Answer:
Let's take the frequency receive by police officer to be
f¹/f²= u-v/u+v
So 1255/1205= 340-v/340+v
V= 6.9m/s positive value implies that the car is moving toward the police
2 to find frequency we use
f/1205= 340+25/340-25
f= 1396Hz
A 5 kg object is launched from a 35 m high cliff at an angle of 30 degrees with a speed of 100 m/s. How far from the cliff does it hit the ground
Answer:
The object will hit the ground at 882.77 m from the lunch
Explanation:
we are to find the range of the motion
What is range?
It is the distance from the point of projection to the point where the object hits the ground
R=(v^2sin2θ)/g
Given data
v= 100 m/s
θ= 30 degree
g= 9.81 m/s^2
Substituting to find the R we have
R= 100^2 *sin(2*30)/9.81
R= (10000*0.866)9.81
R= 8660/9.81
R= 882.77 m
Two campers in a national park hike from their cabin to the same spot on a lake, each taking a different path, as illustrated below. The total distance traveled along Path 1 is 7.5 km, and that along Path 2 is 8.2 km. What is the final displacement of each camper?
Answer:
Their displacement is 5 Km from the cabin.
Explanation:
The displacement is define is the shortest distance between two points. It is the shortest distance of a line that joins two points together. It quantifies both the distance and direction of the net or total motion along a straight line from the initial position to the final position of the point trajectory. In this case, the straight line joining the cabin to the stream is line S which is equal to 5 Km
Examples of sources of physical entropy for secure random number generation include:________
Answer:
Noise in the environment
Electrons emitted via the photoelectric effect
Explanation:
Physical entropy can be seen as a disorderliness that can be observed in a physical system. The noise in a physical system can be used for secure number generation because of its randomness.
Noise is known to have no defined pattern and hence, can be used to creates secure random key generations.
Electrons emitted via the photoelectric effect: Electrons are emitted in a random order whenever a beam of light is incident on a photoelectric material. These electrons emitted can be used for random key generations
Which of the following describe a condition or location for the right environment for tropical cyclone formation over the north eastern tropical Pacific Ocean?
A. light surface winds
B. a La Nina event
C. stable air
D. a deep layer of humid air
E. converging surface winds
F. ocean surface temperature greater than 80 °F
Answer:
E. converging surface winds
Explanation:
For the formation of tropical cyclones to occur in the northeast of the tropical Pacific Ocean, it is necessary to have converging surface winds that present a strong convection. This allows for the formation of vertical movements of an ascending nature that have great strength and are intense and violent. This also allows closed cyclonic circulation to occur at the lower levels which together with a low frontal pressure system over the waters of the Pacific Ocean can form the tropical cyclone.
Use the table below to calculate the acceleration of the object. Time (s) 0.0 3.0 6.0 9.0 Velocity (m/s) 0.0 1.2 2.4 3.6
explanation
a=average velocity/average time
average velocity=0.0+1.2+2.4+3.6/4
average velocity=7.2/4
average velocity=1.8 m/s
average time=0.0+3.0+6.0+9.0/4
average time=18/4
average time=4.5 s
a= average velocity/average time
a=1.8/4.5
a=0.4 m/s²
URGENT!!!!! I WILL MARK U AS BRAINLIEST!!!!!!! A step-down transformer converts 120 V to 5 V in a phone charger. If the primary coil has 600 turns, how many turns are in the secondary coil? SHOW ALL WORK WITH CORRECT ANSWER WITH CORRECT UNIT AS WELL.
Answer:
25 turns
Explanation:
The voltage ratio is the turns ratio:
secondary turns / primary turns = secondary voltage / primary voltage
secondary turns / 600 = 5/120
secondary turns = 600(5/120) = 25 . . . turns
The secondary coil has 25 turns.
(a) Calculate the kinetic energy, in joules of a 1200 -kg automobile moving at 18 m/s .
(b) Convert this energy to calories.
(c) When the automobile brakes to a stop is the "lost" kinetic energy converted mostly to heat or to some form of potential energy?
Answer:
a) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules, b) The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories, c) the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat.
