A right-triangle has the hypotenuse length of 5 units long. One of the other sides of the triangle is 3 units. What is the length of the remaining side

Answer:

slope = 2

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (0, 6) ← 2 points on the line

m = [tex]\frac{6-0}{0-(-3)}[/tex] = [tex]\frac{6}{0+3}[/tex] = [tex]\frac{6}{3}[/tex] = 2

Answer:

x=12

Step-by-step explanation:

x^9=12^9

power of 9 cancel eachother at both sides of equation.

so

x=12

The slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.

According to the question,

Line 'a' is perpendicular to the line 'b'. If the slope of the line 'a' is 7.

The condition of slopes if two lines are perpendicular m₁ m₂ = -1

(7)(m₂) = -1

   m₂ = -1/7

Hence, the slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.  

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Answer:

Gavin has 19 nickels & 114 quarters

Step-by-step explanation:

N : D : Q

1 : 3 : 6 = 57

x : 57 : y

57 / 3 = 19

1 x 19 : 3 x 19 : 6 x 19

19 : 57 : 114

No, this not plagiarism .You can use generally accepted facts without citing them.

What defines self-plagiarism?

Self-plagiarism is defined as a type of plagiarism in which the writer republishes a work in its entirety or reuses portions of a previously written text while authoring a new work.

What is considered general knowledge in plagiarism?

How to Avoid plagiarism common knowledge?

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Answer:

2.78%

Step-by-step explanation:

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

We are told that the six-sided dice is fair. This means that each of the faces has the same probability of being rolled.

Therefore, the probability of rolling one is:

[tex]\implies \sf P(x = 1)=\dfrac{1}{6}[/tex]

The probability of rolling six is:

[tex]\implies \sf P(x = 6)=\dfrac{1}{6}[/tex]

Therefore, the probability of rolling one and then six is:

[tex]\begin{aligned}\implies \sf P(x=1)\:and\:P(x=6) & = \sf \dfrac{1}{6} \times \dfrac{1}{6}\\& =\sf \dfrac{1}{36}\\& = \sf 0.0278\:(3\:s.f.)\\& = \sf 2.78\%\:(3\:s.f.)\end{aligned}[/tex]

Total elements in sample space=6

P(1)

P(6)

P(1 and 6)

The values of x is 1 and 6.

According to the statement

we have two tangents which are represented by x+5 and x+1 then

we have to find the value of x to get the perfect value of tangent

so, due to interior values of tangent they are equal to each other but in opposite sign.

But here we have to find the value of x one by one.

It means

Here we take interior value of tangent and exterior value of tangent equal to each other

So, the equations become are written below

X+5= 6 then x = 1

X+1= 7 then x = 6

So, The values of x is 1 and 6.

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Using translation concepts, the equations are given as follows:

a) [tex]y = \sqrt{16 - 4x^2}[/tex]

b) [tex]y = 3\sqrt{16 - x^2}[/tex]

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the parent function is:

[tex]y = \sqrt{16 - x^2}[/tex]

In item a, when it is horizontally compressed by a factor of 2, it means that x -> 2x, hence:

[tex]y = \sqrt{16 - (2x)^2} = \sqrt{16 - 4x^2}[/tex]

In item b, the transformations are given as follows:

Then:

[tex]y = 3\sqrt{16 -(-x)^2} = 3\sqrt{16 - x^2}[/tex]

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Answer:

[tex]a=\sqrt{40.768}[/tex]

Step-by-step explanation:

Given a leg and a hypotenuse we can find the third side by substituting the known values using Pythagorean theorem, let the unknown be a.

[tex]a^2+3.24^2=7.16^2[/tex]

Now all we must do is solve for a:

[tex]a^2+3.24^2=7.16^2\\a^2+10.4976=51.2656\\a^2=40.768\\a=\sqrt{40.768}[/tex]

The quadrants in which all the coordinates given are located is; As explained below.

1) (2, 4) is located in Quadrant I where both x and y-values are positive.

2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.

3) (-1, 1/2) is located in Quadrant IV.

4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.

5) (0, 6) is located in Quadrant I where both x and y-values are positive.

6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.

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The  truncation error for s3  is 0.008

The  truncation error serves as the  difference between a truncated value as well as  the actual value.

This truncated quantity can be a numeral having a fixed number of allowed digits.

Therefore the value of S_3=0.008

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Answer:

C

Step-by-step explanation:

[tex]\frac{x+1}{x-4}[/tex] × [tex]\frac{5x}{x+1}[/tex] ← cancel x + 1 on numerator and denominator

= [tex]\frac{1}{x-4}[/tex] × [tex]\frac{5x}{1}[/tex]

= [tex]\frac{5x}{x-4}[/tex]

Answer:

5x/(x-4)

Step-by-step explanation:

To multiply fractions, all we have to do is multiply the numerators together and the denominators together. If we do that, we get the following:

[tex]\frac{x+1}{x-4}*\frac{5x}{x+1}=\frac{(x+1)(5x)}{(x-4)(x+1)}[/tex]

We notice that both the numerator and the denominator have an (x+1) term. Whenever you have something divided by itself, you get 1. In other words, they cancel out. As such, we can remove them from our answer to simplify it:

[tex]\frac{5x}{x-4}[/tex]

If we do that, we get the expression above. 5x/(x-4) is the reduced product of the rational expression given.

