A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.
There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.
Problem 8. (Continues previous problem.) A type I error occurs if (Q12)
Problem 9. (Continues previous problem.) A type II error occurs if (Q13)
Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)
Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)
Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)
Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)
Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)
(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.
Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)
Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)
Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)

Answer:

[tex]\displaystyle \oint_C {3y \, dx + 2x \, dy} = \boxed{\bold{2}}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]
Derivative Rule [Basic Power Rule]:

Integration

Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Multivariable Calculus

Partial Derivatives

Vector Calculus

Circulation Density:
[tex]\displaystyle F = M \hat{\i} + N \hat{\j} \rightarrow \text{curl} \ \bold{F} \cdot \bold{k} = \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}[/tex]

Green's Theorem [Circulation Curl/Tangential Form]:
[tex]\displaystyle \oint_C {F \cdot T} \, ds = \oint_C {M \, dx + N \, dy} = \iint_R {\bigg( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \bigg)} \, dx \, dy[/tex]

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \oint_C {3y \, dx + 2x \, dy}[/tex]

[tex]\displaystyle \text{Region:} \ \left \{ {{0 \leq x \leq \pi} \atop {0 \leq y \leq \sin x}} \right.[/tex]

Step 2: Integrate Pt. 1

Step 3: Integrate Pt. 2

We can evaluate the Green's Theorem double integral we found using basic integration techniques listed above:
[tex]\displaystyle \begin{aligned}\oint_C {3y \, dx + 2x \, dy} & = - \int\limits^{\pi}_0 \int\limits^{\sin x}_0 {} \, dy \, dx \\& = - \int\limits^{\pi}_0 {y \bigg| \limits^{y = \sin x}_{y = 0}} \, dx \\& = - \int\limits^{\pi}_0 {\sin x} \, dx \\& = \cos x \bigg| \limits^{x = \pi}_{x = 0} \\& = \boxed{\bold{2}}\end{aligned}[/tex]

∴ we have evaluated the line integral using Green's Theorem.

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Topic: Multivariable Calculus

Unit: Green's Theorem and Surfaces

Answer:

B. j(kl)

Step-by-step explanation:

(jk)l

We can change the order we multiply and still get the same result

j(kl)

Answer:

Step-by-step explanation:

its B i did it

Answer:

-4x - 3.

Step-by-step explanation:

f(x) = -4x + 5.

f(x + 2) = -4(x + 2) + 5

= -4x - 8 + 5

= -4x - 3.

Hope this helps!

Answer:

f(x+2)=-4x-3

Step-by-step explanation:

We are given:

[tex]f(x)= -4x+5[/tex]

and asked to find f(x+2). Therefore, we must substitute x+2 for each x in the function.

[tex]f(x+2)=-4(x+2)+5[/tex]

Now, simplify. First, distribute the -4. Multiply each term inside the parentheses by -4.

[tex]f(x+2)=(-4*x)+(-4*2)+5\\f(x+2)=-4x+(-4*2)+5\\f(x+2)=-4x-8+5[/tex]

Next, combine like terms. There are 2 constants (terms without a variable) that can be added. Add -8 and 5.

[tex]f(x+2)=-4x(-8+5)\\f(x+2)=-4x-3[/tex]

f(x+2) is -4x-3.

Answer:

P = 3x - 4

Step-by-step explanation:

Side 1 = x - 3

Side 2 = x

Side 3 = 2 + (Side 1) = 2 + x - 3 = x - 1

Perimeter = 20 in

Perimeter = Side 1 + Side 2 + Side 3

Perimeter = (x - 3) + (x) + (x - 1)

Perimeter = x - 3 + x + x - 1

Perimeter = 3x - 3 - 1

Perimeter = 3x - 3 - 1

Perimeter = 3x - 4

P = 3x - 4

Answer:

(x − 7)2 + (y − 8)2 = 11

Step-by-step explanation:

