Answer:
a) 0.73A
b) 0.23A
c) 2.76V
Explanation:
We need to first resolve the two resistors in series. The resistors in series are
12 Ω and 3 Ω AND 6 Ω and 3 Ω
For 12 Ω and 3 Ω in series, total effective resistance = 12 Ω + 3 Ω = 15 Ω
For 6 Ω and 3 Ω in series, total effective resistance = 6 Ω + 3 Ω = 9 Ω
Since the equivalent series resistors i.e 15Ω ND 9Ω are connected in parallel, the total effective resistance Rt will be expressed as;
1/Rt = 1/15+1/9
1/Rt = (3+5)/45
1/Rt = 8/45
Rt = 45/8 Ω
a) If a potential difference of 4 V is applied across it, the total current I in the circuit can be derives using the ohms law.
According to the law E = IRt
Given E = 4V, Rt = 45/8
I = E/Rt
I = 4/(45/8)
I = 4 * 8/45
I = 32/45
I = 0.73A
Hence, the current drawn from the battery is 0.73A
b) Before we can calculate the current in the 12Ω resistor, we need to calculate the current in the equivalent resistance of 15Ω(sum of 12Ω and 3Ω)
Current in the 15Ω resistor = Voltage across the 15Ω resistor/Resistance
Current in the 15Ω resistor = 4/15
Current in the 15Ω resistor = 0.27A
Since the same current flows in a series connected resistors, hence the correct in the 12ohms resistor is also 0.27A.
c) Before we can calculate the pd across the 6ohms resistor, we need to know the voltage across the effective resistance of 9ohms(6ohms+3ohms). The pd across the 9ohm resistance will be the same as the source voltage i.e 4Volts.
We will need to share this 4volts between the 6ohms and the 3ohms using ohms law.
According to the law, V = IR
For the 6ohms resistor, voltage across it will be;
V = (0.73-0.27)×6
V= 0.46×6
V = 2.76Volts.
Hence the voltage across the 6ohms resistor is 2.76V.
What is the cat's displacement t=0.5s to 1.5s,
Answer:
3.75m
Explanation:
area under graph
5+2.5=7.5
7.5/2=3.75
3.75x0.5=1.875
1.875x2=3.75m
why do objects in equilibrium have a net force of 0?
Answer:
Because there is no net force acting o an object in equilibrium.
Explanation:
When object is in equilibrium (either at rest or moving with constant velocity, the net force acting o it is zero.A vector can only have zero magnitude fall of its components are zero this means that all forces acting on the object are balanced.
Convert 60 kg to mg using the method of dimensional analysis
600,000
PLEASE MARK AS BRAINLIEST ANSWER
given that the amplitude of the scattered light is (1) directly proportional to that of incident light (2) directly propotional to the volume of the scattering dust particles (3)inversely proportional to its distance from the scattering particles and (4) dependent upon the wavelength of the light. show that the intensity of scattered light varies as 1/wavelength^4
Answer:
The correct answers are 2, 4
Explanation:
The dispersion of light occurs due to the interaction of electromagnetic radiation with matter, let's analyze the phenomenon, when a ray of light reaches a particle is absorbed and subsequently re-emitted in all directions, for radiation of lower wavelength (higher frequency ) the highest absorptions and therefore the missionary also the highest; An example of this is the blue light from the atmosphere, which is the absorption of blue light and its subsequent re-emission
Based on this explanation, the dispersion in gas particles or molecules is proportional to the frequency of the light (inversely proportional to the wavelength) and is also proportional to the number of dispersing particles in the air, that is, to the total volume of the particles. dispersers.
The correct answers are 2 and 4
What evidence supported the inflation theory? (the big bang theory one pls)
Answer:
The comic microwave background
Explanation:
The cosmic microwave background is said to be part of the remnant of the Big Bang that happened which resulted in the formation of the universe. This is because the universe was thought to be a very hot place which resulted in the expansion of it.
