a nickel has 5 grams what is the mass of a nickel in milligrams

Answer:

1/3 and -1/2

Step-by-step explanation:

You can use the factoring method to identify the solutions of x

6x^2+x-1

2 numbers have to multiply to 6 and subtract to 1 because x is the same as 1x

So, you get 3x and 2x

since you know that -1x1 is -1 you will get

(3x-1)(2x+1)=0

Now, since (3x-1) and (2x+1) multiply to get 0, if either (3x-1) or (2x+1) is 0 the statement will be valid

3(1/3)-1=0

2(-1/2)+1=0

So, your answers are 1/3 and -1/2

Expression which is equivalent to [tex]$\sqrt{8 x^{7} y^{8}}[/tex] is [tex]$=2 \sqrt{2} x^{3} y^{4} \sqrt{x}$[/tex].

What are equivalent expressions?

Expressions that function identically despite having distinct appearances are called equivalent expressions. If two algebraic expressions are equivalent, then when we enter the same value(s) for the variable, the two expressions have the same value (s).

Solution of the given equation [tex]$\sqrt{8 x^{7} y^{8}}[/tex].

      [tex]$\sqrt{8 x^{7} y^{8}}=\sqrt{8} \sqrt{x^{7}} \sqrt{y^{8}}$[/tex]

                    [tex]$=\sqrt{8} \sqrt{x^{7}} \sqrt{y^{8}}$[/tex]

Simplify [tex]$\sqrt{x^{7}}: x^{3} \sqrt{x}$[/tex]

                     [tex]$=\sqrt{8} x^{3} \sqrt{x} \sqrt{y^{8}}$[/tex]

Simplify [tex]$\sqrt{y^{8}}: y^{4}$[/tex]

                     [tex]$=\sqrt{8} x^{3} \sqrt{x} y^{4}$[/tex]

                [tex]$\sqrt{8}=2 \sqrt{2}$[/tex]

                     [tex]$=2 \sqrt{2} x^{3} \sqrt{x} y^{4}$[/tex]

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The complete question is :

Which expression is equivalent to StartRoot 8 x Superscript 7 Baseline y Superscript 8 Baseline EndRoot? Assume x greater-than-or-equal-to 0. x y squared StartRoot 8 x cubed EndRoot 2 x cubed y cubed StartRoot x y squared EndRoot 2 x cubed y Superscript 4 Baseline StartRoot 2 x EndRoot 4 x cubed y Superscript 4 Baseline StartRoot x EndRoot

The percent increase in employment would be necessary for the number of workers to be greater than 375 is 25%

The given parameters are:

Initial = 350

Final = 375

The rate is calculated as:

Rate = Final/Initial - 1

So, we have:

Rate = 375/300 - 1

Evaluate

Rate = 1.25 - 1

This gives

Rate = 0.25

Express as percentage

Rate = 25%

Hence, the percent increase in employment would be necessary for the number of workers to be greater than 375 is 25%

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The value of k in the polynomial is 3

The quotient is given as:

(x^2+5x+k)/(x+6)

The remainder is 9

Set the denominator to 0

x + 6 = 0

Solve for x

x = -6

This means that:

f(-6) = 9

So, we have:

(-6)^2 + 5(-6) + k = 9

Evaluate

6+ k = 9

Subtract 6 from both sides

k = 3

hence, the value of k is 3

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Answer:

Step-by-step explanation:

(a)

      1 - Simplify 4 - 9 to -5.

         ⇒ | - 5 |

      2 - Simplify.

       ⇒ 5

  (b)  

   1 -  Simplify

 ⇒ -5

Option B. ($99,242.00, $100,758.01)

a) For n - 1 = 49 degrees of freedom, we have form t distribution tables:

P( t < 2.010) = 0.975

Therefore, P(-2.010 < t < 2.010) = 0.95

Therefore the confidence interval here is obtained as:

X +₋ t 8/√ⁿ

100 \pm 2.010*\frac{2}{\sqrt{50}}

100 \pm 0.5685

(99431.61, 100568.39)

Therefore A is the correct interval here.