I took the test

The equation of the circle with center at (7, 8) and radius of 11 is

(x - 7)²  +  (y - 8)²  =121

The equation of a circle with center at (a, b) and radius of r is:

(x - a)²  +  (y - b)²  =  r²

The center of the circle, (a, b)  =  (7, 8)

That is, a = 7, b = 8

The radius, r = 11

Substitute a = 7, b = 8, and r = 11 into the equation (x - a)²  +  (y - b)²  =  r²:

(x - 7)²  +  (y - 8)²  =  11²

(x - 7)²  +  (y - 8)²  = 121

Therefore, the equation of the circle with center at (7, 8) and radius of 11 is

(x - 7)²  +  (y - 8)²  =121

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Answer:

Hey there!

The area of a rectangle is the length times width.

Thus, we can write the equation, 600=30w.

Solving for the width, we get that the width is equal to 20 ft.

Let me know if this helps :)

Answer:

20 feet across.

Step-by-step explanation:

You will have to do a simple equation solve.

x is how many feet across the court is.

* could be our multiplying sign

600 = 30*x

Now divide 30 on both sides. 30 will cross out (since 30/30 is 1 and anything times 1 is the same number as it was before) on the right side and 600/30 is 20 so we change the 600 to 20.

That leaves 20 = x.

So it is 20 feet across.

Answer:

10

Step-by-step explanation:

these are small bags (just as comment), so in real life the cost of using bags would add significantly to the price of the apples.

anyway, so we need to find how many units of 3/5 pounds do we need to get 6 pounds ?

3/5 × x = 6

3 × x = 30

x = 10

she buys 10 bags to get 6 pounds.

Answer:

True

Step-by-step explanation:

The normal form of equation of a line is the radius of p. Tangent to a circle is the line that touches one point on the circle. The radius is the circumference of the circle. The tangent line on the circle is always perpendicular to the radius. The statement is correct.

[tex]f(x)=\sqrt{x+3}\\g(x)=8x-7\\\\f(g(x))=\sqrt{8x-7+3}=\sqrt{8x-4}[/tex]

Answer:

Matrix :

[tex]\begin{bmatrix}1&1&1&|&380\\ 5&3&10&|&1460\\ -2&1&0&|&0\end{bmatrix}[/tex]

Solution Set : { x = 123, y = 246, z = 11 }

Step-by-step explanation:

Let's say that x represents the number of car wash tickets, y represents the number of silly sting fight tickets, and z represents the number of dance tickets. We know that the total tickets = 380, so therefore,

x + y + z = 380,

And the car wash tickets were $5 each, the silly sting fight tickets were $3 each and the dance tickets were $10 each, the total cost being $1460.

5x + 3y + 10z = 1460

The silly string tickets were sold for twice as much as the car wash tickets.

y = 2x

Therefore, if we allign the co - efficients of the following system of equations, we get it's respective matrix.

System of Equations :

[tex]\begin{bmatrix}x+y+z=380\\ 5x+3y+10z=1460\\ y=2x\end{bmatrix}[/tex]

Matrix :

[tex]\begin{bmatrix}1&1&1&|&380\\ 5&3&10&|&1460\\ -2&1&0&|&0\end{bmatrix}[/tex]

Let's reduce this matrix to row - echelon form, receiving the number of car wash tickets, silly sting fight tickets, and dance tickets,

[tex]\begin{bmatrix}5&3&10&1460\\ 1&1&1&380\\ -2&1&0&0\end{bmatrix}[/tex] - Swap Matrix Rows

[tex]\begin{bmatrix}5&3&10&1460\\ 0&\frac{2}{5}&-1&88\\ -2&1&0&0\end{bmatrix}[/tex] - Cancel leading Co - efficient in second row

[tex]\begin{bmatrix}5&3&10&1460\\ 0&\frac{2}{5}&-1&88\\ 0&\frac{11}{5}&4&584\end{bmatrix}[/tex] - Cancel leading Co - efficient in third row