The heat was said to have resulted in the cooling of gases present and the remnant of the heat is what formed the radiation called the cosmic wave background.
A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 76.8 m/s2 for 1.99 seconds, at which point its fuel abruptly runs out. Air resistance has no effect on its flight. What maximum altitude (above the ground) will the rocket reach?
Answer:
Explanation:
Take note that when the fuel of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be moving up until all the forces of gravity would dominate and change the direction of the rocket. Hence, there will be a need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction.
Given:
a = 76.8 m/s^2
t = 1.99 s
Solution:
d = vi (t) + 0.5 (a) (t^2)
d = (0) (1.99) + 0.5 (76.8) (1.99)^2
d = 0+38.4×3.9601
d = 152.068m
vf = vi + at
vf = 0 + 76.8 (1.99)
vf = 152.83 m/s (velocity when the fuel is consumed completely)
Then, we calculate the time it takes until it reaches the maximum height.
vf = vi + at
0 = 152.83+(-9.8) (t)
0 = 152.83 + (-9.8) (t)
-152.83 = -9.8t
t = 152.83/9.8 s
t = 15.59s
Then, the second distance
d= vi (t) + 0.5 (a) (t^2)
d = 152.83 (15.59) + 0.5 (-9.8) (15.59^2)
d = 2382.6197- 1190.93
d = 1191.68m
Then, we determine the maximum altitude:
d1 + d2 = 152.068 m + 1191.68m = 1343.748m
Monochromatic light of wavelength 649 nm is incident on a narrow slit. On a screen 2.25 m away, the distance between the second diffraction minimum and the central maximum is 1.99 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.
Answer:
a)0.51°
b)1.47×10^-4m
Explanation:
a)for a single slit experiment, the minima that has an angle of θ towards the centre needs to satisfy the expression below.
bsin(θ)= mλ.........................(*)
Where b= width of the slit
The distance on the screen from Central angle can be expressed as
Sin(θ)= y/d............. (**)
d and y is the horizontal distance between slit and screen
If we input eqn(**) into equation (*) we have
y= mλd/b................(z)
In order to find angle (θ) we have
(θ)= sin-(1.99×10^-2)/2.25
= 0.51°
Therefore, angle of diffraction θ of the second minimum is 0.51°
b)to find the width of the sloth using eqn(z) by substitute the values, we have
b= (2)(649×10^-9)(2.25)/1.99×10^-2
b= 1.47×10^-4m
Therefore, the width of the slit is 1.47×10^-4m
What is the goal of the scientific method
Answer:
Regardless of how the steps are documented, the goal of scientific method is to gather data that will validate or invalidate a cause and effect relationship.
Hope this helped!!!
A girl walks 55 m downhill in 3.2 s. What is her average velocity?
Answer:
V = 17.2
Explanation:
Speed = distance(m) / time(s)
= 55m / 3.2s
=17.2 m/s
If, on a particular day, atmospheric pressure is 730 mm
of mercury, what is this
a) in pascals
b) in atmospheres
c) in millibars?
Answer:
b) in atmostphere
Explanation:
I made lots of research and it should be b.
a. On a particular day, atmospheric pressure is 730 mm of mercury In pascals 97392.2896252, b. On a particular day, atmospheric pressure is 730 mm of mercury in atmospheres 0.960526316 atm, c. on a particular day, atmospheric pressure is 730 mm of mercury in millibars 973.70355547 mb.
a) To convert atmospheric pressure from mm of mercury to pascals, we can use the conversion factor: 1 mm Hg = 133.322387415 pascals.
Pressure in pascals = 730 mm Hg * 133.322387415 = 97392.2896252 pascals.
b) To convert atmospheric pressure from mm of mercury to atmospheres, we can use the conversion factor: 1 atm = 760 mm Hg.
Pressure in atmospheres = 730 mm Hg / 760 = 0.960526316 atm.
c) Atmospheric pressure is often expressed in millibars (mb), where 1 atmosphere is approximately equal to 1013.25 millibars.
