A sample of flammable liquid is placed into an enclosed cylinder which is then fitted with a movable piston. Initially the cylinder maintains a volume of 1.7 L. The sample is ignited producing gas and releasing 439.6 J of energy. To what volume will the cylinder expand to if it must expand against a pressure of 738.52 mmHg. Assume all the energy released is converted to work used to push the piston? Answer to 1 decimal space.

Answers

Answer 1

Cylinder will expand to 6.08 Lit by assuming that all the energy released is converted to work used to push the piston.

Concept of work :If we  apply force on an object and if the object moves and changes it's position, then product of the force and the displacement of an object in the direction of applied force is called work.

Given,

Pressure= P= 738.52 mm Hg = 0.97 atm. (∵ 760 mm Hg = 1 atm)

Initial volume =V1= 1.7 L

Work done = W = 439.6 J

As we need our answer in litters ..

let's convert the work done into suitable units

∴work done = W = 4.26 L-atm (∵ 1 J = 101.3 L-atm)

As given all the energy is assumed to converted into work so we need not to worry About heat loss or entropy.

work done = pressure * difference in volume

W = PΔV

ΔV = 4.26÷ 0.97

∴ΔV = 4.38 LIt

There for, the volume expanded = 4.38 Lit

So, total volume = 4.38+ 1.7 = 6.08 Lit.

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Related Questions

Calculate the pOH for the following:
1. [H+] = 1 x 10-12 M


2. [OH-] = 1 x 10-6 M


3. [H+] = 1 x 10-1 M


4. [H+] = 1 x 10-4 M


5. [OH-] = 1 x 10-7 M

Answers

The  pOH refers to the negative logarithm of the hydroxide concentration.

What is the pOH?

The term pOH refers to the negative logarithm of the hydroxide concentration. Now we know that there is a relation that states that;

[H+]  [OH-]  = 1 * 10^-14

We shall now apply this relation in each case as follows;

[OH-]  =  1 * 10^-14/1 x 10-12

[OH-]  = 1 * 10^-2

pOH = 2

2. pOH = -log( 1 x 10-6 M) = 6

3.  [OH-]  =  1 * 10^-14/ 1 x 10-1

[OH-]  =  1 * 10^-13

pOH = 13

4.  [OH-]  =  1 * 10^-14/  1 x 10-4

[OH-]  =   1 * 10^-10

pOH = 10

5.  pOH = -log(  1 x 10-7) = 7

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Calculate the percent yield of a reaction that produced 0.350 mol HCI if the theoretical yield was 15.36 g

Answers

The percent yield of the reaction that produced 0.350 mol HCI is 83.17%

How to determine the actual yield (in grams)Mole of HCl = 0.350 moleMolar mass of HCl = 36.5 g/molActual yield =?

Actual yield = 0.35 × 36.5

Actual yield = 12.775 g

How to determine the percentage yield Actual yield of HCl = 12.775 gTheoretical yield of HCl = 15.36 gPercentage yield =?

Percentage yield = (Actual / Theoretical) × 100

Percentage yield = (12.775 / 15.36) ×100

Percentage yield = 83.17%

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Gelatin is a solid that can strengthen protein networks. How would yogurt that contains gelatin be different from yogurt that does not contain gelatin? Explain your answer.

Answers

Ice cream that contains gelatin will have a thicker consistency than on that does not contain gelatin.

What is gelatin?

Gelatin is a proteoglycan which is made from boiling tendons.

Gelatin is used as a  thickening agent.

Therefore Ice cream that contains gelatin will have a thicker consistency than on that does not contain gelatin.

In conclusion, gelatin is used to thicken foods.

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A 0.266-g sample of NaC1 (molar mass = 58.44 g/mol) is dissolved in enough water to make 5.20 mL of
solution. Calculate the molarity of the resulting solution.
O 0.875 M
O 4.55 x 10-3 M
O 0.987 M
O 1.14 M
O 0.731 M

Answers

0.266g / 58.44g/mol= 0.00455mol
M= moles / volume (L)
0.00455mol / .0052L
M= 0.875

How many molecules of zinc oxide are there in a 2 kg sample?

