A research center is interested in investigating the height and age of children who are between 5 to 9 years old. In order to do this, a sample of 15 children is selected and the data are given below.
Age (in years) Height (inches)
7 47.3
8 48.8
5 41.3
8 50.4
8 51
7 47.1
7 46.9
7 48
9 51.2
8 51.2
5 40.3
8 48.9
6 45.2
5 41.9
8 49.6
Requried:
a. Develop a scatter chart with age as the independent variable. What does the scatter chart indicate about the relationship between the height and age of children?
b. Use the data to develop an estimated regression equation that could be used to estimate the height based on the age. What is the estimated regression model?
c. How much of the variation in the sample values of height does the model estimated in part (b) explain?
Answers
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data:
Age(x)
7
8
5
8
8
7
7
7
9
8
5
8
6
5
8
Height (Y)
47.3
48.8
41.3
50.4
51
47.1
46.9
48
51.2
51.2
40.3
48.9
45.2
41.9
49.6
The estimated regression equation:
ŷ = 2.73953X + 27.91395
Where ;
X = independent variable
ŷ = predicted or dependent variable
27.91395 = intercept
C.) To obtain the variation in sample values of height estimated by the model, we obtain the Coefficient of correlation:
Using the online pearson correlation Coefficient calculator :
The correlation Coefficient is 0.9696.
which means that the regression model estimated in part (b) explains approximately (0.9696 * 100) = 96.96% = 97% of the variation in the height in the sample.
Related Questions
what is sum of all palindromic numbers from 1 to 100
Answers
Answer:
540
Step-by-step explanation:
0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99
Answer:
540
Step-by-step explanation:
Hey there!
Well we need to first find all the palindromic numbers,
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99
Add
= 540
Hope this helps :)
look at the image below plzz urgant help !!!!!! NEED DONE IN TEN MINUTES
Answers
Answer:
V≈113.1
Step-by-step explanation:
V=πr2h
3=π·32·12
3≈113.09734
Some one please help with question 10!!!
Answers
Answer:
Choice A.
[tex]2 {x}^{ \frac{2}{5} } \times y ^{ \frac{2}{3} } [/tex]
Simplify -12w + 7w - 3 - 6
Answers
Answer: Hi!
We can simplify this by combining like terms:
-12w + 7w - 3 - 6
-12w + 7w = -5w
-3 - 6 = -9
Out equation now looks like this:
-5w - 9
There's nothing left to simplify, so we're done!
Hope this helps!
Heidi bought a machine that throws tennis balls for her dog to fetch. The height of each ball thrown by the machine, in feet, is modeled by the function f(x) = –x2 + x + 2, where x represents time in seconds. How many seconds after the machine throws the ball does it hit the ground?
Answers
Answer:
2 seconds
Step-by-step explanation:
Given the equation:
[tex]f(x) = -x^2 + x + 2[/tex]
Where f(x) represents the height of each ball thrown by machine.
and x represents the time in seconds.
To find:
The number of seconds after which the machine throws the balls hits the ground = ?
Solution:
In other words, we have to find the value of [tex]x[/tex] after which the [tex]f(x) = 0[/tex]
(Because when the ball hits the ground, the height becomes 0).
Let us put [tex]f(x) = 0[/tex] and solve for [tex]x[/tex]
[tex]f(x) = -x^2 + x + 2 =0\\\Rightarrow -x^2 + x + 2 =0\\\Rightarrow x^2 - x - 2 =0\\\Rightarrow x^2 - 2x+x - 2 =0\\\Rightarrow x(x - 2)+1(x - 2) =0\\\Rightarrow (x+1)(x - 2) =0\\\Rightarrow x =-1, 2[/tex]
[tex]x=-1[/tex] sec is not a valid answer because time can not be negative.
So, the answer is after 2 seconds, the ball hits the ground.
Find the interquartile range of the following data set. Number of Points Scored at Ten Basketball Games 57 63 44 29 36 62 48 50 42 34 A.21 B.28 C.6 D.34
Answers
Answer:
total number(n)=10
divided the total number into two equal parts so
in one group of number =5
ln first phase group of number middle value =44
In second phase group of number middle value=50
then using formula,q1=44 q3=50
inter quartile range =q3_q1
=50-44
=6
therefore interquartile range =6
Answer: The answer is 6
Cho A=( căn x -4x /1-4x -1) : (1+2x/1-4x -2căn x/ 2căn x -1 -1)
Answers
Answer:
0.85714285714286 x 100 = 85.7143%.
