = 7 ft³

An additional volume of 7 cubic feet is needed for the sandbox.

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f(x) = x + 2
g(x) = 3x² - 5
Find (f.g)(x).
OA. (f g)(x) = 3x³ - 10
OB. (f g)(x) = 3x³ + 6x² - 5x - 10
OC. (f. g)(x) = 3x³ + 10
OD. (f g)(x) = 3x³ + 6x² + 5x + 10
SUBMIT

Answers

Answer:

It's option B, (f • g)(x) = 3x^3 + 6x^2 - 5x - 10

Step-by-step explanation:

In this problem, we are dealing with a branch of functions called composite functions. What the difference is between normal and composite functions is that we instead of defining a value for f(x), take two functions, f(x) and g(x), in the form of f and g. For instance, h(x) = g.

• Take the products of both functions.

f(x)g(x) = 3x²+5 • x-2

• Next, expand the functions. We expand by combining like terms.

= 3x^3 - 6x^2 + 5x - 10

Since the function cannot be simplified further, this leads to option B being our answer.

Hope this helps!

Describe in words where the square root of 50 minus 10 would be plotted on a number line.

Between −3 and −2, but closer to −3
Between −3 and −2, but closer to −2
Between 6 and 7, but closer to 6
Between 6 and 7, but closer to 7

Answers

The required value lies Between 6 and 7, but closer to 6. Option C is correct.

Given that,
The square root of 50 minus 10 would be plotted on a number line.

What is a number line?

A number line is defined as the number marked on the line calibrated into an equal number of units. For example -1, 0, 1, and so on.

According to the question,
= √[50-10]
= √40
= 6.32
Which is closer to 6.

Thus, the required value lies Between 6 and 7, but closer to 6. Option C is correct.

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PLEASE HELP ME ON THIS!!!!!!!!!!!!!!
A student would like to show their teacher that they have practiced long enough for the day. Which measure of center should the student give to their teacher? Explain your answer.

Answers

Answer: hours

Step-by-step explanation:

minutes would be way too many

seconds - just self explanatory

days- would be less than one

hours is the only possible solution

Using the declining-balance method, complete the table as shown (twice the straight-line rate): (Enter your answers as a whole dollar amount.)

Auto $29,000
5 years
Residual $2,000


Year Cost Accumulated
Depreciation B.O.Y Book Value B.O.Y Depreciation
Expense Accumulated
Depreciation E.O.Y Book Value E.O.Y
1 A B C D E F
2 G H I J K L
3 M N O P Q R

Answers

Using the double-declining-balance method of depreciation, the completion of the table as shown is as follows:

Year Cost   Accumulated   Book Value  Depreciation Accumulated  Book

                   Depreciation        B.O.Y         Expense      Depreciation   Value

                        B.O.Y                                                               E.O.Y       E.O.Y

1    $29,000          $0           $29,000         $11,600            $11,600   $17,400

2   $29,000    $11,600          $17,400          $6,960           $18,560  $10,440

3   $29,000   $18,560          $10,440           $4,176           $22,736   $6,264

What is the double-declining-balance method?

The double-declining-balance method is one of the depreciation methods in use, but it allocates more cost to the earlier years of the asset's life.

This depreciation method uses twice the straight-line rate, which is computed as the product of 100/estimated useful life multiplied by 2.

For each year's depreciation expense, the double rate is applied at the end of the year's balance.

For the last year, the difference between the previous year's ending balance and the residual value is taken as the depreciation expense.

Auto  = $29,000

Estimated useful life = 5 years

Residual = $2,000

Depreciable amount = $27,000 ($29,000 - $2,000)

Straight-line depreciation rate = 20% (100/5)

Double-declining depreciation rate = 40% (20% x 2)

Depreciation Expense:

1st year = $11,600 ($29,000 x 40%)

2nd year = $6,960 ($17,400 x 40%)

3rd year =  $4,176 ($10,440 x 40%)

4th year = $2,506 ($6,264  x 40%)

5th year = $1,758 ($3,758 - $2,000)

Year Cost   Accumulated   Book Value  Depreciation Accumulated  Book

                   Depreciation        B.O.Y         Expense      Depreciation   Value

                        B.O.Y                                                               E.O.Y       E.O.Y

1    $29,000          $0           $29,000         $11,600            $11,600   $17,400

2   $29,000    $11,600          $17,400          $6,960           $18,560  $10,440

3   $29,000   $18,560          $10,440           $4,176           $22,736   $6,264

4   $29,000  $22,736           $6,264          $2,506           $25,242   $3,758

5  $29,000  $25,242            $3,758           $1,758           $27,000  $2,000

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1. Classify the figure in as many ways as possible. (1 wwwwww www Orectangle; square; quadrilateral; parallelogram; Orectangle; square; parallelogram Orhombus; quadrilateral; square MI​

Answers

The figure given can be classified into; rhombus, quadrilateral, square.

