a small truck has a mass of 2095 kg. how much work is required to decrease the speed of the vehicle from 25.0 m/s to 15.0 m/s on a level road?

To learn the viscosity and speed and resistance to calculate the diameter.

What is viscosity?

Viscosity is a fluid's (liquid or gas) resistance to a change in shape or motion of adjacent parts concerning one another. Viscosity indicates resistance to flow.

What constitutes speed?

The speed of a change in an object's position in any direction Speed is defined as the ratio of distance to the amount of time it takes to cover that distance. Since speed has only a direction and no magnitude, it is a scalar quantity.

Resistance AC circuit

in resistance AC circuit the voltage and current are related as,

Emf; E= EoSinωt

where, I_O=E_O/R

In purely resistive circuit, there is no phase change occurs. the phase angle between voltage and current is zero.

the maximum value of current is I_0 =v_0\R

if tha maximum volatge v_0 is increase with decrease of resistance R then current in the circuit will maximum and denoted asI_0

capacitive AC circuit

In capacitive AC circuit the voltage and current are related as,

Emf: E=E_Osinωt

and current I =I_Osinωt

⇒ I =I _0sin(ωt+π/2)

where,I_0 =E_0/X_C

in purely capacitive circuit, current leads the end by phase of π/2. the phase angle between volatge and current is π\2

The maximum value of current is,I_0 =E_0\X_C

if the maximum voltage E_0 is increases with decreases of capacitive X_c then current in the circuit will maxmium and denoted as I_0

when the emf is zero then current is maximum magnitude.so the current is maxmium before it leads or lag in the circuit.

inductive AC circuit:

Inductive AC circuit the voltage and current are related as

Emf: E= E_0sinωt

And current : I= (-)I_0cosωt

⇒ I= I_0sin(ωt -π/2)

where, Iπ_0 =E_0/X_L and x=∈L

In purely inductive circuit, the current lags behind the voltage (emf) by phase of π/2. The phase angle between volatge and current is π/2

The maximum value of current is, I_0 = E_0/X_L

if the maximum voltage E_0 is increase with decrease of inductive resistance X_L then current in the circuit will maximum and denoted is I_0.

Therefore, the emf is zero then current is maximum magnitude. so the current is maximum before it leads or lag in the circuit.

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Answer:

280 N

Explanation:

Remember   F = ma

F = 2000  *  .14   = 280 N

The weight the scale would read if the sphere of mass 20 kg with a 10 cm radius was totally submerged in water is 155.1 N

Fg = m g

Fb = ρ V g

Fg = Force of gravity

Fb = Buoyant force

m = Mass

g = Acceleration due to gravity

ρ = Density of medium

V = Volume of object

m = 20 kg

g = 9.8 m / s²

ρ = 1000 kg / m³

r = 10 cm = 0.1 m

Fg = 20 * 9.81

Fg = 196.2 N

Fb = ρ ( 4 / 3 π r³ ) g

Fb = 1000 * 4 / 3 * 3.14 * 0.1³ * 9.8

Fb = 41.1 N

N = Fg - Fb

N = Scale reading

N = 196.2 - 41.1

N = 155.1 N

Therefore, the scale reading if the sphere was totally submerged in water is 155.1 N

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The direction of the angular displacement of the wheel is -Toward you.

The definition of angular displacement is "the angle, expressed in radians (degrees, revolutions), through which a point or line has been rotated in a particular sense about a certain axis." It is the angle at which a body travels around in a circle.

A vector quantity, angular velocity has both a magnitude and a direction. The direction matches the direction of the angular displacement, which is where we derived the angular velocity.

The rate at which angular velocity changes over time is referred to as angular acceleration. Typically, it is stated in radians per second per second. As a result, d = d t. The term "rotational acceleration" also applies to the angular acceleration.

