A rock is thrown vertically downward from a
building with an unknown initial (1-d) velocity.
If the rock hits the ground after 3.50 s, with a
final (1-d) velocity of -50.0 m/s, what was the
initial (1-d) velocity of the rock?
[?] m/s
Signs: Define "up" positive, "down" negative.

Answers

Answer 1

The initial velocity is -25m/s.

What is velocity?

Velocity, which is a vector quantity, is referred to as the "pace at which an item changes its position." Imagine someone moving quickly, constantly going back to their starting position after taking one step forward. The velocity would be zero, even though there might be a frenzy of activity as a result.

What is acceleration?

Acceleration is the rate at which the direction and speed of motion change over time. Anything is said to have been accelerated when it moves straighter and faster or slower. Motion on a circle accelerates even though the speed is constant because the direction is constantly changing.

Is up in physics positive or negative?

If you choose to make the upward direction negative and the downward direction positive (the commonly accepted convention), then g will be positive if the object is stationary or moving downwards. If an object is moving upward, g will be negative.

Therefore, the initial velocity is -25m/s.

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Related Questions

how much work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed vv to a speed 2v2v?

Answers

Using the concepts of work, we got that we need to work three times of the previous work to accelerate the object from a speed v to a speed 2v.

We know that to change the velocity of any object we need to do some work on it.

When an object having some mass m moving with velocity v, then the kinetic energy stored in that object is given by(KE₁) =(1/2)mv².

Now, When an object having some mass m moving with velocity 2v,then the kinetic energy stored in that object is given by(KE₂) =(1/2)m(2v)².

New kinetic energy is =4[(1/2)mv²] or 4KE₁

So, net work to accelerate the object is =KE₂-KE₁

                                                               W=4KE₁-KE₁=3KE₁.

Hence,  the amount of  work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed v to a speed 2v is 3 times the energy stored on a object.

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two identical, parallel-plate capacitors are connected to identical batteries and allowed to charge fully. a dielectric is placed between the plates of one of the capacitors while still connected to the battery and allowed to reach a steady state. discuss whether the capacitance, charge, and electric potential of the capacitor with the dielectric are greater than, less than, or equal to the capacitor without the dielectric.

Answers

Capacitance, charge and electric potential will be greater than the capacitor without the dielectric.

Capacitance is the a property of an electric conductor or set of conductors that is measured by the amount of separate electric charge that can be stored on it per unit change in electric potential.

The value of capacitance for the parallel plate is C = (3∈0AK)/d

Since two identical, parallel-plate capacitors are connected

therefore the value of capacitance for both the plate is C

Ceq. = (C1*C2) / C1 + C2 = C*C / C+C = C2

When the battery remains connected, the potential difference [V] remains constant

Q=CV

∴Cafter>Cbefore [C increased]

∴Qafter>QBefore [Q increased]

Potential difference and charge across the capacitor before the dielectric:

Qbefore = [tex]\frac{CV}{2}[/tex]

Vbefore = Vafter = V

Potential difference and charge on the capacitor after inserting the dielectric:

Qafter = Ceq*V = [tex]\frac{kCV}{k+1}[/tex]

Vafter = Q*After / KC =  [tex]\frac{\frac{kCV}{k+1}}{kc}[/tex]

Vafter=  [tex]\frac{V}{k+1}[/tex]   [K>1]

[Hence V decreases]

Vbefore > Vafter

Also,  E = [tex]\frac{V}{d}[/tex]

therefore [E]before > [E]after [E decreases]

Energy stored in the capacitor:-

U=[tex]\frac{1}{2} CV^{2}[/tex]

As V= constant

Cafter > Cbefore .

Hence Uafter > Ubefore

Thus, the electrostatic potential increases.

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two polarizers are oriented to each other by an angle of 75 degrees. polarized light with a polarization angle 25 degrees from the axis of the polarizer is incident on the first polarizer. how much of the light incident on the first polarizer (what percentage) makes it through the second?