Pressure in millibars = 0.960526316 atm * 1013.25 mb/atm = 973.70355547 mb.
Atmospheric pressure is the force exerted by the weight of air molecules in the Earth's atmosphere. It can be measured in various units, including millimeters of mercury, pascals, atmospheres, and millibars.
Converting between these units involves using conversion factors based on established relationships between them.
In this case, the provided pressure of 730 mm Hg was converted to pascals, atmospheres, and millibars using the appropriate conversion factors.
Conversions help express pressure measurements in units that are more suitable for different contexts or calculations.
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3. What two characteristics do you need to include when defining a force? (a) speed and direction (b) strength and direction (c) acceleration and time (d) distance and direction
4. When a bug traveling west hits the windshield of a car that is traveling east, what can be said about the collision? (a) The bug feels a stronger force than the car. (b) The car and the bug feel the same size force. (c) The car accelerates more than the bug. (d) The bug does not accelerate due to the force.
5. What is the reaction force to the force on a baseball from a bat? (a) The force of the bat on the ball (b) The force of the ball on the ground (c) The force of the bat on the players hand (d) The force of gravity on the
Answer:
2
yes
Explanation:
been submitted to the Theme 20 participants will be there was a lot of fun and I will be there at Home
Help uhh i need to know this answer
Answer:
Explanation:
2. 330.63 ft because v*t=d and 3.09*107=330.63
3. 4.2 because 10/2.4=4.1666
4. 130 miles because 2 hours times 65mph= 130
5. 62.3 seconds because 480000/7700=62.33766233
8. 60 meters, because 0.5 *120 (because 2 minutes converted to seconds is 120) is equal to 60.
The mass of an object is 4kg and it has a density of 5gcm^-3. what is the volume
Answer:
density = mass/ volume
5=4000/ volume
volume=4000/5
volume=800 cm^-3
Explain the structure of a clinical thermometer
Explanation:
a clinical thermometer is a thermometer used to measure human body temperature. mostade in the 20th century are mercury-in-glass thermometer. they ate accurate and sensitive having a narrow place where the mercury level rises very fast. a kink in the tube stops the mercury level from falling on its own.
hope it helps you
briefly explain what EMF of a cell cell is
Answer:
The emf of a cell is the sum of the electric potential differences (PDs) produced by a separation of charges (electrons or ions) that can occur at each phase boundary (or interface) in the cell. The magnitude of each PD depends on the chemical nature of the two contacting phases.
Explanation:
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The energy change in an endothermic reaction is: A. Internal B. External C. Negative D. Positive
Answer:
Positive
Explanation:
In an endothermic reaction, the products are at a higher energy than the reactants. This means that the enthalpy change of the reaction (∆H) is positive
what is the scientific notation for 1,500,000
Answer:
[tex]1.5 * 10^6[/tex]
Explanation:
Given
Digit: 1,500,000
Required
Represent using scientific notation
We start by expressing the given digit as a product of 1.5 and a multiple of 10
[tex]Digit = 1.5 * 1,000,000[/tex]
1,000,000 can be represented as 10⁶
So; the digit becomes
[tex]Digit = 1.5 * 10^6[/tex]
Hence, the scientific notation of 1,500,000 is 1.5 * 10⁶
A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit, the separation distance between adjacent bright fringes on the screen is 0.0290 mm. When instead, 500 nm light is used, what is the separation distance (in mm) between adjacent bright fringes
Answer:
β 2 = 0.02575 mm
Explanation:
given data
wavelength = 563 nm
separation distance between adjacent bright fringes = 0.0290 mm
wavelength = 500 nm
solution
we get here separation distance between adjacent bright fringes that is express as
β = [tex]\frac{\lambda D }{d}[/tex] ..................................1
here D is distance from plane of slit to screen
and d is slit sepation that is constant
so
[tex]\frac{\beta 1}{\beta 2} = \frac{\lambda 1}{\lambda 2}[/tex]
β 2 = [tex]\frac{500}{563} \times 0.0290[/tex]
β 2 = 0.02575 mm
When light travels from air into water, Group of answer choices its wavelength changes, but its velocity and frequency does not change its velocity remains constant, but its frequency and wavelength changes its velocity, wavelength and frequency all change its velocity and wavelength changes, but its frequency does not change
Answer:
its velocity, wavelength and frequency all change
Explanation:
Whenever a wave crosses the boundary between two media of different densities, its velocity, frequency and wavelength changes. This appears as a bending of the wave as it crosses the boundary from one medium to another.
