A crystalline form of solid fat is Glycerides
Hope it helped :)
The South Pole has warm summers. True False
Answer:False
Explanation:
Kinda of a opinionated question, but unless you call -12 C warm then the answer is False
500.0 mL sample of a gas at 760.0 mm Hg were compressed to 200.0 mL. Find the new pressure if the temperature remains constant
Answer:
1900 mmHg.
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 500 mL
Initial pressure (P1) = 760 mmHg
Final volume (V2) = 200 mL
Final pressure (P2) =?
Temperature = constant.
Since the temperature is constant, we shall use the Boyle's law equation to obtain the new pressure as illustrated below:
P1V1 = P2V2
760 × 500 = P2 × 200
Divide both side by 200
P2 = (760 × 500) / 200
P2 = 1900 mmHg
Therefore, the new pressure is 1900 mmHg.
The energy of a photon is ________ proportional to its wavelength. The energy of a photon is ________ proportional to its frequency.
Answer: Inversely , Directly
Explanation:
The energy of a photon is inversely proportional to its wavelength and directly proportional to its frequency.
As can be seen from this equation;
E = hv = h c / ∧
Where E = Energy of a photon
v = Frequency
h = Planck Constant
c = speed of light
∧ = Wave length
Blood is maintained at a pH of 7.4 by the primary buffers in the plasma and secondary buffers in the erythrocytes. The plasma contains carbonic acid/bicarbonate as one of its primary buffers. The pK for this buffer system is 6.3. H2CO3 → H+ + HCO3-Required:What is the ratio of bicarbonate to carbonic acid in normal blood plasma?
Answer:
74.456.6.4.7.5.3.33-6.57
Explanation:
Why at night, under the mercury or sodium vapor lights in a mall parking lot, do cars seem to be peculiar colors?3
Answer:
Because these lights work with a combination of gases that emits a yellow-orange light that reacts with the paint of cars.
Explanation:
The mercury or sodium vapor lights work with a very interesting gas structure that when reacting with each other, emit yellow-orange lights that react with the color of the cars making them appear to have other colors.
When these lights are placed in parking lots, the white cars will turn orange. This is because the white paint used in cars contains particles that emit a yellow-orange spectrum. However, cars of other colors do not have these particles and therefore become black under these lights.
A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00 mL volumetric flask "B," which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 2.00 mL of the solution in volumetric flask "A" is transferred by pipet to 50.00 mL volumetric flask "B" and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask "B". How do I solve this?
Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M
Explanation:
Given that;
the Molarity of stock solution M₁ = 1.25M
The molarity os solution in volumetric flask A (M₂) = M₂
Volume of stock solution pipet out (V₁) = 5.00mL
Volume of solution in volumetric flask A V₂ = 25.00mL
using the dilution formula
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
WE SUBSTITUTE
M₂ = ( 1.25 × 5.00 ) / 25.00 mL
M₂ = 0.25 M
Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL
Molarity of solution in volumetric flask B (M₃) = M₃
Volume of solution in volumetric flask B V₃ = 50.00m L
Using dilution formula again
M₂V₂ = M₃V₃
M₃ = M₂V₂ / V₃
WE SUBSTITUTE
M₃ = ( 0.25 × 2.0) / 50.0
M₃ = 0.0100 M
Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M
The concentration of the final solution is 0.01 M.
This is a problem of serial dilution. We have to first obtain the concentration of the solution in the new flask.
C1V1 = C2 V2
C1 = concentration of stock solution = 1.25 M
V1 = volume of stock solution = 5.00 mL
C2 = concentration of solution in the new flask = ?
V2 = volume of solution in flask B in the new flask = 25.00 mL
C2 = C1V1 /V2
C2 = 1.25 M × 5.00 mL/ 25.00 mL
C2 = 0.25 M
Again we need to find the concentration when this solution is further diluted;
C1 = 0.25 M
V1 = 2.00 mL
C2 = ?
V2 = 50.00 mL
C2 = C1V1/V2
C2 = 0.25 M × 2.00 mL/50.00 mL
C2 = 0.01 M
The concentration of the final solution is 0.01 M.