Answers

There are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample. Details about number of molecules can be found below.

How to calculate number of molecules?

The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

According to this question, there are 2000g of ZnO in a sample. Zinc oxide has a molar mass of 81.38 g/mol.

no of moles = 2000g ÷ 81.38g/mol

no of moles = 24.57mol

number of molecules = 24.57 × 6.02 × 10²³

number of molecules = 147.95 × 10²³

Therefore, there are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample.

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In this activity, you are tasked with designing an airbag for a company that creates airbags for automobiles. You must design the driver’s front airbag for a specific car model so it will protect the driver as effectively as possible. For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.

Answers

The airbag is designed to produce the volume of nitrogen gas required to fill up the airbag.

What is the function of an airbag?

An airbag is a bag which is designed to self-inflate and serve as a cushion for the head and neck of a driver to prevent injuries when an impact occurs head-on on the car.

The gas that inflates the airbag is nitrogen which is produced from sodium azide according to equation below:

2NaN₃ → 2Na + 3N₂

In conclusion, the design of the airbag is such that the correct amount of sodium azide is present to produce the volume of nitrogen required to fill up the airbag.

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What is the theoretical yield of bromobenzene in this reaction when 24.8 g of benzene reacts with 52.3 g of bromine?

Answers

Answer:

49.8 g C₆H₅Br

Explanation:

The theoretical yield is the maximum calculated amount of product that can be made from a reaction. To find the theoretical yield, you need to (1) determine the chemical reaction which is taking place, then (2) calculate the molar masses of the relevant reactants and product, then (3) convert grams of each reactant to grams of bromobenzene (using molar masses and mole-to-mole ratio from reaction coefficients), and then (4) determine the limiting reagent and the theoretical yield.

(Step 1)

Bromine = Br₂

Benzene = C₆H₆

Bromobenzene = C₆H₅Br

The balanced equation:

Br₂ + 2 C₆H₆ ----> 2 C₆H₅Br + H₂

(Step 2)

Molar Mass (Br₂): 2(79.904 g/mol)

Molar Mass (Br₂): 159.808 g/mol

Molar Mass (C₆H₆): 6(12.011 g/mol) + 6(1.008 g/mol)

Molar Mass (C₆H₆): 78.114 g/mol

Molar Mass (C₆H₅Br): 6(12.011 g/mol) + 5(1.008 g/mol) + 79.904 g/mol

Molar Mass (C₆H₅Br): 157.01 g/mol

(Step 3)

52.3 g Br₂           1 mole             2 moles C₆H₅Br         157.01 g
----------------- x  ------------------  x  -------------------------  x  ---------------  =
                          159.808 g              1 mole Br₂               1 mole

=  103 g C₆H₅Br

24.8 g C₆H₆         1 mole            2 moles C₆H₅Br          157.01 g
-------------------  x  ---------------  x  --------------------------  x  ---------------  =
                             78.114 g           2 moles C₆H₆             1 mole

=  49.8 g C₆H₅Br

(Step 4)

Because C₆H₆ produces a smaller amount of product than Br₂, it must be the limiting reagent. This means that it will run out before all of the Br₂ is used up. Therefore, the actual theoretical yield of C₆H₅Br is 49.8 grams.

I need help with my work

Answers

By the mean value theorem, the function y = sin x² on the interval [0, π/4] has this guaranteed number: x ≈ 0.460.

How to find a number that guarantees the mean value theorem

According to the mean value theorem, a function that is differentiable at an interval [a, b] has a number c within the interval such that:

f'(c) = [f(b) - f(a)]/(b - a)     (1)

The first derivative of the function is f'(x) = 2 · x · cos x² and by the mean value theorem we know that:

2 · c · cos c² = [sin (π/4)²- sin 0²]/(π/4 - 0)

2 · c · cos c² = [- √2 / 2]/(π /4)

2 · c · cos c² ≈ 0.900

This equation cannot be solved analytically. By the resource of a graphing tool we found the following solution within the interval: c ≈ 0.460.

