Answer:
Density, d = 5.37 g/cm³
Explanation:
Given that,
Diameter of coin is 19.55 mm
Thickness of the cone is 1.55 mm
Mass of the coin is 2.5 g
We need to find its density. Density is equal to mass upon volume. So,
[tex]d=\dfrac{m}{V}[/tex]
V is volume, V = A d, d is thickness
Radius = d/2 = (1.955/2) cm=0.9775 cm
Thickness, d = 1.55 mm = 0.155 cm
[tex]d=\dfrac{m}{\pi r^2 \times d}\\\\d=\dfrac{2.5}{\pi (0.9775\ cm)^2\times 0.155\ cm}\\\\d=5.37\ g/cm^3[/tex]
So, the density of the coin is 5.37 g/cm³.
A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its average velocity.
Answer:
1.43 × 10^-2 m/s
Explanation:
Given the following :
Distance covered away from it's master = D1 = 24×10^-2 m
Time taken to cover the distance = t1 = 12.6s
Then runs halfway back D2 =
D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m
Time taken =T2 = T1/3 = 12.6/3 = 4.2s
Since the kitten ran in a straight line, the it is linear :
Average speed
Linear Average Velocity:
Change in distance / change in time
(D1 - D2) / (T2 - T1)
(24 - 12)×10^-2 / (12.6 - 4.2)
(12 × 10^-2)m / 8.4s
1.4285 × 10^-2
= 1.43 × 10^-2m/s
the effect on any force depends on what two things
Answer: mass and distance
Explanation: Two major factors, mass and distance, affect the strength of gravitational force on an object. You witness the first factor in everyday life - more massive objects are heavier. The second factor, distance, is less familiar, as it takes a distance of many thousands of kilometers to significantly weaken the pull of Earth's gravity.
Answer:
The factor of a force depends on two things:
1. the amount of a force applied. The more the force applied the greater the effect.
2.the area on which the force is applied. The smaller the area the force is applied on, the greater the effect.
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Find the tension between the 4 kg and the 6 kg blocks once the system is released from rest and the 9 kg block accelerates downward.
Answer:
Tension on the string is 48 N
Explanation:
Mass of A = 6 kg
mass of B = 4 kg
If the 9 kg accelerates downwards then the equation for the 6 kg mass side of the pulley will be
6g - T = 6a ....1
where
g is acceleration due to gravity = 10 m/s^2
a is the acceleration of the body
T is the tension in the string.
For the 4 kg mass side of the string, we have
T - 4g = 4a ....2
transposing, we have
T = 4a + 4g ....3
substitute equation 3 in equation 1, we have
6g - (4a + 4g) = 6a
6g - 4a - 4g = 6a
6g - 4g = 6a + 4a
2g = 10a
but g = 10 m/s^
2 x 10 = 10a
20 = 10a
acceleration a = 20/10 = 2 m/s^2
substitute value of a in equation 1
6g - T = 6a
6(10) - T = 6(2)
60 -T = 12
60 - 12 = T
T = 48 N
A cannonball falls at a rate of about 10 m/s2 due to gravity. It has a mass of 200 kg. What is the total force of the
cannonball?
[tex]\star[/tex][tex]\blue\star[/tex]
[tex]\blue\star[/tex]Givenmass = 200kgacceleration = 10m\s^2Star coding
[tex]\blue\star[/tex]As we know that force = mass × accelerationF = m×aF = 200 ×10F = 2000N[tex]\blue\star[/tex]so mate here is ur ans force is equal to 2000N.Hope it helps
If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed
Answer:
speed=d/t.
s=4/5=0.8m/s.
A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed
Answer:
6779.7m/s
Explanation:
Using
GMm/(Re +h)² = mv²/ (Re+h)
So making v subject we have
V= √GM/Re+h
So
V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3
V= 6779.7m/s
Note h = height of satellite
Re= radius of the earth
M = mass of the earth
What is the toy's total energy at any point of its motion? Express your answer with the appropriate units.]
The complete question is as follows:
A 0.150-kg toy is undergoing SHM on the end of a horizontal spring with force constant k = 300 N/m. When the toy is 0.0120 m from its equilibrium position, it is observed to have a speed of 0.400 m/s.
Answer:
The correct answer is 0.034 J.
Explanation:
Given :
mass of the toy is m = 0.15 kg.
The force constant of restoring force k = 300 Nm⁻¹
When the position of the toy from the equilibrium is x = 0.012m, then the
speed of the toy vx = 0.4m s
The total mechanical energy in SHM is given by
E= 1/2 (mv²+ kx²) = 1/2 kA²
(here, m = mass of the object, vx = velocity, k = force constant
of restoring force, and A = amplitude of SHM.)
Hence by substituting the numerical values in equation 1, we get
[tex]E= \frac{1}{2} (0.15* 0.4) + \frac{1}{2} (300* 0.012)[/tex]
= 0.034 J
Thus, the correct answer is 0.034 J.
Which of the following does NOT cause acceleration?