[tex]\begin{bmatrix}5&3&10&1460\\ 0&\frac{11}{5}&4&584\\ 0&\frac{2}{5}&-1&88\end{bmatrix}[/tex] - Swap second and third rows

[tex]\begin{bmatrix}5&3&10&1460\\ 0&\frac{11}{5}&4&584\\ 0&0&-\frac{19}{11}&-\frac{200}{11}\end{bmatrix}[/tex] - Cancel leading co - efficient in row three

And we can continue, canceling the leading co - efficient in each row until this matrix remains,

[tex]\begin{bmatrix}1&0&0&|&\frac{2340}{19}\\ 0&1&0&|&\frac{4680}{19}\\ 0&0&1&|&\frac{200}{19}\end{bmatrix}[/tex]

x = 2340 / 19 = ( About ) 123 car wash tickets sold, y= 4680 / 19 =( About ) 246 silly string fight tickets sold, z = 200 / 19 = ( About ) 11 tickets sold

Answer:

Here's what I get  

Step-by-step explanation:

h = 0.5d + 4

A function rule tells you how to convert an input value (x) into an output value (y).

Your function rule is

ƒ(x) = 0.5x + 4

An easy way to represent your function is to make a graph.

The easiest way to make a graph is to make a table containing some inputs and their corresponding outputs.  

Here's a typical table.

[tex]\begin{array}{cc}\textbf{x} &\textbf{y} \\0 & 4 \\2 & 5 \\4 & 6 \\6 & 7\\6 & 8 \\\end{array}[/tex]

The graph is like the one below.

Answer:

In mathematics, an area model is a rectangular diagram or model used for multiplication and division problems, in which the or the and define the length and width of the rectangle.

We can break one large of the rectangle into several smaller boxes, using number bonds, to make the calculation easier. Then we add to get the area of the whole, which is the or quotient.

To multiply two 2-digit numbers, using the area model, follow the given steps:

Write the multiplicands in expanded form as tens and ones.

For example, 27 as 20 and 7, and 35 as 30 and 5.

Draw a 2 × 2 grid, that is, a box with 2 rows and 2 columns.

Write the terms of one of the multiplicands on the top of the grid (box). One on the top of each cell.

On the left of the grid, write the terms of the other multiplicand. One on the side of each cell.

Write the product of the number on the tens in the first cell. Then write the product of the tens and ones in the second and third cell. Write the product of the ones in the fourth cell.

write the product in the cell

Finally, add all the partial products to get the final product.

Here, for example, the area model has been used to multiply 27 and 35.

area model multiplication

Let us see how to find the product of 3-digit number by a 2-digit number using the area model.

Find the Product using Area Model

Let us now use the area model for the division. Here, we divide 825 by 5.

Area Model Division 1

Area Model Division 2

Fun Facts

The area model is also known as the box model.

The area model of solving multiplication and division problems is derived from the concept of finding the area of a rectangle. Area of a rectangle = Length × Width.

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Answer:

-5/8

Step-by-step explanation:

13/ -56   -x = 11/28

Add 13/56 to each side

13/ -56   + 13/56  -x = 11/28+ 13/56

-x = 11/28 + 13/56

Get a common denominator

-x = 11/28 *2/2 +13/56

-x = 22/56 + 13/56

-x = 35/56

Divide top and bottom by 7

-x = 5/8

Multiply both side by -1

x = -5/8

Answer:

The critical value for two tailed test at alpha=0.1 is ± 1.645

The calculated  z= 9.406

Step-by-step explanation:

Formulate the hypotheses as

H0: p1= p2 there is no difference between the population scrap rates between the old and new cutting methods

Ha : p1≠ p2

Choose the significance level ∝= 0.1

The critical value for two tailed test at alpha=0.1 is ± 1.645

The test statistic is

Z = [tex]\frac{p_1- p_2}\sqrt pq(\frac{1}{n_1} + \frac{1}{n_2})[/tex]

p1= scrap rate of old method = 62/200=0.31

p2= scrap rate of new method = 36/400= 0.09

p = an estimate of the common scrap rate on the assumption that the two rates are same.

