A cube of Iron, 0.0800 m on a side, has a density of 7874 kg/m^3. What is its mass? a (Unit = kg) ​

Here is your Answer:-

Ohm's Law

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance, one arrives at the usual mathematical equation that describes this relationship: I=V/R, where I is the current through the conductor in units of amperes, V is the voltage measured across the conductor in units of volts, and R is the resistance of the conductor in units of ohms.

Conventional Domestic Fans.

Electric Heaters. The electric heaters are the common appliances used in winters throughout the world.

Electric Kettles and Irons. The electric kettle and irons have a lot of resistors in them.

Design of Electric Devices.

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential  is given by;

[tex]\rm V=Ed[/tex]

[tex]\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V= 10 \frac{Nm}{C} = 10 \frac{J}{C} = 10 V.[/tex]

The work is defined as the product of the potential difference and charge of an electron.

[tex]\rm W= 10 \times 1.602 x 10^{-19} \\\\\ \rm W= 1.6 x 10^{-18 }J[/tex]

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

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first part is 10 second part is 1.6

Answer:

Explanation:

Potential drop across R1, VR1

= Supply Voltage

= 24V

Well look at the diagram

We know

according to ohms law

[tex]\\ \rm\Rrightarrow \dfrac{V}{I}=R[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{V}{R}=I[/tex]

Option C is correct

ANSWER:

pascal (pa) or newton per square metre

Answer:

acceleration= Final velocity - initial velocity/time taken

or u can put the formula by their symbols

a= V-u/t

a=150m/s - 30m/s= 120

120/40s= 3s

so the answer is 3s.

Answer:

2 m/s^2

Explanation:

Use Newton's 2nd Law of motion:

F = ma

12N = (6kg)a

a = 12/6

a = 2 m/s^2

It is all about the dilation of pupils. When darkness falls, your pupils enlarge, whereas in daylight, your pupils shrink.

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The electrical field along the horizontal axis is 3.36N/C and the 8.11N/C along the vertical axis

Data;

The electrical field force is given as

[tex]E = \frac{kQ}{r^2}[/tex]

The distance apart will be

[tex]r = \sqrt{1.1^2 + 2.6^2} = 2.8m[/tex]

Let's find E1 and E2

E1 will be

[tex]E_1 = \frac{-9*10^9 * 7.5*10^-^9}{2.8^2} = -8.61N/C[/tex]

E2 will be

[tex]E_2 = \frac{-9*10^9*1.5*10^-^9}{2.8^2} = -1.72N/C[/tex]

Let's find the angle between the charges

[tex]tan\theta = \frac{2.6}{1.1} \\\theta = 67.04^0[/tex]

The value E12

[tex]E_1_2 = |E|cos\theta = 8.61(cos67.04) = 3.36N/C[/tex]

The value of E21 = 0

The value of electrical field along the horizontal axis

[tex]E_x = 3.36 N/c[/tex]

The value along the vertical axis

[tex]E_1_y = -|E_1|sin \theta = -7.93 N/C\\E_2_y = E_2 sin 90^0 = -1.72N/C\\E_y = \sqrt{7.93^2 + 1.72^2}= 8.11N/C[/tex]

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Answer: More info please

Explanation:

Sirius represented a satellite constellation operated by the Nordic Satellite AB (NSAB). It was used by Nordic countries.

Sirius was a satellite constellation operated by the SES SIRIUS AB (or former Nordic Satellite AB) created by Sweden and Norway governments.

Sirius constellation provided the Nordic countries with different types of communications outcomes (for example, for tv issues).

This satellite constellation composed of Sirius satellites was the only one to operate in the Tundra orbit (5.0° East, geostationary orbit).

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The frictional force between two bodies depends mainly on three factors: (I) the adhesion between body surfaces

(ii) roughness of the surface

(iii) deformation of bodies.

<3

Answer:

The answer would be Increase becaause the springs constantmotion is increasing.

Explanation:

Answer:

The gases which are very good at absorbing long wave photons of infrared gas.

Explanation:

KE = 1/2 mv²

v = 10 km/h = 2.78 m/s

v = 20 km/h = 5.56 m/s

10 = 1/2 m . 2.78²

m = 2.59 kg

KE = 1/2 x 2.59 x 5.56²

KE = 40.03 J

Answer:

The Force of Friction!

Explanation:

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Answer:

According to our present theory of solar system formation, why were solid planetesimals able to grow larger in the outer solar system than in the inner solar system? Because only metal and rock could condense in the inner solar system, while ice also condensed in the outer solar system.

Explanation:

Answer:

e. V

Explanation:

Electric potential is the amount of work needed to move a unit charge from a reference point to a specific point against an electric field.

