Wavelength of 685 nmnm and the frequency of the light 0.43765322
What is the frequency of the light ?Light has a wavelength of 685 nm, which can alternatively be written as 685 x 10-9 m. Wavelength: [=]
We are aware that light travels at a speed of 299 792 458 m/s, or around 3 x 108 m/s. [light speed equals c]
We may use the following formula to determine the frequency (f) given the two values:
f = c / ʎ
replacing the specified values:
f = (685 x 10-9 m) / (3 x 108 m / s)
f = 0.43765322
The frequency of the light 0.43765322
The range of the frequency of visible light is roughly 400 to 700 THz. A Terahertz, or THz, is a frequency measurement equal to one trillion Hertz. the range of electromagnetic fields. f = (463 x 10-9 m) / (3 x 108 m / s)to learn more about frequency of the light refer to:
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An 800-kg car traveling in a straight line at a speed of 30 m/s applies its brakes. During braking, there is a net force of 2000 N in the horizontal direction on the car. What distance will the car move from the time it applies its brakes until it has stopped?
a.12
b.75
c.180
d.300
e.60000
Answer:
Explanation:
c = 180
i have same problem and it work
Two vehicles r moving in the same direction one has the velocity of 24m/s and another has 18m/s.find their relative velocity & also their relative velocity when they are in opposite direction
When a body is moving in the same direction, its relative speed is 6m/s, while when it is moving in the opposite direction, it is 42 m/s.
Describe relative velocity and its unit.The units used to measure speed and velocity are the same. The meter is the SI unit for measuring both distance and displacement. The second is the second as defined by the International System of Units. Two meters per second divided by two is the SI unit of velocity and speed.
What does Class 11 formula for relative velocity mean?It is calculable using an intermediary reference frame. The velocity vector sum can be used to represent this simply. vAB = vA - vB is the way to express the relative velocity formula.
velocity is the same as the relative velocities of A and B.
A=24,B=18
Vab=24-18=6m/s
In opposite direction
Vab=24-(-18)=42m/s
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Which is an outer planet in our solar system?
A.Earth
B.Jupiter
C.Mars
D.Venus
Question:
Which is an outer planet in our solar system?
Answer:
B. Jupiter
Answer: Jupiter
Explanation: As its situated outside the asteroid belt
which one of the following statements is true concerning a magnifying glass? group of answer choices the object must be placed outside the focal point of the lens. it produces an inverted image. it produces a virtual image. the image distance will be less than the object distance. it can be made from a diverging lens.
The statements is true concerning a magnifying glass is it produces a virtual image.
A virtual image is what exactly?A divergent lens or a convex mirror are used to create a virtual image. Finding a virtual image involves tracking actual rays that leave an optical tool back to their observed or apparent sources. A virtual image cannot be projected onto a screen because the rays never truly converge.
The mirror reflection is the best illustration of a virtual image. Real images are made when rays connect, but virtual images are made when rays diverge. On a screen, real images can be projected but virtual ones cannot. Two opposing lenses, concave and convex, are used to create real images.
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1.8-kg copper block is given an initial speed of 3.1 m/s on a rough horizontal surface. because of friction, the block finally comes to rest. (a) if the block absorbs 85% of its initial kinetic energy as internal energy, calculate its increase in temperature.
Therefore, U equal to cV T represents the change in internal energy for an ideal gas, where cV stands for specific heat (at constant volume) and T for change in temperature.
Calculate its increase in temperature ?Increase in temperature is 0.0176 degree Celsius. b. the remaining energy will be lost.
The mass of copper block = 1.8kg
Initial speed = 3.1 m/s
Specific heat of copper = 0.385 j/g degree Celcius.
a. The increase in temperature is calculated below:
Change i kenetic energy = 1/2mv²
= 1/2 *1.8*4²= 14.4J
85% of energy is converted into internal energy.
mc =14.4*0.85
1.8*385 = 14.4*0.85
12.24/693
=0.0176
The remaining 15 per cent of kinetic energy will be lost and it will be changed into other forms.
