A rifle bullet is fired from the top of a cliff at an angle of 30o below the horizontal. The initial velocity of the bullet is 800 m/s. If the cliff is 80 m high, how far does it travel horizontally

Answer:

He can lift on the earth is 60 kg

Answer:

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

Explanation:

Step 1: Write out equation

[tex]\frac{1}{2} mv^2+Fd=mgh[/tex]

Step 2: Subtract FD on both sides

[tex]\frac{1}{2} mv^2=mgh-Fd[/tex]

Step 3: Subtract mgh on both sides

[tex]\frac{1}{2} mv^2-mgh=-Fd[/tex]

Step 4: Divide both sides by -d

[tex]\frac{\frac{1}{2} mv^2-mgh}{-d} =F[/tex]

Step 5: Rewrite

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

Explanation:

Total displacement =30+20=50 Km

Average velocity =displacement /time

V=50/1.5=33.33km/hr

Answer:

Total Displacement: 10

Average velocity, closest option is 10.

Explanation:

30-20=10

Answer:

σ = 1.09 mm

Explanation:

Step 1: Identify the given parameters

rod diameter = 20 mm

stiffness constant (k) = 55 MN/m = 55X10⁶N/m

applied force (f) = 60 KN = 60 X 10³N

young modulus (E) = 200 Gpa = 200 X 10⁹pa

Step 2: calculate length of the rod, L

K = \frac{A*E}{L}K=

L

A∗E

L = \frac{A*E}{K}L=

K

A∗E

A=\frac{\pi d^{2}}{4}A=

4

πd

2

d = 20-mm = 0.02 m

A=\frac{\pi (0.02)^{2}}{4}A=

4

π(0.02)

2

A = 0.0003 m²

L = \frac{A*E}{K}L=

K

A∗E

L = \frac{(0.0003142)*(200X10^9)}{55X10^6}L=

55X10

6

(0.0003142)∗(200X10

9

)

L = 1.14 m

Step 3: calculate the displacement of the rod, σ

\sigma = \frac{F*L}{A*E}σ=

A∗E

F∗L

\sigma = \frac{(60X10^3)*(1.14)}{(0.0003142)*(200X10^9)}σ=

(0.0003142)∗(200X10

9

)

(60X10

3

)∗(1.14)

σ = 0.00109 m

σ = 1.09 mm

Therefore, the displacement at the end of A is 1.09 mm

Answer

ANSWER WITH FULL EXPLANATION

If a speed is given  km/h, then the formula to convert the speed from km/h to m/s is  

km/h = m/s

In other words, if you want to convert the given speed from km/h to m/s, then multiply the given number by  and put "m/s" after it.  

The speed of a car is 72 km/h.  

Converting the speed into m/s

72 km/h =  m/s = 20 m/s

∴ The speed of the car (expressed in m/s) is 20 m/s.

SHORT ANSWER

1km/h=5/18m/s

72km/h=72×5/18m/s

=4×5m/s

=20m/s.

HOPE  THIS HELPS YOU PLEASE MARK ME AS BRAINLIEST

[tex]\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}[/tex]

Mass of rifle = 4kg

Mass of bullet = 50g = 0.05kg

Initial velocity of bullet = 35m/s

[tex]\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}[/tex]

Recoil velocity of rifle.

[tex]\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}[/tex]

Recoil velocity of rifle is given by

[tex]\dag\:\boxed{\bf{\purple{V=-\dfrac{mv}{M}}}}[/tex]

[tex]:\implies\sf\:V=-\dfrac{mv}{M}[/tex]

[tex]:\implies\sf\:V=-\dfrac{0.05\times 35}{4}[/tex]

[tex]:\implies\sf\:V=-\dfrac{1.75}{4}[/tex]

[tex]:\implies\bf\:V=-0.437\:ms^{-1}[/tex]

[Note : -ve sign shows opposite direction]

Answer:

MgVg=MbVb.

4×Vg=0.05×35.

4Vg=1.75.

Vg=1.75/4

=0.4375 ~ 0.4m/s.

Answer:

Greater than

Explanation:

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

Speed = distance / time

Velocity = displacement / time

Since you return to your starting point, your displacement is 0 m, so your average velocity is 0 m/s.  Therefore, your average speed is greater than your average velocity.

Speed ls a function of distance and time, while velocity is a function of displacement and time. Since the rider returned to his starting point, then the magnitude of the average speed is greater than the magnitude of the average velocity

The total distance traveled will be sum of the 'to' and 'fro' distance.