Step-by-step explanation:
) If the half-life of 238Pu is 87.7 yr, write a function of the form =QtQ0e−kt to model the quantity Qt of 238Pu left after t years. Round the value of k to five decimal places. Do not round intermediate calculations.
Answers
Answer:
0.079
Step-by-step explanation:
According to the given situation, the calculation of the value of k is presented as follows:
[tex]Q(t)= Q_0e^{-kt}\\\\ 0.5Q_0 = Q_0e^{-k(97.7)}\\\\ 0.5 = e^{-k(87.7)}[/tex]
now,
[tex]k = \frac{In0.5}{-87.7}[/tex]
After solving the above equation we will get the value of k.
= 0.079
Therefore for determining the value of k we simply solve the above equation i.e. by considering all the information mentioned in the question
Answer:
3.5e^-0.0079t
Step-by-step explanation:
None, Good luck mate
11
12
13
14
15
16
Write the appropriate pronoun that can replace the subject in this sentence.
Tomás va a comer galletas.
ella
O él
Ο Ο Ο Ο
O nosotros
O usted
Answers
Answer:
The answer is usted
Step-by-step explanation:
And if you want to learn more download duolingo
Let f(x) =
[tex] \sqrt[3]{11x - 3 \:} determine \: {f}^{ - 1} (x)[/tex]? here
Answers
Step-by-step explanation:
Set up f(x).
[tex] \sqrt[3]{11x - 3} = f(x)[/tex]
Replace f(x) with y
[tex] \sqrt[3]{11x - 3} = y[/tex]
Swap x and y
[tex] \sqrt[3]{11y - 3} = x[/tex]
Solve for y
Cube both sides
[tex]11y - 3 = {x}^{3} [/tex]
Add 3 to both sides
[tex]11y = {x}^{3} + 3[/tex]
Divide both sides by 11
[tex]y = \frac{x {}^{3} + 3 }{11} [/tex]
so
[tex]f {}^{ - 1} (x )= \frac{ {x}^{3} + 3}{11} [/tex]
Solve for h: W = 5h - 90 (must show step by step)
Answers
Answer:
[tex]W = 5h - 90 \\ 5h = W + 90 \\ h = \frac{W + 90}{5} [/tex]
Answer:
h = w+90/ 5
Step-by-step explanation:
5h-90=w
5h/5= w+90/5
h= w+90/5
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviation of σ=12.5 beats per minute. Complete parts (a) through (c) below.a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 76 beats per minute.b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?A. Since the mean pulse rate exceeds 30, the distribution of sample means is a normal distribution for any sample size.B. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size.C. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample size.D. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.
Answers
Answer:
a. the probability that her pulse rate is less than 76 beats per minute is 0.5948
b. If 25 adult females are randomly selected, the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849
c. D. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.
Step-by-step explanation:
Given that:
Mean μ =73.0
Standard deviation σ =12.5
a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 76 beats per minute.
Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.
Then : X [tex]\sim[/tex] N ( μ = 73.0 , σ = 12.5)
The probability that her pulse rate is less than 76 beats per minute can be computed as:
[tex]P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})[/tex]
[tex]P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})[/tex]
[tex]P(X < 76) = P(Z< \dfrac{3}{12.5})[/tex]
[tex]P(X < 76) = P(Z< 0.24)[/tex]
From the standard normal distribution tables,
[tex]P(X < 76) = 0.5948[/tex]
Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948
b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.
now; we have a sample size n = 25
The probability can now be calculated as follows:
[tex]P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})[/tex]
[tex]P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})[/tex]
[tex]P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})[/tex]
[tex]P( \overline X < 76) = P(Z< 1.2)[/tex]
From the standard normal distribution tables,
[tex]P(\overline X < 76) = 0.8849[/tex]
c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?
In order to determine the probability in part (b); the normal distribution is perfect to be used here even when the sample size does not exceed 30.
Therefore option D is correct.
Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.
PLEASE HELP !! (1/5) - 50 POINTS - no wrong answers please. A) y = 6x - [tex]\frac{11}{8}[/tex] B) y = -6x - 2 C) y = [tex]\frac{3}{2}[/tex] x - [tex]\frac{1}{8}[/tex] D) y = -3x + 9
Answers
Answer:
C) 3/2x-1/8
Step-by-step explanation:
We can see that it has a generally positive slope, which rules out B and D.
Plugging in a few numbers for x, we can quickly see that 6 is too high of a slope. (If we plug in 6 for x, the y value would be almost 35, not 10). This rules out A.
While it doesn’t fit perfectly, C is by far the closest.