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Two asteroids each have mass of 1.41 x 1014 kg. The strength of the gravitation force between them is 1,030 N.
Calculate the distance between the asteroids.
The distance between the two asteroids, given that the gravitation force between them is 1030 N, is 3.59×10⁷ m
How do I determine the distance?From Newton's law of universal gravity, we understood that the force of attraction / repulsion between two objects is given as:
F = GM₁M₂ / r²
Where
F is the force of attraction / repulsionG is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartWith the above formula, we can determine the distance between the two asteroids. This is illustrated below:
Mass of 1st asteroid (M₁) = 1.41×10¹⁴ KgMass of 2nd asteroid (M₂) = 1.41×10¹⁴ KgGravitational force (F) = 1030 NGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Distance between the asteroids (r) = ?F = GM₁M₂ / r²
1030 = (6.67×10¯¹¹ × 1.41×10¹⁴ × 1.41×10¹⁴) / r²
Cross multiply
1030 × r² = 6.67×10¯¹¹ × 1.41×10¹⁴ × 1.41×10¹⁴
Divide both sides by 1030
r² = (6.67×10¯¹¹ × 1.41×10¹⁴ × 1.41×10¹⁴) / 1030
Take the square root of both sides
r = √[(6.67×10¯¹¹ × 1.41×10¹⁴ × 1.41×10¹⁴) / 1030]
r = 3.59×10⁷ m
Thus, the distance between them is 3.59×10⁷ m
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what is the difference of chinese and korean music
The music performed on the Chinese instrument was typically fast-paced, technically impeccable, and pitched high. The Korean instrument, however, is normally performed in a low range and with less emphasis.
What's the name of that instrument from China?Chinese musical instrument known as the pipa has four strings and is classified as a plucked instrument. The instrument, which is sometimes referred to as the "Chinese lute," features a peculiar pear-shaped wooden body and 12 to 26 frets.
What is the most popular instrument in China?According to Shanghai Chinese Orchestra director Luo Xiaoci, the guzheng is now regarded as the most well-liked traditional Chinese musical instrument and is comparable to the piano for Western music. A flexible instrument with a wide variety of tones is the guzheng.
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find the moment of inertia of a point of mass of 0.005g at a perpendicular distance of 3m from its axis of rotation.
Answer:
Explanation:
Given:
m = 0.005 g = 5·10⁻⁶ kg
R = 3 m
__________
J - ?
J = m·R² = 5·10⁻⁶·3² ≈ 45·10⁻⁶ kg·m²
Answer:
The snapshot of idleness of given point mass still up in the air by,
Where,
- snapshot of idleness
- mass = 0.005 g = ( 0.005/1000 ) = 5 × 10⁻⁶ kg
- opposite distance = 3 m
Put the qualities in the equation,
Hence; the snapshot of idleness of given point mass is 4.5 × 10⁻⁵ kgm².
To find out about snapshot of idleness,
Explanation:
Snapshots of dormancy can be found by adding or coordinating over each 'piece of mass' that makes up an article, increased by the square of the distance of each 'piece of mass' to the hub. In vital structure the snapshot of latency is I=∫r2dm I = ∫ r 2 d m .
For a planar item, the snapshot of idleness about a hub opposite to the plane is the amount of the snapshots of dormancy of two opposite tomahawks through a similar point in the plane of the article. The utility of this hypothesis goes past that of computing snapshots of rigorously planar items.
Picture result for track down the snapshot of idleness of a mark of mass of 0.005g at an opposite distance of 3m from its hub of revolution.
What is snapshot of inactivity of an empty circle about a hub going through its middle ? Arrangement : 'I = (2)/(3) MR^(2)', where 'M' is the mass and 'R' is sweep of the empty circle.