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Perform the calculation, rounding your answer to the proper number of significant figures.
0.867 +3.72 + 18.0045 =
Answer:
Hey!
0.867 + 3.72 + 18.0045 = 22.5915
Explanation:
22.5915 ROUNDED TO 2 significant figures...
2 s.f = 23
(3 s.f = 22.6)
SO ROUNDING TO 2 s.f is easier and more accurate...
ANSWER = 23 (2 s.f)
HOPE THIS HELPS!!
The calculation, rounding your answer to the proper number of significant figures would be 22.60.
0.867 +3.72 + 18.0045 =22.60
What are significant figures?
In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.
As given in the problem we have to perform the calculation, by rounding the answer to the proper number of significant figures.
0.867 +3.72 + 18.0045 =22.5915
=22.59
=22.60
Thus, the calculation, rounding your answer to the proper number of significant figures would be 22.60.
To learn more about significant figures here, refer to the link;
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What happens if you rub a balloon against wool and put it against water dripping from a cup
Answer:
The water bends due to the static electricity on the balloon.
Explanation:
The static electricity you built up by rubbing it against the balloon attracts the stream of water, bending it towards the comb or balloon like magic!
Negatively charged particles called electrons jump the wool to the balloon as they rub together, the comb now has extra electrons and is negatively charged. The water features both positive and negatively charged particles and is neutral. Positive and negative charges are attracted to each other so when you move the negatively charged balloon towards the stream, it attracts the water's positively charged particles and the stream bends!
What is the order of increasing rate of eusion for the following gases, Ar, CO2, H2, N2?
A. CO2
B. Ar
C. CO2
D. N2
E. Ar
Answer:
H2 > N2 > Ar > CO2
Explanation:
Graham's law explains why some gases efuse faster than others. This is due to the difference i their molar mass. Generally; The rate of effusion of gaseous substances is inversely proportional to the square rot of its molar mass.
This means gases with low molar masses would have higher efusion rate compared to gases with higher molar masses.
So now we just need to compare the molar masses of the various gases;
Ar - 39.95
CO2 - 44.01
H2 - 2
N2 - 28.01
To obtain the order in increasing rate, we have to order the gases in decreasing molar mass. This order of increasing rate is given as;
H2 > N2 > Ar > CO2
If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then container A will have:
Answer:
Higher pressure, is the right answer.
Explanation:
The A will have a higher pressure. Since we have given the volume and temperature is same in both containers A and B. Below is the calculation for proof that shows which container has the higher pressure while keeping the volume and temperature the same.
[tex]So, \ V_A = V_B \\\frac{n_A T_A}{P_A} = \frac{n_B T_B}{P_B} \\Here, \ T_A = T_B \\P_A = \frac{n_A}{n_B} \times P_B \\\frac{n_A}{n_B} > 1 \\\frac{P_A}{P_B} > 1 \\P_A > P_B \\[/tex]
Therefore, the container “A” will have higher pressure.
Container A will have a higher pressure than container B.
According to the approximations of ideal gas conditions, the pressure of a gas is directly proportional to the number of molecules of a gas at constant temperature and volume.
Having this in mind, at constant temperature and volume, container A has more gaseous molecules than B, then container A will have a higher pressure than container B.
Missing parts;
If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then container A will have: A) Higher pressure B) Lower pressure C) A greater universal gas constant D) A smaller universal gas constant
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A mixture is made by adding 50.0 mL of 0.20 M NaOH(aq) to 50.0 mL of water. At 25.0 °C, what is its pH?
Answer:
13
Explanation:
From the dilution formula;
C1V1 = C2V2
C1= concentration of the stock solution = 0.2 M
V1 = volume of the stock solution = 50.0 ml
C2= concentration of the diluted solution= the unknown
V2= volume of diluted solution= 100 ml
C2= C1V1/V2
C2= 0.2 × 50/100
C2= 0.1 M
But
pOH= -log[OH^-]
But [OH^-] = 0.1 M
pOH= -log [0.1]
pOH= 1
Since;
pH +pOH = 14
pH= 14 - pOH
pH= 14- 1
pH= 13
How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant figures.