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An object I aid to be positively charged if it has a number of electrons i greater than the number of protons. TRUE

If an object has extra protons than electrons, then the internet fee on the item is fantastic. If there are extra electrons than protons, then the net charge at the item is bad. If there are equal numbers of protons and electrons, then the object is electrically impartial.

An electrical price is created while electrons are transferred to or removed from an object. because electrons have a bad charge, while they are added to an item, it turns negatively charged. when electrons are removed from an object, it will become undoubtedly charged.

A positively charged object has misplaced electrons. A definitely charged object has won protons. A negatively charged item has lost protons. If the variety of electrons is greater than the range of protons, the particle is a negative ion, also referred to as an anion.

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Disclaimer:- your question is incomplete, please see below for the complete question.

An object I aid to be positively charged if it has a number of electrons i greater than the number of a proton. TRUE/FALSE

The initial speed of a shopping cart is 36 m/s.

What is acceleration?

Acceleration is the term used to describe how quickly a velocity's speed and direction change over time. It is said to have been accelerated when something changes its direction and moves faster or slower. Motion on a circle accelerates even when the speed is constant because the direction is constantly changing.

What is kinematic equation?

The set of equations known as the kinematic equations describes how an object moves with constant acceleration. Integrals, rates of change, and derivatives must be understood in order to solve kinematic equations.

List the known and unknown values.

u = initial velocity = 20 m/s

v = final velocity = ? m/s

a = acceleration = 4 m/s²

t = time interval = 4 s

s = displacement = ? m

The following kinematic equation should be used to determine the final velocity.

v = u + at

v = 20 m/s + (4 m/s² × 4 s) = 36 m/s

Now calculate the displacement using the following kinematic equation.

s = ut + ½at²

s = (20 m/s × 4 s) + (0.5 × 4 m/s² × (4 s)²)

s = 80 m + 32 m = 112 m

Therefore, the initial speed of a shopping cart is 36 m/s.

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Thousands of small rocky objects known as asteroids can be found in the solar system between Mars and Jupiter.

The Solar System is composed of the Sun and the objects that orbit it. It was created by the gravitational collapse of a massive interstellar molecular cloud 4.6 billion years ago. The Sun contains the vast majority of the system's mass, with Jupiter holding the majority of the remaining mass.

Asteroids are rocky bodies that orbit the Sun. Although asteroids orbit the Sun in the same way that planets do, they are much smaller. In our solar system, there are numerous asteroids. The majority of them are found in the main asteroid belt, which lies between the orbits of Mars and Jupiter.

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Using the concepts of simple harmonic progression, we got that period of the standing wave changes directly proportional as the length of the slinky is altered.

We know very well that a standing wave traverse alternatively from crest to trough.

Crest is defined as that point when amplitude is maximum in positive y-direction and trough is defined as that point when amplitude is maximum in negative y-direction.
To traverse from crest to trough, a standing wave requires some time.

When the length of standing wave changes the time required by the standing wave also changes.

It means if we increase the length of slinky then the time required by the standing wave also increases and if we decrease the length of slinky then the time required by the standing wave also decreases.

Hence, when the fundamental standing wave is oscillating on a slinky, the period of the standing wave change directly proportional  as the length of the slinky is altered.

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The sun is moving toward the constellation Cygnus, as discovered by Herschel when they counted stars in 683 regions around the Milky Way.

One of the significant discoveries made by Galileo in his Sidereus Nuncius in 1610 was that, when viewed through a telescope, some of the Milky Way resolved into a cluster of numerous stars.

The Sun is the darker star towards the image's center. Herschel has indicated its location in the image above. Herschel's research leads to the conclusion that the Sun is situated at or close to the Milky Way's center.

The Milky Way galaxy is the home of the Sun. About 100,000,000,000 stars are thought to be present in the Milky Way alone, according to astronomers.

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Answer:

Determine the total capacitance between points A and B in the figure below. C =104F C = 5uF C=20uF MAE ce Select the best answer: 2.84uF 2.80uF O 2.90pF 2.86F

Explanation:

hoped it help cutie if u need more help js ask meh

The subject tested alone would yield better findings and higher alpha values than the subject evaluated in a lab with several pupils.