Answers

82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.

We can use Snell's law to find out how much of the light makes it through the second polarizer.

Snell's law gives us:

sin(θ1)×sin(θ2)=n1×n2

Solving for n1, we get:

n1=(sinθ1cosθ2)/(sinθ1sinθ2)

We know that θ1 and θ2 are each 75 degrees, so we can put this into our equation:

n1=(0.5)(0.5)/(0.25)(0.75)=0.8333

This means that 82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.

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later the car is traveling along a long straight road when it passes over a hill. the hill has a radius of 230 m. what is the minimum speed the car must have in order to become airborne as it crests the hill?

Answers

The minimum speed at which a car can leave the road at the top is 47.47 m/s

What is the minimum speed?

Following are the calculations for the minimal speed at which a vehicle can veer off the road;

The hill has a radius of 230 m

Fc = Fn

[tex]\frac{mv^{2} }{r} = mg \\\frac{v^{2} }{r} =g\\v^{2} =rg \\v=\sqrt{rg}[/tex]

where;

The curving road's radius is 230 meters, and

the acceleration caused by gravity is 9.8 meters per second.

[tex]v = \sqrt{230* 9.8}[/tex]

r = 47.47

As a result, 47.47 m/s is the lowest speed at which a vehicle can exit the road at the top.

Find the approximate centripetal acceleration caused by gravity, g, in meters per second squared, and the radius of the vertical circular motion, r, in meters. Step 2: Using the formula vmin=rg v min = r g, get the object's minimum speed (the speed at the top of the circle).

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mountain goats can easily scale slopes angled at from horizontal. what are the normal force and the static friction force acting on a mountain goat that weighs 900 n and is standing on such a slope?

Answers

Using these formulas, determine the normal and static friction forces acting on the mountain goat.

What is normal force?

The normal force is the pressure that surfaces apply to stop solid objects from piercing one another. The normal force is a force in contact. Two surfaces cannot exert a normal force on one another if they are not in contact.

What exactly is static friction force?

An object experiences static friction when a force is applied to it; as a result, the object resists the applied force and stays at rest until static friction is removed. In kinetic friction, the frictional force opposes an object's motion.

Given:

The 60° angle from horizontal

900 N is the weight of the mountain goat.

To calculate the normal force, the weight perpendicular to the tilt must be resolved. As a result, we can write:

N = W CosΘ

= 900 N(Cos 60°)

= 900 N(0.5) (0.5)

= 450 N

The forces acting in conjunction with the inclination must all be added to determine the static friction force. We document:

F = W sinΘ

= 900 N(sin 60°)

= 900 N(0.8660254038) (0.8660254038)

= 779.42 N

Therefore, the normal force is 450 N, and the static friction force is 779.42 N.

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what must be the magnitude of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

Answers

magnetic field caused by the combination of wires to cancel out, the current will flow in a direction . The current will therefore move in the other direction,. The outside wire is experiencing a 15.83 A current.

What is the current physics equation?

The electric current formula, I=V/R, can be used to determine how much current is flowing. The "current equation," as it is commonly known, is derived from Ohm's Law. The variable "I" denotes current, "V" denotes voltage, and "R" denotes resistance.

What do current and electron actually mean?

Electron movement is referred to as electron current. The positive terminal receives electrons that are released by the negative terminal. Traditional current, usually referred to as just current, exhibits behavior consistent with positive charge carriers being the source of current flow. A positive terminal receives normal current, which then travels to a negative terminal.

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Joe is using a crowbar to remove a tree stump. He applies 2066 J of work to the crowbar. The output work of the crowbar is 1240 J. What is the efficiency of the crowbar?

Answers

Joe is using crowbar to remove tree stump. When output and input work is given then the efficiency can be calculated as 60%.

How is efficiency defined ?

Efficiency can be defined as how good a device is at transferring input energy to useful output energy . The efficiency of a device is the proportion of the energy supplied that is transferred for useful work. The efficiency is calculated as a decimal or a percentage.