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5. Which of the following personal protective equipment is selected based on a
chemical's IDLH value?
O A. Respirator
O B. Eyewear
O C. Body suit
O D. Gloves

Answers

Answer is A. Respirator
Reason

IDLH atmospheres require a full-face piece, pressure demand self-contained breathing apparatus (SCBA) or supplied-air respirator (SAR) with self-contained auxiliary air supply.

Respirator - It is chosen based on a chemical's IDLH value, ensuring protection against immediate life-threatening respiratory hazards.

Option (A) is correct.

The correct personal protective equipment (PPE) selected based on a chemical's IDLH (Immediately Dangerous to Life or Health) value is a respirator. IDLH value is a critical safety parameter that represents the maximum concentration of a chemical in the air above which an individual could suffer immediate or long-term health effects, such as life-threatening respiratory issues.

When a chemical's IDLH value is exceeded, it becomes essential to use appropriate respiratory protection. A respirator helps filter and remove harmful contaminants from the air, preventing inhalation and protecting the wearer's respiratory system.

Different types of respirators are available, ranging from simple dust masks to full-face air-purifying respirators or supplied-air respirators, based on the specific hazard and IDLH value of the chemical involved.

Eyewear, body suits, and gloves are essential PPE, but they are not specifically selected based on the chemical's IDLH value.

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will mark brilliant pls help question is above​

Answers

Answer:

a.) The garden plants provide energy to all the other organisms. While not every organism consumes garden plants directly, every organism's food lineage can be traced to garden plants. For instance, while ground beetles do not directly consume garden plants, they do eat snails, and snails eat garden plants.

b.) The slug population might increase is the aphid population decreased because there would be less competition for food resources. Both populations consume garden plants, and there is only a finite number of garden plants. Therefore, there is a limit that each population can consume. If there were less aphids eating the garden plants, there would be more left for the slugs. Less starving slugs would lead to greater reproduction and thus a higher slug population.

How many moles of chlorine gas at 120. °C
and 33.3 atm would occupy a vessel of 11.5
L?

Answers

Answer:

11.9 moles Cl₂

Explanation:

To find the number of moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 33.3 atm                         R = 0.0821 L*atm/mol*K

V = 11.5 L                              T = 120. °C + 273.15 = 393.15 K

n = ? moles

PV = nRT

(33.3 atm)(11.5 L) = n(0.0821 L*atm/mol*K)(393.15 K)

382.95 = n(0.0821 L*atm/mol*K)(393.15 K)

382.95 = (32.2776)n

11.9 = n

A soil test recommends applying 193 lbs N per acre. Using a 36-6-18 fertilizer, how much fertilizer is needed to meet the recommendation? Round your answer to nearest whole number.

Answers

The mass of 36-6-18 fertilizer fertilizer required is 536 lb.

What mass of nitrogen fertilizer is required for the acre of land?

The mass of nitrogen fertilizer required for the acre of land is determined as follows:

Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.

Mass of Nitrogen required per acre = 193 lbs

Mass of fertilizer required = 193 * 100/36

Mass of fertilizer required  = 536 lb of fertilizer.

In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.

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How is the kinetic energy of the particles of a substance affected during a phase change?

O Kinetic energy increases during exothermic changes and decreases during endothermic changes.

O Kinetic energy decreases during exothermic changes and increases during endothermic changes.

O Kinetic energy does not change, but the potential energy does.

O Kinetic energy changes in the opposite way that the potential energy changes.

Answers

Answer:

O Kinetic energy does not change, but the potential energy does

You need to calculate the enthalpy change (AH) of the reaction A + 2B → C.
How can the enthalpies given for the reaction steps below be combined to
give the overall change in enthalpy?
D+B
D+3B
A. AH = AH2-A H₁
B. AH=2AH₁+AH²₂
OC. AH AH ₁ +AH²₂
D. AH = A H₁-AH₂
A
C
A
AH°,
A Hº

Answers

The enthalpy change of the reaction:  A + 2B → C is determined as follows: ΔH = ΔH₁ +  ΔH₂; option C

What is enthalpy change?

Enthalpy change refers to the change in heat content as reactant molecules combine to form products.

The enthalpy change of a multistep reaction is calculated from by summing the enthalpy changes of the intermediate steps that leads to the overall reaction.