Q2) From t distribution tables, we have here:

P(-2.680 < t < 2.680) = 0.99

Therefore the confidence interval here is obtained as:

100 \pm 2.010*\frac{2}{\sqrt{50}}

100 \pm 0.7580

(99242, 100785)

1) A university wants to determine the average salary of its graduating computer science majors. The university asks the graduating classes of 50 students to share their starting salaries when hired. The 50 students had an average salary of $100,000 with a standard deviation of $2,000. Find a 95% confidence interval for the average starting salary of computer science majors from the university.

a - ($99,431.61, $100,568.39)

b - ($99,445.64, $100,554.36)

c- ($99,982.26, $100,017.74)

d - The salaries are not normally distributed so we cannot compute a confidence interval

2) Find a 99% confidence interval for the previous problem.

a - ($99,271.44, $100,728.56)

b - ($99,242.00, $100,758.01)

c - ($99,996.46, $100,003.55)

d - The salaries are not normally distributed so we cannot compute a confidence interval

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Answer:

Corresponding parts of similar triangles are congruent.

Step-by-step explanation:

The measure of angle D in the convex pentagon ABCDE is 132°

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the measure of angle D, hence:

angle A = x - 40.

∠A + ∠B + ∠C + ∠D + ∠E = 540° (sum of angle in a pentagon)

3(x - 40) + 2x = 540

x = 132°

The measure of angle D in the convex pentagon ABCDE is 132°

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The maximum height of the ball after its third bounce is equal to 3.568 feet.

In this question we are aware that the maximum height reached by the ball decreases linearly after each bounce. To determine that height, we must take advantage of the recursive formula described in statement:

n = 0

a₀ = 10 ft

n = 1

a₁ = 0.85 · 10 - 1

a₁ = 8.5 - 1

a₁ = 7.5 ft

n = 2

a₂ = 0.85 · 7.5 - 1

a₂ = 5.375 ft

n = 3

a₃ = 0.85 · 5.375 - 1

a₃ = 3.568 ft

The maximum height of the ball after its third bounce is equal to 3.568 feet.

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The first one is 10 feet.
The second one is 6.141 feet.

Step-by-step explanation: Edge 2023

Option C

Answer:

Step-by-step explanation:

Step-by-step explanation:

15 r blue marbles

20- 5 = 15

The transformed function is defined by:

g(x) = -f(x/5 - 2) - 6

Where f(x) is the given function.

Here we start with the function:

f(x) = (1/3)*x

(I don't know if this is the actual function, but that does not matter, I will solve it in a general way).

If first, we reflect it vertically, then the new function is:

g(x) = -f(x).

If now we compress it horizontally by a factor of 5, then we get:

g(x)  = - f(x/5)

Now we shift it 2 units to the right, then:

g(x) = -f(x/5 - 2)

Finally, we shift it down 6 units, then we get:

g(x) = -f(x/5 - 2) - 6

That is the general form of the function g(x).

Replacing f(x) by what is defined above, we get:

g(x) = -(1/3)*(x/5 - 2) - 6

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Applying the area of a rectangle, the cost to make the part of the compass is: $129.85.

Area of a triangle = 1/2(base)(height).

Find the height of the triangle using the Pythagorean theorem:

Height = √(5² - 1²) ≈ 4.9 cm.

Base = 2 cm

Area of the two triangles = 2[1/2(base)(height)]

Area of the two triangles = 2[1/2(2)(4.9)] = 9.8 cm².

Cost to to make this part of the compass = 9.8 × $13.25 = $129.85.

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Answer: 129.82

Step-by-step explanation: its on edge I got it right :)

Considering the logarithmic loudness equation, the relative intensity of 120 decibels is of [tex]R = 10^{12}[/tex].

The equation is:

[tex]L = 10\log{R}[/tex]

In which:

For this problem, we have that L = 120, hence the relative intensity is found as follows:

[tex]120 = 10\log{R}[/tex]

[tex]\log{R} = 12[/tex]

[tex]R = 10^{12}[/tex]

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Answer:??? rest of the question I think is what will be the exponent of 10 in the quotient? answer is 8

Step-by-step explanation:

Jhon was between 6:12 p.m and 6:52 p.m. So, Jhon left home for exact 40 minutes. Using the angle made by the hands in the clock, the required value is calculated.

The general formula for finding the angle between the minute hand and the hour hand is

M = [tex]\frac{2}{11}[/tex] (H × 30 ± θ)

It is given that,

Jhon left home after 6 p.m with an angle of 110° formed by the minute hand and hour hand.

So,

M = [tex]\frac{2}{11}[/tex] (H × 30 - θ)

   = [tex]\frac{2}{11}[/tex] (6 × 30 - 110)

   = [tex]\frac{2}{11}[/tex] (180 - 110)

   = [tex]\frac{2}{11}[/tex] × 70

   = 140/11

So, he left after 6:12 p.m

Jhon returned home before 7 p.m with angle of 110° formed by the minute hand and hour hand.