In the SI, the units are Volts denoted by the letter V, in honor of Alessandro Volta

Option E is the correct answer

The National Grid network is made of high-voltage power lines, gas pipelines, interconnectors, and storage facilities that together enable the distribution of electricity. The grid ensures that all areas of Said country have power/gas/oil products. this also allows more efficient power generators like nuclear plants to contribute more to the power grid than just where they are located.

Answer:

brain cells that are in your brain

Explanation:

it has something to do with brain cells

Answer:

the cart will have an acceleration of 1,25 m.s‐²

Answer:

positive gradient

Negative gradient

Explanation:

An object's acceleration describes its change in speed. If the speed of an object increases with time, its graph will have a positive gradient. If an object slows down, its graph will have a Negative gradient.

A straight line sloping upward to the right represents a positive gradient while a straight line sloping downward to the right represents negative gradient.

An object's acceleration describes its change in speed. If the speed of an object increases with time, its graph will have a positive gradient. If an object slows down, its graph will have a negative gradient.

An object's acceleration describes its change in speed.

If the speed of an object increases with time, its graph will have a positive gradient.

If an object slows down, its graph will have a negative gradient.

The gradient of a graph is the slope of the line. In the case of a speed-time graph, the gradient of the graph represents the acceleration of the object. If the gradient of the graph is positive, the object is accelerating. If the gradient of the graph is negative, the object is decelerating.

When an object's speed increases, the graph of its speed-time will have a positive gradient. This is because the object is getting faster over time, which means that its acceleration is positive.

When an object's speed decreases, the graph of its speed-time will have a negative gradient. This is because the object is getting slower over time, which means that its acceleration is negative.

Hence, An object's acceleration describes its change in speed. If the speed of an object increases with time, its graph will have a positive gradient. If an object slows down, its graph will have a negative gradient.

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#SPJ3

Answer:

B

Explanation:

Here .

B is denoted to asthenosphere

Answer:

9m/s^2

Explanation:

a= dv/dt, 90m/s-0m/s/10s-0s=9m/s^2

Explanation:

This is the formula for the change in distance (δx) of an object moving with constant acceleration (a) and initial velocity (v), one of the standard Equations of motion. To solve for t first rearrange

12at2+vt−δx=0

then apply the formula for solving a Quadratic equation if our equation is At2+Bt+C=0 then the solution is

t=−B±B2−4AC√2A,

here A=12a, B=v, C=−δx so plugging these in the formula gives

t=−v±✓v2−4(12a)(−δx)√2(12a) (Apply quandriatic equation)

simplifying

t=−v±v2+2aδx√a.

Note how there are two possible solutions one corresponding to the + and one to the -. Sometimes one of these will give a negative time, so you may want to eliminate that. Indeed if δx>0, v>0 and a>0 we only want the positive solution. In other cases you may want to consider both solutions, for instance if we thow a ball up in the air the initial velocity is positive and the acceleration is negative, it will pass a fixed height above your head twice, once on the way up and once on the way down.

Answer:

it is inertia

Explanation:

Answer:

Newton's first law: the law of inertia

Explanation:

Answer:

The rocket would appear more blue than it actually is.

Explanation:

Assume that the rocket was initially at a distance of [tex]d[/tex] away from the Earth. Let [tex]c[/tex] denote the speed of light. It would take a time of [tex](d / c)[/tex] before the first crest of the light (an electromagnetic wave) from the rocket arrive at the Earth.

If [tex]T[/tex] denote the period of this EM wave. The next crest of this wave would leave the rocket at a time of exactly [tex]T\![/tex] after the previous crest.

Let [tex]v[/tex] denote the speed at which the rocket travels toward the Earth. In that time period of [tex]T[/tex], the rocket would have moved towards the earth by [tex]v\, T[/tex]. Thus, the next crest of this wave would need to cover a distance of only [tex](d - v\, T)[/tex] (as opposed to [tex]d[/tex], the distance required for the first crest) before reaching the Earth. Thus, this subsequent crest would need to travel for a distance of only [tex](d - v\, T) / c[/tex] before reaching the earth.

Let [tex]t = 0[/tex] refers to the time when the first crest of the light from the rocket leaves the rocket. The next crest would leave the rocket at time [tex]t = T[/tex].

Thus, it would appear to an observer on the earth that the period of the light from the rocket was:

[tex]\begin{aligned}& \left(T + \frac{d - v\, T}{c}\right) - \left(\frac{d}{c}\right) \\ =\; & T - \frac{v\, T}{c}\end{aligned}[/tex].

In other words, observers on the Earth would find the period of this wave shorter than it actually is at the rocket ([tex]T - (v\, T) / c[/tex] as opposed to [tex]T[/tex].)

The frequency of a wave is inversely proportional to the period of that wave. Thus, observers on the Earth would find the frequency of the wave from the rocket higher than the frequency of this wave at the rocket.

EM waves of higher frequency (higher energy) appear more blue than ones of lower frequency. Therefore, this rocket would appear more blue to observers on the Earth than it actually is.