p = n1p1+ n2p2/ n1 + n2

p =200 (0.31) + 400 (0.09) / 600

p= 62+ 36/600= 98/600 =0.1633

now q = 1-p= 1- 0.1633= 0.8367

Thus

z= 0.31- 0.09/ √0.1633*0.8367( 1/200 + 1/400)

z= 0.301/√ 0.13663( 3/400)

z= 0.301/0.0320

z= 9.406

The calculated value of z falls in the critical region therefore we reject the null hypothesis and conclude that the 10% significance level that the scrap rate of the new method is different from the old method.

9514 1404 393

Answer:

  A. 281,634

Step-by-step explanation:

You can identify the number after the first two "rules".

Choices A and C have 3 in the tens place.

Choice A has 6 in the hundreds place.

9514 1404 393

Answer:

Step-by-step explanation:

If Charles is 22 years older, he will be double Danielle's age when she is 22. If that is 10 years from now, Danielle is 12 and Charles is 34.

Answer:

Selling price=rs.600.

Profit of rs=100.

Step-by-step explanation:

C.P=500; profit%=20%

S.P.=100+profit%×C.P/100

S.P=120×500/100

=rs.600

S.P>C.P

Profit S.P-C.P

600-500=100

he gained for rs.100.

9514 1404 393

Answer:

  (x, y) = (4, -4)

Step-by-step explanation:

A graphing calculator makes graphing very easy. The attachment shows the solution to be (x, y) = (4, -4).

__

The equations are in slope-intercept form, so it is convenient to start from the y-intercept and use the slope (rise/run) to find additional points on the line.

The first line can be drawn by staring at (0, -2) and moving down 1 grid unit for each 2 to the right.

The second line can be drawn by starting at (0, 2) and moving down 3 grid units for each 2 to the right.

The point of intersection of the lines, (4, -4), is the solution to the system of equations.

Answer:

Correct answer is option d. increase of $1 in advertising is associated with an increase of $4000 in sales.

Step-by-step explanation:

Given the equation of regression analysis is given as:

[tex]y= 30,000 + 4x[/tex]

where [tex]x[/tex] is the cost on advertising in Dollars.

and [tex]y[/tex] is the sales in Thousand Dollars.

To find:

The correct increase in sales when there is increase in the advertising cost.

Solution:

Suppose there is an increase of [tex]\$1[/tex] in the advertising cost.

Let the initial cost be [tex]x[/tex] then the cost will be [tex](x+1)[/tex].

Initial sales

[tex]y= 30,000 + 4x[/tex] ....... (1)

After increase of $1 in advertising cost, final cost:

[tex]y'= 30,000 + 4(x+1)\\\Rightarrow y' = 30,000+4x+4\\\Rightarrow y' = 30,004+4x ..... (2)[/tex]

Subtracting (2) from (1) to find the increase in the sales:

[tex]y'-y=30004+4x-30000-4x = 4[/tex]

The units of sales is Thousand Dollars ($1000).

So, increase in sales = [tex]4 \times1000 = \bold{\$4000}[/tex]

So, correct answer is:

d. increase of $1 in advertising is associated with an increase of $4000 in sales.

Answer:

0.07047

Step-by-step explanation:

at least 4 people survive is

4 people survive and 2 don't +

5 people survive and 1 doesn't +

all 6 people survive

the probability of 4 people to survive is the product of the individual probabilities :

0.3×0.3×0.3×0.3 = 0.3⁴ = 0.0081

times the probability 2 don't survive

0.7×0.7 = 0.49

0.0081×0.49 = 0.003969

now, the chance that 4 out of 6 survive is that probabilty times how many times we can select 4 out of 6.

to select 4 out of 6 is

[tex] \binom{6}{4} [/tex]