Given output work as 1240 J

input work as 2066 J

Then efficiency can be calculated by using the formula :

Efficiency= (output work/ input work) * 100%

=( 1240/2066) * 100%

Efficiency = 60%

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You land on an unexplored foreign planet, and have with you a 2.5 tool. You determine that the force of gravity acting on the tool
is 19.5. What is the gravitational acceleration of the planet?

Answers

Based on the value of the mass of the tool and the force of gravity on that planet, the gravitational acceleration of the planet is 7.8 m/s².

What is the gravitational acceleration of that planet?

The mass and force of gravity acting on a body are related by the formula given below:

Force of gravity = mass * gravitational acceleration

The mass of a body is constant but the force of gravity acting on a body or the weight of the body varies depending on the value of the gravitational acceleration.

Considering the given values:

Mass of tool = 2.5 kg

Force of gravity acting on the tool = 19.5

gravitational acceleration = force of gravity / mass

gravitational acceleration = 19.5 / 2.5

gravitational acceleration = 7.8 m/s²

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1. Imagine you rubbed just one side of a thick piece of Styrofoam.
What do you think you would observe if you brought the rubbed side of the Styrofoam up to a neutral object?
2. What do you think you would observe if you brought the unrubbed side of the Styrofoam up to a neutral object?

Answers

The answers include the following:

The observation if you brought the rubbed side of the Styrofoam up to a neutral object is that the both of them will become negatively charged and repel.The observation if you brought the unrubbed side of the Styrofoam up to a neutral object is that they will be repulsion because it involves two neutral charges.

What is Charge?

Thus is referred to as the physical property of matter that causes it to experience a force when placed in an electromagnetic field. We should also note that like poles repel and unlike poles attract.

When the styrofoam is rubbed, it becomes negatively charged which when placed in contact with another neutral charge will result in the repulsion. In the case in which the unrubbed side of the styrofoam is placed near a neutral charge there will also be repulsion.

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you pull a box with a constant force of 250 n. it takes you 20 s to move the box 10 m along a rough surface at a constant speed. what power are you transferring to the system of the box and the rough surface?

Answers

Your power usage when pulling the box is 125 Watts. It takes 20 seconds to move a box 10 meter's along a rough surface when applying a continuous 250 n force.

Given: force = 250 N; distance = 10 m; speed = distance/time (10/20); speed = 0.5 m/s

W = work completed, where W = 250*10 = 2500 Joules.

Your labour of 2500 J by pulling the box

Thermal energy produced—considering that the box's surface and interior are both made of wood. Therefore, the kinematic friction coefficient is 0.3.

The thermal energy is therefore 75 N

thermal energy = 75*10 = 750 Joules, or thermal energy = force*d

force = mu

 force= 0.3*250.

So pulling the Box produces 750 Joules of thermal power.

Power exerted = force* v

= 250*0.5

=125 Watts

so, The power exerted by you while pulling box is 125 Watts.

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if a radiograph is done using an 80 inch ffd and 12 mas and a second image is done using a 40 inch ffd, what is the new mas that should be used?

Answers

The new mas that needs to be applied reduces mAs 1 devided by 4 , which is 3.

How do you locate fresh mAs?Milliamperage and time are multiplied to get the unit mAs (mA). A typical technique setting for imaging a hurt hand, for instance, may be 60 kVp, 100 mA, and 1/100 of a second (0.01). In this case, 100 milliamperes times 0.01 secondes = one milliampere (or 1 milliampere-second).Usually, the word "más" is used as an adverb to denote "more" or "most." Más, which means "more," can also be used as an adjective or pronoun. The term mais, which is a literary word that means "but," is not the same as the word más.  

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What does water's high specific heat capacity explain about water?

A) why water bonds with other molecules
B) why water is often used as a solvent
C) why water is unable to absorb energy
D) why water is liquid at room temperature

Answers

Water's high specific heat capacity explains why why water bonds with other molecules.