Refraction is a fundamental property of waves. Hence when light is travelling from air into water, it wavelength, speed and frequency all changes at the interface between the two media.
A butterfly is flying around and its velocity(v) as a function of time(t) is given in the graph below where rightwards is the positive velocity direction. What is the butterfly's displacement x from t=2 to 4s? Answer with two significant digits.
Answer: 19 meters.
Explanation:
We want to find the total displacement between t = 2s and t = 4s.
To do it, we can integrate our function, first write our velocity equation.
for t ≤ 3s, we have a linear equation, let's write it:
A linear relationship can be written as:
y = a*t + b
where a is the slope and b is the y-axis intercept.
For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:
a = (y2 - y1)/(x2 - x1).
Now we can see that our line passes through the points (1, 0) and (0, -2)
then the slope is:
a = (0 -(-2)/(1 - 0) = 2/1 = 2
and knowing that when t = 0s, v(0s) = -2m/s, then our equation is:
v(t) = (2m/s^2)*t - 2m/s for t ≤ 3s
now, for t ≥3s the equation is constant, v(t) = 4m/s.
then we have
v(t) = (2m/s^2)*t - 2m/s -------if t ≤ 3s
v(t) = 4m/s ----- if t ≥ 3s
Now we integrate over time to get the position:
for t ≤ 3s we have:
p(t) = (1/2)*(2m/s^2)*t^2 - 2m/s*t + C
where C is a constant of integration, as we are calculating the displacement this constant actually does not matter, so we can use C = 0m
p(t) = (1m/s^2)*t^2 - 2m/s*t for t ≤ 3s
and p(3s) = (1m/s^2)*3s^2 - 2m/s*3s = 9m - 6m = 3m is the initial position of the other part of the function.
for t ≥ 3s we have:
p(t) = 4m/s*t + p(3s) = 4m/s*t + 3m
then the position equation is:
p(t) = (1m/s^2)*t^2 - 2m/s*t ---- t ≤ 3s
p(t) = 4m/s*t + 3m --- if t ≥ 3s
Now the displacement will be:
p(4s) - p(2s) where for each time, you need to use the correct function:
p(4s) = 4m/s*4s + 3m = 16m + 3m = 19m
p(2s) = (1m/s^2)*2s^2 - 2m/s*2s = 4m - 4m = 0m
p(4s) - p(2s) = 19m - 0m = 19m
The butterfly displacement x from t=2 to 4s is 19 meters.
What is displacement?The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolised as d or s), commonly known as length or distance.
The total displacement between t = 2s and t = 4s.
Integrate our function, the velocity equation.
for t ≤ 3s, we have a linear equation, let's write it:
A linear relationship can be written as:
y = a x t + b
where a is the slope and b is the y-axis intercept.
For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:
a = (y2 - y1)/(x2 - x1).
