A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms value of the electric field?

Answer:

The  value is  [tex]\theta = 34.40^o[/tex]

Explanation:

From the question we are told that

   The  index of refraction is  [tex]n_s = 1.77[/tex]

   The  refractive index of air is  [tex]n_a = 1.0[/tex]

Generally the critical angle is mathematically represented as

      [tex]\theta = sin ^{-1} [\frac{1}{n_s} ][/tex]

=>    [tex]\theta = sin ^{-1} [\frac{1}{1.77} ][/tex]

=>    [tex]\theta = sin ^{-1} [0.565 ][/tex]

=>    [tex]\theta = 34.40^o[/tex]

Answer: table

Explanation:

Answer:Table

Explanation:

A table is a way to represent data , but does not identify trends in the data

Answer:

1.938*10^3N/C

Explanation:

Using F= qE

E= F/q

Where q= 1.6x10-19

So 3.1*10^-16/1.6*10^-19

= 1.938*10^3N/C

Explanation:

Answer:

The mass of water that will evaporate 2.857 kg.

Explanation:

Given;

temperature of the water, T = 100 c

rate of heat transfer,  H = 2 kW = 2000 w

time, t = 10 min = 10 min x 60s = 600s

heat capacity of water is given by;

Q = McΔT

Where;

Q is the quantity of heat transfer to the pan = P x t =  2000 x 600 = 1200000 J.

c is specific heat capacity of water = 4200 J/kg.°C

m = (Q) / (cΔT)

m = (1200000) (4200 x 100)

m = 2.857 kg

Therefore, the mass of water that will evaporate 2.857 kg.

Complete Question

A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.

Answer:

The value [tex]v_2 = 4 \sqrt{10} \ m/s[/tex]

Explanation:

From the question we are told that

   The  charge on the first sphere is  [tex]q_1 = 2\mu C = 2*10^{-6} \ C[/tex]

    The charge on the second sphere is  [tex]q_2 = 8 \mu C = 8*10^{-6} \ C[/tex]

     The  mass of the second charge is [tex]m = 1.50 \ g = 1.50 *10^{-3} \ kg[/tex]

      The  distance apart is  [tex]d = 0.4 \ m[/tex]

      The  speed of the second  sphere is  [tex]v_1 = 20 \ ms^{-1}[/tex]

Generally the total energy possessed by when [tex]q_2[/tex] and  [tex]q_1[/tex] are separated by [tex]0.8 \ m[/tex] is mathematically represented

     [tex]Q = KE + U[/tex]

Here KE   is  the kinetic energy which is mathematically represented as

     [tex]KE = \frac{1 }{2} m (v_1)^2[/tex]

substituting value

     [tex]KE = \frac{1 }{2} * ( 1.50 *10^{-3}) (20 )^2[/tex]

     [tex]KE = 0.3 \ J[/tex]

And  U is  the  potential  energy which is mathematically represented as

        [tex]U = \frac{k * q_1 * q_2 }{d }[/tex]

substituting values

       [tex]U = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.8 }[/tex]

      [tex]U = 0.18 \ J[/tex]

So

       [tex]Q = 0.3 + 0.18[/tex]

       [tex]Q = 0.48 \ J[/tex]

Generally the total energy possessed by when [tex]q_2[/tex] and  [tex]q_1[/tex] are separated by [tex]0.4 \ m[/tex] is mathematically represented

         [tex]Q_f = KE_f + U_f[/tex]

Here [tex]KE_f[/tex] is  the kinetic energy which is mathematically represented as

     [tex]KE_f = \frac{1 }{2} m (v_2^2[/tex]

substituting value

     [tex]KE_f = \frac{1 }{2} * ( 1.50 *10^{-3}) (v_2 )^2[/tex]

     [tex]KE_f = 7.50 *10^{ -4} (v_2 )^2[/tex]

And  [tex]U_f[/tex] is  the  potential  energy which is mathematically represented as

        [tex]U_f = \frac{k * q_1 * q_2 }{d }[/tex]

substituting values

       [tex]U_f = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.4 }[/tex]

      [tex]U_f = 0.36 \ J[/tex]

From the law of energy conservation

     [tex]Q = Q_f[/tex]