The correct answer choice is option a.

Why water bonds with other molecules

Water has the ability to easily attract other molecules simply because of the fact its hydrogen and oxygen components is made up of positive and negative ions respectively.

Technically, the bonds in hydrogen possess a form of electrostatic force which makes it very possible for water to bond with other molecules with its high specific heat capacity.

So therefore, we can now confirm and deduce that from the simple note given above that the hydrogen bonds presence in water molecule makes it easy for water to combine with other molecules.

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30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? a 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? 2.07 m 1.93 m 2.12 m 2.20 m 1.98 m

Answers

The length of the beam on which the the two boys are lying is 1.01 m.

The mass of one kid is 30 kg and the mass of the beam is 20kg, the beam is balanced at a distance of 1.10 m from the 30 kg boy when a 40kg boy was sitting at the other end of the beam.

If the beam is balanced at 1.10 m from the 30kg boy it means that there lies the center of mass of the system.

So, let us assume the length of the beam to be X meters and the assume the center of mass to be at center.

So,

0 = M₁X₁ + M₂X₂/M₁+M₂

M₁ is 30kg and X₁ is 1.10m.

M₂ is 40kg and the X₂ is (X-1.10)m.

Putting values,

0 = 30 x 1.1 + 40 x (X-1.1)

(1.1 - X)40 = 3.3

X = 1.01 m.

So, the length of the Beam is 1.01 m.

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a funny car accelerates from rest through a measured track distance in time t with the engine operating at a constant power p. if the track crew can increase the engine power by a differential amount dp, what is the change in the time required for the run? (use any variable or symbol stated above as necessary.)

Answers

dT = -T^4/(2mD^2)dP


P = W/T = FD/T = (m a)D/T

dP = -maD/T^2 dT

dT = -T^2/(maD)dP

V = aT

D = 1/2 a T^2

a = 2D/T^2

dT = -T^4/(2mD^2)dP



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It takes 6 people pulling with a force of 500. N each to begin moving the opposing team which was pulling with a combined force of 2500. N during a match of tug-of -war. If the total mass of both teams was 2000. kg, what was the force due to static friction? HELP ME .

Answers

From the calculations, we have the coefficient of friction as  0.026.

What is the coefficient of static friction?

We know that friction has to do with the force that tends to oppose the motion of an object. As such, the point where the force of friction acts is actually the surface that lies between two bodies.

Now, we can see that It takes 6 people pulling with a force of 500 N each to begin moving the opposing team which was pulling with a combined force of 2500 N. This implies that the total force of the people that are pulling from this other side is 6 (500N) = 3000 N

Now we have the net force that is acting on the the rope as; 3000 N - 2500 N = 500 N

Then;

Coefficient of friction = Net force/ Normal reaction

= 500 N/(2000 * 9.8) N

= 0.026

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the system produces 80,176 watts, what is the energy worth per day? assume electricity costs of $0.08 per kwh

Answers

Electricity costs of the system at $0.08 per kwh for a day is $153.9

What is power?

Power refers to the rate of work. It is work done per unit of time. The SI unit for power is the watt (W), which is the joule per second (J/s).

Power = Work / time

P = W / t

One kilowatt hour is said to be one thousand watts sustained for one hour i.e. KWh = (Watts × Hours) ÷ 1,000

For the given case,

Power = 80,176 watts

Rate = $0.08 per kwh

kWh = (watts × hrs) ÷ 1,000

kWh = (80,176 × 24)

= 1924.224 kWh

Total cost of the day is = 1924.224 × 0.08

= $ 153.9

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A 900 kg coaster car is 13 m high traveling at 28 m/s at point C. If point E is 10 m high, how fast will the car be traveling assuming no frictional forces?

Answers

The velocity of the car at point E which is  10 m is determined as 24.2 m/s.

What is the final velocity of the coaster?