Explanation:
a) Let be the automobile considered as particle travelling on horizontal ground, so that motion is entirely translational and whose formula for kinetic energy, measured in joules, is:
[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]
Where:
[tex]m[/tex] - Mass, measured in kilograms.
[tex]v[/tex] - Speed of automobile, measured in meters per second.
If [tex]m = 1200\,kg[/tex] and [tex]v = 18\,\frac{m}{s}[/tex], the kinetic energy of the automobile is:
[tex]K = \frac{1}{2}\cdot (1200\,kg)\cdot \left(18\,\frac{m}{s} \right)^{2}[/tex]
[tex]K = 194400\,J[/tex]
The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 194400 joules.
b) A calory equals 4.186 joules. The kinetic energy in calories is:
[tex]K = 194400\,J \times \left(\frac{1}{4.186}\,\frac{cal}{J} \right)[/tex]
[tex]K = 46440.516\,cal[/tex]
The kinetic energy of the 1200-kg automobile moving at 18 meters per second is 46440.516 calories.
c) When the automobile brakes to a stop, the kinetic energy is transformed into work due to friction, which is a non-conservative force. And such work is dissipated in the form of heat. Hence, such energy cannot be recovered. Potential energies are conservative by nature.
Formula of velocity
Answer:
s = d/t
Explanation:
s= speed
d = distance traveled
t = time elapsed
PLEASE HELP NEED ANSWERS NOW! Time-Distance Graph
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, some have more details available when you click on them. Drag and drop each label to the corresponding area it identifies in the image.
Answer: I added a picture of the answer
Explanation: its right
The image of answer with labeled Time-Distance Graph is attached.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
What is a Distance-Time Graph?How far an object has moved in a certain amount of time is displayed on a distance-time graph. The graph that shows the results of the distance vs time analysis is a straightforward line graph.
The Y-axis represents the distance.The X-axis is used to plot time.When the object's motion is uniform, and the graph is a straight line. we can determine the object's speed at any given moment of time from the graph. The object was in the following positions when it started and stopped:
Speed = (Final Position-Initial position)/Time
Drawing a rectangle anywhere along the straight line that regulates the object's speed will reveal the slope of the line. A horizontal line on the distance-time graph indicates that an object is at rest if it is not moving.
Learn more about speed here:
https://brainly.com/question/28224010
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You toss a 100-g rock in the air with a kinetic energy of 5.0 J. How much is its speed as it leaves your hand
Answer:
The speed is 10 m/s
Explanation:
Th mass if the rock = 100 g = 0.1 kg
The kinetic energy = 5.0 J
speed of the rock = ?
The kinetic energy of the rock is given by the equation
E = [tex]\frac{1}{2} mv^{2}[/tex]
where
m is the mass of the rock
V is the velocity of the rock
substituting, we have
5 = [tex]\frac{1}{2} *0.1*v^{2}[/tex]
[tex]v^{2}[/tex] = 5/0.05 = 100
v = [tex]\sqrt{100}[/tex] = 10 m/s
Where on the physical activity pyramid do sedentary activities belong?
Answer:A
Explanation:
i just did the test
Answer: A.
Explanation: Edge said it was right
What is the direction of the magnetic field at the location of the charge due to the current-carrying wire
Answer: please find the answer in the explanation.
Explanation:
The direction of the magnetic field at the location of the charge due to the current-carrying wire can be determined by using right hand rule.
The thumb points in the direction of current while the fingers curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight wire. The thumb is pointed in the direction of the current and the fingers then give the direction of the magnetic field lines.
A football is kicked from ground level with an initial velocity of 23.8 m/s at angle of 42.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.
Answer:
The value is [tex]t = 3.28 \ s[/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]u = 23.8 \ m/s[/tex]
The angle is [tex]\theta= 42.5^o[/tex]
Generally from the projectile motion equation we know that the time of flight is mathematically represented as
[tex]t = \frac{2 * u *sin (\theta )}{ g }[/tex]
=> [tex]t = \frac{ 2 * 23.8 * sin (42.5)}{9.8 }[/tex]
=> [tex]t = 3.28 \ s[/tex]
A container of gas at 2.7 atm pressure and 133 ∘C is compressed at constant temperature until the volume is halved. It is then further compressed at constant pressure until the volume is halved again.
a) What is the final pressure (atm)?
b) What is the final temperature (C)?