Answer:
1.8 × 10² s
Explanation:
Let's consider the reduction that occurs upon the electroplating of copper.
Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)
We will establish the following relationships:
1 g = 1,000 mgThe molar mass of Cu is 63.55 g/molWhen 1 mole of Cu is deposited, 2 moles of electrons circulate.The charge of 1 mole of electrons is 96,486 C (Faraday's constant).1 A = 1 C/sThe time that it would take for 336 mg of copper to be plated at a current of 5.6 A is:
[tex]336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s[/tex]
The reaction N O space plus thin space O subscript 3 space rightwards arrow space N O subscript 2 space plus thin space O subscript 2 is first order with respect to both NO and O3. The rate constatnt is 2.20 x 107 M-1s-1. If at a given moment, the concentration of NO is 3.3 x 10-6 M and the concentration of O3 is 5.9 x 10-7 M, what is the rate of reaction at that moment
Answer:
4.3 × 10⁻⁵ M s⁻¹
Explanation:
Step 1: Given data
Rate constant (k): 2.20 × 10⁷ M⁻¹s⁻¹Concentration of NO ([NO]): 3.3 × 10⁻⁶ MConcentration of O₃ ([O₃]): 5.9 × 10⁻⁷ MFirst order with respect to both NO and O₃Step 2: Write the balanced reaction
NO + O₃ ⇒ NO₂ + O₂
Step 3: Calculate the reaction rate
The rate law is:
rate = k × [NO] × [O₃]
rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M
rate = 4.3 × 10⁻⁵ M s⁻¹
Show that the units of kinetic energy (from ½ mv2 ) and gravitational potential energy (from mgh) are the same.
Answer:
The units of both types of energy are Joule (kg × m² × s⁻²).
Explanation:
Step 1: Show the units of kinetic energy
The equation for kinetic energy is:
K = 1/2 × m × v²
where,
m: mass
v: speed
The units are:
K = 1/2 × m × v²
[K] = kg × (m/s)²
[K] = kg × m² × s⁻² = J
Step 2: Show the units of gravitational potential energy
The equation for gravitational potential energy is:
G = m × g × h
where,
m: mass
g: gravity
h: height
The units are:
G = m × g × h
[G] = kg × m/s² × m
[G] = kg × m² × s⁻² = J
Which of these names can be used to describe
this substance?
propylbutane
propane
dimethylmethane
Answer:
Dimethylmethane and propane
Explanation:
electrons are blank in an ionic bond, whereas they are blank in a polar covalent bond, and blank in a nonpolar covalent bond
Answer:
Electrons are transferred in an ionic bond, whereas they are unequally shared in a polar covalent bond, are equally blank in a nonpolar covalent bond.
Explanation:
An ionic bond involved the transfer of electron(s) from one atom to another. For instance, NaCl is formed by a transfer of one electron from sodium to chlorine.
A polar covalent bond is formed by an unequal sharing of electrons between atoms of different electro negativities. This is the case in polar HCl.
Non polar covalent bonds are formed when electrons are equally shared between two or more atoms such as in CH4.
digesting a candy bar is a physical change or chemical change? why?
Answer:
Chemical Change
Explanation:
Because it dissolves with the help of saliva , then into stomach and excreted in a different form
Answer:
Yess its a chemical change
:*
Explanation:
Is radium fluoride soluble? (RaF2)
Answer:
No it is not soluble
Explanation:
if you were to look at the solubilibity table its not there
Explain why different liquids do not reach the same height in capillary tubes of the same diameter. Please choose the best explanation. a) Different liquids have different intermolecular forces. b) The stronger the intermolecular forces within the liquid, the higher the liquid rise in the capillary tube. c) Cohesive forces stronger than adhesive forces reduce the height of the liquid in the capillary tube, whereas adhesive forces stronger than cohesive forces increase the height of the liquid. d) Polar molecules climb higher than nonpolar molecules. e) The larger the dipole moment, the higher the liquid rises. f) The height of the liquids in the capillary tubes depends on the density of the liquid.