So

    [tex]0.48 = 0.36 +(7.50 *10^{-4} v_2^2)[/tex]

   [tex]v_2 = 4 \sqrt{10} \ m/s[/tex]

Answer:

velocity^2=force*length/mass

Explanation:

velocity^2=force*length/mass  is dimensionally consistent

as we know that

unit of force=Newton

unit of length=meter

unit of mass=kilogram so

velocity^2=newton*meter/kilogram

newton=kg*m/sec^2 therefore

v^2=kg*m*m/sec^2*kilogram

v^2=kg*m^2/sce^2*kg

v^2=m^2/sec^2

taking square root on both side

√ v²=√m²/sec²

v=m/s  now the dimensions of V is

v=(L/T)

so option A is dimensionally consistent

It should be related like  velocity^2=force*length/mass

Since we know that

unit of force=Newton

unit of length=meter

And,

unit of mass=kilogram

Therefore,

velocity^2=newton*meter/kilogram

Now

newton=kg*m/sec^2

So,

v^2=kg*m*m/sec^2*kilogram

v^2=kg*m^2/sce^2*kg

v^2=m^2/sec^2

Now we take square root on both side

So,

√ v²=√m²/sec²

v=m/s  

v=(L/T)

Therefore, option A is correct

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Answer:

What is the radius of the table tennis ball?

 ⇒ 2.1 cm  

What is the radius of the golf ball?

2.0  cm

Explanation:

divide the radius and round it to the nearest 10th place..... but hope that help ;)

Answer:

1) What is the radius of the table tennis ball?

2.1 cm

2) What is the radius of the golf ball?

2.0 cm

Explanation:

Did this on Edge 2023 and got it right. Hope this helps :)

Answer:

The maximum speed the ball can have is 15.37 m/s

Explanation:

Given;

mass of the ball, m = 0.4 kg

radius of the chord, r = 1.5 m

maximum tension on the chord, T = 63 N

The maximum tension on the chord is given by;

[tex]T_{max} = \frac{mv_{max}^2}{r} \\\\v_{max}^2 = \frac{T_{max} *r}{m}\\\\ v_{max} = \sqrt{\frac{T_{max} *r}{m}} \\\\ v_{max} =\sqrt{\frac{63 *1.5}{0.4}}\\\\v_{max} = 15.37 \ m/s[/tex]

Therefore, the maximum speed the ball can have is 15.37 m/s

Answer:

  25 turns

Explanation:

The voltage ratio is the turns ratio:

  secondary turns / primary turns = secondary voltage / primary voltage

  secondary turns / 600 = 5/120

  secondary turns = 600(5/120) = 25 . . . turns

The secondary coil has 25 turns.

Answer:

E. converging surface winds

Explanation:

For the formation of tropical cyclones to occur in the northeast of the tropical Pacific Ocean, it is necessary to have converging surface winds that present a strong convection. This allows for the formation of vertical movements of an ascending nature that have great strength and are intense and violent. This also allows closed cyclonic circulation to occur at the lower levels which together with a low frontal pressure system over the waters of the Pacific Ocean can form the tropical cyclone.

Answer:

magnitude = 7.446 km, direction = 75.22° north of east

Explanation:

From the questions,

To get the the magnitude of the resultant vector we use Pythagoras theorem

a² = b²+c²

From the diagram,

y² = 1.9²+7.2²

y² = 55.45

y = √(55.45)

y = 7.446 km.

The direction of the dolphin is given as,

θ = tan⁻¹(7.2/1.9)

θ = tan⁻¹(3.7895)

θ = 75.22° north of east

Hence the magnitude of the resultant vector = 7.446 km, and it direction is 75.22° north of east

Answer:

Total speed of the insect as seen by a person standing on the side of the road is 22 m/s

Explanation:

There i a composition of velocities, since the air inside the bus is moving at the same speed as the bus, and the insect flying relative to it.

So for an observer on the side of the road, the insect is flying at a speed of :

20 m/s + 2 m/s = 22 m/s

Answer:

Weight

Explanation:

Weight is the downward pull on an object due to gravity.

For example, the moon has less gravity than Earth so we would weigh less on the moon. Our Mass and volume always stay the same but our weight could change.