The oxidation of copper(I) oxide, Cu 2 O ( s ) , to copper(II) oxide, CuO ( s ) , is an exothermic process. 2 Cu 2 O ( s ) + O 2 ( g ) ⟶ 4 CuO ( s ) The change in enthalpy upon reaction of 98. 93 g Cu 2 O ( s ) is − 100. 9 kJ. Calculate the work, w , and energy change, Δ U rxn , when 98. 93 g Cu 2 O ( s ) is oxidized at a constant pressure of 1. 00 bar and a constant temperature of 25 ∘ C. Note that Δ E rxn is sometimes used as the symbol for energy change instead of Δ U rxn
Copper II oxide is created through the oxidation of copper I oxide, cu2os cu2os. Cuo s An exothermic reaction is Cuo S. The formula is 2cu2o s)+ o2 G 4cuo S.
A simple definition of oxidation is what?Cu2O(s), a copper(I) oxide, is oxidized to copper(II) oxide, CuO, by exothermic processes (s). Cu2O(s), a copper(I) oxide, is oxidized to copper(II) oxide, CuO, by exothermic processes (s).
An oxidation reaction is a chemical process that takes place when an object comes into contact with oxygen or another oxidizing agent (OK-sih-DAY-shun). Oxidation is characterized by the brown hue of sliced apples and rust. In the past, the term "oxidation" was used to describe any chemical reaction that involved oxygen and an element. When magnesium metal and oxygen react, magnesium oxide is produced as a result, which serves as an illustration of this.
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the graph below shows the position vs. time for a 932 kg cart moving along a horizontal track. To the nearest tenth of a kilojoule, what is the car's kinetic energy at 8.0 seconds?
Answer:use 1/2 x M x V^2
Explanation:
to calculate the kinetic energy, observe the velocity from the graph at 8.0 seconds. and use the formula!
what is a strength of a magnetic field for a current loop with 5 a current and diameter of 1.0 m from an electric wire?
0.80tesla is a strength of a magnetic field.
how strong is the magnetic field, exactly?At a distance r from the wire, a current I flowing through a long, straight wire generates a magnetic field with intensity H=I/2r. In other words, the field's strength is inversely proportional to the distance from the wire.
How is field strength determined?Newtons per coulomb (N/C) or volts per meter (V/m) are the SI units for measuring electric field strength. E = F/q, where F is the force felt by a very small test charge q placed in a field E in a vacuum, gives the force felt by the charge.
given,
I = 5A , r = 1.0m
H=I/2πr
H = 5 / 2*3.14*1.0
H = 0.80tesla
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A 1.80-kg block is suspended from a spring with a spring constant of 220.0 N/m. A 0.060-kg bullet is fired into the block from directly below with a speed of 270.0 m/s and is embedded in the block. (A) Find the amplitude of the subsequent motion. (B) What fraction of the original kinetic energy of the bullet appears as mechanical energy in the system of block-spring-bullet?
The fraction of the original kinetic energy of the bullet appears as mechanical energy in the system of block-spring-bullet is 0.72 m.
Amplitude=0.72 m
KE of system=0.5*(1.8+0.06)*8.7^2=70.39 j
Conservation of momentum
0.06*270=(1.8+0.06)*v
v=8.7 m/s
conservation energy
0.5*(1.8+0.06)*8.7^2=0.5*220*x^2+(1.8+0.06)*9.81*x
x=0.72 m
Amplitude=0.72 m
Original KE of bullet = 0.5*0.06*270^2=2187j
KE of system = 0.5*(1.8+0.06)*8.7^2=70.39 j
Amplitude in physics is stated to be the maximum displacement or distance that is moved by a factor on a body that is vibrating or wave measured from its equilibrium role.
As the pendulum swings through its equilibrium point (straight down), it swings to a maximum distance away from the center.
The amplitude of a wave is related to the amount of energy it includes. An excessive amplitude wave consists of a massive amount of power; a low amplitude wave consists of a small quantity of strength. Amplitude and intensity are associated, but not equal.
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a model airplane with mass 0.750 kg is tethered to the ground by a wire so that it flies in a horizontal circle 30.0 m in radius. the airplane engine provides a net thrust of 0.800 n perpendicular to the tethering wire. (a) find the torque the net thrust produces about the center of the circle. (b) find the angular acceleration of the airplane. (c) find the translational acceleration of the airplane tangent to its flight path.
