A particule accelerates uniformly from rest at 6.0m/s for 8seconds determine the magnitude of its velocity​

Answers

Answer 1

The particle has a 48 m/s maximum velocity.

How can I calculate the speed of an object?

The equation for uniformly accelerated motion, which states that an object's final velocity, v, is equal to its beginning velocity, u, plus the product of its acceleration, a, and the time taken, t, serves as the theoretical foundation

As v = u + at, this formula can be used.

Following are the procedures to determine a particle's velocity:

Use the equation v = u + at in step one, where v is the end velocity, u is the beginning velocity, an is the acceleration, and t is the duration.

Substitute the values into the formula in step 2 to complete. Here, u = 0 (since the particle is initially at rest),

a = 6 m/s2 and t = 8 s

v = 0 + (6 m/s2) × (8 s) (8 s)

v = 48 m/s

The particle's speed is therefore 48 m/s on average.

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Related Questions

which of the following set of tools would be most useful in an experiment measuring the rate of thermal energy in four different liquids? ​

Answers

What are the answer choices? To measure liquids u use a thermometer

The wave speed on a string is 155 m/s when the tension is 78.0 N .What tension will give a speed of 177 m/s ?

Answers

If the linear mass density of the string stays constant, a tension of 4.92 x 10⁴ N will result in a wave speed of 177 m/s.

Examples of wave speed formula what is it?

When the wavelength and wave frequency are known, the wave speed equation may be used to get the wave speed. Think about a wave in the water that has a 1 hertz frequency and a wavelength of 3 metres. Speed is calculated as follows: Speed = 3 m x 1 wave/s = 3 m/s.

v = √(T/μ)

where v is the wave speed, T is the tension in the string, and μ is the linear mass density of the string (mass per unit length).

To solve for the tension T, we may rearrange this equation as follows:

T = μv²

So, if we want to find the tension required to give a wave speed of 177 m/s, we can plug in the given values and solve for T:

T = μv² = (155 g/m) x (177 m/s)² = 4.92 x 10⁴ N

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A car starts from rest and travels 33m in 4 seconds. How far will it travel in 8 seconds?

Answers

Answer: 66m

Explanation:

If the car travels 33m in 4 seconds, the car travels at a speed of 33/4 meters per second.

Using this, we can find the distance traveled in 8 seconds, which is

33/4*8

= 66

Therefore, we can find that the car travels 66m in 8 seconds.

A pulse has a speed of 5cm.s^-1 how far does it travel in 2,5

Answers

The distance travelled by the pulse in 2.5 seconds is 12.5 cm.

What is the distance travelled by the pulse in 2.5 seconds?

The distance travelled by the pulse in 2.5 seconds is calculated by applying the speed, time and distance equation as shown below.

Mathematically, speed, distance and time equation is given as;

d = v x t

where;

v is the speed of the pulset is the time of motion of the pulse

The distance travelled by the pulse in 2.5 seconds is calculated as;

d = ( 5 cm/s ) x  ( 2.5 s )

d = 12.5 cm

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The complete question is below:

A pulse has a speed of 5cm.s^-1 how far does it travel in 2.5 seconds?

What type of electromagnetic wave is sent as a signal by a cell phone to the nearest cell tower?

Answers

The type of electromagnetic wave sent as a signal by a cell phone to the nearest cell tower is radio waves.

Cell phones use radio waves, a type of electromagnetic radiation, to communicate with the nearest cell tower. Radio waves have the longest wavelength and the lowest frequency of all electromagnetic waves. They fall within the frequency range of 3 kHz to 300 GHz. They are used for a wide variety of communications including television and radio broadcasting, cell phone and satellite communications, and wireless networking.

When a call is made or data is sent on a cell phone, the phone sends out a radio frequency (RF) signal to the nearest cell tower. The tower then sends the signal to the intended recipient. The signal is sent using a specific frequency band that is assigned for cellular communication. This frequency band is divided into smaller frequency channels and each channel is assigned to a specific cell phone call or data transfer.

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Answer: The type of electromagnetic wave sent as a signal by a cell phone to the nearest cell tower is radio waves.