Q1) Two balls are randomly selected without replacement from a box containing three black balls numbered 1, 2, 3 and two white balls numbered 4 and 5. Assuming that all outcomes are equally likely. Find out the probabilities of following events. a) Probability that the color of second ball is white. b) Probability that the color of second ball is black. c) Probability that both balls are black. d) Probability that both balls are white.
Answers
[tex]|\Omega|=5\cdot4=20[/tex]
a)
[tex]|A|=3\cdot2+2\cdot1=8\\\\P(A)=\dfrac{8}{20}=\dfrac{2}{5}[/tex]
b)
[tex]|A|=3\cdot2+2\cdot3=12\\\\P(A)=\dfrac{12}{20}=\dfrac{3}{5}[/tex]
c)
[tex]|A|=3\cdot2=6\\\\P(A)=\dfrac{6}{20}=\dfrac{3}{10}[/tex]
d)
[tex]|A|=2\cdot1=2\\\\P(A)=\dfrac{2}{20}=\dfrac{1}{10}[/tex]
9) Given a circle with radius = 6 meters, a central angle of 77 degrees will intercept an arc of what length?
Please show all work
Answers
Hey there!
If our central angle is 77, our arc on the outside that it intercepts is going to be 77/360 of the total circumference of the arc. This is because a full circle angle is 360 degrees, so if our central angle was 360, we would just find the circumference of the circle as the arc would be the entire circle.
In our case, we will just find the circumference and then multiply it by 77/360 to find our arc length as we are just looking for a fraction of our total circle.
Circumference is 2πr, so we have 2π(6)≈37.68
Now we multiply this by 77/360.
37.68×77/360≈ 8.06
So now, if you have a radius r and a central angle x, you can use the formula x/360 ×2πr to find the arc length.
Have a wonderful day! :D
PLEASE HELP
-6/5k=12
Show your work in details if you can, I have a hard time understanding this.
Answers
[tex]\begin{cases}\large\bf{\green{ \implies}} \tt \: - \frac{6}{5} \: k \: = \: 12 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{6k}{5} \: = \: 12 \\ \\ \large\bf{\green{ \implies}} \tt \: - 6k \: = \: 12 \: \times \: 5 \\ \\ \large\bf{\green{ \implies}} \tt \: - 6k \: = \: 60 \\ \\ \large\bf{\green{ \implies}} \tt \: k \: = \: \cancel\frac{60}{ - 6} \\ \\ \large\bf{\green{ \implies}} \tt \: k \: = \: - 10 \end{cases}[/tex]
Let U = {q,r,s,t,u,v,w,x,y,z}, A={q,s,u,w,y}, B={q,s,y,z}, and C={v,w,x,y,z}. List the elements in the set open parentheses A union B close parentheses to the power of apostrophe intersection C
Answers
[tex]A\cup B=\{q,s,u,w,y,z\}\\(A\cup B)'=\{r,t,v,x\}\\\boxed{(A\cup B)'\cap C=\{v,x\}}[/tex]
If the bathtub holds a total of 46.2 gallons, how many minutes would it take to fill the entire bathtub? Write an equation in one variable to help you solve the problem. The variable represents the unknown time in minutes.
Answers
Answer:
2.8
Step-by-step explanation:
Hey there!
Well to find the amount of minutes needed to fill a 46.2 gallon bathtub we’ll divide.
46.2 / 16.5
= 2.8
2.58 minutes
Hope this helps :)
Is x - 0.30x equivalent to 0.70x?
Answers
hi
it's equal to as X = 1X
so 1X-0.3X = 0.7X
Answer:
yes
Step-by-step explanation:
as
x - 0.3x = 1×x - 0.3x = (1-0.3)x = 0.7x
Need help on polynomial expressions
Answers
Answer:- 10[tex]m^{2}[/tex] + 3m -9
Step-by-step explanation: Given ;
A= -3 -m
B= 3m -5[tex]m^{2}[/tex]
2B + 3A
solution
2B + 3A
substitute A and B in the formula
2(3m - 5[tex]m^{2}[/tex]) + 3(-3 -m)
6m - 10[tex]m^{2}[/tex] - 9 - 3m group like terms
- 10[tex]m^{2}[/tex] + (6m -3m) -9
- 10[tex]m^{2}[/tex] + 3m -9
Using your textbook, solve the problems below. Show your work.