Thus, the enthalpy change of the reaction:  A + 2B → C is determined as follows:

ΔH = ΔH₁ +  ΔH₂

In conclusion, the enthalpy change of the reaction is determined from the summation of the enthalpy changes that occur in the intermediate steps.

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If 48.0 g of iodine are reacted with an excess of phosphorus according to the following chemical equation:

2 P(s) + 3 I2(s) → 2 PI3(s)

Calculate the theoretical yield of PI3.

If the actual yield of PI3 is 50.0 g, what is the percentage yield?

Answers

Answer:

Theoretical Yield  =  51.9 grams PI₃

Percentage Yield  =  96.3% PI₃

Explanation:

To find the theoretical and percent yield of PI₃, you need to (1) convert grams I₂ to moles I₂ (via molar mass), then (2) convert moles I₂ to moles PI₃ (via mole-to-mole ratio from reaction coefficients), then (3) convert moles PI₃ to grams PI₃ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answers should have 3 sig figs to match the sig figs of the given values.

Molar Mass (I₂): 2(126.90 g/mol)

Molar Mass (I₂): 253.8 g/mol

Molar Mass (PI₃): 30.974 g/mol + 3(126.90 g/mol)

Molar Mass (PI): 411.674 g/mol

2 P(s) + 3 I₂(s) -----> 2 PI₃(s)

48.0 g I₂            1 mole              2 moles PI₃            411.674 g
---------------  x  -----------------  x  ----------------------  x  ------------------  =  
                         253.8 g               3 moles I₂              1 mole

=  51.9 g PI

                                           Actual Yield
Percentage Yield  =  ---------------------------------  x  100%
                                      Theoretical Yield

                                     50.0 g PI₃
Percentage Yield  =  --------------------  x  100%
                                     51.9 g PI₃

Percentage Yield  =  96.3% PI


perform the following mathematical operation, and report the answer to the correct number of significant figures. 0.34 x 0.568=?

How do I know how many significant figures to round to?

Answers

The correct answer to the problem is 0.193 which is three significant figures.

What are significant figures?

The term significant figures has to do with the figures that have a mathematical meaning. We know that the result has to correspond to the highest number of significant figures.

Hence, If we multiply 0.34 x 0.568 the result ought to be recorded as 0.193 which is three significant figures.

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liquid octane(CH3)(CH2)6CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water(H2O). If 5.18 g of carbon dioxide is produced from the reaction of 3.43 g of octane and 19.1 g of oxygen gas, calculate the percent yield of carbon dioxide. Round your answer to 3 significant figures.

Answers

The percent yield of carbon dioxide will be 49.0 %.

Percent yield

First, let's look at the equation of the reaction:

[tex]2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O[/tex]

The mole ratio of octane to oxygen is 2:25.

Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol

Mole of 19.1 g oxygen = 19.1/32 = 0.60 mol

Thus, octane is limiting.

Mole ratio of octane to carbon dioxide = 2:16.

Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol

Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams

Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %

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Calculate the mass in grams of benzophenone required to make a solution of 2.5 mmoles

Answers

Answer:

0.46 grams (C₆H₅)₂CO

Explanation:

To find the mass of benzophenone ((C₆H₅)₂CO), you need to (1) convert mmoles to moles and then (2) convert moles to grams (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 2 sig figs to match the sig figs of the given value (2.5 mmoles).

Molar Mass ((C₆H₅)₂CO): 13(12.011 g/mol) + 10(1.008 g/mol) + 15.998 g/mol

Molar Mass ((C₆H₅)₂CO): 182.221 g/mol

2.5 mmoles (C₆H₅)₂CO               1 mole                  182.221 g
-----------------------------------  x  ------------------------  x  -------------------  =
                                                1,000 mmoles            1 mole

=  0.46 grams (C₆H₅)₂CO

Identify the chirality center (sometimes called chiral atom) in each molecule. If the molecule does not contain a chirality center, select none.

Answers

The only chiral center in the molecule is carbon 4 because is attached to four different atoms or groups.

What is a chiral center?

The term chiral center refers to a carbon atom that is attached to four different atoms or groups. This kind of carbon atom is able to rotate the direction of plane polarized light.