The final velocity of the coaster car is calculated by applying the principle of conservation of energy.

total kinetic energy of the coaster = total potential energy of the coaster

K.E = P.E

-¹/₂mv₁² + ¹/₂mv₂² = -mgh

-v₁² + v₂² = -2gh

v₂² = v₁² - 2gh

where;

m is the mass of the coasterv₁ is the initial velocity of the coasterv₂ is the final velocity of the coasterh is the height of travel of the coaterg is acceleration due to gravity

The given parameters include;

initial velocity of the coaster = 28 m/sheight of travel = 10 m

v₂² = v₁² - 2gh

v₂² = (28²) - (2 x 9.8 x 10)

v₂² = 588

v₂ = √588

v₂ = 24.2 m/s

Thus, the final velocity of the coaster car at the given height will be smaller than the initial velocity due to effect of gravity.

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a 70kg skater from side to side on a curved ramp they start at a height of 5m
at the boot on of the ramp they have the speed of 9.5m/s
on the opposite side of the ramp they only reach a maximum height of 4cm
describe the energy stores and transfers that take place as the skater moves form side to side on the ramp

Answers

The velocity of the skater will increase as he moves towards the center of the ramp and consequently the kinetic energy will increase. The kinetic energy will converted into potential energy as he moves towards the maximum height.

What is law of conservation of energy?

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

As the skater move from side to side on the curved ramp, his kinetic energy will be converted into potential energy.

Mathematically, it be written as;

K.E = P.E

¹/₂mv²  =  mgh

where;

m is the mass of the skaterv is the speed of the skater at the lowest pointh is the maximum height attainedg is acceleration due to gravity

As the skater moves from the highest point with zero velocity, he will have maximum potential energy which decreases as he moves towards the center of the ramp. The velocity will increase as he moves towards the center of the ramp and consequently the kinetic energy will increase.

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a projectile is fired into a region of no air resistance the horizontal component of velocity remains constant because projectiles
A) is not acted on by any horizontal force
B) is affected by gravity
C) has no vertical component of velocity

Answers

A projectile is fired into a region of no air resistance the horizontal component of velocity remains constant because projectiles

A) is not acted on by any horizontal force

Velocity remain constant until unless any net external force acts on the object . While in a projectile motion , there is a gravitational force which act in downward direction . And there is no horizontal force , hence horizontal velocity remain unchanged . Velocity remains constant because projectiles

A) is not acted on by any horizontal force

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A rocket is burning fuel at the rate of 300g/s and electing all the gas. In one direction of the rate of 500m/s what is maximum weight the rocket burn have if it going to move Vertically upward.

Answers

Correct option is D)

Overall momentum of the system is conserved.

Therefore, change in momentum of the rocket will be equal to that of the fuel.

Change in momentum of the fuel will be

Δmv=60000

Hence, change in momentum of the rocket will also be:

△P=60000

Thrust force F=

△t

△p

F=60000 N

what effect does the amplitude setting on the function generator have on oscope display of the voltage in the small coil?

Answers

As the amplitude increases from the wave generator, the Voltages passing through the inductor will be higher. and consequently, the current passing through the inductor will also be higher Remember that when a voltage is applied across the inductor, the current is driven in the inductor due to the applied voltage.

When the applied voltage is sinusoidal it creates a sinusoidal current in the inductor with the same frequency as the applied voltage. As this current increases, it creates an induced potential difference proportional to the rate of change of current, and hence there is a sinusoidal induced voltage in the Inductor.

The function generator's amplitude control changes the voltage difference between the output signal's high and low voltage. Its direct current offset control changes the signal's average voltage with regard to the ground. A function generator is equipment to generate input functions for your circuit. It can generate sinewaves, square waves, triangular waves, modulated signals, and so on. An oscilloscope is equipment to display the signals in the circuit.

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Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in one year.

State the speed in mi/s, using scientific notation. (1 mile = 5280 feet exactly, by definition; i.e., this is not a measurement.)

Answers

The speed of light in miles per second (mi/s) is 186,000 mi/s.

