A conduit of circular cross section has 7 cables all same diameter. Inside diameter of conduit is 30cm. What is the cross sectional area of the conduit not part of the 7 cables

Answer:

-1.5

Step-by-step explanation:

To work out the gradient of the line, we use this equation:

[tex] \frac{y2 - y1}{x2 - x1} [/tex]

Substituting in, we get:

[tex] \frac{5 - ( - 4)}{ - 2 - 4} [/tex]

Which simplifies to:

[tex] \frac{9}{ - 6} = \frac{3}{ - 2} = - \frac{3}{2} = - 1.5[/tex]

LHS = (1-sin² cos²)/(cos²)

= (sin² + cos² - sin² cos²)/(cos²)

= (sin/cos)² + 1 - sin²

= tan² + cos²

= RHS

A=prt

A=2000×7%×4

=560

Answer:
False
Any integers that the numbers 5, 10 , 15 but 20 can be used as a counter argument against the statement.

Step-by-step explanation:

The claim is that A⊆B which stands for that A is a SUBSET in B, or that B contains A.

The truth is that B⊆A since 5 has more possible outcomes than 20 in the number of integers.
So the list of all possible answers are r5, r10, and r15 where N⊆Z.

For example I choose r=3 and r15, 3(15)= 45. I can use the number 45 as a counter argument that the statement of A⊆B is false.

The dairy farmer would mix 1120 pounds of 75% protein supplement and 280 pounds of 50% protein ration to make 1400 pounds of a high grade 70% protein ration.

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the amount of 75% protein supplement and y represent the amount of 50% protein, hence:

x + y = 1400     (1)

Also:

0.75x + 0.5y = 0.7(1400)     (2)

Hence:

x = 1120, y = 280

The dairy farmer would mix 1120 pounds of 75% protein supplement and 280 pounds of 50% protein ration to make 1400 pounds of a high grade 70% protein ration.

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The true statements are

The function g(x) is given as:

[tex]g(x) = -12(\frac 13)^x[/tex]

Set x = 0, to determine the y-intercept

[tex]g(0) = -12(\frac 13)^0[/tex]

g(0) = -12

From the table, we y-intercept of f(x) is

f(0) = -12

This means that they have the same y-intercept

Because the functions have negative initial values, they would approach negative infinity as x approaches negative infinity

Hence, the true statements are (d) and (e)

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Answer:

  (6, 1)

Step-by-step explanation:

The formula for dividing segment AB into parts in the ratio M:N is ...

  P = (M·B +N·A)/(M+N)

Using the above formula with the given values, we have ...

  P = (3(12, 3) +2(-3, -2))/5 = (36 -6, 9 -4)/5 = (30, 5)/5

  P = (6, 1)

The point P that divides segment AB into parts in the proportion 3:2 is ...

  P = (6, 1)

Adding the difference between [tex]$\frac{9}{16}[/tex] and [tex]$\frac{5}{4}[/tex] we get [tex]$1 \frac{13}{16}[/tex].

Find the least common denominator or LCM of the two denominators:

LCM of 4 and 16 exist 16.

Subsequently, estimate the equivalent fraction of both fractional numbers with denominator 16.

For the 1st fraction, since 16 × 1 = 16,

9/16 = (9 × 1) / (16 × 1) = 9/16

For the 2nd fraction, since 4 × 4 = 16,

5/4 = (5 × 4) / (4 × 4) = 20/16

Add the two like fractions, then we get

(20/16) + (9/16) = (20 + 9)/16 = 29/16

So, [tex]$\frac{5}{4}+\frac{9}{16} =\frac{29}{16}[/tex]

In mixed form: [tex]$1 \frac{13}{16}[/tex].

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Answer:

y=-1/4x+3​ is the answer.

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Answer: 3 to the 3rd power equals 27

Step-by-step explanation: Because a exponent is the number times itself 3x3 equals 9 that's already 2 then 9x3 equals 27 so anything above is to much

Answer:

firstly,need to know domain and range

Answer:

t >= [tex]\frac{25}{3}[/tex] or 8.33333333333

Step-by-step explanation:

We need to set up an inequality where demand is less than or equal to 0. The inequality looks like this:

50 - 6t <= 0

50 <= 6t

t >= [tex]\frac{25}{3}[/tex] or 8.33333333333

The ends of the major axis is = (0, ± 13) and that of the foci is: (0,±5).