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Produced the model is the resistance of the circuits decreased as a battery voltage increased (option-B).

Ohm's Law describes how current, voltage, and resistance are related to one another. According to this, as long as the temperature doesn't change, the current flowing through a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.

The more work a certain quantity of electrons can accomplish at a given voltage. The quantity of electrons that are presently moving through any one point in a circuit at any particular time is known as the current. At the same voltage, a larger current can perform more work. Current times voltage equals power.

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Answer:

b

Explanation:

The stress that spreads over the soles of the feet by the body is 18000 N/m².

The compressive stress exerted on a body is given by the force applied to the body divided by the area,

So, we can write,

Stress = force/area

In this case, the force will be equal to the weight of the body.

F = Mg

M is the mass of the person,

g is the acceleration due to gravity.

F = 72×10

F = 720N

The area of the soles is given to be 200 cm²

Converting into meter square,

Area = 0.02 m²

As there are two soles,

Area = 0.04

Putting values to find stress,

Stress = 720/0.04

Stress = 18000N/m²

So, the stress on the soles is 18000 N/m².

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Adding a third resistor in series with two resistors connected across a constant voltage source without internal resistance will cause the power supplied by the source to decrease.

The reason is that adding the extra resistor will increase the total resistance and decrease the current through all three resistors. The new total resistance is: Rtot = R1 + R2 + R3

And as we see from Ohm's Law, V/I = R, so we can also express this as: V2/I2 + V1/I1 + V3/I3 = V4/I4.

From here, we can see that when we add a third resistor in series with two others, we have more voltage across each individual part of our circuit, but less current flowing through each part of it. That means our total power supplied by the source decreases because there is less current flowing through all three resistors combined.

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The thickness of each page is 0.06 mm

You can measure the thickness of paper with a vernier caliper. Insert a piece of paper or cardboard between the caliper jaws. Then tighten the jaws and measure the distance between them. A digital caliper can indicate the thickness of a piece of paper.

Given,

number of pages book = 120

Total thickness of book = 8.2 mm

Thickness of front and back cover of the book =  0.5 mm

Thickness of pages = Total thickness - Thickness of front and back cover

Thickness of pages = 8.2 mm - 1 mm

Thickness of pages = 7.2 mm

Thickness of each page = 7.2/120

Thickness of each page = 0.06 mm

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Ball’s weight is 4.4129925 N ,  net force on the ball is 2.25 N , Ryan has to apply a force of 4.9 N.

What is force ?

Whenever there is an interaction between two objects, there is a force acting on each object. When the interaction stops, the two objects no longer receive forces. Forces arise only through interactions , describes the technique of rocks converting their bodily houses with out converting their simple composition.

What is acceleration ?

Acceleration is a vector quantity defined as the rate at which an object's velocity changes. An object accelerates when its velocity changes.

What is friction ?

Friction is the resistance to movement of 1 item transferring relative to another. According to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab), it isn't always handled as a essential force, like gravity or electromagnetism. Instead, scientists accept as true with it's miles the end result of the electromagnetic appeal among charged debris in touching surfaces.

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Answer:

That's all i know

Anyway welcome

The rate is the current changing is = - 1.3 x 10⁻⁴ A/s

Solution:

We take the derivative of Ohm's law with respect to time

V = IR

Using the product rule:

dV/dt = I(dR/dt) + R(dI/dt)

We are given that voltage is decreasing at 0.01 V/s

resistance is increasing at 0.04 ohm/s

resistance itself is 400 ohms,

and current is 0.04 A

Substituting:

-0.01 V/s = (0.04 A)(0.04 ohm/s) + (400 ohms)(dI/dt)

dI/dt = -1.3 x 10⁻⁴ A/s.