A change in the magnitude of the velocity
A change in the direction of the velocity
Constant speed
Increasing speed
Decreasing spped
Answer:
Constant speed
Explanation:
Acceleration is a change of magnitude and (or) direction of velocity, it will cause increase or decrease, or changing of the direction of the velocity.
An electron moving parallel to the x axis has an initial speed of 4.10 106 m/s at the origin. Its speed is reduced to 1.76 105 m/s at the point x = 2.00 cm.
Required:
a. Calculate the electric potential difference between the origin and that point.
b. Which point is at the higher potential?
Answer:
a
[tex]V = -47.65 N/C[/tex]
b
At the origin
Explanation:
From the question we are told that
The initial speed is [tex]v_1 = 4.10 *10^{6} \ m/s[/tex]
The speed at (x = 2.00 cm) is [tex]v_f = 1.76 *10^{5} \ m/s[/tex]
Generally the electric potential difference is mathematically represented as
[tex]V = \frac{W}{q}[/tex]
Here W is the work-done which is mathematically represented as
[tex]W = K_f - K_i[/tex]
Here [tex]K_f[/tex] is the kinetic energy at x = 2.00 cm mathematically expressed as
[tex]K_f = \frac{1}{2} * m* v^2_f[/tex]
and
[tex]K_i[/tex] is the kinetic energy at origin mathematically expressed as
[tex]K_f = \frac{1}{2} * m* v^2_i[/tex]
So
[tex]V = \frac{1}{q} [ \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2][/tex]
[tex]V = \frac{m}{2q} [v_f^2 - v_i^2][/tex]
Here m is the mass of electron with value [tex]m = 9.1*10^{-31} \ kg[/tex]
q is the charge on the electron with value [tex]q = 1.60*10^{-19} \ C[/tex]
So
[tex]V = \frac{(9.1 *10^{-31})}{2(1.60*10^{-19})} [(1.76*10^{5})^2 - (4.10*10^{6})^2][/tex]
[tex]V = -47.65 N/C[/tex]
So given that the difference is negative then potential is higher at the origin
If the steam in the engine is able to raise a 30 kg piston to a height of 0.68 m, how much work has been done by the steam?
Answer:
199.92joules
Explanation:
workdone = Mgh
mass x height x acceleration due to gravity
What is the momentum of a tiger that has a mass of 81 kg and runs with a velocity of 5.4 m/s to the east
Given :
Mass of tiger , m = 81 kg .
Velocity of tiger , v = 5.4 m/s .
To Find :
The momentum of tiger .
Solution :
We know , momentum of a body is given by the product of its mass and velocity .
[tex]P=m\times v[/tex]
Now , putting value of m and v in above equation , we get :
[tex]P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s[/tex]
Therefore , the momentum of tiger is 437.4 kg m/s .
Hence , this is the required solution .
Answer:
437.4
Explanation: did the math
A variable is defined as anything that
Acceleration of 1.5 ms expressed in km /hr2?
a net external force of 100.0 N acts on an object of mass 20.0 kg whose initial speed is 10.0 m/s. The force acts in the opposite direction from the objects motion, and it acts for 1.00 s. what is the objects final speed in m/s
Explanation:
We know that :
[tex]F = m\frac{(v - u)}{t} [/tex]
[tex]100 = 20 \frac{(v - 10)}{1} [/tex]
[tex]v(final \: velocity) = 15 \: m \: sec^{ - 1} [/tex]
As the frequency of the ac voltage across an inductor approaches zero, the inductive reactance of that coil Group of answer choices
Answer:
The inductive reactance also approaches zero
Explanation:
This is because from the relation
XL = 2πfL
Meaning frequency f and inductive reactance XL are directly proportional so as one approaches zero so does the other
which component of health related fitness is developed by performing a wall sit
Answer:
it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle
define polarization in reference in the simple cell
Answer:polarization pertains to the act or process of producing a positive electrical charge and a negative electrical charge such that between a nerve cell internal electrical charge..................
Explanation:
A toy police car moves across the room in 10 seconds. The distance the car traveled is
450 centimeters. At what speed did the car travel?
Answer:
45cm/s
Explanation:
If the distance traveled is 450 centimeters we can assume the speed is 45cm/s by taking the distance and dividing by the time, in this case that is 450 and 10
so our answer would be 45cm/s
Robert pushes the box to the left at constant speed. In doing so, Robert does ______ work on the box. A. positive B. negative C. zero
Answer:
He does postive work
Explanation:
Because W= F xS sinစ
So since work is done such that Force and distance have the Sam direction
Thus စ=0
Then work is positive in value
X-rays with wavelength of 2.0 nm scatter from a NaCL crystal with plane spacing of 0.281 nm. Find the scattering angle for the second order maxima.
Explanation:
Wavelength of x-rays = 2 nm
Plane spacing, d = 0.281 nm
It is assumed to find the scattering angle for second order maxima.
For 2nd order, Bragg's law is given by :
[tex]2dsin\theta =n\lambda[/tex]
For second order, n = 2
[tex]sin\theta =\frac{n\lambda}{2d} \\Sin\theta =\frac{2\times2}{2\times0.281} \\\theta =\arcsin (7.14)[/tex]
Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.
what magnetic field strength will allow the electron to pass between the plates without being deflected
Complete Question
An electron travels with speed 2.0 X 10^7 m/s between two parallel charged plates. The plates are separated by 2.0 cm and are charged by a 400V battery. What magnetic field strength and direction will allow the electron to pass between the plates without being deflected.?
