Answer:
where is the question?
1. Black Panther ran 567.6 km to the east in 23 hours then turned around and ran 221.8 km to the west in 1.2 hours. What was his average velocity during the trip in km h?p
Answer:
80.08 km/h
Explanation:
Given that Black Panther ran 567.6 km to the east in 23 hours
Velocity = distance covered/time
Substitute the distance covered and time into the formula
Velocity = 567.6/23
Velocity = 24.68 km/h
then turned around and ran 221.8 km to the west in 1.2 hours.
Velocity = 221.8/1.2
Velocity = 184.83 km/h
What was his average velocity during the trip in km/h ?
Average velocity = (V + U)/2
Since the two velocity are opposite to each other, the average velocity will be:
Average velocity = (-24.68 + 184.83)/2
Average velocity = 160.15/2
Average velocity = 80.08 km/h
Therefore, his average velocity during the trip is 80.08 km/h
A stone is thrown with an initial upward velocity of 7.0 m/s and experiences negligible air resistance. If we take upward as the positive direction, what is the velocity of the stone after 0.50 s?
Answer:
2.1 m/s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 7 m/s
Time (t) = 0.50 s
Final velocity (v) =?
Since the is thrown upward, it means that the stone is going against gravity. Thus, the value of the acceleration due to gravity will be negative i.e – 9.8 m/s²
Thus, we can obtain the velocity of the stone after 0.50 s as follow:
Initial velocity (u) = 7 m/s
Time (t) = 0.50 s
Acceleration due to gravity (g) = – 9.8 m/s²
Final velocity (v) =?
v = u + gt
v = 7 + (– 9.8 × 0.5)
v = 7 – 4.9
v = 2.1 m/s
Therefore the velocity of the stone after 0.5 s is 2.1 m/s.
A ball is held at rest and then dropped. The final velocity of the ball was 45 m/s just before it hit the ground. How high was the ball when it was dropped?How much time past before the ball hit the ground?
Answer:
a) y = 103.21 m
b) t = 4.6 s
Explanation:
a) The height at which the balls was is given by:
[tex] V_{f}^{2} = V_{0}^{2} - 2g(y_{f} - y_{0}) [/tex]
Where:
[tex]y_{f}[/tex]: is the final height = 0
[tex]y_{0}[/tex]: is the initial height =?
[tex]V_{f}[/tex]: is the final velocity = 45 m/s
[tex]V_{0}[/tex]: is the initial velocity = 0 (is held at rest
g: is the gravity = 9.81 m/s²
Hence, the height is:
[tex] y_{0} = \frac{V_{f}^{2}}{2g} = \frac{(45 m/s)^{2}}{2*9.81 m/s^{2}} = 103.21 m [/tex]
b) The time before the ball hit the ground is:
[tex] V_{f} = V_{0} - g*t [/tex]
[tex] t = -\frac{V_{f}}{g} = -\frac{- 45 m/s}{9.81 m/s^{2}} = 4.6 s [/tex]
Therefore, 4.6 seconds passed before the ball hit the ground.
I hope it helps you!
A gas is taken in a vessel which is then sealed. The gas is then heated. How will the
temperature, pressure and volume of the gas change?
Since the vessel is sealed, all of
them will remain the same.
А
B
The temperature will increase,
the pressure and volume will
remain the same.
The temperature and pressure
will increase, the volume will
remain the same.
The temperature, pressure and
volume will all increase.
D
I
Answer:
B
Explanation:
heating increases the temperature, increase in temperature increases number of collisions hence increases pressure,volume still remains because there is no addition
Heating increases the temperature, increase in temperature increases the number of collisions hence increasing pressure, volume still remains because there is no addition
The answer is option B.
Does increasing temperature increase the number of collisions?Due to the fact the frequency of collisions depends on the temperature, A is virtually now not steady. Instead, A will increase slightly with temperature as the extended kinetic energy of molecules at higher temperatures reasons them to move barely faster and for that reason go through more collisions consistent with unit time.
The extent of the fuel consequently turns large because the temperature of the fuel will increase. As the number of gas particles increases, the frequency of collisions with the partitions of the box ought to grow.
Learn more about kinetic energy here: https://brainly.com/question/25959744
#SPJ2
The recommendations state that "members of the general public should not be exposed on a continuous basis to___________ electric field strengths exceeding 5 kV/m," or to magnetic fields exceeding 0.1 mT (1 gauss or 1,000 mG).