Solve for y:
y + 8 = 2
Answers
Answer:
i dont know lol
Step-by-step explanation:
What is the error in this problem
Answers
Answer:
The angle of elevation is not properly represented
Step-by-step explanation:
Given
The question in the attachment;
Required
Determine the error
See attachment for proper representation of the angle of elevation;
Solving further (From the Attachment)
[tex]Tan22 = \frac{x}{3000}[/tex]
Multiply both sides by 3000
[tex]x = 3000 * tan22[/tex]
[tex]x = 3000 * 0.4040[/tex]
[tex]x = 1212[/tex]
The cliff is about 1212 feet high
Choose the best answer
Question
Cube A has volume V The edges of cube Bare 3 times as long as the edges of cube A. What is the
volume of cube B, in terms of V?
1.3V
2.9V
3.18V
4.27V
Answers
Answer:
4). 27V
Step-by-step explanation:
Let the edge of the cube A be x
Volume of Cube A= V
Volume= x*x*x= x³
so V = x³
Edge of cube B = 3 times edge of cube A
Edge of cube B = 3x
Volume of cube B =( 3x)³
volume of cube B = 27x³
But x³= V
So volume of cube B = 27v
A sport jacket is on sale for 35% off, if the originsl price is $140, what is the sale price?
Answers
Answer:
$91
Step-by-step explanation:
If a jacket is on sale for 35% off, that means that the price of the jacket is [tex]100-35=65[/tex]% of its original price.
We can find 65% of 140 by making 65% into a decimal - 0.65, then multiply it by 140.
[tex]140\cdot0.65=91[/tex]
Hope this helped!
Answer:
$91.00
Step-by-step explanation:
The jacket is on sale for 35%. Usually, you pay for 100% of the jacket's price. Since it is on sale, we can subtract 35% from 100%.
100%-35%=65%
With the sale, you only pay for 65% of the price.
Now, we can multiply 65% and 140.
65% * 140
Convert 65% to a decimal. Divide 65 by 100 or move the decimal place 2 spots to the left.
65/100=0.65
65.0 --> 6.5 --> 0.65
0.65 * 140
Multiply
91
$91
The sale price for the sports jacket is $91.00
Given below are descriptions of two lines. Line 1: Goes through (-2,10) and (1,1) Line 2: Goes through (-2,8) and (2,-4)
Answers
Answer:
Option (2)
Step-by-step explanation:
1). If two lines have the same slope, lines are defined as parallel.
m₁ = m₂
2). If the multiplication of the slopes of two lines is (-1), lines will be perpendicular.
m₁ × m₂ = (-1)
Line 1 : It passes through two points (-2, 10) and (1, 1).
Slope of the line 1 = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{1+2}{10-1}[/tex]
= [tex]\frac{3}{9}[/tex]
m₁ = [tex]\frac{1}{3}[/tex]
Line 2 : It passes through two points (-2, 8) and (2, -4).
Slope of the line 2 = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{8+4}{-2-2}[/tex]
= [tex]-\frac{12}{4}[/tex]
m₂ = -3
Since, m₁ × m₂ = [tex]\frac{1}{3}\times (-3)[/tex]
= (-1)
Therefore, given lines are perpendicular to each other.
Option (2) is the correct option.
Hellllppp!!!! Please!Match the numbers with the correct label.
Answers
Answer:
(a = 1/7 (b = .2 (c = 3/9
Step-by-step explanation:
1/7 = .14
1/4 = .25
3/9 = .33
a & b are lower than 1/4 and c is higher
A random sample of 1003 adult Americans was asked, "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1003 adults surveyed, 521 indicated that televisions are a luxury they could do without.
Requried:
a. Obtain a point estimate for the population proportion of adult Americans who believe that televisions are a luxury they could do without.
b. Verify that the requirements for constructing a confidence interval about p are satisfied.
c. Construct and interpret a 95% confidence interval for the population proportion of adult Americans who believe that televisions are a luxury they could do without.
d. Is it possible that a supermajority (more than 60%) of adult Americans believe that television is a luxury they could do without ? Is it likely?
e. Use the results of part (c) to construct a 95% confidence interval for the population proportion of adult Americans who believe that televisions are a necessity.