The relationship between current, voltage, and resistance. The amount of continuous current flowing through many materials is directly proportional to the potential difference or voltage between them.

Law of Electricity The strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit. Ohm's Law is a formula for calculating the relationship between voltage, current, and resistance in a circuit. Ohm's law describes the relationship between current, voltage, and resistance. This shows that at a constant temperature, the current through the circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.

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A system's Center of Mass won't change if no external forces are applied to it, which means no forces from sources outside the system.

In a uniform gravity field, the phrases "center of mass" and "center of gravity" are interchangeable to refer to the particular place in an item or system that can be used to describe how the system reacts to outside forces and torques. The idea of the center of mass is to calculate the average mass by dividing it by the distance from a fixed location.

Because no external force actuated on the system or any of its components, C.M. velocity is zero (0) for this problem. Although it is true that the two people exerted pressures on themselves, these forces were internal (i.e., produced by system components themselves) and as a result, the system Center of Mass was unaffected.

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Since the meter's 3V terminals are connected to the circuit, we have to read the "zero-to-3" scale on the meter to get our measurement.  That's the scale under the marks.

On that scale, the needle points to  1.4 DC Volts.  That's the potential difference between the two points the meter probes are touching.

The farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

From the graph,

The positions reached after,

5 s = 4 m

10 s = 2 m

20 s = 2 m

35 s = 3 m

40 s = 0 m

So the farthest position here is 4 m into the tunnel.

The rate of change of positions is displacement. So displacement will be change in initial and final positions divided by change in time.

s = Δx / Δt

Therefore, the farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

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As the tension of the spring is held constant as well as the frequency of the resulted sinusoidal wave, if the power delivered to the string is quadrupled, the amplitude will increase by factor 2.

If the frequency is held constant, the energy delivered to a wave is directly proportional to the square of its amplitude, or:

E ∝ A²

Where:

E = energy

A = amplitude

Power is energy per unit time, therefore power is also directly proportional to the square of amplitude.

P₂ : P₁ = A₂² : A₁²

From the problem, we know that P₂ = 4P₁

Hence,

4P₁ : P₁ = A₂² : A₁²

A₂² = 4 A₁²

A₂ = 2 A₁

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Explanation:

While the unitarios fought for a centralized government, located in the city of Buenos Aires, the federales sought political decentralization so that the autonomy of the provinces within the nation would be respected.

Compared to the orbital speeds of the planets in our solar system, the Milky Way Galaxy's rotation curve is far more flat and steady. While there is less mass as we get farther from the sun in our solar system.

The orbital speed of an astronomical body or object (such as a planet, moon, artificial satellite, spacecraft, or star) in gravitational bound systems is its speed relative to the most massive body's centre of mass, or the barycenter, if one body is significantly more massive than the other bodies in the system put together.

The phrase can be used to describe either the mean orbital speed (i.e., the speed throughout the course of an orbit) or its instantaneous speed at a specific location in the orbit. For objects in closed orbits, the maximum (instantaneous) speed occurs at periapsis (perigee, perihelion, etc.), whereas the smallest speed occurs at apoapsis (apogee, aphelion, etc.). When two-body systems are perfect, things An astronomical body or object (such as a planet, moon, man-made satellite, spacecraft, or star) moves through space at a certain speed called its orbital speed in gravitational bound systems.

When a system closely resembles a two-body system, the object's specific orbital energy, also known as "total energy," and its distance from the central body can be used to calculate the object's instantaneous orbital speed at a specific point in the orbit. Independent of position, the specific orbital energy is constant.

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The mass of the meter stick is 0.15 kg.