The force on the section of the wall of the airplane is 3N.
The pressure outside the cabin of the commercial airplane is 0.150 atm and the pressure inside the airplane cabin is 0.900 atm.
The dimensions of the section of wall of the airplane are 2.00 m × 2.00m.
The area of the section = 4.00 m².
We know,
Force applied on the portion = pressure applied on that area × area
So, the force on the section of the wall of airplane will be,
Force = (0.900-0.150)×4
Force = 3N.
So, the force on the airplane is 3 Newtons.
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A caterpillar tries to climb straight up a wall two meters high, but for every 2 cm up it climbs, it slides down 1 cm. Eventually, it reaches the top. When it reaches the top, it does not pull itself over so it will slide down 1 cm. At this point, the caterpillar was exhausted and fell to the ground. What is the total displacement?
In the first box, select the total displacement. In the second box, indicate the direction whether up, down or n/a.
It is to be noted that the total displacement is 0cm. Note that displacement is different from distance traveled.
What is displacement in Physics?Displacement is described as the total change in an object's location as well as the direction of motion.
The formula is given as:
Displacement = Final position – initial position = change in position.
Given that the caterpillar falls back to the ground, it means that the total displacement is zero.
Final Position = 0
Initial position = 0
Displacement, thus = 0-0 =0
When distinguishing between displacement and distance, we know that distance is the total length of the path between any two places.
Displacement is defined as the direct length between any two places measured via the shortest path between them.
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a 3 kg block starts from rest at the top of a 30 degree incline and slides a distance of 2 m down the incline in 1.50 seconds. find the magnitude of the acceleration of the block. find the coefficient of kinetic friction between the block and the ramp.
The magnitude of the acceleration of the block is 1.78m/s².
The coefficient of kinetic friction between the block and the ramp is 0.368.
How can I calculate the coefficient of kinetic friction?The resistive force of friction (Fr), which pushes the objects together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.
Given,
m=3.00kg, θ=30° ,
x= 2.00m, t=1.50s.
constant rate of acceleration,
[tex]X_{f} = v_{i} t[/tex] + 1/2at²
solving,
a = 2([tex]X_{f}[/tex]-[tex]v_{i} t[/tex])/t²
a = 2(2-0)/(1.5)²
a = 1.78m/s².
We have neither a burrowing-in nor a taking-off action when Newton's law is applied in the y direction, which is perpendicular to the inclination. The y component of acceleration is then equal to zero:
∑ [tex]F_{y}[/tex]=n–mgcosθ=0
Thus n=mgcosθ
Because f=[tex]\mu_{k}[/tex]n
[tex]\mu_{k}[/tex] = f/mgcosθ
[tex]\mu_{k}[/tex] = 9.37/3×9.8×cos30°
[tex]\mu_{k}[/tex] = 0.368.
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The driver of a car going 90.0 km/h suddenly sees the lights of a barrier 35.0 m ahead. it takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2. what is the maximum speed at which the car could be moving and not hit the barrier 35.0 m ahead? assume that the acceleration doesn't change.
The maximum speed at which the car could be moving will be 20 m/s.
Speed is the ration of total distance travelled by an object to the total time taken by the object to cover that particular distance.
Mathematically, Speed (v) = [tex]\frac{Distance (d)}{Time (t)}[/tex]
d = v*t
d = distance traveled
v = initial speed
t = time = 0.75v
d1 = 0.75(t)
Total distance = d1 + d2 = 35m
35 = 0.75v + d2
d1=35-0.75v
According to the Equations of motion.
[tex]v^{2} = s^{2} - 2sd1[/tex]
[tex]v = \sqrt{s^{2} - 2ad1 }[/tex]
where
s = final speed = 0m/s
v = Initial speed
a = acceleration = -10m/s2
d1 = displacement
[tex]v = \sqrt{0 - 2(-10)(35-0.75v) }[/tex]
[tex]v^{2} = 700 - 15v[/tex]
[tex]v^{2} + 15v -700 = 0[/tex]
On solving the above quadratic equation we get two values of v as:
v1 = 20 m/s
v2 = -35m/s
Since the velocity of the car has to be taken and also the car is moving in the forward direction, therefore v1 will be considered as the final velocity of the car, i.e. the maximum speed at which the car could be moving and not hit the barrier 35.0 m ahead will be 20 m/s.