The line passes through the points (1, 0) and (0, -2)
The slope is:
a = (0 -(-2)/(1 - 0) = 2/1 = 2
When t = 0s, v(0s) = -2m/s, then our equation is:
v(t) = (2m/s²) x t - 2m/s for t ≤ 3s
now, for t ≥3s the equation is constant, v(t) = 4m/s.
v(t) = (2m/s²) x t - 2m/s -------if t ≤ 3s
v(t) = 4m/s ----- if t ≥ 3s
Now we integrate over time to get the position:
for t ≤ 3s we have:
p(t) = (1/2) x (2m/s²) x t^2 - 2m/s x t + C
where C is a constant of integration, to calculate the displacement this constant actually does not matter,
p(t) = (1m/s²)*t^2 - 2m/s x t for t ≤ 3s
and p(3s) = (1m/s^2) x 3s² - 2m/s x 3s = 9m - 6m = 3m is the initial position of the other part of the function.
for t ≥ 3s we have:
p(t) = 4m/s x t + p(3s) = 4m/s x t + 3m
then the position equation is:
p(t) = (1m/s^2) x t² - 2m/s x t ---- t ≤ 3s
p(t) = 4m/s x t + 3m --- if t ≥ 3s
Now the displacement will be:
p(4s) - p(2s) where for each time, you need to use the correct function:
p(4s) = 4m/s x 4s + 3m = 16m + 3m = 19m
p(2s) = (1m/s²) x 2s²- 2m/s x 2s = 4m - 4m = 0m
p(4s) - p(2s) = 19m - 0m = 19m
Thus, the displacement is 19 m.
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IMPORTANT 3 QUESTIONS!
Answer:
7. 20,000,000 mL.
8. 8,000 m.
9. 120,000 secs.
10. 4
Explanation:
7. Determination of the volume in millilitres (mL)
Volume in litre (L) = 20,000 L
Volume in millilitres (mL) =..?
The volume in mL can be obtained as follow:
1 L = 1,000 mL
Therefore,
20,000 L = 20,000 x 1,000 = 20,000,000 mL.
Therefore, 20,000 L is equivalent to 20,000,000 mL.
8. Determination of the distance in metre (m)
Distance in mile = 5 mile
Distance in metre =?
First, we shall convert from mile to kilometre.
This can be done as follow:
1 mile = 1.6 km
Therefore,
5 mile = 5 x 1.6 = 8 km
Finally, we shall convert 8 km to metre (m).
This is illustrated below:
1 km = 1,000 m
Therefore,
8 km = 8 x 1,000 = 8,000 m
Therefore, 5 miles is equivalent to 8,000 m.
9. Determination of the time in seconds.
Time = 400 minutes for 5 days.
First, we shall convert 400 mins to hour.
This is illustrated below:
60 minutes = 1 hour
Therefore,
400 mins = 400/60 = 20/3 hours
The time (hours) is 20/3 hours in 1 day.
Therefore, the time (hours) in 5 days will be = 20/3 x 5 = 100/3 hours.
Next, we shall convert 100/3 hours to minutes.
This is illustrated below:
1 hour = 60 minutes
Therefore,
100/3 hours = 100/3 x 60 = 2000 mins
Finally, we shall convert 2000 mins to seconds.
This is illustrated below:
1 mins = 60 secs
2000 mins = 2000 x 60 = 120,000 secs.
Therefore, the time is 120,000 secs.
10. Determination of the number of significant figures.
To obtain the significant figures of a number, we simply count all the numbers available.
Therefore, the number of significant figures for 9876 is 4.
If you have a 200g sample of a radioactive isotope that has a half life of 50 years, hc
much will you have left at the end of 200 years?
a. 12.5 g
b. 100 g
c. 50 g
d. 25 g
Answer:
The correct option is;
a. 12.5 g
Explanation:
The given parameters are;
The initial mass of the radioactive substance = 200 g
The half life of the radioactive substance = 50 years
The time duration for the disintegration = 200 years
The formula for half life is given as follows;
[tex]N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}[/tex]
Where:
N(t) = Quantity of the remaining substance
N₀ = Initial radioactive substance quantity = 200 g
t = Time duration = 200 years
[tex]t_{1/2}[/tex] = Half life of the radioactive substance 50 years
Therefore, we have;
[tex]N(t) =200 \times \left (\dfrac{1}{2} \right )^{\dfrac{200}{50} } =200 \times \left (\dfrac{1}{2} \right )^4 = 12.5 \ g[/tex]
Therefore, at the end of 200 years, the quantity left = 12.5 g.
