A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to reverse your car If you can't do it
Red is typically used to indicate danger or warning, and on traffic lights, it indicates a potential hazard ahead and, as a result, serves as a signal for drivers to stop. If the traffic light turns red while you are already at a junction, you must move swiftly to the opposite side to avoid a potential accident with oncoming traffic.
If the traffic light has turned red as you approach the junction and you are just entering it, you must stop. Unless there is a sign clearly telling you not to turn left at the red light, you may do so. Give way to people and cars coming from other directions when turning.
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Answer: you are not allowed to turn left on a red light from a two way to a two way
A force of 50 n is used to push a wheelchair forward at constant velocity. if the wheelchair is displaced 0.5 m each second, what is the mechanical power expended when transporting the wheelchair?
The mechanical power expended when transporting the wheelchair is 25 Watts
What is power?Power is defined as the amount of energy transferred or converted per unit time. The unit of power is measured in Watts. The higher units are kilowatts, megawatts etc.
The formula for calculating the power expended is expressed as:
Power = Workdone/Time
Since workdone = force * distance, the formula for power will be:
Power = Force*distance/Time
Given the following parameters
Force = 50N
distance = 0.5m
time = 1 second
Substitute to determine the power
Power = 50*0.5/1
Power = 25/1
Power = 25Watts
Hence the mechanical power expended when transporting the wheelchair is 25 Watts
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The flywheel shown has a radius of 20 in., a weight of 330 lbs, and a radius of gyration of 15 in. A 110-lb block A is attached to a wire that is wrapped around the flywheel, and the system is released from rest. The effect of friction is neglected.
The acceleration Block A is derived as a= 11.983ft/s². See explanation below.
What is the calculation deriving the above?Recall that we are given the following:
Radium = 20 inches
Weight = 330lbs
Radius of gyration = 15in
Mass of Block = 110lb
The formula for Moment of Inertia is also given as:
I = mk²
= 330 [ 15/12]²
I = 515.625 lb/ft²
To derive the moment about O, we recourse to
∈M₀ = I∝
TR = I∝
T [20/12] = 515.625 ∝
T = 309.375∝
Next, to derive the weight of the block A hanging freely,
Wa = MAg
= 110 x 32.2
= 3542 lbf
Acceleration is derived by
A = r∝
= [20/12] ∝
a = 1.667 ∝.........Lets call this equation 1
Value of the acceleration derived by Dalembert Principle
∈Fy = mAa
Wa-T = mAa
3542 - 309.375∝ = 110 x 1.667∝
3542 = 492.745∝
∝ = 7.8188 Rad/s²............Lets call this equation 2
Substituting the value of ∝ in equation 1, we have
a = 1.667∝
= 1.667 x 7.1883
a = 11.983 ft/s²
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Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minute for the next 350 meters, and 3 minutes for the rest.
Cindy’s average speed for the entire run is
meters per minute. One kilometer is the same as 1,000 meters.
Answer:
200 m / min
Explanation:
Total distance = 2000 m
Total time = 2+4+1+3 = 10 minutes
Average speed = 2000 m / 10 min = 200 m/min
Jan is holding an ice cube. What causes the ice to melt?
Thermal energy from the ice is transferred to the air.
Thermal energy from Jan’s hand is transferred to the ice.
The air absorbs thermal energy from Jan’s hand.
Jan’s hand absorbs thermal energy from the ice.
The ice melts because Thermal energy from Jan’s hand is transferred to the ice.
What is thermal energy?Thermal energy is the energy due to temperature difference.
Thermal energy flows from hotter to colder bodies.
The ice Jan is holding melts because heat is transferred from his hands t the ice.
In conclusion, thermal energy flow causes melting.
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Answer:
its b
Explanation:
because the heat from your hand makes the ice melt!
What is the tangential speed of a lug nut on a wheel of a car if the lug nut is located 0.114 m from the axis of rotation; and the wheel is rotating at 6.53 rev/sec
The tangential speed of a lug nut on a wheel of a car will be 4.68 m/s
Given:
Distance of lug nut = 0.114 m
wheel is rotating at speed = 6.53 rev/sec
To Find:
tangential speed of a lug nut
Solution: Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center
Vr = r.ω
(0114 m)(41.03 rad/s) = Vr
Vr = 4.68 m/s
Hence, tangential speed of lug nut on wheel of car is 4.68 m/s
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Why stars are shows like twinkling in the sky’s!