The correct answer option is option c

How to classify a figure?

Quadrilateral: This is a polygon with four sides.

Rhombus: This is a parallelogram having all sides of equal length.

Rectangle: A quadrilateral having opposing sides parallel and four right angles.

Square: A polygon with four sides of equal length and four right angle.

Parallelogram: This is a convex quadrilateral in which each pair of opposite edges are parallel and of equal length.

In conclusion, the figure can be classified into quadrilateral, rhombus and square.

Complete question:

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Which expression represents the number of tiles on Wendy's kitchen floor?

Wendy lays rows of 8 tiles each to cover her kitchen floor. Use t
for the number of rows.
t−8

8×8t

8t

8+t

Answers

The expression that represents the number of tiles on Wendy's kitchen floor is B. 8 × 8t.

What is an expression?

An expression refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.

In this case, Wendy lays rows of 8 tiles each to cover her kitchen floor.

Let t = the number of rows.

Therefore, the number of tiles on Wendy's kitchen floor will be:

= 8 × 8t.

Therefore, the correct option is B.

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I’m doing my geometry homework and don’t remember the formula or way to solve the lengths of a triangle side with graph points. How do I solve both parts of #1?

Answers

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ E(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad F(\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill EF=\sqrt{(~~ 3- 2~~)^2 + (~~ 1- 3~~)^2} \\\\\\ ~\hfill EF=\sqrt{( 1)^2 + ( -2)^2} \implies \boxed{EF=\sqrt{ 5 }}[/tex]

[tex]F(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill FD=\sqrt{(~~ -1- 3~~)^2 + (~~ -1- 1~~)^2} \\\\\\ ~\hfill FD=\sqrt{( -4)^2 + ( -2)^2} \implies \boxed{FD=\sqrt{ 20 }} \\\\\\ D(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad E(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill DE=\sqrt{(~~ 2- (-1)~~)^2 + (~~ 3- (-1)~~)^2} \\\\\\ ~\hfill DE=\sqrt{( 3)^2 + (4)^2} \implies DE=\sqrt{ 25 }\implies \boxed{DE=5} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]E(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad F(\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{2}}} \implies \cfrac{ -2 }{ 1 } \implies - 2 \\\\[-0.35em] ~\dotfill[/tex]

[tex]F(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{3}}} \implies \cfrac{ -2 }{ -4 } \implies \cfrac{1 }{ 2 } \\\\[-0.35em] ~\dotfill[/tex]

[tex]D(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad E(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{(-1)}}} \implies \cfrac{3 +1}{2 +1} \implies \cfrac{4 }{ 3 }[/tex]

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answers

The correct representations of the given inequality -3(2x - 5) < 5(2 - x) include the following:

-6x + 15 < 10 - 5xAn open circle is at 5 and a bold line starts at 5 and is pointing to the right.

What is an inequality?

An inequality simply refers to a mathematical relation that can be used to compare two (2) or more numbers and variables in an algebraic equation, especially based on any of the following inequality symbols:

Greater than (>).Greater than or equal to (≥).Less than (<).Less than or equal to (≤).

For this exercise, we would evaluate and simplify the given inequality so as to enable use determine its solution as follows:

-3(2x - 5) < 5(2 - x)

Opening the bracket, we have:

-6x + 15 < 10 - 5x (correct representation)

Rearranging the algebraic equation by collecting terms, we have:

-6x + 5x < 10 - 15

-x > -5

x > 5 (correct representation)

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The scores on a psychology exam were normally distributed with a mean of 72 and a standard deviation of 6. A failing
grade on the exam was anything 2 or more standard deviations below the mean. What was the cutoff for a failing
score? Approximately what percentage of the students failed?
The cutoff for a failing score was?

Answers

Cut off for the failing score is 60.

Percentage of the student failed is 12.5%.

What is standard deviation?

The term "standard deviation" (or "SD") refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed.

What is normail distribution?

A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.