We can see from the structure of the molecule that the only chiral center in the molecule is carbon 4 because is attached to four different atoms or groups.

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How do you separate Sand Potassium Nitrate and Champhor

Answers

Heating & Cooling: The mixture is heated to get a saturated solution and it crystallises on cooling. Now since, potassium nitrate is more soluble it gets filtered out from the hot saturated solution and recrystallised in hot water and then dried. This separates the two mixtures into crystals.

PLEASE ANSWER THIS FAST... tysm
●what will happen to the texture off egg shell if you place it in.
1. Coca cola

2. orange juice

3. grape juice

4. normal water

5. a dark coloured sugary drink like sting


Answer all these correctly please

thanks​

Answers

Answer:

4. the egg shell you place in normal water

Question 9
What pressure will be exerted by 15 g of carbon dioxide gas in a 20 L container at 0 °C?

Answers

Answer:

0.382 atm

Explanation:

In order to find the pressure, you need to know the moles of carbon dioxide (CO₂) gas. This can be found by multiplying the mass (g) by the molar mass (g/mol) of CO₂. It is important to arrange the conversion in a way that allows for the cancellation of units.

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

15 grams CO₂               1 mole
----------------------  x  ------------------------  =  0.341 moles CO₂
                                44.007 grams

To find the pressure, you need to use the Ideal Gas Law equation.

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After you convert Celsius to Kelvin, you can plug the given and calculated values into the equation and simplify to find the pressure.

P = ? atm                              R = 0.08206 atm*L/mol*K

V = 20 L                               T = 0 °C + 273.15 = 273.15 K

n = 0.341 moles

PV = nRT

P(20 L) = (0.341 moles)(0.08206 atm*L/mol*K)(273.15 K)

P(20 L) = 7.64016

P = 0.382 atm

• An alkane with the formula C5H12 undergoes chlorination to give only one product with the formula C5H11Cl. What is the structure of this alkane? •​

Answers

Answer:

When an alkane undergoes a halogenation reaction, the majority of the products will add the halogen to the most substituted and most stable carbon. In this case, this would likely be the third carbon (middle).

Key:

Leftmost molecule = C₅H₁₂

Rightmost molecule = C₅H₁₁Cl

*Not pictured = HCl (another product)

1.______ language is the ability to understand what’s said.

2. When babies handle objects, they learn that they can
make something happen. This helps them begin to
understand and _______.

3. Caregivers can encourage language development by _____
to the baby.

4.______ is the ability of an infant to understand when
an object is present even if he or she can't see it.

5. Language development and thinking ability are _______.

6. Toddlers gain self-confidence when they _______.
Caregivers should expect toddlers to _______.

7.Caregivers should help children select television programs to watch and _______ the time they spend in this activity.


8. Superhero and fantasy play should be tempered with discussing the differences between _______ and reality.

Answers

The 1 month old baby sees up to 30 cm away, following objects and people that move around him and fixing his gaze on bright and flashy objects. To say that he wants something or that something is bothering him, the baby usually expresses himself through crying.

What is baby development?

1.Clear language is the ability to understand what’s said.

2. When babies handle objects, they learn that they can

make something happen. This helps them begin to

understand and do.

3. Caregivers can encourage language development by sign

to the baby.

4.imagine is the ability of an infant to understand when

an object is present even if he or she can't see it.

5. Language development and thinking ability are indispensable.

6. Toddlers gain self-confidence when they make mistakes.

Caregivers should expect toddlers to mistakes.

7.Caregivers should help children select television programs to watch and monitor the time they spend in this activity.

8. Superhero and fantasy play should be tempered with discussing the differences between fantasy and reality.

With this information, we can conclude that If your baby does not respond to stimuli and even as the months go by, simple steps of the baby's development are not happening, such as smiling, turning around, crawling, the pediatrician will follow up and refer the competent specialist to carry out evaluation tests to investigate a possible delay. psychomotor.

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If you react 9.10g of vinyl chloride with 7.80g of oxygen, what is the theoretical yield of carbon dioxide

Answers

The theoretical yield of the CO2 produced is 4.22 g.

What is the theoretical yield of carbon dioxide?