Reply please!
Answer:
As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.
How stars are twinkling in the sky?
Answer:
As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.
The speed of water flowing through a hose increases from 2.05 m/s to 31.4 m/s as it goes through the nozzle. What is the pressure in the hose, assuming the absolute pressure in the nozzle is atmospheric pressure
The pressure in the hose as the speed of water changes from 2.05 m/s to 31.4 m/s as it goes through the nozzle is 5.92 × 10⁵ N/m².
Given:
The flow of water through the hose initially, v₁ = 2.05 m/s
The flow of water through the hose initially, v₂ = 31.4 m/s
Calculation:
From Bernoulli's equation we have:
P₁ + 1/2 ρv₁² + ρgh₁ = P₂ + 1/2 ρv₂² + ρgh₂
where P₁ is atmospheric pressure
P₂ is the pressure in the hose
ρ is the density of the fluid
h₁ is the initial height
h₂ is the final height
v₁ is the initial velocity of the fluid
v₂ is the final velocity of the fluid and
g is the acceleration due to gravity
Re-arranging the above equation we get:
P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (h₁-h₂)
Applying values in the above equation we get:
P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (0)
= (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [(31.4m/s)²-(2.05 m/s)²]
= (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [981.7575]
= (1.01 × 10⁵ Pa)+ (4.91 × 10⁵ Pa)
= 5.92 × 10⁵ Pa
= 5.92 × 10⁵ N/m²
Therefore, the pressure in the hose is 5.92 × 10⁵ N/m².
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Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds. approximately how far away is vega from the sun?
Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds, approximately Vega will be 25.076 Light year or 7.692 Parsec away from the sun
The parallax angle is the angle between the Earth at one time of year, and the Earth six months later, as measured from a nearby star.
Mathematically it can be understood as that the parallax angle is the angle which is taken from a point at one time on the earth and again after six months later from the same point on the earth. The parallax angle is the semi-angle of inclination between the two lines to sight.
Stellar parallax is the basis for the parsec, which is the distance from the Sun to an astronomical object that has a parallax angle of one arcsecond.
Distance (in parsec) = 1 / (parallax angle ( arcsec))
given
parallax angle = 0.13 arcseconds
Distance (in parsec) = 1/ 0.13 = 7.692 Parsec
if 1 Parsec = 3.26 Light year
So, 7.692 Parsec will be equal to = 3.26 * 7.692 = 25.076 Light year
≈ 25.076 Light year
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7. A battery is used to light a 24 W electric lamp. The battery provides a charge of 120 C in
60 s.
TH
24W
What is the potential difference across the lamp?
Answer:
power p =24 watt
charge q=120 C
time t = 60s
let V be the potential difference
we know that
work done =qV = pt
qV = Pxt
120V = 24 * 60
V = (24 * 60) / 120
V = 12 volts
A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from the ground, which path would the bowling ball most closely follow after leaving the airplane?
The path the bowling ball would most closely follow after leaving the airplane is horizontal direction.
Path of the bowling ball
Based on the law of inertia, which is the reluctance of an object to stop moving once in motion or start moving when it is at rest.
The bowling ball will maintain the path of the airline in the first few seconds of fall, after which it will change its path to vertical direction.
Thus, the path the bowling ball would most closely follow after leaving the airplane is horizontal direction.
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Work is being done in "which of these situations? All motions
are at a constant velocity (including velocity = zero).
O Jessica pushes a 25 kilogram cart a distance of 10 meters.
O
A weightlifter holds a 100 k/fogram barbell over his head.
O Bane carries a 20 kilogram box a distance of 50 meters.
O Ali is trying to push a truck away from the parking lot.
Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.
What is Work ?Work is the product of force and distance in the direction of the force. And the S.I unit of work is Joule
Looking at the given options one by one;
O Jessica pushes a 25 kilogram cart a distance of 10 meters. Work is done by Jessica. The work done = 25 x 10 x 10 = 2500 Joules
O A weightlifter holds a 100 kilogram barbell over his head. The weightlifter does no work.