M = [tex]\frac{2}{11}[/tex] (H × 30 + θ)

   = [tex]\frac{2}{11}[/tex] (6 × 30 + 110)

   = [tex]\frac{2}{11}[/tex] (180 + 110)

   = [tex]\frac{2}{11}[/tex] × 290

   = 580/11

So, he returned before 6:52 p.m

Then,

The time taken for returning home = 580/11 - 140/11 = 440/11 = 40 minutes.

Therefore, he took 40 minutes to return home.

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Answer:

a = -22/13.

Step-by-step explanation:

By the Remainder Theorem

p(3) = remainder    when p(x) is divided by x-3.

q(3)  is equal to the same remainder.

So we have:

p(3) = q(3) , so

a(3)^3 + 4(3)^2 + 3(3) - 4 = 3^2 - 4(3) + a

27a + 36 + 9 - 4 = 9 - 12 + a

27a - a = 9 - 12 - 36 - 9 + 4

26a = -12 - 36 + 4

26a = -44

a = -44/26

a = -22/13.

You have to find the slope of the line. It will give you the conversion rate from inches to centimetres or the other way around.

Looking closely at the graph, or using a ruler as reference, you can estimate that 30 cm ≈ 12 in. In terms of the graph, the line very nearly passes through the point (12, 30). It also passes through the origin, (0, 0), since 0 cm = 0 in exactly.

The slope of the line is then

[tex]\dfrac{30\,\mathrm{cm}-0\,\mathrm{cm}}{12\,\mathrm{in}-0\,\mathrm{in}} = \dfrac{30\,\rm cm}{12\,\rm in} = \dfrac{5\,\rm cm}{2\,\rm in} = 2.5\dfrac{\rm cm}{\rm in}[/tex]

which means that 1 in ≈ 2.5 cm.

So, if Sarah's height is 64 in, we convert this to cm and find her height is (approximately)

[tex]64\,\mathrm{in} \times 2.5\dfrac{\rm cm}{\rm in} = \boxed{160\,\rm cm}[/tex]

The time for the village to dig the new well is about 7 1/2 years. At this time the population doubles from its current size.

For a function f(x) = y, the steps to draw a graph for the given function are as follows:

It is given that,

f(x) = 200 × [tex](1.098)^x[/tex]

Village's population growing rate = 9.8%

Creating a table for x and f(x) values:

x: 0   2   4   6   8   10

f(x = 0) = f(0) = 200 × [tex](1.098)^0[/tex] = 200

f(x = 2) = f(2) = 200 × [tex](1.098)^2[/tex] = 241

f(x = 4) = f(4) = 200 × [tex](1.098)^4[/tex] = 291

f(x = 6) = f(6) = 200 × [tex](1.098)^6[/tex] = 350

f(x = 8) = f(8) = 200 × [tex](1.098)^8[/tex] = 423

f(x = 10) = f(10) = 200 × [tex](1.098)^1^0[/tex] = 509

So,

(x, f(x)): (0, 200)  (2, 241)  (4, 291)  (6, 350)  (8, 423)  (10, 509)

Plotting these points in the graph and joining the points, the graph is shown below.

Finding the time for the village to dig a new well:

It is given that the population doubled from its current size, the village will need to dig new water well.

The current size of the village = 200

If it doubles for a certain time 't' = 400

So,

400 = 200 × [tex](1.098)^t[/tex]

⇒ [tex](1.098)^t[/tex] = 2

⇒ log[tex](1.098)^t[/tex] = log 2

⇒ t log(1.098) = 0.301

⇒ t × 0.04 = 0.301

∴ t = 7.525 years

Therefore, the village's population becomes double at the time 7 and half years from now. So, after 7 1/2 years, the village needs to dig a new well.

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The sum of the areas of circle C and circle D is 98 units square. Option D

It is important to note that the if the circles overlap each other, then the most have the same radius

Also, the formula for area of a circle is given as;

Area = [tex]\pi r^2[/tex]

For Circle C

The value for π = 3. 142

radius = 7cm

Substitute the values into the formula

We have

Area = π × 7 × 7

Area = 49 π units square

For Circle D

Substitute the values into the formula

Area = [tex]\pi r^2[/tex]

Area = π × 7 × 7

Area = 49 π units square

Sum of the areas of circle C and circle D = area of circle C and area of circle D

Sum of the areas of circle C and D = 49π + 49 π

= 98 units square

The sum of the areas of the circles is 98 units square

Thus, the sum of the areas of circle C and circle D is 98 units square. Option D

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Answer:

6 [tex]units^{2}[/tex]

Step-by-step explanation:

The formula for the area of a triangle is A = [tex]\frac{1}{2} bh[/tex]. The base in this case is the length of DE, 4 - 1 = 3 units. The height of this triangle is 1 + 3 = 4 units.

