It will take the lightbulb 2875 seconds to use 2.3×10⁵J of energy.
Why does power matter?Power is the amount of work completed in a given amount of time, or time spent working. The joules per second (J/s)-based SI unit of power is the Watt (W).
Given,
Power (P) = 80 J/s
Energy (E) = 2.3×10⁵ J
Time (t) = ?
The pace at which energy is utilized is a straightforward definition of power. Power can be mathematically stated as:
Energy x time equals power
P = E/t
We can calculate the time it takes for the bulb to use 2.3 105 J using the formula above. This is attainable as follows:
Power (P) = 80 J/s
Energy (E) = 2.3×10⁵ J
Time (t) = ?
Power = Energy / time
P = E/t
80 = 2.3×10⁵ /t
80 × t = 2.3×10⁵
Divide both side by 80
t = 2.3×10⁵ / 80
t = 2875 s
As a result, it will take the lightbulb 2875 seconds to use 2.3×10⁵J of energy.
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Complete question is "A light bulb consumes energy at a rate of 80joules per second . How long in seconds will it take for the light bulb to consume 2.3×10⁵in energy?".
a 39-kg crate rests on a horizontal floor, and a 68-kg person is standing on the crate. (a) determine the magnitude of the normal force that the floor exerts on the crate. n (b) determine the magnitude of the normal force that the crate exerts on the person.
The floor normally presses down on the carton with a force of 1049.67N.
The box normally applies 667.08 N of force to the person.
What do you mean by normal reaction force?A perpendicular force that acts on two surfaces that are touching. It stands in for the pressure pressing the two surfaces together. With the size of the usual response force, the value of limiting friction grows. If the weight is the only vertical force acting on an object that is lying or moving on a horizontal surface, While acting in the opposite direction from the weight, the normal response force is of identical size. Raising the weight results in increased friction.
Given,
The crate's mass, mp=68kg, is maintained on a horizontal floor.
mc=39kg is the mass of the guy standing above the crate.
(a) determine the normal force the floor applies to the crate:
N =(mc+mp)g
N =(39kg+68kg)×9.81m/s²
N = 1049.67kg⋅m/s² [tex]\frac{1N}{1Kg.m/s^{2} }[/tex]
N = 1049.67N
∴ The floor normally presses down on the carton with a force of 1049.67N.
(b) determine the typical force the crate would apply to the person:
N = mp g
N = 68kg×9.81m/s²
N = 667.08m/s² [tex]\frac{1N}{1Kg.m/s^{2} }[/tex]
N = 667.08 N
∴ The box normally exerts 667.08 N of force on the person.
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How is it that a piece of wool can become positively charged in some situations and negatively charged in other situation?
The wool becomes positively charged because it gives up electrons to the rubber rod whereas wool is rubbed against a Nylon strip so the wool will steal electrons from the Nylon and form a negative charge.
What is the charge that occurs on wool?When the woolen cloth is stroke against the plastic, both wood and plastic get electrified due to friction built while rubbing. So, plastic has greater electron affinity (ability to attract electrons) in a contrast to wool, therefore, plastic acquires a negative charge and wool obtains a positive charge. When you rub a balloon with a cloth made of wool, the balloon captures electrons from the wool, leaving the balloon with a negative charge and the wool with a positive charge. If both balloons are pat with wool, they will both have the same charge (negative) and therefore will repel each other.
So we can conclude that Wool is a conductive material, which means it readily gives away its electrons. accordingly, when you rub a balloon on wool.
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if the intensity of a sound increases from 1 bel (10 db) to 3 bel (30 db), what is the increase in energy per square meter?
The increase in energy is 100times.
Does distance affect the loudness of a sound?The square of the distance from the source of the sound wave determines the inverse proportionality of sound intensity. The strength of a sound wave reduces with increasing distance from the source because sound waves transmit their energy via a two-dimensional or three-dimensional medium.
A sound wave's amplitude determines its intensity, and its frequency corresponds to its rate of vibration.