Answer:
The value [tex]B = 0.001 \ T[/tex]
Explanation:
From the question we are told that
The speed of the electron is [tex]v = 2.0 *10^{7} \ m/s[/tex]
The voltage is [tex]V = 400 \ V[/tex]
The distance of separation is [tex]d= 2.0 \ cm = 0.02 \ m[/tex]
Generally the electric field is mathematically represented as
[tex]E = \frac{V}{d }[/tex]
=> [tex]E = \frac{400}{0.02 }[/tex]
=> [tex]E = 20000 V/m[/tex]
Generally for the electron to pass without deflection then
[tex]F_B = F_E[/tex]
Where [tex]F_B[/tex] is the maximum magnetic force acting on the electron which is mathematically represented as
[tex]F_B = evBsin (\theta )[/tex]
Since we are considering maximum magnetic field then [tex]\theta = 90^o[/tex]
=> [tex]F_B = evB[/tex]
And
[tex]F_E[/tex] is the electric force on the electron which is mathematically represented as
[tex]F_E = e * E[/tex]
Here e is the charge on the electron with the value [tex]e = 1.60 *10^{-19} \ C[/tex]
=> [tex]F_E = 1.60*10^{-19} * 20000[/tex]
=> [tex]F_E = 3.2*10^{-15} \ N[/tex]
So
[tex]3.2*10^{-15} = q* v B[/tex]
=> [tex]B = \frac{3.2*10^{-15}}{ 2.0*10^7 * 1.6*10^{-19}}[/tex]
=> [tex]B = 0.001 \ T[/tex]
It takes Serina 4.44 hours to drive to school. Her route is 15 km long. What is Serina’s average speed on her drive to school?
Answer: 3.38 km per hour
Explanation:
Tim can type 2,000 words at a speed of 50 words per min.
Bob's typing speed is 80 words per min. How much less time
did Bob take than Tim to type 2000 words?
min
h
Answer: the awnser to this question is 15
Explanation:
First you will divide the typing speed and the total number of words by the speed 2000 ÷ 50
Then divide bobs typing speed by 2000 equation 2000÷80 once you get the total both you will subtract the 2 totals together and get 15 as your awnser.
Hoped this helped!
Find the value of x in the triangle shown below.
9
C
3
A car traveling at 7 m/s accelerates at a rate of -0.8 m/s for an interval of 2 seconds.
Find the final velocity.
The nosition of a ninewood derhucar a ohraniodaturi
Answer:
6.2m/s
Explanation:
v=u+at
v=7+(-0.8/2)(2)
v=7-0.8
v=6.2m/s
What operation do you apply to the position function of a particle to compute the particles velocity
Answer:
the derivative with respect to time
Explanation:
This is an exercise in kinematics, where the velocity is defined as a function of the position of a body of the form
v = dx/dt
where v is the velocity of the body, x is the position that we assume is a continuous and differentiable function.
The function written in the equation is the derivative with respect to time
You want to create an electric field vector E = < 0, 5 104, 0> N/C at location < 0, 0, 0>. Where would you place a proton to produce this field at the origin?
Answer:
1.696 × 10^(-7) m on the y axis.
Explanation:
We are given the electric field as;
E = < 0, 5 × 10⁴, 0> N/C
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
E = 5 × 10⁴ N/C in the y direction.
Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
The proton to produce this field at the origin should be put on [tex]1.696 \times 10^{(-7)} [/tex]m on the y axis.
The calculation is as follows:We are given the electric field as;
[tex]E = < 0, 5 \times 10^{4}, 0> N/C[/tex]
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
[tex]E = 5 \times 10^{4} N/C[/tex] in the y direction.
The Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Now Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
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When a circuit is arranged in parallel
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
B. There is only one path the electrons can take through the circuit, and they must pass through all circuit components
Answer:
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
Explanation:
Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).
when would a swimmer have the most potential energy due to her position
Answer: A
Explanation:
A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
What is potential energy?The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.
The potential energy is found as;
[tex]\rm PE = mgh[/tex]
The potential energy is mainly depending upon the height of the object.
When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
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The harder a gas pedal in a car is pressed the faster the car's velocity increases. Which phrase best describes the relationship between how hard the gas pedal is pressed and the acceleration of the car?
A. There is both a negative correlation and causation
B. There is a positive correlation but no causation.
C. There is a negative correlation but no causation.
D. There is both a positive correlation and causation.
Answer:
D
There is both a positive correlation and causation
The relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
From the given statement the relationship between the cause (pedal) and the effect (velocity) can be described as direct relationship.
In direct proportionality, the outcome of one variable produces similar effect to the other variable.The harder the gas pedal in a car is pressed, the velocity increases. This shows that as the force applied to the gas pedal increases (the cause of the action), the greater the velocity of the car (the effect of the cause).
Thus, we can conclude that the relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
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