A man has a total of 200 apples divided evenly among 5 boxes. How many apples are in each box?
If the total number of apples is A and the number of boxes is B, write an equation to solve for the amount
of apples in each box. (You should probably have some sort of ratio or fraction with the letters A and B written,
as well as any numbers you may need)
#apples in each box =

Answer:

D. x=4 did the test on edge

Step-by-step explanation:

Answer:

1-->15 min

4-->x min

Step-by-step explanation:

x=15×4=60

4 buses will take 60 min to refill

In hours, 60min÷60=1 hour

Answer:

Step-by-step explanation:

x=15×4=60

4 buses will take 60 min to refill

In hours, 60min÷60=1 hour

Answer:

[tex]d=2\sqrt{17}\approx8.2462[/tex]

Step-by-step explanation:

To find the distance between two points, use the distance formula.

The distance formula is:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

Let (3,-4) be x₁ and y₁ and let (5,4) be x₂ and y₂. Therefore:

[tex]d=\sqrt{(5-3)^2+(4--4)^2[/tex]

Simplify:

[tex]d=\sqrt{(2)^2+(8)^2[/tex]

Square:

[tex]d=\sqrt{4+64}[/tex]

Add:

[tex]d=\sqrt{68}[/tex]

Simplify:

[tex]d=\sqrt{4\cdot17}=\sqrt4\cdot\sqrt{17}[/tex]

Simplify:

[tex]d=2\sqrt{17}\approx8.2462[/tex]

Answer:

[tex]\boxed{2\sqrt{17}}[/tex]

Step-by-step explanation:

To find the distance between two points, we use the distance formula. The distance formula is:

[tex]\boxed{d=\sqrt{(x_{2}-x_{1})^{2}+({y_{2}-y_{1})^{2}}}}[/tex]

Therefore, we can label our coordinate pairs and solve for d.

Because we are given two coordinate pairs, we will follow the standard naming system for coordinate pairs. This is [tex](x_{1}, y_{1}) \text \: {and} \: (x_{2}, y_{2})[/tex]. Therefore, we can implement the distance formula and solve.

[tex]\sqrt{(5-3)^{2}+(4-(-4))^{2}}\\\\\sqrt{(2)^{2}+(8)^{2}}\\\\\sqrt{4 + 64} \\\\\sqrt{68} \\\\\boxed{2\sqrt{17} }[/tex]

Answer:

  8

Step-by-step explanation:

The product of terms on the left of the equal sign is ...

  (x+6)(x+k) = x^2 +(6+k)x +6k

So, you have two clues to the value of k. The coefficient of x must match, and the constant must match.

  6+k = 14   ⇒   k = 8

  6k = 48   ⇒   k = 8

The value of k is 8.

Answer:

4(x+y)

Step-by-step explanation:

x+y is one side length and there are 4 side lengths.

Answer: -18 - 27x, or -27x - 18

1. Solution Steps

[tex]-9(2+3x)[/tex]

Use the distributive property to multiply −9 by 2+3x.

[tex]-18-27x[/tex]

Expand

[tex]-27x-18[/tex]

2. Solution Steps

[tex]-9(2+3x)[/tex]

Use the distributive property to multiply −9 by 2+3x.

[tex]-18-27x[/tex]

Answer:

f(x) = x + 2

Step-by-step explanation:

If we graph x + 2, we can see that it passes the Vertical Line Test. Each x-value only has 1 y-value.

It depends on which culture you're looking at to be honest. But in the current environment, one item that is fairly prevalent is the coronavirus facemask. You could say it symbolically represents the idea of trying to stay safe and it represents a new norm (that many may consider strange since people are used to seeing each other's faces).

4b+4<20-12b

16b<16

b<1 olur.

İYİ DERSLER!

Answer:

See answer in the image below.

Answer:

(a+2)(a-12)

Step-by-step explanation:

[tex]a^2-10a-24\\\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(a^2+2a\right)+\left(-12a-24\right)\\\\\mathrm{Factor\:out\:}a\mathrm{\:from\:}a^2+2a\mathrm{:\quad }a\left(a+2\right)\\\\\mathrm{Factor\:out\:}-12\mathrm{\:from\:}-12a-24\mathrm{\\:\quad }-12\left(a+2\right)\\=a\left(a+2\right)-12\left(a+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}a+2\\=\left(a+2\right)\left(a-12\right)[/tex]

Answer:

(a + 2)(a - 12)

Step-by-step explanation:

a^2 - 10a - 24

using splitting method

a^2 - 12a + 2a - 24

taking separate common from both pairs

a(a - 12) + 2(a - 12)

(a + 2)(a - 12)

Answer: negative

Step-by-step explanation: Whenever you are adding negative

numbers together, you will always get a negative number.

