A right triangle has leg lengths of 1 m and √15 m. What is the length of the hypotenuse?

Answer:

12624 packets

Step-by-step explanation:

To solve this let the unknown number of packets be x.

        1 box ⇒ 48 packets

263 boxes ⇒ x

Now let us use cross multiplication to find the value of x.

1 × x = 48 × 263

1x     = 12624

Divide both sides by 1.

x = 12624

Answer:

$324.33

Step-by-step explanation:

the answer is $324.33

The amount of interest capitalized is greater than the minimum amount that she could pay to prevent interest capitalization by; D: $324.33

We will use the formula: A = P(1 + r/n)^(nt)

Where:

A = final amount

P = initial principal ($9300)

r = interest rate (6.4% or 0.064)

n = number of times interest applied per time period

t = number of time period elapsed.

Thus;

9300(1 + 0.064/12)^(12*4) - 9300 = $2705.13

Also;

9300(0.064/12) * 4 * 12 = $2380.8

Answer = $2705.13 - $2380.8

Answer = $324.33

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Answer:

you think about it. if you dont do the work yourself u wont ever learn.

Step-by-step explanation:

6x10^6=6,000,000

2.4x10^8=240,000,000

The greatest relative frequency is the relative frequency that gives the highest probability

The greatest relative frequency given discrete random variable X, when X∼B(4,110) is  x=3

For a discrete random variable, the smaller the value of the variable, the higher its relative frequency.

This means that:

A variable x = 0 would have a greater relative frequency than a variable x =  n, where n > 0

This means that, the greatest relative frequency given discrete random variable X, when X∼B(4,110) is  x=3

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Answer:

can't you do Russian math homework on your own

Step-by-step explanation:

Answer:

A) 0

Step-by-step explanation:

x = 3 is a vertical line.

A line perpendicular to x = 3 is a horizontal line.

A horizontal line has slope = 0.

Answer:

C

Step-by-step explanation:

Each input value can have only one output value for it to be a function. In other words, there should only be one y value for each x value. The only option that satisfies this is C.

Step-by-step explanation:

12% of 125

or is ×

12% × 125

12% as a decimal

do you know what 12% is as a decimal comment below

Answer:

15

Step-by-step explanation:

12% of 125 is 15

Answer:

x^2-x^2=BC4

oh yeaa u know im right

It's a rectangle

Area:-

Answer:

distance: 7.81 miles

Explanation:

simply use distance formula:  [tex]\sf \sqrt{(y_2 -y_1)^2 + (x_2-x_1)^2}[/tex]

using the equation:

[tex]\hookrightarrow \sf \sqrt{(8-3)^2+(10-4)^2}[/tex]

[tex]\hookrightarrow \sf \sqrt{(5)^2+(6)^2}[/tex]

[tex]\hookrightarrow \sf \sqrt{25+36}[/tex]

[tex]\hookrightarrow \sf \sqrt{61}[/tex]

[tex]\hookrightarrow \sf 7.81 \ miles[/tex]

Answer:

the answer is so you need takes Away -5

Answer:

76

its going by 15's so you add 15

>> Question

1, 6, 13, 22, 33, 46, 61 what comes next??

>> Answer :

1, 6, 13, 22, 33, 46, 61, 78, 97, 118, 141, 166

= +5 , +7, +9 , +11, +13, +15, +17, +19, +21, +23, +25

Step-by-step explanation:

I Hope This Helps

Four Answers:

====================================================

Explanation:

A rational number is any fraction of two whole numbers.

Examples: 7/9 and -8/12

This can be extended to some numbers like [tex]\sqrt{49}[/tex] because

[tex]\sqrt{49} = \sqrt{7^2} = 7 = \frac{7}{1}[/tex]

As you can see, any whole number is also rational but not the other way around.

