A. Reflection around the x-axis:
1. A (5, 1)→ A'
2. B (1, 3) B¹.
3. C (-2, 2)→ C'.
4. D (-5, 4) D'
B. Reflection around the y-axis:
1. A (5, 1)→ A'
2. B (1, 3) B¹.
3. C (-2, 2)→ C'_
4. D (-5, 4) D'

Step-by-step explanation:

So generally whenever you have a problem like this, you want to factor out the denominator and numerator, that way when dividing, you can easily see what the domain is by looking at factors.

So let's start by factoring the numerator and denominator of f(x)

[tex]f(x) = \frac{3x-6}{2x+10}\implies \frac{3(x-2)}{2(x+5)}[/tex]

Now let's do this with the g(x)

[tex]g(x) = \frac{-2x+8}{x+2}\implies\frac{-2(x-4)}{x+2}[/tex]

Now when you divide f(x) by g(x), you keep f(x), change division to multiplication, and flip the g(x) so it's the reciprocal. This gives you the expression

[tex]\frac{f(x)}{g(x)}=\frac{3(x-2)}{2(x+5)}*\frac{x+2}{-2(x-4)}[/tex]

Now just multiply the numerator and denominator

[tex]\frac{f(x)}{g(x)}=\frac{3(x-2)(x+2)}{2(x+5)*-2(x-4)}[/tex]

So the main point of factoring was to easily see when the denominator is  zero, (since if one of the factors is zero, the entire thing will be zero, since zero * anything = zero), but it was also to find any removable discontinuities. Which are just when you have factor in the denominator and numerator, so you can simplify the fraction further by canceling it out. To give an example: [tex]f(x)=\frac{(x-2)(x+4)}{(x-2)(x+3)}\implies\frac{x+4}{x+3}[/tex]. But the domain of f(x) is still restricted so that: [tex]x\ne 2, -3[/tex]. But there will not be a vertical asymptote at x=2 like with traditional domain restrictions in a rational function. This is because you can technically define f(2), but only if you use the most simplified form. This will result in a hole being at that point to signify that it's a removable discontinuity.

Anyways a bit off topic, but something that may be necessary in other examples. Anyways, now to find the domain, we just need to find when f(x)/g(x) is not defined. Or more specifically we find when the denominator is going to be zero. So we just need to set both factors equal to zero.

[tex]0 = 2(x+5)\\\text{divide both sides by 2 (a bit redundant)}\\0 = x+5\\\text{subtract 5 from both sides}\\-5 = x[/tex]

[tex]0 = -2(x-4)\\\text{divide both sides by -2 (a bit redundant)}\\0 = x-4\\\text{add 4 to both sides}\\x=4[/tex]

So the domain restrictions would be: [tex]x\ne-5, 4[/tex]

This can be expressed in interval notation: [tex](-\infty, -5) \cup (-5, 4) \cup (4, \infty)[/tex].

You can also express this in terms of set builder notation: [tex]D: \{x|x\ne-5, x\ne4\}[/tex]

we can see that when they join with Carla, Carter and Isabella will get $200 less (individually).

When Carter and Isabella work together, they have a revenue of $6000, which is split in 50/50, so each one gets:

$6000/2 = $3000

Carter wins $3000 and Isabella wins $3000.

If they join with Carla, the revenue increases by $2400, so now the total revenue is:

$6000 + $2400 = $8400

And now they split it between 3, so each one gets:

$8400/3 = $2800

The difference of Carter's (Or Isabella's) part is:

$3000 - $2800 = $200

Then we can see that when they join with Carla, Carter and Isabella will get $200 less (individually).

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Using secant rule, the value of variable x in the diagram is 10.

A secant is a line that intersect a circle in two points.

Therefore, the following rule guides a secant.

(x + 32)32 = (20 + 28)28

Hence,

32x + 1024 = (48)28

32x + 1024 = 1344

32x = 1344 - 1024

32x = 320

divide both sides by 32

32x / 32 = 320 / 32

x = 10

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Answer:

1.  x = -1  y= -2
2. infinitely many solutions

3. x = 6 y= -7

4.no solution

5. x = -3 y = -17

6. x= 3 y = 7

Step-by-step explanation:

1) y=x-1

7x+6y= -19

6y= -19 -7x

y= (-7x-19)/6

since x-1 and (-7x-19)/6 are both equal to y they are equal to each other

this is how to get x

x-1 = (-7x-19)/6

6x-6 = -7x-19

13x = -13

x = -1

now put back -1 in the equation to get y

y=x-1

y = -1 -1

y= -2

2)-10x+2y=-12

y=5x-6

2y= -12 + 10x

y= -6 + 5x

y = 5x - 6

5x-6 = 5x - 6

0 = 0

when something is

equal to itself its

infinitely many solutions

(when something is not equal to something its no solution)

