A parallel plate capacitor has a potential difference between its plates of 1.6 V and a plate separation distance of 2.5 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.4 is inserted between the plates

Answers

Answer 1

(a) The magnitude of the electric field of the material is 600 V/m.

(b) The magnitude of the electric field of the material in the presence of dielectric constant is 176.5 V/m.

Electric field of the material

The magnitude of the electric field of the material is calculated as follows;

E = V/d

where;

E is the electric fieldV is the potential difference between the platesd is the distance of separation

Substitute the given parameter into the equation above.

E = 1.5/(2.5 x 10⁻³)

E = 600 V/m

Electric field in the presence of dielectric constant

E = E₀/k

E = 600/3.4

E = 176.5 V/m

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Related Questions

What is radioactivity????​

Answers

Radioactivity is a nuclear phenomenon. It is the process of spontaneous emission of α (alpha particles) or β (beta particles) and γ (gamma particles ) radiations from the nucleus of atoms during their decay.

Uranium and radium are the two radioactive substances.

Explanation:

Hope it helps you!!

Answer:

radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration.

Explanation:

6. How much heat is absorbed by a persons hand if 100 grams of liquid water at 100°C is poured on his hand? (Assume the final temperature of the water will be normal body temperature of 37°C)

Answers

The heat absorbed by a persons hand is 26,359.2 J.

Heat absorbed

The quantity of heat absorbed by the persons hand is heat gained or transferred from the hot water to cold hand. This is based on the principle of conservation of energy.

The quantity of heat absorbed is calculated as follows;

Q = mcΔθ

where;

Q is the quantity of heat absorbedm is mass of the liquidΔθ is change in temperature

Q = 100 x 4.184 x (100 - 37)

Q = 26,359.2 J

Thus, the heat absorbed by a persons hand is 26,359.2 J.

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A ball is dropped off a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window what is the distance from the top of the building to the top of the window?

Answers

0.616 is the distance from the top
of the building to the top of the window.

An object of mass M is at rest at the origin at time t = 0 . At that time, a force F = A(t^2) (where A is a positive constant and F is in newtons when t is in seconds) is applied to the object. After 2 s, the velocity of the object in m/s will be

Answers

At that time, a force F = A(t²), after 2 s, the velocity of the object in m/s will be 8 (A/M) m/sec.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Let a be acceleration of mass M

By Newton 2nd Las, Force = mass * acceleration

F = A (t²) = M * a

a = A (t²) / M

By kinematics, final velocity = initial velocity + acceleration * time

Mass is at rest at t = 0 so initial velocity

So velocity after 2 s is

= 0 + A (2²) / M * 2

= 8 (A / M) m/sec

At that time, a force F = A (t²), after 2 s, the velocity of the object in m/s will be 8 A/M m/sec.

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The velocity of the object after 2 seconds will be the result of integrating the acceleration in time. The acceleration of the object is the second derivative of position, which is the first derivative of velocity. Therefore, we can calculate the velocity of the object at any time t from the formula:

velocity = integral(acceleration)

The acceleration in this case is the force F divided by the mass M, or A(t^2)/M. Therefore, *the speed of the object after 2 seconds would be:

velocity = integral(A(t^2)/M)= (A/M) * integral(t^2)= (A/M) * (t^3/3) + C

Where C is a constant of integration. Since the object was at rest at time t=0, its velocity will also be zero at that moment. Therefore, we can set C=0 and calculate the velocity of the object after 2 seconds:

velocity = (Y/M) * (2^3/3)= (Y/M) * (8/3)= (8/3) * A/M m/sAfter 2 s, the speed of the object in m/s will be 8 (A/M) m/s.

Put these 5 events in the correct order. Formation of Atoms, Time begins, Formation of Galaxies
Formation of subatomic particles, Formation of stars

Answers

Answer:

Time begins, Formation of subatomic particles, Formation of Atoms, Formation of stars, Formation of Galaxies

Explanation:

At the beginning right after the big bang time starts then sub-atomic particles forms i.e. protons, neutrons from this atoms form and after that stars and galaxies form.

Please answer this question. Thank you and have a fruitful day.

Answers

#Up

The upward force is caused by floating equipments attached below in ship to make it float.

#Down

Weight or acceleration due to gravity

F=mg

#Right

The drag force or friction from water surface

#Left

Force of motor to go ahead

You need to make a generator for your bicycle light that will provide an alternating emf whose peak value is 4.2 V. The generator coil has 55 turns and rotates in a 0.040-Tesla magnitude magnetic field.