Explanation: Cell phones use radio waves, a type of electromagnetic radiation, to communicate with the nearest cell tower. Radio waves have the longest wavelength and the lowest frequency of all electromagnetic waves. They fall within the frequency range of 3 kHz to 300 GHz. They are used for a wide variety of communications including television and radio broadcasting, cell phone and satellite communications, and wireless networking.

An object is placed 40 mm away from a diverging lens with a focal length of 10 cm. Find the object distance and determine whether the image is upright or inverted and real or virtual.

Answers

The distance between the object and a diverging lens is -20 cm and the image is virtual and inverted.

How to calculate object's distance?

The object distance for this scenario is 40 mm, as given in the problem statement.

To determine the image properties, we need to use lens equation which is 1/f = 1/u + 1/v where f is the focal length, u is the object distance and v is the image distance.

Using the given information, the lens equation can be written as:

1/10 = 1/40 + 1/v

Solving for v, we get:

v = -20 cm

As the image distance is negative, it means that the image is virtual and inverted.

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A ball is dropped from the top of a building. After 2 seconds, its velocity is measured to be 19.6 m/s. Calculate the acceleration for the dropped ball.

Answers

9.8m/s²

Explanation:

the acceleration is the acceleration due to gravity which is 9.8 m/s² downwards.

for proof;

V=u+at

where v=final velocity

u= initial velocity

t=time

u=0, v=19.6m/s, t=2

19.6=0+a×2

19.6=2a

a=19.6/2

a=9.8m/s²

At t=3s, Bob was at x=9. If Bob has an average velocity of -4/s, what is his velocity at 11s?

Answers

The velocity of Bob at 11 seconds is 4.27 m/s.

What is the velocity of Bob at 11 seconds?

The velocity of Bob at 11 seconds is calculated by applying average velocity formula as shown below.

v = ( total displacement ) / ( total time )

v = ( X₃ + X₁₁ ) / ( 3 + 11 )

where;

X₃ is the displacement at 3 secondsX₁₁ is the displacement at 11 secondsv is the average velocity = 4 m/s

4 = ( 9 + 11u ) / ( 14 )

where;

u is the velocity at 11 s

The velocity of Bob at 11 seconds is calculated as;

4 = ( 9 + 11u ) / 14

9 + 11u = 56

11u = 56 - 9

11u = 47

u = 47 / 11

u = 4.27 m/s

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The amount of kinetic energy (KE) depends on the mass of a moving object.
True
False

Answers

Answer: True

Explanation: To calculate KE you use 1/2 Mass x velocity^2

In the metric mks system of units, the letter k stands for

Answers

In the metric MKS system of units, the letter k stands for kilogram (kg).

What is MKS system of units?

The metre, kilogram, and second (MKS) serve as the foundational units in the MKS system of units, which is a physical method of measurement. The International System of Units (SI) is built on top of it, albeit SI has since been modified with new fundamental constants.

Following the Metre Convention of 1875, work on the kilogramme and metre international prototypes began. These prototypes were officially approved by the General Conference on Weights and Measures (CGPM) in 1889, formalizing the MKS system by utilizing the kilograms and metre as base units.

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The tracking of the direction of the wind as it moves from areas of
high pressure to areas of low pressure is

Answers

Tracking wind direction from high pressure areas to low pressure areas is called the Coriolis effect.

What is the Coriolis effect?

As air tries to move from high to low pressure in the atmosphere, the Coriolis force diverts the air so that it follows the pressure contours. This means that in the Northern Hemisphere, air is blown anticlockwise around low pressure and clockwise around high pressure.

Winds flow counterclockwise (cyclonically) around low pressure and clockwise (anticyclonically) around high pressure at the surface. These systems' actual pressure can be measured in either inches of mercury or millibars.

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An amusement park ride consists of a rotating

circular platform 8.73 m in diameter from

which 10 kg seats are suspended at the end

of 3.76 m massless chains. When the system

rotates, the chains make an angle of 23.9◦ with

the vertical.

The acceleration of gravity is 9.8 m/s^2

Answers

The centripetal acceleration of the system is: a_c = (v^2)/r , v = (r * ω) An amusement park ride consists of a rotating.

What is centripetal acceleration?

Centripetal acceleration is the acceleration of an object in a curved path. It is directed towards the center of the circle and is equal to the square of the object's velocity divided by the radius of the circle.