So far, these examples help show that choices A, C, D, and J are rational numbers. Choice D might need a bit of rewriting like so:

[tex]\frac{0.5}{8} = 0.5 \div 8\\\\ = \frac{1}{2} \div \frac{1}{8} \\\\= \frac{1}{2} \times \frac{8}{1}\\\\ = \frac{8}{2}\\\\ = 4[/tex]

In short, the expression for choice D simplifies to 4 = 4/1 showing that is rational. Or you can use the shortcut that rational/rational = rational.

------------------

A number like [tex]\sqrt{13}[/tex] is NOT rational because the 13 is not a perfect square. There's no way to rewrite that square root as a ratio or fraction of integers. This allows us to rule out choice B. Choices E, F, and G are eliminated for similar reasoning.

Choice H is ruled out because circle areas involve pi = 3.14159... which is famously an irrational number. The proof of which is very lengthy to go over, but the short version is the decimal digits go on forever without a pattern. This is an informal way to check if we have an irrational number.

Choice I is only eliminated if and only if the side lengths of the square are rational, and also when the side lengths are whole numbers. Its not clear what your teacher's intentions here are, but I'll assume this is the case.

------------------

To summarize, we eliminated B, E, F, G, H, I

We're left with A, C, D, J as the final answers. They either can be written as fractions of integers, or already are fractions of integers.

Answer:

A recursive sequence is a sequence in which terms are defined using one or more previous terms which are given. If you know the nth term of an arithmetic sequence and you know the common difference , d , you can find the (n+1)th term using the recursive formula an+1=an+d .

Answer:

(a) = 26.4 or (132/5); 0

(b) = 26.4 or (132/5); -220

(c) = 0; -220

(d) = 0

Step-by-step explanation:

-5k²- 22k + 15

(a)

-5( -3/5 )² - 22( -3/5 ) + 15

     -1.8 + 13.2 + 15 = 26.4 or

     (-9/5) + (66/5) + 15 = (132/5)

I don't know if you do decimal points or fractions so I did both.

-5( -5 )² - 22( -5 ) + 15

-125 + 110 + 15 = 0

(b)  -5 ( -3/5 )²- 22( -3/5 ) + 15

  -1.8 + 13.2 + 15 = 26.4 or

     (-9/5) + (66/5) + 15 = (132/5)

     -5 ( 5 )²- 22( 5 ) + 15

-125 - 110 + 15 = -220

(c)

-5 ( 3/5 )²- 22( 3/5 ) + 15

-1.8 - 13.2 + 15 = 0 or

     (-9/5) - (66/5) + 15 = 0

-5 ( 5 )²- 22( 5 ) + 15

-125 - 110 + 15 = -220

(d)

-5 ( 3/5 )²- 22( 3/5 ) + 15

-1.8 - 13.2 + 15 = 0 or

     (-9/5) - (66/5) + 15 = 0

-5( -5 )² - 22( -5 ) + 15

-125 + 110 + 15 = 0

I hope this helps!

Answer:

The area of any rectangular place is or surface is its length multiplied by its width. For example, a garden shaped as a rectangle with a length of 10 yards and width of 3 yards has an area of 10 x 3 = 30 square yards. A rectangular bedroom with one wall being 15 feet long and the other being 12 feet long is simply 12 x 15 = 180 square feet.

Step-by-step explanation:

Answer It's gonna have to be i think mabey also 12

que dijiste buenas noches

Answer: 0.024

Step-by-step explanation:

percents are out of 100 so 2.4% divided by 100 = the decimal. 2.4/100 = 0.024

Given :

⠀

To Find :

⠀

Solution :

⠀

Then, We know,

[tex] \qquad \sf \dashrightarrow \: 3x + 5x + 7x = 300 \: \: \: \: \: \: \: Perimeter_{(Triangle)}[/tex]

[tex]\qquad \sf \dashrightarrow \: 15x = 300 [/tex]

[tex]\qquad \sf \dashrightarrow \: x = \dfrac{300}{15} [/tex]

[tex]\qquad \bf\dashrightarrow \: x = 20 [/tex]

⠀

So, The sides of the triangle are :