If the coil rotates at 400 revolutions per second, what must the area of the coil be to develop this emf?

Answers

The area of the coil must be 7.6 x 10⁻⁴ m².

Peak induced emf

The peak emf induced in a coil is determined by applying Faraday's law of electromagnetic induction as shown below;

emf(peak) = NBAω

Where;

ω is the angular frequency in rad/sA is the area of the coilN is number of turnsB is magnetic field strength

[tex]\omega = 400 \ \frac{rev}{ s} \times \frac{2\pi \ rad}{1 \ rev} \ = 2,513.6 \ rad/s[/tex]

[tex]A = \frac{emf (peak)}{NB\omega} \\\\A = \frac{4.2}{55 \times 0.04 \times 2,513.6} \\\\A = 7.6 \times 10^{-4} \ m^2[/tex]

Thus, the area of the coil must be 7.6 x 10⁻⁴ m².

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why a drop of spirit on the hand feels colder than a drop of water at the same temperature​

Answers

Answer:

This is because spirit has a lower boiling point when compared to water

Explanation:

spirit has a lower boiling point when compared to water which means it has the capacity to pull more heat from your hand and also it can do this very fast. This is why our hand feels colder.

1) If the red motorcycle and the blue motorcycle have the same speed but the red one has more mass, which one has more momentum? explain

Answers

Answer:

The blue motorcycle.

Explanation:

The red one, since it has more mass, meaning it is denser, would drag on less. Less mass equals more momentum, since there is less holding it down.

1. How friction is being applied when you perform the activity in making the T-Shirt design with iron on transfer using crayons and sandpaper?

2. Describe what kind of friction is applied when you rub the crayons with the sandpaper.​

Answers

(a) The inscriptions made in the design is possible due to friction when carving.

(b) The friction applied when you rub the crayons with the sandpaper is kinetic friction

What is friction?

Friction is a force that opposes two surfaces that are in contact. It limits the movement between these two surfaces.

Friction applied in the design

The inscriptions made in the design is possible due to friction when carving.

Friction between the crayon and sandpaper

There are two types of friction, static and kinetic friction. The friction applied when you rub the crayons with the sandpaper is kinetic friction because of there is movement between two surfaces.

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Describe how to make an electromagnet. Use the following words and phrases:

Power supply, coil of wire, current, iron core

Answers

Required items:

battery a coil of wireiron core

Electromagnet can be created by wrapping a coil of wire on top of the iron core and passing an alternating current through it with the help of power supply.

the magnetic field will be constantly changing.

Answer:

Explanation:

Unlike permanent magnet, electromagnet require a power supply to work.  The power supply drives an electric current through coil of wire wrapped around an iron core.

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A student taking an Earth Science class tries to move a rock with a weight of 10,000 N. He strains and huffs and puffs but fails to budge the rock. How much work did your friend do?

Answers

Answer:

zero

Explanation:

zero, because no displacement

(a ) A 14 turns circular coil is placed on a paper which lies in 1.2 T magnetic field pointing inwards to the paper. The coil's diameter changes from 22.5 cm to 7.2 cm in 1.8 s.
(i) Determine the direction of the induced current. .
(ii) Calculate the magnitude of the emf induced in the circuit.
(iii) Calculate the induced current if the circular coil resistance is 7.5 Ω

(b) A circular coil of N turns with current 9.4 mA has an inductance 15 mH. Calculate
(i) magnetic flux linkage through the coil. (ii) radius of the coil if N = 420 turns.​

Answers

(i) The direction of the current will be in opposite direction to the magnetic field.

(ii) The magnitude of the emf induced in the circuit is 0.359 V.

(iii) The induced current if the circular coil is 0.048 A.

b(i) The magnetic flux linkage through the coil is 1.41 x 10⁻⁴ Tm².

b(ii) The radius of the coil is r√3 m.

Direction of the current

The direction of the current will be in opposite direction to the magnetic field.

Emf induced in the circuit

Initial area of the coil = (πd²)/4

Initial area of the coil = (π x 0.225²)/4 = 0.0398 m²

Final area of the coil = (π x 0.072²)/4 = 0.001296 m²

[tex]emf = \frac{NB(A_1 - A_2)}{t} \\\\emf = \frac{14 \times 1.2(0.0398 - 0.001296)}{1.8} \\\\emf = 0.359 \ V[/tex]