The total displacement will be 0 (Final position - Initial position) ; since the rider returned to his starting position.

This means the average velocity will be 0 while the average speed will have a value greater than 0.

Therefore, the average speed will be greater.

Learn more :https://brainly.com/question/23774048

Answer:

v = 11.2 m/s

Explanation:

A stone is dropped near the lunar surface and falls freely for 7 seconds. The acceleration of lunar gravity is 1.6 m / s², what speed will it reach?

Given that,

The acceleration due to the gravity of lunar gravity is 1.6 m/s²

A stone is dropped near the lunar surface and falls freely for 7 seconds.

We need to find the speed with which it reach.

The initial velocity of the stone will be 0 as it was at rest.

Using equation of kinematics v=u+at

[tex]v=1.6\times 7\\\\v=11.2\ m/s[/tex]

So, the stone will reach with a speed of 11.2 m/s

Answer:

The participants who were given the coffee

Explanation:

This is the group which the experiment is centered or focused around in order to achieve a result of derive informations regarding their exposure to some things.

Dr. Sampson is studying the effects of caffeine on hunger which means he hypothesizes that people who ingest more caffeine experience less hunger pangs throughout the day. He designs a study where one group of participants is given caffeine throughout the day, and the other group is not allowed to have any caffeine. All this talks about The participants who were given the coffee being the experimental group

Not even a week. If you looking for a number it would be 0.00051091. Again not even a week.

Answer:

0.000510913 weeks...

Not even one week.

Answer:

there are many metals in the periodic table and all have different atomic number and mass

Explanation:

Answer:

9.8 m/s

Explanation:

Distance Traveled = 98 m

Total Time = 10 s

Average Speed = Total Distance/Total Time

= 98/10

= 9.8 m/s

Hope this helped...

Answer:

I think it is the third one

Explanation:

Everything about it is flipped

The electromagnets with poles that are reversed from the electromagnet  is according to image C.

A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.

A bar is a magnet which can attract the particle which are charged. It has two poles North and South.

The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.

An electromagnet is a soft metal core made into a magnet by the passage of electric current through a coil surrounding it.

When the poles are reversed, then the direction of current flow is also reversed.

Thus, the correct option is C.

Learn more about magnet.

https://brainly.com/question/2841288

#SPJ2

Answer:

a

     t =  1.235 s

b

  [tex]h_{max} = 2.55 \ m[/tex]

c

 [tex]v = -7.10 m/s[/tex]

Explanation:

From the question we are told that

    The  initial  velocity is [tex]u = 5.0 \ m/s[/tex]

      The  take of height is  [tex]h = -1.30 \ m[/tex]

The negative sign show that the height is on the negative y-axis when the take off point is consider as the origin

Generally from the kinematic equation we have that

       [tex]s = ut + \frac{1}{2}at^2[/tex]

=>     [tex]-1.30 = 5.0 t + \frac{1}{2} (-9.8)t^2[/tex]

Here g is negative given that the swimmers jump motion is against gravity

    [tex]4.9t^2 - 5t - 1.30[/tex]

solving using quadratic formula we obtain that

    t =  1.235 s

Generally the highest point is mathematically evaluated as

      [tex]h_{max} = \frac{v^2 - u^2 }{2 * (-g) }[/tex]

Here v =  0 m/s since the velocity at the highest point is 0

   [tex]h_{max} = \frac{0^2 - 5^2 }{2 * (-9.8) }[/tex]

   [tex]h_{max} = 2.55 \ m[/tex]

Generally her velocity when the feet hits the water is mathematically evaluated from kinematic equation as

     [tex]v = \pm \sqrt{ u^2 + 2 (-g) * (-h)}[/tex]

      [tex]v = -7.10 m/s[/tex]

The  negative value of the velocity is selected because the velocity is on the negative y-axis

Answer:

The trains will collide at a distance 1660 m from the station

Explanation:

Let the train traveling due north with a constant speed of 100 m/s be Train A.

Let the train traveling due south with a constant speed of 136 m/s be Train B.

From the question, Train B leaves a station 2,881 m away (that is 2,881 m away from Train A position).

Hence, the two trains would have traveled a total distance of 2,881 m by the time they collide.

∴ If train A has covered a distance [tex]x[/tex] m by the time of collision, then train B would have traveled [tex](2881 - x)[/tex] m.

Also,

At the position where the trains will collide, the two trains must have traveled for equal time, t.