The balanced reaction equation is;

2C2H3Cl + 5O2 ------>2CO2 + 2H2O + 2HCl

Number of moles of  vinyl chloride =  9.10g /62 g/mol = 0.15 moles

Number of moles of oxygen = 7.80g/32 g/mol = 0.24 moles

Now;

2 moles of C2H3Cl reacts with 5 moles of oxygen

0.15 moles of C2H3Cl reacts with 0.15 moles * 5 moles / 2 moles

= 0.375 moles

Hence oxygen is the limiting reactant;

5 moles of oxygen produces 2 moles of CO2

0.24 moles of oxygen produces 0.24 moles * 2 moles /5 moles

= 0.096 moles

Mass of CO2 produced = 0.096 moles * 44 g/mol

= 4.22 g

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9. Predict the full Robinson Annulation product (including all intermediates) and 10. Show the stepwise mechanism for the following reaction.

Answers

The Robinson Annulation is the name for a process that combines two key reactions you've learned previously into one longer sequence. The reaction begins with a Michael reaction, followed by an intramolecular aldol condensation to give a new six-membered ring containing an alpha, beta unsaturated ketone.10-Dec-2018

How is the rate of a reflection affected when the temperature increases

Answers

The rate of a reflection decreases when the temperature increases

This goes to say that the rate of reflection will go down more whenever there is an increase in temperature

What is reflection?

Reflection can simply be defined as the the throwing back by a body of light without absorbing it.

reflection of

In conclusion, the rate of a reflection decreases when the temperature increases

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What volume of barium chloride, BaCl2 is needed to make a 2.5 M barium
chloride solution with 0.45 mol BaCl2?

Answers

Answer:

0.18 L

Explanation:

You can find the volume using the molarity ratio:

Molarity = moles / volume (L)

You can plug the given values into the equation and simplify to find the volume.

Molarity = moles / volume                           <----- Molarity ratio

2.5 M = 0.45 moles / volume                      <----- Insert values

(2.5 M) x volume = 0.45 moles                   <----- Multiply both sides by volume

volume = 0.18 L                                            <----- Divide both sides by 2.5

When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely

Answers

When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

What is super saturation?

Super saturation occurs with a chemical solution when the concentration of a solute exceeds the concentration specified by the value equilibrium solubility.

Additional water into the soil will cause the soil to be super saturated and eventually runs off due to the steepness of the area.

Thus, when the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

Learn  more about surface run off here: https://brainly.com/question/21926984

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1. A 4.0-g sample of glass was heated from 274K to 314 K. a temperature increase of 40 K, and was
found to have absorbed 32J of energy as heat.
a. What is the specific heat of this type of glass?
b. How much energy will the same glass sample gain when it is heated from 314 K to 344 K?

Answers

Answer:

See below

Explanation:

Q = m c T      c = specific heat   T = temp change  Q = heat joules

32 = 4 c 40     c = .2 J/g-C

314 to 344 k is a change of 30 K  

Q = m c T

  = 4 * .2 * 30 = 24 Joules

Answer:

(a) 0.2 J/g°K

(b) 24 J

Explanation:

(a)

To find the specific heat capacity, you need to use the following equation:

Q = mcΔT

In this formula,

-----> Q = heat energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°K)

-----> ΔT = change in temperature (K)

You can plug the given values into the equations and simplify to find the missing value.

Q = 32 J                          c = ? J/g°K

m = 4.0 g                        ΔT = 40 K

Q = mcΔT                                              <----- Equation

32 J = (4.0 g) x c x (40 K)                     <----- Insert variables

32 J = (160) x c                                      <----- Multiply 4.0 and 40

0.2 = c                                                   <----- Divide both sides by 160

(b)

To find the energy of the same sample, you can use the same equation. This time, you know the specific heat capacity, have a different change in temperature, and are solving for energy (Q).

Q = ? J                           c = 0.2 J/g°K

m = 4.0 g                       ΔT = 344 K - 314 K = 30 K

Q = mcΔT                                         <----- Given equation

Q = (4.0 g)(0.2 J/g°K)(30 K)             <----- Insert values

Q = 24                                              <----- Multiply

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