A = [tex]\frac{1}{2} bh[/tex] = [tex]\frac{1}{2} *3*4[/tex] = 6

Answer:

Answer: B.156

Step-by-step explanation:

Given: Total seashells = 160

mean = 120

population standard deviation = 26 grams

The probability that the seashells weigh at least 68 grams :-'

Total seashells weigh at least 68 grams = 0.9772 x 160 = 156.352≈ 156

Hence, the correct option is B.156

Answer:

90 is the right answer

Step-by-step explanation:

because it give the value pf o is tan o

The perimeter of the rectangle is 70 Inches square

The formula for perimeter of a rectangle is given as;

Perimeter = 2 ( l + w)

length = 20 inches

width = 15 inches

Perimeter = 2 ( 20 + 15 )

Perimeter = 2 ( 35)

Perimeter = 70 Inches square

Thus, the perimeter of the rectangle is 70 Inches square

Note that it is a general knowledge on the given question.

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Joel spent 72.5% of his time exercising after playing soccer on Tuesda

The given parameters are

Minutes spent on Tuesday = 27 more minutes than Monday

Total minutes spend = 60

This means that

Tuesday = Monday + 27

Monday + Tuesday = 60

Make Monday the subject in Tuesday = Monday + 27

Monday = Tuesday - 27

Substitute Monday = Tuesday - 27 in Monday + Tuesday = 60

Tuesday - 27 + Tuesday = 60

Evaluate

2 * Tuesday = 87

Divide by 2

Tuesday = 43.5

The percentage of time spent exercising on Tuesday is then calculated as

Percentage = 43.5/60 * 100%

Evaluate the expression

Percentage = 72.5%

Hence, Joel spent 72.5% of his time exercising after playing soccer on Tuesday

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The quadratic equation given in the graph can be represented in these two following ways:

The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:

[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]

In which a is the leading coefficient.

In this graph, the roots are [tex]x_1 = 0, x_2 = 4[/tex], hence the factored form of the polynomial is:

f(x) = ax(x - 4).

When x = 5, y = 10, hence the leading coefficient is found as follows:

10 = 5a(5 - 4)

5a = 10

a = 2.

Hence the factored form of the polynomial is:

f(x) = 2x(x - 4).

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

In this problem, the vertex is at point (2,-8), hence h = 2, k = -8 and:

y = a(x - 2)² - 8

When x = 5, y = 10, hence the leading coefficient is found as follows:

10 = a(5 - 2)² - 8

9a = 18

a = 2.

Hence the equation in vertex-form is:

y = 2(x - 2)² - 8

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The correct option is C. political affiliation.

An example of quantitative data are-

Data that expresses a definite quantity, amount, or range is known as quantitative data. In most cases, the data is accompanied with measuring units, such as metres in the case of a person's height. Setting boundaries for such data makes sense, and performing mathematical operations on the data has significance.

Types of Quantitative Data are-

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The complete question is-

8. Each of the following is an example of quantitative data, except ______.

A. weight in ounces

B. income in dollars

C. political affiliation

D. age in years

Answer:

Either 9.71 (adjacent to 36°) or 7.05 (opposite 36°)

Step-by-step explanation:

The question doesn't specify which leg is under question.  Is it the adacent leg or the opposite leg?  I'll assume adjacent.

We can use the acronym

SOHCAHTOA which is a helpful mnemonic for remembering the definitions of the trigonometric functions.  For an angle other than the right angle, the following relationships are defined.

SOH:  S is sine = Opposite/Hypotenuse

CAH:  C is cosine = Adjacent/Hypotenuse

TOA:  T is tangent = Opposite/Adjacent

For a side adjacent (A) to the 36° angle, we can use

Cosine = Adjacent/Hypotenuse

Since we know the hypotenuse (12) we can find A:

Cosine(36) = A/12

A = Cosine(36)*12

A = (0.809)*12

Adjacent = 9.71

====================

If the opposite leg is calculated, we would use

Sine= Opposite/Hypotenuse

Sine(36) = Opposite/12

O = (0.5877)*12

Opposite = 7.053

Answer:

See attached image

Step-by-step explanation:

I'm uncertain as to the "best statement."  None seem to accurately describe the situation. I picked the one that was least incorrect (if that makes any sense).