= 6! / (4! × (6-4)!) = 6! / (4! × 2!) = 6×5/2 = 30/2 = 15

so, the probability of having 4 survivors is

15×0.003969 = 0.059535

the probability of 5 people surviving is 0.3⁵ times one not

0.3⁵×0.7 = 0.001701

we have 6 over 5 combinations to pick 5 out of 6 = 6.

so, in total for 5 survivors we get

6×0.001701 = 0.010206

and the probabilty of all 6 surviving is

0.3⁶ = 0.000729

so, the probability of at least 4 out of 6 surviving is

0.059535 +

0.010206 +

0.000729

---------------

0.070470

Answer:

4.2

Step-by-step explanation:

f varies inversly with L can be translated matimatically as:

● f = k/L

It takes 7 pounds of pressure to break a 3 feet long board.

Replace f by 7 and L by 3.

● 7 = k/3 => k=7×3=21

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let's find tge length of a board that takes 5 pounds of pressure to be broken.

● 5 = k/L

● 5 = 21/L

● L = 21/5 = 4.2

So the board is 4.2 feet long

Sol-1

[tex]\\ \sf\longmapsto |y-12|=21[/tex]

[tex]\\ \sf\longmapsto y+12=21[/tex]

[tex]\\ \sf\longmapsto y=21-12[/tex]

[tex]\\ \sf\longmapsto y=9[/tex]

Sol:-2

[tex]\\ \sf\longmapsto y-12=21[/tex]

[tex]\\ \sf\longmapsto y=21+12[/tex]

[tex]\\ \sf\longmapsto y=33[/tex]

Answer: 3 pounds.

Step-by-step explanation:

We have two metals:

One that contains 20% nickel, let's call it metal A.

One that contains 80% nickel, let's call it metal B.

We have 6 pounds of metal B, in those 6 punds we have:

0.80*6lb = 4.8lb of nickel.

Now, if we add X pounds of metal A, then we will have:

X + 6lb in total weight.

4.8lb + 0.2*X of nickel.

And we want to have exactly 60% of nickel, so we must have that the quotient between the amount of nickel and the total weight is equal to 0.6

(4.8lb + 0.2*X)/(6lb + X) = 0.6

now we solve it for X:

(4.8lb + 0.2*X) = 0.6*(6lb + X) = 3.6lb + 0.6*X

4.8lb - 3.6lb = 0.6*X - 0.2*X

1.2lb = 0.4*X

1.2lb/0.4 = 3lb = X

We should use 3 pounds of the metal with 20% of nickel.

Answer: 0.10299,0.1037  ,0.1038 ,0.9

Step-by-step explanation:

In all the numbers we could see that 0.9 is the greatest because it has the greatest tenth value. The rest three have the same tenth value which is one and the same hundredth value which is 0 so we will compare the numbers using  their thousandth values.

In the numbers 0.1038,0.10299, 0.1037   The first one has a thousandth value of 3, the second one has a thousandth value of 2, and the third one has a thousandth value of 3. Which means the first and the second have the same thousandths value so using their last numbers which is 8  and 7 , 8 is greater than 7  so  0.1038  is greater than 0.1037 and 0.10299.  The same way 0.1037 is greater than 0.10299.

So to order them from least to greatest,

0.10299 will be first

0.1037  will be second  

0.1038  will be the third  

0.9  will be the last.

Answer:

Step-by-step explanation:

a) The sample space, n(S) = 6^6 = 46656

Let the number fair dice toss that show 6 = n(A)

Hence, the probability of getting, P(A) = n(A)/n(S)

b) Sample space, n(S) = 6^42

n(A) = 6^9

∴ P(A) = n(A)/n(S) = 6^9/6^42 = 1/(6^33) = 2.09 X 10^(-26)

c) No

Answer:

Step-by-step explanation:

The answer is that 1 variable is allowed to change. The others are held at a constant.

An example would be the growth of a poinsettia. These Christmas plants are very touchy. They respond badly to too much water or not enough water. So you keep the amount of dirt, the amount of sunlight, the amount of support that each plant receives as a constant.