[tex]\qquad \sf \dashrightarrow \: 3 \times 20 \: m = \bf60 \: m [/tex]

[tex]\qquad \sf \dashrightarrow \: 5 \times 20 \: m = \bf 100 \: m [/tex]

[tex]\qquad \sf \dashrightarrow \: 7 \times 20 \: m = \bf140 \: m [/tex]

⠀

Now, Using Heron's formula :

We have,

[tex]\qquad \sf \dashrightarrow \: s = ( {60 + 100 + 140}) \: m = 300 \: m [/tex]

[tex]\qquad \sf \dashrightarrow \: s = \dfrac {60 + 100 + 140}2 \: m = 150 \: m [/tex]

⠀

And the Area will be :

[tex]\qquad \sf \dashrightarrow \: \sqrt{150(150 - 60)(150 - 100)(150 - 140)} \: {m}^{2} [/tex]

[tex]\qquad \sf \dashrightarrow \: \sqrt{150 \times 90 \times 50 \times 10} \: \: {m}^{2} [/tex]

[tex] \qquad \sf \dashrightarrow \: 1500 \sqrt{3} \: {m}^{2} [/tex]

Answer:

2598m²

Step-by-step explanation:

Figure :

[tex]\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf A$}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\put(5,1){$\bf 3x $}\put(2.5, - .5){$\bf 7x $}\put(.5,1){$\bf 5x $}\put(4.5,4){$\bf not \: to \: scale \: $}\end{picture} [/tex]

Here we are given that the ratio of sides of a triangular plot is 3:5:7 and its perimeter is 300m . We are interested in finding the area of the rectangle . Firstly , let us take the given ratio's HCF be x , then we may write the ratio as ,

[tex]\longrightarrow 3x : 5x : 7x [/tex]

According to the question ,

[tex]\longrightarrow 3x + 5x + 7x = 300m \\ [/tex]

[tex]\longrightarrow 15x = 300m\\ [/tex]

[tex]\longrightarrow x =\dfrac{300m}{15}\\ [/tex]

[tex]\longrightarrow x = 20m [/tex]

Therefore , the sides will be ,

[tex]\longrightarrow 3x = 3(20m) = \red{60m}\\ [/tex]

[tex]\longrightarrow 5x =5(20m)= \red{100m}\\ [/tex]

[tex]\longrightarrow 7x =7(20m)=\red{140m}[/tex]

Now we may use Heron's Formula to find out the area of triangle as ,

Heron's Formula :-

Here ,

[tex]\longrightarrow s =\dfrac{300m}{2}=150m [/tex]

Therefore ,

[tex]\longrightarrow Area =\sqrt{ 150(150-60)(150-100)(150-140)}m^2\\ [/tex]

[tex]\longrightarrow Area =\sqrt{ 150 \times 90 \times 50 \times 10}m^2\\ [/tex]

[tex]\longrightarrow Area = \sqrt{ 50^2 \times 30^2\times 3}m^2\\[/tex]

[tex]\longrightarrow Area = 50\times 30 \times 1.732 m^2\\[/tex]

[tex]\longrightarrow\underline{\underline{ Area = 2598m^2}} [/tex]

And we are done !

The number of dogs that are not puppies is 17, the number of adult dogs without long hair is 6, the number of puppy dogs with long hair is 8 and the number of puppy dogs without long hair is 7.

To complete the chart it is necessary to determine:

Number of dogs that are not puppies:

Adult dogs without long hair:

Puppy dogs with and without long hair

Total of puppy dogs = 15, this number can be obtained by adding 9+6 or 7+8. From these combinations, the only one that meets the rule "There are 6 more dogs that have long hair than dogs that do not have long hair" is 8 puppies with long hair and 7 puppies without long hair.

Note: This question is not written correctly; here is the correct and complete question.

Samantha gathered the following information on a given day at the dog park.

There are 32 dogs playing at the dog park.

15 of the dogs are puppies.

11 of the dogs are not puppies and have long hair.