Acoustic intensity, also referred to as sound intensity, is the amount of energy carried by sound waves per unit of area in a direction perpendicular to that area. The SI unit for intensity, which also includes sound intensity, is the watt per square meter (W/m²).
Mathematically, the sound intensity level can be expressed as,
β(dB) = 10log₁₀(I/I₀)
β₂-β₁ = 10log₁₀(I/I₀)
30-10 = 10log₁₀(I/I₀)
20 = 10log₁₀(I/I₀)
I/I₀ = 10²(or) 100times.
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a 873-kg (1930-lb) dragster, starting from rest, attains a speed of 26.3 m/s (58.9 mph) in 0.59 s. find the average acceleration of the dragster during this time interval. what is the magnitude of the anverage net force on the dragster durng this time?
The average acceleration of the dragster during this time interval is 44.57 m/s² and the average net force on the dragster during this time is 38915N.
The initial speed U of the dragster is zero while the final speed V of the dragster is 26.3m/s. The director runs for a total of time t of 0.59 seconds.
According to the equation of motion,
V = U+at
Putting values,
26.3 = 0.59a
a = 44.57 m/s².
So, the acceleration of the dragster is 44.57 m/s².
The force on the director is given by,
F = ma
m mass of the dragster and a is the acceleration of the dragster.
F = 873×44.57
F = 38915N.
So, the net average force on the dragster during this time is 38915 Newton.
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other than 120 and 240 volts, what is another common voltage used inside a building? i. 208 ii. 277 iii. 480
Other than 120 and 240 volts, what is another common voltage used inside a building is 208,277and 480volts.
What is the standard input voltage?When the same signal is applied to the IN(+) and IN(-) terminals of an op-amp, it must operate satisfactorily within a range of input voltages known as the common-mode input voltage (CMVIN), which is described in the datasheet of the device. You may think of it as never applying common-mode signals to an op-amp.
The voltage shared by an electrical device's two input terminals is known as a common-mode signal. The common-mode signal on a transmission line in telecommunications is also referred to as longitudinal voltage. The signal is typically transmitted between two conductors using a differential voltage in electrical circuits.
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a cat, also of weight wa , falls asleep on top of block a. if block b is now set into downward motion, what is the magnitude of its acceleration?
The magnitude of its acceleration is a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] )
What is meant by magnitude of acceleration?The length of the vector is all there is to an acceleration's magnitude. To put it another way, writing the magnitude of acceleration indicates how quickly velocity varies. In the standard international (SI) system, the acceleration is measured in units of meters per second square.
Let T be the rope's tension, assuming it has no mass.
T =( 2[tex]W_{A}[/tex])a/g ------- 1
([tex]W_{B}[/tex]) - T = ([tex]W_{B}\\[/tex])a/g ------- 2
Add 1 and 2
[tex]W_{B}[/tex] =(a/g)( 2[tex]W_{A}[/tex]+ [tex]W_{B}[/tex])
a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] ).
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which is greater, the force of her finger on the table, or the force of the table back on her finger?
More force is exerted by the table against her finger than she exerts against the surface.
Explain about the Force?Active power is the force behind motion or change that is exerted or brought to bear. the elements of nature
The term "force" has a clear definition in science. It is quite acceptable to refer to a force of this level as a push or a pull. An object does not "have in it" or "contain" a force. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.
The newton is the SI unit of force. As they relate to force, the base units are: The symbol for the length measurement known as the meter is m. The symbol for the kilogram, a unit of mass the sign s represents the second, a unit of time.
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Which two measurements are needed in order to calculate the speed of an object in motion?.
The two measurements, which are needed in order to calculate the speed of an object in motion, be: amount of distance travelled at a particular time interval and the time interval.
What is speed?Speed is characterised as the rate at which an object's position changes in any direction.
The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity. SI unit of speed be meter/second.
The equation provides the speed formula: s = d/t
Where,
the speed in m.s^-1 is s.
The distance in m is represented by d.
The time interval in s is t.