Answers
Answer:
a)0.519
b)requirements for constructing a confidence interval about p are satisfied.
c)0.488, and 0.550
d)yes this is because there is no possibility
that the true proportion is not captured in the confidence interval.
e)
0.450, 0.512
Step-by-step explanation:
a)The point estimate for the population proportion of adult Americans who believe that televisions are a luxury they could do without can be calculated as
521 of that adult that indicated that televisions are a luxury they could do without/1003 adults surveyed,
p = 521/1003
= 0.519.
b)
np(1-p)=1003×(0.519)×(1-0.519)
=250.39≥10 and the sample size is less than 5% of the population
therefore, requirements for constructing a confidence interval about p are satisfied.
c) we were given 95% confidence,
Then α=(1-0.95)
= 0.05
From the Z-tables,we can get the critical value is Z , which is (0.05/2) = Z (0.025) = 1.96
confidence interval can the be calculated using the formula below
- p ± Z*√ p (1 – p)/n
=0.519 ± 1.96√0.519×(1 – 0.519)/(1003)
= 0.519 ± 1.96×0.0158
0.519 ± 0.031
= 0.488, and 0.550
d) yes this is because there is no possibility
that the true proportion is not captured in the confidence interval.
e)the sample size can be calculated as
P=x/n
=(1003-521)/1003
=0.481
But we're given 95% confidence interval
Then
α=(1-0.95)=
0.05
From the Z-tables,we can get the critical value is Z , which is (0.05/2) = Z (0.025) = 1.96
Then convidence interval=
- p ± Z*√ p (1 – p)/n
=0.481 ± 1.96√0.481×(1 – 0.481)/(1003)
0.450, 0.512
Which of the following uses parallel construction? Select one: a. Jim likes to hunt, bike, and throwing darts. b. Mimie has to study, drive her sister to the store, and enjoy herself in the garden. c. Joe will go running, biking, and hunting. d. Jane will throw a ball, then she will mow the lawn.
Answers
Answer:
The correct answer is:
c. Joe will go running, biking and hunting
Step-by-step explanation:
Parallel construction or parallelism or parallel structure is a style used in writing a sentence, where there is a balance in phrases or clauses within one or more sentences by them having the same grammatical structure. parallelism adds elegance, clarity and symmetry to sentences. It essentially has to so with a repetition of a chosen grammatical form within a sentence.
In our example:
a. Jim likes to hunt, bike, and throwing darts. (not parallel)
Jim likes to hunt, bike, and throw darts (parallel)
The verbs, hunt, bike and throw must be in the same form (present continuous) to be parallel
b. Mimie has to study, drive her sister to the store, and enjoy herself in the garden. (not parallel).
The sentence in option b is not parallel because the other actions apart from "study" have a place where they took place; drive her sister to the store, enjoy herself in the garden, however, "study" doesn't have a place where the action occurs.
c. Jane will throw a ball, then she will mow the lawn. (not parallel)
the sentence is not parallel because there is an inconsistency in the pattern of the construct. a parallel version is:
Jane will first throw a ball, then she will mow the lawn, or
jane will throw a ball and mow the lawn.
d. Joe will go running, biking, and hunting. (parallel)
all the verbs are in the present continuous form.
If a recipe which makes 8 servings calls for 2 cups of sugar, how many cups of sugar will it take to make 18 servings?
Answers
Answer:
4.5
Step-by-step explanation:
2/8=x/18
Answer:
4.5 cups
Step-by-step explanation:
first you set up the problem like servings/cups. This would look like 8/2. Then you add the 18 servings and make it a cross multiplication problem. The expression would look like 8/2=18/x. You cross multiply and get 8x=36. Divide by 8 and get x=4.5 cups.
confidence interavls for a population proportion. suppose that a random sample of 1000 mortgage loans that were defaulted within the first year reveals 410 of these loans were approved on hte basis of falsified applications. what is point estiamte of and a 95% confidence interval for p, the proportion of all first year defaults that are approved on the basis of flsified application
Answers
Answer:
The 95% confidence interval is [tex]0.3795 < p < 0.4405[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 1000[/tex]
The number of approved loan is k = 410
Generally the sample proportion is mathematically represented as
[tex]\r p = \frac{k}{n}[/tex]
substituting values
[tex]\r p = \frac{410}{1000}[/tex]
[tex]\r p = 0.41[/tex]
Given that the confidence level is 95% then the level of significance is mathematically represented as
[tex]\alpha = 100 - 95[/tex]
[tex]\alpha = 5\%[/tex]
[tex]\alpha = 0.05[/tex]
Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table,the value is
[tex]Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p(1- \r p)}{n} }[/tex]
substituting values
[tex]E = 1.96 * \sqrt{\frac{ 0.41(1- 0.41)}{1000} }[/tex]
[tex]E = 0.03048[/tex]
The 95% confidence interval for p is mathematically represented as
[tex]\r p - E < p < \r p + E[/tex]
substituting values
[tex]0.41 - 0.03048 < p < 0.41 + 0.03048[/tex]
[tex]0.3795 < p < 0.4405[/tex]