Induced current

I = emf/R

I = 0.359/7.5

I = 0.048 A

Magnetic flux linkage through the coil

Ф = LI

Ф = 0.015 x 0.0094

Ф =  1.41 x 10⁻⁴ Tm²

Radius of the coil

[tex]L = \frac{\mu_o N^2\pi r^2}{l} \\\\r^2 = \frac{Ll}{\mu_o N^2\pi } \\\\r = \sqrt{\frac{Ll}{\mu_o N^2\pi } } \\\\r = \sqrt{\frac{0.015(l)}{4\pi\times 10^{-7} \times (420)^2 \pi } } \\\\r = 3 \sqrt{l} \ m[/tex]

where;

l is length of the coil

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a measure has true value of 2.00and the measurement value was found to e 1.95.calculate the precision of the measuring instruments​

Answers

Answer:

(2 - 1.95 / 2) = .05 / 2 = .025 or 2.5 %

The value found should be within ±2.5%

The precision of the measuring instruments will be 2.5%.

What is precision?

It should be noted that precision simply means how close a test result will be when it's repeated.

In this case, the precision of the measuring instruments will be:

= (2 - 1.95)/2.

= 0.05/2

= 2.5%

Therefore, the the precision of the measuring instruments will be 2.5%.

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Kraig pulls on a rope attached to a box with a mass of 500kg to the right at an angle of 40 degrees to the horizontal with a force of 30 N for 150 seconds. The box does not move from its’ original position, determine the work done by Kraig.

Answers

Answer:

zero

Explanation:

The box does not move from its’ original position, so the displacement is zero, then the work done is zero.

which of the following can enter and exit an open system?
A. Matter but not energy
B. energy but not matter
C. Matter and energy
D. Neither energy nor matter

Answers

A open system that is open to its surroundings can trade both matter and energy.

In an open system, what is possible?

Both matter and energy can be transferred between an open system and its surroundings. The stovetop example would be regarded as an open system because heat and water vapour might be lost to the atmosphere. On the other hand, a closed system can only exchange energy, not matter, with the environment.

A system is considered to exist when energy can enter or escape it.

A closed system is a type of thermodynamic system in which mass is conserved within the system's boundaries but energy can easily enter or leave the system. Depending on what is being exchanged, the interactions between the system and its environment alter.

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Answer: C

Explanation:

i just took it

Use this sentence: A large tray is filled with flour and a fan is turned on so that it blows wind across the top.

Which natural process is this modeling?

(1 point)


physical weathering (i picked this)

chemical weathering


erosion


deposition

Answers

Answer: Physical weathering

Explanation:

Find the period of oscillation of a pendulum with a length of 0.75 m.

Answers

Answer:

1.74 s

Explanation:

[tex]T=2\pi\sqrt\frac{L}{g}=2\pi\sqrt\frac{0.75}{9.81}[/tex]

T = 1.74 s

A plane took from Chicago to Paris 8 h to finish a journey. If the distance of the journey was 6600 km, at what average speed did the plane travel​

Answers

Answer:

825 km/hr

Explanation:

To find the average speed, you simply have to divide the distance by the time taken.

Distance travelled = 6600 km

Time Taken: 8 hours

Average speed = 6600 ÷ 8 or 6600/8 = 825 km/hr

Your final answer would be the plane travelled at an average speed of 825 kilometres per hour.

_________________ usually have larger amplitudes and longer wavelengths.

A. Surface waves

B. Transverse waves

C. Compression waves

D. Longitudinal waves

Answers

Answer:

longitudinal wave

i guess

sry if its wrong

Write a script that depicts an employer meeting expectation and failing meeting expectations

Answers

Answer: On Monday, XX/XX, the XXXX you presented in our weekly review were not accurate and I’m worried that this reflected poorly on our team’s credibility. This could negatively impact senior leadership’s confidence in our team’s effectiveness at a time when headcount is already being scrutinized and potentially eliminated. Next time you present XXXX, my expectation is that everything will have been double or triple-checked in advance of the meeting so that all figures are reported accurately.

Statement: Baseball is not a dangerous sport unless either a bat breaks or a player is hit with a ball.
Key: B = A bat breaks.
D = Baseball is a dangerous sport.
P = A player is hit with a ball.

Answers

Answer:

P

Explanation:

If the bat break it will get replaced and you will get another bat,but if u get hit with the ball it's dangerous in many ways

A spring that can be assumed to be ideal hangs from a stand, as shown above. The spring constant, k, of an ideal spring is defined as the force per unit length and differs from one spring to another. It can be measured in both a static (motionless) and dynamic (in motion) mode A You wish to determine experimentally the spring constant k of the spring in a static (motionless) situation What additional, commonly available equipment would you need? ü What measurements would you make? m. How would k be determined from these measurements? 1 B. You wish to determine experimentally the spring constant k of the spring in a dynamic (moving) situation. What additional, commonly available equipment would you need? What measurements would you make C. Assume that the spring constant is determined to be 500 N/m A 20 kg mass is attached to the lower end of the spring and released from rest. Determine the frequency of oscillation of the mass

Answers

(a) The additional commonly available equipment you would need is stop watch.