Answer:
5.4atm ,66.5°c
Explanation:
Note that we are given the initial temperature to constant,
Thus PV = constant
so volume halved means pressure doubled from P1v1= p2v2
Hence P2 = 2.7*2atm = 5.4atm
next step we keep pressure constant thenV/T = constant
so volume halved means temperature also halved from V1/T1= v2/T2
Hence
T = 133/2 = 66.5°C
A hole is drilled in a metal plate. When the metal is raised to a higher temperature, what happens to the diameter of the hole?
Answer:
The diameter of the hole increases
Explanation:
Metals expand and contract with temperature. Whenever metal is heated, it usually expands in relation to its thermal expansivity. This expansion leads to a slight increase in surface area.
Once the surface area of the metal changes, this means that the dimensions of the whole metal surface changed. As a result, the diameter of the hole drilled in the metal plate will change also. In our case, the diameter of the hole will increase.
Add the following vectors using head-to-tail method and verify your results using the component method.
1. Vector A has a magnitude of 4.0 cms at an angle of 30 degrees with the positive X-axis; vector B has a magnitude of 3.0 cms at 90 degrees with + X-axis; vector C has a magnitude of 5.0 cms at 120 degrees with + X-axis.
2. In addition to vectors A, B, and C in problem # 1, there is a vector D with a magnitude of 6.0 cms at an angle of 210 degrees with +X-axis.
Note: Use a graph paper to show your work for problem number 1 and 2 using the head-to-tail method.
Do the component method analysis of both of these problems using the component method of adding vectors. Show your work step by step by taking the x and y components of all the vectors; adding all the x and y components together and then finding the resultant vector magnitude and direction knowing x and y are perpendicular to each other.
Compare the results of the graphical analysis as well as the component method and find the percent error using the component method as standard result
Answer:
See attached image for the requested graphs.
Part 1 : Vector sum is about 9.4 cm long in the graph, from components: about 9.35 cm long. Percent difference = 0.5%
Part 2: Vector sum is about 7.6 cm long in the graph and from components: 7.57 cm long. Percent difference = 0.4%
Explanation:
Part 1.
The graphical addition of the three vectors A, B and C gives a vector sum of approximately 9.4 cm at an angle of about 84 degrees
The component form addition is
Ax + Bx + Cx = 3.5 + 0 + (-2.5) = 1
Ay + By + Cy = 2.0 + 3 + 4.3 = 9.3
Magnitude: [tex]\sqrt{1^2+9.3^2} \approx 9.35\,\,cm[/tex]
The percent difference is: (9.4-9.35) * 100 /9.35 = 0.5%
Part 2.
The graphical addition of the four vectors (A, B, C, and D) measures approximately 7.6 cm at an angle of about 124 degrees.
The component form addition is
Ax + Bx + Cx + Dx = 3.5 + 0 + (-2.5) + (-5.2) = -4.2
Ay + By + Cy + Dy = 2.0 + 3 + 4.3 + (-3) = 6.3
Magnitude = [tex]\sqrt{(-4.2)^2+6.3^2} \approx 7.57\,\,cm[/tex]
The percent difference is: (7.6-7.57) * 100 /7.57 = 0.4%
A dolphin swims due east for 1.90 km, then swims 7.20 km in the direction south of west. What are the magnitude and direction of the vector that will take the dolphin back to its starting point? (Enter the magnitude in km and the direction in degrees north of east.)
Answer:
magnitude = 7.446 km, direction = 75.22° north of east
Explanation:
From the questions,
To get the the magnitude of the resultant vector we use Pythagoras theorem
a² = b²+c²
From the diagram,
y² = 1.9²+7.2²
y² = 55.45
y = √(55.45)
y = 7.446 km.
The direction of the dolphin is given as,
θ = tan⁻¹(7.2/1.9)
θ = tan⁻¹(3.7895)
θ = 75.22° north of east
Hence the magnitude of the resultant vector = 7.446 km, and it direction is 75.22° north of east
if the DIY parachute is dropped freely from the rooftop of the building of a building and reached the ground 3s later.Upon reaching the ground,What is the (a)final velocity of DYI parachutes ?(b) Height of the rooftop?