We have lcm(2, 3, 5) = 30, but none of 30/2 = 15, 30/3 = 10, nor 30/5 = 6 are divisible by 2, 3, and 5, respectively.

To account for this, take the square of 30, 30² = 900. Then 900/2 = 450, 900/3 = 300, and 900/5 = 180 are respectively divisible by 2, 3, and 5.

Multiply this by 2 to get a 4-digit number. It follows that [tex]\boxed{a=1800}[/tex].

❄ Hi there,

let us revise the rounding rules and then, get down to rounding the number.

[tex]\sf{Rounding \ Rules:}[/tex]

Now we can start the rounding process.

Reading the problem & the directions, we notice that we need to round to 3 decimal places (3 numbers after the decimal point).

Looking at the fourth number, we notice that it's less than 5.

∴ we need to round down ↡

↬[tex]\sf{18.57631 \ rounded \ to \ 3 \ DP \ = \bf{18.576}}[/tex]

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

❄

Answer: 7

Step-by-step explanation:

By the triangle proportionality theorem,

[tex]\frac{?}{21}=\frac{3}{9}\\\\?=7[/tex]

The mean height of plants is 44.07cm.

Given that a raj measures the height of 70 plants which is shown in the table in the image attached below.

The mean is defined as the mean value equal to the ratio of the total number of a given set of values ​​to the total number of values ​​contained in that set.

Firstly, we will find the midpoint of the height by using the formula

(upper limit +lower limit)/2

When h is 10<h<20 then the midpoint is

x₁=(10+20)/2

x₁=15

When h is 20<h<0 then the midpoint is

x₂=(20+40)/2

x₂=30

When h is 40<h<50 then the midpoint is

x₃(40+50)/2

x₃=45

When h is 50<h<60 then the midpoint is

x₄=(50+60)/2

x₄=55

When h is 60<h<90 then the midpoint is

x₅=(60+90)/2

x₅=75

Now, we will find the mean height by using the formula

x=(f₁x₁+f₂x₂+f₃x₃+f₄x₄+f₅x₅)/(Σfi)

Here, f₁=7,f₂=15,f₃=27,f₄=13,f₅=8

and Σfi=7+15+27+12+8=70

Substitute these values in the formula, we get

x=(7×15+15×30+27×45+12×55+8×75)/70

x=(105+450+1215+715+600)/70

x=(3085)/70

x=44.07

Hence,  the estimate of the mean height of the plants when raj measures the height of 70 plants is 44.07cm.

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A = 6 cm; B = 3 cm; C = 8 cm; D = 10 cm

The Surface area of the prism = 120 cm².

Surface area = Area of A + B + C + D

The side lengths are:

A = 6 cm

B = 3 cm

C = 8 cm

D = 10 cm

Surface area of the prism = 2(area of triangular face) + area of rectangle 1 + area of rectangle 2 + area of rectangle 3

Area of triangular face = 1/2(b)(h) = 1/2(8)(6) = 24 cm

Area of rectangle 1 = (length)(width) = (10)(3) = 30 cm²

Area of rectangle 2 = (length)(width) = (6)(3) = 18 cm²

Area of rectangle 3 = (length)(width) = (8)(3) = 24 cm²

Surface area of the prism = 2(24) + 30 + 18 + 24 = 120 cm².

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[tex] {\qquad\quad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } = 34[/tex]

[ add 2 on both sides ]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } + 2 = 34 + 2[/tex]

[ form identity : a² + b² + 2ab ]

[tex]\qquad \sf  \dashrightarrow \: {(x)}^{2} + { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2} + 2 \sdot(x) \sdot \bigg(\cfrac{1}{x} \bigg) = 36[/tex]

[ a² + b² + 2ab = (a + b)² ]

[tex]\qquad \sf  \dashrightarrow \: {\bigg (x + \cfrac{1}{x} \bigg) }^{2} = 36[/tex]

[tex]\qquad \sf  \dashrightarrow \: {\bigg (x + \cfrac{1}{x} \bigg) }^{} = \sqrt{ 36}[/tex]

[tex]\qquad \sf  \dashrightarrow \: x + \cfrac{1}{x} = \pm 6[/tex]

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

Answer:

Total cost is $177.50.

Step-by-step explanation:

Rackets:

Divide the cost for racket by 6 to find the cost per racket.

186÷6=31

Multiply 31 by 5 to find the cost for 5 rackets.

31×5=155

$155

Tubes of balls:

Divide 27 by 6 to find the cost per a tube of balls.

27÷6=4.50

Multiply 4.50 by 5 to find the cost for 5 tubes of balls.

4.50×5=22.50

$22.50

Add the amounts for rackets and tubes of balls to find the total cost.

155+22.50=177.50

The total cost is $177.50.

Hope this helps!

The surface area of pyramid is 47km^2

A regular pyramid has a base that is a regular polygon and a vertex that is above the center of the polygon.