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) a 45 kg box is pulled horizontally across the floor will a force directed horizontally to the left with a magnitude of 200.0n. (a) what is the acceleration of the box if the coefficient of kinetic friction is 0.10? (b) if the box starts from rest, how fast will it be moving at 3.0 s assuming the constant force is applied for the entire 3.0s?
The acceleration of the box is 3.4m/s² and if the box starts from rest at constant force for 3 seconds, then the speed of the box will be 10.2m/sec
The frictional force (f) = μN
where μ= coefficient of kinetic friction
N = Normal force = mg
The given value for μ = 0.10
∴ f = 0.10 × 45 × 10
f = 45 N
Hence F net = applied force - frictional force
F net = 200 - 45
F net = 155N
Thus, the acceleration of box (a) will be, F = ma
where m = mass of box =45kg
a = F /m
a = 155/45
a = 3.4 m/s²
a) Hence acceleration of the box pulled horizontally is 3.4m/s²
The speed of the box pulled, if initially the box was at rest and constant force is applied for 3 seconds,
v = u + at
v = 0 + 3.4 × 3
v = 10.2 m/s
b) Hence, the speed of the box at constant force is 10.2m/s
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What wavelength is the maximum absorbance observed in the spectrum displayed in figure 10. 11? report your answer using 3 significant figures.
The spectrum shown has a maximum absorption of 278.4 nm.
The absorbance between 400 and 650 nm is measured, often at intervals of 25 nm, to identify the wavelength of maximum absorption. To identify the wavelength of greatest absorption, the data can be analyzed or graphed.
The useful absorbance range for the majority of spectrometers and colorimeters is between 0.1 and 1. Values of absorbance more than or equal to 1.0 are excessive. Your solution is overly concentrated if the absorbance readings you are getting are 1.0 or higher.
Maximum Absorbance refers to an area with the highest absorbance level. We can infer from the graph that the absorbance is at its highest at wavelength 278.45 nm.
Therefore, maximal absorbance occurs at 278.4 nm wavelength.
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4. Predict whether a greater amount of energy will be
transferred as heat between 1 kg of water at 10 °C
and a freezer at -15 °C or between 1 kg of water at
60 °C and an oven at 65 °C.
The greater amount of energy is transferred during the first case and the difference in energies is: 84 × 10³ J
What is internal energy of a system?Internal energy refers to all energy within a particular system, including the kinetic energy of molecules and the energy stored in chemical bonds between molecules. The interaction of heat, work, and internal energy involves the transfer and conversion of energy whenever a change is made to the system.
The amount of heat (Q) gained or lost from the sample can be calculated using the formula Q = mcΔT. where m is the mass, c is the specific heat, and ΔT is the temperature change.
For the first case:
Q = mcΔT
Q = mc(T₁ - T₂)
m = 1 kg or 1000 g
c = 4.2 J g⁻¹/°C
T₁ = 10 °C
T₂ = -15 °C
Q₁ = 1000 × 4.2 × (10 -(-15))
Q₁ = 105 × 10³ J
For the second case:
Q = mcΔT
Q = mc(T₂ - T₁)
m = 1 kg or 1000 g
c = 4.2 J g⁻¹/°C
T₁ = 60 °C
T₂ = 65 °C
Q₂ = 1000 × 4.2 × (65 - 60)
Q₂ = 21 × 10³ J
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a horizontal force is applied to a glider moving along a horizontal air track bringing it to a stop in t seconds. if the same force is applied to a second glider with half the mass and four times the initial velocity, how long does it take for the glider to come to a stop?
The second glider will stop after it travels the distance of 8 times the distance of the first glider.
Let subscript 1 and 2 represent parameters related to glider 1 and glider 2.
According to the Newton's law:
F = m . a
Where:
F = force
m = mass
a = acceleration
Since both gliders received the same forces,
F₁ = F₂
m₁ . a₁ = m₂ . a₂
m₁ . a₁ = 1/2m₁ . a₂
a₂ = 2a₁
Hence, the acceleration of the 2nd glider is twice of that of the 1st glider.