O Bane carries a 20 kilogram box a distance of 50 meters. Bane does work. The work done = 20 x 10 x 10 = 2000 Joules
O Ali is trying to push a truck away from the parking lot. Since there is no movement, there is no work done.
Therefore, Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.
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The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce. Stars over this limit tend to be surrounded by massive nebulae of material blasted off of their surfaces.
The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity
What are stars?Stars are a fixed luminous point in the sky which is a large and remote incandescent body
So therefore, the hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity
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A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if the mass is doubled to 2m?.
If a mass m is attached to an ideal massless spring and has a period of t, then the period of the system when the mass is 2m is [tex]\sqrt{2}t[/tex].
Calculation:
Step-1:
It is given that a mass m is attached to an ideal massless spring and the period of the system is t. It is required to find the period when the mass is doubled.
The time it takes an object to complete one oscillation and return to its initial position is measured in terms of a period, or T.
It is known that the period is calculated as,
[tex]T=2 \pi \sqrt{\frac{m}{k}}[/tex]
Here m is the mass of the object, and k is the spring constant.
Step-2:
Thus the period of the system with the first mass is,
[tex]t=2 \pi \sqrt{\frac{m}{k}}[/tex]
The period of the system with the second mass is,
[tex]\begin{aligned}\\t^'&=2 \pi \sqrt{\frac{m}{k}}\\&=\sqrt{2}\times2 \pi \sqrt{\frac{2m}{k}}\\&=\sqrt{2}\times t\end{aligned}[/tex]
Then the period of the system with the second mass is [tex]\sqrt{2}[/tex] times more than the period of the system with the first mass.
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A loop rests in the plane of a page of textbook while a magnetic field is directed into the page. A clockwise current is induced.
(b) when the magnetic field gets stronger.
correct option :
When a loop rest in the plane of the page and magnetic field is directed into the page then we will apply here right hand thumb rule in which thumb represent the direction of magnetic field and curling fingers represent direction of induced current. So, in this case the direction of magnetic field is into the page and curling fingers shows induced current in clockwise direction.
Thus, option (b) is correct.
Incorrect options:
option (A) is incorrect because when magnetic field will change
according to flux.
option (C) is incorrect because field is stronger so it does not matter
size of loop increases or decreases.
option (D) is incorrect because it moves any other side the field will be
stronger.
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[Your question is incomplete, but most probably your full question was-Check all that apply:
A. when the magnetic field is tilted so it is no longer perpendicular to the page
B. when the magnetic field gets stronger
C. when the size of the loop decreases
D. when the loop is moved sideways across the page]
Which meteorological parameter is expressed as the ratio between the air’s actual water vapor content and the amount of water vapor required for saturation at that temperature?
Which meteorological parameter is expressed as the ratio between the air’s actual water vapour content and the amount of water vapour required for saturation at that temperature: relative humidity.
Water vapour is the primary form of atmospheric moisture. Although its storage in the atmosphere is comparatively small, water vapour is extremely important in forming the moisture supply for dew, frost, fog, clouds, and precipitation.
Water vapour is also the most important greenhouse gas in the atmosphere. Water vapour can be produced from the evaporation or boiling of liquid water or from the sublimation of ice.
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Earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) Determine the Earth’s average orbital speed expressed in kilometers per hours.
b) Based on the information given in this question, calculate the approximate mass of the Sun.
The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg
Relationship between Linear and angular speedLinear speed is the product of angular speed and the maximum displacement of the particle. That is,
V = Wr
Where
V = Linear speedW = Angular speedr = RadiusGiven that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed
W = 2[tex]\pi[/tex]/T
W = (2 x 3.143) / (365.26 x 24)
W = 6.283 / 876624
W = 7.2 x [tex]10^{-4}[/tex] Rad/hr
The Earth’s average orbital speed V = Wr
V = 7.2 x [tex]10^{-4}[/tex] x 149.6 x [tex]10^{6}[/tex]
V = 107225.5 kilometers per hours.
b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law
M = (4[tex]\pi ^{2}[/tex][tex]r^{3}[/tex]) / G[tex]T^{2}[/tex]
M = (4 x 9.8696 x 3.35 x [tex]10^{24}[/tex]) / (6.67 x [tex]10^{-11}[/tex] x 7.68 x [tex]10^{11}[/tex])
M = 1.32 x [tex]10^{26}[/tex] / 51.226
M = 2.58 x [tex]10^{24}[/tex] Kg
Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg
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When a 3.0 N weight is attached to a vertical coil spring, it stretches 5.0 cm. What weight would be required to stretch the spring 12.5 cm?