Where ω is the angular velocity of the system

ω = 2πf

Where f is the frequency of rotation

f = (1/T)

Where T is the period of rotation

T = (2π * (8.73m/2))/ (3.76m/s)

v = (r * (2π * (1/T)))

a_c = ((r * (2π * (1/T)))^2)/r

a_c = (2π^2 * (8.73m/2)^2 * (1/T^2))/ (8.73m/2)

a_c = (2π^2 * (8.73m/2) * (1/T^2))

a_c = (19.64 * (1/T^2))

a_c = (19.64 * (1/((2π * (8.73m/2))/ (3.76m/s))^2))

a_c = (19.64 * (1/((2π * (4.365m))/ (3.76m/s))^2))

a_c = (19.64 * (1/(2π * (1.163m/s))^2))

a_c = (19.64 * (1/(2π * (1.163m/s))^2))

a_c = 19.64 * (1/3.8139)

a_c = 5.12 m/s^2

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4. A car travels at a speed of v = 54 km/h. During emergency braking, the wagon decelerates (brakes) with a deceleration (braking) of 3m/s per second. a) Convert the speed into the unit m/ s.b) Calculate how long the braking lasts. c) Sketch the v-t diagram and calculate the braking distance!​

Answers

The given velocity is 54km/hr, which, when converted to m/s using 1km = 1000m and 1 hour = 3600 seconds, equals 15m/s.

How to calculate distance?

Now substitute the initial speed u = 15m/s values.

v = 0m/s as the final velocity

Time is 6 seconds.

In the a= -3 m/ s2 equation,

s= ut + 1/2at2 s= 15 6+ 1/2(-3)(6)2 s= 90-45 s = 45m

As a result, after using the brakes, the car will halt for up to 45 meters.

The inverse of acceleration is deceleration. The deceleration will be calculated by dividing the final velocity minus the initial velocity by the time required for the velocity drop.

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4. Compare energy transformation in fossil fuel
combustion and fuel cells.

a) How are these processes similar?
b) How do they differ?

Answers

When compared to combustion engines, fuel cells emit either no emissions or very little.

What happens to energy when it is transformed in fossil fuels?

The process of converting energy starts with chemical energy that is held in the fuels, moves through heat energy during combustion, kinetic energy during the rotation of massive turbines, and ends with electrical energy. The environmental impact of using fossil fuels is a problem.

Compared to combustion engines, fuel cells run more efficiently and are capable of directly converting the chemical energy in fuel into electrical energy at efficiencies of more than 60%. The combustion process needs oxygen. Hydrocarbons, which make up the majority of fossil fuels, undergo combustion to produce carbon dioxide and water. The cleanest burning fossil fuel we are aware of is natural gas.

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Identify the source of thermal energy in an internal combustion engine.

Answers

The source of thermal energy in an internal combustion engine is the combustion of fuel.

What is thermal energy?

Thermal energy is the energy contained within a system that controls its temperature. The flow of thermal energy is defined as heat. The internal combustion engine works by igniting a mixture of fuel and air inside the engine's cylinders.

The combustion process releases heat energy, which is used to heat up the working fluid (usually air) which then expands and generates mechanical power to move the vehicle. This process converts the chemical energy stored in the fuel into thermal energy which then converted into mechanical energy to move the vehicle.

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Answer: combustion of fuel

Explanation:

What are the types of contexts that are most influential in early childhood? How does this shift when children start school, and why does the relative importance of different contexts shift as children age?

Answers

Neighborhood, familial, and sociodemographic factors make up the three contextual factors.

Developmental theory and research emphasize a variety of contexts for children's development, including families, peers, schools, and neighborhoods. 1 These contexts are distinct from the other child development and well-being categories and should be assessed separately. Knowing whether or not a child is overweight or exercises enough, for example, can help describe the physical health of the child in a meaningful way.

Children from homes where the parents may or may not exercise frequently or actively encourage their children to exercise represent family situations that affect children's development and welfare. The family's level of money has an impact on the child's access to food as well (socio-demographic context).

In early life, gender is one of the clearest and most reliable signs that allows us to categorize our social environment. In the early stages of development, a person's ethnic origin does not provide the infant with any information beyond his perceptible characteristics; however, age can be a reliable indicator of expertise, competence, reliance, and authority, and gender can provide accurate information about potential areas of interest. Therefore, unlike someone who just shares the same hue, infants and children may have expectations regarding shared knowledge with someone who has or does not have the same competence (age) and interest (gender).