What is the distance travelled by light in a year?

The distance travelled by light in a year is known as light-year. This distance travelled by light in a year depends on the speed of light.

The speed of light in a year is given as 982,080,000 ft/s. The unit of this speed of light in feet per seconds can be converted into miles per second.

The speed of light in miles per second (mi/s) is calculated by using the following conversion factor.

1 mile = 5280 feet

982,080,000 ft/s = 982,080,000 ft/s x 1 mile/5280 ft

982,080,000 ft/s = 186,000 miles/s

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what is the fundamental resolution limit (diffraction limit) for a telescope with a mirror that is 30 meters in diameter at a wavelength of 500 nanometers (green light)? give your answer in degrees or radians.

Answers

By using  Rayleigh criterion principle, we can calculate the Fundamental resolution limit would be 20.33 x [tex]10^{-9}[/tex] radians

The Rayleigh criterion for the diffraction limit to resolution states that two images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other.

According to the Rayleigh criterion principle, we have

Ф = 1.22 λ/D

where Ф is the resolution limit in radians

λ = wavelength of the light

D = diameter of the lens or the telescope

putting  the appropriate values, we get

Ф  = 1.22 x 500 x [tex]10^{-9}[/tex] / 30

Ф   = 20.33 x [tex]10^{-9}[/tex] radians

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3. (a) calculate the work done on a 1500-kg elevator car by its cable to lift it 40.0 m at constant speed, assuming friction averages 100 n. (b) what is the work done on the elevator car by the gravitational force in this process? (c) what is the total work done on the elevator car?

Answers

(a) Work done on the car by its cable will be 5.92 * [tex]10^{5}[/tex] J.

(b) Work done on the car by the gravitational force will be -5.92 * [tex]10^{5}[/tex] J.

(c) Total work done on the car will be 0 J.

Work done is the product of force and displacement.

Mathematically, Work-done = W = Force * Distance

Mass of the car = m = 1500 kg

Distance lifted by the cable = d = 40 m

Frictional force experienced by the car = Fs = 100 N

(a) According to the Newton's second law of motion

F = Fcable - mg - Fs = ma

Fcable = mg + Fs

Work done by the same force = W1

W1 = Fcable * d

W1 = (mg + Fs) * d

W1 = (1500*9.8 + 100) * 40

W1 = 592600

W1 = 5.92 * [tex]10^{5}[/tex] J

(b) Work done by the gravitational force = W2 = mg * d

W2 = 1500*(-9.8)*40

Since the acceleration is acting downwards 'g' will be considered with a negative sign.

W2 = -5.88 * [tex]10^{5}[/tex] J

(c) The total work done on the lift is the work done by the net force exerted on the car during this process:

W3 = Fnet * d

Fnet =  -5.88 * [tex]10^{5}[/tex] J +  5.92 * [tex]10^{5}[/tex] J

Fnet = 0

W3 = 0 * 40

W3 = 0 J

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ssm a warehouse worker exerts a constant horizontal force of magnitude 85 n on a 40 kg box that is initially at rest on the horizontal floor of the warehouse. when the box has moved a distance of 1.4 m, its speed is 1.0 m/s. what is the coefficient of kinetic friction between the box and the floor?

Answers

The coefficient of the kinetic friction between the box and the floor is μk 0.21.

Friction is the force resisting the relative motion of strong surfaces, fluid layers, and fabric elements sliding against every different. There are several sorts of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.

Calculation:-

Given,

mass = 40 Kg

Applied force F = 85 N

initial velocity u = 0 (rest)

distance moved = 1.4 meter

Final velocity = 1 m/s

coefficient of kinetic friction =?

Normal force = N = mg = 400 N

v² = u² +2as

a = v²/2s

  = 1/2×1.4

 = 0.36 m/s²

F = μkN

μk = F/N

     = 85/400

     0.21

Friction is a shape of touch pressure. It exists between the surfaces which are in touch. The frictional force relies upon on the person of the surface in contact. The rougher the floor, the greater the friction is involved. The frictional force is proportional to the urgent pressure, this is the weight of the body. it's far impartial of the place of the touch.