An observer is standing next to the tracks, watching a train approach. The train travels at 30 m/s and blows its whistle at 8,000 Hz as it approaches and then passes by the observer without slowing down. Assuming the speed of sound is 340 m/s, how much of a frequency change did the observer hear?
7351.35Hz
f0= v-Vo/v-Vs × FSA
= 340-0 /340+30 ×8000
= 340/370× 8000
= 7351.35hz
Is there a way for us to control motion
Answer:
They are:
1) change position
2) distract yourself
3) Get fresh air
4) Face the direction you are going.
5) Drink water.
6) Play music.
7) Put your eyes on horizon.
Explanation:
Hope it helps.
Astronauts train for space flight in a centrifuge,which consists of a rotating arm with a cab at the outer end of thearm. The arm, which has a length of 58 feet, is revolved about thecenter of the centrifuge. An astronaut sits in the cab, which is thenrotated 50 times per minute. To the nearest hundred feet, how fardoes the astronaut travel in one minute?
Explanation:
We know that,
[tex]v = rw[/tex]
Where, v = tangential velocity (m/sec)
r = radius = 17.67 m
w = angular velocity = 0.83 revs/ sec
v = 14.66 m/sec
Distance in one minute = 879.6 m
= 2885.82 feet
The Doppler effect a. can be applied only to sound waves. b. is the basic explanation for the blue shift of light in our Universe. c. occurs when the frequency of sound waves received is lower if the wave source is moving toward you than if it's moving away. d. occurs when the pitch of a sound gets lower if the source is receding.
Answer:
a. can be applied only to sound waves.
c. occurs when the frequency of sound waves received is lower if the wave source is moving toward you than if it's moving away
d. occurs when the pitch of a sound gets lower if the source is receding.
Explanation:
[tex].[/tex]
This is actually an earth science question. What is the exact elevation of each point?
Answer:
A = 100m
B = 120m
C = 170m
D = 160m
E = 190m
F = 145m
G = 130m
H = 170m
I = 100m
J = 95m
K = 100m
Explanation:
A = 100m
B = 120m
C = 170m
D = 160m
E = 190m
F = 145m
G = 130m
H = 170m
I = 100m
J = 95m
K = 100m
The contour intervals are 10m apart, anything exactly between 2 contour lines is 5m, and the cut lines are depressions so insisted of going up they go down.
Which of the following is a true statement about mass and weight? Mass is a measure of how much matter an object has, while weight is a measure of how much space the object takes up. Mass will not change based on location, while weight will change based on gravitational pull. Mass is a measure of a gravitational pull on an object, while weight is a measure of how much matter is an object has. Mass is proportional to the force of gravity, while weight is proportional to the amount of mass.
Answer:
Mass will not change based on location, while weight will change based on gravitational pull.
Explanation:
The formula for weight is mass*gravitational pull, hence weight changes based on gravitational pull
Mass will not change based on location, while weight will change based on gravitational pull. This is a true statement about mass and weight.
What are mass and weight?The most fundamental characteristic of matter is mass, which is one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass (kg). A body's mass remains constant at all times.
The amount of weight t indicates how much gravity is pulling on a body. The weight formula is provided by: w = mg
Weight being a force The SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change from one location to another, the acceleration caused by gravity does.
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73Ge
32
has
neutrons.
A person holds a 25 kg (250 newton) bag of cement over his head and moves it a distance of 10 m, taking 2 minutes, while another person carries it on a wheelbarrow that same distance, taking 1 minute.Who does more work ? What is the power of each person?
Explanation:
Assuming the 10 m distance is the vertical displacement, the work done by both people is the same.
Work = force × distance
W = (250 N) (10 m)
W = 2500 J
The power of the first person is:
Power = work / time
P = 2500 J / 120 s
P = 20.83 W
The power of the second person is:
P = 2500 J / 60 s
P = 41.67 W