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“We are observing wasted heat in everyday life for example in Pakistan heavy generated are installed, during their supply of electricity an excessive amount of wasted heat is produced in its surrounding, similarly when we drive a vehicle a heat is available in the surrounding of engine of that vehicle, we can also see many more such examples of wastage of heat. This heat is effecting the environment of Pakistan badly.

Is it conceivable to convert this wasted heat into some useful work/energy/electricity or not. If yes how? If no why

Answers

It is indeed possible to convert wasted heat into useful work, energy, or electricity. This process is known as "waste heat recovery," and it involves capturing the heat that is normally released into the environment and using it to generate electricity or to perform other useful work.

What are the ways to convert wasted heat into electricity?

There are several ways to convert wasted heat into useful energy or electricity:

Heat exchangers: These devices transfer heat from one fluid to another, and can be used to capture heat from industrial processes, engines, and other sources.

Thermoelectric generators: These devices use the difference in temperature between two materials to generate electricity. They can be used to capture heat from engines, industrial processes, and other sources.

Organic Rankine Cycle (ORC) systems: These systems use a working fluid (such as water or a special fluid) to convert heat into mechanical energy, which can then be used to generate electricity.

Combined heat and power (CHP) systems: These systems generate electricity and heat simultaneously, by using waste heat to generate electricity and using the heat generated by the electricity-generating process to heat buildings or other spaces.

In Pakistan, it is possible to recover the wasted heat generated by the power plants and use it to generate electricity or perform other useful work. The government of Pakistan should invest in technology and research to develop these systems to minimize the environmental impact of wasted heat and to improve energy efficiency.

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1- Find the center of mass of the three-mass system shown in Fig. Specify relative to the left-hand 1.00-kg mass.
1.00 kg
1.50 kg 1.10 kg
0.50 m
0.25 m

Answers

The center of mass of the three-mass system will be 0.438

What is a center of mass?

A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component. The center of mass is situated at the centroid for straightforward stiff objects with homogeneous density.

The first mass m1 = 1.00 kg

The second mass m2 = 1.50 kg

The third mass m3 = 1.10 kg

If the origin of the system is from the mass m1

The distances from the origin to the masses are

x1 = 0

x2 = 0.5 m

x3 = (0.5 + 0.25) m = 0.75 m

Center of mass = (m1x1 + m2x2 + m3x3) / (m1+m2+m3)

                           = (1*0 + 1.5*0.5 + 1.1*0.75) / (1+1.5+1.1)

                          = 0.438

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Pulley system is marked wih a Mechanical Advantage of 2.5. A worker applies 450n to the pulley in an attempt to lift a sound system with a 1500n weight. Of this task we could say that:

Answers

The worker must apply 600N of force to lift the sound system. The mechanical advantage of 2.5 means that the worker only needs to apply 600N of force to lift the sound system.

What is Pulley system?

We can employ pulley systems to provide ourselves a mechanical advantage by multiplying our input effort to apply more force to a load.

They can be used to apply tension within a system, such as in a Tensioned Line or Tyrolean, in addition to their traditional uses of hauling and lifting loads. The basic operating principles of pulley systems are explained on this page; for details on how to use them for hauling, check the topic on hauling systems.

The dynamic unit of Newtons is commonly used to express force, which is an impact that has both magnitude and direction (N). On this page, kilograms have been utilized for the sake of clarity.

Therefore, The worker must apply 600N of force to lift the sound system. The mechanical advantage of 2.5 means that the worker only needs to apply 600N of force to lift the sound system.

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Does changing the amount of a substance change its mass volume or density

Answers

Changing the amount of a substance changes its mass or volume but won't change its density.

What is Density?

This is used to describe how compact a material is and it is also the mass per unit volume of a material substance with its S.I unit being  grams per cubic centimetre.

We should note that hanging the amount of a substance changes its mass or volume .However ,if the amount of matter is increased without changing the volume, then the density increases which is therefore the reason why it was chosen as the correct choice.

