Advanced Placement (AP) College

A family of 11 members went for a picnic at a park. There they saw a long straight bench that could
accommodate all of them so they decided to sit on it. Now, the two youngest members of the family had an
argument the previous day so they refused to sit together.
What is the probability that out of all seating arrangements that are possible, one arrangement is picked
such that the two youngest members don't sit together?

Answers

Answer 1

Probability tells us how often some event will happen after many repeated trials. This topic covers theoretical, experimental, compound probability

What is the likelihood that one seating arrangement will be chosen out of all possible seating arrangements?

Make all possible arrangements for 12/78 or 2/13, with the two youngest members being 1 and 2.

Then 1 will form a pair with 3,4,5,6,7,8,9,10,11,12,13 = 12 pairs, but 1 will not form a pair with 2 according to the question.

2 pairs = 3,4,5,6,7,8,9,10,11,12,13 = 11 pairs

Then 3 will make 4,5,6,7,8,9,10,11,12,13 = 10 pairs, not 1 and 2 as they did previously.

Then 4 becomes 5,6,7,8, and so on.

Then you make pairs with all of the numbers.

As a result, total pairs formed with 1 = 12, 2 = 11, 3 = 10, and so on until 78 pairs were formed.

12 people in total are seated together.

12/78 = 2/13

To learn more about probability  refer to:https://brainly.in/question/48506528

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