Answer:
It depends on what the parachute is made out of.
Explanation:
Andy took a bus and then walked from his home to downtown.
For the first 16 hour, the bus drove at an average speed of 15
km/h. For the next 0.4 hours, he walked at an average speed
of 4.5 km/h. What was the average speed for the whole
journey?
Given :
Speed of bus for first 16 hours is , u = 15 km/h .
Distance he walked for next 0.4 hour is , v = 4.5 km/h .
To Find :
The average speed for the whole journey.
Solution :
Average speed is given by :
[tex]v_{avg}=\dfrac{u_1t_1+u_2t_2}{t_1+t_2}\\\\v_{avg}=\dfrac{15\times 16 + 4.5\times 0.4}{16+0.4}\\\\v_{avg}=14.74\ km/h[/tex]
Therefore , the average speed of the journey is 14.74 km/h .
Hence , this is the required solution .
Sapphire has an index of refraction of 1.77. The critical angle for sapphire in air with an index of refraction of 1.0 is _____ degrees.
Answer:
The value is [tex]\theta = 34.40^o[/tex]
Explanation:
From the question we are told that
The index of refraction is [tex]n_s = 1.77[/tex]
The refractive index of air is [tex]n_a = 1.0[/tex]
Generally the critical angle is mathematically represented as
[tex]\theta = sin ^{-1} [\frac{1}{n_s} ][/tex]
=> [tex]\theta = sin ^{-1} [\frac{1}{1.77} ][/tex]
=> [tex]\theta = sin ^{-1} [0.565 ][/tex]
=> [tex]\theta = 34.40^o[/tex]
A current of 1.70 A flows in a wire. How many electrons are flowing past any point in the wire per second
Answer:
1.0625×10¹⁹ electrons
Explanation:
From the question,
Using,
Q = It........................ Equation 1
Where Q = charge, I = current flowing in the wire, t = time (seconds)
Given: I = 1.70 A, t = 1 Seconds.
Substitute these values into equation 1
Q = 1.7(1)
Q = 1.7 C.
But,
1.6×10⁻¹⁹ C = 1 electron
Therefore,
1.7 C = 1.7/(1.6×10⁻¹⁹) electrons
= 1.0625×10¹⁹ electrons
Hence, 1.0625×10¹⁹ electrons flows through the wire per seconds.
"Which gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string?"
Answer:
the second derivative of y with respect to time gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string
Explanation:
This is because the transverse wave movement of particles take place in direction 90° to direction of movement of the wave (x) itself, so second derivative of y with respect to time (t)is what will be required
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Complete Question
A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.
Answer:
The value [tex]v_2 = 4 \sqrt{10} \ m/s[/tex]
Explanation:
From the question we are told that
The charge on the first sphere is [tex]q_1 = 2\mu C = 2*10^{-6} \ C[/tex]
The charge on the second sphere is [tex]q_2 = 8 \mu C = 8*10^{-6} \ C[/tex]
The mass of the second charge is [tex]m = 1.50 \ g = 1.50 *10^{-3} \ kg[/tex]
The distance apart is [tex]d = 0.4 \ m[/tex]
The speed of the second sphere is [tex]v_1 = 20 \ ms^{-1}[/tex]
Generally the total energy possessed by when [tex]q_2[/tex] and [tex]q_1[/tex] are separated by [tex]0.8 \ m[/tex] is mathematically represented
[tex]Q = KE + U[/tex]
Here KE is the kinetic energy which is mathematically represented as
[tex]KE = \frac{1 }{2} m (v_1)^2[/tex]
substituting value
[tex]KE = \frac{1 }{2} * ( 1.50 *10^{-3}) (20 )^2[/tex]
[tex]KE = 0.3 \ J[/tex]
And U is the potential energy which is mathematically represented as
[tex]U = \frac{k * q_1 * q_2 }{d }[/tex]
substituting values
[tex]U = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.8 }[/tex]
[tex]U = 0.18 \ J[/tex]
So
[tex]Q = 0.3 + 0.18[/tex]
[tex]Q = 0.48 \ J[/tex]
Generally the total energy possessed by when [tex]q_2[/tex] and [tex]q_1[/tex] are separated by [tex]0.4 \ m[/tex] is mathematically represented