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2. The diagram below shows two charged spheres that are separated by a distance of 3.8 x 104 m.
What is the force between the two spheres, and is it attractive or repulsive? SHOW ALL WORK
- 3.8 X 10-4 m
K
A
5.2 X 10-6 C
B
-6.2 x 10-6 C

Answers

The charges are of the same type. As a result, any force exerted between them will be repulsive.

What exactly is force?

Force is an influence that causes an object to accelerate, decelerate, or change its direction of motion. It is a vector quantity, meaning it has both magnitude (strength) and direction. Examples of forces include gravity, friction, electromagnetic fields, and the applied force of pushing or pulling on an object.

The charges of the same nature repel each other because of the electrostatic force of repulsion. This is because like charges have the same sign and the electrostatic force of repulsion between them is stronger than the attraction between opposite charges. This repulsive force increases as the distance between the charges decreases. This is why two objects with the same charge will be pushed away from each other.

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Are we more than flesh and blood ?

Answers

All human being are more than flesh and Blood we can do mechanical , Inteligence and other things that only blood and Flesh can not make up.

What is Human Body Composition ?

Only six elements make up the majority of the human body: oxygen, hydrogen, nitrogen, carbon, calcium, and phosphorus. The remaining mass is composed of sulphur, potassium, sodium, chlorine, and magnesium, which together make up around 0.85% of the total mass. These 11 components are all necessary components.

Cells, which are regarded as the basic building blocks of life, make up every living thing. Even one-celled creatures are sophisticated! Atoms create molecules, which create the cell organelles and structures within each cell. Similar cells form tissues in multicellular organisms.

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Jacobie wanted to test the projectile motion of a pumpkin. His hypothesis was if the pumpkin had a larger mass, then the higher he could throw it, because the larger pumpkins would have more force. He bought three orange pumpkins and tested them all on the same day. His results are shown at right. Does the data support his hypothesis?

Answers

The data does not support his hypothesis because the heaviest mass travelled the least distance.

How does mass affect the height travelled by an object?

The weight of an object is the force of gravity acting on the object and the force of gravity increases with increase in the mass of the object.

W = mg

where;

m is the mass of the objectg is acceleration due to gravity

Based on law of conservation of energy;

P.E = K.E

mgh = ¹/₂mv²

h = ( v² ) / ( 2g )

The height travelled by an object increases with increase in speed of the object and heavier objects will have greater speed, hence travel greater height.

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The complete question is below:

Jacobie wanted to test the projectile motion of a pumpkin. His hypothesis was if the pumpkin had a larger mass, then the higher he could throw it, because the larger pumpkins would have more force. He bought three orange pumpkins and tested them all on the same day. His results are shown at right. Does the data support his hypothesis?

5kg = 10meters

10kg = 5 meters

15kg = 1 meter

A horizontal force of 600 N is used to push a box 8 m across a room. Which of
these variables must be known to determine the power used in moving the box?

A.The potential energy of the box.

B.The weight of the box.

C.The length of the box.

D.The time it takes to move the box.

Answers

Answer: B.
the answer is b because it is

The variables must be known to determine the power used in moving the box is the time it takes to move the box.

Which factor is used to calculate force?Isaac Newton's second rule of motion, which says that the net external force on an object is equal to the product of its mass and acceleration, is where the standard force formula is obtained. Force is simply defined as mass times acceleration.Power is determined by the product of force, velocity, and distance travelled (in the force's direction). (However, this only functions if the velocity is constant; in other words, the force is not the force acting as a result of the moving item.)A horizontal force is one that moves in a direction perpendicular to the horizon.

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Which graph represents y=x²-b.
where b is a positive real number?
J
K
L
M
N

Answers

According to the question,M  is a positive real number.

What is the positive ?

The positive is having an optimistic outlook on life. It means looking on the bright side of things, maintaining a positive attitude, and having hope for the future. Having a positive attitude can help you to stay motivated and focused, even when things get tough. It can also help you to build strong relationships with others and make the most of opportunities. Being positive can lead to greater success and improved well-being.It can also help you to build strong relationships with others and make the most of opportunities. Being positive can lead to greater success and improved well-being.