Velocity formula for decelerated move
v² = u² - 2.a.s
Where:
v = final velocity
u = initial velocity
s = distance.
Since the gliders stop, v = 0
Hence,
u₁² = 2.a₁.s₁
u₂² = 2.a₂ . s₂
Substitute u₂ = 4u₁, a₂ = 2a₁
(4u₁)² = 2.(2a₁) . s₂
16 u₁² = 4 a₁ . s₂
16. (2.a₁.s₁) = 4 a₁ . s₂
s₂ = 8 s₁
Hence, the distance of glider 2 is 8 times the distance of glider 1
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you throw a ball upward with an initial speed of 4.5 m/s. when it returns to your hand 0.92 s later, it has the same speed in the downward direction (assuming air resistance can be ig- nored). what was the average acceleration vector of the ball?
The average acceleration vector of the ball is - 9.78 m/s².
When you throw a ball upward with an initial speed, it will go up until reaching its highest peak then it will go down. So the ball doing non-uniform motion. The formula for non-uniform motion including initial speed, and final speed with time is
v = u+at
u = initial speed (m/s) = 4.5 m/sv = final speed (m/s) = - 4.5 m/s (because it's going down)t = elapsed time (s) = 0.92 sa = acceleration (m/s²)v-u = at
[tex]a = \frac{v - u}{t}[/tex]
[tex]a = \frac{- 4.5 - 4.5}{0.92}[/tex]
[tex]a = \frac{- 9.0}{0.92}[/tex]
a = 9.78 m/s²
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please complete both question
this is urgent so please try and complete it as fast as possible
due today
Answer:
[tex]\textsf{a)} \quad x=\dfrac{25(7-\sqrt{13})}{3}=28.2870727\; \sf mm[/tex]
[tex]\textsf{b)} \quad V=379037.8082\; \sf mm^3[/tex]
Explanation:
[tex]\boxed{\begin{minipage}{5 cm}\underline{Volume of a rectangular prism}\\\\$V=w\:l\:h$\\\\where:\\ \phantom{ww}$\bullet$ $w$ is the width of the base. \\ \phantom{ww}$\bullet$ $l$ is the length of the base. \\ \phantom{ww}$\bullet$ $h$ is the height.\\\end{minipage}}[/tex]
Given:
l = 200 mmw = 150 mmThe dimensions of the rectangular prism in terms of x are:
Length = 200 - 2xWidth = 150 - 2xHeight = xSubstitute these values into the formula for volume to create an equation in terms of x:
[tex]\begin{aligned}\implies V&=(150-2x)(200-2x)x\\&=(30000-700x+4x^2)x\\&=4x^3-700x^2+30000x\end{aligned}[/tex]
To find the value of x that will give the maximum volume, differentiate the equation for volume.