For example, (-1) + (-1) will give you -2.

In the same way, (-5) + (-4) gives you -9.

Answer: negaitive

When you add a negative plus a negative you always get another negative

Answer:

[tex]$-\frac{1}{4} (-2x-9+\sqrt{65})(2x+9+\sqrt{65})$[/tex]

Step-by-step explanation:

We have a second-degree polynomial:

I will find the roots (y = 0) completing the square:

[tex]$x^2+9x+\frac{81}{4}-\frac{81}{4}+4=0$[/tex]

[tex]$\left(x+\frac{9}{2} \right)^2 -\frac{81}{4} +4 =0$[/tex]

[tex]$\left(x+\frac{9}{2} \right)^2 -\frac{81}{4} +\frac{16}{4} =0$[/tex]

[tex]$\left(x+\frac{9}{2} \right)^2 -\frac{65}{4} =0$[/tex]

[tex]$\left(x+\frac{9}{2} \right)^2 =\frac{65}{4} $[/tex]

[tex]$\left(x+\frac{9}{2} \right)^2 =\pm \sqrt{\frac{65}{4} } $[/tex]

[tex]$x =-\frac{9}{2} \pm \frac{\sqrt{65} }{2} $[/tex]

[tex]$x =\frac{-9 \pm \sqrt{65} }{2} $[/tex]

[tex]$\boxed{x_1 =\frac{-9 + \sqrt{65} }{2}} $[/tex]

[tex]$\boxed{x_2 =\frac{-9 - \sqrt{65} }{2}} $[/tex]

Answer:

Step-by-step explanation:

[tex]4z^2 - 3z - 4​\\z =2[/tex]

Substitute 2 for z in the given equation

[tex]4(2)^2 - 3(2) -4\\[/tex]

Follow the PEMDAS order of operations

[tex]\mathrm{Calculate\:exponents}\:\left(2\right)^2\::\quad 4\\=4\cdot \:4-3\left(2\right)-4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:4\times\:4\::\quad 16\\=16-3\left(2\right)-4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\left(2\right)\::\quad 6\\=16-6-4\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:16-6-4\::\quad 6[/tex]

Answer:

Step-by-step explanation:

Plug in z = 2 in the expression

4z² - 3z - 4 = 4*2² - 3*2 -4

                 = 4*4 - 6 - 4

                 = 16 - 6 - 4

                 = 10 - 4

                 = 6

If you subtract x from both sides, then you go from

x-2 < x-4

to

-2 < -4

which is a false statement. The value -2 is not smaller than -4. It's the other way around. I recommend looking at a number line to compare the two values.

This means that x-2 < x-4 is never true regardless of what x value you pick. So there are no solutions.

Answer:

x=  [tex]\frac{1}{2}[/tex]go+23

Step-by-step explanation:

Answer:

5/9 = 0.5

Step-by-step explanation:

hope it helps leme know if u hab doubts

Answer:

Huda found the product of –3 and 9 as positive.

Step-by-step explanation:

Given the expression and result below :

Huda evaluated the expression below. Negative 3 (8 minus 5) squared minus (negative 7) = negative 3 (3) squared minus (negative 7) = negative 3 (9) minus (negative 7) = 27 minus (negative 7) = 34

-3(8 - 5)² - (-7) =

Step 1:

- 3(3)² - (-7)

Step 2:

-3(9) - (-7)

Step 3:

27 - (-7) = 34 (error in the third step)

-3(9) = - 27

Hence,

-27 - (-7) = - 27 + 7 = - 20

Answer:

its B on edge

Step-by-step explanation:

I just took the test

A. x ≤ - 9 or x ≥ 9

x² ≥ 81

| x | ≥ 9

x ≥ 0 => x ≥ 9 => x ∈ [ 9 ; + oo)

x < 0 => x ≤ - 9 => x ∈ ( -oo ; - 9 ]

x ∈  ( -oo ; - 9 ] ∪ [ 9 ; + oo)

Answer:

[tex]\lim_{x\to3^-}\sin{\frac{\pi}{\floor[x]}=1[/tex]

[tex]\lim_{x\to3^+}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]

[tex]\lim_{x\to3}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]

Step-by-step explanation:

So we want to left and right hand limits of the function:

[tex]f(x)=\sin{\frac{\pi}{\floor[x]}[/tex]

as x approaches 3.

Note that the [x] means the floor function a.k.a the greatest integer function. In other words, the value of the function will be the greatest integer less than or equal to x.