The term 'foci' is known to be the point at which there is the coming together of light or any other kinds of electromagnetic radiation, particles, etc.

It is also seen as the point from which they seems to go apart.

[tex]\frac{x^{2} }{144} + \frac{y^{2} }{169} = 1[/tex]

[tex]\frac{x^{2} }{12^{2} } + \frac{y^{2} }{13^{2} }[/tex]

Hence, major axis is = (0, ± 13)

e = [tex]\sqrt{1 -\frac{12^{2} }{13^{2} } }[/tex]

= 5/13

Foci is: (0± 13 x [tex]\frac{5}{13}[/tex])

Foci is: (0, ±5)

Therefore, The ends of the major axis is = (0, ± 13) and that of the foci is: (0,±5).

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The mass of the second object exists at 3 kg.

Let, F be the Force

a be the acceleration

m be the mass

The formula of force exists F = m [tex]*[/tex] a

Since force exists constant, then:

[tex]$m_1 = 2 kg, a_1 = 12 m/s^2[/tex] subset 1 designates the first object

[tex]$m_2 = ? , a_2 = 8m/s^2[/tex] subset 2 designates the second object

To estimate the mass of the second object

A constant force indicates [tex]$ m_1 * a = m_2 * a[/tex]

The mass of second object [tex]m_2[/tex], we get

[tex]m_1 * a = m_2 * a[/tex]

[tex]$m_2 = \frac{m_1 * a}{a}[/tex]

[tex]$=\frac{2*12}{8}[/tex]

= 24/8 = 3 kg

Therefore, the mass of the second object exists at 3kg.

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Answer:

The answer is choice C from the given alternatives.

Based on the triangle proportionality theorem, the true proportion is h/j=k/i

In the diagram that we have here, we have TU to be parallel to QR.

We have following

ST is equal to h, TQ is equal to j, SU is equal to k and UR is equal to i.

This can then be used to form the equation

ST/TQ = SU/UR

When we h/j = k/i

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The solution to the system of equations is: x = -4, y = -15.

Given the equations of a system as:

y = 3/4x - 12 --> eqn. 1

y = -4x - 31 --> eqn. 2

Substitute y = (-4x - 31) into eqn. 1 to find x:

-4x - 31 = 3/4x - 12

-4x - 3/4x = 31 - 12

-19/4x = 19

Multiply both sides by -4/19

x = 19(-4/19)

x = -4

Substitute x = -4 into eqn. 2

y = -4(-4) - 31

y = 16 - 31

y = -15

The solution is: x = -4, y = -15.

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Answer: (2, -25)

Step-by-step explanation:

The x coordinate of the vertex is [tex]x=-\frac{-4}{2(1)}=2[/tex].

When x=2, [tex]h(2)=2^2 - 4(2)-21=-25[/tex].

So, the vertex is (2, -25).

Since the multiplication between two matrices is not commutative, then [tex]\vec A\, \times\,\vec I \ne \vec I \,\times \,\vec A[/tex], regardless of the dimensions of [tex]\vec A[/tex].

In linear algebra, we define the product of two matrices as follows:

[tex]\vec C = \vec A \,\times \vec B[/tex], where [tex]\vec A \in \mathbb{R}_{m\times p}[/tex], [tex]\vec B \in \mathbb{R}_{p\times n}[/tex] and [tex]\vec C \in \mathbb{R}_{m \times n}[/tex]     (1)

Where each element of the matrix is equal to the following dot product:

[tex]c_{ij} = \left[\begin{array}{cccc}a_{i1}&a_{i2}&\ldots&a_{ip}\end{array}\right]\,\bullet\,\left[\begin{array}{ccc}b_{1j}\\b_{2j}\\\vdots\\b_{pj}\end{array}\right][/tex], where 1 ≤ i ≤ m and 1 ≤ j ≤ n.     (2)

Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not commutative because of the nature and characteristics of the definition itself, which implies operating on a row of the former matrix and a column of the latter matrix.

Such "arbitrariness" means that resulting value for [tex]c_{ij}[/tex] will be different if the order between [tex]\vec A[/tex] and [tex]\vec B[/tex] is changed and even the dimensions of [tex]\vec C[/tex] may be different. Therefore, the proposition is false.

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The probability of winning this game is 0.003

Let us name p to be the probability of winning the game.