Answer:
electric field must not exceed 5000 V / m ( 5 kV/m)
Explanation:
All electrical equipment produces electric and magnetic fields that must be within the range recommended by WHO, the upper limit for the sum of all fields is
The electric field must not exceed 5000 V / m
to get an idea of the intensity produced by one of the devices that has the largest electric field in the radio with 180 V / m
Answer
What is moment? What are the two factors which affect moment
Explanation:
moment is an expression involving the product of a distance and physical quantities.
-the size of force applied.
-the perpendicular distance from the pivot to the line of action of the force
QUESTION 5
A small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79
mL. What is the density of the frog? (You know the mass of the frog, first find the volume of the frog, then use the density formula to.
Answer:
0.69 g/cm^3
Explanation:
Given that a small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79mL.
The volume of the frog will be:
79 - 50 = 29mL
Convert it to litre by dividing it by 1000
29/1000 = 0.029 L
Since 1L = 1000 cm^3
Convert it to cm^3 by multiplying it by 1000
0.029 × 1000 = 29 cm^3
Density = mass/volume
Substitute the mass and volume into the formula
Density = 20/29
Density = 0.6896 g/cm3
Therefore, the density of the frog is 0.69 g/cm^3 approximately
Turner’s treadmill starts with a velocity of −3.0 m/s and speeds up at regular intervals during a half-hour workout.After 33 min, the treadmill has a velocity of −6.7 m/s. What is the average acceleration of the treadmill during this period? Answer in units of m/s^2
Explanation:
Acceleration is change in velocity over change in time.
a = Δv / Δt
a = (-6.8 m/s − (-3.0 m/s)) / (33 min × 60 s/min)
a = (-3.8 m/s) / (1980 s)
a = -0.0019 m/s²
Your new pet kitten is trapped in a ten foot deep hole. You need a contraption to safely rescue your poor animal. How can I solve this problem? please give me a list of ideas thank you.
what instrument will we use to find liquid volume
Answer:
Volumetric cylinders (would appreciate brainliest
Explanation:
Volumetric cylinders and volumetric flasks are used to measure volume of liquids contained in them. They are calibrated for volume included in them - this is indicated by the marking "IN". The liquid has accurate volume when it reaches the corresponding marking on the scale.
why is skipping quicker than running
Answer:
because you are taking longer and faster strides
Explanation:
Answer:
you are taking longer to skip.
Explanation:
The atmospheric pressure on a mountain is 550 mmHg and 1 atm is equal to 760 mmHg. What is the pressure in atm? Give your answer to 2 significant figures760 mmHg what is the pressure in atm?
Answer:
0.72 atm
Explanation:
Given that the atmospheric pressure on a mountain is 550 mmHg.
Where 1 atm is equal to 760 mmHg.
To Convert millimetre mercury (mmHg) into atmospheric pressure units (atm) , divide the magnitude of pressure by 760. That is,
Pressure = 550/760
Pressure = 0.724 atm
Therefore, pressure in atm is 0.72 atm in two significant figures
What does Pascal's principle state?
A. The pressure at two pistons within an enclosed fluid system is
always the same.
B. The buoyant force on an object is equal to the weight of the fluid
displaced by the object.
C. The pressure of a fluid decreases as the speed of the fluid
increases.
D. The pressure exerted by a fluid decreases as depth increases.
why is MA always less than VR?
Answer:
[tex] \boxed{ \bold{ \boxed{ \sf{see \: below}}}}[/tex]
Explanation:
MA ( Mechanical Advantage ) is always less than VR ( Velocity Ratio ) because MA is reduced by friction but VR is not affected by friction.
Hope I helped!
Best regards! :D
fastest to slowest: 5.0 m/s, -10.0 m/s, 520.0 cm/s, 18.0 cm/s ,2.0 cm/s
Given : We have given sets of speed 5.0 m/s, -10.0 m/s, 520.0 cm/s, 18.0 cm/s ,2.0 cm/s .
To Find : Order the given speed from fastest to lowest .
Solution :
First of all we have to convert all the given speed in same units .
We know , 1 m = 100 cm .
Therefore , speed in units cm/s is :
500 cm/s , -1000 cm/s , 520 cm/s , 18 cm/s , 2 cm/s .
We know , that -ve and +ve sign only indicates the direction .