Answer:

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Explanation:

Answer:

7482.5VA

Explanation:

We have that,

phase voltage of a three phase load is,240v

The phase current of a three phase load is, 18A

So To find apparent load we use

VA= √3*E*I

=√ 3*240*18

=7482.5VA

Answer:

Uses of concave mirror:

Shaving mirrors.

Head mirrors.

Ophthalmoscope.

Astronomical telescopes.

Headlights.

Solar furnaces.

Uses of convex mirror:

Convex mirrors always form images that are upright, virtual, and smaller than the actual object. They are commonly used as rear and side view mirrors in cars and as security mirrors in public buildings because they allow you to see a wider view than flat or concave mirrors.

please give me full points.

Answer:

The distance is [tex]r_2  =  0.24 \  m[/tex]

Explanation:

From the question we are told that

       The  distance from the conversation is [tex] r_1    =  24.0 \ m[/tex]

       The  intensity of  the sound at your position is  [tex]\beta _1 =  40 dB[/tex]

        The  intensity at the sound at the new position is  [tex]\beta_2 =  80.0dB[/tex]

Generally the intensity in  decibel is  is mathematically represented as

      [tex]\beta  =  10dB log_{10}[\frac{d}{d_o} ][/tex]

The intensity is  also mathematically represented as

      [tex]d =  \frac{P}{A}[/tex]

So

    [tex]\beta  =  10dB *  log_{10}[\frac{P}{A* d_o} ][/tex]

=>   [tex]\frac{\beta}{10}  =  log_{10} [\frac{P}{A (l_o)} ][/tex]

From the logarithm definition

=>    [tex]\frac{P}{A  *  d_o}  =  10^{\frac{\beta}{10} }[/tex]

=>      [tex]P =  A (d_o ) [10^{\frac{\beta }{ 10} } ][/tex]

Here P is the power of the sound wave

 and  A is the cross-sectional area of the sound wave  which is generally in spherical form

Now the power of the sound wave at the first position is mathematically represented as

               [tex]P_1 =  A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ][/tex]

Now the power of the sound wave at the second  position is mathematically represented as

               [tex]P_2 =  A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ][/tex]

Generally  power of the wave is constant at both positions  so  

    [tex]A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]  = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ][/tex]

      [tex]4 \pi r_1 ^2   [10^{\frac{\beta_1 }{ 10} } ]  = 4 \pi r_2 ^2   [10^{\frac{\beta_2 }{ 10} } ][/tex]

        [tex]r_2 =  \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}[/tex]

       substituting value

        [tex]r_2 =   \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}[/tex]

        [tex]r_2  =  0.24 \  m[/tex]

Answer:

The speed is 10 m/s

Explanation:

Th mass if the rock = 100 g = 0.1 kg

The kinetic energy = 5.0 J

speed of the rock = ?

The kinetic energy of the rock is given by the equation

E = [tex]\frac{1}{2} mv^{2}[/tex]

where

m is the mass of the rock

V is the velocity of the rock

substituting, we have

5 = [tex]\frac{1}{2} *0.1*v^{2}[/tex]

[tex]v^{2}[/tex] = 5/0.05 = 100

v = [tex]\sqrt{100}[/tex] = 10 m/s

Answer:

for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.

Explanation:

Let us consider a ball falling from its maximum height

For a body falling from its maximum height to a point p

change in height = Δh

The potential energy decrease is then proportional to

ΔPE = mgΔh

where

ΔPE is the decrease in kinetic energy

m is the mass of the ball

g is acceleration due to gravity

Δh is the change in height

For a body falling from its maximum height, the increase change in velocity

Δv = u + 2gΔh    (at maximum height u = 0)

where

u is the initial kinetic energy of the ball

Δv = 0 + 2gΔh

Δv = 2gΔh

The kinetic energy increases by

ΔKE = [tex]\frac{1}{2}[/tex]m(Δv)^2

but Δv = 2gΔh

therefore

ΔKE = [tex]\frac{1}{2}[/tex]m(2gΔh)^2 = 2m(gΔh)^2

comparing the increase in kinetic energy to the decrease in potential energy, we have

(2m(gΔh)^2)/(mgΔh) = 2gΔh

This means that for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.