Group of answer choices
a. 7.5 N
b. 15 N
c. 4.5 N
d. 1.2 N
The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)
Data obtained from the questionInitial weight (W₁) = 3 N Initial Length (L₁) = 5 cmNew length (L₂) = 12.5 cmNew Weight (W₂) =? How to determine the new weightThe new weight required to stretch the spring can be obtained as follow:
W₁ / L₁ = W₂ / L₂
3 / 5 = W₂ / 12.5
Cross multiply
W₂ × 5 = 3 × 12.5
Divide both sides by 5
W₂ = (3 × 12.5) / 5
W₂ = 7.5 N
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Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle q1. Is it pushing to the right, or to the left?
The net force on particle particle q1 is 13.06 N towards the left.
Force on q1 due to q2
F(12) = kq₁q₂/r₂
F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)
F(12) = -14.41 N (towards left)
Force on q1 due to q3F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)
F(13) = 1.352 N (towards right)
Net force on q1F(net) = 1.352 N - 14.41 N
F(net) = -13.06 N
Thus, the net force on particle particle q1 is 13.06 N towards the left.
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Answer:
its +
Explanation:
When a person is standing upright, the weight of anything being lifted and carried in the hands is first reflected onto the:
Pelvic girdle
In human anatomy, the pelvis is a complex of bones that connects the trunk and the legs, supports and balances the trunk, and houses and supports the intestines, the urinary bladder, and the internal organ. It is sometimes referred to as the bony pelvis or the pelvic girdle.
One is located on the left side of the body and the other is located on the right. They come together to make the pelvic girdle, a portion of the pelvis. The hip bones are attached to the upper portion of the skeleton at the sacrum.
The pelvic girdle's main function is to support the upper body's weight while seated and transfer that weight to the lower limbs while standing. For the muscles in the trunk and lower limbs, it functions as attachment point.
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Two worlds in the outer solar system that seem remarkably similar to each other are:
Two worlds in the outer solar system that seem remarkably similar to each other are: Triton and Pluto
The outer solar system comprises the next four planets and everything beyond the planet Neptune but within the gravitational pull of the Sun. The Kuiper Belt and the Oort Cloud are also parts of the outer region.
Triton is only slightly larger than Pluto. Both worlds have similar surface materials, such as nitrogen, methane and carbon monoxide. Their diameters, masses and densities are also similar. Both Triton and Pluto may also have originated within the Kuiper Belt. Triton is thought to be originally a Kuiper Belt Object that was captured by Neptune's gravity.
Because Triton and Charon-Pluto are both from the Kuiper belt they are both made of similar materials such as nitrogen, methane, carbon dioxide and water ice. Both have large cores that are made primarily of rock with mantles of water ice and crusts made of frozen nitrogen. Neither of them have a magnetic field.
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Consider the following forces. (1) frictional (2) gravitational (3) tension (4) strong nuclear (5) normal (6) electroweak which of the forces listed are considered fundamental forces?
The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.
Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.
Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.
The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.
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The 0.20 kg puck on the frictionless, horizontal table in the figure is connected by a string through a hole in the table to a hanging 1.20 kg block.(Figure 1)
The speed with which the puck must rotate in the circular path is 5.42 m/s.
Speed of the puck in circular pathThe speed of the puck is calculated as follows;
centripetal force = weight of hanging mass
mv²/r = W
where;
W is weight of the hanging massm is mass of the puckr is radius of the circular pathv² = Wr/m
v² = (1.2 x 9.8 x 0.5) / (0.2)
v² = 29.4
v = √29.4
v = 5.42 m/s
Thus, the speed with which the puck must rotate in the circular path is 5.42 m/s.
The complete question is below:
With what speed must the puck rotate in a circle of radius 0.50 m if the block is to remain hanging at rest?