That is, At the point of collision,

[tex]t_{A} = t_{B}[/tex]

[tex]t_{A}[/tex] is the time spent by train A

[tex]t_{B}[/tex] is the time spent by train B

From,

[tex]Velocity = \frac{Distance }{Time }\\[/tex]

[tex]Time = \frac{Distance}{Velocity}[/tex]

Since the time spent by the two trains is equal,

Then,

[tex]\frac{Distance_{A} }{Velocity_{A} } = \frac{Distance_{B} }{Velocity_{B} }[/tex]

[tex]{Distance_{A} = x[/tex] m

[tex]{Distance_{B} = 2881 - x[/tex] m

[tex]{Velocity_{A} = 100[/tex] m/s

[tex]{Velocity_{B} = 136[/tex] m/s

Hence,

[tex]\frac{x}{100} = \frac{2881 - x}{136}[/tex]

[tex]136(x) = 100(2881 - x)\\136x = 288100 - 100x\\136x + 100x = 288100\\236x = 288100\\x = \frac{288100}{236} \\x = 1220.76m\\[/tex]

[tex]x[/tex]≅ 1,221 m

This is the distance covered by train A by the time of collision.

Hence, Train B would have covered (2881 - 1221)m = 1660 m

Train B would have covered 1660 m by the time of collision

Since it is train B that leaves a station,

∴ The trains will collide at a distance 1660 m from the station.

Time = distance / speed

Time = (100 km) / (5.7 km/yr)

Time = 17.5 years

If this is true, then it's not likely that any member of the species has ever traveled 100 km in its lifetime.  Weird !

Answer:

The force magnitude is 1.75 μN acting outward from the origin towards x₂

Explanation:

The given parameters, are;

The location of q₁ = The origin

The location of q₂ = 14.7 mm from q₁

The repulsive force exerted on q₂ by q₁ = 2.62 μN

The location the particle q₂ is located to =  18.0 mm from q₁

By Coulomb's law, we have;

[tex]F = k\dfrac{q_1 \times q_2 }{r^2}[/tex]

Where;

k = Coulomb constant ≈ 8.99 × 10⁹ kg·m³/(s²·C²)

r = The distance between the particles

F = The force acting between the particles

When r = 14.7 mm F = 2.62 μN

∴ q₂ × q₁ = r² × F/k = (14.7×10^(-3))²×2.62×10^(-6)/(8.9875517923^9) ≈ 1.48 × 10⁻¹⁸

q₂ × q₁ = 1.48 × 10⁻¹⁸ C²

When the distance is increased to 18.0 mm, we have;

F = (8.9875517923^9) × 1.4796647 × 10^(-18)/((18×10^(-3))²) = 1.75 × 10⁻⁶ N

∴ F = 1.75 μN.

Therefore;

The force magnitude is 1.75 μN outward from the origin towards  x₂.

To magnitude of the force that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location is 1.75 µN.

Given the following data:

Scientific data:

To calculate the force (magnitude and direction) that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location, we would apply Coulomb's law:

Mathematically, the force in an electric field is given by this formula:

[tex]F=\frac{kq_1q_2}{r^2}[/tex]

Where:

[tex]q_1q_2 =\frac{F}{k} \times r^2\\\\q_1q_2 =\frac{2.62 \times 10^{-6}}{8.99 \times 10^9} \times 0.0147^2\\\\q_1q_2 = 2.914 \times 10^{-16} \times 0.00021609\\\\q_1q_2 = 6.30 \times 10^{-20}\;C^2[/tex]

For the force, when r = 0.018:

[tex]F =\frac{8.99 \times 10^9 \times 6.30 \times 10^{-20}}{0.018^2} \\\\F =\frac{5.66 \times 10^{-10}}{0.000324} \\\\F = 1.75 \times 10^{-6}[/tex]

Note: 1 µN = [tex]1 \times 10^{-6}\;N[/tex]

Force, F = 1.75 µN.

In conclusion, the direction of the force at the new location is outward from the origin along [tex]X_2[/tex].

Read more on electric field here: https://brainly.com/question/14372859

Answer:

100 L

Explanation:

10 dL =  1 L

Answer:

A balance

Explanation:

Scientists measure mass with a balance, such as a triple beam balance or electronic balance. In science, the volume of a liquid might be measured with a graduated cylinder.

Answer: Scientists often measure mass with a balance

Hope this helps

Answer:

3 Mg, 2 P, 14 O, 12 H

Explanation:

Answer: please find the answer in the explanation

Explanation:

Velocity is the distance covered in a specific direction per time taken.