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Point l is located a distance d2–√ from the midpoint between the two wires. Find the magnitude of the net magnetic field bl created at point l by both wires.
the magnitude of the magnetic field bl created at point l by both wires. is 0.0071 μI / d
since we know the formula we can refer to the magnetic field is
B= μI / 2πR
where I is the current flowing through the wires, R is the distance
Here Using the Pythagoras theorem
R= √d² + (2d)²
R = √d² + 4d²
r = √5d²
r = d√5
substituting the value of R in the formula, we get
= μI / 2π(d√5)
= μI / 2dπ√5
= (1 / 2π√5)(Iμ/d)
=0.0071 μI / d
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in this problem, you will use lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. you will need to use the right-hand rule to find the direction of the induced current. the switch on the electromagnet, initially open, is closed. what is the direction of the induced current in the wire loop (as seen from the left)?
The magnetic fuse dropped and the field's magnetic direction remained the same when the switch was reopened in this case. following which the loop's current flows in a clockwise direction.
iron filings on paper placed above a bar magnet to represent the direction of magnetic direction. Compass needles point in the direction of the surrounding magnetic field, away from the north pole of a magnetic direction towards its south pole. The movement of electrical charge carriers like electrons is known as current. Positive and negative locations both experience current flow. The ampere is the SI unit for calculating electrical current (A). The movement of electrical charge carriers like electrons is known as current. Positive and negative locations both experience current flow. The ampere (A) is the SI unit used to measure electric current.
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A golf ball is thrown straight up in the air at a velocity of 8.3 . Determine the maximum height of the golf ball.
(b) How long will it take the ball to reach its maximum height?
(c) How long will it take the ball to fall from its maximum height to the height from which it was initially launched?
a) The maximum height is 3.5 m
b) The time taken to reach this height is 0.85 seconds
c) The time taken to return to the original point is 0.85 seconds.
What is the maximum height?We know that the maximum height can be obtained from the use of the kinematic equations. We know that;
a) v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = maximum height attained
v= 0 /ms at the maximum height
u^2 = 2gh
h = u^2/2g
h = (8.3)^2/2 * 9.8
h = 68.89/10.6
h = 3.5 m
b) Time taken to reach the maximum height;
v = u - gt
v= 0 /ms at the maximum height
u = gt
t = u/g
t = 8.3/9.8
t = 0.85 seconds
c) The time taken to return is the same as the time taken to go up which is 0.85 seconds.
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the magnitude of kf depends on the identity of the [ select ] and the magnitude of kb depends on the identity of the
magnitude of kf and the magnitude of kb depends upon the identity of solvent
what is kf and kb?Kf is the depression in freezing point produced by 1 molal solution of a nonvolatile solute while Kb is the elevation in boiling point produced by 1 molal solution of a nonvolatile solute.
Boiling point elevation is the difference in temperature between the boiling point of the pure solvent and that of the solution.
Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution.
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suppose you have a planet with the same average density as the earth, but half the radius. how would the acceleration due to gravity on an object near the surface of that planet compare to our g (the acceleration due to gravity on an object near the surface of the earth)?
It would be half of (1/2) acceleration due to gravity on an object near the surface of that planet compare to our g.
Gravity on the planet (g') = [tex]\frac{GM}{R'^{2} }[/tex] = G(ρx [tex]\frac{4}{3}[/tex][tex]\pi[/tex][tex]R^{3}[/tex])/[tex]R'^{2}[/tex]
Where R' is the radius of the planet.
g' = [tex]\frac{4}{3}[/tex][tex]\frac{\pi GPR'}{1}[/tex]
gravity on the Earth (g) = G[tex]M_{E}[/tex]/RE
= G([tex]\frac{P 4/3\pi R_{E} ^{3} }{R_{E^{2} } }[/tex])
g = 4/3 [tex]\pi[/tex]GP[tex]R_{E}[/tex]
Now, g'/g = R'/[tex]R_{E}[/tex] = [tex]R_{E} 2[/tex]/[tex]R_{E}[/tex] = 1/2
g' = 1/2
it would be half of g.