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"a crate is released from the highest point of a 12m ramp inclined at 45 degrees with the horizontal. The motion is frictionless. What is the speed of the crate at the base of the ramp? "

Answers

Answer:

mgh=1/2  m v^2

Explanation:

mgh=1/2  m v^2

v =sqrt( 2gh)

What force is required to move a 4 kg object in a circle with an acceleration of 5.7 m/s2?

Answers

Answer: Therefore, to move a 4 kg object in a circle with an acceleration of 5.7 m/s², it requires a force of 22.8 Newton.

Explanation:

What force is required to move a 4 kg object in a circle with an acceleration of 5.7 m/s²?

Data:

F = force =

m = mass = 4 kg

a = acceleration = 5.7 m/s²

To solve, we apply the formula of Newton's Second Law, which is F = m * a, it is not necessary to solve, since we want to calculate the force, then

F = m * a F = 4 kg * 5.7 m/s² F = 22. 8 N

Therefore, to move a 4 kg object in a circle with an acceleration of 5.7 m/s², it requires a force of 22.8 Newton.

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Formula for force:

[tex]F=ma[/tex]

force(measured in newtons) = mass(measured in kg) * acceleration(measured in m/s^2)

__________________________________________________________

Given:

[tex]m=4kg[/tex]

[tex]a=5.7m/s^2[/tex]

[tex]F=?[/tex]

__________________________________________________________

Finding force:

[tex]F=ma[/tex]

[tex]F=4\times5.7[/tex]

__________________________________________________________

Answer:

[tex]\fbox{F = 22.8 Newtons}[/tex]

Suppose a man's scalp hair grows at a rate of 0.37 mm per day. What is this growth rate in feet per century?

Answers

Suppose a man's scalp hair grows at a rate of 0.37 mm per day. this growth rate in feet per century is: 44 ft per century .

How to find the growth rate in feet per century?

1m = 1000mm

1m = 3.281ft

1 day = 25 hours

1 year = 365 days

1 century = 100 years

Growth rate = 0.37 mm per day

Now let find the growth rate in feet per century

Growth rate in feet per century = (0.37 mm / day) × (1m / 1000 mm) ×( 3.281ft/ 1m) × (365 days/ 1year) × (100 year/ 1 century)

Growth rate in feet per century = 44 ft per century

Therefore we can conclude that the growth rate in feet per century is 44ft per century.

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A jet aircraft being launched from an aircraft carrier is accelerated from rest along a 94-meter track for 2.5s. What is the launch speed of the jet?

Answers

Explanation:

To solve for the launch speed of the jet, we need to use the equation of motion: v = at, where v is the final velocity, a is the acceleration and t is the time.

Given, a = 94m / (2.5s)^2 = 18.72 m/s^2

And t = 2.5s

So, v = at = 18.72 m/s^2 x 2.5s = 46.8 m/s.

Therefore, the launch speed of the jet is 46.8 m/s.

Answer:

46.8 m/s.

Explanation:

Planet Q in an extra-solar system has a period of 712 days and an orbital radius of 6.0 AU. Calculate the length of the orbital period of a second Planet R if it's orbital radius is 12 AU.

Answers

Planet Q in an extra-solar system has a period of 712 days and an orbital radius of 6.0 AU. The orbital period of Planet R is approximately 2036.467821 days.

What is the length of the orbital period?

Generally, We can use Kepler's third law of planetary motion to calculate the length of the orbital period of Planet R.

Kepler's third law states that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit. More specifically, the equation is:

T^2 = k * (a^3)

where

T is the orbital period, a is the semi-major axis of the orbit (which is equal to the orbital radius in this case), and k is a constant.

Since we know that Planet Q has an orbital period of 712 days and an orbital radius of 6.0 AU, we can use this information to find the value of k. We can plug in the known values and solve for k:

712^2 = k * (6.0^3)

k = (712^2) / (6.0^3)

Now that we know the value of k, we can use it to find the orbital period of Planet R. We know that Planet R has an orbital radius of 12 AU, so we can plug this value into the equation and solve for T:

T^2 = k * (12^3)

[tex]T = \sqrt(k * (12^3))\\\\T = \sqrt(((712^2) / (6.0^3)) * (12^3))\\\\T = \sqrt(((509824) / (216)) * (1728))\\\\T = \sqrt(509824 * 1728) / 216\\\\T = \sqrt(895795456) / 216\\\\[/tex]

T = 2036.467821 days

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