[tex]\begin{aligned}\implies \dfrac{\text{d}V}{\text{d}x}&=3 \cdot 4x^{3-1}-2 \cdot 700x^{2-1}+30000x^{1-1}\\&=12x^2-1400x+30000\end{aligned}[/tex]
Set the derivative to zero and solve for x using the quadratic formula:
[tex]\implies x=\dfrac{-(-1400) \pm \sqrt{(-1400)^2-4(12)(30000)}}{2(12)}[/tex]
[tex]\implies x=\dfrac{1400 \pm \sqrt{520000}}{24}[/tex]
[tex]\implies x=\dfrac{1400 \pm \sqrt{40000 \cdot 13}}{24}[/tex]
[tex]\implies x=\dfrac{1400 \pm \sqrt{40000}\sqrt{13}}{24}[/tex]
[tex]\implies x=\dfrac{1400 \pm 200\sqrt{13}}{24}[/tex]
[tex]\implies x=\dfrac{175\pm 25\sqrt{13}}{3}[/tex]
[tex]\implies x=\dfrac{25(7\pm\sqrt{13})}{3}[/tex]
To determine which value of x will give the maximum volume, differentiate again:
[tex]\begin{aligned}\implies \dfrac{\text{d}^2V}{\text{d}x^2}&=2 \cdot12x^{2-1}-1400x^{1-1}+0\\&=24x-1400\end{aligned}[/tex]
Substitute both values of x into the second derivative:
[tex]x=\dfrac{25(7+\sqrt{13})}{3} \implies \dfrac{\text{d}^2V}{\text{d}x^2}=721.1102551 > 0\implies \sf minimum[/tex]
[tex]x=\dfrac{25(7-\sqrt{13})}{3} \implies \dfrac{\text{d}^2V}{\text{d}x^2}=-721.1102551 < 0\implies \sf maximum[/tex]
Therefore, the value of x which will give the maximum volume is:
[tex]x=\dfrac{25(7-\sqrt{13})}{3}=28.2870727\; \sf mm[/tex]
To find the maximum volume of the box, substitute the found value of x into the equation for volume:
[tex]\begin{aligned}\implies V_{\sf max}&=4\left(\dfrac{25(7-\sqrt{13})}{3}\right)^3-700 \left(\dfrac{25(7-\sqrt{13})}{3}\right)^2+30000 \left (\dfrac{25(7-\sqrt{13})}{3}\right)\\\\&=379037.8082\; \sf mm^3\end{aligned}[/tex]
The dimensions of the box with maximum possible volume will be:
Length = 143.4 mm (1 d.p.)Width = 93.4 mm (1 d.p.)Height = 28.3 mm (1 d.p.)Refraction of a light ray may be defined as
A. bouncing off the boundary
B. passing through the boundary
C. maintaining speed after a boundary
D. changing direction while crossing a boundary
Answer:
Explanation:
Refraction of a light ray may be defined as:
D. changing direction while crossing a boundary
question: if so, what is the star's average absolute magnitude (m) (think average luminosity) to 0.01 magnitudes? (1 point)
Mv is equal to m - 2.5 log(d/10)2. There is a minus sign in the expression because stars distant than 10 pc have Mv that is more negative than m. Make careful you provide the star's given distance in parsecs (1 pc = 3.26 ly = 206265 AU) if you use this formula.
The moon can appear to be nearly -13 magnitude bright, the moon can appear to be -6 magnitude bright, and stars can get as bright as nearly -1.5 magnitude.
The star's actual magnitude is determined by subtracting its apparent magnitude by five times the trigonometric parallax of its distance from the star.
First-magnitude stars have apparent magnitudes less than +1.50, making them the brightest stars in the night sky. In the first century B.C., Hipparchus invented the magnitude scale. He assigned first magnitude to the 20 brightest stars and sixth magnitude to the stars that are faint enough to be seen with the unaided eye.
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Can a spectrophotometer be used to measure the absorption of a particular wavelength of light that is not visible to the human eye?.
Yes, a spectrophotometer can be used to measure the absorption of a particular wavelength of light that is not visible to the human eye.
What is a spectrophotometer?A spectrophotometer is an instrument used to measure the intensity of electromagnetic radiation at different wavelengths.
Spectrophotometry is a standard biological technique used to measure light absorption or the amount of chemicals in a solution. This technique uses a light beam which passes through the sample, and each compound in the solution absorbs or transmits light over a certain wavelength.
Spectrophotometry is the quantitative analysis of electromagnetic spectra by use of a spectrophotometer; especially in order to determine the structure or quantity of a substance.
Using the spectrophotometer, absorption of light can be measured, even if we cannot observe it unaided.
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a piston has an external pressure of 11.0 atm . how much work has been done in joules if the cylinder goes from a volume of 0.160 liters to 0.570 liters? express your answer with the appropriate units.
Work done by the system is calculated to - 456.863 J, when pressure and volume change is given.
What is work done when pressure and volume change is given?For a gas, work is the product of the pressure and the volume during a volume change. Relationship between pressure and volume can be found out by Boyle's Law. As the pressure on a gas increases then the volume of the gas decreases because the gas particles are forced closer together.