There are 6 more dogs that have long hair than dogs that do not have long hair.

Fill in the table completely to represent Samantha’s data.

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Answer: 8/7

Step-by-step explanation:

=====================================================

Explanation:

The x coordinate of (-2,4) is -2

The y coordinate of (3,-2) is -2

Joining those two up gets us (-2,-2) as one of the answers

--------------

The x coordinate of (3,-2) is 3

The y coordinate of (-2,4) is 4

This leads to the other answer (3,4)

Check out the diagram below.

The answer points are marked in red.

Answer:

C. (–2, –2) and E. (3, 4)

Step-by-step explanation:

Answer:

a) Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

b) Given:

Substituting these values into the equation and rearranging:

⇒ (x - 3)² + x² = 15²

⇒ x² - 6x + 9 + x² = 225

⇒ 2x² - 6x - 216 = 0

c) Solve  2x² - 6x - 216 = 0  by factorizing:

2x² - 6x - 216 = 0

⇒ x² - 3x - 108 = 0

⇒ x² - 12x + 9x - 108 = 0

⇒ x(x - 12) + 9(x - 12) = 0

⇒ (x - 12)(x + 9) = 0

⇒ x - 12 = 0 ⇒ x = 12

⇒ x + 9 = 0 ⇒ x = -9

As distance is positive, x = 12 only.

Therefore, the height of the pole is 12 ft.

So the distance from the hook to the base = 12 - 3 = 9 ft

We need x

Apply Pythagorean theorem

[tex]\\ \rm\Rrightarrow 15^2-x^2=(x-3)^2[/tex]

[tex]\\ \rm\Rrightarrow 225-x^2=x^2-6x+9[/tex]

[tex]\\ \rm\Rrightarrow 2x^2-6x-216=0[/tex]

[tex]\\ \rm\Rrightarrow x^2-3x-108=0[/tex]

[tex]\\ \rm\Rrightarrow (x+9)(x-12)=0[/tex]

[tex]\\ \rm\Rrightarrow x=-9,12[/tex]

We are given with an equation and need to find it's solution set also we are given with a condition that m ≠ {0, 1} . So , let's start ;

So we are given with :

[tex]{:\implies \quad \sf \dfrac{6}{m}+2=\dfrac{m+3}{m-1}}[/tex]

First , we will simplify the given Equation and then we will solve it . So , now taking LCM in LHS ;

[tex]{:\implies \quad \sf \dfrac{6+2m}{m}=\dfrac{m+3}{m-1}}[/tex]

Now , Cross Multiplying ;

[tex]{:\implies \quad \sf (m-1)(6+2m)=m(m+3)}[/tex]

[tex]{:\implies \quad \sf m(6+2m)-1(6+2m)=m^{2}+3m}[/tex]

[tex]{:\implies \quad \sf 6m+2m^{2}-6-2m=m^{2}+3m}[/tex]

Now , transposing whole RHS to LHS and collecting like terms ;

[tex]{:\implies \quad \sf (2m^{2}-m^{2})+(6m-2m-3m)-6=0}[/tex]

[tex]{:\implies \quad \sf m^{2}+m-6=0}[/tex]

Now , we will solve this by splitting the Middle term ;

[tex]{:\implies \quad \sf m^{2}+3m-2m-6=0}[/tex]

[tex]{:\implies \quad \sf m(m+3)-2(m+3)=0}[/tex]

[tex]{:\implies \quad \sf (m+3)(m-2)=0}[/tex]

So , now either , m+3 = 0 or m-2 = 0 . On simplification we will get , m = 2 , -3. So m = {-3, 2}

Hence Option 1) {-3, 2} is correct

Answer:

  (d)  -11

Step-by-step explanation:

The sum of the acute angles of a right triangle is 90°. (That makes the sum of all angles be 180°, as it is for any triangle.)

  65° +(36 +x)° = 90°

  x = 90 -101 . . . . . . . . divide by °, subtract 101

  x = -11