So , comparing their magnitude , we get the order as :
-1000 cm/s , 520 cm/s , 500 cm/s , 18 cm/s , 2 cm/s .
Hence , this is the required solution .
0.075 L - 9 mL = _____________ L?
What is mean by physics, where the word derived from...what is mean by the word mean by science,from where it is derived from????
Answer:
The word physics originates from Greek word meaning nature physics is therefore a science dealing with the study of nature and various natural phenomenon.Physcis is the branch of science which deals with the study of matter,energy and the relationship between them.
Science is derived from the Greek word scientia which means knowledge science is defined as the knowledge gathered from observations and experimentations.
Explanation:
Hope it will help you. :)
Calcula la energía cinética de un coche de 500kg de masa que se mueve a la velocidad de 100 km/h. Pasamos la velocidad a las unidades del sistema internacional.
Responder:
192,900.64 Julios
Explicación:
La energía cinética es la energía que posee un cuerpo en virtud de su movimiento. Sea la masa del cuerpo m, su velocidad v.
Energía cinética = 1/2 mv²
Parámetros dados
masa del coche = 500 kg
velocidad = 100 km / h
La velocidad debe estar en m / s según la unidad internacional estándar. Al convertir;
100 km / h = 100 * 1000/3600 m / s
100 km / h = 27,8 m / s
velocidad del cuerpo = 27,8 m / s
Necesario
Energía cinética del coche = 1/2 * 500 * 27,8²
Energía cinética del automóvil = 1/2 * 500 * 771.6
Energía cinética del automóvil = 1/2 * 385,801.28
Energía cinética del automóvil = 192,900.64 Julios
Por lo tanto, la energía cinética del automóvil es 192,900.64 julios.
Using the same cost and time estimates, consider the time-effectiveness of each engineer.
If SciTech is most concerned about meeting a deadline regardless of the cost, which engineer should the company choose?
Camilla
John
Nora
Oracio
Answer:
Camilla
Explanation:
Answer:Camilla
Explanation:
Figure shows three blocks that are being pulled along a smooth horizontal surface. The masses of the blocks
are shown in figure and tension force in cord connecting A and B = 120 N. The pulling force Fis:
A SZONB
C С
4kg 4kg 2kg
Fu
Smooth
(C) 125 N
(A) 50 N
(B) 100 N
(D) 200 N
Answer:
The pulling force F is 200 N
Explanation:
We note that the tension in a rope between two or three blocks is given by the relation;
Where we have;
m₁ → T₁ → m₂ → T₂ → m₃ → F
[tex]T_1 = \dfrac{m_1}{m_1 + m_2 + m_3} \times F[/tex]
[tex]T_2 = \dfrac{m_1 + m_2}{m_1 + m_2 + m_3} \times F[/tex]
m₁ = 2 kg
m₂ = 4 kg
m₃ = 4 kg
T₂ = 120 N
Therefore, by substitution, gives;
2 kg → T₁ → 4 kg → 120 N → 4 kg → F
[tex]120 \ N = \dfrac{2 \ kg + 4 \ kg}{2 \ kg+ 4 \ kg+ 4 \ kg} \times F = \dfrac{6 \ kg}{10 \ kg} \times F[/tex]
F = 120 N × (10 kg)/(6 kg) = 200 N
The pulling force F = 200 N.
When the course deviation indicator (CDI) needle is centered during an omnireceiver check using a VOR test signal (VOT), the omnibearing selector (OBS) and the TO/FROM indicator should read:_______
Answer:
0° FROM or 180° TO
Explanation:
A course deviation indicator or the CDI may be defined as an avionics tool or instrument that is used in the aircraft navigation which is used to determine an aircraft's lateral position with relation to a course.
While using the VOT service, we should tune the VOT frequency of the VOR receiver. And with the CDI leveled centered, the omnibearing selector or the OBS should read as 0° with the TO/FROM indicator showing 'FROM'. Else the OBS should read as 180° with the TO/FROM indication showing 'TO.'
why does an object appear to be moving faster as it moves away from the axis of rotation
Answer:
I suppose that this is a problem of rotation with constant angular velocity.
This can be answered with arcs.
Suppose that we have a circle of radius R, and an angle A (A expressed in radians)
The length of that arc will be:
L = R*A
Now, a rotating object that rotates at a constant angular velocity, in a time t moves an angle A.
so if this object is moving in a circle of radius R, in the time t the distance traveled is the same that we found above.