((when something is equal to just one answer its one solution)

3) y= -4x+17

y=x-13

-4x+17 = x-13

30 = 5x

x = 6

y=x-13

y=6-13

y= -7

4) -3x-15y=8

x+5y=5

-3x-15y=8 -> y = -1/15(3x-8)

5y=5-x -> y= 1/5 (5-x)

-1/15(3x-8) = 1/5 (5-x)

-x-8/3 = 5-x

0 = 23/3

(when something is not equal to something its no solution)

5) -3x+6y=-3

3x-y=8

-3x+6y= -3 -> y = 1/6(3x-3)

3x-y=8 -> y = 3x-8

1/6(3x-3) = 3x-8

3x-3 = 18x-48

x-1 = 6x - 16

5x = -15

x = -3

3x-y=8

3(-3)-y=8

-9-8 = y

y = -17

6) -6x+6y=24

-3x-8y=1

-6x+6y=24 -> y = 1/6(6x+24) -> y = x+4

-3x-8y=1 -> -3x-1 = 8y -> y = 1/8 (-3x-1)

1/8 (-3x-1) = x+4

-3x-1 = 8x+32

11x = 33

x= 3

-6x+6y=24

-6(3)+6y=24

-18 + 6y = 24

6y = 24 + 18

6y = 42

y = 7

The unknown number of the given expression is 8

Let the unknown number be x such that three times the sum of some number plus 3 is equal to 7 times the number minus 23 is expressed as;

3(x + 3) = 7x - 23

Expand

3x + 9= 7x - 23

Collect the like terms

3x-7x = -23 - 9

-4x = -32

x = 8

Hence the unknown number of the given expression is 8

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A) The original claim in symbolic form is; p > 0.50

B) The Null Hypothesis is;

H₀: p = 0.50

Alternative Hypothesis is;

H_a: p > 0.50

We are given;

Sample size; n = 576

Sample Proportion; p^ = 59% = 0.59

A) The percentage of 59% represents the proportion of a sample and thus we are making a claim about the population proportion p in the hypotheses.

We claim "most of the adults", which indicates more than 50% or 0.50. Thus, the claim in symbolic form is; p > 0.50

B) The Null Hypothesis is;

H₀: p = 0.50

Alternative Hypothesis is;

H_a: p > 0.50

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hi,

a point is given  ( x; y)

standar line equation is  :  y = ax+b

So  with  (3;5)  and  (8;15)  we have  :  

   3a+b = 5

   8a+b = 15

so :  

8a+b - ( 3a +b) =  15 -5

8a +b -3a -b = 10

8a-3a = 10

5a = 10

   a = 10/5

    a = 2

if a = 2  so  3*2 +b = 5

                     6+b = 5

                       b = 5-6

                       b = -1

so let check :  

8*2 + (-1) = 16 -1 = 15

and  3*2 -1 = 6-1 = 5

coordonnate works for both point, so line  is   y = 2x -1

The scale factor Of the larger prism to the smaller prism is 0.9

The given parameters are

Large area = 441

Small area = 361

Divide the small area by the large area

Small/Large = 361/441

Take the square root to determine the scale factor k

[tex]k = \sqrt{\frac{361}{441}[/tex]

Evaluate

k = 0.9

Hence, the scale factor Of the larger prism to the smaller prism is 0.9

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The depreciation expense per unit of production for the Textile Company is D. $0.20.

The unit-of-production depreciation method uses the useful life of an asset based on the units of production and the depreciable amount to estimate the depreciation expense per unit.

For each period, the depreciation expense per unit is multiplied by the units of production to determine the period's total depreciation expense.

Cost of equipment = $40,000

Residual value = $6,000

Depreciable amount = $34,000 ($40,000 - $6,000)

Estimated useful life = 170,000 units

Depreciation expense per unit of production = $0.20 ($34,000/170,000)

Thus, the depreciation expense per unit of production for A Textile Company is D. $0.20.

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Solving a system of equations we will see that they sold 80 adult tickets.