What is acceleration?Acceleration is defined as the rate of change of velocity with respect to time. Acceleration is a vector quantity because it has both magnitude and direction. It is also the second derivative of position with respect to time or the first derivative of velocity with respect to time. The SI unit of acceleration is as [tex]m/s^2[/tex].
An object is said to accelerate when its velocity changes. A change in the speed of an object can be an increase or decrease in speed or a change in direction of motion. Some examples of acceleration are a falling apple, the moon orbiting the Earth, or a car stopping at a traffic light.
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a merry-go-round with a radius of 1.5 m is spinning at 2.0 rad/s when a young girl pushes on it for 5.0 revolutions applying an acceleration of 3.0 rad/s2. what is the final angular velocity of the merry-go-round?
The final angular velocity of the merry-go-round is 8 rad/s.
The radius of the Merry-go-round is 1.5 m and it is spinning with a speed of 2rad/s the girl pushes on it for 5 revolutions which applies and acceleration of 3rad/s².
The final angular velocity of the merry-go-round can be given by the equation,
W'² - W² = 2AS
Where,
W' is the final angular velocity,
W is the initial angular velocity,
A is the angular acceleration,
S is the angular displacement which is 10 rad in this case.
Putting values,
W'² - (2)² = 2(10)(3)
W' = 8rad/s.
So, the final angular velocity is 8rad/s.
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a heavy brass ball is used to make a pendulum with a period of 5.5 s. part a how long is the cable that connects the pendulum ball to the ceiling? how long is the cable that connects the pendulum ball to the ceiling? 4.7 m 6.2 m 7.5 m 8.7 m request answer provide feedback
The length of the cable that connects the pendulum ball to the ceiling with a period of 5.5 s is 7.5 m
T = 2 π √ ( L / g )
T = Time period
L = Length of the pendulum
g = Acceleration due to gravity
T = 5.5 s
g = 9.8 m / s²
5.5 = 2 * 3.14 √ ( L / 9.8 )
√ L = 0.88 * √ 9.8
L = 0.77 * 9.8
L = 7.5 m
A simple pendulum consists of a mass suspended in air by a massless and unstretchable string that is fixed to a rigid support on the other end. The time taken to complete on oscillation is the time period of a simple pendulum.
Therefore, the length of the cable is 7.5 m
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Describe the motion of a hockey puck between the instant the puck leaves a player's stick and the instant it hits something. (No "slap shot" allowed, the puck must remain in contact with the ice.)
Answer:
Explanation:
it will have constant friction, or slowing, as it slides along the ice.
What the relationship between frequency and wavelength of electromagnetic radiation? choose. If you double the wavelength of light, what happens to the energy of the photons? choose. Which has a greater energy, long wavelength red light or short wavelength uv light? choose.
Frequency is inversely proportional to the wavelength of electromagnetic radiation.
When the wavelength of light is doubled, the frequency is reduced to its original value.
Short wavelength UV (ultraviolet) light will have more energy.
What is meant by wavelength?The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal propagated in space or along a wire is defined as the wavelength.
The relationship between frequency of electromagnetic radiation and wavelength of radiation is:
ν==1/λ
Where,
ν= frequency
As a result, the frequency of electromagnetic radiation is inversely proportional to its wavelength.
The frequency is reduced to its original value when the wavelength of light is doubled.
The energy of a photon is proportional to the frequency of light.
Using Relationship,
E=hν=h c/λ
h = Planck's constant
c = speed of light
Both h and c are constants
As a result, energy will be reduced to its initial value.
The light with the shortest wavelength will have the greatest energy.
UV (ultraviolet) light with a shorter wavelength has more energy.
It is because of the previously stated relationship..