The parameter

Calculate the weight of the mass.

w = mg

w = [tex]0.05 \times 10[/tex]

w = 0,5 N

Look at the picture. The weight of the stick is in the middle of its length at 50 cm. The meter stick is balanced in the horizontal position. At point A

Σ τ = 0

(ws × 10) - (w × 30) = 0

ws × 10 = w × 30

ws × 10 = 0.5 × 30

ws × 10 = 15

[tex]w_s = \frac{15}{10}[/tex]

ws = 1.5 N

ms × 10 = 1.5

[tex]m_s = \frac{1.5}{10}[/tex]

ms = 0.15 kg

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It will take the lightbulb 2875 seconds to use  2.3×10⁵J of energy.

Power is the amount of work completed in a given amount of time, or time spent working. The joules per second (J/s)-based SI unit of power is the Watt (W).

Given,

Power (P) = 80 J/s

Energy (E) = 2.3×10⁵ J

Time (t) = ?

The pace at which energy is utilized is a straightforward definition of power. Power can be mathematically stated as:

Energy x time equals power

P = E/t

We can calculate the time it takes for the bulb to use 2.3 105 J using the formula above. This is attainable as follows:

Power (P) = 80 J/s

Energy (E) = 2.3×10⁵ J

Time (t) = ?

Power = Energy / time

P = E/t

80 = 2.3×10⁵ /t

80 × t = 2.3×10⁵

Divide both side by 80

t = 2.3×10⁵ / 80

t = 2875 s

As a result, it will take the lightbulb 2875 seconds to use  2.3×10⁵J of energy.

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Complete question is "A light bulb consumes energy at a rate of 80joules per second . How long in seconds will it take for the light bulb to consume  2.3×10⁵in energy?".

Answer:

Approximately [tex]0.033\; {\rm m\cdot min^{-1}}[/tex] (meters per minute.)

Explanation:

Let [tex]A[/tex] and [tex]B[/tex] denote the bottom and top width of the trough, respectively. It is given that [tex]A = 30\; {\rm cm} = 0.30\; {\rm m}[/tex] and [tex]B = 80\; {\rm cm} = 0.80\; {\rm m}[/tex]. Let [tex]H[/tex] denote the height of this trough; [tex]H = 50\; {\rm cm} = 0.50\; {\rm m}[/tex].

Let [tex]h[/tex] denote the current depth of the water in this trough.

Let [tex]b[/tex] denote the current width of the surface of the water. As water fills the trough, this width increases from [tex]A = 0.30\; {\rm m}[/tex] (width of bottom of trough) to [tex]B = 0.80\; {\rm m}[/tex] (width of top of trough.)

The relationship between [tex]b[/tex] and [tex]h[/tex] is linear:

[tex]\displaystyle b = \frac{h}{H}\, (B - A) + A[/tex].

Cross-section area of water in this trough:

[tex]\begin{aligned}(\text{area}) &= \frac{1}{2}\, (A + b) \, h \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h \\ &= A\, h + \frac{1}{2\, H} (B - A)\, h^{2}\end{aligned}[/tex].

Let [tex]L[/tex] denote the length of this trough; [tex]L = 10\; {\rm m}[/tex].

Let [tex]v[/tex] denote the volume of water in this trough:

[tex]\begin{aligned}v &= (\text{area})\, L \\ &= \frac{1}{2}\, (A + b) \, h\, L \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h\, L \\ &= A\, L\, h + \frac{L}{2\, H} (B - A)\, h^{2}\end{aligned}[/tex].

Differentiate both sides implicitly with respect to [tex]v[/tex]:

[tex]\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}\left[A\, L\, h + \frac{L}{2\, H}\, (B - A)\, h^{2}\right][/tex].

[tex]\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}[A\, L\, h] + \frac{d}{dv}\left[\frac{L}{2\, H}\, (B - A)\, h^{2}\right][/tex].

[tex]\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{2\, H}\, (B - A)\, 2\, h\, \frac{dh}{dv}[/tex].

(Note that [tex]A[/tex], [tex]B[/tex], [tex]L[/tex], and [tex]H[/tex] are constants.)

Rearrange this equation to obtain:

[tex]\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{H}\, (B - A)\, h\, \frac{dh}{dv}[/tex].