Answer:
c) Cohesive forces stronger than adhesive forces reduce the height of the liquid in the capillary tube, whereas adhesive forces stronger than cohesive forces increase the height of the liquid.
Explanation:
Two types of forces bring about capillary action.
One is cohesion, which is the intermolecular attraction between like molecules (that is, the liquid molecules). The second force, called adhesion, is an attraction between unlike molecules, such as those in a liquid and in the sides of a glass tube.
If adhesion is stronger than cohesion, the contents of the tube will be pulled upward. This process continues until the adhesive force is balanced by the weight of the liquid in the tube.
A piece of metal with a mass of 150 g is placed in a 50 mL graduated cylinder. The water level rises from 20 mL to 45mL. What is the volume of the metal
Answer:
25 mL
Explanation:
The water level increased from 20mL to 45mL
That is the volume of the metal
45 - 20 = 25
The volume of the metal was 25 mL
Density = mass / volume
Density = 150 / 25
Density = 6 grams / mL
Which substance can be described as cations bonded together by mobile electrons?a. S8(s)b. Ag(s)c. SiO2(s)d. KCl(s)e. Kr(l)
Answer:
Ag(s)
Explanation:
Metal atoms are held together by the metallic bond. The metallic bond consists of cations held together by a sea of mobile electrons.
Thus, the crystal of Ag(s) is composed of silver ions held together by a sea of mobile electrons. Electrostatic forces of attraction holds the crystal together.
The substance describing the cations bonded by mobile electrons is Ag. Thus option B is correct.
The chemical bond with the ability to exist as a cation with mobile electrons has been a metallic bond.
The metallic bond if found to be existing of central nuclei, with the sea of electrons present outside the nucleus, and has been shared by the atoms.
With the presence of the metal or metallic bond in a compound, the cation has been bonded with the mobile electrons.
The chemical bond present in the following compounds has been:
[tex]\rm a.\;S_8\;=\;Covalent\;bond\\b.\;Ag\;=\;Metallic\;bond\\\\\rm c.\;SiO_2\;=\;\rm Covalent\;bond\\\\d.\;KCl\;=\;Ionic\;bond\\\\e.\;Kr(I)\;=\;Covalent\;bond[/tex]
The substance with the presence of metallic bond has been Ag. Thus, Ag has presence of cations bonded together by mobile electrons. Thus, option B is correct.
For more information about the cations, refer to the link:
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There is 6.83L of water in a container. Calculate the volume of water in gallons.
Answer:
1.804295
Explanation:
Hope this helps <3
A frying pan needs a Teflon coating of 1.00 mm in thickness to cover an area of 36.0 square inches. How many ounces of Teflon are needed? The density of Teflon = 0.805 g/mL
Answer:
m = 0.659 ounce
Explanation:
It is given that,
The thickness of a Teflon coating is, d = 1 mm
Area of the coating, A = 36 inch²
The density of Teflon, d = 0.805 g/mL
We need to find ounces of Teflon are needed.
Firstly, find the volume of the Teflon needed,
1 inch² = 6.4516 cm²
36 inch² = 232.258 cm²
Density,
[tex]\rho=\dfrac{m}{V}[/tex]
V is volume of the Teflon needed, V = Ad
So,
[tex]m=\rho V\\\\m=0.805\ g/cm^3\times 232.258\ cm^2 \times 0.1\ cm\\\\m=18.69\ g[/tex]
Also, 1 gram = 0.035274 ounce
18.69 gram = 0.659 ounce
So, 0.659 ounces of Teflon are needed.
Choose the best answer below. Which of the following reactions will have the largest equilibrium constant at 298 K?
a) 302(g) → 203(9) AGOrxn = +326 kJ
b) Mg(s) + N20(g) → Mgo(s) + N2(g) AG9rxn = -673.0 kJ
c) 2Hg(g) + O2(g) → 2HgO(s) AGºrx = -180.8 kJ
d) CaCO3(s) » Cao(s) + CO2(g) AG = +131.1 kJ
It is not possible to determine the reaction with the largest equilibrium constant using the given information.