W= -p ΔV
p is pressure and ΔV is volume change
Given that volume changes from 0.160 liters to 0.570 liters
ΔV = 0.570 - 0.160
= 0.41 L
Given p = 11 atm
Now, W = -11 * 0.41
As 1 atm L = 101.3 J
Hence W= -11 * 0.41 * 101.3
Work = - 456.863 J (work done by system)
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After energy conversions, you end up with the same total amount of energy as the original amount energy. Which law explains this rule?.
The law that explains after energy conversions, the total amount of energy has the same amount as the original amount of energy is the Law of conservation of energy.
The state law of conservation of energy is that energy cannot be created, the energy cannot be destroyed, and the energy can be converted from one form of energy to another form of energy. Examples like mechanical energy. Mechanical energy is the sum of potential energy and kinetic energy.
Potential energy is the kind of energy stored by an object because of its position.Kinetic energy is the kind of energy that is possessed by an object in motion.If an apple fell from a branch of a tree
The potential energy on the branch is the maximum potential energy.When it fell, the potential energy reduces and changes into kinetic energy.When the apple almost reaches the ground, the potential energy gets smaller and the kinetic energy gets bigger.Before it hit the ground the potential energy is the minimum potential energy, but the kinetic energy reaches the maximum kinetic energy. At every point in its movement, the mechanical energy is always the same amount of energy.Learn more about Law of conservation of energy here: https://brainly.com/question/24772394
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what is the radius of an object turn if the acceleration is 1.4m/s^2 and has a velocity of 5.3 m/s
Answer:
Radius 20 m.
Explanation:
Given:
aₙ = 1.4 m/s²
V = 5.3 m/s
___________
R - ?
Centripetal acceleration:
aₙ = V² / R
Radius:
R = V² / aₙ
R = 5.3² / 1.4 ≈ 20 m
distinguishing inner and outer planetsa 2 column by 2 row table. column 1 is titled planet with the following entries: a, b. column 2 is titled length of a day in hours with the following entries: 16 hours, 1,408 hours.which planet is an inner planet, and which one is an outer planet? explain your answer.
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A child whose weight is 350 N swings out
over a pool of water using a rope attached
to the branch of a tree at the edge of the
pool. The branch is 10.2 m above ground
level and the surface of the water is 1.79 m
below ground level. The child holds on to a
rope of length 7.2 m attached to the branch
and moves back until the angle between the
rope and the vertical is 12◦. When the rope is
in the vertical position, the child lets go and
drops into the pool. The acceleration due to gravity is 9.81 m/s^2
Find the speed of the child at the surface of
the water.
Answer in units of m/s.
The speed of this child from this surface would be 14.69 m / s
How to solve for the speedWe have the formula for energy conservation as:
E - potential = E - kinetic
We have the following details with which we are to solve the problem
weight of child w = 350 N
length of rope L = 7.2m
angle θ = 12 degrees
we would have the solution as
m x 9.8m/s² x (10.2 + 1.79 - 7.2 x cos 12) = 1/2 mv²
we would have to solve out the expression that we have above. Such that :
9.8m * (11.99 - 0.9781) = 1/2 mv²
107.9 m = 1/2 mv²
cancel out m
107.9 = 0.5v²
divide through by 0.5
107.9 / 0.5 = v²
215.8 = v²
v = √215.8
v = 14.69
Hence the speed of the child at the surface of the water would be given as 14.69 m / s
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Major activity injuries include
Bone breaks
Concussions
Joint Dislocations
All of the above
Explanation:
Major activity injuries include:
Bone breaksConcussionsJoint DislocationsAll of the aboveAnsver:
All of the above
what is the wavelength range in an am radio band (with frequency range 563 khz1649 khz)? answer in units of m.
Amplitude modulated (AM radio) carrier frequencies lie in the frequency range 535 to 1605 kHz. Carrier frequencies from 540 to 1600 kHz are assigned in 10 kHz increments.