[tex]\displaystyle 1 = \left(A\, L + \frac{L}{H}\, (B - A)\, h \right)\, \frac{dh}{dv}[/tex].

[tex]\displaystyle \frac{dh}{dv} = \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}[/tex].

Let [tex]t[/tex] denote time. It is given that the trough is being filled at a rate of [tex]0.2\; {\rm m^{3}\cdot min^{-1}}[/tex]. In other words:

[tex]\displaystyle \frac{dv}{dt} = 0.2\; {\rm m^{3}\cdot min^{-1}}[/tex].

Apply the chain rule to find the rate at which [tex]h[/tex] is changing with respect to time [tex]t[/tex]:

[tex]\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \end{aligned}[/tex].

Substitute in [tex]A = 0.30\; {\rm m}[/tex], [tex]L = 10\; {\rm m}[/tex], [tex]H = 0.50\; {\rm m}[/tex], [tex]B = 0.80\; {\rm m}[/tex], [tex]h = 0.30\; {\rm m}[/tex] (converted from [tex]30\; {\rm cm}[/tex]), and that the rate of change in [tex]v[/tex] is [tex]0.2\; {\rm m^{3}\cdot min^{-1}}[/tex]:

[tex]\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \\ &= \frac{0.2\; {\rm m^{3}\cdot min^{-1}}}{\displaystyle 0.30\; {\rm m} \times 10\; {\rm m} + \frac{10\; {\rm m}}{0.60\; {\rm m}}\, (0.80\; {\rm m} - 0.30\; {\rm m}) \, 0.30\; {\rm m}} \\ &=0.033\; {\rm m\cdot min^{-1}} \end{aligned}[/tex].

In other words, the depth of the water in this trough increases at a rate of approximately [tex]0.033\; {\rm m \cdot min^{-1}}[/tex] (meters per minute.)

Most ground water will move rather slowly when compared to how fast water moves in streams.

The statement is true

Water quantity both affect flow. It is significant because it affects the habitats of living things in the stream as well as the water quality. Small streams are less able to dilute and degrade contaminants than large, fast running rivers, which can receive pollution releases with little impact.

To "flow" is to move in a stream, just like water. As air circulates, the word "flow" also signifies to move. Flow is a noun that refers to motion that resembles a stream. The noun and verb 'flow' can be used in a variety of various contexts. Something flows when it moves like a stream of water.

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Using the concepts of atwood machine, we got 4.05m[tex]s^{-2}[/tex]. is the acceleration of system when released from rest.

We know very well that in atwood`s two bodies having different mass are hanged around the pulley.

The accceleration of the atwood is given by :

a=((m2-m1)/(m2+m1))×g, where m2 is the mass of heavier body,m1 is the mass of lighter body and g is the acceleration due to gravity.

So, according to question m2=11.9,m1=4.93 and g=9.8

So, on putting the value in above formula, we got

a=[(11.9-4.93)/(11.9+4.93)]×9.8

=>a=[(6.97)/(16.83)]×9.8

=>a=4.05m[tex]s^{-2}[/tex].

Hence, an  atwood machine in which two masses: one of mass 4.93 kg and the other of mass 11.9 kg. when released from rest, the acceleration of the system is 4.05m[tex]s^{-2}[/tex].

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Rachel is correct because she said that is body receive equal magnitude of impulse which completely satisfy the law of conservation of linear momentum.

According to law Conservation of Linear Momentum, if there is no external force working on the system, then the linear momentum remains conserved before and after the collision.

We know that,

Momentum is nothing but the product of force and the time taken for the contact period of the colliding bodies.

We assume that during the head on collision of the body, the body is remain in contact for such a short period of time that there is no external force all the impulse created due to the external force is neglected.

So, because the impulse imparted on both the bodies are equal to each other.

We know that impulse is nothing but the change in momentum.

So, from here we conclude that bodies received equal magnitude of impulse.

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