Given that,

mean = 72

standard deviation = 6

So,

(a) Cutoff score = mean-(2 x standard deviation)  [tex]=72-(2\times 6)[/tex][tex]= 72-12[/tex]  [tex]=60[/tex].

(b) In a normal distribution, 95% of students fall on both sides of mean in 2 standard deviations range. i.e., [tex]\frac{95}{2} = 47.5[/tex] of students between mean and (mean-2 x standard deviation). So, the percentage of students below 2 standard deviations from mean = 60-47.5 = 12.5%.

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Sets A, B, and C are subsets of the universal set U.
These sets are defined as follows:
U= {f, g, h, p, q, r, x, y, z}
A= {f, g, p, q}
B= {g, h, q, x, y}
C={ p, q, x, y, z}

Find (A' u B) ∩ C'.
Write your answer in roster form or as Ø.

Answers

Answer:   {g, h, r}

=====================================================

Explanation:

Unfortunately the U from "universal set" and the union symbol look almost identical.

What I'll do to avoid confusion is to let E represent the set of everything we care about, aka universal set.

E = {f, g, h, p, q, r, x, y, z}

Feel free to use other notation if it makes better sense to you.

From this set, we'll erase items that are found inside set A = {f, g, p, q}

So we go from this

E = {f, g, h, p, q, r, x, y, z}

to this

A' = {h, r, x, y, z}

Everything found in here is guaranteed to not be inside set A.

------------------------

The next step is to union set A' with set B. This is where we combine those two sets into a larger set of items. Toss out any duplicates. Each unique letter is to be listed once.

A' u B = {h, r, x, y, z}  U  {g, h, q, x, y}

A' u B = {h, r, x, y, z,        g, h, q, x, y}

A' u B = {g, h, q, r, x, y, z}

It's recommended you sort the items in a consistent fashion.

Set this result aside for now, and come back to it later.

------------------------

Go back to the set of everything, aka universal set.

E = {f, g, h, p, q, r, x, y, z}

Cross off stuff found in set C, so we guarantee to form the opposite or complement set C'

C' = set of everything NOT found in C

C' = erase "p,q,x,y,z" from set E

C' = {f, g, h, r}

------------------------

To recap we found

A' u B = {g, h, q, r, x, y, z}C' = {f, g, h, r}

Intersect those sets by looking at what they have in common. This is the overlapped region between the sets.

The three items in common are: {g, h, r}  which forms the final answer.

A company has 35% and 3% hydrogen peroxide solutions. They need an 8 L container with a 12% concentration of hydrogen peroxide. How much of the 3% hydrogen peroxide solution should they include in the container?​

Answers

Answer:

2 L

Step-by-step explanation:

If the first one is 12% then the 3% one would be 2L because of algebra

5.75 liters of 3 percent hydrogen peroxide solution are included by the company in the container.

What is the percentage?

A measurement used to determine a number's value out of 100 is the percentage.

Hydrogen peroxide solutions in various containers have concentrations of 35% and 3%.

Since the corporation wants an 8-liter container with a 12% hydrogen peroxide concentration.

Use mixture and allegation property,

35           3

       12

9       :       23

Total quantity = 23x + 9x = 32x

Since, the company wants 8 liters,

therefore, 32x = 8 ⇒ x = 1/4

3.5 percent hydrogen peroxide solution will be equal to = 23x = 23/4 = 5.75. 5.75 liters of 3 percent hydrogen peroxide solution are needed.

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12u–9u–5u+13= -5

find u

Answers

To solve this, we combine like terms. Our equation becomes:

-2u + 13 = -5

Now to subtract both sides by 13 to find that:

-2u = -18

Finally, we divide both sides by the coefficient and find that:

u = 9

The note F# has a frequency of 1,480 hertz. The note B has a frequency of 988 hertz. Find the ratio of F# to B to two decimal places. Express the answer in integer-ratio form.
answer is a fraction.

Answers

The ratio of F# to B to two decimal places is 1.50:1.

What is ratio?

A ratio is simply used to compare two things or numbers.

In this case, the note F# has a frequency of 1,480 hertz and the note B has a frequency of 988 hertz.

The ratio of F to B will be:

= 1480 / 988

= 1.50

The ratio is 1.50:1.

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Answer:

3/2

Step-by-step explanation:

help asap thanks yall so much

Answers

Answer:

a and c

Step-by-step explanation:

if you evaluate each one on either side of the equal sign you get the same number on both sides

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