L = R*A
Now, if the object moves away from the axis of rotation, we have that the radius of the circle R increases, then also does the value of L (the distance traveled in the time t)
Then, when the object moves away from the axis of rotation, in the same time t, the distance traveled will be higher, which means tath the tangential velocty increased (regardless the fact that the angular velocity is constant)
3. You are walking at a 1m/s velocity and carrying a tray with a ball at rest on the tray. You come to a brief stop and the ball rolls off the tray. What causes the ball to roll off the tray?
Help ????????????????
Answer:
Inertia.
Explanation:
You are moving with a speed of 1 m/s. You are carrying a tray and the ball is at rest in the tray. You stops and the ball rolls off the tray. Whenever you starts moving with a speed of 1 m/s and when ball is at rest, due to inertia of motion the ball comes in motion. But when you stops, the ball is still in motion due to its inertia.
Hence, due to inertia the ball roll off the tray.
613 kg - 3514 hg = ______________g?
Answer:
261600 grams
1 kilogram is equal to 10 hg or 1000 g
How can an object's motion be predicted by using a graph?
Answer:
Explanation:
For velocity
Velocity = Gradient of displacement - Time graph
That is, velocity (speed) = distance (or displacement) / time
Jake drove 160 kilometres in 2 hours. What was his speed, in kmh-1
Answer:
80 kmh
Explanation:
IDK lol i just divided it by 2 because he drove 80 kilometres in one hour
Answer:
80kmph
Explanation:
speed = d/t
d= distance
t= time
s=160/2
s=80kmph
If two conductors are not touching but are close to each other, a large enough voltage will cause an _________________ to occur between the conductors.
Answer:
Electrical breakdown.
Explanation:
When two conductors are relatively close enough, and have a very large voltage between them, it can lead to a Dielectric breakdown. A dielectric breakdown occurs when an insulator is subjected to a high enough voltage, suddenly becomes an electrical conductor and electric current flows through it. The air between the conductors is the insulator that breaks down, leading to an electrical discharge arc to flow between the two conductors. This electrical breakdown can cause catastrophic failure of electrical equipment, and fire hazards.
2500m =_____km
480cm=_______m
75mL=______L
65g=________mg
5.6kg=_______g
50cm=______m
6.3cm=________mm
Answer:
1. 2.5km
2. 4.8m
3. 0.075 litre
4. 65000mg
5. 5600g
6. 0.5m
7. 63mm
Explanation:
1. 1000m in 1 km so divide by 1000
2. 100cm in m so divide by 100
3. 1000ml in 1l so divide by 1000
4. multiply the mass value by 1000
5.multiply the mass value by 1000
6. divide the length value by 100
7. multiply the length value by 10
hope this helps
If a honeybee is flying 7.0 m/s, what is the kinetic energy (Joules) if its mass is 0.1 g?
Answer:
KINETIC ENERGY=K.E=0.00245 Joules ≈ 0.003 Joules
Explanation:
mass=m=0.1g=0.0001kg
velocity=v=7.0m/s
kinetic energy=K.E.=?
as we know that
[tex]kinetic energy=\frac{1}{2}mv^2\\ putting values\\kinetic energy=\frac{1}{2}(0.0001kg)(7.0m/s)^2\\ kinetic energy=\frac{1}{2} 0.0049joules\\kinetic energy= 0.00245Newton meter or joules[/tex]
hope it will help ^_^
An elevator has the mass of 3 tons of power needed to raise the elevator 50m in 15 s?
Answer:
Mass=3,time=15,height=50,g=10,Power=?.
Power=mgh/t.....3×10×15=1500/15=100Watts.
Answer:
[tex]\huge \boxed{\mathrm{100 \ Watts}}[/tex]
Explanation:
[tex]\sf \displaystyle P=\frac{mgh }{t} \\\\\\ P=power \ (W) \\\\ m=mass \ (kg) \\\\ g=gravity \ acceleration \ (m/s^2) \\\\ h=height \ (m) \\\\ t=time \ taken \ (s)[/tex]
[tex]\sf \displaystyle P=\frac{3 \times 10 \times 50 }{15}[/tex]
[tex]\sf \displaystyle P=\frac{1500 }{15}[/tex]
[tex]\sf \displaystyle P=100[/tex]