Answer:

1200 lb-ft

Explanation:

Weight of diver W = 150 lb

length of board L = 8 ft  

This board is pivoted at one end therefore, the perpendicular distance from the pivot = 8 ft

Torque = weight x perpendicular distance from pivot

T = WL

Torque = 150 x 8 = 1200 lb-ft

Answer:

the instantaneous velocity of P is greater that Q because P obviously passes Q at that instant in time t

2. P has greater velocity at that instant (to) because P will need to be at a greater velocity to pass Q

Speed = distance / time

Speed = (33 cm) / (2min 20sec)

Speed = (0.33 m) / (140 sec)

Speed = 0.0024 m/s

Speed = (0.0024 m/s) x (3600 sec / 1 hr) x (1 km / 1000 m)

Speed = (0.0024 x 3600 / 1000) (m-sec-km / sec-hr-m)

Speed = 0.0085 km/hr

For the time of 2 min and 20 seconds, Archie's speed in m/s will be 0.0024 m/s and Archie's speed in km/hr will be 0.0085 km/hr.

The "speed at which an object is traveling," or speed, is a scalar quantity. The speed of an object is the rate at which it moves through space. A fast-moving object covers a considerable distance in a short amount of time while traveling at a high speed. An object moving slowly, on the other hand, moves a comparatively modest distance in the same amount of time. An object with zero speed is one that is not moving at all.

According to the question, the given values are :

Distance, d = 33 inches or,

d = 33 cm

Time, t = 2 minutes 20 seconds, or,

t = 140 seconds.

Speed is the ratio of distance to time.

s = 33/140

s = 0.0024 m/s

Now the distance in km/hr will be :

s = 0.0024 m/s × 3600 sec / 1hr × 1 km/ 1000 m

s= 0.0085 km/hr

Hence, the speed in km/hr is 0.0085 km/hr and in m/s speed is 0.0024 m/s.

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Answer:

The diameter of the hole increases

Explanation:

Metals expand and contract with temperature. Whenever metal is heated, it usually expands in relation to its thermal expansivity. This expansion leads to a slight increase in surface area.

Once the surface area of the metal changes, this means that the dimensions of the whole metal surface changed. As a result, the diameter of the hole drilled in the metal plate will change also. In our case, the diameter of the hole will increase.

Answer:

a) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules, b) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories, c) the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat.

Explanation:

a) Let be the automobile considered as particle travelling on horizontal ground, so that motion is entirely translational and whose formula for kinetic energy, measured in joules, is:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v[/tex] - Speed of automobile, measured in meters per second.

If [tex]m = 1200\,kg[/tex] and [tex]v = 18\,\frac{m}{s}[/tex], the kinetic energy of the automobile is:

[tex]K = \frac{1}{2}\cdot (1200\,kg)\cdot \left(18\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 194400\,J[/tex]

The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules.

b) A calory equals 4.186 joules. The kinetic energy in calories is:

[tex]K = 194400\,J \times \left(\frac{1}{4.186}\,\frac{cal}{J} \right)[/tex]

[tex]K = 46440.516\,cal[/tex]

The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories.

c) When the automobile brakes to a stop, the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat. Hence, such energy cannot be recovered. Potential energies are conservative by nature.

Answer:

Angular size in arc-minutes = 17.4 arc-minutes

Explanation:

Given:

Angular size = 0.29

Find:

Angular size in arc-minutes

Computation:

1 degree = 60 arc-minutes

So,

0.29 degree = 60 × 0.29 arc-minutes

0.29 degree = 17.4 arc-minutes

Angular size in arc-minutes = 17.4 arc-minutes

Answer:

1.0625×10¹⁹ electrons

Explanation:

From the question,

Using,

Q = It........................ Equation 1

Where Q = charge, I = current flowing in the wire, t = time (seconds)

Given: I = 1.70 A, t = 1 Seconds.

Substitute these values into equation 1

Q = 1.7(1)

Q = 1.7 C.