We have the expected value to be 100

100 = probability of winning + 1-p x loss

win = 100000 - 200

We then input in the formula

100 = p*99800 +(1-p) x -200

100 = 99800p - 200 + 200p

Collect like terms

100 + 200 = 99800 + 200p

300 = 100000p

Divide through by 100000

This give the

Probability of winning =  0.003

The probability of winning the game is very low hence I would not play.

The factors that would influence the decision are:

A game has an expected value to you of ?$100. It costs ?$200 to? play, but if you win you receive? $100,000 (including your ?$200 ?bet), for a net gain of ?$99,800. What is the probability of? winning

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Answer:

The equation of the line passing through the points (3,7) and (-2,5) is y=⅖x+29/5

Step-by-step explanation:

Greetings !

[tex]first \: find \: the \: slope \: m \\ m = \frac{(Y₂-Y₁)}{(X₂-X₁)} ..substitute \: vlues \\ m = \frac{(5 - 7)}{( - 2 - 3)} = \frac{ - 2}{ - 5} = \frac{2}{5} \\ y = mx + b \: to \: find \: equation \: of \: aline \\ between \: two \: poins and \: use \: \\ one \: of \: the \: two \: points \: lets \: take( - 2.5) \\ y = mx + b \\ 5 = \frac{ - 2}{5} ( - 2) + b \\ 5 = \frac{ - 4}{5} + b \\ 5 + { - 4}^{5} = b \\ \frac{25 + 4}{5} = b \\ b = \frac{29}{5} \\ finally \: equation \: of \: the \: line \: will \: be \\ y = \frac{2}{5} x + \frac{29}{5} [/tex]

Answer:

Step-by-step explanation:

hello :

a(x) = 3x - 12 and b(x) = x-9, so

a[b(x)]=a(x-9) =3(x-9)-12

a[b(x)]=3x-9-12

a[b(x)]=3x+21

Answer:

The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides. Observe the following triangle ABC, in which we have BC2 = AB2 + AC2. Here, AB is the base, AC is the altitude (height), and BC is the hypotenuse. It is to be noted that the hypotenuse is the longest side of a right-angled triangle.

Pythagoras Theorem Equation

The Pythagoras theorem equation is expressed as, c2 = a2 + b2, where 'c' = hypotenuse of the right triangle and 'a' and 'b' are the other two legs. Hence, any triangle with one angle equal to 90 degrees produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.

Answer:

the point-slope form is:

y + 5 = -(9/11)*(x - 3)

A line that passes through a point (x₁, y₁) and has a slope m, can be written in point-slope form as:

y - y₁ = m*(x - x₁)

Here we know that the line passes through (3, -5) and (-8, 4).

Then the slope is:

[tex]m = \frac{-5 - 4}{3 - (-8)} = \frac{-9}{11}[/tex]

And we can use (3, -5) as the point (x₁, y₁), then the point-slope form is:

y + 5 = -(9/11)*(x - 3)

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The limit of

[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)=1$$[/tex].

In Mathematics, a limit exists described as a value that a function approaches the output for the provided input values. Limits exist necessary in calculus and mathematical analysis and exist utilized to determine integrals, derivatives, and continuity.

Given:

[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)$$[/tex]

Substitute the value x = 0, then we get

[tex]$=\frac{0 \cdot \cos (\theta)-\theta \cos (0)}{0-\theta}$$[/tex]

Simplify the above equation, we get

[tex]$\frac{0 \cdot \cos (\theta)-\theta \cos (0)}{0-\theta}= 1$[/tex]

Therefore, the limit of

[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)=1$$[/tex]

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Using it's concept, the standard deviation for the given data-set is of 8.22.

The mean for this problem is:

M = (17 + 26 + 28 + 9 + 30 + 29 + 6 + 21 + 23)/9 = 21

Hence the standard deviation is:

[tex]S = \sqrt{\frac{(17-21)^2 + (26-21)^2 + (28-21)^2 + \cdots + (21-21)^2 + (23-21)^2}{9}} = 8.22[/tex]

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The area of the circle with the given circumference is: 42.25π in.².

Area = πr²

Circumference = 2πr.

Given the following:

Circumference of the circle = 13π in.

Find the radius (r):

2πr = 13π

Divide both sides by 2π

2πr/2π = 13π/2π

r = 13/2

r = 6.5

Area = πr² = π(6.5²) = 42.25π in.²

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Answer:

4 ft

Step-by-step explanation:

The area of each tile is tile is 1 square ft, so the total area of the floor is 16 square ft.

Therefore, the side length is 4 ft.