So for the maximum wavelength, the speed of light divided by the minimum frequency of FM, which is 88 megahertz, is 3.41 meters. The minimum wavelength is 10 to the power of 8 meters divided by 108 megahertz. Therefore, FM wavelengths are between 2.78 meters and 3.41 meters. Since they are electromagnetic waves, they travel at the speed of light and their wavelength is given by the relationship ν = c/λ. where c is the speed of light. The wavelength of a 1,000 kHz radio wave is (2.998 × 108 m/s)/(1.000 × 106/s) = 299.8 m.
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If it took Beth 2 hours to drive her truck 60 miles, what was her average speed?
Explain, using words, the steps you took to calculate Beth's average speed.
What are some objects that have faster or slower average speeds than Beth's truck?
How much energy is needed to raise the temperature of 0, point, 20, k, g,0.20kg of cooking oil by 50, degrees if the specific heat capacity of this oil is 1800, j, slash, left bracket, k, g, degrees, c, right bracket,1800j/(kg
Answer:
See below
Explanation:
1800 j/(kg C) = x J / (.20 kg * 50 C)
solve for x J = 180 000 J
The amount of energy needed to raise the temperature of 0.20 kg of cooking oil by 50°C is 18000 J.
What is the amount of energy?The amount of energy (Q) needed to raise the temperature of a substance can be calculated using the formula:
Q = mcΔT
where Q is the amount of energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
In this case, the mass of the cooking oil is 0.20 kg, the specific heat capacity of the oil is 1800 J/(kg·°C), and the temperature needs to be raised by 50°C. Substituting these values into the formula, we get:
[tex]Q = (0.20 kg) x (1800 J/(kg·°C)) x (50°C)[/tex]
Q = 18000 J
Therefore, the amount of energy needed to raise the temperature of 0.20 kg of cooking oil by 50°C is 18000 J.
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four resistors having a value of 100 ohms each are connected in parallel. what is the total resistance of the circuit?
The total resistance of the circuit is 25 ohms.
How can the resistance of a circuit with four resistors in parallel be determined?In the same way, if three or more resistors of the same value are connected in parallel, the equivalent resistance will be equal to R/n, where R is the resistor's value and n is the total number of resistors in the arrangement.
How do you calculate a parallel resistor's total resistance?The total current flowing from the source is the sum of the currents through each of the paths. Using the following formula, you can get the overall resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... Even if one of the parallel channels breaks, current will still flow.
[tex]R_{total}[/tex] = 100/4 = 25ohms
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way?
27. What is the average acceleration of the Blue Flame speed car if its initial velocity is 1000 km/h and it
comes to a complete stop in a distance of 2.0 km?
Answer:
Explanation:
Given:
V₀ = 1 000 km/h = 1 000 000 m / 3 600 s ≈ 280 m/s
V = 0 m/s - the Blue Flame car stopped
D = 2.0 km = 2 000 m - distance
________________________________
a - ?
D = (V₀² - V²) / (2·a)
Acceleration:
a = (V₀² - V²) / (2·D)
a = (280² - 0²) / (2·2000) ≈ 20 m/s²
these stick figures are each in a hurry to catch a flight. they are both walking at a speed of 1 m/s on a walkway that has a velocity of 0.5 m/s to the west. explain which stick figure is moving more quickly relative to the ground.
The stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.
Vsg = Vsw + Vwg
Vsg = Relative velocity of stick figure wrt ground
Vsw = Relative velocity of stick figure wrt walkway
Vwg = Relative velocity of walkway wrt ground
Let the stick figure that is walking to the west be A and the stick figure that is walking to the east be B.
For A,
Vsw = - 1 m / s
Vwg = - 0.5 m / s
Vsg = - 1 - 0.5
Vsg = - 1.5 m / s
For B,
Vsw = 1 m / s
Vwg = - 0.5 m / s
Vsg = 1 - 0.5
Vsg = 0.5 m / s
The negative symbol indicates direction. So Vsg for A > Vsg for B
Therefore, the stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.
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A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?
The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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