The amount of water is what you change in one of the plants. The one plant (or a few) will measure the growth of the plant.

So the last answer is the one you want.

[tex]\dfrac{x}{5}=-2\\\\x=-10[/tex]

Answer:

[tex]\huge \boxed{{x=-10}}[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{x}{5} =-2[/tex]

We need the x variable to be isolated on one side of the equation, so we can find the value of x.

Multiply both sides of the equation by 5.

[tex]\displaystyle \frac{x}{5}(5) =-2(5)[/tex]

Simplify the equation.

[tex]x=-10[/tex]

The value of x that makes the equation true is -10.

Take

[tex]u=\ln x\implies\mathrm du=\dfrac{\mathrm dx}x[/tex]

[tex]\mathrm dv=4x^2\,\mathrm dx\implies v=\dfrac43x^3[/tex]

Then

[tex]\displaystyle\int4x^2\ln x\,\mathrm dx=\frac43x^3\ln x-\frac43\int x^2\,\mathrm dx=\frac43x^3\ln x-\frac49x^3+C[/tex]

[tex]=\boxed{\dfrac49x^3(3\ln x-1)+C}[/tex]

The required integration is,

∫4x² lnx dx = (lnx) [(4/3)x³ + C₁] - (4/9)x³ + C

The given integral is,

∫4x² lnx dx

Using integration by parts, choose u and dv.

In this case, we choose u = lnx and dv = 4x²dx.

Using the formula for integration by parts, we have:

∫ u dv = uv - ∫ v du

Substituting the values of u and dv, we get:

∫4x² lnx dx = (lnx) (∫ 4x² dx) - ∫ [(d/dx)lnx] (∫4x² dx) dx

Simplifying the first term using the power rule of integration, we get:

∫ 4x² dx = (4/3)x³ + C₁

For the second term, we need to evaluate (d/dx)lnx,

Which is simply 1/x. Substituting this value, we get:

∫ [(d/dx)lnx] (∫4x² dx) dx = ∫ [(1/x) ((4/3)x³ + C₁)] dx

Simplifying this expression, we get:

∫4x² lnx dx = (lnx) [(4/3)x³ + C₁] - ∫ [(4/3)x³/x] dx

Using the power rule of integration again, we get:

∫4x² lnx dx = (lnx) [(4/3)x³ + C₁] - (4/9)x³ + C

Where C is the constant of integration.

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Answer:

P(C|Y) = 0.5.

Step-by-step explanation:

We are given the following table below;

               X             Y               Z             Total

A             32           10             28              70

B              6             5              25              36

C             18            15              7                40

Total       56           30            60              146

Now, we have to find the probability of P(C/Y).

As we know that the conditional probability formula of P(A/B) is given by;

                    P(A/B) =  [tex]\frac{P(A \bigcap B)}{P(B)}[/tex]

So, according to our question;

P(C/Y) =  [tex]\frac{P(C \bigcap Y)}{P(Y)}[/tex]

Here, P(Y) = [tex]\frac{30}{146}[/tex] and P(C [tex]\bigcap[/tex] Y) =  [tex]\frac{15}{146}[/tex]  {by seeing third row and second column}

Hence, P(C/Y) =  [tex]\frac{\frac{15}{146} }{\frac{30}{146} }[/tex]

                       =  [tex]\frac{15}{30}[/tex]  = 0.5.

Answer: 0.5

Step-by-step explanation:

edge

Answer:

Hello,

Answer

[tex]\sigma=457,95...[/tex]

Step-by-step explanation:

p(z<a)=0.9

p(z<1.29)=0.9015

p(z<1.28)=0.8997

using linear interpolation: with 4 decimals

p(z<1.282)<0.9

[tex]\dfrac{1628-1500}{\sigma} =1.282\\\\\sigma =\dfrac{1628-1500}{1.282}\\\\\sigma=457,95...\\[/tex]