But,

1.6×10⁻¹⁹ C = 1 electron

Therefore,

1.7 C = 1.7/(1.6×10⁻¹⁹) electrons

= 1.0625×10¹⁹ electrons

Hence, 1.0625×10¹⁹ electrons flows through the wire per seconds.

Answer:

Their displacement is 5 Km from the cabin.

Explanation:

The displacement is define is the shortest distance between two points. It is the shortest distance of a line that joins two points together. It quantifies both the distance and direction of the net or total motion along a straight line from the initial position to the final position of the point trajectory. In this case, the straight line joining the cabin to the stream is line S which is equal to 5 Km

Given :

Speed of bus for first 16 hours is , u = 15 km/h .

Distance he walked for next 0.4 hour is , v = 4.5 km/h .

To Find :

The average speed for the whole  journey.

Solution :

Average speed is given by :

[tex]v_{avg}=\dfrac{u_1t_1+u_2t_2}{t_1+t_2}\\\\v_{avg}=\dfrac{15\times 16 + 4.5\times 0.4}{16+0.4}\\\\v_{avg}=14.74\ km/h[/tex]

Therefore , the average speed of the journey is 14.74 km/h .

Hence , this is the required solution .

Answer:

b. False

Explanation:

The Bernoulli's equation is given by;

[tex]P + \rho gh + \frac{1}{2} \rho v^2 = constat[/tex]

Divide through by the density of the fluid and acceleration due to gravity (ρg), to obtain energy per unit weight of the fluid known as head;

[tex]\frac{P}{\rho g} + h + \frac{v^2}{2g} = constant[/tex]

where;

[tex]\frac{P}{\rho g}[/tex] is pressure head

h is datum head (mechanical energy due to height of the fluid)

[tex]\frac{v^2}{2g}[/tex] is velocity head (mechanical energy due to velocity of the fluid)

Thus, the mechanical energy of a fluid per unit weight of the fluid, measured relative to the bottom of the channel is datum head.

The correct option is "b. False"

This question is incomplete, the complete question is;

A student dropped a textbook from the top floor of his dorm and it fell according to the formula s(t) = -16t² + 8√t, where t is the time in seconds and s(t) is the distance in feet from the top of the building.

(a) Write a formula for the average velocity of the ball for t near 4.

(b) Find the average velocity for the time interval beginning when t = 4 with duration 1 seconds, 0.5 seconds, and 0.05 seconds

(c) What is your estimate for the instantaneous velocity of the ball at t = 4

Answer:

a)

Average velocity, (Vavg)  of the ball for t near 4.

Vavg = [s(4) - s(0)] / (4 - 0)

Where s(4) = -16 × 4² + 8 × √4= - 240 m

s(0) = -16 × 0 + 8 * 0 = 0

b)

duration = 1 sec

Vavg = [s(5) - s(4)] / (5 - 4)

s(5) = -16 × 52 + 8 × √5 = - 382 m

s(4) = -16 × 42 + 8  √4 = - 240 m

Vavg = (-382 - (-240)) / (5 - 4)

Vavg = - 142.1 m/s

duration = 0.5 sec

Vavg = [s(4.5) - s(4)] / (4.5 - 4)

s(4.5) = -16 × 4.52 + 8 × √4.5 = - 307 m

s(4) = -16 × 42 + 8 × √4 = - 240 m

Vavg = (-307 - (-240)) / (4.5 - 4)

Vavg= - 134.1 m/s

duration = 0.05 sec

Vavg = [s(4.05) - s(4)] / (4.05 - 4)

s(4.05) = -16 × 4.052 + 8 × √4.05 = - 246 m

s(4) = -16 × 42 + 8 × √4 = - 240 m

Vavg = (-246 - (-240)) / (4.05 - 4)

Vavg= - 126.8 m/s

c)

Instantaneous velocity, v = ds/dt

= - 16 × 2 × t + 8 ×× (0.5 / √t )

= - 32 × t + 4/√t

ds/dt at t = 4 is,

v = - 32 × 4 + 4 / √4

= - 126 m/s

Answer:

cosine is adjacent over hypotenuse

Explanation:

How I know? It's just a basic formula for triangles, and my teacher taught me this. Sorry if this didn't help.

Answer:

D.cos(e)

hypotenuse adjacent

SUENT

Explanation:

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