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why does saturn radiate even more excess energy than jupiter? why does saturn radiate even more excess energy than jupiter? saturn can fuse hydrogen into helium in its core, like the sun. helium rain gives off heat as it differentiates toward saturn's center. saturn's atmosphere contains much methane, creating a large greenhouse effect. saturn's thick cloud layer contributes to a larger greenhouse effect. saturn is still radiating heat left over from its formation.

Answers

Saturn radiates even more excess energy than Jupiter Helium rain gives off heat as it differentiates toward Saturn's center. Option B.

Its density is so low that it floats on water. Like Jupiter, Saturn emits almost twice as much energy as it receives from the Sun. This is because it has its own internal heat source driven by the slow gravitational collapse that began with the planet's formation. The Jupiter planet draws heat from the Sun and from within.

Jupiter produces a lot of internal heat and emits thermal radiation to release this heat. In fact, Jupiter produces so much internal heat that it emits almost twice as much energy as it receives from the Sun. Hydrogen exists in a liquid metallic state around the central rocky core and surrounds the inner half of the planet. Compared to Jupiter, Saturn's mass and volume consist of this conductive metallic liquid which may partly explain why Saturn's magnetic field is much weaker.

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If a car, with an initial velocity of 15 m/s, accelerates at a rate of 5 m/s^2 for 4 seconds, what will its final velocity be? ​

Answers

Answer:

35 m/s

Explanation:

vf = vo + at

vf = 15  +  5(4) = 35 m/s

Question 8
The scientist mixed a substance A into water. After mixing the substance the scientist
saw that most of the substance did not dissolve making the solution supersaturated.
The scientist wrote a conclusion on his experiment and noted that he put to much solute
in his solvent. Which of the following substances should the scientist use less of next
time substance A or water?
O Water
3 pts
O Substance A
O Solution

Answers

Answer:

It is likely water

Explanation:

Due to an average medium PH level it doesn't dissolve much.

To become familiar with the order of magnitude of magnetic effects, consider the situation in a television cathode ray tube (not a flat-panel TV). In order to bend the electron trajectory so that the electron hits the top of the screen rather than going straight through to the center of the screen, you need a radius of curvature in the magnetic field of about 20cm20cm (Figure 20.95 ). If the electrons are accelerated through a 15,000 VV potential difference, they have a speed of 0.7×108m/s0.7×108m/s Calculate the magnitude of the magnetic field required to make the electrons hit the top of the screen. Is the magnetic field into or out of the page?

Answers

4.1510^-3 tesla the magnitude of the magnetic field required to make the electrons hit the top of the screen

v=0.7×10^8m/s

q=1.6×10^-19 C

B= ?

Voltage= 15,00 V

r= 20cm= 0.2 m

r=mVqB

B=mv/qr

B=4.1510^-3 tesla

To observe magnetic forces, one can utilize a magnetic field, an electric current, a changing electric field, or a vector field surrounding a magnet. Magnetic compass needles and other permanent magnets point in the general direction of magnetic fields resembling those on Earth. Electrically charged particles move in a helical or circular pattern in magnetic fields. Electric motors operate on this force, which is applied to electric currents in wires in a magnetic field.

Magnetic fields can be visualized as continuous lines of force or magnetic flux that travel from south to north magnetic poles. The lines' density reveals the magnetic field's strength. One or more of a magnet's poles are

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according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is?

Answers

According to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs

To identify individual conductors in a telecommunications twisted pair cable the 25-pair color code is used. These colours are marked on the conductor's insulation. The primary colours are white, red, black, yellow and violet. The secondary colours are blue, orange, green, brown and slate.

The primary colours are called as tip which is positive and the secondary colours are called as ring which is negative. In the pair only one colour from each group should be used. So the possible combinations are 25 pairs.

Therefore, according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs

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