[tex]Q_f = KE_f + U_f[/tex]
Here [tex]KE_f[/tex] is the kinetic energy which is mathematically represented as
[tex]KE_f = \frac{1 }{2} m (v_2^2[/tex]
substituting value
[tex]KE_f = \frac{1 }{2} * ( 1.50 *10^{-3}) (v_2 )^2[/tex]
[tex]KE_f = 7.50 *10^{ -4} (v_2 )^2[/tex]
And [tex]U_f[/tex] is the potential energy which is mathematically represented as
[tex]U_f = \frac{k * q_1 * q_2 }{d }[/tex]
substituting values
[tex]U_f = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.4 }[/tex]
[tex]U_f = 0.36 \ J[/tex]
From the law of energy conservation
[tex]Q = Q_f[/tex]
So
[tex]0.48 = 0.36 +(7.50 *10^{-4} v_2^2)[/tex]
[tex]v_2 = 4 \sqrt{10} \ m/s[/tex]
Rayna studied rats in a lab. She observed that all 50 rats in her sample preferred to eat brand A rat food and would eat brand B food only when brand A was not available. Can she correctly conclude that all rats prefer brand A rat food over brand B food? Why or why not?
Answer:
it is correct to conclude that rats prefer food A over food B
the standard deviation is zero
Explanation:
In the experiment performed when both meals are available, rats prefer food A and eat only B when no other is available.
Therefore it is correct to conclude that rats prefer food A over food B
This conclusion is correct because ours is significant with a population of 50 animals all have the same preference for which the standard deviation is zero
A proton accelerates from rest in a uniform electric field of 660 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. m/s2 (b) Over what time interval does the proton reach this speed? s (c) How far does it move in this time interval? m (d) What is its kinetic energy at the end of this interval? J
Answer:
a) a = 6.31 10¹⁰ m / s² , b) t = 2.06 10⁻⁵ s , c) x = 13.39 m , d) ΔK = 1.41 10⁻¹⁵ J
Explanation:
a) Since they indicate that the speeds are non-relativistic, we can use the kinematics relations and Newton's second law
F = m a
The force in electrical is
F = qE
qE = m a
a = qE / m
we calculate
a = 1.6 10⁻¹⁹ 660 / 1.673 10⁻²⁷
a = 6.31 10¹⁰ m / s²
b) Let's use the one-dimensional kinematics relation
v = v₀ + a t
as part of rest its initial velocity is zero
v = a t
t = v / a
t = 1.30 10⁶ / 6.31 10¹⁰
t = 2.06 10⁻⁵ s
c) We use the kinematics displacement equation
x = v₀ t + ½ a t²
initial velocity is zero
x = ½ a t²
x = ½ 6.31 10¹⁰ (2.06 10⁻⁵)²
x = 1,339 10¹ m
x = 13.39 m
d) the kinetic energy is
ΔK = Kf -K₀
ΔK = ½ m v² - 0
ΔK = ½ 1.673 10⁻²⁷ (1.30 10⁶) 2
ΔK = 1.41 10⁻¹⁵ J
When a rubber ball dropped from rest bounces off the floor, its direction of motion is reversed becaue
(A) energy of the ball is conserved
(B) momentum of the ball
(C) the floor exerts a force on the ball that stops its fall and then drives it upward
(D) the floor is in the way and the ball has to keep moving
(E) none of the above
Answer:In physics, energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object.[note 1] Energy is a conserved quantity; the law of conservation of energy states that energy can be converted in form, but not created or destroyed. The SI unit of energy is the joule, which is the energy transferred to an object by the work of moving it a distance of 1 metre against a force of 1 newton.
Common forms of energy include the kinetic energy of a moving object, the potential energy stored by an object's position in a force field (gravitational, electric or magnetic), the elastic energy stored by stretching solid objects, the chemical energy released when a fuel burns, the radiant energy carried by light, and the thermal energy due to an object's temperature.
Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.
Living organisms require energy to stay alive, such as the energy humans get from food. Human civilization requires energy to function, which it gets from energy resources such as fossil fuels, nuclear fuel, or renewable energy. The processes of Earth's climate and ecosystem are driven by the radiant energy Earth receives from the sun and the geothermal energy contained within the earth.
Explanation:
Some forms of energy (that an object or system can have as a measurable property)
Type of energy Description
Mechanical the sum of macroscopic translational and rotational kinetic and potential energies
Electric potential energy due to or stored in electric fields
Magnetic potential energy due to or stored in magnetic fields
Gravitational potential energy due to or stored in gravitational fields
Chemical potential energy due to chemical bonds
Ionization potential energy that binds an electron to its atom or molecule
Nuclear potential energy that binds nucleons to form the atomic nucleus (and nuclear reactions)
Chromodynamic potential energy that binds quarks to form hadrons
Elastic potential energy due to the deformation of a material (or its container) exhibiting a restorative force
Mechanical wave kinetic and potential energy in an elastic material due to a propagated deformational wave
Sound wave kinetic and potential energy in a fluid due to a sound propagated wave (a particular form of mechanical wave)
Radiant potential energy stored in the fields of propagated by electromagnetic radiation, including light
Rest potential energy due to an object's rest mass
Thermal kinetic energy of the microscopic motion of particles, a form of disordered equivalent of mechanical energy
Main articles: History of energy and timeline of thermodynamics, statistical mechanics, and random processes
A right triangle has a hypotenuse of 37 and a leg of 10. What is the second leg of the triangle?
Answer:
The second leg of the triangle is 35.62
Explanation:
Given that
Hypotenuse = 37
A leg = 10
Based on the above information
The second leg of the triangle is
According to the Pythagorean theorem
a^2 + b^2 = c^2
where,
a and b = legs
And, the c = hypotenuse.
Now put these values to the above formula
So,
10^2 + b^2 = 37^2
b^2 = 37^2 - 10^2
b^2 = 1269
b = sqrt(1269)
b = 35 .62
Hence, the second leg of the triangle is 35.62
The other leg is 35 mm.
What speed would such a block have if pushed horizontally 108 m along a frictionless track by such a laser
Hello. This question is incomplete. The full question is:
You've recently read about a chemical laser that generates a 20-cm-diameter, 25.0 MW laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a 20-cm-diameter, 100 kg,perfectly absorbing block. What speed would such a block have if pushed horizontally 108 m along a frictionless track by such a laser?
Answer:
V = 0.408 m / s
Explanation:
First, it is necessary to find the radiation pressure on the surface. You will find it using the following formula:
P = P / (πr ^ 2) c
where P is the pressure and c is the speed of light in vacuum
P = 25 * 10 ^ 6 / π (0.2 / 2) ^ 2 * (3 * 10 ^ 8) = 2,652 N / m ^ 2.
Then you must calculate the force (F) and the acceleration (a). This is done through the formulas:
F = P * (πr ^ 2)
F = 2,652 * π * (0.2 / 2) ^ 2 = 0.083N
a = F / m
a = 0.083 / 100 = 0.0002129 m / s ^ 2
You can now calculate the speed.
V = √2ad
V = √2 *0.0002129 * 108
V = 0.2144 m / s
An optical fiber made of glass with an index of refraction 1.50 that is coated with a material with index of refraction 1.30 has a critical angle of
Answer:
A critical angle of 60.1°
Explanation:
Let's say
n1 Refractive index of rarer medium
n2 Refractive index of denser medium
So using the relation
စc= Sin^ -1(n1/n2)
So
စc = Sin^-1(1.3/1.5) = 60.1°
If the charge remains the same but the radius of the sphere is doubled, the electric flux coming out of it will be
Answer:
Explanation:
We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .
∫ E ds = q / ε
Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so
∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .
This also represents total flux coming out of the charge q on all sides .
This is equal to q / ε where ε is a constant called permittivity which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .
If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .
It is so because flux coming out of charge q is q / ε . It does not depend upon surface area enclosing the charge . It depends upon two factors
1 ) charge q and
2 ) the permittivity of medium ε around .