To solve this, we need to solve a system of equations. To define said systems of equations, we first need to define the variables, we will use:

They sold 20 more adult tickets than student tickets, then:

x = y + 20

And they collected a total of $880, then:

x*$8 + y*$4 = $880

The the system of equations is:

x = y + 20

x*$8 + y*$4 = $880

Isolating y on the first equation we get:

y = x - 20

Replacing that on the other equation we get:

x*$8 + (x - 20)*$4 = $880

Now let's solve that for x.

x*$12 - $80 = $880

x*$12 = $880 + $80 = $960

x = $960/$12 = 80

They sold 80 adult tickets.

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The number of bacteria present after 15 hours is 18928

An exponential equation is represented as;

y = ab^x

Where

a = y, when x = 0

From the table, we have:

y = 1796 when x = 0

So, we have:

y = 1796b^x

Also, we have the point (1, 2097)

This gives

2097 = 1796b^1

Divide by 1796

b = 1.17

Substitute b = 1.17 in y = 1796b^x

y = 1796(1.17)^x

This means that the exponential equation is y = 1796(1.17)^x

After 15 hours, we have:

y = 1796(1.17)^15

Evaluate

y = 18928

Hence, the number of bacteria present after 15 hours is 18928

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The algebraic description that maps the image ΔABC onto ΔA′B′C′ is (x, y) ⇒ (x + 7, y - 4)

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, rotation, translation and dilation.

Translation is the movement of a point either up, left, right or down in the coordinate plane.

The algebraic description that maps the image ΔABC onto ΔA′B′C′ is (x, y) ⇒ (x + 7, y - 4)

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Using the Poisson distribution, we have that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

For this problem, the mean is given as follows:

[tex]\mu = 13[/tex]

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859[/tex]

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0[/tex]

[tex]P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003[/tex]

[tex]P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019[/tex]

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

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Answer:3522

Step-by-step explanation:222

2

Based on the profit function given, the level of production that yields the maximum profit is 55 units. The maximum profit is $2,025.

With a profit function:

=-x² + 110x - 1,000

Using a parabola function, we know:

= -b / 2a

The maximum units is:

= -110 / (-2 x 1)

= 55 units

The maximum profit is:

= -(55)² + (110 x 55) - 1,000

= $2,025

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Answer:

22222222222222222222222222+22222222

The average price paid by him for the shares after 3 months is ksh. 163.33

Average price paid for the shares after 3 months

= (120 + 160 + 210) / 3

= 490 / 3

= 163.333333333333

Approximately,

ksh. 163.33

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Answer:

when the question is rearranged so that y is by itself, any of the options that say - 2.5x will be parallel.

Step-by-step explanation:

5x + 2y = 1

to get y by itself, simple algebra rules must be applied.

1. subtract 5x from both sides.

5x - 5x + 2y = 1 - 5x

2y = 1 - 5x

divide both sides by 2

2y / 2 = 1 / 2 - 5x / 2

therefore the new equation is:

y = 0.5 - 2.5x

this is very close to standard form for a line which is y = mx + b

rearrange the right side of the equals sign:

y = -2.5x + 0.5

in a standard linear equation, the x value determines the gradient of the line. therefore, anything with the same gradient (in this case -2.5x) will be parallel to the given equation.

Hope this makes sense :)

Using the law of cosines, it is found that the approximate length of side a is 3.99 units.

The law of cosines states that we can find the side c of a triangle as follows:

[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]

in which:

In the context of this problem, we have that side a is opposite to the angle of 53º, hence:

[tex]a^2 = b^2 + c^2 - 2bc\cos{53^\circ}[/tex]

We are given that:

Then:

[tex]a^2 = 34 - 30\cos{53^\circ}[/tex]

a² = 15.95

[tex]a = \sqrt{15.95}[/tex]

a = 3.99.

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Answer: Use this calculator to easily calculate the area of a trapezoid given its base s and height. The formula for the area of a trapezoid is (base 1 + base 2) / 2 x height,

Step-by-step explanation:

The cubic foot is a unit of volume used in the imperial and U.S. customary measurement systems.

The cubic foot can be used to describe a volume of a given material, or the capacity of a container to hold such a material.

The number of dogs in the animal shelter which comprise of cats, dogs, and rabbits is 84 dogs.

Total animals = 5 × 47

= 235

235 = d + (d + 20) + 1/2(d + 20) - 5

235 = d + d + 20 + 1/2d + 10 - 5

235 = 2 1/2d + 25

235 - 25 = 2 1/2d

210 = 2 1/2d

d = 210 ÷ 2 1/2

d = 210 ÷ 5/2

= 210 × 2/5

= 420/5

d = 84 dogs

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Answer: (-1, 4)

Step-by-step explanation:

[tex]\left(\frac{-2+0}{2}, \frac{-1+9}{2} \right)=\boxed{(-1, 4)}[/tex]

(-1, 4) is the midpoint of the segment with endpoints at (-2,-1) and (0, 9). This can be obtained by using the formula for finding the midpoint of a line segment.