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an ultrashort pulse has a duration of 7.20 fs and produces light at a wavelength of 556 nm. what is the momentum of a single photon in the pulse?
The momentum of a single photon in the pulse is 1.19 * 10^-27 kg m/s.
It is the quantity of motion of a moving body, measured as a product of its mass and velocity.
How to calculate the momentum of a single photon in the pulse?
Wavelength of light is given,
λ = 556nm = 556 * 10^-9m
Wavelength and momentum (p) are related by
λ = h/p
Where h is the planck constant = 6.63 * 10^-34 m^2 kg/s
So, the momentum is
p = h/λ
[tex]\frac{6.63*10^{-34} }{ 556*10^{-9}}[/tex]
p = 1.19 * 10^-27 kg m/s
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A 3000 W oven is cooking your Sunday roast for 1 hour and
35 minutes. How much did it cost to cook it?
Cost estimated is ₹[19/4]y/-.
Given :- Power=3kW , Time=1hr 35min
Now to convert this time completely into hours following steps can be adopted:- 1 min =1/60 hour, so 35min =35/60 hour
35min= 35/60 =7/12 hour
So total computed time = 1hr + [7/12]hr
computed time =19/12hr
Now since in the question there is no mention about cost , so let the cost be ₹y/unit.
Mathematically , Energy is the product of power and time , i.e.
E= Power x Computed time = 3 x 19/12 = 19/4 units.
Now the energy estimated is 19/4 units whose cost equivalent will be ₹[19/4]y/- , as cost of one unit energy is ₹y/- so cost of 19/4 energy units will be ₹[19/4]y/-.
Once the cost of one unit energy is known to us then just its value in the place of y and we will get the exact amount expended on the total energy consumption.
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What do you think happens to a sound wave when the volume of sound increase
Answer:
sound wave's amplitude relates to the change in pressure caused by the wave measured at a specific location. The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases.
the hydrogen in a star emits light at 484 nm as observed by an astronomer. which describes the motion of the star if the laboratory value of this spectral line of hydrogen is measured at 486 nm? question 9 options: approaching at 6.17 105 m/s moving away at 6.17 105 m/s approaching at 1.23 106 m/s moving away at 1.23 106 m/s
If the laboratory value of this hydrogen spectral line is detected at 486 nm, the star is moving toward us at a speed of 6.17 105 m/s.
How might Bohr's theory explain the hydrogen spectrum?In less than a year, Niels Bohr had a hydrogen atom model that "explained" the spectral lines. The energy level was a novel idea that Bohr introduced. Sharp spectral lines were released when an electron in hydrogen moved from one of its permitted energy levels, which were defined by the hydrogen atom.The wavelengths, measured from the scale, are 435 nm (purple), 486 nm (blue), and 657 nm (red).Hydrogen has numerous different energy levels while having just one electron. A photon is released when an electron in an object jumps from one energy level to another. Due to the various levels, those photons produce light with various colors and wavelengths.To learn more about Hydrogen atom model refer to:
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you are in a rocket ship in deep space, far away from any gravity. you decide to do an experiment to determine the mass of your rocket ship. initially your ship is traveling to the right at 800 m/s, then the engines begin to exert 300,000 n of constant force to the left and do so for 40 seconds. afterward, your rocket ship is traveling to the left at 200 m/s. what is the mass of your rocket ship?
The mass of the rocket travelling in the space is 20000 kg.
The initial velocity of the rocket is 800m/s.
The final velocity of the rocket is 200m/s.
The time for which the constant force of 300000 Newton is applied is 40 second.
We know that if the force is constant than the acceleration must be constant and for the constant acceleration we can use the equation of motion,
V = U + at
Where,
V is the final velocity,
Uis the initial velocity,
a is the acceleration,
t is the time period.
Putting values,
800 = 200 + a40
600 = 40a
a = 15m/s².
The acceleration of the rocket is 15m/s².
The force on an accelerated bodies given by,
F = Ma
M is the mass of the rocket,
Putting values,
300000 = M(15)
M = 20000 Kg.
So, the mass of the rocket is 20000 kg.
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