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The length of a rectangular plot of land is 151.28 m, and its width is 72.35 m. What is the perimeter of this plot?
605.1 m
223.6 m
289.4 m
a.
b. 447.3 m
c.
d.
Please select the best answer from the choices provided
OA
OB
OC
OD
[tex] \large{ \boxed{ \tt{447.3 \: m}}}[/tex]
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A boy moves down a waterslide from a height of 10 meters. what is his velocity when he hits the water at the bottom of the slide?
The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
Velocity of the boy at the bottom of the slide
The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
h is height of the boyg is acceleration due to gravityv = √(2 x 9.8 x 10)
v = 14 m/s.
Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
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Why might the measurements of ""true distances"" be different for different groups even though they are measuring the same distance?
While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.
While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error
As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.
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A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.
The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.
The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.
The kinetic energy for the protons can be computed by using the formula:
K.E = 1/2mv²mv² = 2 K.E
v = sqrt( 2*KE / M)
the kinetic energy of the medical isotopes = 6.5 MeV
substituting the values,
v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )
v = 3.53 × 10⁷ m/s
The radius of the orbit can be estimated by using the formula:
mv² / R = qvB
r = q*v / mv²
r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )
r = 0.19415 m
Since diameter (D) = 2r,
D= 2(0.19415 m)
D= 0.39 m
D≅ 39 cm
The time period to complete a revolution around the spiral trajectory is:
T = 2πr / v
T = 2*3.14* 0.1941 / 3.53*10^7
T = 0.7 × 10⁻⁷ s
Finally, the number of orbits that the proton does to complete the revolution in 1 ms is:
n = t / T
n = 10^-3 / (0.7*10^-7)
n = 14285.71
n ≅ 14000 revolutions
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Your question is incomplete, but most probably full question was:
A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.
(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous
(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?
A stone ‘X’ of mass 2 kg is at the height of 20m in two minutes, calculate the power delivered. [g=10 m/s-2]
400 J power will be delivered by lifting a stone of mass 2 kg at the height of 20m in two minutes.
What is power?The quantity of energy transferred or transformed per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as an activity in ancient writings. A scalar quantity is a power.
Work completed and time is linked in the power equation. Since forces may move objects and we know that forces perform work, we might anticipate that by understanding the power, we can gain insight into how a body moves through time. This outcome may be especially beneficial.
Given that, a stone ‘X’ of mass 2 kg is lifted to the height of 20m in two minutes, and g=10 m/s-2
Power Delivered = Work done in lifting the stone
Work Done = Potential energy = mgh
Work done = 2 × 10 × 20
Work done = 400 J
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A velocity-time graph is shown below:
The average acceleration in the first 10 seconds of the journey is 2 m/s²; option B.
What is acceleration?Acceleration is the rate of change of velocity with time.
Acceleration = change in velocity/timeFrom the graph;
Acceleration in first seconds = 20 - 0/5 = 4 m/s²
Acceleration in second 5 seconds = 0
Average acceleration = 4 + 0/2
Average acceleration = 2 m/s²
In conclusion, average acceleration is the average of the final and initial acceleration.
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A bicyclist covers the first leg of a journey that is d1meters in t1seconds at a speed of v1m/s and the second leg of d2meters in t2seconds at a speed of v2m/sIf his average speed is equal to the average of v1 and v2
then which of the following is true?
1. t1=t2
2. t1≠t2
3. d1=d2
4. d1≠d2
According to motion in straight line t1≠t2
A biker travels d1 meters in t1 seconds at v1 m/s for the first leg and d2 meters in t2 seconds at v2 m/s for the second leg. It's possible that t1t2 if his average speed is equal to the average of v1 and v2.
An object is said to be in motion if its position in relation to its surroundings changes over time. It is a shift in an object's position over time. The only type of motion that exists is motion in a straight line.
A reference system is constantly used to describe a particle's motion. An arbitrary origin point is used to create a reference system, and a coordinate system is imagined to be connected to it. The reference system for a specific problem is the coordinate system that has been selected for it. For the majority of the problems, we typically select an earth-based coordinate system as the reference system.
To learn more about Motion in straight lines please visit -https://brainly.com/question/17675825
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