When the end points of a line segment are known, the mid point of the line segment is calculated using the midpoint formula,

Midpoint formula,

                   [tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex]

(x₁, y₁) and (x₂, y₂) are the endpoints of the line segment.

⇒ This means that, the midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) is [tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex].

From the question it is given that,

are the endpoints of the line segment.

By using the Midpoint formula we get,

[tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex] = [tex](\frac{-2+0 }{2},\frac{-1+9}{2})[/tex]

[tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex] = [tex](-1, 4)[/tex]

Hence (-1, 4) is the midpoint of the segment with endpoints at (-2,-1) and  (0, 9).

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The area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

Since the curves are

We find their point of intersection.

So, r² = r²

2sin(2θ) = 1²

2sin(2θ) = 1

sin(2θ) = 1/2

2θ = sin⁻¹(1/2)

2θ = π/6

θ = π/12

So, we integrate the area from θ = 0 to θ = π/12

Now the area A of the region between two curves between θ = α to θ = β is

[tex]A = \int\limits^{\beta }_\alpha ({r^{2} - r^{'2} }) \, d\theta[/tex]

So, the area betwwen the curves r² = 2sin(2θ),  r = 1 between θ = 0 to θ = π/12 is

[tex]A = \int\limits^{\frac{\pi}{12} }_0 ({r^{2} - r^{'2} }) \, d\theta \\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1^{2} }) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1}) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 {2sin2\theta}\, d\theta - \int\limits^{\frac{\pi}{12} }_0 {1} \, d\theta\\= [2(-cos2\theta)/2 - \theta]_{0}^{\frac{\pi}{12} } \\= [-cos2\theta - \theta]_{0}^{\frac{\pi}{12} } \\= -cos2\frac{\pi}{12} - \frac{\pi}{12} - ( -cos2(0) - 0)\\[/tex]

[tex]= -cos2(\frac{\pi}{12}) - \frac{\pi}{12} - ( -cos2(0) - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -cos0 - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -1)\\= -(\frac{\sqrt{3} }{2} ) - \frac{\pi}{12} + 1\\= -0.8660 - 0.2618 + 1\\= -1.1278 + 1\\= -0.1278[/tex]

So, the area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

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The pressure of the submarine at a depth of 23000 meters is 2.3575 * 10⁸ N/m²

An equation is an expression that shows the relationship between two or more variables and numbers.

Pressure = density * acceleration due to gravity (g) * depth

g = 10 m/s², hence:

Pressure = 1025 * 10 * 23000 = 2.3575 * 10⁸ N/m²

The pressure of the submarine at a depth of 23000 meters is 2.3575 * 10⁸ N/m²

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There are no real solutions to solve Z. If there may be a typo or something, there are no solutions.

Using proportions, it is found that:

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The heights are measured in units, hence the ratio is:

[tex]r = \frac{5}{25} = \frac{1}{5}[/tex]

The surface areas are measured in units squared, hence the ratio is:

(1:5)² = 1:25.

The volumes are measured in cubic units, hence the ratio is:

(1:5)³ = 1:125.

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Answer:

7.5. hours

Step-by-step explanation:

Trust me

12 men will take 3.34 hours to build a similar storeroom if they work at the same rate.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

It is given that it took 8 hours for 5 men to build a storeroom. The time required by 12 men to do the same work will be calculated as below:-

Time taken by one man  = 8 x 5 = 40 hours

Time is taken by 12 men will be = 40 / 12 = 3.34 hours

Therefore, 12 men will take 3.34 hours to build a similar storeroom if they work at the same rate.

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The place value in the thousands for the 0 in 10,000 is three (3).

A place value refers to a numerical value which denotes a digit based on its position in a given number and it includes:

In this scenario, the place value in the thousands for the 0 in 10,000 is three (3).

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Answer:

A) 69

Step-by-step explanation:

• First , we put the numbers of the distribution in order:

60 , 66 , 72 , 78 , 80 , 82 , 88 , 90

• Notice that the set has 8 numbers which is an even number.

Then

→ the lower quartile is the mean of the set :

60 , 66 , 72 , 78

Which is the average of the two middle numbers 66 and 72.

Then

[tex]\text{the lower quartile}=\frac{66+72}{2} = 69[/tex]