And in velocity, we have final velocity V and initial velocity U.

The definition of average velocity is:

Average velocity = (V + U)/2

Since velocity involves direction, if the initial velocity U is of the same magnitude as the final velocity V and both are of opposite direction. Then,

Average velocity = (-U + V)/2

Since they are of the same magnitude,

V = U.

Therefore,

Average velocity = (-U + U)/2 = 0

Answer: C

Explanation: just did it

Answer:

C

Explanation:

edg 2021 AP Physc

Answer:

Explanation:

b 0.2m

Answer:

D. 1.0M Fe3+

Explanation:

I just took a took a test on this exact question.

Answer:

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Explanation:

Given the following length measurement :

micrometer Kilometer decimeter centimeter nanometer dekameter.

Sorting in increasing order of magnitude from Smallest to Largest.

Expressing in terms of meters :

1 meter = 0.1 decameter

1 meter = 1 × 10^9 nanometer

1 meter = 1 × 10^2 centimeter

1 meter = 1 × 10^1 decimeter

1 meter = 0.001 kilometer

1 meter = 1 × 10^6 micrometers

Hence, arranging from Smallest to Largest :

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Answer:

the answer is A. working against a force

Explanation:

Answer:

A. working against a force

Explanation:

Answer:

Please see explanation below

Explanation:

Recall that trigonometric functions like cosine (cos) and sine (sin) of an angle are defined based on the relationships between the sides and hypotenuse of a right angle triangle:

[tex]sin(\theta)=\frac{opposite}{hypotenuse} \\cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

where the terms "opposite" and "adjacent" refer to the sides opposite and adjacent to the angle in question.

Based on such, one can solve for example for the "adjacent" side (the horizontal component of the 200 N vector you need to find) to the known angle ([tex]\theta[/tex]) in the following way:

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(30^o)=\frac{adjacent}{200}\\adjacent=200\,\,cos(30^o)[/tex]

Answer:

The correct option is;

C. Repeating an experiment to verify results

Explanation:

A scientific theory is a statement explaining an observed natural phenomenon which can be simulated for verification ensuring that all protocols of the scientific method of investigation are observed.

By repeating the experiment under particular conditions such as through verification of data from direct observation such as in astronomy, a scientific theory can be improved by pointing out the natural behavior of the phenomenon to better clarify the assumptions made in the theory.

Answer:

Developing new technologies.

Explanation:

Explanation:

It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m

The ball remains in the air for 5.4 s, the time of flight is 5.4 s

Time of flight : [tex]T=\dfrac{2v\sin\theta}{g}[/tex]

[tex]5.4=\dfrac{2v\sin\theta}{g}\\\\v\sin\theta=\dfrac{5.4\times 9.8}{2}\\\\v\sin\theta=26.46[/tex]

Maximum height of the projectile : [tex]H=\dfrac{v^2\sin^2\theta}{2g}[/tex]

We need to find H.

So,

[tex]H=\dfrac{(v\sin\theta)^2}{2g}\\\\H=\dfrac{(26.46)^2}{2\times 9.8}\\\\H=35.72\ m[/tex]

So, it will rise to a height of 35.72 m.

Answer:

Explanation:

[tex]Speed = 4m/s\\Time = 2m = 120 secods\\\\Distance = ?\\Distance = Speed \times time \\\\Distance = 4 \times 12\\= 48\: meters[/tex]

The distance covered by the person is 480 meters.

We have a a person who runs at 4 m/s for 2 minutes.

We have to determine how far he had run.

The distance travelled by the body can be given by -

d = v x t

where -

v - velocity of body

t - time for which the body travelled

According to question, we have -

v = 4 m/s

t = 2 minutes = 120 seconds

Therefore, the distance travelled will be -

d = v x t

d = 4 x 120

d = 480 meters

Hence, the distance covered by the person is 480 meters.

To solve more questions on Kinematics, visit the link below -

https://brainly.com/question/19127971

#SPJ2

Answer:

The displacement of the boat is 7.41 m

Explanation:

Given;

initial velocity of the motorboat, u = 6.5 m/s west

final velocity of the motorboat, v = 1.5 m/s west

acceleration of the motorboat, a = -2.7 m/s² east

The displacement of the boat is given by;

v² = u² + 2ad

where;

d is the displacement of the motorboat

1.5² = 6.5² + 2(-2.7)d

1.5² -  6.5² = -5.4d

-40 = -5.4d

d = (40) / 5.4

d = 7.41 m

Therefore, the displacement of the boat is 7.41 m