A pyramid is named after the shape of its base. A rectangular pyramid has a rectangle base. A triangular pyramid has a triangle base.

Given that the base of the pyramid is 5 km and the slant height is 4.7km

We need to find the surface area of pyramid

We know that

The lateral surface of pyramid = 4 *(1/2* length of base * slant height)  

= 2*5*4.7

=47km^2

Hence the surface area of the pyramid is 47km^2

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Answer:

a₃₂ = 131

Step-by-step explanation:

the nth term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 7 and d = 4 , then

a₃₂ = 7 + (31 × 4) = 7 + 124 = 131

The given statements:

1) ΔQRS ≅ ΔSTU (according to the ASA axiom)

2) The congruent ∠S: ∠RSQ ≅ ∠UST (Vertical angles)

The ASA axiom states that "two triangles are said to be congruent if two pairs of corresponding angles and the sides between these angles are equal".

It is given that,

S is the midpoint of QT.

So, SQ ≅ ST <S>

Since ∠S is at the intersection of two transversal lines, ∠RSQ ≅ ∠UST <A>.  This is beacuse they are vertically opposite.

And QT is the transverse line for the parallel lines, QR║UT. So, the alternate angles(interior) are congruent. I.e., ∠SQR ≅ ∠UTS <A>.

From this, the given triangles have two equal corresponding angles and congruent sides in between them.

So, ΔQRS ≅ ΔSTU according to ASA axiom.

Therefore, ΔQRS ≅ ΔSTU and ∠RSQ ≅ ∠UST.

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Answer:

-12

Step-by-step explanation:

First, solve in parentheses.

2(-2-4)

=

2(-6)

Next, multiply 2 by -6.

Which equals -12.

So therefore using the distributive property shown above, the answer would be -12.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{What is the distributive formula?}[/tex]

[tex]\mathsf{a(b + c)}[/tex]

[tex]\mathsf{= a(b) + a(c)}[/tex]

[tex]\mathsf{= ab + ac}[/tex]

[tex]\huge\textbf{What is the equation?}[/tex]

[tex]\mathsf{2(-2 - 4)}[/tex]

[tex]\huge\textbf{What are we simplifying?}[/tex]

[tex]\mathsf{2(-2 - 4)}[/tex]

[tex]\mathsf{= 2(-2) + 2(-4)}[/tex]

[tex]\mathsf{= -4 - 8}[/tex]

[tex]\mathsf{= -12}[/tex]

[tex]\huge\textbf{How are you going to translate to}\\\\\huge\textbf{easier terms?}[/tex]

[tex]\mathsf{2(-2 - 4)}[/tex]

[tex]\mathsf{= 2(-6)}[/tex]

[tex]\mathsf{= -12}[/tex]

[tex]\huge\textbf{What is the ANSWER to the question?}[/tex]

[tex]\huge\boxed{\mathsf{-12}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The graph that models the pH of this solution is graph A.

It should be noted that a graph is a diagram such as a series of one or more points, lines, line segments, curves, or areas which represents the variation of a variable in comparison with that of one or more other variables.

The pH is a measure of how acidic or basic water is. It should be noted that the range goes from 0 - 14, with 7 being neutral. The pHs of less than 7 indicate acidity, while a pH of greater than 7 indicates a base. The pH is really a measure of the relative amount of free hydrogen and hydroxyl ions that are in the water.

In this case, x represents the concentration of the hydrogen ions. The first graph illustrates this.

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Complete question:

The ph of a particular solution is given by pH=-log(x-2) where x represents the concentration of the hydrogen ions in the solution in moles per liter. Which graph models the ph of this solution?

Answer:

[tex]T_{23}=-153[/tex]

Step-by-step explanation:

[tex]T_{23}=a+(n-1)d\\[/tex]

[tex]=a+(23-1)d=a+22d[/tex]

Now [tex]a=-21[/tex] and

[tex]d=-27-(-21)\\=-6[/tex]

So [tex]T_{23}==21+((22)6\times-1)[/tex]

[tex]=-153[/tex]

Using an exponential function, it is found that there will be 32,768 bacteria after 3 hours.

An exponential function is modeled by:

[tex]y = ab^x[/tex]

In which:

For this problem, the parameters are:

a = 8, b = 4.

3 hours is 6 periods of 30 minutes, hence the amount is:

[tex]y = 8 \times 4^6 = 32768[/tex]

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The amount of money Kim, maneet and Sutopa have is $115.6, $97.6 and $73.2 respectively.

x + (x - 18) + 3/4(x-18) = 286.40

x + x - 18 + 3/4x - 13.5 = 286.40

2 3/4x = 286.40 + 13.5 + 18

11/4x = 317.9

x = 317.9 ÷ 11/4

= 317.9 × 4 / 11

= 1,271.6 / 11

x = $115.6

So,

Kim = x

= $115.6

Maneet = x - 18

= 115.6 -18

= $97.6

Sutopa = 3/4(x-18)

= 3/4(97.6)

= $73.2

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Answer:

(f-g)(x)= (3x + 10) - (5x -3)

f-g = 3x + 10 - 5x + 3

f-g = -2x + 13