Answer:
Explanation:
Relation between ΔG₀ and K ( equilibrium constant ) is as follows .
lnK = - ΔG₀ / RT
[tex]K = e^{-\frac{\triangle G_0}{RT}[/tex]
The value of R and T are same for all reactions .
So higher the value of negative ΔG₀ , higher will be the value of K .
Mg(s) + N₂0(g) → MgO(s) + N₂(g)
has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .
in chemistry when using electrical equipment, what should you look for?
ASAP! pls !
Answer:
Check if the equipment is in a good condition.
Check if it can cause any harmful hazards.
Check if the equipment is what you need for the experiment
which statment best describes the chamces that occured in the reactant in forming the alkene product
Hello. You did not enter answer options. The options are:
a. The OH group was removed from the reactante
b. The OH group was replaced by an H atom.
c. Two atoms were removed from the reactant.
d. An H atom abd a OH group have been removed drom the reactant.
In addition, you forgot to add an image that complements the question. The image is attached below.
Answer:
d. An H atom abd a OH group have been removed drom the reactant
Explanation:
As you can see in the image, the reagent is an alcohol molecule. For the transformation of the alcohol molecule into an alkene molecule, it is necessary that an intramolecular dehydration occurs, that is, it is necessary that a water molecule (two H atoms and an O atom) go out from inside the alcohol and that is exactly what happened, that is, we can say that an H atom and an OH group were removed from the reagent to form the alkene.
An experiment requires that enough SiCl2Br2 be used to yield of bromine . How much SiCl2Br2 must be weighed out?
Answer:
42.75 grams of SiCl2Br2 must be weighed out
Explanation:
Here is the complete question:
An experiment requires that enough SiCl2Br2 be used to yield 13.2g of bromine . How much SiCl2Br2 must be weighed out?
Explanation:
First, we will determine the Molar mass of SiCl2Br2,
Si = 28.08, Cl = 35.45, Br = 79.90
Molar mass of SiCl2Br2 = 28.08 + 35.45(2) + 79.90(2)
= 258.78
Hence, the molar mass of SiCl2Br2 is 258.78 g/mol
If 79.90 grams of bromine is present in 258.78 grams of SiCl2Br2
Then, 13.2 grams of bromine will be present in [tex]x[/tex] grams of SiCl2Br2
[tex]x[/tex] = (13.2× 258.78) / 79.90
[tex]x[/tex] = 42.75 grams
Hence, 42.75 grams of SiCl2Br2 must be weighed out.
Which of the following questions could be answered by a scientific experiment?
a. Which type of flower is the prettiest?
b. Which type of music is the most relaxing?
c. Which type of thermos keeps ice water cold the longest?
d. What is the best color to paint your bedroom?
the answer to it is C...
Answer:
C.
Explanation:
All other questions are opinion-based and can't have a definite answer.
Why is the oxygen end of the water molecule attracted to the sodium ion
Explanation:
oxygen has a negative charge
sodium has a positive charge
opposites attract
The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ΔH, ΔS, and ΔG for the boiling process at this temperature
The question is incomplete; the complete question is;
The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the
signs of ∆H, ∆S, and ∆G for the boiling process at this temperature.
A. ∆H > 0, ∆S > 0, ∆G < 0
B. ∆H > 0, ∆S > 0, ∆G > 0
C. ∆H > 0, ∆S < 0, ∆G < 0
D. ∆H < 0, ∆S > 0, ∆G > 0
E. ∆H < 0, ∆S < 0, ∆G > 0
Answer:
∆H > 0, ∆S > 0, ∆G < 0
Explanation:
If we look at the question carefully, we will observe that it deals with a phase change from liquid to vapour phase.
Energy is required to break the intermolecular bonds in the liquid as it changes into vapour hence the process is endothermic, ∆H>0.
Also, the entropy of the vapour phase is greater than that of the liquid phase hence there is a positive change in entropy, ∆S>0.
Lastly, the process is spontaneous, hence the change in free energy ∆G is less than zero.