1) Left

So we have the limit:

[tex]\lim_{x\to3^-}\sin{\frac{\pi}{\floor[x]}[/tex]

Note that since we're coming from the left, the values are 2.9, 2.99, and 2.999...

As I mentioned previously, the floor function outputs the greatest integer less than or equal to x.

With 2.9, 2.99, and 2.999, the greatest integer less than or equal to x is 2.

Therefore:

[tex]=\sin{\frac{\pi}{2}[/tex]

Simplify:

[tex]=1[/tex]

So:

[tex]\lim_{x\to3^-}\sin{\frac{\pi}{\floor[x]}=1[/tex]

2) Right:

[tex]\lim_{x\to3^+}\sin{\frac{\pi}{\floor[x]}[/tex]

Since we're coming from the right this time, the values are going to be 3.01, 3.001, 3.001.

And, the greatest integer less than or equal to 3.01, 3.001, and 3.001... is 3.

Therefore:

[tex]=\sin{\frac{\pi}{3}[/tex]

Simplify:

[tex]=\frac{\sqrt3}{2}[/tex]

So:

[tex]\lim_{x\to3^+}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]

At 3:

So we have:

[tex]\lim_{x\to3}\sin{\frac{\pi}{\floor[x]}[/tex]

The greatest integer of 3 is just 3. So:

[tex]=\sin{\frac{\pi}{3}\\[/tex]

Simplify:

[tex]=\frac{\sqrt3}{2}[/tex]

So:

[tex]\lim_{x\to3}\sin{\frac{\pi}{\floor[x]}=\frac{\sqrt3}{2}[/tex]

Answer:

m=−  33/14   =−2.357

Step-by-step explanation:

if you search up you question the first thing will come up is an answer from tiger algebra  is may not be you question but click on it is will take to to this search bar area clear it and put you question in it then it will give your answer and step by step explanation

Step-by-step explanation:

x+2<−5

Step 1: Subtract 2 from both sides.

x+2−2<−5−2

x<−7

Answer:

x<−7

Answer:

ΔB

Step-by-step explanation:

ΔA's angles are: 58º, 54º, and 68º

68º is found by 180 - (58 + 54)

ΔB's angles are: 54º, 68º, and 58º

58º is found by 180 - (68 + 54)

ΔA and ΔB have the same angles, therefore they are similar triangles

Answer:

triangle b

Step-by-step explanation:

i measured

B={1,2,3,4,6,8,12,24}

n(B)=8

Answer:

[tex] \boxed{ \huge{ \bold{ \boxed{ \sf{3 \:  ,  \: 6 \:  ,  \: 12}}}}}[/tex]

Step-by-step explanation:

Given,

E = { 1 , 2 , 3 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 , 15 , 16 }

Here, E is the universal set.

A = { x : x is a multiple of 3 }

Here, we have to list the multiples of 3 less than 16

A = { 3 , 6 , 9 , 12 , 15 }

B = { x : x is a factor of 24 }

Here, we have to list the factors of 24 less than 16 }

Factor of 24 means the numbers that can divide 24 easily.

Factor of 24 includes :

B = { 1 , 2 , 3 , 4 , 6 , 8 , 12 }

C = { x : x is an odd number }

Here, we have to list the odd numbers which are less than 16

C = { 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 }

Finding A ∩ B

Here, We have to find the common elements that are present in both A and B

{ 3 , 6 , 9 , 12 , 15 } ∩ { 1 , 2 , 3 , 4 , 6 , 8 , 12 }

= { 3 , 6 , 12 }

Hope I helped!

Best regards!!

Answer:

[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Answer:

Well the real answer is 1st 2nd and 5th

Step-by-step explanation:

Just took the quiz

Answer:

The total number of paints used for the month = $350

Step-by-step explanation:

Given that:

Spackle paint had a beginning inventory of 10 can of paint at $25 per can =

10× $25 = $250

They purchased 20 at $30 per can.

The amount of the 20 purchased can = 20 × $30 = $600

The total inventory for this supply = $600 + $250

= $850

They had an ending inventory valued 500.

∴

The total number of paints used for the month = total inventory  - ending inventory

The total number of paints used for the month = $850 - $500

The total number of paints used for the month = $350

Answer:

$8460

Step-by-step explanation:

So for this problem we will use the base price of $8000 and add the additional cost of the 5.75% to find the total cost for the car.

So, to find the 5.75%, we simply multiply 8000 by .0575 to get 460.

So 8000 + 460 = 8460.

Thus, the total price of the car would be $8460.

Cheers.

Answer: $8,460

Step-by-step explanation: If you multiply the cost of the car by the sales tax you get your answer. Hope this helps!