(b) The measurement obtained with stop watch is period of oscillation. The period of oscillation can be used to determine angular speed and the angular speed is used to determine the spring constant.

(c) The frequency of oscillation of the mass is 0.8 Hz.

Value of spring constant from experiment

The value of spring constant can be determined experimentally with a mass and stop watch to record the period of oscillation.

How to calculate spring constant

k = ω²m

where;

ω is angular speed = 2πf = 2π/Tm is mass

With a known mass attached to the spring, the period of the oscillation can be determined using stop watch. The period of the oscillation can be used to determine the frequency and angular speed of the oscillation. The angular speed can be used to determine the spring constant, K.

Frequency of the oscillation

ω² = K/m

ω² = 500/20

ω² = 25

ω = √25

ω = 5 rad/s

ω = 2πf

f = ω/2π

f = 5/2π

f = 0.8 Hz

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(6) Two long, straight, parallel wires carry currents that are directed perpendicular to the page as shown in Figure. Find the value and direction of hy in terms of I to have net magnetic field equal zero at the origin.​

Answers

The point at which the net magnetic field will be zero, the magnetic field due to first wire must be equal and opposite in direction to the magnetic field due to the second wire.

Magnetic field between two the parallel wires

The magnetic field between two parallel wires is determined as follows;

B = μI/2πd

where;

B is magnetic field strengthI is the current in one wired is the distance between the parallel wires.

From the formula above we can conclude that, the point at which the net magnetic field will be zero, the magnetic field due to first wire must be equal and opposite in direction to the magnetic field due to the second wire.

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Compare the gravitational acceleration on the following objects compared to the Sun using:
g(star)/g(Sun) =(M(star)/M(Sun) )/〖(R(star)/R(Sun) )〗^2

Object M(star)/M(Sun) R(star)/R(Sun) g(star)/g(Sun)
White dwarf
Neutron star
Star Betelgeuse

Answers

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

Mass of the planets

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765  x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

Radius of the planets

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

Gravitational acceleration of White dwarf compared to Sun

[tex]\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86[/tex]

Gravitational acceleration of Neutron star compared to Sun

[tex]\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}[/tex]

Gravitational acceleration of Star Betelgeuse compared to Sun

[tex]\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}[/tex]

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1. A cart moving at 5.0 m/s is brought to a stop by the force plotted in the force-time graph shown here. Find the impulse and the approximate mass of the cart. Show all your work

Answers

Answer:

Impulse is 0.4 x 18= 7.2

Explanation:

Impulse is defined as the integral of force over the time duration. When you do the integration of Newtons second law, momentum is

[tex]\int\limits^a_b {F} \, dt =\int\limits^a_b {\frac{dp}{dt} } \, dt[/tex]

= Δp

If momentum p is defined as the integral of force per unit time, then we can take the area under the curve to find momentum, as the area under the curve can approximate the integral of the function.

Therefore, to quickly summarize, taking the maximum force, 18N , multiplied by duration of the interaction, which is 0.5s-0.1s=0.4s, will give your momentum, in the units of  kg•m/s.

Hope that helps!

PLEASE HELP ASAPPP !!!!!!

Answers

Answer:

the answer is the answer

Explanation:

if you find the answer you get the answer

What do waves transfer? Question 1 options: only matter energy only water only particles

Answers

Answer:

they transfer Matter and energy

What is the mass of a 330 N television? The acceleration due to gravity at the surface of Earth is 9.8 m/s^2

Answers

Answer: 33.7kg

Explanation:

Using Newton's 2nd Law, the force of gravity is equal to the mass times the acceleration:
[tex]F=ma[/tex]

The force would be the weight due to the gravitational field. And the acceleration would be the one due to gravity:

[tex]330N=m(9.8m/s^2)[/tex]

[tex]m=330/9.8[/tex]

[tex]m=33.7kg[/tex]

An undersea research chamber is spherical with an external diameter of 6.20 m. The mass of the chamber, when occupied, is 60400 kg. It is anchored to the sea bottom by a cable. The density of sea water is 1025 kg/m3. Calculate the following: (express your answers using appropriate mks units.)

(a) the buoyant force on the chamber

(b) the tension in the cable

Answers

I think the answer is b
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